A 5.0-m-diameter merry-go-round is turning with a 3.7 s period. Part A What is the speed of a child on the rim

Answer:

Given = 55kg, 4.5 m

Unknown = Work done

Formula = (mg) × d

Solution = 2425.5 J

Answer = 2425.5 J

Explanation:

Formula we use,

→ W = (mg) × d

Then the value of work done is,

→ (55 × 9.8) × 4.5

→ 539 × 4.5

→ 2425.5 J

Hence, the work done is 2425.5 J.

Answer:

The inertia of an object does not change as the objects velocity changes because the inertia will remain the same as long as the mass is the same.

:

Answer:

112.5 J

Explanation:

I calculated it by K/G BY M/S TO POTENTIAL ENERGY.

Given values are:

The change in Potential energy is:

→ [tex]\Delta PE = mgh[/tex]

By substituting the values, we get

            [tex]= 1.0\times 9.8\times 15[/tex]

            [tex]= 147 \ J[/tex]

Thus the above response is correct.  

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Answer:

I = 1.5*10⁻³ kg*m²

Explanation:

       [tex]I = \frac{1}{2}*m*r^{2} = \frac{1}{2}*0.400 kg*(0.0865m)^{2} = 1.5e-3 kg*m2[/tex]

1) The longitudinal waves move in parallel direction to the source of vibration. The transverse waves move in perpendicular direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.

2) Reflection occurs when waves bounce from a surface back toward the source. Refraction is when waves are deflected when the waves go through a substance.

3) The Law of Conservation of Energy

states that energy can neither be created

nor destroyed, it can only be transferred or

changed from one form to another.

Explanation:

Because it is the easiest branch of science to understand

Answer:

The frequencies the other string could have are 258.4 Hz and 261.6 Hz.

Explanation:

Given;

beat frequency, Fb = 1.60 Hz

frequency of the first string, F₁ = 260.00 Hz

frequency of the second string, F₂ = ?

Beat frequency is given as;

Fb = F₂ - F₁     or      Fb = F₁ - F₂

Fb + F₁ = F₂    or      F₂ = F₁ - Fb

1.6 + 260 = F₂   or   F₂ = 260 - 1.6

261.6 Hz = F₂  or   F₂ = 258.4 Hz

Therefore, the frequencies the other string could have are 258.4 Hz and 261.6 Hz.

Answer:

The time spent in air by the rock before it returns to the thrower is 4.5 s

Explanation:

Given;

initial velocity of the rock, u = 22 m/s

Neglecting air resistance, the time it takes the rock to go up equals the time it takes it to return to the thrower. This is also called time of flight.

The time to go up is calculated as;

v = u - gt

where;

v is the final velocity at the maximum height

0 = u - gt

gt = u

t = u / g

t = 22 / 9.8

t = 2.245 s

thus time to go up = 2.245 s

and time to return to the thrower = 2.245s

The total time spent in air by the rock before it returns to the thrower

 = 2.245 s + 2.245s

 = 4.5 s

Answer:

It is a value that reading in the galvanometer must be multiplied with to get the ordinary unit

Explanation:

What is a galvanometer?

A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.

A Number by which a certain function of the reading of a galvanometer must be multiplied to obtain the current value in ordinary units is a galvanometer constant

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

Answer:

Steel Wool + Oxygen, Steel wool has a hard texture but is a grayish color. It looks like it's a powder, and also that it was rusted steel wool and then broken apart converted into a powder. So Iron oxide is 7 grams and combined steel wool is 7 grams, so you may assume that the mass has been retained. Yeah, it is a chemical change since the corrosion and rust in steel wool is a chemical process, but iron oxide is triggered by a physical change.

Egg + Heat, In the center, the egg has a yellow yolk while at the edge of the egg there is a kind of liquid, but it is visible, the heat becomes hot but clear The egg transformed into a delicious food called an omelet, which was yolk staid as a liquid but got a little harder, It was retained because the eggshell was 4 grams and the fried egg is 41 grams, but the clear border around it changed color. It is a chemical transition, and it results in the creation of new particles and the chemical bonds split apart and new ones are formed

Water + Heat, Water is a clear liquid, while the heat is very hot yet transparent. Once 5 g of liquid is a gas, it'll become 5 g of water vapor. Water + Heat Water is really a clear liquid. The mass of the liquid water is simply transformed into mass of the water vapor that is freshly created. There was no chemical process although water vapor can also be converted back to water, but it only shifted from a liquid to a gas and the structure did not change.

Zinc + Hydrogen Chloride Zinc, a metal white/silver solid. A clear, colorless liquid fluid with a really low pH in hydrogen chloride In hydrogen chloride, zinc is “dissolved” while releasing a colorless vapor. The liquid, possibly still having a low pH from the remaining acid, stays a colorless liquid.As sparked with a burning wooden splint, the colorless gas gathered in a tube provides a loud bang, because it is neither air trapped in the zinc, nor absorbed in hydropower acids. Well, even if the zinc is 12 grams and not 15 grams, the gas released was 3 grams and, as we all know, 3 + 12 is 15, so you could claim also that volume has also been saved.

Sodium Hydroxide + Copper, Sulfate Sodium hydroxide is a turbid solution and bright blue crystals are formed from copper sulfate A pale blue powder of basic copper hydroxide a solution of neutral salt sulfuric acid would be produced when their solutions are mixed with each other. The combined sodium hydroxide and copper sulfate make a total of 67 grams and the product is split because the sodium sulfate is 47 grams and the copper hydroxide is 20 grams, but all together it is still 67 grams, and you could assume that now the mass has been conserved. The evidence of a response was its image of royal blue basic copper hydroxide precipitates and a neutral salt sodium solution

Explanation:

Answer:

Work done = 1/2 × Ne

Explanation:

Given that if  a force of N stretches a spring m beyond its natural​ length, how much work does it take to stretch the spring m beyond its natural​ length

Using Hook's law

Force = N

Let the extension = e

Work done in stretching spring m beyond its natural length will be

Workdone = 1/2 × Ne

Or

From Hook law,

N = Ke

Work done = 1/2 × Ke^2

Answer:

1.791 MN

Explanation:

Thrust of the rocket can be found using the relation

T = v.dm/dt, where

T = thrust off the rocket

v = speed of the rocket, 9 km/s = 9000 m/s

dm/dt = rate at which fuel burns, 199 kg/s

Substituting the values into the formula, we have

T = 9000 * 199

T = 1791000 N

T = 1.791*10^6 N

Since 1 MN = 10^6, thus

T = 1.791 MN

The thrust of the rocket in units of MN is 1.71 Meganewton.

Given the following data:

Conversion:

Relative speed = 9 km/s to m/s = 9000 m/s

To determine the thrust of the rocket in units of MN:

Mathematically, the thrust of an object is given by this formula:

[tex]Thrust = V\frac{dm}{dt}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Thrust = 9000 \times 199[/tex]

Thrust = 1,791,000 Newton

In units of MN:

1 MN = [tex]1 \times 10^6\;N[/tex]

Thrust = 1.71 MN

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Answer:

The heat absorbed in each cycle is 9,234.286 J

Explanation:

Given;

power output, P = 5 kW = 5,000 W

efficiency of the engine, e = 30 % = 0.3

thermal heat expelled, [tex]Q_c[/tex] = 6464 J

let the heat absorbed = [tex]Q_h[/tex]

The efficiency of the engine is given as;

[tex]e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.[/tex]

Therefore, the heat absorbed in each cycle is 9,234.286 J.

Answer:

0.56 km/s

Explanation:

We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.

[tex]560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s][/tex]

Therefore the speed of 0.56 [km/s] is the greatest of all

Answer:

[tex]CPD = 80[/tex]

[tex]PCD = 44[/tex]

Explanation:

Given

[tex]AB || CD[/tex]

[tex]BAD = 56[/tex]

[tex]CPA = 100[/tex]

See attachment

Required

Determine PCD and CPD

First, we need to calculate CPD

Since DPA is a straight line and CPA = 100;

We have that:

[tex]CPA + CPD = 180[/tex] --- angle on a straight theorem

Substitute 100 for CPA

[tex]100 + CPD = 180[/tex]

Subtract 100 from both sides

[tex]100-100 + CPD = 180-100[/tex]

[tex]CPD = 80[/tex]

Next, we calculate PCD

We have that:

[tex]DAB= ADC = 56[/tex]  --alternate angle

In triangle PCD

[tex]PCD + CPD + PDC = 180[/tex] --- angles in a triangle

Where

[tex]PDC = ADC = 56[/tex]

So, we have:

[tex]PCD +80 + 56 = 180[/tex]

[tex]PCD +136 = 180[/tex]

Subtract 136 from both sides

[tex]PCD = 180 - 136[/tex]

[tex]PCD = 44[/tex]

Answer:

magma

Explanation:

I wanna think that that's right if it's not in so sorry but I'm pretty sure it's magma

Intrusive magma forced up towards the ocean ridge is the force responsible for seafloor spread. The correct option is B.

Seafloor spreading is a process that occurs at mid-ocean ridges where the oceanic crust is produced by volcanic activity and then moves away from the ridge.

Plate tectonics' continental drift is explained by seafloor spreading. When oceanic plates diverge, tensile stress causes fractures in the lithosphere.

Ridge push occurs when plates are not subducting and are driven by gravity as they slide off the elevated mid-ocean ridges.

Magma rises from the fractures at a spreading center and cools on the ocean floor to form a new seabed.

The spreading rate is the rate at which an ocean basin widens due to seafloor spreading and determines whether the ridge is fast, intermediate, or slow.

Thus, the correct option is B.

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Answer:

0 m/s^2

Explanation:

If you're driving at constant speed in the same direction, your acceleration is always 0 m/s^2. acceleration is a vector, so any change in speed or direction would result in acceleration.

Answer:

3.33s

Explanation:

Given parameters:

Acceleration  = 15m/s²

Initial velocity  = 0m/s

Final velocity  = 50m/s

Unknown:

Time taken for the acceleration  = ?

Solution:

To solve this problem, we must understand that acceleration is the rate of change of velocity with time.

Mathematically;

           a  = [tex]\frac{v - u}{t}[/tex]  

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

     So;

          15  = [tex]\frac{50 - 0}{t}[/tex]  

           15t  = 50

              t  = 3.33s

Answer:

[tex]t = 0.55[/tex]

Explanation:

Given

[tex]Height, s = 1.5m[/tex]

[tex]Velocity, v = 70m/s[/tex]

Required

Determine the time to hit the ground

Using free fall formula:

[tex]S = \frac{1}{2}gt^2[/tex]

Take g as 9.8 and substitute value for S

[tex]1.5 = \frac{1}{2} * 9.8 * t^2[/tex]

[tex]1.5 = 4.9 * t^2[/tex]

Make t^2 the subject

[tex]t^2 = \frac{1.5}{4.9}[/tex]

[tex]t^2 = 0.30612244898[/tex]

Solve for t

[tex]t = \sqrt{0.30612244898[/tex]

[tex]t = 0.55[/tex] -- approximated

Answer:

L/E =de/dl so dl is 10m de=4m E=5N

Explanation:

L=(de x E)/dl = 2N

so when load is < effort it is speed multiplayer

Pretty sure answer is B

due to the fact your exerting extra force down on the lawn mower to move it

Answer:

its it filled with energy

Answer:

The light slows down.

Explanation:

Answer:

25 N

If you’re doing ck-12

The object may be swung with maximum velocity of 7.07 m/s without breaking the string.

The centripetal force definition states that: The force applied to an item in curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.

Newtons are used to measure centripetal force.

Given that:

mass of the object = 0.500 kg.

The length of the string = 1.00 m.

If the maximum speed of the object be v,

maximum centripetal force be = 0.5v²/1.0 N = v²/2 N.

As the maximum force the string can withstand without breaking is 25.0 N,

25.0 = v²/2

⇒ v = 5√2 m/s = 7.07 m/s.

Hence,   the object may be swung with maximum velocity of 7.07 m/s without breaking the string.

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Answer:

c) Aeroplane

Explanation:

The aeroplane has the greatest mass than the other three objects, so it experiences the greatest gravitational force. Hence, the option (c) is the answer.

Answer:

0 m/s2

Explanation:

khan

Answer:

a spring scale

Explanation:

i think it is correct

Solution :

The expression for the intensity of light is given by :

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a \sin \theta}{\lambda}}{\frac{\pi a \sin \theta}{\lambda} }\right)^2$[/tex]

For a small angle, θ

sin θ = tan θ

        [tex]$=\frac{y}{L}$[/tex]

Therefore the above equation becomes,

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a y}{\lambda L}}{\frac{\pi a y}{\lambda L} }\right)^2 $[/tex]

The given data is

λ = 546.1 nm

L = distance between the slit and the screen = 140 cm

  = 1.40 m

a = width of the slit

  = [tex]$0.50 \times 10^{-3} \ m$[/tex]

Therefore,

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20}}{\frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20} }\right)^2 $[/tex]

  [tex]$=\left(\frac{0.170}{9.82}\right)^2$[/tex]

 [tex]$= 2.89 \times 10^{-4} \ I_{max}$[/tex]

Therefore the fractional intensity is   [tex]$\frac{I}{I_{max}}= 2.89 \times 10^{-4} $[/tex]

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

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Answer:

the cloth is old by 1,844 years

Explanation:

The computation is shown below:

The half-life of C^(14) is 5730 years

Now

[tex]\lambda[/tex] =1.210 × 10^-4 years^(-1)

Now

[tex]N(t) = Ce^{-\lambda\times t}[/tex]

[tex]0.8 \times (N_0) = N_0 \times e^{-\lambda \times t}\\\\ln(0.8) = (-\lambda \times t)\\\\t = \frac{-(ln(0.8))}{\lambda}[/tex]

[tex]\lambda[/tex] = .000121,

so t = 1844 yrs

hence, the cloth is old by 1,844 years