Answer:
2 times some thing and plus 3 equals -7
Step-by-step explanation:
x = -5
One number is 11 less than the other number. If their sum is increased by 8, the result is 71. Find the numbers.
First number = [tex]x[/tex]
Second number = [tex]x-11[/tex]
[tex]x+x-11+8=71[/tex]
[tex]2x-3=71[/tex]
[tex]2x=71+3[/tex]
[tex]2x=74[/tex]
[tex]x=37[/tex]
First number = [tex]x=37[/tex]
Second number = [tex]x-11=37-11=26[/tex]
Consider two unique parallel lines. What aspects of
these two lines are the same? What aspects of these two
lines would have to be different? Explain your reasoning.
Answer:
The slope of two parallel lines will always be the same. If the slope was slightly different, then the lines would intersect at some point, which breaks the definition of parallel lines.
The y-intercepts of two parallel lines have to be different, or else the two lines would be the same line. If the y-intercept and the slope are the same, then the lines will essentially equal each other.
Answer:
Sample Response: Two parallel lines will have the same slope. The slopes of parallel lines have to be equal. The y-intercepts of those two lines have to be different, otherwise they would be the same line. The x-intercepts of the parallel lines would also be different.
Step-by-step explanation:
edge 2020
What is simplified form of the fifth square root of x times the fifth square root of x times the fifth square root of x times the fifth square root of x
Answer: This was a bit hard to understand, x times the 5th root of x
Step-by-step explanation:
When you multiply square roots of the same root and inside value, they essentially get rid of the square roots. So the first two terms boil down to just x. Then multiply x by the 5th root of x to get:
[tex]x\sqrt[5]{x}[/tex]
Answer:
[tex]x[/tex]
Step-by-step explanation:
Apply exponent rules.
[tex]\sqrt{x} =x^\frac{1}{2}\\\:a^b\times \:a^c=a^{b+c}[/tex]
[tex]\sqrt[5]{x} \times\sqrt[5]{x} \times\sqrt[5]{x} \times\sqrt[5]{x} \times\sqrt[5]{x}[/tex]
[tex]x^{\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}+\frac{1}{5}}[/tex]
[tex]x^1[/tex]
Write the equation of the line shown in the graph above in slope-intercept form. Question 3 options: A) y = –2∕3x + 1 B) y = –x + 2∕3 C) 2x + 3y = 3 D) y = 2∕3x + 1
Answer:
A) y = -2/3x + 1
Step-by-step explanation:
Slope - intercept form is y = mx + b, where m is the slope and b is the y - intercept.
The line is falling from left to right, so it has a negative slope.
y = -mx + b
The line has a slope of -2/3.
y = -2/3x + b
The line has a y - intercept of 1.
y = -2/3x + 1
I hope this helps :)
A) y = -2/3x + 1, the equation of the line shown in the graph above in slope-intercept form.
What is a straight line?A straight line is an endless one-dimensional figure that has no width. It is a combination of endless points joined both sides of a point and has no curve.
here, we have,
Slope - intercept form is y = mx + b,
where m is the slope and b is the y - intercept.
The line is falling from left to right, so it has a negative slope.
y = -mx + b
As, the line passes through (0,1) and (1.5,0)
The line has a slope of -2/3.
y = -2/3x + b
The line has a y - intercept of 1.
y = -2/3x + 1
hence, A) y = -2/3x + 1, the equation of the line shown in the graph above in slope-intercept form.
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Determine the magnitude of the resultant force by adding the rectangular components of the three forces.
a) R = 29.7 N
b) R = 54.2 N
c) R = 90.8 N
d) R = 24.0 N
PLEASE HELP IM STUCK ON A PROBLEM....
Answer:
Number line A.
Step-by-step explanation:
|-5x| - 11 = -1
Add 11 to both sides.
|-5x| = 10
-5x = 10 or -5x = -10
x = -2 or x = 2
Answer: Number line A.
Concur Technologies Inc is a large expense-management company located in Redmond Washington. The wall street Journal asked Concur to examine the data from 8.3 million expense reports to provide insights regarding business travel expenses. Their analysis of the data showed that New York was the most expensive city with an avg daily hotel room rate of $198 and an avg amount speny on entertainment, including group meals and tickets for shows sports and other events of $172 in comparison the U.S averages for these two categories were $89 for the room rate and $99 for entertainment the following table shows the average daily hotel room rate and the amount spent on the entertainment for a sample of 9 of the 25 most visited U.S cities Room Rate EntertainmentCity ($) ($)Boston 148 161Denver 96 105Nashville 91 101New orleans 110 142Phoenix 90 100San Diego 102 120San Francisco 136 167San Jose 90 140Tampa 82 98 develop a scatter diagram for these data with the room rate as the independent variablewhat does the scatter diagram developed in part (a.) indicate about the relationship between the two variablesdevelop the least squares estimated regression equationprovide an interpretation for the slope of the estimated regression equationthe avg room rate in Chicago is $128 considerably higher than the U.S avg predict the entertainment expense per day in Chicago
Answer:
Step-by-step explanation:
Hello!
Given the variables
X: daily hotel room rate
Y: amount spent on the entertainment
See second attachment for scatter plot.
The population regression equation is E(Yi)= α + βXi
To estimate the y-intercept and the slope of the regression equation you have to apply the following formulas:
[tex]b= \frac{sum XY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} }[/tex]
a= Y[bar]-bX[bar]
n= 9; ∑X= 945; ∑X²= 103325; ∑Y= 1134 ∑Y²= 148804; ∑XY= 123307
X[bar]= ∑X/n= 945/9= 105
Y[bar]= ∑Y/n= 1134/9= 126
[tex]b= \frac{123307-\frac{945*1134}{9} }{103325-\frac{(945)^2}{9} }= 1.03[/tex]
a= 126 - 1.03*105= 17.49
^Y= 17.49 + 1.03Xi
Slope interpretation: The estimated average amount spent on entertainment increases 1.03 every time the daily hotel room rate increases one unit.
If the room rate for Chicago is $128 (X), to predict the mount spent in entertainment (Y) you have replace it in the estimated regression line:
^Y= 17.49 + 1.03Xi= 17.49 + 1.03*128= 149.33
The expected amount spent on entertainment for Chicago is $149.33
I hope this helps!
Determine whether the geometric series 192 + 48 + 12 + ... converges or diverges, and identify the sum if it exists.
A.) Converges: 768
B.) Diverges
C.) Converges; 64
D.) Converges; 256
Answer:
D.) Converges; 256
Step-by-step explanation:
x0= 192
x1 = 48 = 192/4
x2 = 12 = 192/(4 x 4)
Therefore, this series can be written as:
[tex]x_n = \frac{192}{4^n}[/tex]
Applying limits at infinity:
[tex]\lim_{n \to \infty} x_n= \lim_{n \to \infty} (\frac{192}{4^n}) = \frac{192}{\infty}=0[/tex]
Since the terms of the series tend to zero, we can affirm that the series converges.
The sum of an infinite converging series is:
[tex]S=\frac{x_0}{1-r} \\S=\frac{192}{1-\frac{1}{4} }\\S=256[/tex]
Thus, the answer is D.) Converges; 256
16. Convert 55° to radians.
Answer:
0.96 radians
Step-by-step explanation:
Formula
1° = [tex]\frac{\pi }{180}[/tex] radians
Multiplying both sides by 55, It becomes
55° = [tex](\frac{\pi }{180} )*55[/tex]
55° = [tex]\frac{55\pi }{180}[/tex]
= 172.8/180
= 0.96 radians
Question 7 (5 points)
Which of the following is the simplified fraction that's equivalent to 0.3
OA) 35/999
OB) 31/99
C) 105
7333
OD) 35
D) 35/111
Answer: B. although none are exactly 0.3 B is closest
Step-by-step explanation:
a. 35/999 = .0350
b. 31/99 = .3153
c. 105/7333 = .0143
d. 35/111 = .3135
Deepak is a landscaper who charges $30 for each job he does plus an additional $15 for each hour he works. He only accepts jobs if he will earn at least $90 the job. He writes this inequality to determine x, the number of hours he must work during each job in order to accomplish this.
30 + 15 x greater-than-or-equal-to 90
Which best describes the restrictions on the jobs Deepak will accept?
He only accepts jobs that last 4 or more hours.
He only accepts jobs that last 5 or more hours.
He only accepts jobs that last 8 or more hours.
He only accepts jobs that last 9 or more hours.
Hey there! I'm happy to help!
The only thing we have to do is solve our inequality to find the answer!
30+15x ≥ 90
We subtract 30 from both sides.
15x ≥ 60
Finally, we divide both sides by four.
x ≥ 4
Therefore, Deepak can only accept jobs that last 4 or more hours.
I hope that this helps! Have a wonderful day!
The solution for the inequality is x≥4. Therefore, option A is the correct answer.
Given that, Deepak is a landscaper who charges $30 for each job he does plus an additional $15 for each hour he works.
What are inequalities?Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.
The inequality for the given situation is 30+15x≥90
Subtract 30 on the both the sides of an inequality, which is
30+15x-30≥90-30
⇒ 15x≥60
Divide 15 on the both the sides of an inequality, that is
15x/15≥60/15
⇒ x≥4
The solution for the inequality is x≥4. Therefore, option A is the correct answer.
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The drama club is selling candles for a fundraiser. They spend $100 on the candles and sell them for $4.50 each. How many candles must they sell to make more than $125 profit?
Let x represent the number of candles sold. Which inequality can you use to find x?
So I try to help
Step-by-step explanation:
I don't no sorrry
Answer:
the first one!!
Step-by-step explanation:
The average math SAT score is 511 with a standard deviation of 119. A particular high school claims that its students have unusually high math SAT scores. A random sample of 55 students from this school was selected, and the mean math SAT score was 528. Is the high school justified in its claim? Explain. ▼ No Yes , because the z-score ( nothing) is ▼ unusual not unusual since it ▼ does not lie lies within the range of a usual event, namely within ▼ 1 standard deviation 2 standard deviations 3 standard deviations of the mean of the sample means. (Round to two decimal places as needed.)
Answer:
No, because the z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual event, namely within 2 standard deviations of the mean of the sample means.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Unusual
If X is more than two standard deviations from the mean, x is considered unusual.
In this question:
[tex]\mu = 511, \sigma = 119, n = 55, s = \frac{119}{\sqrt{55}} = 16.046[/tex]
A random sample of 55 students from this school was selected, and the mean math SAT score was 528. Is the high school justified in its claim?
If Z is equal or greater than 2, the claim is justified.
Lets find Z.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{528 - 511}{16.046}[/tex]
[tex]Z = 1.06[/tex]
1.06 < 2, so 528 is not unusually high.
The answer is:
No, because the z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual event, namely within 2 standard deviations of the mean of the sample means.
The statement that could be made regarding the high school about the justification of its claim would be:
- No, because the z-score of Z = 1.06 is not unusual since it does not lie within the range of a usual event, namely within 2 standard deviations of the mean of the sample means.
Given that,
μ = 511
σ = 119
Sample(n) = 55
and
s = [tex]119/\sqrt{55}[/tex]
[tex]= 16.046[/tex]
As we know,
The claim of the high school could be valid and justified only when
[tex]Z > 2[/tex]
To find,
The value of Z
So,
[tex]Z = (X -[/tex] μ )/σ
by putting the values using Central Limit Theorem,
[tex]Z = (528 - 511)/16.046[/tex]
∵ [tex]Z = 1.06[/tex]
Since [tex]Z < 2[/tex], the claim is not justified.
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A cereal box has a volume of 225 cubic inches. The length of the base is 9 inches and the width of the base is
2.5 inches. What is the height of the box?
Answer:
10
Step-by-step explanation:
First multiply 9 by 2.5
Then divide 225 by 22.5
Find the area and the circumference of a circle with radius 7 cm.
Use the value 3.14 for me, and do not round your answers. Be sure to include the correct units in your answers.
cm
7 cm
Area: 0
Circumference: 0
Х
[tex]answers \\ area = 153.86 \: {cm}^{2} \\ circumference = 43.96 \: cm \\ \\ solution \\ radius = 7cm \\ area \: of \: circle = \pi {r}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \: 3.14 \times {7}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.14 \times 49 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 153.86 \: {cm}^{2} \\ circumference \: of \: circle = 2\pi \: r \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times 3.14 \times 7 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 43.96 \: cm \\ hope \: it \: helps \\ good \: luck \: on \: you r \: assignment[/tex]
Answer:
[tex] Area \: of \: circle = 153.86 \: {cm}^{2} \\ \\ Perimeter \: of \: circle = 43.96 \: cm [/tex]
Given:
Radius of circle (r) = 7 cm
Step-by-step explanation:
[tex]Area \: of \: circle = \pi {r}^{2} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi \times ({7}^{2} ) \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \pi \times 49 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.14 \times 49 \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 153.86 \: {cm}^{2} [/tex]
[tex]Circumference \: of \: circle = 2\pi r \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2 \times \pi \times 7\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 14 \times \pi\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 14 \times 3.14\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 43.96 \: cm[/tex]
An on-line retailer identified the web browser being used by a sample of 50 shoppers to its online site. The accompanying data table identifies the browser being used by a shopper. Previously in 2010, 64% of shoppers used Browser A, 24% Browser B, 6% Browser C, 3% Browser D, and 3% Browser E.
Required:
a. Using software, tabulate the frequency of the choice of browser used by these shoppers.
b. Present a bar chart and a pie chart of these frequencies. Which is more useful to compare the distribution of these to those observed in 2010?
c. Do you see any changes in the distribution of the choice of browser?
Answer:
See Explanation
This question is answered using Microsoft Office Excel 2013
Step-by-step explanation:
Given
Browser A - 64%
Browser B - 24%
Browser C - 6%
Browser D - 3%
Browser E - 3%
Total Frequency = 50
a.
To tabulate the frequency of the choice of browser, the total frequency is multiplied by each individual percentage as follows;
Browser A - 64% * 50 = 32
Browser B - 24% * 50 = 12
Browser C - 6% * 50 = 3
Browser D - 3%* 50 = 1.5
Browser E - 3% * 50 = 1.5
See Attachment for frequency table (using software)
b. See Attachment for pie chart and bar chart.
Both charts are useful for data presentation but in this case, the pie chart is a better option to use because it shows how the distribution of each browser and how they make up as a whole.
The main circle of the pie chart shows how individual browser are distributed through segments; This is not so for the bars of the bar chart which.
c. Yes, there are changes in the choice of browser.
Aside from Browser D and E that has the same frequency, other browsers (A-C) have different frequency.
Also, the distribution shows that more users make use of browser A than other browsers and the least frequent used browser are browser D and E.
Working on Summer Vacation. An Adweek/Harris (July 2011) poll found that 35% of U.S. adults do not work at all while on summer vacation. In a random sample of 10 U.S. adults, let x represent the number who do not work during summer vacation
a. For this experiment, define the event that represents a "success"
b. Explain why x is (approximately) a binomial random variable
c. Give the value of p for this binomial experiment
d. Find P(x = 3)
e. Find the probability that 2 or fewer of the 10 U.S. adults do not work during summer vacation
A becuase i worked it out and i got that so im really confident
Do the points shown represent additive inverses? Explain why or why not
Answer:
Yes additive inverse is two complete opposite numbers if added = 0
Answer:
additive
Step-by-step explanation:
Because the point is not past the postive live or below the negative.
Evaluate the expression 2x-7 for x = -4
Answer:
-15
Step-by-step explanation:
The solution of expression for x = - 4 is,
⇒ - 15
We have to given that,
An expression is,
⇒ 2x - 7
Now, We can simplify the expression for x = - 4 as,
An expression is,
⇒ 2x - 7
Plug x = - 4;
⇒ 2 × - 4 - 7
⇒ - 8 - 7
⇒ - 15
Thus, The solution of expression for x = - 4 is,
⇒ - 15
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The data represents the heights of eruptions by a geyser. Use the heights to construct a stemplot. Identify the two values that are closest to the middle when the data are sorted in order from lowest to highest.
Height of eruption
62 33 50 90
80 50 40 70
50 63 74 53
55 64 60 60
78 70 43 82
Required:
Identify the two values that are closest to the middle when the data are sorted in order from lowest to highest. The values closest to the middle are_________inches and_______inches.
Answer:
[tex] Median = \frac{60+60}{2}=60[/tex]
And we see that the closest values to 60 are 62 and 63 and then the answer would be:
The values closest to the middle are 62 inches and 63 inches.
Step-by-step explanation:
We have the following dataser given:
62 33 50 90 80 50 40 70 50 63 74 53 55 64 60 60 78 70 43 82
We can sort the values from the lowest to the highest and we got::
33 40 43 50 50 50 53 55 60 60 62 63 64 70 70 74 78 80 82 90
Now we see that we have n=20 values and the values closest to the middle and we can use the middle as the median and for this case the median can be calculated from position 10 and 11th and we got:
[tex] Median = \frac{60+60}{2}=60[/tex]
And we see that the closest values to 60 are 62 and 63 and then the answer would be:
The values closest to the middle are 62 inches and 63 inches.
The values closest to these middle elements are 60 and 63 inches
The dataset is given as:
62 33 50 90 80 50 40 70 50 63 74 53 55 64 60 60 78 70 43 82
Next, we sort the data elements in ascending order
33 40 43 50 50 50 53 55 60 60 62 63 64 70 70 74 78 80 82 90
The length of the dataset is 20.
So, the elements at the middle are the 10th and the 11 elements.
From the sorted dataset, these elements are: 60 and 62
Hence, the values closest to these middle elements are 60 and 63
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The ability of ecologists to identify regions of greatest species richness could have an impact on the preservation of genetic diversity, a major objective of the World Conservation Strategy. A study used a sample of n = 33 lakes to obtain the estimated regression equation
y = 3.89 + 0.033x1 + 0.024x2 + 0.023x3 − 0.0080x4 − 0.13x5 − 0.72x6
where y = species richness, x1 = watershed area, x2 = shore width, x3 = poor drainage (%), x4 = water color (total color units), x5 = sand (%), and x6 = alkalinity.
The SSR and SSE have been calculated to be:_________.
SSR = 752.25 and SSE = 300.9.
ANSWER:
I believe you wish to calculate the sum of squares total (SST) for this regression analysis. The sum of squares total is 1053.15
Step-by-step explanation:
The sum of squares total is numerically derived by adding the sum of squares regression (regression sum of squares) to the sum of squares error (error sum of squares). The regression sum of squares here is 752.25 and the error sum of squares is 300.9
This gives us a total sum of squares of 1053.15
Sums of squares tell if a linear regression of one variable (or variables) on another is good or not.
The squared differences between the observed dependent variable and its mean is a measure of the total variability of the data set.
So the SST is equal to 752.25 + 300.9 = 1053.15
From the mid-1960s to the early 1990s, there was a slow but steady decline in SAT scores. For example, take the Verbal SAT. The average in 1967 was about 543; by 1994, the average was down to about 499. However, the SD stayed close to 110. The drop in average has a large effect on the tails of the distribution. 0.7% 7% 7.67% 7.6%
Complete Question
From the mid-1960's to the early 1990's, there was a slow but steady decline in SAT scores. For example, take the Verbal SAT. The average in 1967 was about 543; by 1994, the average was down to about 499. However, the SD stayed close to 110. The drop in average has a large effect on the tails of the distribution.
Estimate the percentage of students scoring over 700 on 1967.
A 0.7%
B 7%
C 7.67%
D 7.6%
Answer:
The correct option is D
Step-by-step explanation:
From the question we are told that
The average SAT score in 1967 is [tex]\= x_1 =543[/tex]
The standard deviation of score in 1967 is [tex]\sigma_ 1= 110[/tex]
The average SAT score in 1994 is [tex]\= x_2 = 499[/tex]
The standard deviation of score in 1967 is [tex]\sigma_ 2 = 110[/tex]
The percentage of students scoring over 700 on 1967 is mathematically represented as
[tex]P(X > 700)[/tex]
Where X is the random variable representing score of student above 700
Now normalizing the above probability we have
[tex]P(X > 700) = P(Z > \frac{700 - \= x_1 }{\sigma } )[/tex]
substituting values
[tex]= P(Z > \frac{700 - \= 543}{110 } )[/tex]
[tex]= P(Z > 1.83 )[/tex]
Form the normalized z table
= 0.076
= 7.6 %
What is the measure of XYZ?
please help me out
Answer:
The answer is C.
Step-by-step explanation:
You have to divide it by 2 :
∠XYZ = 148° ÷ 2
= 74°
What one is it I have have been struggling with this
Answer:
C is the correct answer.
Step-by-step explanation:
The reason it is C is because pi/the symbol on top is irrational.
Hope you have a good rest of your day :)
Simplify: 5y + 2p – 4y – 6P
Answer:
[tex]y-4p[/tex]
Step-by-step explanation:
Add/subtract like terms.
[tex]5y+2p-4y-6p\\5y-4y+2p-6p\\y-4p[/tex]
Please answer this correctly
Answer:
1
Step-by-step explanation:
Set the height of the bar to 1 because there is only 1 number between 40-49 i.e. 49
20000 rupees to US dollars
Answer: $264.54
Hope this helped! God bless!
Please help! Which statement is true, about the following of the two triangles? (Refer to image)
A: ΔADC≅Δ ACB, by the SSS congruence postulate.
B: ΔADC≅ΔACB, by the SAS congruence postulate.
C: ΔADC≅ ΔCBA, by the SSS congruence postulate.
D: ΔADC≅ΔCBA, by the SAS congruence postulate.
Answer:
The answer is C because DC = BA and DA = CB (given) and AC = CA (reflexive property).
Find the product. (4p – 6)(4p + 6) a. 16p2 + 36 b. 16p2 – 36 c. 16p2 – 48p – 36 d. 16p2 + 48p + 36
Answer:
Brainleist to me!
Step-by-step explanation:
(4p – 6)(4p + 6) =
B) 16 p^2 - 36
just use a online calculator
Answer:
16p²-36
Step-by-step explanation:
1(4p-6)(4p+6)
as we know that (a+b)(a-b)=a²-b²
=(4p)²-(6)²
=16p²-36
Amit found and labeled the areas of each of the faces of the triangle prism as shown which area calculation did Amit calculate incorrectly
Complete Question:
Amit found and labeled the areas of each of the faces of the triangular prism as shown.
Which area calculation did Amit calculate incorrectly?
Rectangular face with area 30 cm2
Rectangular face with area 40 cm2
Rectangular face with area 50 cm2
Triangular faces with areas 48 cm2
Answer:
Triangular faces with areas 48 cm2
Step-by-step Explanation:
To find out which area calculation Amit got wrong, let's calculate each faces of the given triangular prism attached below:
There area of theb5 faces should be as follows:
Area of rectangular face with L = 10 and B = 5 would be ==> 10*5= 50cm²
Area of rectangular face with L = 8 and B = 5 would be 8*5 = 40cm²
Area of rectangular face with L = 6 and B = 5 would 6*5 = 30cm²
Area of each of the triangular faces will be ½*8*6 = 48/2 = 24cm²
From our calculations, we'd observe that Amit didn't calculate the area of the triangular faces correctly. Amit got 48cm² instead of 24cm²
Answer:
Triangular faces with areas 48 cm2
Step-by-step explanation: