Answer:
Approximately [tex]0.8\; \rm s[/tex] (assuming that air resistance is negligible.)
Explanation:
Let [tex]v_0[/tex] denote the initial velocity of this ball. Let [tex]\theta[/tex] denote the angle of elevation of that velocity.
The initial velocity of this ball could be decomposed into two parts:
Initial vertical velocity: [tex]v_0(\text{vertical}) = v_0 \cdot \sin(\theta)[/tex].Initial horizontal velocity: [tex]v_0(\text{vertical}) = v_0 \cdot \cos(\theta)[/tex].If air resistance on this ball is negligible, [tex]v_0(\text{vertical})[/tex] alone would be sufficient for finding the time of flight of this ball.
Calculate [tex]v_0(\text{vertical})[/tex] given that [tex]v_0 = 8 \; \rm m \cdot s^{-1}[/tex] and [tex]\theta = 30^\circ[/tex]:
[tex]\begin{aligned}& v_0(\text{vertical}) \\ &= v_0 \cdot \sin(\theta) \\ &= \left(8 \; \rm m \cdot s^{-1} \right) \cdot \sin\left(30^{\circ}\right) \\ &= 4\;\rm m \cdot s^{-1} \end{aligned}[/tex].
Assume that air resistance on this ball is zero. Right before the ball hits the ground, the vertical velocity of this ball would be exactly the opposite of the value when the ball was launched.
Since [tex]v_0(\text{vertical}) = 4\; \rm m \cdot s^{-1}[/tex], the vertical velocity of this ball right before landing would be [tex]v_1(\text{vertical}) = -4\; \rm m \cdot s^{-1}[/tex].
Calculate the change to the vertical velocity of this ball:
[tex]\begin{aligned}& \Delta v(\text{vertical}) \\ & = v_1(\text{vertical}) - v_0(\text{vertical}) \\ &= -8\; \rm m \cdot s^{-1}\end{aligned}[/tex].
In other words, the vertical velocity of this ball should have change by [tex]8\; \rm m \cdot s^{-1}[/tex] during the entire flight (from the launch to the landing.)
The question states that the gravitational field strength on this ball is [tex]g = 10\; \rm m \cdot s^{-2}[/tex]. In other words, the (vertical) downward gravitational pull on this ball could change the vertical velocity of the ball by [tex]10\; \rm m\cdot s^{-1}[/tex] each second. What fraction of a second would it take to change the vertical velocity of this ball by [tex]8\; \rm m \cdot s^{-1}[/tex]?
[tex]\begin{aligned}t &= \frac{\Delta v(\text{initial})}{g} \\ &= \frac{8\; \rm m \cdot s^{-1}}{10\; \rm m \cdot s^{-2}} = 0.8\; \rm s\end{aligned}[/tex].
In other words, it would take [tex]0.8\; \rm s[/tex] to change the velocity of this ball from the initial velocity at launch to the final velocity at landing. Therefore, the time of the flight of this ball would be [tex]0.8\; \rm s\![/tex].
intensity of light in SI system
Answer: candela
Explanation:
The SI unit for the measurement of intensity is referred to as the candela. The candela is simply used in the measurement of the visual intensity with regards to light sources such as the bulb we have in torches or the light bulbs that we have in our various homes. It is the power that a light source emits in a certain direction.
An object of mass 8 kg Is attached to a massless string of length 2 m And Suong With a tangentialVelocity of 3 m/s what isThe tension in the string
Answer:
36 N
Explanation:
The tension on the string :
T =mv²/r ------where
m= mass of object = 8 kg
v= tangential velocity = 3 m/s
r= length of the string = 2m
T= [ 8 * 3² ] / 2
T= 36 N
which of the following can carry light waves but not sound waves
Laney et al. (false memory):(a) Outline the rating scale used in the Food History Inventory [2 marks]
Answer: The rating scale that is used in food history inventory is from 1 to 8.
Explanation:
In this case the participants have to rate 24 items on a scale of 1 to 8.There are variety of questions related to food or fooding habits.
The questions like do you go out for food?
Do you like bread ? if yes how will you rate it on a scale of 1 to 8.
The questions like this has to be answered in a way . It is done in order to see the preferences and false memory regarding the food preference that people have.
What scientific concept is
being illustrated in this
model?
Answer:
the scientific concept being illustrated in this model is dispersion
a bicycle wheel with a radius of 0.31 m rotates with an angular speed of 21 rad/s about its axle, which is at rest. What is the linear speed of a point on the rim of the wheel
Answer:
The linear speed is 6.51 m/s
Explanation:
Uniform Circular Motion
It's a movement of an object along the circumference of a circle. It can also be defined as a rotation along a circular path.
The angular speed can be calculated as follows:
[tex]\displaystyle \omega=\frac{v}{r}[/tex]
Where:
v = tangential or linear speed
r = radius of the circle described by the rotating object
To calculate the linear speed, solve for v:
[tex]v = \omega\cdot r[/tex]
[tex]v = 21\ rad/s\cdot 0.31\ m[/tex]
[tex]v = 6.51\ m/s[/tex]
The linear speed is 6.51 m/s
Sonny Toomey 16 seconds to finish a 100-m race. What was Sonny's average speed in the race? Give your answer in the decimal form.
Answer:
6.25 m/s.
Explanation:
Total distance travelled = 100 m
Total time = 16 s
Average speed =?
Average speed is simply defined as the ratio of total distance travelled to the total time taken to cover the distance. Mathematically, it is expressed as:
Average speed = total distance / total time
With the above formula, we can obtain the average speed of Sonny Toomey as illustrated below:
Total distance travelled = 100 m
Total time = 16 s
Average speed =?
Average speed = total distance / total time
Average speed = 100 / 16
Average speed = 6.25 m/s
Therefore, the average speed of Sonny Toomey is 6.25 m/s
How would you rate your mental health from a scale of 1 (lowest) to 5 (highest) and why?
A car accelerates uniformly from rest and
reaches a speed of 9.2 m/s in 9.7 s. The
diameter of a tire is 47.8 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slip-
ping
Answer in units of rev.
Answer:
29.75 revolutions
Explanation:
The kinematic formula for distance, given a uniform acceleration a and an initial velocity v₀, is
[tex]d=v_0t+\frac{1}{2}at^2[/tex]
This car is starting from rest, so v₀ = 0 m/s. Additionally, we have a = 9.2/9.7 m/s² and t = 9.7 s. Plugging these values into our equation:
[tex]d=0t+\frac{1}{2}\left(\frac{9.2}{9.7}\right)(9.7)^2\\d=\frac{1}{2}(9.2)(9.7)\\d=4.6(9.7)\\d=44.62[/tex]
So, the car has travelled 44.62 m in 9.7 seconds - we want to know how many of the tire's circumferences fit into that distance, so we'll first have to calculate that circumference. The formula for the circumference of a circle given its diameter is [tex]c=\pi{d}[/tex], which in this case is 47.8π cm, or, using π ≈ 3.14, 47.8(3.14) = 150.092 cm.
Before we divide the distance travelled by the circumference, we need to make sure we're using the same units. 1 m = 100 cm, so 105.092 cm ≈ 1.5 m. Dividing 44.62 m by this value, we find the number of revs is
[tex]44.62/1.5\approx29.75[/tex] revolutions
Some sharks can swim at average cruising speeds of three miles per hour. If a shark swam at that average speed for seven hours, how far would it have traveled?
Answer:
21 miles
Explanation:
3 miles an hour for 7 hours
Its simply 7m*3m/hr=21 miles
what is the volume of the following: *
110
121
120
Answer:
120
Explanation:
10 x 3 = 30
30 x 4 = 120
I hope this helps u! :D
Answer: ayee fanks bro
Explanation:
Need 100 IQ and more
A food package is dropped from a helicopter flying horizontally at a height of 125m. If the magnitude of the velocity of the packageafter 2seconds is 25m/s. Find
a. The speed of the helicopter at the moment the package is dropped.
b. The position of the package after 2s.
c. The time of flight of the food package
d. The horizontal distance covered.
Answer:
a. The speed of the helicopter at the moment the package is dropped is approximately 15.519 m/s
b. The position of the package 2s after it is dropped is (31.038 m, -9.8 m)
c. The time of flight of the food package is approximately 5.105 seconds
d. The horizontal distance covered is approximately 79.22 m
Explanation:
The given parameters are;
The height at which the helicopter is flying = 125 m
The magnitude of the velocity of the package after 2 seconds, v = 25 m/s
a. The vertical velocity of the package, [tex]v_y[/tex], is given as follows;
[tex]v_y[/tex] = [tex]u_y[/tex] + g·t
Where;
[tex]u_y[/tex] = 0 m/s for the dropped food package
t = The duration of the package in the air = 2 s
g = The acceleration due to gravity = 9.8 m/s²
Therefore;
[tex]v_y[/tex] = g·t = 9.8 m/s² × 2 s = 19.6 m/s
We have, [tex]v = \sqrt{v_x^2 + v_y^2}[/tex],
Where;
vₓ = The horizontal velocity of the food package = The horizontal speed of the helicopter
therefore, [tex]v_x = \sqrt{v^2 - v_y^2}[/tex], which gives;
[tex]v_x = \sqrt{v^2 - v_y^2} = \sqrt{25^2 - 19.6^2} \approx 15.519 \ m/s[/tex]
The speed of the helicopter at the moment the package is dropped ≈ 15.519 m/s
b. The vertical if the package after 2 s is given as follows;
The vertical position of the package after 2 s is given by the kinematic equation, h = 1/2·g·t² = 1/2 × 9.8 m/s² × 2 s = 9.8 m
The food package is located 9.8 m vertically below the point where it is dropped
The horizontal position, x, of the package after 2 s is given by the following kinematic equation, x = vₓ × t
Therefore, x = 15.519 m/s × 2 s ≈ 31.038 m
The coordinates of the location of the package 2 seconds after it is dropped is (31.038 m, 9.8 m)
c. The time of flight, [tex]t_{tot}[/tex], of the food package which is the time it takes the package to reach the ground from 125 m, is given as follows;
[tex]t_{tot} = \sqrt{\dfrac{2 \cdot h}{g} } = \sqrt{\dfrac{2 \times 125 \ m}{9.8 \ m/s^2} } \approx 5.051 \ seconds[/tex]
The time of flight of the food package, [tex]t_{125}[/tex] ≈ 5.105 seconds
d. The horizontal distance covered, [tex]x_{tot}[/tex] = vₓ × [tex]t_{tot}[/tex] ≈ 15.519 m/s × 5.105 s = 79.224495 m ≈ 79.22 m.
If you want a charged object to become neutral,then you have to ————-? A.Touch it with a positively charged object B.Touch it with neutral objects C.Touch it with a negativity charged object D.Touch it with the ground
Answer: D.Touch it with the ground
Explanation:
The charged object can become neutral if touched with the ground in a process known as grounding.
If the charged object is negatively charged, excess electrons will flow into the ground thus making the object neutral. If the object is positively charged, electrons will flow from the ground into the object and neutralise it.
if you divide velocity by time what unit do you get
Answer:
m/s^2, acceleration
Explanation:
velocity in SI units is meter / second
dividing by time(second) gives meter / second^2 which is acceleration.
How many atoms are in 3.5mol?
Answer:
A mole of any chemical is 6.02 x 1023 units of that chemical. So, 3.5 moles of carbon means 6.02 x 1023 x 3.5 atoms of Carbon.
Explanation:
what effect does an unbalanced force have on an object?
Answer:
An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.
The graph above shows the position and time calculate the velocity of the particle from T=0s to T=4s?
0.75m/s
0.5m/s
2m/s
1.33m/sm/s
Answer:
The velocity of the particle from T = 0 s to T = 4 s is;
0.5 m/s
Explanation:
The given parameters from the graph are;
The initial displacement (covered) at time, t₁ = 0 s is x₁ = 1 m
The displacement covered at time, t₂ = 4 s is x₂ = 3 m
The graph of distance to time, from time t = 0 to time t = 4 is a straight line graph, with the velocity given by the rate of change of the displacement to the time which is dx/dt which is also the slope of the graph given as follows;
[tex]The \ slope \ of \ the \ displacement \ time \ graph, \ m =velocity, \ v= \dfrac{x_2 - x_1}{t_2 - t_1}[/tex]
[tex]Therefore, \ the \ velocity \ of \ the \ particle \ v = \dfrac{3 \ m - 1 \ m}{4 \ s - 0 \ s} = \dfrac{2 \ m}{4 \ s} = \dfrac{1}{2} \ m/s[/tex]
The velocity of the particle from t = 0 s to t = 4 s = 1/2 m/s = 0.5 m/s.
HELP ME PLSSLSLSPSPS im stuck pls help
A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)
What is the relationship between Newton's first law of motion and inertia?
Explanation: Newton's first law of motion states that a body at rest remains at rest, or, if in motion, remains in motion at a constant velocity unless acted on by a net external force. This is also known as the law of inertia. Inertia is the tendency of an object to remain at rest or remain in motion.
5.How far must a 5 N force pull a 50 g toy car if 30 J of energy are transferred?
Answer:
5 meters
Explanation:
Step one:
given data
mass of the toy car= 50g
Work done= 30J
Force applied F= 5N
Required
The distance moved
Step two:
The expression for the work done is given as
WD= force * distance
substitute
30= 5*d
divide both sides by 5
d=30/5
d= 5m
The distance moved is 5 meters
which correctly describes how the energy of a wave on the electromagnetic spectrum depends on wavelength and frequency?
Answer:
The answer to this question is given below in this explanation section.
Explanation:
"electromagnetic spectrum depends on wavelength and frequency"
When electromagnetic radiation interacts with single atoms and molecule,its behavior also depends on the amount of energy per quantum(photon)it carries wave number =1/wavelength in cm speed of light=wavelength x frequency energy = Planck's constant x frequency.
Electromagnetic radiation interacts with matter in different parts of the spectrum.
Electromagnetic radiation interacts with matter in different ways in different parts of the spectrum.The types of interaction can be so different that it seems justified to refer to different types of radiation.There is a continuum containing all these different kind of electromagnetic radiation.Thus we refer to spectrum but divide it up based on the different interaction with matter.
Answer:
Energy increases with decreasing wavelength and increasing frequency.
Explanation:
Describe how radio waves are different from sound waves
Answer:radio waves are electromagnetic waves propagating in any non-conductive media by varying the field at each point in it. Sound is a wave of pressure changes of the medium such as air. Radio waves are a combination of electric and magnetic fields that need no medium to travel upon.
Explanation:please give brainliest
Radio waves are longest electromagnetic waves whereas sound waves are mechanical waves. Sound waves can move only through a medium and electromagnetic waves does not need a medium to travel.
What is radio waves ?Radio waves are a kind of electromagnetic waves. In the electromagnetic spectrum, radio waves has the longest wavelength and smallest frequency. Thus, radio waves have lower energy in comparison to other electromagnetic waves.
Sound waves are mechanical waves. Mechanical waves needs a medium to travel where as electromagnetic waves does not need a medium and they can moves through vacuum.
Sound waves are longitudinal mechanical waves where, the oscillation of particles is in the direction along the wave propagation. Electromagnetic waves are more energetic and faster than sound waves.
To find more on sound waves, refer here:
https://brainly.com/question/16951692
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High- and low-pressure areas leading to air movement happen when there are differences in which factor?
clouds
density
atmosphere
precipitation
whoever gets the answer will get brainliest!! :D
Answer:
The answer is density
Explanation:
They density of the air is what makes a difference.
HELP PLSSS
A 13.3 kg box sliding across the ground
decelerates at 2.42 m/s2. What is the
coefficient of kinetic friction?
(No unit)
ps( its not 0.242)
Given :
A 13.3 kg box sliding across the ground decelerates at 2.42 m/s².
To Find :
The coefficient of kinetic friction.
Solution :
Frictional force applied to the box is :
[tex]f = ma[/tex] ....1)
Also, force of friction is given by :
[tex]f = \mu mg[/tex] ....2)
Equating equation 1) and 2), we get :
[tex]\mu mg = ma\\\\\mu = \dfrac{a}{g}\\\\\mu = \dfrac{2.42}{9.8}\\\\\mu = 0.247[/tex]
Therefore, the coefficient of kinetic friction is 0.247 .
two carts are pushed apart by an expanding spring, as shown in the diagram. if the average force on the 1kg cart is 4N, what is the acceleration of each cart
The acceleration of each cart be 4 meter/second².
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given parameters:
the average force on the 1kg cart is 4N.
Hence, the acceleration of the 1 kg cart be = force/mass
= 4/1 meter/second²
= 4 meter/second².
As two carts are pushed apart by an expanding spring, the acceleration of the other carts also be 4 meter/second².
Learn more about acceleration here:
brainly.com/question/12550364
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Type the correct answer in the box. Round your answer to the nearest whole number.
What’s the percentage of organisms that survived?
A natural disaster caused a population of 4,695 organisms to migrate to a new habitat. A few generations after the disaster, it was observed that the new habitat did not support the survival of the species. The table shows the population of the species in the two habitats.
Original Habitat New Habitat
4,695 2,326
Based on the table, the population in the new habitat is about percent of the original population.
Answer:
50%
Explanation:
2326/4696 = 0.495
Can be rounded to: 0.50
50%
Answer:
50
Explanation:
just took the test :)
Help me with this homework please
Answer:
100 N
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 5 kg
Acceleration (a) = 20 m/s
Force (F) =?
Force is simply defined as the product of mass and acceleration. Mathematically, it can be expressed as:
Force (F) = mass (m) × acceleration (a)
F = ma
With the above formula, we can obtain the force need to move the object. This can be obtained as follow:
Mass (m) = 5 kg
Acceleration (a) = 20 m/s
Force (F) =?
F = ma
F = 5 × 20
F = 100 N
Therefore, a force of 100 N is needed to move the object.
6th grade science!!!!!!!!!
As the altitude decreases,air pressure increases. The statement is true. Option A is correct.
What is pressure?The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.
It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.
As the altitude decreases,air pressure increases. The statement is true.
Hence, option A is correct, and the given statement is true.
To learn more about the pressure, refer to the link;
https://brainly.com/question/356585
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Fill in the blank..
The moon takes _______ to revolve around the Earth.
ANSWER CHOICES:
A. 27 days
B. About a month
Answer:
The moon takes 27 days to revolve around the earth.
Explanation:
I hope this helps :)
The moon takes 27 days to revolve around the Earth.
Pictures below :)
Have a nice day!!
Answer:
17N right
Explanation: