A ball is thrown with a velocity of 10 m/s at a 25º from the horizontal. How far does the ball travel?

Answers

Answer 1

Answer:

use a=v-u/t formula it will be correct


Related Questions

The gravitational force between two objects is 3600 N.
What will be the gravitational
force between the objects the
mass of each object is reduced to one-third of its original mass?
O 400 N
O 1200 N
O 10,800 N
O 32,400 N

Answers

The gravitational force between the two objects whose mass is reduced to one-third of its original mass is 400 N

We know that,

F = G[tex]m_{1}[/tex][tex]m_{2}[/tex] / r²

F = Gravitational force

G = Gravitational constant

[tex]m_{1}[/tex], [tex]m_{2}[/tex] = Mass of two objects

r = Distance between two objects

G = 3600 N

[tex]m_{1}'[/tex] = [tex]m_{1}[/tex] / 3

[tex]m_{2}'[/tex] = [tex]m_{2}[/tex] / 3

F' = G [tex]m_{1}'[/tex] [tex]m_{2}'[/tex] / r² = G[tex]m_{1}[/tex][tex]m_{2}[/tex] / 9 r²

F' = F / 9

F' = 3600 / 9

F' = 400 N

Gravitational force is the force of attraction between two objects due to the presence of gravity.

Therefore, the gravitational force between the two objects whose mass is reduced to one-third of its original mass is 400 N

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The power in a lightbulb is given by the equation P=I^2 R, where I is the current flowing through the lightbulb and R is the resistance of the lightbulb. What is the current in a circuit that has a resistance of 25.0 Ω and a power of 30.0 W? A 0.830 A B 1,20 A C 0.910 A D 1.09 A

Answers

Answer:

Explanation:

The correct option will be the option (d) that is 1.09 A.

According to the equation given in the question:

That is; P=i^2R                  where I= current, R= resistance

           P=30 W

           R=25 ohm

            30=i^2*25

              I^2=30/25

             I^2=1.2

             I=1.09A

So, the correct answer of the given question will be 1.09A

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HELP! Along the line through the centers of the Moon and the Earth, there is a point where the gravitational forces exerted by the Moon and the Earth, respectively, are equal. We consider an elementary mass located at this point. How can this state be rated? Stable equilibrium, unstable equilibrium, total mechanical energy minimum, total mechanical energy maximum or minimum

Answers

We consider an elementary mass located at this point to be in a stable equilibrium.

What is stable equilibrium?

An equilibrium is said to be stable if small, externally induced displacements from that state produce forces that tend to oppose the displacement and return the body or particle to the equilibrium state.

Also a body is said to be in a stable equilibrium, if the opposing forces acting on a body are equal.

Examples of a stable equilibriuma weight suspended by a springa brick lying on a level surfacea cone resting on its base

Thus, along the line through the centers of the Moon and the Earth, there is a point where the gravitational forces exerted by the Moon and the Earth, respectively, are equal. We consider an elementary mass located at this point to be in a stable equilibrium.

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At the beginning of a 3.0-h plane trip, you are traveling due north at 192 km/h. At the end, you are traveling 250 km/h in the northwest direction (45° west of north).


Find the magnitude of the change in velocity.



Find the change in direction of your velocity. Enter the angle in degrees where negative indicates north of west and positive indicates south of west.



What is the magnitude of your average acceleration during the trip?


EDIT: ANSWERED

Magnitude of the change in velocity: 177.4 km/h
Change in direction of velocity: 4.9°
Magnitude of average acceleration during trip: 59.1 km/h2

Answers

The magnitude of the change in velocity is determined as 408.94 km/h.

The change in direction of the velocity is 64.4⁰ north of west.

The magnitude of the average acceleration during the trip is 0.0105 m/s².

Magnitude of change in velocity

The magnitude of change in velocity is the resultant velocity of the plane.

v² = a² + b² - 2ab cosθ

where;

θ is the angle between the two velocities = 45 + 90 = 135

v² = (192²) + (250²) - 2(192 x 250) cos(135)

v² = 167,236

v = √167,236

v = 408.94 km/h

Vertical component of the velocity

vyi = 192 km/h

vy2 = 250 x sin(45) = 176.77 km/h

vy(total) = 192 km/h + 176.77 km/h = 368.77 km/h

Horizontal component of the velocity

vxi = 0

vx2 = - 250 km/h x cos(45) = -176.77 km/h

Change in direction of the velocity

θ = arc tan (Vy/Vx)

θ = arc tan(368.77 / -176.77)

θ = -64.4 ⁰

θ = 64.4⁰ north of west.

Acceleration of the trip

a = v/t

v = 408.94 km/h = 113.6 m/s

h = 3 h = 10,800 seconds

a = (113.6 m/s) / ( 10,800 s)

a = 0.0105 m/s²

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An object dropped from the window of a tall building hits the ground in 12.0 s. If its acceleration is 9.80 m/s2, the height of the window above the ground is

Answers

Answer:

58.8 metres

Explanation:

using the formula

h=ut+½gt

U=0

g=9.8m/s²

t=12.0a

Hence, h= 0.5 × 9.8 × 144

h = 58.8 metres

ANSWER NOW PLEASE
When you are standing still on the Earth, your speed relative to the sun is approximately how many km/s.

Answers

If you were standing still on the equator of Earth you would move at nearly 1,000 miles/hour which is approximately 1,600 km/hr.

What is speed?

Speed is measured as the ratio of distance to the time in which the distance was covered.

The Earth is round and spins once every 24 hours. This spinning of the earth causes the daily motion which we feel here. If you were standing still on the equator of Earth you would move at nearly 1,600 km/hr.

Speed is a scalar quantity as it has only direction and no magnitude.

Speed is defined mathematically as distance/ time.

speed = distance/time expressed in m/s.

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A test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction of the initial acceleration vector and compare the initial acceleration vector's magnitude with respect to the crash acceleration magnitude.

Question 8 options:

The direction of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration vector of the crash.


The direction of the initial acceleration vector will point away from the wall, and its magnitude will be more than the acceleration vector of the crash.


The direction of the initial acceleration vector will point away from the wall, and its magnitude will be less than the vector of the crash.


The direction of the initial acceleration vector will point towards the wall, and its magnitude will be more than the acceleration vector of the crash.

Answers

The direction of the initial acceleration vector will point towards the wall, and its magnitude will be less than the acceleration vector of the crash, therefore the correct answer is option A.

What is acceleration?

The rate of change of the velocity with respect to time is known as the acceleration of the object.

As given in the problem, a test car carrying a crash test dummy accelerates from 0 to 30 m/s and then crashes into a brick wall. Describe the direction of the initial acceleration vector and compare the initial acceleration vector's magnitude with respect to the crash acceleration magnitude.

Thus, the initial acceleration vector will point in the direction of the wall and be smaller than the crash's acceleration vector, therefore the correct answer is option A.

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An electric stove is rated 1200,
240v-calculate?

Answers

(a) The current drawn is 5A.

(b) The resistance of the filament is 48Ω.

(a) The formula for power is:

P = VI

therefore, current drawn is;

[tex]I = \frac{P}{V}[/tex]

[tex]I = \frac{1200}{240}[/tex]

I = 5A

Therefore, the current drawn is 5A.

(b) Using, ohm's law:

V = IR

therefore, resistance of the filament is:

[tex]R = \frac{V}{I}[/tex]

[tex]R = \frac{240}{5}[/tex]

R = 48Ω

Therefore, the resistance of the filament is 48Ω.

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Purpose
Students will us vector addition on
the Flat-Earth Model.
Theory
Vector addition is easy and useful.
To add (24,0) to (0,-7), the 1st numbers
are added, as are the 2nd, and the order
stays the same: (24,-7). These can be x-
and y-positions, velocities, forces, etc.
Which way are the streaks on the
side windows of a car going 24 MPH if
driving through rain falling at 7 MPH?
That's a vector of (24,-7). The angle is
found by taking the arctangent of the
second 2nd over the 1st: tan¹(-4)=16⁰.
The Flat-Earth Model claims earth
is a horizontal disk. The north pole is at
the center, "Antarctica" is a rim wall at
the edge, and the sun and moon move
in circular paths above the disk. If true,
it should be easy to measure the sun's
altitude and make predictions.
Procedure
1. Find a cardboard box about the size
of a microwave, cut off the top flaps,
and set it on its side outdoors at noon.
2. Cut a coffee-cup-sized hole in the
middle of the upper wall and tape a
sheet of aluminum foil over it. Poke a
small hole in that with a pin or tack.
3 With the sun overhead, even if it is
slightly cloudy, a spot of light should
show on the bottom surface in the box.
Propping the box at a tilted angle may
be necessary, but then don't move it.
Mark the box bottom where the spot is
at noon, and then again at 1PM.
4. Find a ruler and measure the height
from the noon mark up to the foil hole.
Let this be y. Also measure the distance
between the marks. Let this be x. Units
can be inches, centimeters, whatever.
The sun's ray vector in the box is (x,y).
This vector can also be used to find the
sun's angle above the horizon.
Figure 02: The box as described.
5. The sun apparently moves 1000 mi
in an hour. (Call someone in Ft. Worth
and ask them what time of day the sun
is highest in the sky, if skeptical.) The
sun's height in miles is h = 1000-y/x.
6 If the Flat-Earth model is right, the
sun always keeps this height, so after
seven hours, the spot goes 7-x laterally.
Find the predicted sun angle above the
horizon at 7 PM using tan-¹(). Wait
for 7 PM and see if that's nearly right.
Analysis
Please answer each of the following
in Canvas using complete sentences:
1. How high up (h) is the sun using the
Flat-Earth Model?
2. At what angle above the horizon is
the sun at 10 PM using this model?
3. What is the diagonal distance to the
sun at 10 PM by this model when its
position vector is (10000,h) miles?
4. Did this lab disprove all unpopular
scientific viewpoints? Why or why not?



* I’ve already found my sun’s ray vector in the box which was (4.25, 17.25). *

Answers

On the day of the summer solstice, at noon, Eratosthenes was aware of a deep well on the Nile close to Aswan where the sun shone all the way to the bottom. Because the sun was not overhead in Alexandria, the length of that shadow was not zero.

We believe that the light rays from the sun that reach us are all traveling in the same direction; they are parallel, as the sun is thought to be extremely far away. No shadow would be formed by a vertical stick at point A, a "moderate" shadow by a stick at point B, and a very long shadow by a stick at point C. A radius of the earth leading to point A is shown on the diagram, and another leading to point B. A little geometry reveals that the angle between those two radii and the difference between the shadow angles are the same. In our example, the shadows indicate that during our journey from Florida to Pennsylvania, we had rotated the earth by about 10 degrees.

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What is the relationship between the distance traveled and time for an object that travels at a constant speed ?

Answers

The total distance traveled is directly proportional to the square of the time. As such, if an object travels for twice the time, it will cover four times (2^2) the distance; the total distance traveled after two seconds is four times the total distance traveled after one second.

A 5.1 kg textbook is raised a distance of 21.2 cm as a student prepares to leave for school. How much work did the student do on the book ?

Answers

Work done on the book is 10.595 Joules .

Work done on the book would be equal to the Potential Energy

Work Done = Potential Energy

W = m g h

where ,  ' m ' represents mass of the book

' g ' stands for  Acceleration due to gravity

' h ' represents the height to which the book is raised

So, according to the given question ,

m = 5.1 kg

g = 9.8 m / s ²

h = 21.2 cm

  =  0.212 m

W = m g h

    = 5.1 kg x 9.8 m / s ² x 0.212 m

    = 10 . 595 Joules

Hence, Work done on the book is 10.595 Joules .

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Alexus was resting on the couch but then decided she needed some food. She ran at up to 15m/s, accelerating
at 3m/s² the whole time, until she got to the fridge. How far away is the fridge from the couch?

Answers

Alexus was resting on the couch but then decided she needed some food. She ran at up to 15m/s, accelerating at 3m/s² the whole time, until she got to the fridge . The fridge will be 37.5 m far away from the couch

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Equation of kinematics  are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

given

final velocity = 15m/s

initial velocity = 0

a = 3m/s²

s = ?

a = acceleration = final - initial / time

3 = 15 - 0 / time

time = 15 /3 = 5 seconds

[tex]v^{2}[/tex] - [tex]u^{2}[/tex] = 2as

[tex]15^{2}[/tex] - 0 = 2 * 3 * s

s = 225 /6

  = 37.5 m

The fridge will be 37.5 m away from the couch

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Estimate the car's velocity at 4.0 s . Express your answer to two significant figures and include the appropriate units.

Answers

Answer- V≈75(m/s)

—(v=x/t) velocity is equal to distance, or x, over time, or t. at t=4, x is approximately equal to 300. therefore you would divide 300 by 4, getting 75

The magnitude of the impulse on a ball bouncing off a wall is equal?

Answers

The impulse is equal to the rate of change of momentum.

What is impulse?

The term impulse refers to the product of force and time. Let us recall that from Newton's law, impulse is proportional to the change in the momentum of the ball.

We can write from Newtons law;

F. t = Mv - Mu

F = force

t = time

M = mass

v = final velocity

u = initial velocity

Thus, the impulse is equal to the rate of change of momentum.

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Ann is driving down a street at 56 km/h. Suddenly a child runs into the street. If it takes Ann 0.749 s to react and apply the brakes, how far will she have moved before she begins to slow down? Answer in units of m.

Answers

The distance travelled by Ann before she begins to slow down is 11.65 m

How do I determine the distance travelled by Ann?

First, we shall enlighten ourselves on what speed is. This is given below.

Speed is the distance an object travelled per unit time. It can be expressed as:

Speed = distance / time

Finally, we can obtain the distance Ann travelled as illustrated below.

From the question given above, the following data were obtained:

Speed = 56 Km/h = 56 / 3.6 = 15.56 m/sTime = 0.749 sDistance =?

Speed = distance / time

15.56 = distance / 0.749

Cross multiply

Distance = 15.56 × 0.749

Distance = 11.65 m

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Select the correct answer.
Which physical property causes you to lean to one side when the bus you are traveling in takes a sharp turn?
A.
inertia
B.
mass
C.
speed
D.
velocity

Answers

Answer: I believe that the answer to your question is "Inertia", or A

Explanation:

100 Points!
A projectile is fired in the earth's gravitational field with a horizontal velocity of v=9.00 m/s. How far does it go in the horizontal direction in 0.550s? Show your work.

B) How far does the projectile go in the vertical direction in 0.550s. Show your work

Answers

Answer:

A)  4.95 m

B)  1.48225 m

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]  

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the projectile separately.

Part A

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

[tex]u=9.00\quad v=9.00 \quad a=0\quad t=0.550[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = \left(\dfrac{u+v}{2}\right)t:\\\\s&= \left(\dfrac{9+9}{2}\right)(0.550)\\s&= (9)(0.550)\\ \implies s&= 4.95\:\sf m\\\end{aligned}[/tex]

Part B

As the projectile is fired horizontally, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↓ as positive:

[tex]u=0\quad a=9.8\quad t=0.550[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\s&= (0)(0.550)+\dfrac{1}{2}(9.8)(0.550)^2\\s&= 0+(4.9)(0.3025)\\\implies s&= 1.48225\:\sf m\\\end{aligned}[/tex]

I 'm driving down the street at 15 m/s, it takes me 20 minutes to get to my destination. What was the distance to my destination?

Answers

20 minutes = 20 x 60 = 1200 seconds

15 x 1200 = 18000 metres or 18km

The distance to the destination is 18,000 meters or 18 kilometers. the formula for calculating the distance is speed × Time.

Using the formula:

Distance = Speed × Time

Speed = 15 m/s (meters per second)

Time = 20 minutes

First, we need to convert the time from minutes to seconds, as the speed is given in meters per second.

1 minute = 60 seconds

Time in seconds = 20 minutes × 60 seconds/minute = 1200 seconds

Now, we can calculate the distance:

Distance = 15 m/s × 1200 seconds

Distance = 18,000 meters

So, the distance to the destination is 18,000 meters, or 18 kilometers (since 1 kilometer = 1000 meters).

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physics help needed

Answers

Answer: 1 > 3 > 2

Explanation: The range will increase with the velocity. If they are all launched at the same time the ones that are launched the hardest or with the most velocity will go the furthest horizontally. But because they are all launched from the same height and the force of gravity on all three projectiles is constant (the same for all three) they will all hit the ground at the same time but different distances from the starting point.

In camping, you drop a stone from the 1st spot to the lake. The splash is heard 4 seconds later. After walking, you drop a stone again at 2nd spot at the same lake. This time the splash is heard 12 seconds later. The height of the 2nd spot is ___ times the 1st spot.

A-3
B-12
C-6
D-9

Answers

The height of the 2nd spot is 3 times the height of the 1st spot (Option A)

How to determine the height of the first spot

We'll begin by obtaining the height of the first spot. This can be obtained as follow:

Time (t) = 4 seconds Velocity of sound (v) = 343 m/sHeight of first spot (x) =?

v = 2x / t

343 = 2x / 4

Cross multiply

2x = 343 × 4

2x = 1372

Divide by 2

x = 1372 / 2

Height of first spot = 686 m

How to determine the height of the second spotTime (t) = 12 seconds Velocity of sound (v) = 343 m/sHeight of second spot (x) =?

v = 2x / t

343 = 2x / 12

Cross multiply

2x = 343 × 12

2x = 4116

Divide by 2

x = 4116 / 2

Height of second spot = 2058 m

How to compare 2nd height with 1st height Height of 1st spot = 686 mHeight of 2nd spot = 2058 mComparison =?

Comparison = Height of 2nd spot / Height of 1st spot

Height of 2nd spot / Height of 1st spot = 2058 / 686

Height of 2nd spot / Height of 1st spot = 3

Cross multiply

Height of 2nd spot = 3 × Height of 1st spot

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Someone pls tell me what the answer is

Answers

The distance of the ball that would land which was launched horizontally at a speed (s) of 3.4 m/s from a table that is 7.8 m tall (d) will land is 4.29m

Consider the ball moving horizontally off the table. When it moves, gravitational force acts on it pulling the ball downwards. In addition to that objects that are falling down would accelerate quickly i.e., let’s take an object falling at the speed of x, after time t it would travel at 2x, after 2t it would be 4x.

We need to find time to calculate distance by using speed equation.

For calculating time, let’s use the freefall formula,

d = 1/2 gt²

t = √(2d) / g

t = √2 (7.8)/ 9.8

t = 1.262 s

To calculate distance, we could use speed equation as we have both Time and Velocity

s = d / t

d = s t

d = 1.262 * 3.4

d = 4.29 m

Thus, the distance of the ball that would land is 4.29 m

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The most commonly used conductor in the laboratory is?

Answers

Answer:

A battery

Explanation:

A battery is the biggest conductor. I think.

convert these into proper Vector notation Westward velocity of 42 km/h

Postion 6.5 measured in m that is North of the refrence point.

Downward acceleration measured in m/s2 that has a magnitude of 1.9.

Answers

Proper vector notations are V = 42i  km/hr, r = 6.5j m, and a = -1.9j m/s².

In physics, a vector is a quantity with both magnitude and direction. It is typically represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity.

A) Let us assume that the west direction is the positive X-axis.

In vector notation, the X-axis is denoted by "i". So, the westward velocity of 42 km/hr  will be written as

V = 42i  km/hr

B) Let us assume that the North direction is the positive Y- axis.

In vector notation, the  Y-axis is denoted by "j". Also, the position vector is represented by the letter 'r'. So position 6.5 measured in m, that is North of the reference point will be written as

r = 6.5j m

C) Let us assmue thaat the downward direction is negative  Y-axis.

In vector notation, the  Y- axis is denoted by "j". so, the downward acceleration measured in m/s2 that has a magnitude of 1.9 will be written as

a = 1.9 × (-j) m/s²

a = -1.9j m/s²

So, proper vector notations are V = 42i  km/hr, r = 6.5j m, and a = -1.9j m/s².

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Calculate the frequency of this radiation.

Answers

The frequency of a radiation that has a wavelength of 9.17 × 10-⁷m is 3.27 × 10¹⁴ Hz.

How to calculate frequency?

The frequency of a radiation can be calculated by dividing the velocity of the radiation by the wavelength. That is;

f = v/(λ)

According to this question, some radiation detected by a thermal imaging camera during a training exercise has a wavelength of 9.17 × 10-⁷m. The frequency can be calculated as follows:

f = 3 × 10⁸m/s ÷ 9.17 × 10-⁷m

f = 3.27 × 10¹⁴ Hz

Therefore, the frequency of a radiation that has a wavelength of 9.17 × 10-⁷m is 3.27 × 10¹⁴ Hz.

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A baseball player throws a ball horizontally.
Which statement best describes the ball's
motion after it is thrown? [Neglect the effect of
friction.]

Answers

The vertical speed of the ball increases and its horizontal speed remains constant as usual because air friction is being neglected.

By definition, air resistance refers to the forces that work against an object's relative motion as it travels through the atmosphere. These drag forces cause the object to move more slowly by acting in opposition to the speed of the incoming flow. Since drag is the part of the net aerodynamic force operating in the opposite direction to the direction of the movement, it differs from other resistance forces in that it directly depends on velocity.

Fluid friction includes friction in the air. These friction forces differ from the conventional model of surface friction in that they rely on velocity. Only rare examples can be dealt with analytically since the velocity dependence may be extremely intricate. Air resistance is roughly proportional to velocity and can be represented in the form of very low speeds for microscopic particles.

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During camp, a simple way to estimate the height of a cliff is to drop a stone from the top and hear the splash when it hits the water below. The stone takes 3.6 seconds to drop. Assume sound speed is infinite. The height of the cliff is ___ meters.

Answers

The heigth of the cliff is 63.504 m.

What is height?

Height is the vertical distance  between two points.

To calculate the height of the cliff, we use the formula below.

Formula:

S = ut+gt²/2........... Equation 1

Where:

S = Height of the clifft = Timeu = Initial velocityg = Accceleration.

From the question,

Given:

u = 0 m/st = 3.6 sg = 9.8 m/s²

Substitute these values into equation 1

S = 0×3.6+9.8×3.6²/2S = 63.504 m

Hence, the heigth of the cliff is 63.504 m.

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If an object travels at 10 m/s constantly for 1 minute, how far will it have travelled?

Answers

1min = 60sec
d=vt=10*60=600m

pls pls help !!! <33

Answers

Answer: Vx is changing  and  Vx is greatest near the beginning of the launch.

Explanation: Think of Vx as a bullet fired from a gun. As soon as it is fired it starts to slow down so Vx is changing and at the beginning Vx has its greatest velocity because it can only go slower from there.

answers are B and C. horizontal velocity never changes so A cannot be the answer. that makes B one of the answers. I would also say that the horizontal velocity is greatest near the beginning of the launch as it just starts, since it stays at a constant pace after, so D is not an answer. hope this helps ^_^

Girl runs 40m due south in 40 seconds,he then return to North,20m in 10 seconds,, calculate
1. average speed
2.average velocity
3.change in velocity
4.acceleration

Answers

Acceleration I believe.

If a bat hits a ball with 85 N of force, how much force does the ball exert on the bat?

Answers

If a bat hits a ball with 85 N of force the bat will also exert the same force

85N.

You are probably already aware of the force the ball applies to the wall when it is thrown against it. Similar to how the wall exerts a force on the ball, the ball bounces off the wall. Similar to how the earth drags you down with gravity. You might not be aware of it, but you are also pushing the planet with the same amount of power. The third law of Newton is a result of this amazing event.

Newton's Third Law states that if object A exerts a force on object B, then object B must apply a force on object A that is equal in magnitude and directed in the opposite direction.

An object interacts with another object when a push or pull is applied to it. A product of interaction is force. Frictional force, for example, falls into the category of contact force. Non-contact force, on the other hand, includes gravitational force. Newton's third rule of motion explains that when two bodies contact, they exert force on one another. This force is referred to as an action and reaction pair.

To learn more about Newton's Third Law visit:https://brainly.com/question/23772134

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