The increase in length of the iron wire when warmed from 20°C to 45°C is approximately 8.25 millimeters. The specific heat capacity of the object is approximately 9.62 J/kg°C. The heat capacity of the object is approximately 1.83 J/°C.
ΔL = L × α × ΔT
Where:
ΔL is the change in length
L is the original length of the wire
α is the coefficient of linear expansion for iron
ΔT is the change in temperature
The coefficient of linear expansion for iron is typically 1.1 x [tex]10^(^-^5^)[/tex] °[tex]C^(^-^1^)[/tex].
Given:
L = 30 m (original length of the wire)
α = 1.1 x [tex]10^(^-^5^)[/tex] °[tex]C^(^-^1^)[/tex] (coefficient of linear expansion)
ΔT = 45°C - 20°C = 25°C (change in temperature)
ΔL = 30 m × (1.1 x [tex]10^(^-^5^)[/tex] °[tex]C^(^-^1^)[/tex]) × 25°C
= 30 m × 1.1 x[tex]10^(^-^5^)[/tex] × 25
= 8.25 x [tex]10^(^-^3^)[/tex] m
2) Q = mcΔT
Where:
Q is the heat energy transferred
m is the mass of the object
c is the specific heat capacity
ΔT is the change in temperature
Given:
Q = 2200 J (heat energy transferred)
m = 190 g (mass of the object)
ΔT = 12°C (change in temperature)
a. Specific heat capacity (c):
one need to rearrange the formula to solve for c:
c = Q / (m × ΔT)
Substituting the given values:
c = 2200 J / (190 g × 12°C)
First, need to convert the mass to kilograms:
m = 190 g = 190 g / 1000 = 0.19 kg
Now can calculate the specific heat capacity:
c = 2200 J / (0.19 kg × 12°C)
= 9.62 J/(kg°C)
b. Heat capacity (C):
The heat capacity is the amount of heat energy required to raise the temperature of the object by 1 degree Celsius.
C = mc
Substituting the given values:
C = 0.19 kg × 9.62 J/(kg°C)
= 1.83 J/°C
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What can be said about the speed ofa particle if the net work done on it is zero?
If the net work done on a particle is zero, the particle will move with a constant speed.
The principle of work and kinetic energy, often known as the work-energy theorem, states that the change in kinetic energy of a particle is equal to the sum of the entire work done by all of the forces acting on it.
So,
W = ΔKE
Thus, we can say that the kinetic energy of the particle will not change if the net work done on it is equal to zero.
As a result, the state of motion of the particle will not change, and thus the speed of the particle will also remain constant.
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What is the value of acceleration in the following conditions
when a body comes at its initial position after motion
When a body comes to its initial position after motion, its velocity becomes zero, but the value of acceleration can vary depending on the specific conditions of the motion.
If the body comes to rest smoothly and gradually, the acceleration is zero. This means that there is no net force acting on the body, and it is not experiencing any acceleration. The body's velocity decreases over time until it reaches zero, and it returns to its initial position without any further acceleration.
However, if the body comes to its initial position abruptly, the situation is different. In this case, the body experiences a sudden change in velocity, and the acceleration can be nonzero.
For example, if a body is moving with a certain velocity and suddenly hits an obstacle or encounters a collision that brings it to a stop, the acceleration during the collision will be nonzero. The body experiences a rapid deceleration as it comes to rest, and this deceleration represents a negative acceleration.
In general, when a body comes to its initial position after motion, the value of acceleration can vary depending on the specific circumstances of the motion. It can be zero if the body comes to rest smoothly and gradually, or it can be nonzero if there is a sudden change in velocity leading to deceleration or acceleration.
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QUESTION ❗️❗️❗️❗️❗️❗️
How could you measure the flow rate of various liquid
a.Place each one on a scale and measure its weight versus its volumes
b.Place them in a beaker and se which one floats to the top
c.Pour them down an incline and time how long it takes each one to reach the bottom
d.Burn each sample to create a deposit than can be analyzed
We can measure the flow rate of various liquid by pouring the liquid down an incline and time how long it takes each one to reach the bottom.
option C.
What is the flow rate of a liquid?
The flow rate of a liquid is how much fluid passes through an area in a particular time.
Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume. As liquids are incompressible, the rate of flow into an area must be equivalent to the rate of flow out of an area.
Generally, the best equipment to measure the flow rate of a liquid is flow meters. In the absence of flow meters, we can other methods such as the one given in the options.
We can pour the various liquid down an incline and time how long it takes each one to reach the bottom.
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A virtual satellite orbits the earth at an altitude h = 1600km with an altitude v = 7.1km / s. The amperage of the centrifugal force is F ’= 3151N. Calculate the satellite mass. It is known that the radius of the earth R = 6400 / km.
Alice throws a ball on the ground,and it bounces back to her hand, there is no net change in the kinetic energy. What is the type of collision
Answer: the type of collision is elastic collision because both momentum and kinetic energy are conserved.
hope this helped!
A car travels a distance of 120 km in 4 hours. What is its average speed in kilometers per hour?
Answer:
60 kilometers per hr
Explanation:
Initial State: A sled and child are in motion halfway down a hill.
Final State: The sled and child are at rest at the bottom of the hill.
Notes: The system includes the sled, the child, and the Earth. The sled glides
freely until finally stopped by a rough patch of snow.
We have a sled and a child in motion halfway down a hill, and the final state is that both the sled and the child are at rest at the bottom of the hill. The system includes the sled, the child, and the Earth. The sled glides freely until it is stopped by a rough patch of snow.
The sled and child are in motion halfway down the hill. At this point, both the sled and the child possess kinetic energy due to their motion. The sled's motion is initiated by the force applied by the child or by the gravitational force acting on it.
As the sled and child continue down the hill, they experience a gravitational force pulling them towards the Earth. The sled glides freely, meaning there are no external forces acting on it apart from gravity and any frictional forces present on the hill. The child's weight is also acting on the sled, contributing to the force pushing it downhill.
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What are the similarities and differences between these data sets in terms of their centers and their variability?
Data Set A: 12, 15, 18, 18, 22, 29
Data Set B: 13, 17, 17, 19, 20, 34
Select from the drop-down menus to correctly complete the statements.
Comparing the centers of the data sets, the median for Data Set A is Choose...
Choose.
Set A is Choose... the mean for Data Set B.
less than
equal to
greater than
the median for Data Set B. The mean for Data
4
Polaris has a fixed position in the sky as it lies directly over the celestial North Pole. Therefore, it is useful to be able to identify Polaris, to help you get your bearings. First identify the two stars in the Great Dipper that point to Polaris. Then identify the position of Polaris in this image of the night sky.
Answer:
Explanation:
Unfortunately, as an AI text-based model, I cannot directly view or interpret images. However, I can still provide you with the information you need to identify Polaris and its position in the night sky.
To locate Polaris using the stars of the Big Dipper (also known as the Great Dipper or Ursa Major), you can follow these steps:
1. Locate the Big Dipper: The Big Dipper is a prominent asterism, or a recognizable pattern of stars, within the constellation Ursa Major (the Great Bear). It is visible in the northern hemisphere during most of the year.
2. Identify the pointer stars: The two stars on the outer edge of the Big Dipper's bowl, farthest from the handle, are called the pointer stars. These stars are named Dubhe and Merak.
3. Extend the line between the pointer stars: Mentally extend an imaginary line that passes through Dubhe and Merak, extending it for approximately five times the distance between the pointer stars.
4. Locate Polaris: The extended line will lead you to Polaris, also known as the North Star. Polaris is relatively bright and appears as the last star in the handle of the Little Dipper (Ursa Minor constellation). It lies almost directly above the North Pole of the Earth and remains nearly fixed in the sky while other stars appear to rotate around it as the Earth rotates.
By following these steps, you should be able to identify Polaris and its position in the night sky, even without an image.
Polaris is positioned directly above the celestial North Pole in the sky, making it a useful navigation tool. The easiest way to locate it is by identifying the Great Dipper constellation and using its two pointer stars, Dubhe and Merak, to lead to the North Star.
Explanation:The star Polaris, also known as the North Star, is beneficial for navigation due to its fixed position in the sky above the celestial North Pole. The best way to locate it is by first finding the Great Dipper constellation. Two stars in the bowl of this Dipper, named Dubhe and Merak, form a line that leads directly to Polaris.
In the given image, without the benefit of visual reference, it is difficult to identify the specific position of Polaris. However, remember that in actual practice, you would find the two pointer stars of the Great Dipper and follow a line from these stars to locate Polaris.
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Fill in the blanks: the standard international (SI) unit for mass is the , The standard international (SI) unit for force is the .
The standard international (SI) unit for mass is the kilogram (kg). It is a fundamental unit of measurement used to quantify the amount of matter in an object. The standard international (SI) unit for force is the Newton (N)
The mass of the platinum-iridium cylinder known as the International Prototype of the Kilogramme, which is held at the International Bureau of Weights and Measures in France, is what is used to define the kilogramme.
The newton (N), on the other hand, serves as the standard international (SI) unit for force. The force needed to accelerate a one kilogramme mass by one square metre per second is measured in newtons. It is a derived unit that is frequently used to measure a variety of forces, including electromagnetic, mechanical, and gravitational forces.
Sir Isaac Newton, a distinguished scientist who made substantial advances to our knowledge of forces and motion, is honoured by having his name attached to the newton.
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What is the value of the universal gas constant (R) in Sl units?
Force varies directly with pressure. A force of 22,000 newtons acts on an object, causing 110 N/m² of pressure. The
force decreases to 18,000 newtons. What is the new amount of pressure caused by the force?
○ 45 N/m²
90 N/m²
O 75 N/m²
60 N/m²
The final amount of pressure caused by the force is 90 N/m².
Initial amount of force, F₁ = 22 x 10³ N
Initial amount of pressure produced, P₁ = 110 N/m²
Final amount of force exerted, F₂ = 18 x 10³ N
Pressure is defined as the amount of force acting on an object per unit area of the object.
So, we can say that the force and pressure are directly proportional.
F ∝ P
So, F₁/P₁ = F₂/P₂
Therefore, the final amount of pressure caused by the force is,
P₂ = F₂P₁/F₁
P₂ = 18 x 10³x 110/22 x 10³
P₂ = 18/0.2
P₂ = 90 N/m²
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If you know the answer tell me ASAP
In order to measure the potential difference across one of the bulbs in the circuit, the voltmeter must be connected in parallel with it. So, option D.
When two points in a circuit have different electric potentials, a voltmeter is a tool or instrument that measures their potential difference.
We are aware that a voltmeter is a tool that measures the same potential drop in all configurations that are in parallel.
The potential difference between two points in a circuit is thus always measured by connecting a voltmeter in parallel across the conductor's ends.
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with a hydraulic press a vehicle with a mass of 1,140 kg is lifted using a piston with an area of A2=1.15m². On the other cylinder, a forze F1=182N is applied. what is the value of the area A1 of this cylinder?
The value of the area A₁ of this cylinder of the hydraulic press is determined as 0.019 m².
What is the value of the area A1 of this cylinder?The value of the area A₁ of this cylinder is calculated by applying Paschal principle as follows;
P = F/A
F₁/A₁ = F₂/A₂
where;
F₁ is the force on the first endF₂ is the force on the second endA₁ is the area of the first endA₂ is the area of the second endA₁/F₁ = A₂/F₂
A₁ = (F₁ / F₂ ) A₂
The value of the area A₁ of this cylinder is calculated as follows;
A₁ = (182 / 1140 x 9.8 ) 1.15
A₁ = 0.019 m²
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if 1inch is 2.5cm then 1.0in^2 of surface area is
1.0 square inch of surface area is equal to 6.4516 square centimeters.
An inch is a unit of length commonly used in the United States and some other countries that have not adopted the metric system. It is denoted by the symbol "in" or double prime ("). One inch is equal to exactly 2.54 centimeters. It is subdivided into smaller units such as fractions (e.g., 1/2 inch, 1/4 inch) or decimals (e.g., 0.25 inches, 0.5 inches) for more precise measurements. The inch is primarily used for measuring shorter distances, such as the length of objects, fabric, or paper.
To convert square inches to square centimeters, we need to know the conversion factor for converting inches to centimeters.
Since 1 inch is equal to 2.54 centimeters (not 2.5 centimeters as mentioned in your statement), we can use this conversion factor to calculate the surface area in square centimeters.
To convert 1 square inch to square centimeters, we square the conversion factor:
1 inch^2 = (2.54 cm)^2 = 6.4516 square centimeters (approximately).
Therefore, 1.0 square inch of surface area is approximately equal to 6.4516 square centimeters.
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PLEASE SHOW YOUR WORK!
Question Difficulty: HARD
Point Range: 50 - 70
First Answer Brainly: Yes.
The period of a wave is the amount of time needed for a wave to pass a point. Use the formula to calculate the period of a wave that has a frequency of 0.10 Hz and a wavelength of 14 cm. Formula: f=1/T
Answer:
1.4
Explanation:
We are given,
f=.1 Hz
and
λ= 14
Using the equation for wave speed, we can calculate
v=fλ
=.1 Hz × 14 cm
= 1.4m/s
Hence, the speed of the sound waves in the given medium is 1.4 m/s.
A wagon, Initially traveling at a constant 3.6 m/s, starts going down a hill that creates an acceleration of
1.6 m/s2. What is the wagon's velocity 4.8 s after it starts accelerating down the hill?
A war-wolf or trebuchet is a device used during the Middle Ages to throw rocks at castles and now sometimes used to fling large vegetables and pianos as a sport. A simple trebuchet is shown in the figure below. Model it as a stiff rod of negligible mass, d = 2.60 m long, joining particles of mass m1 = 0.115 kg and m2 = 68.5 kg at its ends. It can turn on a frictionless, horizontal axle perpendicular to the rod and 13.0 cm from the large-mass particle. The operator releases the trebuchet from rest in a horizontal orientation.
Find the maximum speed that the small-mass object attains when it leaves the trebuchet horizontally.
The maximum speed that the small-mass object attains when it leaves the trebuchet horizontally is approximately 28.3 m/s.
To find the maximum speed that the small-mass object attains when it leaves the trebuchet horizontally, we can apply the principle of conservation of mechanical energy.
Initially, the trebuchet is at rest, so its total mechanical energy is zero. As the small-mass object leaves the trebuchet horizontally, it gains kinetic energy. At this point, all of the potential energy of the system is converted into kinetic energy.
The potential energy of the system can be calculated as the sum of the gravitational potential energies of the two masses:
PE = m1 * g * h1 + m2 * g * h2
Since the trebuchet is released from rest in a horizontal orientation, the initial height h1 is zero. The height h2 can be calculated as the perpendicular distance between the pivot point and the center of mass of the larger mass m2:
h2 = 13.0 cm = 0.13 m
Therefore, the potential energy simplifies to:
PE = m2 * g * h2
The kinetic energy of the small-mass object can be calculated as:
KE = (1/2) * m1 * v^2
where v is the maximum speed of the small-mass object.
Since the total mechanical energy is conserved, we have:
PE = KE
m2 * g * h2 = (1/2) * m1 * v^2
Plugging in the given values, such as g = 9.8 m/s^2, m1 = 0.115 kg, m2 = 68.5 kg, and h2 = 0.13 m, we can solve for v:
(68.5 kg * 9.8 m/s^2 * 0.13 m) = (1/2) * 0.115 kg * v^2
Solving for v, we find:
[tex]v^2 = (68.5 kg * 9.8 m/s^2 * 0.13 m) / (0.115 kg)[/tex]
[tex]v^2 = 800[/tex]
v ≈ 28.3 m/s
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Find the x-component of this vector: 12.1 m 48.4° Remember, angles are measured from the +x axis. X-component (m)
The x component of the vector is determined as 8.03 m.
What is the x -component of the vector?The x component of the vector is calculated by applying the following formula as shown below;
Vx = V cosθ
where;
V is the magnitude of the velocityθ is the angle of inclination of the vectorVx is the x component of the vectorThe x component of the vector is calculated as follows;
Vx = 12.1 m x cos (48.4⁰)
Vx = 8.03 m
Thus, the x component of the vector is determined as 8.03 m.
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A spring stretches 0.294-m when a 0.360-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.431-kg mass resting on a frictionless table as in Fig. 11–5. The mass is pulled so that the spring is stretched 0.250-m from the equilibrium point, and released from rest.
Determine:
(a) the spring stiffness constant k.
The spring constant k based on the information is 12.0 N/m.
How to calculate the valueFrom the information, a spring stretches 0.294-m when a 0.360-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.431-kg mass resting on a frictionless table.
The spring constant k is the force required to stretch or compress the spring by a unit distance. In this case, the spring is stretched by 0.294 m when a 0.360 kg mass is suspended from it.
This means that the force exerted by the spring is equal to the weight of the mass, which is 0.360 kg x 9.8 m/s^2 = 3.53 N.
Therefore, the spring constant k is:
= 3.53 N/0.294 m
= 12.0 N/m.
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If you know the answer please tell me ASAP
3. Fulcrum left
Explanation:
Calculate the equivalent resistance of these series - connected resistors : 680Ω , 1.1ΚΩ , and 11ΚΩ .
A spring stretches 0.145-m when a 0.233-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.456-kg mass resting on a frictionless table as in Fig. 11–5. The mass is pulled so that the spring is stretched 0.192-m from the equilibrium point, and released from rest.
Determine:
(c) the magnitude of the maximum velocity vmax.
The maximum velocity of oscillation of the spring is 1.57m/s.
Displacement of the spring, x = 0.145 m
Mass of the object suspended from the spring, m = 0.233 kg
The spring constant of the spring is given by,
k = mg/x
k = 0.233 × 9.8/0.145
k = 15.74 N/m²
The angular frequency of the oscillation of the spring is given by,
ω = √(k/m)
ω = √(15.74/0.233)
ω = 8.21 rad/s
Amplitude of the horizontal oscillation of the spring, A = 0.192 m
Therefore, the maximum velocity of oscillation of the spring is given by,
v(max) = Aω
v(max) = 0.192 x 8.21
v(max) = 1.57 m/s
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Two batteries, A and B are connected in parallel, an 80 ohm resistor is connected across the battery terminals. The e.m.f and the internal resistance of battery A are 100 volts and 5 ohms respectively, and the corresponding values of battery B are 95 volts and 3 ohms respectively. Find the value and direction of the current on each battery and the terminal voltage.
5. Ametal block increases in temprature from 15°c to 60°c when supplied with 13500 joule of heat energy. a. Calculate the heat capacity of the metal. b. Calculate the specific heat capacity of the metal if this sample has a mass of 0.75kg.
The specific heat capacity of the substance is defined as the amount of heat energy supplied to the substance to increase the temperature of the substance by 1°C. The SI unit of specific heat is J/Kg.°C.
The heat energy, q = mC×ΔT, where m is the mass of the substance. C is the specific heat capacity of the material. ΔT is the change in temperature.
From the given,
a) heat supplied, q = 13500J
Initial temperature,T₁ = 15°C
Final temperature, T₂ = 60°C
Specific heat capacity, C=?
q = mCΔT
13500 = C(T₂ - T₁)
13500/(60-15) = C
13500/45 = C
C = 300 J/Kg.°C
Thus, the specific heat capacity is 300J/Kg.°C.
b) mass of the substance = 0.74kg
q = mCΔT
13500 = 0.75×C×(60-15)
13500/(0.75×45) = C
C = 400 J/Kg.°C
Thus, the specific heat capacity with heat energy of 13500 J is 400J/kg.°C.
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Can the sum of the magnitudes of two vectors ever be equal to the magnitude of the sum of the same two vectors? If no, why not? If yes when ?
Yes, the sum of magnitude of two vectors can be equal to the magnitude of sum of these two vectors.
What is the sum of two vectors?The sum of two vectors is determined by applying triangle law of vector addition or parallelogram law of vector addition.
The sum of magnitude of two vectors can be equal to the magnitude of sum of these two vectors when two vectors are colinear.
For example, let vector A = ax and vector B = dy
The sum of the two vectors is given as;
v = √ (a² + d²)
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Type the correct answer in the box. Spell all words correctly.
Mention the term
refers to having a generalized (and biased) belief about a particular group of people.
In social psychology, a stereotype is a generalized belief about a particular category of people.
What is stereotype ?A stereotype can be described as the accepted, condensed, and essentialist opinion with regards to certain population.
I should be nted hat his can be related to gender identity, race as well as ethnicity, country, however there are other things that an be used frequently used to stereotype groups. Stereotypes are pervasively present in both the larger social structure and culture.
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An object is placed at several different distances to the left of the lenses and mirrors (focal length = f). For each case, draw the 3 principal rays to locate the image and then (S.A.L.T.) [Size, Attitude, Location, Type] the image.
To determine the image characteristics using the 3 principal rays and SALTS (Size, Attitude, Location, Type), we'll consider both lenses and mirrors separately. Here's how you can analyze each case:
Lenses:
Place an object at different distances to the left of a lens with a focal length (f).
a) Object placed beyond 2f:
In this case, the object is placed far beyond twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens, between the focal point and twice the focal length.
SALTS:
Size: The image will be smaller than the object.
Attitude: The image will be inverted.
Location: The image will be located between the focal point and twice the focal length.
Type: The image will be real.
b) Object placed at 2f:
In this case, the object is placed at twice the focal length of the lens.
Principal ray 1: A ray parallel to the principal axis will pass through the focal point on the opposite side.
Principal ray 2: A ray passing through the optical center will continue in a straight line without any deviation.
Principal ray 3: A ray passing through the focal point on the object side will emerge parallel to the principal axis.
The image will be formed on the opposite side of the lens at twice the focal length.
SALTS:
Size: The image will be the same size as the object.
Attitude: The image will be inverted.
Location: The image will be located at twice the focal length.
Type: The image will be real.
c) Object placed between f and 2f:
In this case, the object is placed between the focal point and twice the focal length of the lens.
In this case, the object is placed far beyond twice the focal length of the mirror.
Principal ray 1: A ray parallel to the principal axis will reflect through the focal point on the same side.
Principal ray 2: A ray passing through the focal point on the object side will reflect parallel to the principal axis.
Principal ray 3: A ray passing through the center of curvature will reflect back along the same path.
The image will be formed on the opposite side of the mirror, between the focal point and twice the focal length.
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t is the relationship between the ping pong ball's release height and its bounce height, in this
timent? In your answer make sure to:
Restate the question and then Answer it by identifying a relationship shown in the data.
Cite three pieces of numerical evidence to fully show the relationship in the data.
Explain how each piece of evidence supports your claim. Be as specific as possible
Describe how the relationship in the data connects to the following concept:
"Potential energy can be converted into kinetic energy. Kinetic energy can also be
converted back into potential energy."
what is the voltage supplied to a wire that has a resistance of 1200 Q and a current of 0.10 amps
The voltage supplied to the wire is 120 volts.
To calculate the voltage supplied to a wire, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R). Mathematically, this relationship is expressed as V = I * R.
In this case, the wire has a resistance of 1200 Ω (ohms) and a current of 0.10 amps. We can substitute these values into the formula to find the voltage:
V = I * R
V = 0.10 A * 1200 Ω
V = 120 A * Ω
Therefore, the voltage supplied to the wire is 120 volts.
It's important to note that Ohm's Law holds true for resistors and other components in a circuit that obey Ohm's Law. In real-world scenarios, there may be other factors to consider, such as the presence of non-ohmic devices or components with varying resistance.
Additionally, in an AC (alternating current) circuit, the relationship between voltage, current, and resistance may involve complex quantities and phase differences. However, for a simple DC (direct current) circuit with a linear resistor, Ohm's Law provides an accurate relationship between voltage, current, and resistance.
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