7.
(-3x³)(-2x³y⁴z)(-3z²)÷(4x³z)(-3yz) (-3xyz)​

Answer:

[tex]-\frac{x^2y^2}{2}[/tex]

Step-by-step explanation:

We have an extremely large equation and are asked to divide it, so let's solve it step-by-step :

Remove the parenthesis to make it easier to read :

[tex]\frac{-3x^3 *2x^3y^4z *3z^2}{4x^3z*3yz*3xyz}[/tex]

Multiply the numerators :

[tex]\frac{-18x^6y^4z^3}{4*3*3x^3yyzzz}[/tex]

Multiply the denominators :

[tex]\frac{-18x^6y^4z^3}{36x^4y^2z^3}[/tex]

Apply the negative rule :

[tex]-\frac{18x^6y^4z^3}{36x^4y^2z^3}[/tex]

Cancel the common factor which is 18 :

[tex]-\frac{x^6y^4z^3}{2x^4y^2z^3}[/tex]

Apply the addition exponent rule :

[tex]\frac{y^4z^3x^{6-4} }{2y^2z^3}[/tex]

Subtract :

[tex]\frac{x^2y^4z^3 }{2y^2z^3}[/tex]

Apply the rule for y :

[tex]\frac{x^2y^{4-2} z^3 }{2z^3}[/tex]

Subtract :

[tex]\frac{x^2y^2z^3 }{2z^3}[/tex]

Cancel the common factor of z^3 :

[tex]-\frac{x^2y^2}{2}[/tex]

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