2.
What can you infer by looking at the electromagnetic spectrum (see image)? please get it right :(

Answer:

its weight only option a.

Answer:

el plomo será el más largo

Explanation:

Dado que;

longitud inicial (l1) = 4m

Longitud final l2

aumento de temperatura (θ) = 10 ° C

Coeficiente de expansión lineal α

Ahora para el hierro;

α = 11,7 x 10-6

Desde;

l2-l / l1θ = α

l2 = α l1θ + l1

l2 = l1 (αθ + 1)

l2 = 4 ((11,7 x 10-6 * 10) + 1)

l2 = 4.00044 m

Para el plomo

l2 = 4 ((27,3 x 10-6 * 10) + 1)

l2 = 4,00109 m

Para cobre

l2 = 4 ((16,7 x 10-6 * 10) + 1)

l2 = 4.000668 m

Por lo tanto, el plomo será el más largo

Answer:

The weight of an object with mass M, in a place with gravitational acceleration G, is:

W = M*G

We know that in the moon, with G = 1.6 m/s^2, the weight is 160N

Then we have the equation:

160N = (1.6 m/s^2)*M

With this, we can find the mass of the astronaut.

(160N)/(1.6 m/s^2) = M = 100kg.

Then in the Earth, where the acceleration is G = 10 m/s^2, the weight will be:

W = (10m/s^2)*100kg = 1000 N

Answer:

1 the medium around the wire

Explanation:

pls mark brainliest it will be my first just pls

The medium surrounding a wire, like the insulating material, doesn't significantly impact resistance, as long as the wire's physical properties and temperature remain unchanged. The correct ans  is 1. the medium around a wire.

The option that does not change the resistance of a wire is:

The medium around a wire.

Resistance in a wire is primarily determined by its physical properties, such as length, cross-sectional area (thickness), and temperature.

The temperature of a wire affects its resistance. As temperature increases, resistance also tends to increase.

The length of a wire affects resistance; longer wires offer higher resistance than shorter wires, assuming all other factors remain constant.

The thickness of a wire affects resistance; thicker wires (larger cross-sectional area) offer lower resistance than thinner wires.

The medium around a wire (Option 1) does not change the resistance of the wire. The resistance of a wire depends on its material, length, and cross-sectional area (thickness), which are constant properties of the wire. The medium or environment surrounding the wire, such as air or vacuum, does not directly affect its resistance.

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Answer:

Distance = 56km Displacement = 30km

Explanation:

hope I helped

Answer: Don't worry I'm here to save u the answer is lithosphere (D) :D

Explanation: I have once done this question and got it right!

Answer:

-14.2m/s

Explanation:

Given parameters:

Initial velocity of the ball  = 25m/s

Time  = 4s

Unknown:

Final velocity of the ball  = ?

Solution:

To solve this problem, we use the expression below;

               v  = u - gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time

             v = 25  - (9.8 x 4)  = -14.2m/s

Answer:

A. overloading the muscles too often

Overtraining is overloading your muscles.

Overtraining refers to a process when a person continue to exercise despite that he has reach the limit of his ability and ignores the signs of and continues to train. Many believe they need to stress their muscles to be morefit and improve their performance.

Therefore, Overtraining is overloading your muscles.

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When a person carrying the opposite charge contacts the inner surface of the sphere, the charge jumps to the metal, causing a minor shock.

The charge present on the hollow sphere always remain on its outer surface, and there will be no charge on its interior surface. Because there is no charge on the interior surface of the sphere, touching it will not cause harm. When a person with the opposite sign of the same magnitude charge comes into touch with the sphere, both the sphere and the person are neutralized. It only causes a minor shock when there is difference in magnitude. If no one touches the sphere, the charge on the outside surface will be zero, while the charge on the inside surface will be positive.

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Answer:

8.79 J

Explanation:

Given that a slinky is traveling down the stairs, like in the video clip below. What is the total KINETIC ENERGY of the slinky at the bottom of the stairs (just before it stops moving) IF the Height of the stairs is 2 meters, the weight of the slinky is 4.41 Newtons, its spring constant is 0.84 N/m, and the distance the slinky is initially stretched (to get it going) is 0.25 meters??

Total energy = mgh

Total energy = 4.41 × 2 = 8.82 J

Elastic potential energy = 1/2 × Ke^2

Elastic potential energy = 1/2 × 0.84 × 0.25^2

Elastic potential energy = 0.02625

Also,

Total energy = P.E + K.E

Substitute them into the formula above

8.82 = 0.02625 + K.E

K.E = 8.82 - 0.02625

K.E = 8.79375

K.E = 8.79 J

Therefore, the KINETIC ENERGY of the slinky at the bottom of the stairs is 8.79 Joules approximately

Answer:

2.4m/s towards the bowling pins

Explanation:

Given parameters:

Mass of the ball  = 6.6kg

Momentum of the ball  = 15.9kgm/s

Unknown:

Speed of the ball  = ?

Solution:

The momentum is the amount of motion a body posses;

      Momentum = mas x velocity

Insert the parameters and solve;

      15.9  = 6.6 x velocity

        velocity  = 2.4m/s towards the bowling pins

Answer:

Explanation:

H

The opposing electric fields cancel each other out at the center of the ring, producing a result of zero. A is the correct response.

The physical field that surrounds electrically charged particles and pulls or attracts all other charged particles nearby is referred to as the "electric field." It also characterizes the surroundings of a system of charged particles physically.

Given that the ring has a radius of b and a uniformly distributed charge of q all around it, it is perfectly circular.

Given is the electric field that is experienced at the ring's center from opposing directions.

E1 = kₑq/b²

E2 = -kₑq/b²

At the middle, it is exposed to the two opposing electric fields E1 and E2. Thus, the electric field that results is given by:

E = E1 + E2

E = kₑq/b² - kₑq/b²

E = 0

At the center of the circular ring, the opposing electric fields cancel each other out and produce a result of zero.

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Answer:

Wow this I very simple actually, but its hard if you don't know how to do it like me

There would no longer be seasons if Earth's axis was perpendicular to the Sun because the variation in the seasons happens due to the tilt of the earth which results in unequal distribution of the sunlight on the earth's surface throughout the year.

Therefore the correct answer is option B.

The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude.

As given in the problem we have to find what happens if Earth's axis was perpendicular to the Sun,

If the Earth's axis were perpendicular to the Sun, there wouldn't be any seasons since the tilt of the planet causes an uneven distribution of sunlight on its surface throughout the year, which causes seasonal fluctuation.

Thus, the correct answer is option B.

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The proton number is the atomic number of the element, while the electron number is the atomic number minus the charge. A negatively-charged ion or anion has more electrons than protons. Again, the number of protons is the atomic number. The number of electrons is the atomic number added to the charge.

Answer:

well I mean it would depend on where u live for this question that's the only reason I am confused.. I'm pretty sure it's A thi

resultant force is produced by a vertical force of 60.0N and a horizontal force of 100N is [tex]20\sqrt{34}[/tex] N

force is produced by a vertical force of 60.0N

force is produced by a horizontal force of 100N

force.- A force is a push or pull of an object.

It is a vector quantity which having magnitude and direction also.

its unit is newton. denoted by capital N.

To find out the resultant of force

R² = ( (60)² + (100)²

R= √(3600 + 10000)

R =[tex]\sqrt{13600}[/tex]  N

[tex]R = 20\sqrt[]{34} N[/tex]

resultant force is produced by a vertical force of 60.0N and a horizontal force of 100N is [tex]20\sqrt{34}[/tex]N  

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Answer: It is C

Explanation: A disturbance that transfers energy from one place to another, without transferring matter! I just finished that unit! I hope you find this helpful and your welcome!

Answer:

That is when your fingers are bent in a weird way and are distorted...

Explanation:

Answer:

The answer is Watt

Explanation:

Electricity is measured in Watts and kilowatts

Electricity is measured in units of power called Watts, named to honor James Watt, the inventor of the steam engine. A Watt is the unit of electrical power equal to one ampere under the pressure of one volt. One Watt is a small amount of power.

Answer:

1g/cm³ or 1000kg/m³ at 4°C

Answer:

Erosion

Explanation:

Sedimentary rocks are created from the build up of sediments, such sediments can be found in stuff like soil, other rocks and many more. Erosion is involved in these type of rocks because the byproduct of erosion are sediments.

Answer:

Rivers... and Windstorms....

Explanation:

I just did it a p e x

Answer:

C. 211.5 N

Explanation:

We included a free body diagram representation of the concrete block. The equation of equilibrium in the x-direction:

[tex]\Sigma F_{x} = P\cdot \cos \alpha -\mu_{k}\cdot N = m\cdot a[/tex] (1)

[tex]\Sigma F_{y} = N + P\cdot \sin \alpha -m\cdot g = 0[/tex] (2)

Where:

[tex]P[/tex] - External force exerted on the block, measured in newtons.

[tex]N[/tex] - Normal force from the ground to the block, measured in newtons.

[tex]\alpha[/tex] - Direction of the external force, measured in sexagesimal degrees.

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.

[tex]m[/tex] - Mass of the concrete block, measured in kilograms.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]a[/tex] - Net acceleration of the concrete block, measured in meters per square second.

The minimum force to move block occurs when net force is zero, from (2) we get that the normal force is:

[tex]N = m\cdot g -P\cdot \sin \alpha[/tex]

And by applying this formula in (1), we get that the external force is:

[tex]P\cdot \cos \alpha - \mu_{k}\cdot (m\cdot g -P\cdot \sin \alpha) = m\cdot a[/tex]

[tex]P\cdot \cos \alpha -\mu_{k}\cdot m\cdot g +\mu_{k}\cdot P\cdot \sin \alpha = 0[/tex]

[tex]P\cdot (\cos \alpha +\mu_{k}\cdot \sin \alpha)=\mu_{k}\cdot m\cdot g[/tex]

[tex]P = \frac{\mu_{k}\cdot m\cdot g}{\cos \alpha +\mu_{k}\cdot \sin \alpha}[/tex]

If we know that [tex]\mu_{k} = 0.75[/tex], [tex]m = 35\,kg[/tex], [tex]g = 10\,\frac{m}{s^{2}}[/tex] and [tex]\alpha = 30^{\circ}[/tex]. then the external force is:

[tex]P = \frac{(0.75)\cdot (35\,kg)\cdot \left(10\,\frac{m}{s} \right)}{\cos 30^{\circ}+0.75\cdot \sin 30^{\circ}}[/tex]

[tex]P \approx 211.518\,N[/tex]

The correct answer is C.

The intensity that results if the frequency is increased to 2.50 kHz while a constant displacement amplitude is maintained is 3.74 W/m².

The power carried by sound waves per unit area in a direction perpendicular to that region is known as sound intensity or acoustic intensity. The watt per square meter (W/m2) is the SI unit of intensity, which also covers sound intensity. One use for this technology is to measure the amount of sound energy present in the air near a listener. Sound pressure and sound intensity are two different physical quantities. Sound pressure, which is correlated with sound intensity, is sensitive to human hearing. While level disparities are referred to as "intensity" differences in consumer audio electronics, sound intensity is a precisely defined quantity that cannot be detected by a straightforward microphone.

I = 2π2ρf2v∆s

Given:

Frequency, [tex]f_{1}=1\;kHz[/tex]

Increased frequency, [tex]f_{2}=2.50\;kHz[/tex]

Intensity at first, [tex]I_{1}=0.6\;W/m^{2}[/tex]

We know that,

[tex]I \propto f^{2}\;A^{2}[/tex]

Here, constant displacement amplitude is maintained,

[tex]A_{1}= A_{2} =A[/tex]

Therefore,

[tex](\frac{I_{2} }{I_{1} } ) = (\frac{f_{2} }{f_{1} } )^{2} \;(\frac{A }{A })^{2}[/tex]

Substitute the known values in the above equation,

[tex](\frac{I_{2} }{0.65} ) = (\frac{2.4}{1} )^{2}[/tex]

By solving the above equation, we get

[tex]I_{2}=3.74\;W/m^{2}[/tex]

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Answer:

magnet, gravity

Explanation: