The displacement of the ball rolled down the incline is determined as 0.54 m.
What is displacement?
The displacement of an object is the change in the position of the object.
Displacement is a vector quantity and has a direction and magnitude. It is represented as an arrow that points from the starting position to the final position.
The displacement of the ball is calculated as follows;
d = Δx
where;
Δx is change in position of the objectd = 0.86 m - 0.32 m
d = 0.54 m
Thus, the displacement of the ball rolled down the incline is determined as 0.54 m.
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The complete question is below;
A ball is rolled down an incline from the 0.86 meter mark to the 0.32 meter mark. Find the displacement of the ball.
What does someone with low self esteem look like
They feel they are, overall, bad people without any particular skills or value, when they are not.
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A nail of mass ,7.0g is held horizontally and is hit by a hammer of mass 0.25kg moving at 10ms −1. The hammer remains in contact with the nail during and after the blow.
If velocity of nail and hammer immediately after the blow is 9.7ms-1 Calculate the impulse transferred to the nail
Answer:
The impulse transferred to the nail is 0.01 kg*m/s.
Explanation:
The impulse (J) transferred to the nail can be found using the following equation:
[tex] J = \Delta p = p_{f} - p_{i} [/tex]
Where:
[tex]p_{f}[/tex]: is the final momentum
[tex]p_{i}[/tex]: is the initial momentum
The initial momentum is given by:
[tex] p_{i} = m_{1}v_{1_{i}} + m_{2}v_{2_{i}} [/tex]
Where 1 is for the hammer and 2 is for the nail.
Since the hammer is moving down (in the negative direction):
[tex]v_{1_{i}} = -10 m/s [/tex]
And because the nail is not moving:
[tex]v_{2_{i}}= 0[/tex]
[tex] p_{i} = m_{1}v_{1_{i}} = 0.25 kg*(-10 m/s) = -2.5 kg*m/s [/tex]
Now, the final momentum can be found taking into account that the hammer remains in contact with the nail during and after the blow:
[tex] p_{f} = m_{1}v_{1_{f}} + m_{2}v_{2_{f}} [/tex]
Since the hammer and the nail are moving in the negative direction:
[tex]v_{1_{f}}[/tex] = [tex]v_{2_{f}}[/tex] = -9.7 m/s
[tex] p_{f} = -9.7 m/s(7 \cdot 10^{-3} kg + 0.25 kg) = -2.49 kg*m/s [/tex]
Finally, the impulse is:
[tex] J = p_{f} - p_{i} = - 2.49 kg*m/s + 2.50 kg*m/s = 0.01 kg*m/s [/tex]
Therefore, the impulse transferred to the nail is 0.01 kg*m/s.
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What is ther atomic number of an element that has 2 electrons, 3 protons,
and 4 neutrons?
Answer:
9
Explanation:
A atomic number is the addition of every number
HELP PLS I CANT FIND THHE ANSWER ANYWHERE IM BEING TIMED TOO!!
Answer:
I think It's magna! Let me know if It's right.
If a lightning occurred exactly 1 mile from your location, how many seconds will it take for the sound waves created by the thunder to reach your ears at 343 m/s?
Answer:
5 seconds
Explanation:
sound travels 1 km in roughly 3 secs so 1 mile in roughly 5 secs.
Iwill need to use more force to stopa
O Lighter mass
O Heavier mass
Answer:
a heavier mass
Explanation:
If a cannonball were launched with a speed of 35m/s at a 50° angle from the height of 0m, what would be the cannonball's range?
The range of a cannonball launched with a speed of 35 m/s at an angle of 50 would be 119.1 meters.
The launching of a cannonball is a case of projectile motion.
The formula for the range(R) of a projectile is
R = 2 u² sin(θ) cos(θ)/g
Here,
u = initial speed with which the projectile is launched = 35 m/s
θ = Angle at which projectile is launched = 50°
R = 2 (35)² sin(50) cos(50)/ 9.8
R = 2 x 1225 x 0.76 x 0.64/9.8
R = 119.1 m
Thus, The range of a cannonball launched with a speed of 35 m/s at an angle of 50 would be 119.1 meters.
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The radius of the spherical ball is 4.32_+0.01m.what does it mean?
The estimated error rate for spherical volume measurements is 0.694%.Percent error is the difference between the estimated value and the actual value compared to the actual value, expressed as a percentage. So the percent error is the relative error multiplied by 100.
To calculate the Percent error
Subtract the actual value from the estimated value
Divide the result from step 1 by the actual value
to get the total percentage Multiply the result by 100
Formula,
Error Rate = ((Estimated Number – Actual Number)/Actual Number) x 100
from the given data
V=(4/3)πr3
=337.53cm³
so
((339.87-337.53)/337.53)x100
=0.694
So from the given data and substituting that data in the formula , the percentage error to estimate the measurement of the volume of the sphere is 0.694%.
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3. a rocket, initially at rest, is fired vertically with a net upward acceleration of 12 m/s2 . at an altitude of 0.50 km, the engine of the rocket cuts off. a. how long is it in the air?
As a result, the rocket will soar to a maximum height of 0.5 km plus 510.2 m. One kilometre is equal to this. This becomes the beginning velocity for the second stage, and the acceleration in free fall is equal to -g.
0=1002−2×9.8×h
∴h=10,0002×9.8=510.2xm
Is a rocket's acceleration constant?As a result, although there is a constant force acting on the rocket, the resulting acceleration is not constant; rather, it is constantly rising. The amount of fuel burnt will thus have an impact on the rocket's overall change in velocity, and this dependency is nonlinear.
This indicates that the rocket's speed is increasing by 90 m/s every second. This is nine times the gravitational acceleration that is typical.
The space shuttle must accelerate from zero to 8,000 metres per second (almost 18,000 miles per hour) in eight and a half minutes in order to reach the minimum height needed to circle the Earth.
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Your "weight" is properly defined as
Answer:
how heavy you are and how light you are
Explanation:
A 1520 kg car is rolling
down a frictionless
14.4° slope. What is
its acceleration?
Answer:
a = 2.44 m/s²
Explanation:
The Net force acting on the car downwards the plane will be equal to the component of the weight that is parallel to the plane.
Thus;
mg(sin θ) = ma
Thus;. g(sin θ) = a
g is acceleration due to gravity = 9.81 m/s²
θ = 14.4°
Thus;
9.81 × sin 14.4 = a
a = 2.44 m/s²
Answer:
2.44
Explanation:
If your on Acellus the correct answer is 2.44
Give one example which describes Newton's first law of motion.
Answer:
a moving car
Explanation:
a body remains in its constant state unless un extenal force is applied.
What is the difference between a neutralization reaction and a double-displacement reaction? (1 point) Double-displacement reactions are always redox reactions. Double-displacement reactions always involve acids and bases. Neutralization reactions always produce water and a salt. Neutralization reactions are always combustion reactions.
Answer:
Neutralization reactions always produce water and a salt.
Explanation:
There are different types of chemical reactions that occurs. Two of them are neutralization and double-displacement reaction. Neutralization reaction is the reaction between an acid and a base to give an acid salt and water as products. For example:
2NaOH (base) + H2SO4 (acid) → Na2SO4 (salt) + 2H2O (water)
On the other hand, Double displacement reaction is the reaction that involves an ion exchange between the reactants to form new products. This ionic exchange occurs in such a way that two reactants form two new products. For example:
2NaCl + Ca(NO3)2 → CaCl2 + 2NaNO3
Therefore, the major difference between these two types of reactions is that: NEUTRALIZATION MUST ALWAYS PRODUCE WATER AND SALT AS PRODUCTS.
The first five questions refer to the following problem:
A model rocket lifts off with an upward thrust of 35 Newtons. It has a mass of 2.5 kilograms and a weight of 25 Newtons. How quickly does the rocket accelerate?
What is the first equation you would use to answer this question?
Question 3 options:
Fnet=F↑−F↓
Δt=Δdv
Δd=d2−d1
F12=−F21
Answer:
Δd=d2−d1Explanation:
good morningWhat area of science compares and describes quantities and movements of matter and energy?.
Physics is the area of science that compares and describes quantities and movements of matter and energy. The correct option is option 2.
What is physics?Physics is the study of matter and energy in space and time, as well as their interactions. The interactions of particles and physical objects are governed by energy and the fundamental forces of nature. Science's study of matter, its motion through space and time, as well as related ideas like energy and force, is known as physics.
Therefore, the branch of science known as physics compares and describes the amounts and motions of matter and energy. The right choice is number two.
The complete question is given below:-
What area of science compares and describes quantities and movements of matter and energy?
1. earth science
2. physics
3. chemistry
4. biology
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determine the values of mm and nn when the following charge of a proton is written in scientific notation: 0.000000000000000000160 cc . enter mm and nn , separated by commas.
The value of m = 1.6 and n = -19
What do you understand by charge?When there are more or fewer protons in an atom than electrons, the substance has an electric charge. While electrons have a negative charge, protons have a positive charge. If a substance has more protons than electrons, it is positively charged; if it has more electrons, it is negatively charged.
The ability to conduct electricity is a characteristic of many fundamental, or subatomic, components of matter. As an illustration, protons and neutrons both have positive charges but electrons have a negative charge.
given: [tex]q=0.000000000000000000160c[/tex]
Scientific notation of [tex]q= 1.6 X 10^{-19}[/tex]
now compare with the standard form [tex]m X 10^{n}[/tex]
we can say m = 1.6 and n = -19
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Which could be an example of an unbalanced force?
A. A plate sitting on a dining room table.
B. Earth orbiting the Sun
C. A ball at the top of a hill that is not moving.
D. A baseball that has been thrown to home plate.
Answer:i think its D
Explanation:
Which type of motor is shown below?
A.
AC motor
B.
brush motor
C.
DC motor
D.
magnetic motor
E.
split ring motor
Answer:
AC motor........A
Explanation:
Plato, an AC motor is much simpler than a DC motor. As alternating current passes through the coil, it becomes magnetized. Since the current is alternating, the north and south ends keep switching.
Answer:
magnetic
Explanation:
PLATO
You are classifying an organism that is unfamiliar to you.
Which characteristic would be most helpful in identifying it?
A. energy source
B. behavior
C. structure
D. communication
O E. movement
Answer:
I know that we can identify it
Explanation:
C. structure
Answer:
C
Explanation:
In order to know what organism is it, you must obeserve its structure, behavior, movement but the most important is structure.
What perspective emphasizes the human capacity of personal growth?
The ability of people to grow personally is highlighted by the humanistic psychology viewpoint.
In opposition to psychoanalytic theory and behaviorism, the humanistic perspective gained popularity in the middle of the 20th century. It highlights how healthy people develop and a person's innate desire for self-actualization and creativity. The humanistic perspective seeks to understand a person as a complete rather than just via one particular component of their personality. It is a subfield of psychology that deals with the notion of being wholly original and distinctive. A school of thought or philosophy known as "psychological perspective" is one that would help someone comprehend someone else's conduct.
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The freezing point of water is a (physical/chemical) property. The ability of oxygen to react with iron to cause rust is a (physical/chemical) property.
The freezing Point of water is a physical property
The ability of oxygen to react with iron to cause rust is chemical property
Explanation:
A rectangular tank is filled with water to a depth of 4m. Calculate the pressure at the bottom of the tank. PLEASEEE HELP!!
The pressure in a liquid at a given depth is called the hydrostatic pressure. This can be calculated using the hydrostatic equation:
P = ρgh
P = (1000 kg/m³)(9.8 m/s²)(4 m)
P = 39200 PaAnswer:
P = ρgh
P = (1000 kg/m³)(9.8 m/s²)(4 m)
P = 39200 Pa
Explanation:
In the case of the water stored in a tank, the pressure at its bottom is the weight acting on a unit area of the surface where the tank is kept. To turn that into an equation: Pressure = weight/area, and weight = mass (m) * acceleration due to gravity (g). This means pressure = m * g/ area
An engine has 180,000 W of power and can accelerate from rest to a top speed in 9 s. How much work did the engine do?
Answer:
1620000J
Explanation:
Given parameters:
Power = 180000W
Time = 9s
Unknown:
Work done by the engine = ?
Solution:
Power is the rate at which work is being done.
Now,
Power = [tex]\frac{Work done }{time}[/tex]
Work done = Power x time taken
Work done = 180000 x 9 = 1620000J
The section of a longitudinal wave in which the particles are densely packed together
giving an area of high pressure is known as the
Answer:
compressions or refractions
Explanation:
a window washer does not want to change her position. what does she want the forces acting on her to be? small small balanced balanced unbalanced unbalanced large
She must have a balanced force to act on her.
Balanced forces are forces of opposite direction and equal magnitude. These are considered to be in equilibrium. When the forces are balanced, there is no change in direction.
Therefore, the window washer would like to have a balanced force so that she doesn't fall and will maintain her balance and her position will not change.
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A model car company produces battery-powered model cars. At its maximum
acceleration, their latest model accelerates from rest to its top speed in 3.5 s.
a) While the car is travelling at its top speed, it covers 180 m in 9.0 s.
Calculate the car's maximum acceleration.
b) Calculate how fast the car would be moving if it accelerated from rest for 1.5 seconds
with its maximum acceleration.
Answer:
a) 5.714 m/s²
b) 13.33 m/s²
Explanation:
, [tex]\text{The final velocity, }\text{\ensuremath{v_{f}}}\text{ of the car is }\text{\ensuremath{\dfrac{\Delta v}{\Delta t}=}}\dfrac{{180m}}{9.0s}=20\;m/s[/tex]
The car goes from an initial velocity of 0 m/s to this final velocity in t=3.5s
Therefore the acceleration of the car is given by
[tex]\displaystyle a=\boldsymbol{\dfrac{{v}_{f}-{v}_{0}}{t}}[/tex]
where [tex]v_0[/tex] is the initial velocity
[tex]a=\dfrac{20-0}{3.5}=\dfrac{20}{3.5}=5.714\mathrm{m/s^{2}}\[/tex]
Part a
[tex]\text{Maximum\;Acceleration}}}=5.714 \;m/s^{2}[/tex]
Part b)
If the car accelerated from rest and reached final speed of 20 m/s in 1.5s instead of 3.5s then
[tex]a=\dfrac{\boldsymbol{20}}{\boldsymbol{1.5}}={\displaystyle \textbf{13.33}\;m/s^{2}}[/tex]
the metric unit of force is the newton (n) , which is kg⋅m/s2 . convert 10kg⋅cm/s2 to newtons. 1×10−1n 1 times 10 to the power of negative 2 uppercase n 1×10−2n 1 times 10 to the power of negative 5 uppercase n 1×10−5n 1 times 10 to the power of negative 6 uppercase n 1×10−6n
The metric unit of force is the newton (n) , which is kg⋅m/s2 . convert 10kg⋅cm/s2 to newtons is 1 x 10⁻¹.
Newton's LawThe three fundamental laws of classical mechanics known as Newton's laws of motion. These laws can be stated as follows : Unless acted upon by a force, a body remains at rest or in motion in a straight path at a constant speed.
First law : Unless a force acts on an item, it will not modify its motion.
Second law : An object's force is determined by multiplying its mass by its acceleration.
The third law states that every action has a corresponding and opposing reaction.
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a body of mass m is projected at an angle θ with the horizontal with an initial velocity u. the average power of gravitational force over the whole time of flight is (a) mgu cosθ (b) 1 2 mg u cosθ (c) 1 2 mgu sinθ (d) zero
When the body of mass m is projected at angle θ, the displacement is horizontal to the earth's surface, but the force of gravity is perpendicular to the motion of the body.
Therefore, the gravitational force on the body is zero.
Work done will also be zero due to zero gravitational force.
Displacement can be defined as the shortest distance covered by the object or it is the change in the position of the object.
Therefore the average power i.e. P = (Work/Time) of gravitational force over the whole time of flight is zero.
Option (d) zero
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Water at a pressure of 3.00 × 105 Pa flows through a horizontal pipe at a speed of 1.00 m/s. The pipe narrows to one-fourth its original diameter. What is the speed of the flow in the narrow section?
Answer:
The answer is "[tex]16 \ \frac{m}{s}[/tex]"
Explanation:
[tex]Pressure \ (P) = 3.00 \times 10^{5}\ Pa\\\\Velocity\ V_1 = 1.00 \ \frac{m}{s}[/tex]
Using the formula for equating the continuity equation:
[tex]\to V_1 \times A_1 = V_2 \times A_2\\\\\to A_2 = \frac{A_1}{16} \\\\\therefore \\\\\to V_2 = V_1 \times \frac{A_1}{A_2} \\\\\to V_2 = 1 \times 16 = 16 \ \frac{m}{s}[/tex]
The speed of the flow in the narrow section is [tex]16m/s[/tex].
To find the speed of the flow in the narrow section, We use equation of continuity.
[tex]V_{1}*A_{1}=V_{2}*A_{2}[/tex]
Given that , initial speed [tex]V_{1}=1m/s[/tex]
Let us consider that, initial cross-section area is[tex]A_{1}=A[/tex].
When the pipe narrows to one-fourth its original diameter.
Then, Area [tex]A_{2}=\frac{A}{4^{2} }=\frac{A}{16}[/tex]
Substituting values in above equation.
[tex]1*A=V_{2}*\frac{A}{16}\\\\V_{2}=16m/s[/tex]
Hence, the speed of the flow in the narrow section is [tex]16m/s[/tex].
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how can a cell quickly decrease its s/v by decreasing its surface area, while keeping its volume about the same
The surface area to volume ratio declines with cell expansion. This is due to the fact that as a cell expands, its volume (internal contents) develops more quickly than its surface area (its cell membrane). Because the cell membrane needs to have enough surface area for the transfer of materials into and out of the cell, this is an issue for cells. The cell must go through mitotic cell division or cease to function if its volume grows to the point where not enough materials can be carried into and out of it. Cells are so tiny because of this.
A cell's surface area to volume ratio will decrease as its surface area will decrease keeping the volume constant. A cell with a smaller surface area to volume ratio has less plasma membrane and more volume.
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