Answer:
x=3,2i,-2i
Step-by-step explanation:
A company is manufacturing computer monitors that are 22 inches wide, 22 inches across, and 2 inches thick. If the average cost to produce a computer monitor is $0.43 per cubic inch, then about how much would it cost the company to make 10 computer monitors?
Answer:
$4162.4
Step-by-step explanation:
As per the question statement,
The computer monitors are in cuboid structure.
Width of computer monitors = 22 inches
Length of computer monitors = 22 inches
Thickness of computer monitors = 2 inches
Average cost of production per cubic inch = $0.43
To find:
Cost to the company to make 10 monitors.
Solution:
Volume of a cuboid is given as following:
[tex]Volume = Length \times Width \times Height[/tex]
Volume of one computer monitor as per the given dimensions = [tex]22\times 22 \times 2[/tex] = 968 cubic inches
Volume of 10 such monitors = 968 [tex]\times[/tex] 10 = 9680 cubic inches
Cost of manufacturing of 1 cubic inch = $0.43
Cost of manufacturing of 9680 cubic inch = $0.43 [tex]\times[/tex] 9680 = $4162.4
Victoria created the scatterplot below based on the data in the table for the ages and heights of some teachers in her school. Teacher Age vs. Height Teacher Age Height (in.) 1 36 62 2 28 70 3 50 60 4 44 72 5 58 68 6 24 65 A graph titled Teacher Age versus height has age on the x-axis and height (inches) on the y-axis. Points are at (22, 66), (28, 70), (35, 62), (42, 72), (60, 50) and (59, 69). She wants to see if a teacher’s height depends on his or her age. What did she do wrong when she created the scatterplot? She mixed up the independent and dependent variables. She labeled the x-axis of the scatterplot “Age” when she should have labeled it “Teacher.” She plotted the point (36, 62) when she shouldn’t have. She mixed up the x- and y-coordinates of the point representing teacher 3.
Answer:
a
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
I took the test and got 100%.
Choosing an Inequality Last week, Jason ran 26.1 miles. He wants to run further this week. He plans to run 2.4 miles to the park, four times around the park, and 2.4 miles back from the park. To represent that inequality, he wrote: 2.4 + 4p + 2.4 26.1 Which inequality symbol should he use? Why?
Answer:
> or ≥
Step-by-step explanation:
Distance ran last week = 26.1 miles
Since he wants to further on the total miles covered last week, then what is required is that total miles covered this week is greater than the total distance covered last week.
2.4 miles to the park ; 4 times around the park and 2.4 miles back from the park :
His coverage this week is should be represented by the Inequality :
2.4 + 4p + 2.4 > 26.1 ; which denotes that total coverage this week (2.4 + 4p + 2.4) is greater or more than last week's coverage of 26.1 miles
Answer:
He should use the greater than symbol, >. He would not beat his distance if he only ran 26.1 miles, so the greater than or equal to symbol would not be correct.
Step-by-step explanation:
that's the sample response on edge
For each ordered pair determine whether it is a solution to the system of equations 2x-7y=8 -3x+2y=5
Answers:
(-3,-2)
(4,0)
(5,4)
(-7,-8)
Answer:
The solution of this system of linear equations is [tex](x,y) = (-3,-2)[/tex].
Step-by-step explanation:
Let be the following system of linear equations:
[tex]2\cdot x - 7\cdot y = 8[/tex] (1)
[tex]-3\cdot x + 2\cdot y = 5[/tex] (2)
From (1) we clear [tex]y[/tex]:
[tex]2\cdot x -8 = 7\cdot y[/tex]
[tex]y = \frac{2\cdot x - 8}{7}[/tex]
And we apply this variable in (2):
[tex]-3\cdot x+2\cdot \left(\frac{2\cdot x -8}{7} \right)= 5[/tex]
[tex]-3\cdot x +\frac{4}{7} \cdot x -\frac{16}{7} = 5[/tex]
[tex]-\frac{17}{7}\cdot x = \frac{51}{7}[/tex]
[tex]x = -\frac{51}{17}[/tex]
[tex]x = -3[/tex]
And the value of [tex]y[/tex] is:
[tex]y = \frac{2\cdot (-3)-8}{7}[/tex]
[tex]y = -\frac{14}{7}[/tex]
[tex]y = -2[/tex]
The solution of this system of linear equations is [tex](x,y) = (-3,-2)[/tex].
Please help me with 5
Answer:
Fourth chice, 3/5
Step-by-step explanation:
Add all the numbers together, 12 + 3 + 5 = 20
There's 12 green cubes out of the 20 cubes so it's 12/20 which is 3/5
Leon says that when any number between 1 and 9 is multiplied by 0 , the product always has a 0 or 5 in the ones place. Is this reasonable? explain
Answer:
No
Step-by-step explanation:
Any number multiplied by 0 is 0
4 × 0 = 0 , n × 0 = 0
CAN SOMEONE ASP HELP ME
Answer:
152 sq. ft
Step-by-step explanation:
Area of rectangle:
L × W = A16 × 8 = A16 × 8 = 128 sq. ftArea of triangle:
B = 16 - 12B = 4B × H = A4 × 6 = A4 × 6 = 24 sq. ftCombine the areas:
128 sq. ft + 24 sq. ft = 152 sq. ftI hope this helps!
PLEASE HELPPPP ASAPPP !! thank you in advance
Answer:
hakdog keep it up po11828282882827272++--yyyxxxxxx
What is the yyy-intercept of y=5x-1y=5x−1y, equals, 5, x, minus, 1?
Choose 1 answer:
Choose 1 answer:
(Choice A)
A
(-1,0)(−1,0)left parenthesis, minus, 1, comma, 0, right parenthesis
(Choice B)
B
(0,-1)(0,−1)left parenthesis, 0, comma, minus, 1, right parenthesis
(Choice C)
C
(5,0)(5,0)left parenthesis, 5, comma, 0, right parenthesis
(Choice D)
D
(0,5)(0,5)
Answer:
B.(0,-1)
Step-by-step explanation:
Answer:
B.(0,-1)
Step-by-step explanation:
i just got it right
Find the perimeter of the
polygon if ZB = D.
A
5 cm
B
6 cm
D
7 cm
P = [?] cm
What is the perimeter?
Answer: 48
Step-by-step explanation:
yes
A math test has 12 multiplication problems and 24 division problems.
What is the ratio value of multiplication problems to division problems?
Type your answer as a fraction in simplest form.
Answer:
The answer would be 2/3
Step-by-step explanation:
There are 36 total problems and 24 division problems.
So take 24 over 36 and simplify and you get 2/3
stephanie and amanda each improved their yards by planting hostas and shrubs. they bought their supplies from the same store. stephanie spent $141 on 13 hostas and 10 shrubs. amanda spent $87 on 11 and 2 shrubs. what is the cost of one hosta and the cost of one shrub?
where are the answer choices
someone plzzz help me real fast on this its due in 10 mins plz helpppppppppppppppp
Answer:
first one = greater than or equal to 1 and less than 10
Step-by-step explanation:
it's a method of writing numbers as the product of two factors where the first factor is a number whose absolute value is greater than or equal to 1 but less than 10 while the second factor is a power of 10
Subtract 25¢ from $7.42. Include the dollar sign and no spaces in your answer.
Answer:
$7.17
Step-by-step explanation: hope it helped
(04.01 LC)
Simplify quantity x squared plus 5 x plus 6 end quantity over quantity x plus 2
x2 + 1
x2 − 1
x + 3
x − 3
Question 4(Multiple Choice Worth 5 points)
(04.03 MC)
What are the vertical asymptotes of the function f(x) = the quantity of 2x plus 8, all over x squared plus 5x plus 6?
x = −3 and x = −2
x = −3 and x = 2
x = 1 and x = −2
x = 1 and x = 2
Question 5(Multiple Choice Worth 5 points)
(04.02 LC)
Identify the restrictions on the domain of f(x) = quantity x minus 3 over quantity x plus 5.
x ≠ 5
x ≠ −5
x ≠ 3
x ≠ −3
Question 6(Multiple Choice Worth 5 points)
(04.02 LC)
What are the discontinuity and zero of the function f(x) = quantity x squared plus 6 x plus 8 end quantity over quantity x plus 4?
Discontinuity at (4, 6), zero at (−2, 0)
Discontinuity at (4, 6), zero at (2, 0)
Discontinuity at (−4, −2), zero at (−2, 0)
Discontinuity at (−4, −2), zero at (2, 0)
Question 7 (Essay Worth 10 points)
(04.02 MC)
Show all work to identify the asymptotes and zero of the function f of x equals 3 x over quantity x squared minus 9.
Add Audio Add Video
Question 8 (Essay Worth 10 points)
(04.04 MC)
The aquarium has 6 fewer yellow fish than green fish. 40 percent of the fish are yellow. How many green fish are in the aquarium? Show your work.
Answer:
Following are the solution to the given question:
Step-by-step explanation:
In question 1:
[tex]\to \frac{x^2+5x+6}{x+2}\\\\\to \frac{x^2+(3+2)x+6}{x+2}\\\\\to \frac{x^2+3x+2x+6}{x+2}\\\\\to \frac{x(x+3)+2(x+3)}{x+2}\\\\\to \frac{(x+3) (x+2)}{x+2}\\\\\to (x+3)[/tex]
In question 2:
[tex]\to \frac{2x+8}{x^2+5x+6}\\\\[/tex]
[tex]\to x^2+5x+6=0\\\\\to (x+3)(x+2)=0\\\\\to x+3 =0 \ \ \ \ \ \ x+2 =0\\\\\to x = -3 \ \ \ \ \ \ x=-2 \\\\[/tex]
In question 3:
[tex]\to f(x) = \frac{x-3}{x+5}\\\\\to f(x) \neq 0\\\\when\\\to x+5=0\\\\\to x=-4 \ excluded \ value \\\\\to x \neq 5[/tex]
In question 4:
[tex]\to f(x) = \frac{x^2+6x+8}{(x+4)}\\\\\to f(x) = \frac{x^2+(4+2)x+8}{(x+4)}[/tex]
[tex]\to f(x) = \frac{x^2+4x+2x+8}{(x+4)}\\\\\to f(x) = \frac{x(x+4)+2(x+4)}{(x+4)}\\\\\to f(x) = \frac{(x+4)(x+2)}{(x+4)}\\\\\to f(x) = x= -4 and -2[/tex]
In question 5:
[tex]\to f(x) =\frac{3x}{x^2-9} \\\\ \to f(x) =\frac{3x}{x^2-3^2} \\\\ \to f(x) =\frac{3x}{(x+3)(x-3)}[/tex]
In question 6:
total number of fish = x
yellow fish [tex]= \frac{40}{100}=0.4X[/tex]
green fish [tex]= \frac{60}{100}) =0.6X[/tex]
It is now the case that the yellow fish number is 6 less than the green fish number.
[tex]\therefore \\\\\to 0.6x-0.4x = 6 \\\\\to 0.2x = 6\\\\\to x= \frac{6}{0.2} \\\\\to x=30[/tex]
green fish [tex]= 0.6 \times 30=18[/tex]
Y = 9x^2 - 81
Solve by following quadratic function by utilizing the square root method
beth is planning a playground and has decided to place the swings in such a way that they are the same distance from the jungle gym and the monkey bars. if beth places the swings at point d, how could she prove that point d is equidistant from the jungle gym and monkey bars? if segment dc bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. if segment dc bisects segment ab, then point d is equidistant from points a and b because congruent parts of congruent triangles are congruent. if segment ad bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. if segment ad bisects segment ab, then point d is equidistant from points a and b because congruent parts of congruent triangles are congruent.
Answer:
Step-by-step segment dc bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects. if segment dc bisects segment ab, then point d is equidistant from points a and b because congruent parts of congruent triangles are congruent. if segment ad bisects segment ab, then point d is equidistant from points a and b because a point on a perpendicular bisector is equidistant from:
The cost to rent a car is a linear function of the distance driven. A car rental company
charges $100 plus $ 0.40 a mile. Write an equation that represents this situation?
A y = 100x +0.40
B y = 100.4x
C y = 40x+100
Dy =0.4x +100
An online furniture store sells chairs for $150 each and tables for $550 each. The
store must sell at least $8500 worth of chairs and tables each day. Write an inequality
that could represent the possible values for the number of tables sold, t, and the
number of chairs sold, c, that would satisfy the constraint.
Answer: 550t + 150c ≥ 8500
Step-by-step explanation: the store makes 550 for each table sold, so for t tables, the store will make 550t dollars. The store makes 150 for each chair sold, so for c chairs, the store will make 150c dollars. Therefore, the total revenue 550t + 150c must be greater than or equal to 8500
20. What is the slope-intercept form of the equation of the line with a slope of 1/4 and y-intercept at the origin?
Answer
The slope-intercept form of the equation of the line with a slope of 1/4 and y-intercept at the origin:
[tex]y=\frac{1}{4}x[/tex]
Step-by-step explanation:
Given
The slope = m = 1/4The y-intercept is (0, 0)We know that the slope-intercept form of the line equation is
[tex]y=mx+b[/tex]
where m is the slope and b is the y-intercept.
substituting the values m=1/4 and the y-intercept b=0 to determine the equation in slope-intercept form
[tex]y=mx+b[/tex]
[tex]y=\frac{1}{4}x+0[/tex]
[tex]y=\frac{1}{4}x[/tex]
Thus, the slope-intercept form of the equation of the line with a slope of 1/4 and y-intercept at the origin:
[tex]y=\frac{1}{4}x[/tex]
a ² + b ² + 2 (ab + bc + ca)
Answer: = a^2 + 2ab + 2(ac+ b^2 + 2bc)
Step-by-step explanation:
A lady traveled 100 kilometers at a rate of 30 kilometers an hour. If she wants her return trip to be three-fourths of her initial trip, at what rate must she return?
Answer:
Step-by-step explanation:
100/30=3 1/3hrs to go
3 1/3*3/4=
10/3*3/4=30
30/12=2 1/5hrs return
100/2 1/2=
100/(5/2)=
100*2/5=200/5=40
100/2.5=40mph return
A builder has metal rods that are each 3.73 centimeters long. If he puts 8 of them in a line, how long will the line be?
PLEASE HELP ME THIS IS DUE SOON RJFVRPIVNOIEL
Answer:
you can calculate it like two rectangle volume
Help please!!!!!!!!!!!!!!!!!!
Answer:
trapezoid
Step-by-step explanation:
the following are the duration in minutes of a sample of long - distance phone calls made within the continental united states reported by one long - distance carrier.
The correct option is B) 5 minutes.
The width of each class /(class width) is 5 minutes.
What is termed as the class width/class interval?The term "class interval" refers to the numerical width of a class in such a frequency distribution.
Some key features regarding the class width/class interval are-
Data in a grouped frequency distribution is organized into classes. The class interval is defined as the difference between both the upper and lower class limits.There are two kinds of class intervals in statistics: exclusive & inclusive class intervals. A table of frequency distribution can be built using these.A class interval is utilized in a table of frequency distribution to systematically organize data from an experiment. A frequency distribution's classes are usually mutually exclusive. A grouped frequency distribution can be organized according to whether the class intervals are exclusive or inclusive.To know more about the class width/class interval, here
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The complete question is -
The following are the duration in minutes of a sample of long-distance phone calls made within the continental United States reported by one long-distance carrier.
RelativeTime (in Minutes)/
Frequency
0 but less than 5/0.37
5 but less than 10/0.22
10 but less than 15/0.15
15 but less than 20/0.10
20 but less than 25/0.07
25 but less than 30/0.07
30 or more/0.02
What is the width of each class?
A) 1 minute
B) 5 minutes
c) 2%
d) 100%
I need a step by step to solving this problem 4|3x + 4 = 4x + 8
The solution to the equation given as 4(3x + 4) = 4x + 8 is x =-1
What are expressions?Expressions are mathematical statements that are represented by variables, coefficients and operators
How to determine the solution to the equation?The equation is given as
4(3x + 4) = 4x + 8
Open the bracket in the above equation
So, we have
12x + 16 = 4x + 8
Collect the like terms in the above equation
12x - 4x = 8 - 16
Evaluate the like terms in the above equation
8x = -8
Divide both sides by 8 in the above equation
x =-1
Hence, the solution to the equation given as 4(3x + 4) = 4x + 8 is x =-1
Read more about equation at
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Pleaseee helpppp meeee
Answer:
150
Step-by-step explanation:
The question is unclear. Do they want an angle that is under 180 (to your left) or over 180 (to your right)? I'm guessing that it is just under 180.
Each hour on a clock takes up 30 degrees. Each 5 minutes hand sweep out out 5/60 * 360 = 30 degrees as well. This angle looks like it is 5 minutes to seven if it was on a clock.
So the large angle from 12 oclock would sweep out 210 degrees and that would mean that the left angle would be 150. But the time is not quite 7 o,clock.
My guess would be 150. Remember, this is an estimate. You can't use a protractor on the question.
Graph the system of inequalities.
(x-y< or = to 1
(x+2y < 4
Answer:
[tex]y\ge \:-1+x,\:y<\frac{4-x}{2}\quad :\quad \begin{bmatrix}y\ge \:-1+x\\ y<\frac{4-x}{2}\end{bmatrix}\quad \mathrm{Unbounded}[/tex]
The graph is attached below.
Step-by-step explanation:
Given the system of inequalities.
[tex]\begin{bmatrix}x-y\le \:1\\ x+2y<4\end{bmatrix}[/tex]
Isolate y for [tex]x-y\le \:1[/tex]
[tex]x-y\le \:1[/tex]
subtract x from both sides
[tex]x-y-x\le \:1-x[/tex]
simplify
[tex]-y\le \:1-x[/tex]
Multiply both sides by -1 (reverse the inequality)
[tex]\left(-y\right)\left(-1\right)\ge \:1\cdot \left(-1\right)-x\left(-1\right)[/tex]
simplify
[tex]y\ge \:-1+x[/tex]
now solving
[tex]x+2y < 4[/tex]
isolate y for [tex]x+2y < 4[/tex]
[tex]x+2y < 4[/tex]
subtract x from both sides
[tex]x+2y-x<4-x[/tex]
simplify
[tex]2y<4-x[/tex]
Divide both sides by 2
[tex]\frac{2y}{2}<\frac{4}{2}-\frac{x}{2}[/tex]
Simplify
[tex]y<\frac{4-x}{2}[/tex]
Graphing Method:
1. Graph each inequality separately
2. Choose a test point to determine which side of the line needs to be shaded
3. The solution to the system will be the area where the shadings from each inequality overlap one another.
Thus,
[tex]y\ge \:-1+x,\:y<\frac{4-x}{2}\quad :\quad \begin{bmatrix}y\ge \:-1+x\\ y<\frac{4-x}{2}\end{bmatrix}\quad \mathrm{Unbounded}[/tex]
The graph is attached below.
x - 9 = 0.7*x + 0.6*x
Answer:
x = -30
Step-by-step explanation:
[tex]0.7x+0.6x=1x-9\\=>1.3x=1x-9\\=>1.3x-1x=9\\=>0.3x=-9\\=>\frac{3}{10}x =-9\\=>x=\frac{-9*10}{3} =-30[/tex]