Answer:
340000
Explanation:
The answer is 340000 because there will be six digits, as it is one digit followed by five zeroes, but one of the zeroes is a 4 because of the 4 in 3.4. 3.4x10^5 is 340000 in standard form.
HELP PLZ IM BEING TIMED!!
What is the vertical acceleration of a dart that is launched horizontally with an initial velocity of 2.3 m/s?
-9.8 m/s
2 0 m/s2
2.3 m/s2
9.8 m/s2
Answer:
-9.8
Explanation:
EDGE 2021
The vertical acceleration of a dart is equal to the negative of acceleration due to gravity (- g). The vertical acceleration of the dart is equal to -9.8m/s². Therefore, option (1) is correct.
What is the acceleration due to gravity?Acceleration due to gravity is the acceleration acquired by a body due to gravitational force. As gravity has both magnitude and direction, so it is a vector quantity. Acceleration due to gravity is expressed by the symbol 'g'. The SI unit of g is m/s² and the value of g (acceleration due to gravity) on the surface of the earth is 9.8 m/s².
Let us suppose a body with mass (m) is dropped from a height ‘h’ above the surface of the earth with mass (M), it starts to move downwards with an increase in velocity to the earth's surface.
The body starts to accelerate toward the earth’s center under the action of gravitational force which is at a distance ‘r’.
Then, ma = GMm/r²
a = GM/r²
Therefore, the value of the acceleration due to gravity (g) = GM/r2.
Any object freely falling to the surface of the earth has acceleration due to gravity is 9.8m/s².
If the object moves away from the surface of the earth then it experiences the gravitational pull of the earth. Therefore, the acceleration of dart vertically is equal to -g.
Therefore, the vertical acceleration of the dart is equal to -9.8m/s².
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Under what conditions can an object have forces acting on it, but its motion does not change ?
Answer: An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion.
Explanation: I hoped that helped!!
An object with a mass of 43 kg measured on Earth is taken to the Moon. What is the mass of the object on the Moon's surface if the acceleration due to gravity on the Moon is one-sixth of that on Earth? O a. 16 kg O b. 43 kg O c. 7.9 kg O d. 26 kg
Answer:
b 43 kg
Explanation:
mass doesn't differ from place to place.
but the weight may
GOOD MFRNING
PAGE NO.:
DATE:
cap a b
body have larger mess be holter than another of smaller
maws if they are same temperature why,
at the
Answer:
umm im confused
Explanation:
Answer:
larger mass more the molecule more heat absorbed
and vice versa .Thats the reason ok?
A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?
Complete Question
A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the ball's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?
Answer:
The distance covered horizontally is [tex]d = 43 \ m[/tex]
Explanation:
From the question we are told that
The initial horizontal velocity is [tex]u = 10 \ m/s[/tex]
The time taken by the ball in the air is [tex]t = 4.3 \ s[/tex]
Generally the distance traveled by the ball is
[tex]d = u * t[/tex]
=> [tex]d = 10 * 4.3[/tex]
=> [tex]d = 43 \ m[/tex]
A 2,100kg car drives toward a 55kg cart that has a velocity of 0.50m/s west. The two objects collide giving the car a final velocity of 6.31m/s east and the shopping cart a velocity of 13.5m/s east what the initial velocity of the car?
A. 6.68m/s east
B. 7.19m/s west
C. 6.68m/s west
D. 7.19m/s east
Answer: A. 6.68m/s east
Explanation: just did it on ap3x
Which statement describes the pattern in the density of gases in the
atmosphere?
A. They are least dense in the atmosphere near sea level
B. They are less dense near the top of the atmosphere
C. They are densest near the middle of the
atmosphere
D. They are every dense thoughout the attesohere
Gases are less dense near the top of the atmosphere.
What is atmosphere?All life on Earth is shielded by the atmosphere, a layer of gases that regulates temperatures within a narrow range and deflects harmful solar rays.
The layer of gases that covers Earth is known as the atmosphere. The gravitational pull of the Earth keeps it close to the planet's surface. The three primary gases that make up the atmosphere are argon, oxygen, and nitrogen.
Density of atmosphere is high at sea level and gradually decreases with height. And at top of the atmosphere, gas is less dense.
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Un delfín nada en el mar, a una profundidad tal que experimenta es de 2,22 x 10⁵ PA. Si la densidad del agua del mar es de 1030kg/m³, ¿A qué profundidad nada el delfín?
Answer:
El delfín nada a una profundidad de 22 m
Explanation:
El principio fundamental de la hidrostática establece que la presión en un punto del interior de un fluido (presión hidrostática) es directamente proporcional a su densidad, a la profundidad que se encuentre dicho punto y a la gravedad del sitio en el que se encuentre el fluido.
Esto se expresa como:
P=ρ⋅g⋅h
donde:
P es la presión en un punto del fluido. ρ es la densidad del fluido .g es la gravedad del lugar donde se encuentre el fluido. h es la profundidad.En este caso:
P= 2.22*10⁵ Paρ= 1,030 [tex]\frac{kg}{m^{3} }[/tex]g= 9.8 [tex]\frac{m}{s^{2} }[/tex]h= ?Reemplazando:
2.22*10⁵ Pa= 1,030 [tex]\frac{kg}{m^{3} }[/tex] * 9.8 [tex]\frac{m}{s^{2} }[/tex] * h
Resolviendo:
[tex]h=\frac{2.22*10^{5} Pa}{1,030\frac{kg}{m^{3} }*9.8 \frac{m}{s^{2} }}[/tex]
h= 21.993 m ≅ 22 m
El delfín nada a una profundidad de 22 m
Someone help me plz. I have no idea.
Answer:
fault im pretty sure
Explanation:
Answer:
fault............
...........
What happens to the strength of an electromagnet when the number of coils
in the solenoid is increased?
O A. It depends on what metal makes up the solenoid.
B. It increases.
C. It remains the same.
D. It decreases.
Answer:
It decreases
Explanation:
<3
When the number of coils in the solenoid is increased, the strength of the electromagnet also increases. So, the correct option is B.
What is meant by a solenoid ?A solenoid is defined as a type of electromagnet formed by winding a wire into a helical coil on a rod made of solid iron or steel.
Here,
The number of coils in the solenoid is increased. This increase in the number of coils, would affect the strength of the electromagnet.
The equation for the strength of the magnetic field of a solenoid can be written as,
B = μ₀NI/L
where,
B is the magnetic field strength
μ₀ is the permeability of free space
N is the number of turns of the coil
I is the current flowing through the solenoid
L is the length of the solenoid
From the equation, we can say that the magnetic field strength of a solenoid is directly proportional to the number of turns or the number of coils formed.
B [tex]\alpha[/tex] N
Therefore,
As, the number of coils in a solenoid increases, the magnetic field strength of the solenoid also increases.
Hence,
When the number of coils in the solenoid is increased, the strength of the electromagnet also increases.
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what would be the velocity
when a dog of 10kg and it's kinetic energy is 20J
Answer:
2 m/s
Explanation:
Which of the following equations is balanced?
a. 2Al2O3 -----> 3Al + 3O2
b. 3Al2O3 -----> 3Al + 2O2
c. 2Al2O3 -----> 4Al + 3O2
d. 2Al2O3 -----> Al + 3O2
Answer: c
Explanation:
The way to check which one is the correct one is to simply multiply and see if there are the same number of atoms in both sides for each element.
a. 2×2 atoms of Al ≠ 3×1 atoms of Al
2×3 atoms of O = 3×2 atoms of O
BOTH MUST BE EQUAL FOR IT TO BE ADJUSTED!!!!!
b. 3×2 atoms of Al ≠ 3×1 atoms of Al
3×3 atoms of O ≠ 2×2 atoms of O
c. 2×2 atoms of Al = 4×1 atoms of Al
2×3 atoms of O = 3×2 atoms of O
BOTH ARE EQUAL, CORRECT ANSWER!!!
d. 2×2 atoms of Al ≠ 1×1 atoms of Al
2×3 atoms of O = 3×2 atoms of O
a baby carriage is sitting on the top of a hill that is 21 m high. the carriage with a baby 75kg. the carriage has what energy? calculate it
Answer:
It has potential energy
PE = 15450.75 J
Explanation:
we know its potential energy because the carriage is not moving, although it can
PE = mgh
in this case, m is 75, h is 21, and g is always 9.81
plug these in: PE = (75) (21) (9.81)
your answer: PE = 15450.75 J
You are traveling down the highway when you notice a cop 200 meters ahead of you. For the next 5 seconds, you step on the bake to avoid a speeding ticket. The brake causes an acceleration on your car of -2.0 m/s^2.
What is the time it takes?
What is the displacement of your car?
What is the acceleration of your car?
Write the equation you will use to solve the problem.
What was your initial velocity?
Answer:200 5 -20 = v=323
Explanation:
Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to 350 K. If the volume of the bottle remains constant, what is the pressure, in pascals, inside the hot water bottle!
Answer:
128.205.1
Explanation:
What would be the y-component of a velocity vector that had a
magnitude of 37m/s in a direction 30° from the x-axis?
Answer:
18.5 m/s
Explanation:
Just did it on EdPuzzle
The y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s .
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
As given in the problem we have to find out the y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis.
The y-component of a velocity vector = 37 × sin 30
= 18.5 m / s
Thus , y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s.
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A box is pushed horizontally with constant speed across a rough horizontal surface.
Which of the following must be true?
Answer:
what is the answers? so i can't answer.
Explanation:
The statement that is true as regards movement of the box when pushed horizontally with constant velocity is given by;
Option D; The friction is equal to the applied force
The missing options are;
a) The friction is less than the applied force
b) There is no friction acting on the box
c) The friction is greater than the applied force
d) The friction is equal to the applied force
We are told that the box is pushed with constant speed. We know that at constant speed, acceleration is equal to zero. If acceleration is zero, the 2 forces acting on the box will be the applied force and the frictional force from the rough horizontal surface.
Now, if the frictional force was less than the applied force, it means the velocity of the box will gradually be increasing but we are told the velocity is constant.
Also, if the frictional force is more than the applied force, it means the object will not move because the force of resistance is more than the applied force.Finally, if the frictional force is equal to the applied force, then the box will move with a constant motion.
Thus, in conclusion the friction is equal to the applied force.
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how is an object's motion related to speed, velocity, and acceleration?
Answer:
Speed describes only how fast an object is moving, whereas velocity gives both the speed and direction of the object’s motion being a vector quantity. The standard unit to measure velocity is meter per second (m/s or ms-1). For example, “10 meters per second” is scalar and “10 meters per second West” is vector. Acceleration
Density Questions
How many blocks of ice-cream each 10cm x 10 cm x 4cm can be stored in the compartenent of a deep-freeze measuring 40 cm x 40cm x 20cm?
Explanation:
let's take the volume of each first:
ice cream: 10×10×4=400cm^3
freezer: 40×40×20=32,000cm^3
now we just divide: 32000/400=80
When the car was stopped by the tree, its change in velocity during the collision was -6 meters/second. This change in velocity occurred in 2 seconds. What was the acceleration of the car?
En un año se otorgará uno de tres premios (a la investigación, la enseñanza y el servicio) a algunos de los estudiantes, de un grupo de 25, de posgrado del departamento de estadística. Si cada estudiante puede recibir un premio como máximo, ¿cuántas selecciones posibles habría?
Answer:
Habría 13,800 selecciones posibles.
Explanation:
Permutar es colocar elementos en distintas posiciones.
Se llama permutación de m elementos a cada una de las diferentes ordenaciones que se pueden hacer con esos elementos. En otras palabras, se llama permutaciones de m elementos en n posiciones a las distintas formas en que se pueden ordenar los m elementos ocupando únicamente las n posiciones.
En el caso de la permutación no se repiten los elementos, ya que de repetirse o ser iguales entre si, al intercambiarlos no se genera una nueva permutación.
El número de permutaciones de n elementos elegidos k a la vez es calculado como:
[tex]P=\frac{n!}{(n-k)!}[/tex]
Como los premios son distinguibles, la permutación es usada en este caso, donde n=25 y k=3
Entonces:
[tex]P=\frac{25!}{(25-3)!}[/tex]
Resolviendo:
[tex]P=\frac{25!}{(22)!}[/tex]
Recordando que el factorial es una operación matemática que indica que se deben multiplicar todos los números enteros y positivos que hay entre el número al cual deseas calcular el factorial y el número 1, entonces se obtiene:
P= 13,800
Habría 13,800 selecciones posibles.
La selección de los alumnos se puede realizar de 2300 formas.
Teniendo en cuenta eso, tenemos 25 estudiantes graduados para ser seleccionados para tres tipos diferentes de premios, como pabellones de investigación, docencia y servicio.
Ahora;
25C3 = 25! / 3! (25 - 3)!
25C3 = 25! / 3! 22!
25C3 = 2300
La selección de los alumnos se puede realizar de 2300 formas.
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Silver has a mass of 10.5 grams and a volume of 19.3 cm3. What is its density?
Answer:
The answer is 0.54 g/cm³Explanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\ [/tex]
From the question we have
[tex]density = \frac{10.5}{19.3} \\ = 0.54404145...[/tex]
We have the final answer as
0.54 g/cm³Hope this helps you
In a container there are 2 liters of liquid, of which 75% is alcohol and the remaining 25% is water.
Determine how many cm3 of alcohol must be added to bring the alcohol percentage to 80%.
Answer:
There must be added 500 cm3 of alcohol to bring the concentration to 80%.
Explanation:
Concentration
The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solution.
In the container, there are 2 liters (2000 cubic centimeters) of a solution, 75% of which is alcohol (solute) and 25% of water (solvent).
The original amount of alcohol is:
H = 2000*75% = 1500 cc
The original amount of water is:
W = 2000*25% = 500 cc
When we add x cc of pure alcohol, there are 1500+x cc of alcohol out of 2000+x cc of solution.
The new concentration is calculated as:
[tex]\displaystyle \frac{1500+x}{2000+x}[/tex]
And it's known this concentration is 80% (0.8), thus:
[tex]\displaystyle \frac{1500+x}{2000+x}=0.8[/tex]
Multiplying by 2000+x:
[tex]1500+x = 0.8(2000+x)[/tex]
Operating:
[tex]1500+x = 1600+0.8x[/tex]
Rearranging:
[tex]x-0.8x=1600-1500[/tex]
[tex]0.2x=100[/tex]
[tex]x=100/0.2[/tex]
x= 500
There must be added 500 cm3 of alcohol to bring the concentration to 80%
What is the speed in kilometers per hour of a 27.78m/s baseball pitch?
Answer:
I actually don't know
Explanation:
ok chillll
Two teams are competing in a tug-of-war contest. Team A is pulling at 4000N and Team B is pulling at 4900N is the opposite direction.
Answer:
There is 8900N of force on the rope and team B wins
Explanation:
Due to the friction between a tire and the road surface, the temperature of the air inside a tire increases as one drives. If the tire pressure is 37 psi when the car is in the driveway at 25° C, What is the pressure of the tire when the temperature increases to 50° C?
Answer:
40.10 atm .
Explanation:
Here volume of tire is assumed to be nearly constant .
Modified gas law ,
P₁ / T₁ = P₂ / T₂
37 / ( 273 + 25 ) = P₂ / ( 273 + 50)
37 / 298 = P₂ / 323
P₂ = 37 x 323 / 298
= 40.10 atm .
A 200 N net force acts on a 50 kg box. What is the acceleration of the box?
Answer:
a= 4m/s^2
Explanation:
Fnet =200N
m=50kg
a=?
Fnet = ma
200=50a then divide both sides by 50 to get acceleration
Taking into account the Newton's second law, the acceleration of the box is 4 [tex]\frac{m}{s^{2} }[/tex].
In first place, you have to know that Newton's second law, called the fundamental law or fundamental principle of dynamics, states that a body accelerates if a force is applied to it.
Then, the amount of force necessary is proportional to the acceleration that the body acquires, and the constant of proportionality is the mass of the body.
Mathematically, Newton's second law is:
F= m×a
where:
F = Force [N] m = Mass [kg] a = Acceleration [m/s²]In this case, you know:
F= 200 N m= 50 kg a= ?Replacing in the Newton's second law:
200 N= 50 kg×a
Solving:
a=200 N÷ 50 kg
a= 4 [tex]\frac{m}{s^{2} }[/tex]
In summary, the acceleration of the box is 4 [tex]\frac{m}{s^{2} }[/tex].
Learn more about the Newton's second law:
brainly.com/question/23845187?referrer=searchResults brainly.com/question/13959891?referrer=searchResultsThe distance recorded for riding a motorcycle on its rear wheel without stopping is more than 320 km! Suppose the rider in this impressive position is traveling with an initial velocity of 8.0 m/s before accelerating. Then the rider travels 40.0 m at a constant acceleration of 2.00 m/s2. What is the rider's velocity after the acceleration?
Answer:
14.97m/sExplanation:
Given
Initial velocity of the car u = 8m/s
Distance travelled by the rider S = 40m
Acceleration a = 2m/s²
Required
rider's velocity after the acceleration v
Using the equation of motion
v² = u²+2as
v² = 8²+2(2)(40)
v² = 64+160
v² = 224
v = √224
v = 14.97m/s
Hence the rider's velocity after the acceleration is 14.97m/s
A car drives 0.696 km North, and then turns and drives 4.326 km East. Calculate the magnitude of the car's resultant displacement. Include equation, substitution with units, and answer with units.
Answer:
4.3186km
Explanation:
If a car drives 0.696 km North, and then turns and drives 4.326 km East, the magnitude of the car's resultant displacement will be gotten using the Pythagoras theorem as shown;
d² = x²+y²
Given;
x = 4.326km
y = 0.696km
Substitute into the formula and get d;
d² = (4.326)²+(0.696)²
d² = 18.714276+0.484416
d² =19.198692
d = √19.198692
d = 4.3816km
Hence the magnitude of the car's resultant displacement is 4.3186km
Bird man is flying horizontally at a speed of 30m/a and a height of 69 m. Bird man releases a turd directly above the start of the field. How far from the start of the field should the robot hood the bucket to catch the turd?
Answer:
The distance is [tex]d = 112.5 \ m[/tex]
Explanation:
From the question we are told that
The horizontal speed is [tex]v_x = 30 \ m/s[/tex]
The height is [tex]s = 69 \ m[/tex]
Generally from kinematic equation we have that
[tex]s = ut + \frac{1}{2} gt^2[/tex]
Here u is the initial velocity of the turd in the vertical direction and the value is 0 m/s
So
[tex]69 = 0 * t + \frac{1}{2} * 9.8 t^2[/tex]
=> [tex]t = \sqrt{\frac{2 * 69}{4.9} }[/tex]
=> [tex]t = 3.75 \ s[/tex]
Generally the distance which the robot have to hood the bucket in order to catch the turd is mathematically represented as
[tex]d = v_x * t[/tex]
=> [tex]d = 30 * 3.75[/tex]
=> [tex]d = 112.5 \ m[/tex]