23. MATHEMATICAL CONNECTIONS Two lines are cut by
a transversal. Is it possible for all eight angles formed
to have the same measure? Explain your reasoning.

The slope of the line which passes through the points (4, 18) and (6x, 2k) is (k - 9)/(3x - 2).

According to the given question.

A line passes through points (4, 18) and (6x,2k).

Which means we have two points (4, 18) and (6x,2k).

As we know that, the slope of a line is the ratio of the amount that y increases as x increases some amount.And the slope formula is m=(y2-y1)/(x2-x1) if a lines passes through the point (x2, y2) and (x1, y1).

Therefore, the slope of the line which passes through the points (4, 18) and (6x,2k)

= 2k - 18/ 6x - 4

= 2[k - 9]/2[3x - 2]

= (k-9)/(3x - 2)

Hence, the slope of the line which passes through the points (4, 18) and (6x, 2k) is (k - 9)/(3x - 2).

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Answer:

D.MSN

Step-by-step explanation:

Supplementary angles complete each other to 180° and they are on a straight line.

We are asked to find the supplementary angle to angle LSM on figure 2.

Amongst given options we see angle LSM and angle MSN make a straight line therefore they are supplementary angles.

Using a linear function, one constraint on the inequality is given by:

y < -0.5x.

A linear function is modeled by:

y = mx + b

In which:

Given two points, the slope is given by change in y divided by change in x.

For the line in the inequality, the points are:

(-2,1) and (0,0).

Hence the slope is given by:

m = (0 - 1)/(0 - (-2)) = -1/2 = -0.5.

Hence:

y = -0.5x + b.

When x = 0, y = 0, meaning that the y-intercept is of b = 0, and:

y = -0.5x.

Everything below the line is shaded, meaning that the values of y that are less than the line are shaded, and the inequality is:

y < -0.5x.

The inequality is only less, not less or equal, because the line is dashed and not solid.

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The first term of the Geometric Series = 3 and its common ratio = 3/2.

An unlimited number of terms with a fixed ratio between each term make up a geometric series.

For 'n' termed GP with a = first term and r = common ratio, [tex]S_{n}=\frac{a(r^{n}-1)}{r-1}[/tex]

Given:

To find: First term of the GP and the common ratio.

Finding:

As, [tex]S_{n}=\frac{a(r^{n}-1)}{r-1}[/tex], for n =3,

[tex]S_{3}=\frac{a(r^{3}-1)}{r-1}=14.25[/tex] (eqn 1)

=> Similarly for n = 4,

[tex]S_{4}=\frac{a(r^{4}-1)}{r-1} = 24.375[/tex]

On dividing [tex]S_3 by S_4[/tex], we get:

[tex]\frac{14.25}{24.375}=\frac{r^{3}-1}{r^{4}-1}[/tex]

=> On solving the equations, we get:

[tex]14.25r^{4}-24.375r^{3}+10.125=0[/tex]

r = 3/2 (on factorizing the equation)

Now, substituting this in eqn 1

=> [tex]14.25=\frac{a((\frac{3}{2})^{2}-1)}{\frac{3}{2}-1}[/tex]

=> a = 3 on further solving the equation for a.

Hence, the first term of the Geometric Series = 3 and its common ratio = 3/2.

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Answer:

51.3

Step-by-step explanation:

[tex]\tan y=10/8 \\ \\ y=\arctan(10/8) \\ \\ \approx 51.3^{\circ}[/tex]

Answer:

45

Step-by-step explanation:

Original sides of the square before reducing was 11 inches.

A quadratic equation has highest degree of two and it has 2 roots.

According to the given question Miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album.

Assuming sides of the square to be x inches.

∴ From the given data

( x - 3 )( x - 3 ) = 64         ( area of a square is product any two sides )

x² - 6x + 9 = 64

x² - 6x - 55 = 0

x² - 11x + 5x - 55 = 0

x( x - 11 ) + 5( x-11 ) = 0

(x - 11 )( x + 5) = 0

∴ x = 11 or x = -5.                  ( length of something can not be negative )

So, the original length of the sides of the square is 11 inches.

Original area is

= (11×11)

= 121 sq inches.

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The roots of the equation [tex]x^{2}[/tex]-3x-3=0 by completing the square method are 3.79 and -0.79.

Given that the equation is [tex]x^{2}[/tex]-3x-3=0.

We are required to find the roots of the equation by completing the square method.

Equation is basically the relationship between two or more variables that are expressed in equal to form. It may be linear equation, quadratic equation,cubic equation and many more depending on the power of the variables that are present in the equation.

The equation is  [tex]x^{2}[/tex]-3x-3=0.

[tex]x^{2}[/tex]-3x=3

[tex](x+3/2)^{2}[/tex]=-(c-[tex]b^{2}[/tex]/4)

So,

[tex](x-3/2)^{2}[/tex]=-[-3-[tex](-3)^{2}[/tex]/4]

[tex](x-3/2)^{2}[/tex]=-[-3-9/4]

[tex](x-3/2)^{2}[/tex]=21/4

x-3/2=±[tex]\sqrt{21}[/tex]/2

x=([tex]\sqrt{21}[/tex]+3)/2,(-[tex]\sqrt{21}[/tex]+3)/2

x=(4.58+3)/2, (-4.58+3)/2

x=7.58/2, -1.58/2

x=3.79,-0.79

Hence the roots of the equation [tex]x^{2}[/tex]-3x-3=0 by completing the square method are 3.79 and -0.79.

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Answer:

by completing the square method the answer is 3.79 and -0.79.

Step-by-step explanation:

above

The four factors were used to create this Product Game board are  {2, 3, 5, 7} and the product missing from the grid is 25

To see what are factors are used in the given list, we just need to write each of the numbers, as a product of prime factors such as 2, 3, 5, 7 .

9 = 3* 3

15 = 3 *5

18 = 3 *2*3

21 = 7*3

30 = 5*3*2

35 = 7*5

36 = 3*3*2*2

42 = 2*3*7

49 = 7*7

As we can see, the 4 factors used to product the numbers in the given list are {2, 3, 5, 7}

for the second part that is to find the missing number between 21 and thirty we first need to write all the numbers between 21 and thirty and check which number is having the only factors of at least one of (2,3,5,7)

the numbers are 22 , 23 ,24, 25 ,26 ,27 ,28, 29

After checking the missing number is 25(5*5) because there has to be at least 4 products who have same factor and 5 is the factor who has appeared only three times

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Answer:

a geometric model shows the lay out of places like earth it tells us where our best water sources are.

endpoint y would be

(7,-4)

because when you graph all 3 points

(7,-4) adds nicely to the line that the other 2 make

Answer:

x>-3

Step-by-step explanation:

collect like terms by changing the signs ..

x+4>-3x-8:to: x+3x>-8-4

Hence find the value of x

:4x>-12

4x/4 >-12/4

x>-4

Answer: w can be 1,2,4,5

Step-by-step explanation:

Let's recap the formula of Area:
Area = width x length = w x l
Area = 40 = w x l

The definition of a whole number: is a number without fractions; an integer such as 0, 1, 2, 3, 4, 5, 6,...

Let's start with 0. 0 times anything is equal to 0, so we cannot make 40 out of zero. Cross this out.

Next, let's try with 1:

a. 1x40 = 40

Then, applying the same concept to the rest we have these multiplications:

b. 2x20 = 40

c. 4x10 = 40

d. 5x8 = 40

e. 8x5 = 40

f. 10x4 = 40

g. 20x2 = 40

h. 40x1 = 40

Let's recap the formula of Perimeter:

P = 2 x (w + l)

So, we have the calculated perimeters (according to the above finding):
a. P= 2x(1+40)=82

b. P= 2x(2+20)=44

c. P= 2x(4+10)=28

d. P= 2x(5+8)=26

The below answers do not fit the [width < length]

e. P= 2x(8+5)=26 [not an answer]

f. P= 2x(10+4)=28 [not an answer]

g. P= 2x(20+2)=44 [not an answer]

h. P= 2x(40+1)=82 [not an answer]

The perimeter of a polygon is 24 units.

In this question, we have been given the coordinates of a polygon.

we need to find the perimeter of a polygon.

Let A= (-3,2), B = (2,2), C = (2,-4), D = (-1,-4), E = (-1,-2), F = (-3,-2)

First we find the length of each side of a polygon.

|AB| = √5² + 0²

|AB| = 5

|BC| = √0² + (-6)²

|BC| = 6

|CD| = √(-3)²+0²

|CD| = 3

|DE| = √0²+2²

|DE| =  2

|EF| = √(-2)²+0²

|EF| = 2

|FA| = √0²+4²

|FA| = 4

The perimeter of a polygon would be,

P = AB + BC + CD + DE + EF + FA

P = 5 + 6 + 3 + 2 + 2 + 4

P = 24 units

Therefore, the perimeter of a polygon is 24 units.

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Answer:

$37.50

Step-by-step explanation:

Answer:

Step-by-step explanation:

-2x^6-9

please give me the brainliest

Answer:

I think it's B (or A?)

Step-by-step explanation:

For alternate interior, they are alternate interior angles

Then for 2, they are equal and congruent, but they are SUBSTITITUING the angle numbers to the equation.

pls brainliest if I'm right :D

Answer:

2 - 5 = -3.

Step-by-step explanation:

I subtracted two from five and got negative three lol

Answer:

He returns the pedalo after 3.00 pm

The equation of the line in fully simplified slope-intercept form is y = -x - 8.

It is assumed that a line in the graph will pass through some points on the x and y-axes.

We must determine the line's fully simplified intercept.

we know the standard form of a line that is

y = mx + b

here, m is a slope and b is the constant

On the graph, there are the y-intercept (0,-8) and the x-intercept (-8,0).

The slope of the line passing through these points is:

[tex]slope = \frac{y2 - y1}{x2 - x1} \\ [/tex]

[tex]slope = \frac{ 8 - 0}{ 0 - 8} [/tex]

slope = 8/(-8)

slope = -1

then find the value of b

if x = 0 y = -8 then

y = mx +b

-8 = -1(0) + b

-8 = b

the value of b is -8

After inserting the values for m and c, the line's equation will be.

y = - x - 8

Hence y = -x - 8 is the equation of the line in fully simplified slope-intercept form.

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Answer:

19

Step-by-step explanation:

When y = 7

Replace 7 with y.

[tex]7 + 12 = 19[/tex]

If this answer helped you, give this answer a heart, rate it and if you could then please mark it brainliest. Thanks!

Answer:

(3, - 1 )

Step-by-step explanation:

given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex] , [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

here (x₁, y₁ ) = R (4, - 5 ) and (x₂, y₂ ) = D (2, 3 )

midpoint = ( [tex]\frac{4+2}{2}[/tex] , [tex]\frac{-5+3}{2}[/tex] ) = ( [tex]\frac{6}{2}[/tex] , [tex]\frac{-2}{2}[/tex] ) = (3, - 1 )

The number of hours Melody worked this week was 15.

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Simple Interest is the method of finding the interest amount for a particular principal amount of money at a particular rate of interest.

The simple interest for $900 at an interest rate of 6% is $108.

Simple Interest is the method of finding the interest amount for a particular principal amount of money at a particular rate of interest.

We have,

Principal = $900

Rate of interest = 6%

Time = 2 years.

Remember that time should always be in years.

The formula for simple interest is given by:

SI = PRT / 100

Where,

P = principal

R = rate of interest

T = Number of years

So,

SI = 900 x 6 x 2 / 100

SI = $108

Thus the simple interest for $900 at an interest rate of 6% is $108.

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Answer:

1.) like terms and 2.) since all you did was combine like terms you didn't change the value, it's the same as before just "fixed" so yes

Answer:

listen there is a lack of information the information you give isn't enough

The correct answer is Team B won by 1.1 points.

To determine which team won the competition, we need to calculate the final scores for both Team A and Team B based on the given weights for each category and the points they received in each category.

For Team A:

- Time to complete (75% of 15 points) = 0.75 * 15 = 11.25 points

- Design (15% of 9 points) = 0.15 * 9 = 1.35 points

- Total cost (10% of 14 points) = 0.10 * 14 = 1.4 points

Total score for Team A = 11.25 + 1.35 + 1.4 = 14 points

For Team B:

- Time to complete (75% of 17 points) = 0.75 * 17 = 12.75 points

- Design (15% of 7 points) = 0.15 * 7 = 1.05 points

- Total cost (10% of 13 points) = 0.10 * 13 = 1.3 points

Total score for Team B = 12.75 + 1.05 + 1.3 = 15.1 points

Now, we compare the total scores of both teams. Team A has a total score of 14 points, while Team B has a total score of 15.1 points. Therefore, Team B won by 1.1 points.

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Answer:

[tex]|4x+3|+7 < 10[/tex]

Step-by-step explanation:

When you evaluate the expression, you get [tex]-\frac{3}{2} < x < 0[/tex]

The Area of the given figure in the radical form is [tex]96\sqrt[4]{x^{9} }[/tex] .

Area of a rectangle can be found by using the formula

Area = length*breadth

in the given question

length of the rectangle

= [tex](4x)^{\frac{3}{2} }[/tex]

On simplifying we get

[tex](4x)^{\frac{3}{2} }=(2^{2} x)^{\frac{3}{2} }\\ \\ =2^{2*\frac{3}{2} } *x^{\frac{3}{2} } }[/tex]      ( as (a.b)ⁿ=aⁿ.bⁿ  )

[tex]=2^{3} *x^{\frac{3}{2} } }\\ \\ =8*x^{\frac{3}{2} } }[/tex]

breadth of the rectangle = [tex]12x^{\frac{3}{4} }[/tex]

The required area = length * breadth

Substituting the values we get

Area = [tex]8*x^{\frac{3}{2} } }[/tex] * [tex]12x^{\frac{3}{4} }[/tex]

=96*[tex]x^{\frac{3}{2}+\frac{3}{4} }[/tex]

taking LCM of exponents as 4 and solving further we get ,

=[tex]96x^{\frac{9}{4} }[/tex]

Expressing in  radical form we get ,

Area = [tex]96\sqrt[4]{x^{9} }[/tex]

Therefore ,  the Area of the figure in the radical form is [tex]96\sqrt[4]{x^{9} }[/tex] .

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