1. An electrical current is flowing through a circuit at a rate of 25 m/s and then decelerates
when it passes through the resistor and reaches a velocity of 13 m/s within 5 seconds.
What is the electrical current's acceleration?

Answer:

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

[tex]B = \mu_{0}nI[/tex]

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

[tex]B_{1} = \mu_{0}n_{1}I ------------------- equation 1[/tex]

For Solenoid 2:

n₂ = 6n₁

Therefore,

[tex]B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I ----------------- equation 2[/tex]

Diving equation 1 and equation 2:

[tex]\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6[/tex]

Hence, the correct option is:

6

The ratio of the magnetic fields in interior 2 to interior 1 will be

[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]

The formula for the magnetic fields inside the solenoid will be given:

[tex]B=\mu_onI[/tex]

here,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For the first Solenoid

[tex]B_1=\mu_on_1I[/tex]..................(1)

For the second solenoid

[tex]n_2=6n_1[/tex]

Now

[tex]B_2=\mu_on_2I[/tex]

[tex]B_2=\mu_o(6n_1)I[/tex]..................(2)

Diving equation 1 and equation 2:

[tex]\dfrac{B_2}{B_1} =\dfrac{\mu_o(6n_1)I}{\mu_on_2I}[/tex]

[tex]\dfrac{B_2}{B_1} =6[/tex]

Thus the ratio of the magnetic fields in interior 2 to interior 1 will be

[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]

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Answer:

All the cells in an organism have exactly the same function

Answer:

16m/s

Explanation:

Given the following data;

Force, F = 16N

Mass, m = 5kg

Time, t = 5 seconds.

First of all, we would find the acceleration of the object.

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is given by the formula;

[tex] F = ma[/tex]

Where;

Making acceleration (a) the subject, we have;

[tex]Acceleration, a = \frac{F}{m}[/tex]

Substituting into the equation;

[tex]Acceleration, a = \frac{16}{5}[/tex]

Acceleration, a = 3.2 m/s²

Now, to find velocity;

We would use the first equation of motion given by the formula;

[tex] V = U + at[/tex]

Where;

We know that acceleration due to gravity is 9.8m/s² and initial velocity (U) is 0 since the object is at rest.

Substituting into the equation, we have;

[tex] V = 0 + 3.2*5[/tex]

[tex] V = 0 + 16[/tex]

Velocity, V = 16m/s.

Answer:

The tension in the string is 52.89 N.

Explanation:

Given;

mass of the string, m = 19.1 g = 0.0191 kg

length of the string, L = 1.95 m

⇒mass per unit length, μ = 0.0191 / 1.95 = 0.009795 kg/m

Also Given;

frequency of the string, F = 440 Hz

wavelength of the sound wave, λ = 16.7 cm = 0.167 m

⇒the speed of the wave, v = Fλ = 440 x 0.167 = 73.48 m/s

The tension T in the string is calculated as;

[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu}\\\\T = v^2 \mu\\\\T = (73.48)^2 (0.009795)\\\\T = 52.89 \ N[/tex]

Therefore, the tension in the string is 52.89 N.

The statements that describe the processes involved in the accretion of planetesimals and protoplanets are :

II. Both processes involve nebular materials becoming solid particles.

IV. In both cases, masses of stuff are clumped together and gases are trapped.

Accretion basically involves the accumulation of particles into a massive object by gravitationally attracting more matter, mainly the gaseous matter, in an accretion disk.

A protoplanet is basically a large planetary embryo that has originated within a protoplanetary disc and which also has undergone internal melting to produce a differentiated interior.

Planetesimals are known to be small rock-type objects which are

formed by collisions with other objects present in the solar system.

Hence, the statements that describe the processes involved in the accretion of planetesimals and protoplanets are :

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The complete question is mentioned below:

Which statements describe processes involved in the accretion of planetesimals and protoplanets?

( I ) Both involve the melting of solid materials in the nebula.

( II ) Both involve the formation of solid particles from nebular materials.

( III ) Both involve the work of the gravitational push on nebular materials.

( IV ) Both involve the trapping of gases and the clumping of masses of matter.

( V ) Both involve the growing of gas grains with the addition of atoms and molecules.

Answer:

Cost = $ 7.72

Explanation:

Considering the trip of 100 km, the cost spent on the fuel during the trip can be calculated by the following formula:

[tex]Cost = Average Fuel Consumption\ x\ Unit Fuel Cost\ x\ Distance[/tex]

where,

Average Fuel Consumption = 6 liter/100 km

Unit Fuel Cost = (1.063 euros/liter)($ 1.21/1 euro) = $ 1.29/liter

Distance = 100 km

Therefore,

[tex]Cost = (6\ liter/100\ km)(\$\ 1.29/liter)(100\ km)\\[/tex]

Cost = $ 7.72

Answer:

-79

Explanation:

because I know because that's what the answer is because it is -79 when it hits the ground

Answer:

9.2m

Explanation:

Think of the woman's path as a triangle. She walks 7m horizontally and 6m vertically. These are the two legs of a triangle. In order to find her distance from the origin, we can use pythagorean theorem to find the hypotenuse of the triangle. The hypotenuse will give us the direct measurement from the origin (0,0) to her current point (7,6).

a²+b²=c²

(7)²+(6)²=c²

49+36=c²

85=c²

Find the square roots of both sides to get c=9.21954...

Round your answer to the nearest 10th:

c=9.2m

The woman is approximately 9.2m from the origin.

Hello!

[tex]\large\boxed{F = 100N}[/tex]

Use the equation F = m · a (Newton's Second Law) to solve. Substitute in the given values:

F = 5 · 20

F = 100N

30.76/s is the angular speed of the car traveling at a constant speed of 14m/s and having a tire of  diameter of 0.91m

The rate of change of angular displacement is known as Angular velocity . The unit of angular velocity is radians/second. The same formula describes both angular velocity and angular velocity. Angular velocity is a vector quantity that expresses both direction and magnitude, but angular velocity expresses only magnitude. Angular velocity (ω) is a scalar measure of rotational speed. The angular distance traveled in one full rotation is 2π and the time is duration (T).

here from the given data that is a constant speed of 14. It tires have a diameter of 0.91

ω=θ/t

V=2πr/t

=14m/s

ω=v/r

=14/0.45

=30.76

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the question you provided was incomplete and I have added the incomplete part that is to find the angular speed of the given data.

Answer:

3.08m/s²

Explanation:

Given parameters:

Radius = 20m

Tangential velocity  = 7.85m/s

Unknown:

Centripetal acceleration  = ?

Solution:

Centripetal acceleration is the acceleration of a body along a circular path.

 it is mathematically given as;

       a  = [tex]\frac{v^{2} }{r}[/tex]  

v is the tangential velocity

r is the radius

      a  = [tex]\frac{7.85^{2} }{20}[/tex]   = 3.08m/s²

Answer:

The appropriate response will be "Infrared has a longer wavelength and lower photon energy".

Explanation:

Answer:

When speed reduces, acceleration decreases

Explanation:

From first equation of motion;

[tex]{ \tt{v = u + at}}[/tex]

When time is constant:

[tex]{ \tt{v = 0 + kt}} \\ { \tt{v = kt}} \\{ \tt{v \: \alpha \: \: a}}[/tex]

When speed is decreasing, velocity and acceleration are in opposite directions.

Answer:

v = 0.6c = 1.8 x 10⁸ m/s

Explanation:

From Einstein's theory of relativity, we know that the length of an object contracts while traveling at a speed relative to speed of light. The contraction is according to following equation:

[tex]L = L_{0}\sqrt{1 - \frac{v^2}{c^2}}[/tex]

where,

L = Relative Length

L₀ = Rest Length

According to given:

L = 0.8 L₀

c = speed of light = 3 x 10⁸ m/s

v = relative speed of train = ?

Therefore,

[tex]0.8L_{0} = L_{0}\sqrt{1 - \frac{v^2}{c^2} } \\\\0.8 = \sqrt{1 - \frac{v^2}{c^2} }[/tex]

squaring on both sides:

[tex]0.64 = 1-\frac{v^2}{c^2}\\\\\frac{v^2}{c^2} = 1-0.64 \\v^2= 0.36c^2\\[/tex]

taking square root on both sides:

v = 0.6c = 1.8 x 10⁸ m/s

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Complete Question

Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of [tex]0.025 \ m^3[/tex]. If the temperature of the gas is 290 K. what is the rms speed of the gas atoms? The atomic mass of Argon is 39.9 u.(l u= 1.66x10-27 kg) Enter your answer in m/s

Answer:

The value is [tex]V_{rms} = 425.75 \ m/s[/tex]

Explanation:

From the question we are told that

     The volume of the space in between the two glass sheet is  [tex]a = 0.025 \ m^3[/tex]

     The temperature of the gas is [tex]T = 290 \ K[/tex]

       The atomic mass of Argon is  [tex]m = 39.9 \ u = 39.9 * 1.66 *10^{-27} = 6.623 *10^{-26} \ kg[/tex]

Generally the root mean square velocity is mathematically represented as

      [tex]V_{rms} = \sqrt{\frac{3 K T}{ m } }[/tex]

Here K is the Boltzmann constant  with value [tex]k = 1.38 *10^{-23} \ m^3 \cdot kg \cdot s^{-2} \cdot K^{-1}[/tex]

So

     [tex]V_{rms} = \sqrt{\frac{3 * 1.38 *10^{-23} * 290 }{ 6.6234*10^{-26} } }[/tex]

=>   [tex]V_{rms} = 425.75 \ m/s[/tex]

Answer:

Counter clockwise

Explanation:

Answer:

The horse moves due to kinetic energy and is walking balanced because of the gravitational energy

Explanation:

hope this helps :) please mark me brainliest

A bowling ball results in kinetic friction compared to a sliding bowling ball.

According to Conservation of momentum, if a bowling ball hits some pins, the momentum that lost by the bowling ball is known to be equal to the momentum obtained by the pins.

The friction that is used in bowling is kinetic friction because the more oil that is placed down, the lower the friction that is found between the ball and that of the lane surface. The  little friction, the stronger it is for the bowler to be able to send the ball in a curved path and thus the formula to find the kinetic friction is know to be : µk=F k/mg.

Therefore, A bowling ball results in kinetic friction compared to a sliding bowling ball.

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This question is incomplete, the complete question is on the image uploaded along this answer.

Answer:

the potential at point B is 5 V, Option d) is the correct answer

Explanation:

Given that;

from the image;

R = 3 + 4 + 5 = 12 Ω

so I = 12/12 = 1 A

Q = 0 + 12 = 12 V

now

VA - VQ = - I × 3 = -3 V

VA = VQ - 3 =  12 - 3 = 9 V

VB - VA = - I × 4Ω = - 4 V

⇒VB = VA - 4 = 9 V - 4 V = 5 V

Therefore the potential at point B is 5 V

Option d) is the correct answer

Answer: A

Explanation:

Answer:

3.69 rad/s

Explanation:

From the question given above, the following data were obtained:

Period (T) = 1.7 s

Angular frequency (ω) =?

Thus, we can obtain the angular frequency (ω) by applying the following formula:

ω = 2π/T

Period (T) = 1.7 s

Pi (π) = 3.14

Angular frequency (ω) =?

ω = 2π/T

ω = 2 × 3.14 / 1.7

ω = 6.28 / 1.7

ω = 3.69 rad/s

Thus, the angular frequency of the motion is 3.69 rad/s

Answer:

Yes it is matter

Explanation:

In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.

Given that,

The rate of change of current = 3.2 A/s

Emf induced in the coil = 5.7 V

To find,

The magnitude of the mutual inductance of the two coils.

Solution,

The mutual inductance between the coils is given by the formula as follows :

[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]

So, the mutual inductance of the two coils is 1.78 H.

Given that,

At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.

To find,

The distance from the source would the sound level be one-fourth the sound level at 3.00 m.

Solution,

The intensity from a source is inversely proportional to the distance.

Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?

Using relation :

[tex]\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\\r_2^2=\dfrac{I_1r_1^2}{I_2}\\\\r_2^2=\dfrac{60\times (3)^2}{15}\\\\r_2=6\ m[/tex]

So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.

Answer:

letter B..

Explanation:

because pinililit you direction pina force nyang itulak

The ball encounters resistance as it travels through the air. Drag is the term for the air's resistance to the ball. Drag slows down the baseball because it is applied against the direction of the ball's flight. Thus, option B is correct.

When two objects rub against one another, a force known as friction is applied. Friction force often works to prevent an object from moving. For instance, friction between a ball and carpet when rolling a ball across it causes the ball to move more slowly.

A baseball in flight is impacted by three forces. The three forces are lift, drag, and weight. Actually, the aerodynamic force exerted on the ball is made up of two parts: lift and drag. Lift acts perpendicular to the motion, and drag acts in the direction opposite to the motion.

Therefore,  the direction of the force the least effect on the motion of a ball.

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"Distance" here is the total distance traveled along the red path (see attached) from point A to point B. Just count how many how sides of each square in the grid are touched by the path. Then distance = 24 units.

"Displacement" is the net distance covered by moving from point A to point B, or the length of the green path. So displacement = 2 units to the right. Of course, your question seems to ask for the displacement in terms of units to the left, in which you could say -2 units to the left.

The mass of the cylinder made of lead is 644.33 kg.

Mass can be defiend as the quantity of matter a contained in a body. The S.I unit of mass is kilogram (kg).

To calculate the mass of the cylindrical lead, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute the values above into equation 1

Hence, the mass of the cylinder made of lead is 644.33 kg.

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