a bag of fruit contains 5 apples, 3 pears, and 6 oranges. Toby randomly selects two pieces of fruit, one at a time and does not put them back. What is the probability that the first piece of fruit Toby selects will be an orange and the second piece of fruit will be an apple? need help asap

fyi its not 2

Answers

Answer 1
the ratio of the orange to apple is 6:5 therefore the probability over is 6:5:3 what are the options?

Related Questions

Does the equation 2(3X + 8) equal 2X +16+ 4X have a solution

Answers

infinitely many solutions 

Example

Simplify left side using distributive property to 6x+16. Combine like terms (2x and 4x) on the right side to 6x+16. Both sides simplify to the same expression (left side = right side) so there are infinitely many solutions. You can plug in any real number for x and the left side will always equal the right side.

HELP PLEASE ASAP!!!!

Answers

The measure of  angle m∠PZQ is 63degrees.

How to find an angle?

A point where two or more line segments meet is called a vertex.

The vertex point also forms an angle.

Therefore,

point P is in the interior of ∠OZQ,

Hence,

<OZQ = <OZP +  m∠PZQ

The following angles are given:

m∠OZQ = 125°

m∠OZP = 62°

Substitute the given values into the expression above:

125 = 62 +  m∠PZQ

m∠PZQ = 125 - 62

m∠PZQ = 63°

Therefore, the measure of  the angle m∠PZQ is 63degrees

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Write the function whose graph is the graph of y=x³ +3, but is reflected about the y-axis.

Answers

Answer:

Reflected function is y = - x³ + 3

Step-by-step explanation:

When a function f(x) is reflected about the y-axis, the reflected function becomes g(x) = f(-x)

f(x) = x³ + 3

f(-x) = (-x)³ + 3 =-x³ + 3

Kelly wants to find out if the townspeople would be in favor of creating a local dog park. she pulls an equal number of people from several age groups and from different areas of town. Is this study likely to yield valid results? Explain.

Answers

Answer: Yes

Step-by-step explanation: Kelly's results are likely to be correct mainly because she pulled votes from several different age groups. The fact that she asked several age groups whether or not they would be in favor of creating a local dog park shows that her results are likely to yield valid results.

Solve 2(x - 3) ≥ -3 (-3 + x)

Answers

Answer:

x ≥ 3

Step-by-step explanation:

2(x - 3) ≥ -3(-3 + x)

2x - 6 ≥ 9 - 3x

5x - 6 ≥ 9

5x ≥ 15

x ≥ 3

Answer:

x ≥ 3

Step-by-step explanation:

write, calculate, divide both sides

Let f(x) = x3 + 10, g(x) = x2 - 8, and h(x) = 5x + 4. Find the rule for the function.

Answers

The rule f ( x ) - g ( x ) is given as x^3 - x^2 + 18

Given data

f(x) = x3 + 10, g(x) = x2 - 8, and h(x) = 5x + 4

How to find f(x) - g(x)

f(x) - g(x) = ( x3 + 10 ) - ( x2 - 8 )

= ( x3 + 10 ) - ( x2 - 8 )

opening the parenthesis gives

= x3 + 10 - x2 + 8

collecting like terms gives

= x3 - x2 + 18

Hence we can say that f(x) - g(x) = x3 - x2 + 18

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complete question

The complete question is attached

A universal set U consists of 19 elements. If sets A, B, and C are proper subsets of U and n(U) = 19, n(An B) = n(An K C) = n(B n C)= 9, n(An B n C) =6, and n(A U B UC) = 15, determine each of the following. a) n(A U B) b ) n ( A' UC c) n(An B)'

Answers

Using Venn sets, the cardinalities are given as follows:

a) n(A U B) = 15.

b) n(A' U C) = 16.

c) n(A ∩ B)' = 10.

What are Venn probability?

Venn amounts relates the cardinality of sets that intersect with each other.

For this problem, the sets are the ones given in this problem, A, B and C, while U is the universal set.

For this problem, the cardinalities are given as follows:

n(U) = 19.n(A ∩ B) = n(A ∩ C) = n(B ∩ C) = 9.n(A ∩ B ∩ C) = 6.n(A U B UC) = 15

Hence:

6 elements belong to all the sets.9 - 6 = 3 belong to these intersections but not the remaining set: A and B, A and C, B and C.15 belong to the union of all of them, hence 4 belong to none.15 - (6 + 3 x 3) = 0 belong to only one set.

Hence:

n(A U B) = 15, as from the final bullet point, there are no elements that belong to only set C.For item b, 6(all) + 3(only A and C) + 3 (only B and C) = 12 elements belong to C, and 4 do not belong to A(the 3 to only B and C is already counted), hence: n(A' U C) = 16, as 12 + 4 = 16.For item c, n(A ∩ B) = 9, hence n(A ∩ B)' = n(U) - n(A ∩ B) = 19 - 9 = 10.

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The area of a rectangular barn is 119 square feet. its length is 10 feet longer than the width. find the length and width of the wall of the barn.

Answers

The length of the field with area 119 square feet is 17 feet and the width of the feet is 7 feet.

The area is the total region or space in two dimension that is covered by a figure , surface or object. Area of a rectangle is calculated by the product of its length and width.

A rectangle has 4 sides where each pair of  opposite side is equal .The length of a rectangle is normally the longer side and the width defines the shorter side.

Given the area of the barn is 119 square feet.

Let us consider the width of the barn to be x feet. As the length is 10 feet longer than the width then we will find the length to be ( x +10 ) feet.

Area = length × width

or, 119 = x × (x+10)

or, 119 = x² +10x

or, x² +10x - 119=0

Now we will solve the quadratic equation thus formed by middle term-factorization method:

or, x² +17x - 7x - 119 = 0

or, x ( x + 17 ) - 7 ( x + 17) = 0

or, ( x + 17 ) ( x - 7 ) = 0

Now either x + 17 = 0 or x - 7 =0

Therefore either x = 7  

or, x = -17 (The width cannot be a negative value)

Width = 7 feet and length = 7 + 10 = 17 feet.

Therefore the length of the field is 17 feet and the width of the feet is 7 feet.

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Which expression is equivalent to the quotient of x and 8 times the difference of 19 and x?

Answers

Answer:

(x/8)(19 - x)

Step-by-step explanation:

The quotient is the answer to a division problem.

The difference is the answer to a subtraction problem.

"Times" indicates multiplication, which you could look at it as a link between the two functions, or quantities (them being the constants and variables sectioned off into parenthesis).

i really need you guys help.

Answers

Answer:

y = - 8x + 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 8x - 2 ← is in slope- intercept form

with slope m = - 8

• Parallel lines have equal slopes , then

y = - 8x + c ← is the partial equation of the parallel line

to find c substitute (- 0.5, 7 ) into the partial equation

7 = 4 + c ⇒ c = 7 - 4 = 3

y = - 8x + 3 ← equation of parallel line

Given mn, find the value of x.
20⁰

Answers

Answer:

x =20°

because m and n is parallel

Saul wants to bike 48 kilometers to taste some really good mangoes.
1. Write an equation that represents how many hours (t) the48km start text, k, m, end text trip will take if Saul bikes at a constant rate of r kilometers per hour.
2. How many hours will the48km48, end text trip take if Saul bikes at a constant rate of 20 kilometers per hour?
hours

Answers

Answer:

[tex]\textsf{1)} \quad t=\dfrac{48}{r}[/tex]

[tex]\textsf{2)} \quad \sf 2.4\:hours=2\:hours\:24\:minutes[/tex]

Step-by-step explanation:

Part 1

[tex]\boxed{\sf Time=\dfrac{Distance}{Speed}}[/tex]

Given:

Time = t hoursDistance = 48 kmSpeed = r km/h

Substitute the given values into the formula:

[tex]\implies t=\dfrac{48}{r}[/tex]

Part 2

Substitute r = 20 km/h into the derived equation from part 1 and solve for t:

[tex]\implies t=\dfrac{48}{20}=2.4\: \sf hours[/tex]

Note: 2.4 hours = 2 hours 24 minutes

Answer: 2.4 hours

Step-by-step explanation: t=time

         r=rate        so question one is equal to t=48/r

then question 2 is 48/20=2.4

Determine which of the numbers below is a possible order of magnitude estimate of the
quantity described.
The weight of a grain of rice.
Select one:
O a. 0.000001 ounces
O b. 0.0006 ounces
OC.0.006 ounces
O d. 0.01 ounces

Answers

A 0.000001 ounces that is the answer

Suppose Albers Elementary School has 76 teachers and Bothel Elementary School has 24 teachers. If 3 teachers teach at both Albers and Bothel, compute the total number of teachers employed at Albers and Bothel combined.

Answers

The number of teachers that work in both schools is 97.

What is an addition?

The addition is a way of combining things and counting them together as one large group.

We have,

Number of teachers in Alberts Elementary school = 76

Number of teachers in Bothel Elementary school = 24

Number of teachers that work in both schools = 3

The number of teachers that work in both schools:

= 76 + 24 - 3

We are subtracting 3 from the total because 3 teachers that work in both schools have been added twice.

= 100 - 3

= 97

Thus the number of teachers that work in both schools is 97.

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1. If you deposit P3,000 in BPI bank account that pays 0.125% interest annually, how much will be in your account after 3 years?

2. If you deposit money today in an account that pays 10.5% annual interest, how long will it take to double your money?

3. What is the future value of a 3% 7-year ordinary annuity that pays20,000 each year?

4. (refer to #3) if this were an annuity due, what would its future value be?

5. I want to retire in 20 years. I currently have P 1,250,000 and I will need P20 million at retirement. What annual interest rate must I earn to reach my goal, assuming this is my only investment fund?

Round off your answer up to four decimal places.

Answers

The amount that would be in the account kept with BPI bank in 3 years is P3,011.2640

It would 6.9422 years for the deposit to double if interest rate is 10,5%

What is future value of immediate amount?

The future value of deposit today in 3 years means its future equivalent when the amount has earned interest over the 3 years period

FV=PV*(1+r)^N

FV=future value after 3 years=unknown

PV=immediate deposit=3,000

r=annual interest rate=0.125%

N=number of years that the deposit lasted=3

FV=3000*(1+0.125%)^3

FV=P3,011.2640

Time taken to double:

FV=future value=3000*2=6000

PV=3000

r=annual interest rate=10.5%

N=number of years that it takes initial deposit to double=unknown

6000=3000*(1+10.5%)^N

6000/3000=(1.105)^N

2=(1.105)^N

take log of both sides

ln(2)=N*ln(1.105)

N=ln(2)/ln(1.105)

N=6.9422 years

Annuity:

FV=PMT*(1+r)^N-1/r

FV=future value of annuity=unknown

PMT=annual payment=20000

r=interest rate=3%

N=number of annual payments=7

FV=20000*(1+3%)^7-1/7%

FV= 153,249.2436

FV=PMT*(1+r)^N-1/r*(1+r)

FV=20000*(1+3%)^7-1/7%*(1+7%)

FV= 157,846.7209

20,000,000=1,250,000*(1+r)^20

20,000,000/1,250,000=(1+r)^20

16=(1+r)^20

(16)^1=(1+r)^20

divide indexes on both sides by 20

(16)^(1/20)=1+r

r=(16)^(1/20)-1

r=14.8698%

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Determine whether the relation is a function. Explain. { ( 2 , 5 ) , ( 4 , − 2 ) , ( 3 , 3 ) , ( 5 , 4 ) , ( − 2 , 5 ) } Multiple choice question. cross out A) Yes; for each element of the domain, there is only one element of the range. cross out B) Yes; for each element of the range, there is only one element of the domain. cross out C) No; the elements –2, 3, 4, and 5 are in both the domain and the range. cross out D) No; the element 5 occurs twice in the range.

Answers

Yes; for each element of the domain, there is only one element of the range.

Function and relations

For a relation in coordinate form to be a function, there is must nor be repetition in the value of its coordinate.

Given the following relation as shown  { ( 2 , 5 ) , ( 4 , − 2 ) , ( 3 , 3 ) , ( 5 , 4 ) , ( − 2 , 5 ) }, since there is no repetition in its domain values, hence the relation is a function.

We can conclude therefore that Yes; for each element of the domain, there is only one element of the range.

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In a class in which the final course grades depends entirely on the average of four equally weighted 100 point test David has scored 81, 92, and 74 on the first three. What range of scores on the fourth test will give David a b for the semester ( an average between 80 and 89 inclusive) assume that all the test scores have a non negative value

Answers

The range of scores on the fourth test to give David a B grade for the semester is at least 73 but less than or equal to 89.

What is a range?

A range refers to the difference between the lowest and the highest score.

A range of scores gives two values, the lowest and the highest scores.

Data and Calculations:

Scores secured by David = 81, 92, and 74

Total scores in three exams = 247

The average score for a B grade is:

80  ≤  B grade  < 90      ["at least" means ≤]

Therefore,

80 ≤ (81 + 92 + 74 + x) / 4  < 89  [assume equal weights for exams]

80 ≤ (247 + x) / 4 ≤ 89  [add values]

320 ≤ (247 + x) ≤ 356   [multiply by 4, retains a sense of inequality]

73 ≤ x < 109                   [subtracting 247 retains a sense of inequality]

Since exams are graded on 100 points, David cannot score 109, so the upper limit is put at 89.

Thus, the exam grade in the fourth test must be at least 73 but less than or equal to 89 to get a B average.

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Which of the following values are solutions to the given
equation?
|x + 2| = 5
Be sure to select ALL numbers which are solutions.
(Select all that apply.)
x = -5
x = -2
x = 3
x = -7
x = -3
x = 7

Answers

Answer:

X= -7

X = 3

Step-by-step explanation:

| x + 2| = 5

|-7 + 2| = 5

|-5| = 5

5 = 5

|x + 2| = 5

|3 + 2| = 5

|5| = 5

5 = 5

X= -7

X = 3

24. The relative frequency of getting a HEAD when tossing a coin is ⅜. How many HEADS would you expect if the coin is tossed 400 times?

Answers

Is there a picture you can take of it

Explain how to graph the line with the equation y = 3/4x - 5

Answers

Answer:

A graphing calculator can help you.

Here is the graph, it is in the photo.

Give the slope of a line that is perpendicular to the line 2x+2y=1 .
-1

Answers

Answer:

- 1

Step-by-step explanation:

2x + 2y = 1

=> 2y = - 2x + 1

=> y = - x + 1

=> Slope = - 1

Consider the three functions below.
- (4) -(41* *--*
Which statement is true?
The range of h(x) is y> 0.
The domain of g(x) is y> 0.
The ranges of f(x) and h(x) are different from the range of g),
The domains of f(x) and g(x) are different from the domain of h(x).

Answers

Answer: c

Step-by-step explanation:

Please help! Thank you

Answers

2/11 sq ft. Hope this helps
A might be the answer.

Helppppppppp pleaseeeeee

Answers

Answer:

The answer is yes. Since there is no x^2

yes there are no exponents in y=3x

[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]​

Answers

(A) (m,n) = g(n,m) for all positive integers m,n,

(B) (m,n + 1) = g(m + 1,n) for all positive integers m,n,

(D) (2m,2n) = (g(m,n))2 for all positive integers m,n

Explanation

[tex] \rm f(m,n,p) = \sum \limits_{i = 0}^{p} {}^{m} C_{i} \: \: {}^{n + i} C_{p} \: \: {}^{p + n} C_{p - i}[/tex]

[tex]\rm {}^{m} C_{i} \: \: {}^{n + i} C_{p} \: \: {}^{p + n} C_{p - i}[/tex]

[tex]\rm {}^{m} C_{i} \dfrac{(n + i)!}{p!(n - p + i)!} \times \dfrac{(n + p)!}{(p - i)!(n + i)!} [/tex]

[tex]\rm {}^{m} C_{i} \times \dfrac{(n + p)!}{p!} \times \dfrac{1!}{(n -p + i)!(p - i)!} [/tex]

[tex]\rm {}^{m} C_{i} \times \dfrac{(n + p)!}{p!} \times \dfrac{1!}{(n -p + i)!(p - i)!} [/tex]

[tex]\rm {}^{m} C_{i} \times \dfrac{(n + p)!}{p!n!} \times \dfrac{n!}{(n -p + i)!(p - i)!} [/tex]

[tex]\rm {}^{m} C_{i} \: \: {}^{n + p} C_{p} \: \: {}^{n} C_{p - i} \: \: \{{}^{m} C_{i} \: \: {}^{n } C_{p - i} = {}^{m + n} C_{p } \}[/tex]

[tex]\rm {}^{m} C_{i} \: \: {}^{n + p} C_{p} \: \: {}^{n} C_{p - i} \: \: \{{}^{m} C_{i} \: \: {}^{n } C_{p - i} = {}^{m + n} C_{p } \}[/tex]

[tex] \rm f(m,n,p) = {}^{n + p} C_{p}{}^{m + n} C_{p}[/tex]

[tex] \rm \dfrac{f(m,n,p)}{{}^{n + p} C_{p}} = {}^{m + n} C_{p}[/tex]

Now,

[tex] \rm g(m,n) = \sum \limits_{p = 0}^{m + n} \dfrac{f(m,n,p)}{{}^{n + p} C_{p}} [/tex]

[tex] \rm g(m,n) = \sum \limits_{p = 0}^{m + n} {}^{m + n} C_{p}[/tex]

[tex] \rm g (m,n) = {2}^{m + n} [/tex]

[tex] \rm(A) \: g(m,n) = q(n,m)[/tex]

[tex] \rm(B) \: g(m,n + 1) = {2}^{m + n + 1} [/tex]

[tex] \rm g(m + n,n ) = {2}^{m + 1 + n} [/tex]

[tex] \rm(D) \: g(2m,2n) = {2}^{2m + 2n} [/tex]

[tex] = \rm( {2}^{m + n} {)}^{2} [/tex]

[tex] = \rm(g(m,n)) {}^{2} [/tex]

Amount of Amy's pocket money each day is 3 times as much as the pocket money of Flora's. And the amount of Paul's pocket money is $7 more than Amy's. If they have $980 of pocket money each week, how much pocket money does Paul have each day? ​

Answers

Answer:-

Paul has $64 pocket money each day.

Explanantion:-

Let amy ,flora and Paul 's pocket money be x,y and z respectively.

So,

By the question :

x = 3y

So, y = x/3 - eqn i

z = 7 + x - eqn ii

7(x + y + z) = 980

x + y + z = 140

Now,

x + y+ z = 140

x + x/3 + 7 + x = 140

or, 2x + x/3 = 133

or, 6x + x = 399

so, x = 399/7

so, x = $57

Now,

z = 7 + x

= 7 + $57

= $64

Simple Math Range and domain help

Answers

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Here we go ~

Domain : All possible values of x for which a function is defined.

According to given graph, the curve extends to infinity on both sides on x - axis, so it is defined for all real values.

i.e : Domain : All real

Range : All possible values of y for x, as per the given function

As per the given graph, the graph extends to infinity on lower end, but has maximum value of 0.

i.e Range : [tex]\boxed{ \sf y < 0} [/tex]

you are stinky . i hope you know tht

Answers

Step-by-step explanation:

wot. that's not even a qn bro

Step-by-step explanation:

the difference between the numbers are 5

so this is an arthimetic sequence with D=5

5n-7 is the formula

An object is moving at a speed of 360 kilometers per hour. Express this speed in miles per day. Round your answer to the nearest whole number.

Answers

About 5368.6 miles per day. Rounded to the nearest whole number would be 5,369

determine the inverse of the function​

Answers

Answer:

[tex]f^{-1}(x)= \dfrac{1}{2}\ln \left(-\dfrac{x^2}{x^2-1}\right), \quad \textsf{for}\:\{x:0 < x < 1\}[/tex]

Step-by-step explanation:

Given function:

[tex]f(x)=\dfrac{e^x}{\sqrt{e^{2x}+1}}[/tex]

The domain of the given function is unrestricted:  {x : x ∈ R}

The range of the given function is restricted:  {f(x) : 0 < f(x) < 1}

To find the inverse of a function, swap x and y:

[tex]\implies x=\dfrac{e^y}{\sqrt{e^{2y}+1}}[/tex]

Rearrange the equation to make y the subject:

[tex]\implies x\sqrt{e^{2y}+1}=e^y[/tex]

[tex]\implies x^2(e^{2y}+1)=e^{2y}[/tex]

[tex]\implies x^2e^{2y}+x^2=e^{2y}[/tex]

[tex]\implies x^2e^{2y}-e^{2y}=-x^2[/tex]

[tex]\implies e^{2y}(x^2-1)=-x^2[/tex]

[tex]\implies e^{2y}=-\dfrac{x^2}{x^2-1}[/tex]

[tex]\implies \ln e^{2y}= \ln \left(-\dfrac{x^2}{x^2-1}\right)[/tex]

[tex]\implies 2y \ln e= \ln \left(-\dfrac{x^2}{x^2-1}\right)[/tex]

[tex]\implies 2y(1)= \ln \left(-\dfrac{x^2}{x^2-1}\right)[/tex]

[tex]\implies 2y= \ln \left(-\dfrac{x^2}{x^2-1}\right)[/tex]

[tex]\implies y= \dfrac{1}{2}\ln \left(-\dfrac{x^2}{x^2-1}\right)[/tex]

Replace y with f⁻¹(x):

[tex]\implies f^{-1}(x)= \dfrac{1}{2}\ln \left(-\dfrac{x^2}{x^2-1}\right)[/tex]

The domain of the inverse of a function is the same as the range of the original function.  Therefore, the domain of the inverse function is restricted to {x : 0 < x < 1}.

Therefore, the inverse of the given function is:

[tex]f^{-1}(x)= \dfrac{1}{2}\ln \left(-\dfrac{x^2}{x^2-1}\right), \quad \textsf{for}\:\{x:0 < x < 1\}[/tex]

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