Answer:
A) 4.95 m
B) 1.48225 m
Explanation:
Constant Acceleration Equations (SUVAT)
[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]
When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.
Consider the horizontal and vertical motion of the projectile separately.
Part AThe horizontal component of velocity is constant, as there is no acceleration horizontally.
Resolving horizontally, taking → as positive:
[tex]u=9.00\quad v=9.00 \quad a=0\quad t=0.550[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s & = \left(\dfrac{u+v}{2}\right)t:\\\\s&= \left(\dfrac{9+9}{2}\right)(0.550)\\s&= (9)(0.550)\\ \implies s&= 4.95\:\sf m\\\end{aligned}[/tex]
Part BAs the projectile is fired horizontally, the vertical component of its initial velocity is zero.
Acceleration due to gravity = 9.8 ms⁻²
Resolving vertically, taking ↓ as positive:
[tex]u=0\quad a=9.8\quad t=0.550[/tex]
[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\s&= (0)(0.550)+\dfrac{1}{2}(9.8)(0.550)^2\\s&= 0+(4.9)(0.3025)\\\implies s&= 1.48225\:\sf m\\\end{aligned}[/tex]
An atom of a _____________________ has two electrons in its outer level and will lose these when it combines with another atom.
a. alkali metal
b. noble gas
c. alkaline earth metal
d. halogen
Answer:
A alkali metals hope this helps
Answer: c. alkaline earth metal
Explanation: group II elements in the periodic table are generally found as 2+ ions. This is because they have lost two electrons to ionic bonding.
A car driver traveling 40 m/s slows down to a speed of 20 m/s in 10 seconds. What is the car’s acceleration?
The equation we use is to determine the acceleration of the car, it is a Uniformly Varied Rectilinear Motion (MRUV) is:
[tex]\boxed{\sf{a=\dfrac{V_{f}-V_{o}}{t}}} \ \ \ \ \ \sf{\longmapsto \ \ \ \ \ Where \ \ \ \ \begin{cases}\sf{V_{f} = Final \ velocity} \\ \sf{V_{o}=Initial \ velocity} \\ \sf{a=Acceleration} \\ \sf{t=Time} \end{cases}}[/tex]
We extract the data of the problem:
[tex]\sf{V_{f}=20 \ m/s}[/tex][tex]\sf{V_{o}=40 \ m/s}[/tex][tex]\sf{t=10 \ s}[/tex]We plug these values into the scalar equation above.
[tex]\sf{a=\dfrac{V_{f}-V_{o}}{t}}[/tex]
[tex]\sf{a=\dfrac{20 \ m/s-40m/s}{10 \ s} }[/tex]
[tex]\sf{a=\dfrac{-20 \ m/s}{10 \ s} }[/tex]
[tex]\boxed{\boxed{\boldsymbol{\sf{a=-2 \ m/s^{2} }}}}[/tex]
Rpta: The acceleration of the car was -2 m/s^2.
What is the volume of a rock with a density of 45 g/mL and a mass of 855 grams?
Your answer must have units
The volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml
We know that,
ρ = m / V
where,
ρ = Density
m = Mass
V = Volume
Given that,
ρ = 45 g / ml
m = 855 g
V = 855 / 45
V = 19 ml
Density is the measure of amount of molecules present in substance. It is denoted by ρ. Its unit is usually g / ml.
Therefore, the volume of the rock with a density of 45 g/mL and a mass of 855 grams is 19 ml
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Please help!Giving Brainliest
I need to turn this in by midnight
u = initial speed = 10 m/s
v = final speed = 14 m/s
Impulse is 2000 N/s
Given,
Mass of car = 500 kg
Force = 200 N
Acceleration = F/M
Acceleration = 0.4 m/s^2
Calculating the final speed,
u = initial speed = 10
v = final speed = ?
t = time of acceleration
v = u + at
v = 10 + (0.4 x 10)
v = 14m/s
Impulse = Ft = mv - uv
(200 x 10) = (500 x 14) - (500 x 10)
2000 = 7000 - 5000
2000 = 2000
Hence our answer is correct and the impulse is 2000 N/s.
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Draw an arrow to represent the friction force.
Answer:
See below
Explanation:
The force of friction is opposite to the force trying to move the block to the right....
A tennis ball is dropped from 1.67 m above the ground. It rebounds to a height of 0.898 m. With what velocity does it hit the ground? The acceleration of gravity is 9.8 m/s2 . (Let down be negative.) Answer in units of m/s.
Velocity of the ball by which it hits the ground is 5.721 m/s.
Height from which the ball has been thrown, s = 1.67m
Acceleration due to gravity, g = 9.81 m/s²
Since, velocity of the ball hitting the ground is being asked, rebound height can be ignored.
So according to the Third Equation of Motion which relates velocity, displacement and acceleration, we can find the velocity of the ball,
[tex]v^{2} = u^{2} + 2as[/tex]
u = initial velocity of the ball = 0 m/s
v² = 0 +2*(-9.8)*(-1.67)
v² = 32.732 m/s
[tex]v = \sqrt{32.732}[/tex] m/s
v = -5.721 m/s
Square root of velocity (v) will give two values, one as positive and the other as negative, and here negative value is considered because the velocity is towards the ground and downwards is taken here as negative.
Therefore the velocity of the ball hitting the ground will be 5.721 m/s.
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True or false-Consider an object that starts from rest and moves with constant acceleration. The plot of displacement versus time for such motion is a curved line while the plot of displacement versus time squared is a straight line.
Question 21 options:
True
False
Mary needs to row her boat across a 140 m-wide
river that is flowing to the east at a speed of
1.5 m/s. Mary can row with a speed of 4.0 m/s.
Answer:
2.5
Explanation:
you just subtract basic math
ighth grade F.1 Identify reactants and products MGX
This passage describes a chemical reaction. Read the passage. Then, answer the question
below.
The cheesemaking process sometimes includes a step called lactic acid fermentation.
This step occurs when a certain type of bacteria is added to milk. The bacteria form
lactic acid (C3H603) by combining water (H₂O) and lactose (C12H22011) in the milk.
When lactic acid forms, the milk's proteins clump into curds that can later be used to
make many types of cheese.
In the chemical reaction described in the passage, which of the following are reactants?
Select all that apply.
water (H₂O)
lactose (C12H22011)
Submit
lactic acid (C3H603)
00
HR
Q
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Stage
Get 5
in a
For identical metallic objects carry the following charges
The final charge on each object is -1.6μC.
Each metallic object has 10^13 electrons on it.
Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge. Unlike charges, they attract one another, while like charges repel one another.The charges are q1 = 1.6μC, q2 = 6.2μC, q3 =-4.8μC, and q4 =-9.4μC.When they are in contact with each other, then the net charge on the four metallic objects is q1 + q2 + q3 + q4 =-6.4μC The final charge on each object is (-6.4μC)/4 = -1.6μC The charge is negative. So it contains electrons. An electron has a charge of -1.6 * 10^(-19)C.The number of electrons on each object is calculated as (1.6*10^(-6)/(1.6*10^(-19)).The number of electrons on each object is 10^13.To learn more about charge, visit :
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3 important science skills
Answer: Inferring,Predicting,Analyzing
if this wasn't what you were looking for, here are some more science skills to help you pass you classes
- Evaluating.
- Generating possibilities.
- Formulating hypothesis.
- Communicating
Explanation: all these science skills will help you get through your science class with no struggles
Which wavelengths will a person be able to see?
760 nm
800 nm
510 nm
300 nm
Answer:
380 to 700 nanometers.
Explanation:
Pleaseee help me with this question?!!!!!!!!!!
In a road with speed limit of 30 miles per hour, how much time (in minutes) will you gain by driving at an average speed of 5 miles per hour over the speed limit if it would take 30 minutes to reach your destination driving at the posted speed limit?
You will gain 150 minutes by driving at an average speed of 5 miles per hour
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
How to determine the distance travelledWe'll begin by calculating the distance travelled. This can be obtained as follow:
Speed = 30 miles per hourTime = 30 minutes = 30 / 60 = 0.5 hourDistance =?Speed = Distance / time
Cross multiply
Distance = speed × time
Distance = 30 × 0.5
Distance = 15 miles
How to determine the time taken to travel at 5 miles per hourSpeed = 5 miles per hourDistance = 15 milesTime = ?Speed = distance / time
5 = 15 / time
Cross multiply
5 × time = 15
Divide both side by 5
Time = 15 / 5
Time = 3 hours
How to determine the time gainedTime for 30 miles per hour = 30 minutesTime for 5 miles per hour = 3 hours = 3 × 60 = 180 minutesTime gained =?Time gained = 180 - 30
Time gained = 150 minutes
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During a collision with a wall, the velocity of a ball mass 0.170kg changes from v1 = 23.1m/s toward the wall to v2 = 17.1m/s away from the wall. If the time the ball was in contact with the wall was t =0.0651s ,what was the magnitude of the average force applied to the ball?
The magnitude of the average force applied to the ball is 104.98 N
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed as
Momentum = mass × velocity
What is impulse?This is defined as the change in momentum of an object.
Impulse = change in momentum
Impulse = final moment – Initial momentum
But
Impulse = force × time
Therefore
Force × time = final moment – Initial momentum
Ft = m(v - u)
How to determine the forceMass (m) = 0.170 KgInitial velocity = 23.1 m/sFinal velocity = 17.1 m/sTime = 0.0651 sForce = ?Ft = m(v + u) (rebound )
Divide both sides by t
F = m(v + u) / t
F = [0.17 × (17.1 + 23.1)] / 0.0651
F = [0.17 × 40.2] / 0.0651
F = 6.834 / 0.0651
F = 104.98 N
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NEED HELP ASAP PLS
If a basketball player jumps and lands on the ground after 3.2 seconds with a final velocity of −5.5 m/s, what is the player’s initial velocity? Assume (a=−9.8 m/s2) (NOTE: Only 1 point if no work is shown)
The player’s initial velocity, given the data from the question is 15.68 m/s
How to determine the time to reach the maximum heightWe'll begin by obtaining the time taken for the player to reach the maximum height. This can be obtannnned as follow:
Time for the entire trip (T) = 3.2 sTime to reach maximum height (t) = ?T = 2t
3.2 = 2t
Divide both sides by 2
t = 3.2 / 2
t = 1.6 s
How to determine the initial velocity of the playerTime to reach maximum height (t) = 1.6 sAcceleration due to gravity (g) = -9.8 m/s²Final velocity (v) = 0 (at maximum height)Initial velocity (u) = ?v = u + gt
0 = u + (-9.8 × 1.6)
0 = u - 15.68
Collect like terms
u = 0 + 15.68
u = 15.68 m/s
Thus, the initial velocity of the player is 15.68 m/s
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a boat whose speed in still water is 1.80 m/s must cross a 285 wide river
The speed of the river current with respect to the boat is(Vₙ)= 1.036 m/s.
What is speed?Speed is a scalar quantity. Speed is a way of measuring how quickly something is moving or being done, or something moving fast.
How can we calculate the values of the speed of the river?To calculate the values of the speed of the river, we are using the formula,
v=1.768-Vₙ
The given parameters;
boat's speed , vₐ= 2.5 m/s
the river's width, w = 285 m
upstream distance , d = 118 m
the pilot's direction, θ = 45⁰
We know the velocity has the vertical and horizontal component, so we can calculate this ;
v(x)=vₐsinθ=2.5*sin45°=1.768m/s
v(y)=vₐcosθ=2.5*cos45°=1.768m/s
To calculate the time taken for the boat is ;
t=w/v(y)
Or, t=285/1.768
Or, t = 161.25 s
To calculate the total horizontal velocity of the boat and the river; we are using the formula,
v=1.768-Vₙ
Or,1.768-Vₙ=d/t
Or, 1.768-Vₙ=118/161.2
Or, 1.768-Vₙ=0.732
Or, Vₙ=1.036m/s
From the above calculation we can conclude that,
The speed of the river current with respect to the boat is 1.036 m/s.
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Note: The question is incomplete in the portal. Here is the total question,
Question: A boat, whose speed in still water is 2.50 m/s, must cross a 285-m wide river and arrive at a point 118m upstream from where it starts. To do so, the pilot must head the boat at a 45.0 degrees upstream angle. What is the speed of the rivers current?
As the coaster starts rolling down the hill, it has a height of 10 m and a velocity of 42 m/s. What is the total energy of the coaster at this point? (It has a mass of 1300 kg.)
The total energy of the coaster at that point is 1274000 J.
What is energy?Energy can be defined as the ability or the capacity for a body to perform work.
From the question, to calculate the total energy of the coaster at that point, we use the formula below.
Formula:
E = mgh+mv²/2........... Equation 1Where:
E = Total energy of the coaster at that point.m = Mass of the coasterh = Height of the coaster at that pointv = Velocity of the coaster at that pointg = acceleration due to gravity.From the question,
Given:
m = 1300 kgh = 10 mv = 42 m/sg = 9.8 m/s²Substitute the values above into equation 1
E = (1300×10×9.8)+(1300×42²/2)E = 127400+1146600E = 1274000 JHence, the total energy of the coaster at that point is 1274000 J.
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How is simple machine are more applicable than complex machine.
Answer:
Explanation:
A simple machine is the simplest device that performs work. A simple machine applies a single force to a single load and generally acts as a building block in developing more complex, compound machines. Simple machines usually fall into one of six categories, including: lever, wheel and axle, pulley, inclined plane, wedge and the screw.
I hope this helps you ")
1. A radiographic technique calls for a 2000 ms (time) exposure, What is
this time in s?
Answer:
2 s
Explanation:
2000 ms / 1000 ms/s = 2 s
Ignore air drag. Drop two balls, one big and one small. The big ball drops ___ the small ball.
A- the same speed as
B- slower than
C- faster than
D- sooner than
If the fuse in one of the houses can withstand a maximum current of 5 A at potential difference of 110 V, The maximum number of lamps that can be lighted at the same time without blow up of the fuse......
lamps
The maximum number of lamps that can be lighted at the same time without blow up of the fuse is 11.
The rate of performing labor is referred to as power. The amount of work (W) to the amount of time (T) is the ratio (t). Power(P)=Time(t) Work(W) In honor of physicist James Watt, the SI system of units uses the symbol W for power. Electric charge passes past a point in a circuit at a constant pace known as current. The rate at which an electric charge flows is defined as current. The potential difference in charge between two sites in an electrical field is known as voltage, also known as electromotive force.
Power= V*I
=110 *5
=550 watt
no. of lamps= 550/5
=11 lamps.
The maximum number of lamps that can be lighted at the same time without blow up of the fuse is 11.
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What subatomic particle is responsible for the observed properties of an atom?
Electrons are responsible for the properties of atoms.
What is an atom?The atom is the smallest particle of a substance that can take part in chemical reaction. We know that an atom is composed of smaller particles that are called subatomic particles. The basic subatomic particles are; electrons proton and neutrons.
The protons and the neutrons are bond up in the nucleus and do not contribute to the properties of the atom. The properties of the atom are due to loss or gain of electrons.
Thus electrons are responsible for the properties of atoms.
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A football is punted to its maximum height. As soon as it starts to fall to the ground it starts to gain kinetic energy. What happens to the potential energy of the football as it starts to gain kinetic energy?
From conservation of energy, the potential energy will begin to reduce as soon as it starts to fall to the ground to gain kinetic energy.
What is Conservation of Energy ?Conservation of energy state that energy can not be created nor destroyed but can only be transformed from one form to another.
Given that a football is punted to its maximum height. At this maximum height, the kinetic energy is zero while the potential energy is maximum.
As soon as it starts to fall to the ground it starts to gain kinetic energy. And what will happen to the potential energy of the football as it starts to gain kinetic energy is the reduction of the potential energy.
Therefore, the potential energy will begin to reduce as soon as it starts to fall to the ground to gain kinetic energy.
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How much work is done to lift a 5.36kg box off the ground 2.2m?
Answer:
Explanation:
Given:
m = 5.36 kg
h = 2.2 m
___________
A -?
Work:
A =m·g·h
A = 5.36·9.8·2.2 ≈ 116 J
A horizontal net force F is exerted on an object at rest. The object starts at x = 0 m and has a speed of 4.0 m/s after moving 4.0 m along a horizontal frictionless surface. The net force F as a function of the object's position x is shown below.
What is the mass of the object?
Answer: 15 kg
THIS IS THE QUESTION AND THE ANSWER! SEE ATTACHED.
A horizontal net force F is exerted on an object at rest and with a speed of 4.0 m/s. The object will be 5 kg in weight.
What is Force?An influence with the capacity to change the motion of an object is called a force. A force acting on an object with mass can cause it to accelerate or modify its velocity. Pushing or pulling is a simple way to explain the force.
According to the question, the given values are :
Initial Velocity, u = 0 at x = 0
Final Velocity, v = 4 m/s at x = 4 m
Work done=Area on graph
1/2 m(v²-u²) = 1/2 × base × height
m (4²-0²) = 4 × 20
m = 5 kg
Hence, the mass of the object will be 5 kg.
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The snell's law is also known as ________?
First law of reflection
Second law of accoutic
Second law of reflection
Second law of refraction
The Snell's law is also known as second law of refraction.
According to the Snell's law , the ratio of the sine of angle of incidence to the sine angle of refraction is equal to a constant of a light ray for two media . And it is given as,
[tex]\frac{sini}{sinr} = constant[/tex]
Where, [tex]sin i[/tex] is the angle of incidence light ray, [tex]sinr[/tex] is the angle of refracted light ray. Refractive index, also known as this constant and referred to as the second medium with respect to the first medium i.e. (₁μ₂) ,therefore the equation can be written as,
μ₁/μ₂ = ₁μ₂= [tex]\frac{sini}{sinr} = constant[/tex]
Refraction is a phenomena in which a light ray bends as it travels through one medium through another .
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What effect generates lift on a Flettner rotor?
Magnus effect generates lift on a Flettner rotor. It is named as Magnus effect, as it was first experimentally investigated by H G Magnus.
A Flettner rotor is a smooth cylinder with a disc plate at the end of it. The disc at the end is called as Thom disc. It optimses aerodynamic efficiency at the end of rotor. The rotor is rotated along its axis by the ship's engines. It is used in ships and airplanes. In ships it is mounted upright whereas in airplanes it is mounted sideways in place of wings.
As air strikes the rotating rotor at right angles to the axis of rotor, the ship moves in the direction perpendicular to both the rotation axis and air flow direction due to aerodynamic force created by Magnus effect.
Therefore, Magnus effect generates lift on a Flettner rotor.
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How much work is done when pushing a desk with a force of 28N across the distance of 1.7 meters?
The work done when pushing a desk is (W)= 47.6 Joules
What is work?When an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement that explains that the work done on a object.
How can we calculate the values of the work?To calculate the values of the work done we are using the formula,
W = F×d
Here, we are given,
F = Exerted Force =28N
d = Covered Distance in the desk =1.7m
We have to calculate,
W = Work done, unit in Nm or joules
Now we put the known values in the above equation, we get,
W = F×d
Or, W = (28N)×(1.7m)
Or, W = 47.6 Nm
Or, W = 47.6 Joules
Now we can say that,
The work done when pushing a desk is (W)= 47.6 Joules
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A rock is thrown vertically upwards at a velocity of 11 meters per second from an initial height of 1.5 meters.
Considering “up” to be the positive y direction, answer the following questions:
How high above the ground does the rock go?
How long does it take to get to the top of its travel?
What is the velocity of the rock half of a second after it is released?
What is the velocity of the rock 1.5 seconds after release?
The height above the ground reached by the rock is 7.7 m.
The time taken for the rock to travel half of a second after it is released is 1.12 seconds.
The velocity of the rock half of a second after it is released is 15.9 m/s.
The velocity of the rock 1.5 seconds after release is 25.7 m/s.
Height travelled by the rock
The vertical height traveled by the rock is calculated as follows;
h = u²/2g
h = (11²)/(2 x 9.8)
h = 6.2 m
Height above the ground reached by the rock = 1.5 m + 6.2 m = 7.7 m
Time of motion of the rockt = √2h/g
t = √(2 x 6.2/9.8)
t = 1.12 seconds
Velocity of the rock half a second after it was releasedv = u + gt
v = 11 m/s + (9.5 x 0.5)
v = 15.9 m/s
Velocity of the rock 1.5 seconds laterv = u + gt
v = 11 m/s + (9.5 x 1.5)
v = 25.7 m/s
Thus, the height above the ground reached by the rock is 7.7 m.
The time taken for the rock to travel half of a second after it is released is 1.12 seconds.
The velocity of the rock half of a second after it is released is 15.9 m/s.
The velocity of the rock 1.5 seconds after release is 25.7 m/s.
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The hammer is the closest of the three bones in the middle ear to the cochlea true or false
False. The hammer is not the closest of the three bones in the middle ear to the cochlea.
The three bones in the middle ear are Malleus, Incus and Stapes. Malleus is commonly known as Hammer, Incus as anvil and stapes as stirrup. Hammer is attached to the ear drum, Anvil is the chain of the bones and Stirrup is attached to the oval window.
Cochlea is a hollow, spiral shaped bone present in the inner ear. So the order of bones from outside to cochlea is Hammer first, followed by Anvil in the middle and Stirrup near the inner ear where cochlea is present.
Therefore, the hammer is not the closest of the three bones in the middle ear to the cochlea
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