A 280 km long pipeline connects two pumping stations. It is desired to pump 0.56 m3/s of oil through a 0.62 m diameter line, the discharge station is 250 m lower in elevation than the upstream station, and the discharge pressure is to be maintained at 300 kPa. The oil has a dynamic viscosity of 3.645 x 10-3 Pa·s and a density of 810 kg/m3. The pipe is constructed of commercial steel and the inlet pressure may be taken as 1 atmosphere. Considering the mechanical-energy friction loss Ff, determine the power required to pump the oil if the power efficiency is 70%. Develop a sketch of the piping system considered.
Ignore energy losses due to contraction, expansion & 90° bends!!!

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Answer 1
Can u answer myn and if u do I’ll do urs

Related Questions

please help me solve this​

Answers

Answer:

Following are the solution to this question:

Explanation:

[tex]\to \Sigma F_x = ma_x \\\\\to 3200 t^2 -440 (9.81) (\frac{8}{17}) = 440 (a) \\\\\to 3200 t^2 -2031.24 = 440 (a)\\\\\to a= 7.27t^2 -4.616\\\\\to dv=a.dt \\\\\to \int^{v}_{2} dv = \int^{2}_{0} (7.27t^2 -4.616) dt\\\\\to v-2 = 7.27 \frac{t^3}{3} - 4.616 t^{2}_{0}\\\\\to v-2 = 7.27 \frac{2^3}{3} - 4.616 {2} \\\\\to v-2 = 10.154\\\\\to v= 12.154 \ \frac{m}{s}\\[/tex]


are considered a form of personal protective equipment (PPE) for eyes.

Answers

Answer:

All of the above

Explanation:

Find the derivative of y = sin(ln(5x2 − 2x))

Answers

Answer:

[tex]y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)[/tex]

Explanation:

Let [tex]y = \sin[\ln(5\cdot x^{2}-2\cdot x)][/tex] and we proceed to find the derivative by the following steps:

1) [tex]y = \sin[\ln(5\cdot x^{2}-2\cdot x)][/tex] Given

2) [tex]y = \sin [\ln[x\cdot (5\cdot x - 2)]][/tex] Distributive property

3) [tex]y = \sin[\ln x + \ln (5\cdot x - 2 )][/tex] [tex]\ln (a\cdot b) = \ln a + \ln b[/tex]

4) [tex]y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)[/tex]  [tex]\frac{d}{dx} (\sin x) = \cos x[/tex]/[tex]\frac{d}{dx}(\ln x) = \frac{1}{x}[/tex]/[tex]\frac{d}{dx}(c\cdot x^{n}) = n\cdot c\cdot x^{n-1}[/tex]/Rule of chain/Result

Omg I just got 17/25 questions wrong using this on an Ag test , but got 100’s every time on health

Answers

Answer:

sorry im answering questions for the points cuz im built dfferent

Explanation:

Answer: That happens to me too sometimes. I hate when people give the wrong answers...like if u don't know the answer, then don't respond

what document is the primary reference document when making ethical decisions?​

Answers

The one that has Ben cited the most and which most directly relates to the topic it is pertaining to.

one number is 11 more than another number. find the two number if three times the larger number exceeds four times the smaller number by 4​

Answers

Answer:

a = 40

b = 29

Explanation:

Give a place holder for the numbers that we don't know.

Lets call the two numbers a and b.

From the given info, we can write an expression and solve it:

"one number is 11 more than another number"

a = 11 + b

from this, we know that a > b.

''three times the larger number exceeds four times the smaller number by 4"

3a = 4b + 4

Now we have 2 equations, we can use them to solve using whatever method you want.

a = 11 + b

3a = 4b + 4

I will be using matrices RREF to solve for this.

a - b = 11

3a - 4b = 4

[tex]\begin{bmatrix}1 & -1 & 11\\3 & -4 & 4 \end{bmatrix}[/tex]

[tex]\begin{bmatrix}1 & 0 & 40\\0 & 1 & 29 \end{bmatrix}[/tex]

a = 40

b = 29

Typical journal-to-bearing clearance is......
A) 0.00015 to 0.00018 inch
B)0.0005 to 0.0025 inch
C) 0.15 to 0.25 inch
D)0.02 to 0.035 inch

Answers

Answer
C



Why
I took the quiz

The typical journal-to-bearing clearance for engines is,

B) 0.0005 to 0.0025 inch

Given that,

To find the typical journal-to-bearing clearance for engines.

Now, The range 0.0005 to 0.0025 inch represents the recommended clearance between the rotating journal of the crankshaft and the bearing surface to ensure proper lubrication and minimal friction.

Hence, The correct option for typical journal-to-bearing clearance for engines is,

B) 0.0005 to 0.0025 inch.

To learn more about journal-to-bearing visit:

https://brainly.com/question/16971319

#SPJ4

1 british gallon = .....litres.
a:4.546
b:3.785
c.5.456
d.7.385​

Answers

Answer:

c

Explanation:

I live in britian

It is preferable not to drive a vehicle in reverse if you have an obstructed view, but if you do, make sure:

Answers

Answer:

While driving in reverse gear it necessary to have reverse audible alarm , a spotter and a rear view mirror.

Explanation:

It is prefer that to not drive a vehicle in reverse. But if we are driving in reverse gear it is necessary to have a reverse audible alarm , a spotter and a rear view mirror.

Most of the work that engineers do with fluids occurs in nature. True False

Answers

True depending the jobs

Answer:

It's False

Explanation:

I did the assignment

Two technicians are discussing hd-obd for trucks technician a says that the simplest most familiar definition is the diagnostic function of electronic control system to identify or self-diagnose system fault and report fault codes technician b says automotive and light duty truck versions of OBD is called OBD2 who is correct

Answers

Answer:

Two technicians are discussing HD-OBD for trucks

Technician a says that the simplest most familiar definition is the diagnostic function of electronic control system to identify or self-diagnose system fault and report fault codes.

Technician A is correct.

Explanation:

Onboard Diagnostics (OBD) is a vehicle's self-diagnostic tool which enables technicians to access the diagnostic information for the purpose of performance monitoring and analyzing repair needs of vehicles.  OBD2 is the diagnostic system that is included in every vehicle made after 1996.  The diagnostics can check the engine and other vehicle systems and also communicate possible vehicular glitches that happen.

A small probe P is gently forced against the circular surface with a vertical force F as shown . Determine the n- and t-components of this force as functions of the horizontal positions.

Answers

This question is incomplete, its missing an image which will be uploaded along this Answer.

Answer:

the normal component of force F_n is F((√(r²-s²)) / r)

the tangential component of force F_t is F(s/r)

Explanation:

Given the data in the image;

from the free body diagram, we write the expression for ∅

sin∅ = s/r

cos∅ = (√(r²-s²)) / r

now expression for normal component of force is;

F_n = Fcos∅

we substitute

F_n = F((√(r²-s²)) / r)

Therefore, the normal component of force F_n is F((√(r²-s²)) / r)

Also for force F_t

F_t = Fsin∅

we substitute

F_t = F(s/r)

Therefore, the tangential component of force F_t is F(s/r)

What should Kimi have done to ensure that she was acting legally and ethically?

Answers

Answer:

Kimi have done to ensure that she was acting legally and ethically by following the measure that are discussed below in detail.

Explanation:

Legal measures are those measures that are outlined in regulatory laws. Ethical measures are based on the human postulates of morality and wrongdoing. The distinctions between them are these: Legal measures are based on transcribed law, while ethical measures are based on human rights and violations.

When handling chemicals and solvents, technicians are recommended to

Answers

Answer:

To wear PPEHave prior knowledge of explosive levels and elemental propertiesKnow procedure to eliminate any threat

Answer

have PPE on wash hands after

Explanation:

The powertrain system is one of the major systems on the vehicle. Tech A states that this system helps to power the vehicle down the road. Tech B states that this system usually contains the engine and transmission. Who is correct?

Answers

Answer:

The powertrain system is one of the major systems on the vehicle.

Tech B states that this system usually contains the engine and transmission.

Technician B is correct.

Explanation:

The powertrain system contains three interconnected systems: the engine, the transmission, and the drivetrain.  The engine part is the power source of the powertrain that ensures vehicular movement.  The transmission system converts the engine's power into the normal movement of the vehicle.  The drivetrain consists of the transmission, driveshafts, and the axles.  These three parts of the powertrain system work seamlessly to ensure that the vehicle is able to move with some speed back and front, as may be desired.

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