A 0.500 cm diameter plastic sphere, used in a static electricity demonstration, has a uniformly distributed 44.0 pC charge on its surface. What is the potential near its surface

Answers

Answer 1

Answer:

Explanation:

Radius of sphere R = .250 x 10⁻² m

Potential on the surface V = k Q / R , where Q is charge on the surface ,  R is radius of the surface and k = 9 x 10⁹

Q = 44  x 10⁻¹² C

V = 9 x 10⁹ x 44  x 10⁻¹² /  ( .25 x 10⁻²)

= 1584 x 10⁻¹ Volt .

= 158.4 Volt


Related Questions

A clump of soft clay is thrown horizontally from 9.80 m above the ground with a speed of 20.0 m/s. Assume it sticks in place when it hits the ground At what time will the clay hit the ground

Answers

Answer:

Explanation:

The time to hit the ground will be same as time taken to fall from the height of 9.8 m with initial vertical velocity of zero .

Considering vertical displacement

initial velocity u = 0

displacement s = 9.8 m

acceleration a = g = 9.8 m /s²

time t = ?

s = ut + 1/2 g t²

9.8 = 0 + .5 x 9.8 x t²

t² = 2

t = √2 = 1.4 s

fertilization that takes place when the union of the sex cells happens outside the body​

Answers

Answer:external

Explanation:EDGE 2021

what kind of lens curve inward toward its center​

Answers

Answer:

A concave lens is exactly the opposite with the outer surfaces curving inward, so it makes parallel light rays curve outward or diverge. That's why concave lenses are sometimes called diverging lenses.

Answer: A concave lens

A concave lens is exactly the opposite with the outer surfaces curving inward, so it makes parallel light rays curve outward or diverge. That's why concave lenses are sometimes called diverging lenses.

Hopes this helps :)

1. In calculating the work W necessary to stretch a spring from its natural length of 8 centimeters to a length of 12 centimeters, we need some more information about the spring. There are two distinct kinds of information, each of which separately would provide the necessary assistance so we could find W. Describe what the two additional kinds of information are.

Answers

Answer:

* displacement from equilibrium position

* The spring constant,

Explanation:

The work done by a spring is two times the expressions

         W = ∫ F. dx

         

in a spring the force is given by hooke's law

          F = - k Δx

we substitute

         W = - k ∫ x dx cos θ

In the case of the spring, the displacement is in the same direction of work, therefore the angle is zero and the cosine is equal to 1

we integrate

           W = ½ k Δx²

we can see that we need two parts to calculate the work

* displacement from equilibrium position

          Δx = 12 -8 = 4 cm

* The spring constant, this constant can be found from the displacement measurements as a function of the applied force.

A 70 kg Throckmorton was riding his skateboard when a small, but juicy 0.001 kg beetle hits the front of his helmet, splattering, obstructing his view. Who experienced the greatest change in momentum?

Answers

Answer:

The beetle

Explanation:

The beetle is correct because of the the force of the Throckmortan was a lot heavier and thus making the beetle feel the force.

Momentum before = momentum after

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(70.0 kg) (3.0 m/s) + (2.0 kg) (3.0 m/s) = (70.0 kg) (3.1 m/s) + (2.0 kg) v

210 kg m/s + 6 kg m/s = 217 kg m/s + (2.0 kg) v

-1 kg m/s = (2.0 kg) v

v = -0.5 m/s

The skateboard's velocity is 0.5 m/s west. Hope I helped and have a good day!

________________________________________________________

前の勢い=後の勢い

m₁u₁+m₂u₂=m₁v₁+m₂v₂

(70.0 kg)(3.0 m / s)+(2.0 kg)(3.0 m / s)=(70.0 kg)(3.1 m / s)+(2.0 kg)v

210 kg m / s + 6 kg m / s = 217 kg m / s +(2.0 kg)v

-1 kg m / s =(2.0 kg)v

v = -0.5 m / s

スケートボードの速度は西に0.5m / sです。私が助けて、良い一日を過ごせることを願っています!

Orion, also called the Hunter, has three stars that make up Orion's belt.

Which star is at the tip of the arrow? PLEASE HELP I NEED THIS FAST


A. Sirius


B. Betelgeuse


C. Rigel


D. Polaris

Answers

Answer - B. Betelguese.

I really hope this helps!!

If rider A is moving 8 meters per second, and rider B is moving 3 meters per second, how far away from rider A was rider B when first observed at the start of the graph?

Answers

Answer:

the answer is 32

Explanation:

he was riding pretty far

Which image best illustrates diffraction

Answers

Answer:

There is no image

Explanation:

Answer: Send me image than I will be able to help

Explanation:

a. As you coast down a hill on your bicycle, you accelerate at 0.5 m/s2. If the total mass of your body and the bicycle is 80 kilograms what is the net force pulling you down the hill (gravity - friction)?

Answers

According to Newton’s second law of motion:
F=ma
=80*0.5
=40N

The net force pulling you down the hill will be = 40 N

What is Newton's Second Law of motion?

The Second Law of motion states that the acceleration of an object depend upon the object and the mass of the object.

F = Mass * acceleration

Given

Total mass  : 80 kg

Acceleration : 0.5 m / s^2

Net Force = mass * acceleration      (Second Law of motion )

Net Force = 80 * 0.5  = 40 N

 The net force pulling you down the hill will be = 40 N

Learn more about  Newton's Second Law of motion:

https://brainly.com/question/11553356?referrer=searchResults

#SPJ2

16. An object has a gravitational potential energy 41,772.5 Jof and has a mass of 1550 kg. How high is it
above the ground?
Plz help

Answers

Answer:

2.75 m.

Explanation:

From the question given above, the following data were obtained:

Potential energy (PE) = 41772.5 J

Mass (m) of object = 1550 kg

Height (h) =?

Potential energy is the energy possess by an object due to its location. Mathematically, potential energy is expressed as shown below:

PE = mgh

Where

PE => potential energy

m => mass of the object

g => acceleration due to gravity

h => height to which the object is located.

With the above formula, we can obtain the height to which the object is located as follow:

Potential energy (PE) = 41772.5 J

Mass (m) of object = 1550 kg

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) =?

PE = mgh

41772.5 = 1550 × 9.8 × h

41772.5 = 15190 × h

Divide both side by 15190

h = 41772.5 / 15190

h = 2.75 m

Thus, the object is located at 2.75 m above the ground.

A spacecraft is flying away from the moon toward earth.

What will be true of the moon’s gravitational pull on the spacecraft?

It will decrease.

It will increase.
It will repel the spacecraft.
It will remain the same.

Answers

Answer:

it will  decrease

Explanation:

According to the law of universal gravitation, the gravitational force exerted by the moon on the spacecraft is equal to the product of their masses and inversely proportional to the square of the distance that separates them. Therefore, as the spacecraft moves away, its distance increases and the force of attraction exerted by the moon decreases.

Answer:

A. It will increase

Explanation:

I took the quiz on K12 and this was the correct option.

Hope I helped

a long solid rod 4.5 cm in radius carries a uniform volume charge density. if the electric field strength at the surface of the rod (not near either end) is 16 kn/c, what is the volume charge density

Answers

Answer:

6.29 μC/m³

Explanation:

Volume charge density is the quantity of charge per unit volume.

The direction of the electric field was not specified, therefore the volume charge density (ρ) is given by:

2πRLE = ρπR²L/ε₀

ρ = 2Eε₀ / R

Where E = electric field strength = 16 kN/C = 16 * 10³ N/C, R = radius of rod = 4.5 cm = 0.045 m, ε₀ = relative permittivity of free space = 8.85 * 10⁻¹² C² / Nm²

Therefore:

ρ = 2(16 * 10³ N/C)(8.85 * 10⁻¹² C²/Nm²) / 0.045 m = 6.29 * 10⁻⁶ C/m³

ρ = 6.29 μC/m³




From the Water in each of the next move

Answers

Any key words? That they put there

A box of bananas weighing 51.0 N rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.46 and the coefficient of kinetic friction is 0.23. Part A If no horizontal force is applied to the box and the box is at rest, how large is the frictional force exerted on the box by the surface

Answers

static friction force = The coefficient of static friction * normal force

static friction force = 0.46 * 51 = 23.46 N

kinetic friction force = The coefficient of kinetic friction * normal force

kinetic friction force = 0.23 * 51 = 11.73 N

the applied force acting on the object must be more than 23.5 N if the object was stationary to move it and must be more than 11.7 N during the movement to keep the object moving

Problem 2: Estimate the electric power requirement, in kW, of a 1,400 ft2floor area (three bedroomshome) with three occupants. Using your home power estimate, predict the power requirementsfor a city of 300,000 people. Use these results to estimate the area (inkm2)of silicon solar cells requiredto satisfy the community power requirements. Assume, thepower requirements for an average single family home of 3 are 108.4 x 106BTU per year and solar panels insolation

Answers

Answer:

a) 3170 kw

b) 377 km^2

Explanation:

Estimate of electric power

a) Given :

Average power consumption for a family of 3 = 108.4 * 106 BTU per year  =  0.0317 kw = 31.7 watts

The power requirement for a city of 300000 people

= 31.7 watts * 100000 = 3170000 watts = 3170 kw

b) Given :

Average solar panel insulation = 8.4 W /m^2

Estimate the area of silicon solar cells required to satisfy community power requirement

= (1 * 3170) * (1000/8.4 )

= 377.380 * 10^3 m2 = 377 km^2

A basketball with a mass of 20 kg is accelerated with a force of 10 N. If resisting forces are ignored, what is the acceleration of the basketball?

Answers

I’m pretty sure it would be 10/20= 0.5m/s2

The driver of a 3000 lb. car, coasting down a hill, sees a red light at the bottom, and must stop. His speed when he applies the brakes is 60 mph, and he is 100 feet (vertically) above the bottom of the hill. (a)How much energy as heat must be dissipated by the brakes if we neglect wind resistance and other frictional effects

Answers

Answer:

Explanation:

60 mph = 60 x 1760 x 3 / (60 x 60) ft /s

speed of car , v = 88 ft /s

kinetic energy of car = 1/2 m v²

= .5 x 3000 x 88²

= 11616 x 10³ poundal - foot

Potential energy = mgh

= 3000 x 32 x 100

=  9600 x 10³ poundal - foot

Total energy = potential energy + kinetic energy

= ( 11616 + 9600 )x 10³

= 21216 x 10³ poundal - foot .

This energy is dissipated as heat when brakes are applied on the car to stop the car .

which newton's laws applies to a slinky?
PLEASE HELP !!

Answers

When a Slinky sits atop a staircase, gravity acts on the toy, keeping it still. Knock over the Slinky, and Newton's second law comes into play. As middle school physics class may have taught you, this law states that providing force to an object increases its acceleration.

hopes this helps uh ❣

Answer:

We know from Newton's First Law of motion that an object at rest stays at rest unless acted upon by an external force. So in the case of the slinky, that is exactly why the bottom of the slinky does not move.

Explanation:

to what temperature it will a 30 KG of glass raise if it absorbs 4275 joules of heat in its specific heat is 0.5 J/KG degree celsius. The initial temperature of the glass is 35°C

Answers

Answer:

230° C

Explanation:

A substance's specific heat tells you how much heat much either be added or removed from 1 g of that substance in order to cause a 1∘C

At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.70 m/s2. At the same instant a truck, traveling with a constant speed of 9.50 m/s, overtakes and passes the automobile. (a) How far beyond the traffic signal will the automobile overtake the truck

Answers

Answer:

66.85 m

Explanation:

We are given that

Acceleration ,a=[tex]2.7m/s^2[/tex]

Speed of truck, v=9.5 m/s

We have to find the distance beyond which the traffic signal will the automobile overtake the truck.

Initial speed of automobile, u=0

We know that

[tex]s=ut+\frac{1}{2}at^2[/tex]

Using the formula

[tex]s=0+\frac{1}{2}(27)t^2=\frac{27}{2}t^2[/tex]

For constant speed

Acceleration, a=0

Again

[tex]s=vt+0=9.5t[/tex]

[tex]9.5t=\frac{27}{2}t^2[/tex]

[tex]t=\frac{9.5\times 2}{2.7}=7.037s[/tex]

Substitute the value of t

[tex]x=9.5(7.037)=66.85m[/tex]

Hence, the distance beyond which the traffic signal will the automobile overtake the truck=66.85 m

A student claims an object in motion must experience a force to stay in motion. Do you agree or disagree?

Answers

Answer:

agree because there is always a force that causes motion..

A hanging wire made of an alloy of titanium with diameter 0.05 cm is initially 2.7 m long. When a 15 kg mass is hung from it, the wire stretches an amount 1.68 cm. A mole of titanium has a mass of 48 grams, and its density is 4.54 g/cm3. Based on these experimental measurements, what is Young's modulus for this alloy of titanium

Answers

Answer:

Explanation:

Young's modulus of elasticity Y = stress / strain

stress = force / cross sectional area

= weight of 15 kg / π r²

= 15 x 9.8 / 3.14 x ( .025 x 10⁻² )²

stress = 74.9 x 10⁷ N / m²

strain = Δ L / L , Δ L is change in length and L is original length

Putting the values

strain = .0168 / 2.7 =.006222

Young's modulus of elasticity Y  = 74.9 x 10⁷ / .006222

= 120.88 x 10⁹ N / m² .

you describe a friend’s position by including distance, direction, and what other term?
Answer choices:
A. Acceleration
B.displacement
C.Average speed
D. Reference point
PLEASE HELP I NEED THIS IN AN HOUR

Answers

Answer:

Acceleration

Explanation:

Answer: Acceleration

Explanation:

What is the frequency of a wave of a light is with a wavelength of 4 x 10-7 m?

Answers

Answer:

7.5 × 10^14 Hz

Velocity of light = 3×10^8m/s

Frequency = (3×10^8)/(4 x 10^-7)

= 7.5 × 10^14 Hz

What must the charge (sign and magnitude) of a particle of mass 1.48 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 640 N/C

Answers

Answer:

[tex]q=-2.26\times 10^{-5}\ C[/tex]

Explanation:

Given that,

The mass of a particle, m = 1.48 g = 0.00148 kg

The electric field, E = 640 N/C

We need to find the charge of the particle when placed in a downward-directed electric field.

The force of gravity is balanced by the electric force such that,

mg = qE

Where

q is the charge of the particle

[tex]q=\dfrac{mg}{E}\\\\q=\dfrac{0.00148\times 9.8}{640}\\\\q=2.26\times 10^{-5}\ C[/tex]

q must be negative, the force must be upward (opposite direction of the electric field).

15 points!!:-) Need help ASAP!

When does a compass NOT point towards magnetic north?

A.during a solar eclipse, which changes

Earth's magnetic field.

B. When there is another magnet close by.

C.When there is an unused battery close by.

D. When there is a coil of copper wire close by.

Answers

Answer:

b i think so because it makes senes

Answer: When there is another magnet close by.

Explanation: The needle of a compass is itself a magnet, and thus the north pole of the magnet always points north, except when it is near a strong magnet. ... When you take the compass away from the bar magnet, it again points north. So, we can conclude that the north end of a compass is attracted to the south end of a magnet.

Which elements have one valence electron?
A. Sodium
B. Carbon
C. Fluorine
D. Magnesium


The answer is A

Answers

Answer:

Well, you said the answer is A, so it’s A!

Haha answer is a you said it

Suppose a cat climbs a tree to a height of 2 meters. If the cat doubles its height to 4 meters, its potential energy will
1)not change
2)reduce to halve
3)double
4)quadruple

Answers

Ep=m*g*h
If h doubles Ep=m*g*2h
Meaning Ep=1*1*2
Ep=2
So 3)potential energy doubles.

If someone walkes 1000m
in 20min, what is their speed?

Answers

Answer:

Distance - 1000m

Time - 20min

Speed - ?

Use the formula of distance ÷ time = speed.

s = d/t

s = 1000m/20min

s = 50 m/min

Hope this helps, thank you !!

Please Help! Will mark brainliest.

Answers

Answer:W = m*g*h

19*9.8*32.4 = 6,032.9 rounded

honestly, I do not know if this is correct so please don't come back at me

hopefully this helps

Explanation: [do the following, if you think I am wrong]

just pick a formula,

plug in the number to the mass, gravity, and height

than multiply

get your answer, but don't forget to round to the nearest tenth

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