1. What is the role of the battery in an electric circuit? a. Transformer b. Conductor c. Source d. switch​

Answer:

V2=809.44 mL

Explanation:

If ans is correct give a comment or ask for explanation with me .

Answer:

Ferromagnetism is a kind of magnetism that is associated with iron, cobalt, nickel, and some alloys or compounds containing one or more of these elements. It also occurs in gadolinium and a few other rare-earth elements.

Explanation:

Hope this helped Mark BRAINLIEST!!!

Answer: the answer is d

Explanation:

I got it right

Answer:

gravitational force remain constant

we have that from the Question, it can be said that  

What happens when an object is moved against gravity, such as rolling a toy car up is

From the Question we are told

What happens when an object is moved against gravity, such as rolling a toy car up

a. Potential energy does not change

b. Potential energy decreases as it is transformed into kinetic energy

c. Kinetic energy does not change

d. Kinetic energy is transformed into potential energy

Generally the equation for  Kinetic energy is mathematically given as

K.E=1/2mv^2

Generally the equation for  Potential energy is mathematically given as

P.E=mgh

Therefore

With increase in height of the car Kinetic energy is transformed into potential energy as g remains constant

Hence

What happens when an object is moved against gravity, such as rolling a toy car up is

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Answer:

35

Explanation:

angle of incidence equals angle of reflection

Answer:

6544.07 J

Explanation:

From the question given above, the following data were obtained:

Distance (d) = 15 m

Force (F) = 628 N

Angle (θ) = 46°

Workdone (Wd) =?

The work done can be obtained by using the following formula:

Wd = Fd × Cos θ

Wd = 628 × 15 × Cos 46

Wd = 9420 × 0.6947

Wd = 6544.07 J

Therefore, the workdone is 6544.07 J

Answer:

B

Explanation:

Answer:

When the image distance is positive, the image is on the same side of the mirror as the object, and it is real and inverted. When the image distance is negative, the image is behind the mirror, so the image is virtual and upright.

Explanation:

Answer:

1st: Radiation

2nd: Conduction

3rd: Convection

Explanation:

I actually learned this before in school. Yay

Answer:

дангггггггггггггггггггггггггггггггггггггггггггггг

Answer: D.

Explanation: I took the test

Answer:

1.heat is a form of 1.temperature is a form

energy that gives of energy that is used to

sensation of measure hotness or

warmth. or coldness of body.

2.its si unit is 2.its si unit is kelvin.

joule.

Answer:

In an electric field a charged particle, or charged object, experiences a force. If the forces acting on any object are unbalanced, it will cause the object to accelerate. With this in mind: If two objects with the same charge are brought towards each other the force produced will be repulsive, it will push them apart.

Explanation:

Answer:

Explanation:

F = -kΔx

Since the spring constant is given in N/m, we need to convert the stretch to meters as well.

12 cm = .12 m

Now we can solve the problem:]

F = -55(-.12) so

F = 6.6N

The force required to stretch the spring is 6.6 N

The force acting on a spring is given by:

Force (F) = spring constant (K) × Extention (e)

F = Ke

With the above formula, we can obtain the force required to stretch the spring as follow:

F = Ke

F = 55 × 0.12

F = 6.6 N

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Answer: The seismic waves are useful for the oil and gas exploration beneath the earth crust.

Explanation:

The seismic waves are sent beneath the earth crust to determine the location of fossil fuels like petrol, and natural gas. These seismic waves bound back and their pattern of reflection and refraction is recorded by using a receiver that is a geophone or can be a hydrophone (in water). The seismic waves bounce back indicating towards the reservoir of fossil fuel exhibit a characteristic pattern that can help in tracing the location of the fossil fuel.

Answer:

Two possibities: Increase in pressure or decrease in temperature.

Explanation:

There are two possibilities under the assumption that mass of the gas is conserved and, consquently, the amount of moles is also conserved, a reduction in the volume of the gas leads to an increase in pressure (Boyle's Law) and a decrease in temperature (Gay-Lussac's Law)

According to the equations of motion, the time taken to reach the ground is 5 seconds.

Using;

s = ut + 1/2gt^2

s = distance

u = initial velocity

t = time taken

g = acceleration due to gravity

Note that u = 0 m/s since the object was dropped from a height

Substituting values;

125 = 1/2 × 10  × t^2

125 = 5t^2

t^2 = 125/5

t^2 = 25

t = 5 secs

Velocity on reaching the ground is obtained from

v = u + gt

Where u = 0 m/s

v = gt

v = 10 × 5

v = 50 m/s

At half the time it takes to reach the ground;

s =  ut + 1/2gt^2

Where u = 0 m/s

s =  1/2gt^2

s = 1/2  × 10  × (2.5)^2

s = 31.25 m

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Answer:

(i) time taken by the ball to reach the

ground is 5 sec.

(ii) velocity of the ball on reaching the

ground is 50 m/s.

(iii) the height of the ball at half the time it

takes to reach the ground is 31.25 m.

Step-by-step explanation:

(i) time taken by the ball to reach the

ground

[tex]\longrightarrow{\sf{ \: \: s= ut + \dfrac{1}{2} a{(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: 125= 0 \times t + \dfrac{1}{2} \times 10 \times {(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: 125= 0 + \dfrac{10}{2} \times {(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: 125= 0 + 5\times {(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: 125= 5\times {(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = \dfrac{125}{5}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = \dfrac{ \cancel{125}}{\cancel{5}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = 25}}[/tex]

[tex]\longrightarrow{\sf{ \: \: t = \sqrt{25} }}[/tex]

[tex]\longrightarrow \: \: {\sf{\underline{\underline{\red{ t = 5 \: sec}}}}}[/tex]

Hence, the ball taken 5 sec to reach the ground.

[tex]\begin{gathered}\end{gathered}[/tex]

(ii) velocity of the ball on reaching the

ground

[tex]\longrightarrow{\sf{ \: \: {v}^{2} - {u}^{2} = 2as}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {v}^{2} - {0}^{2} = 2 \times 10 \times 125}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {v}^{2} = 20 \times 125}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {v}^{2} = 2500}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {v} = \sqrt{2500} }}[/tex]

[tex]\longrightarrow{\sf{ \: \: \underline{\underline{ \red{{v} = 50 \: m/s }}}}}[/tex]

Hence, the velocity of ball is 50 m/s.

[tex]\begin{gathered}\end{gathered}[/tex]

(iii) the height of the ball at half the time it

takes to reach the ground.

[tex]\longrightarrow{\sf{ \: \: s= ut + \dfrac{1}{2} a{(t)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= 0 \times \dfrac{5}{2} + \dfrac{1}{2} \times 10 \times { \left( \dfrac{5}{2} \right)}^2}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= 0 + \dfrac{10}{2} \times { \left( \dfrac{5}{2} \times \dfrac{5}{2} \right)}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times { \left( \dfrac{5 \times 5}{2 \times 2} \right)}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times { \left( \dfrac{25}{4} \right)}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times \dfrac{25}{4}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10 \times 25}{2 \times 4}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{250}{8}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: s= \dfrac{\cancel{250}}{\cancel{8}}}}[/tex]

[tex]\longrightarrow{\sf{ \: \: {\underline{\underline{\red{s= 31.25 \: m}}}}}}[/tex]

Hence, the height of the ball to reach the ground is 31.25 m.

[tex]\underline{\rule{220pt}{3.5pt}}[/tex]

Answer:

3m/s is the answer.

Explanation:

f = c/λ

f = frequency

c = speed (m/s)

λ = wavelength

f = c/λ

1.5 = c/2

c = 3m/s

Solution :

As the charge is stationary, hence

[tex]$F_m= qvB \sin \theta$[/tex]

[tex]$F_m=0$[/tex]

Hence, no torque at all.

When the charge is moving in positive x direction and the field will be in the negative y direction outside the bar, then :

[tex]$F = q(V \hat i \times B(- \hat j))$[/tex]

    [tex]$= -qV B (\hat i \times \hat j)$[/tex]

    [tex]$=qVB(- \hat k)$[/tex]

Hence, the force have direction [tex]$(- \hat k)$[/tex].

When instead of charge, an iron nail is used, then there will be induced magnetic field in the soft iron. The nature of the pole induced will be opposite near tot he bar. That is the north pole will be induced near the south pole and vice versa. That is why whichever be the pole of magnet closest to iron will be attracted by iron.

Answer:

this one is for your egg drop question

first question -

Use this worksheet to design your device and record your data. You can then use this form to help you  write your lab report.  

Height of egg drop: _5ft._

__________________________________________________________

Q2:

Ideas for Prototype Design

Teepee, large cube , small cube

__________________________________________________________

Q3:

Preliminary Sketches (attach separate paper if needed)

Option A: teepee

__________________________________________________________

Q4:

Advantages:                                           Disadvantages:  

● fully covered                  ● egg might crack

●  could stand higher distances    ●egg will most likely bounce around    around but not crack  but most likely to crack

__________________________________________________________

Q5:

Option B: large cube

Option C: smaller cube

__________________________________________________________

Q6:

more advantages and disadvantages

Advantages: Disadvantages:  

● egg will be tightly secured so nothing bounces around

●  egg might crack depending on the impact to the floor

__________________________________________________________

Q7:

Which of the three designs will you move forward with? Explain your reasoning for selecting this design.

I think i'm going to be moving forward with the teepee design

__________________________________________________________

Q8:

Building the Prototype  

What modifications, if any, did you make to the basic design during the construction process?

I made it a little smaller than the original design

__________________________________________________________

Q9:

Predictions  

Will your device cushion the egg? How will your device do this?

I think it will cushion the design if i put the plastic bag in with the egg it should prevent it from moving around to much

__________________________________________________________

Q10:

Will your device increase the time it takes for the egg to impact the ground? How will your device do this?

I think the extra weight added to the design might affect it by speeding up the process down to the floor

__________________________________________________________

Q11:

Observations  

Record your observations and the results of the experimental tests of your device below.

First i tried the egg without the plastic bag and it cracked so i made the design smaller and added the plastic bag this time

__________________________________________________________

Q12:

Evaluating Your Prototype  

What worked well? I would say definitely the plastic bag keeping the egg in place

__________________________________________________________

Q13:

Which features can be improved upon? The structure itself as in where the string and tape were

__________________________________________________________

Q14:

Suggestions  

How could the design of this device be improved? More balance i guess because the egg would move alot without the bag

__________________________________________________________

Q15:

Why would this change be an improvement? What force or momentum principle is this improvement  based on? If the egg had more balance then it would have a less chance of cracking i think this is a type of impulse toward the ground bc of the egg’s weight

__________________________________________________________

Q16:

Sketch of Final Design  

Draw a well-labeled sketch of the final design.

( i provided it :) )

okie peace!

Answer

slope

Explanation:

Answer:

The kinetic energy of the baseball is 306.25 joules.

Explanation:

SInce the baseball can be considered a particle, that is, that effects from geometry can be neglected, the kinetic energy ([tex]K[/tex]), in joules, is entirely translational, whose formula is:

[tex]K = \frac{1}{2}\cdot m\cdot v^{2}[/tex] (1)

Where:

[tex]m[/tex] - Mass, in kilograms.

[tex]v[/tex] - Speed, in meters per second.

If we know that [tex]m = 0.5\,kg[/tex] and [tex]v = 35\,\frac{m}{s}[/tex], then the kinetic energy of the baseball thrown by the player is:

[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex]

[tex]K = 306.25\,J[/tex]

The kinetic energy of the baseball is 306.25 joules.

Answer:

he word that musicians use for frequency is pitch. The shorter the wavelength, the higher the frequency, and the higher the pitch, of the sound. In other words, short waves sound high; long waves sound low. ... In other words, it sounds higher

Explanation:

Answer:

Part A

The power to turn on the lamp, ∑P = 3.36 W

Part B

The Resistor required is approximately 8.04 Ohms

Part C

The time for all the lights to go out is approximately 21.43 hours

Explanation:

The input voltage of the motor battery , V = 12 V

The capacity of the battery, Q = 6 Ah

The number of lamps in parallel = 8 lamps

The maximum voltage of each lamp,  = 3 V

The electric current in each lamp = 140 mA

The energy available in a battery, E = Q × V

For the battery, we have;

E = 6 Ah × 12 V = 72 Wh

The energy available in a battery, E = 72 Wh

Part A

The power used by the lamps, [tex]P_i[/tex] = [tex]I_i[/tex] × [tex]V_i[/tex]

∴ The total power used by the lamp, ∑P = 8 × 0.14 A × 3 V = 3.36 W

The power to turn on the lamp, ∑P = 3.36 W

Part B

The resistance required, is given as follows;

Resistor required = (Battery voltage - Lamp voltage)/(The sum of bulb current)

∴ Resistor required = (12 V - 3 V)/(8 × 0.14 A)

The Resistor required = 8.03571429 Ohms

The Resistor required ≈ 8.04 Ohms

Part C

The time for all the lights to go out = The time for the lamps to use all the power available in the battery

The time for all the lights to go out, t = E/∑P

∴ t = 72 Wh/(3.36 W) = 21.4285714 h

∴ The time for all the lights to go out, t ≈ 21.43 h

The time for all the lights to go out = The time for the lamps to use all the power available in the battery = t ≈ 21.43 h

∴ The time for all the lights to go out ≈ 21.43 hours.

Answer:223.46 MJ

Explanation:

Given

The thermal conductivity of brick wall is [tex]k=1.16\ W/m.^{\circ}C[/tex]

Cross-section of Wall [tex]A=5\m \times 7\ m[/tex]

time period [tex]t=17.2\ h=17.2\times 60\times 60=61,920\ s[/tex]

Inside temperature [tex]T_i=24^{\circ}C[/tex]

Outside temperature [tex]T_o=8^{\circ}C[/tex]

Heat transfer through the bricks

[tex]\dot{Q}=kA\dfrac{dT}{dx}[/tex]

[tex]\dot{Q}=1.16\times 35\times \dfrac{16}{0.18}\\\\\dot{Q}=3608.88\ W[/tex]

Heat flow for 17.2 h

[tex]Q=3608.88\times 61,920=223.46\ MJ[/tex]

Answer:

because they are underaged and prob dont care and also the gov thinks that the youth cant make a reasonable decision for them selves for sum like that and the media influnces them to by saying whats going on and who supports who

Answer:

26.02 ml

Explanation:

0.055(473.0) = 26.02 ml