Answer:
14.57g
Explanation:
Given parameters:
Mass of dish + ball = 15.6g
Initial volume of water in the cylinder = 26.7mL
Final volume of water in the cylinder = 38.9mL
Mass of dish = ?
Unknown
Mass of the ball = ?
Solution;
Since the mass of ball and dish is 15.6g,
Mass of the ball =Mass of ball + dish - mass of the dish
Insert the parameters and solve;
Mass of the ball = 15.6g - 1.03g = 14.57g
Help in history class please Thnks
Answer:
C) Foreign relations and war powers
Please Help!!
Nitrogen gas can be prepared by passing ammonia over copper(II) oxide, and the other products are copper metal and water vapor. If a sample containing 3.58 moles of NH₃ is reacted with excess copper(II) oxide, how many grams of N₂ will be formed?
Mass of N₂ will be formed : 50.12 g
Further explanationReaction
2 NH₃(g) + 3 CuO(s) → N₂(g) + 3 Cu(s) + 3 H₂O(g)
moles NH₃ = 3.58
ratio mol NH₃ : mol N₂ = 2 : 1
so mol N₂ :
[tex]\tt \dfrac{1}{2}\times 3.58=1.79[/tex]
mass N₂ (MW=28 g/mol) :
[tex]\tt 1.79\times 28=50.12~g[/tex]
PLEASE HELP!!!!
what happens when the ocean reaches it’s saturation level of carbon dioxide?
Hi!
When the ocean reaches its saturation level of carbon dioxide, a couple of things will happen:
First, more carbon dioxide will remain in the atmosphere, and second, the ocean's pH will drop.
Carbonate and bicarbonate ions in seawater act as a buffer system which keeps the ocean's pH levels stable. When CO2 dissolves in seawater, it reacts with the ocean's buffer system in such a way that it produces two hydrogen ions, which lowers the pH. As more and more CO2 reacts with the ocean's buffer system and the system becomes saturated, less atmospheric carbon dioxide will cross over into the ocean. This excess CO2 will remain in the atmosphere and contribute to global climate change.
Hope this helped!
When the ocean reaches it's saturation level of carbon dioxide more amount of carbon dioxide remains in the atmosphere and pH of the ocean drops.
What is saturation level?It is defined as the level or extent up-to which a substance is soluble in a particular solvent. Due to global warming ,there is an excessive release of carbon dioxide in atmosphere. The excessive amount cannot be soluble in the ocean water which leads to ocean acidification.
As a result of ocean acidification the pH of water in the ocean drops thus there is less amount of oxygen present for aquatic organisms which is needed to survive. When carbon dioxide dissolves in water it yields carbonic acid which further reduces the pH of water and thus making it unfit for aquatic environment.
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Weathering is the process that takes place as rocks, and other parts of the geosphere, are??
At equilibrium, the value of [H ] in a 0.240M solution of an unknown acid is 0.00417M . Determine the degree of ionization and the Ka of this acid.
Answer:
[tex]ionization=1.74\%[/tex]
Explanation:
Hello!
In this case, since the degree of ionization of an acid is computed in terms of the concentration of hydrogen ions and the initial concentration of the acid:
[tex]ionization=\frac{[H^+]}{[HA]} *100\%[/tex]
Because the ionization reaction is represented by:
[tex]HA\rightleftharpoons H^++A^-[/tex]
Therefore, the degree or percent ionization turns out:
[tex]ionization=\frac{0.00417M}{0.240M} *100\%\\\\ionization=1.74\%[/tex]
Best regards!
While setting up a beaker to boil a solution on a hot plate, you notice that the stirring is erratic and unstable. What should you do to stabilize the stirring solution? a. Clamp the beaker in place at the edge of the hot plate. b. Move the beaker to the center of the hot plate. c. Turn down the stirring speed. d. Completely turn off the stirring function.
Answer:
B. Move the beaker to the center of the hot plate
Explanation:
The erratic and unstable stirring might be caused by the beaker not being properly balanced on the hot place, there by distorting the the center of gravity of the stirring motion.
In properly positioning the stirrer to the hot plate, the magnetic rod is positioned to the center of the fluid, allowing for a more fluid and even effective stirring.
I hope this was helpful.
Would you want to build the wire for a cell phone charger out of nitrogen (N)? Why or why not? Be sure to explain how the properties and structure of nitrogen influence your decision.
Answer:
No
Explanation:
Nitrogen cannot be used to build the wire for a cell phone charger.
What are the elements used to build charger ?
Inside phone chargers is aluminum. Aluminum is used in phone chargers because it does a better job of conducting electricity than copper does. Bauxite is used to make aluminum. The crust of the earth contains aluminum.A phone charger is also made of tungsten. The wire's resistance is provided by tungsten. Wolframite make up tungsten. The crust of the Earth contains tungsten.Additionally, phone chargers contain gold. Because it is a conductor, gold is used in phone chargers. However, gold is also resistant to oxidation. Copper ores are used to make gold. Gold can be found everywhere on Earth and in its oceans.Silver is within your mobile charger. Silver conducts electricity. Silver is comprised of various minerals. Silver can be found free in nature at times, but it can also be found in copper, gold, and nickel.Phone chargers contain copper. Copper is also used to carry electric current.Chalcopyrite make up copper. Copper ore deposits can be found all over the world.Copper windings in a transformer are used to convert a 220 V input voltage into a 5 V operating output voltage in mobile phone chargers. The output voltage is greater than the input voltage if the secondary coil has more turns than the primary coil.Nitrogen (N), a nonmetallic element in the periodic table's Group 15 [Va] group. It is the most abundant element in Earth's atmosphere and a component of all living matter. It is a colorless, tasteless, and odorless gas. Nitrogen is used to shield motors, prevent oxidation and other chemical reactions, pressurize cable jackets, and more in the electrical industry.To know more about Nitrogen check this:
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Suppose in an experiment to determine the amount of sodium hypochlorite in bleach, 0.0000538 mo KIO3 were titrated with an unknown solution of Na2S2O3 and the endpoint was reached after 17.80 mL. How many moles of Na2S2O3 did this require?
Answer:
3.228x10⁻⁴ moles of Na2S2O3 are required
Explanation:
In iodometry, the reaction of KIO3 with Na2S2O3 is:
KIO3 + 6 Na2S2O3 + 6H⁺ → KI + 3Na2S4O6 + 3H2O + 6Na⁺
Where 6 moles of Na2S2O3 reacts per moles of KIO3.
The moles of Na2S2O3 required to reach endpoint when 0.0000538 moles of KIO3 are:
0.0000538 moles of KIO3 * (6 moles Na2S2O3 / 1 mol KIO3) =
3.228x10⁻⁴ moles of Na2S2O3 are requiredOf the following, which is NOT a component of the circulatory system?
A. Heart
B. Veins
ws
C. Arteries
D. Brain
Answer:
D. Brain
~PumpkinSpice1
How many grams of CO2 are produced by the combustion of 344 g of a mixture that is 33.6% CH4 and 66.4% C3H8 by mass
Answer:
1,002.936 g
Explanation:
The combustion equation of each will be;
CH4 + 2O2 = CO2 + H2O
C3H8 + 5O2 = 3CO2 + 4H2O
We are told the mixture is 344g.
Thus;
For CH4 combustion;
Amount of CH4 = 0.336 × 344 = 115.584g
Molar mass of CH4 is 16 g/mol
Number of moles of CH4 is;
n = 115.584g/(16 g/mol)
n = 7.224 moles
n(CO2) = n(CH4) = 7.224 moles
For C3H8 combustion;
Amount of C3H8 = 0.664 × 344 = 228.416 g
Molar mass of C3H8 = 44 g/mol
Thus;
Number of moles of C3H8 = 228.416 g/(44 g/mol) = 5.19 mol
n(CO2) = 3n(C3H8) = 3 × 5.19 = 15.57 moles
Total moles of CO2 = 7.224 moles + 15.57 moles = 22.794 mol
Molar mass of CO2 = 44 g/mol
Thus amount of CO2 by mass = 22.794 mol × 44 g/mol = 1,002.936 g
what processes add methane (CH4) to the atmosphere
Answer:
Cultivated rice paddies
Drilling of natural deposits
Fossil fuel use
Burning of biomass
Landfills
Explanation:
The bulk of the methane released into the atmosphere are as a result of various human activities.
Cultivated rice paddies are a known source of methaneThe drilling of natural deposits and their exploration can release some methane into the atmosphereBurning of fossil fuel and biomass is a source of methane Landfills produces methane as organic materials begins to decay.When 4.58 g of a nonelectrolyte solute is dissolved in water to make 725 mL of solution at 25 °C, the solution exerts an osmotic pressure of 875 torr.
Required:
a. What is the molar concentration of the solution?
b. How many moles of solute are in the solution?
c. What is the molar mass of the solute?
Answer:
a. 0.047 M
b. 0.6778 moles
c. 6.76 g/mol
Explanation:
The formula for osmotic pressure is:
π = i*M*R*TWhere:
i is the van't Hoff's factor (in this case is 1, because it is a non electrolyte solute)M is the molar concentrationR is the ideal gas constantT is the temperature in Kelvina.) So we solve for M:
875 torr ⇒ 785/760 = 1.15 atm25 °C ⇒ 25+273.16 = 298.16 K1.15 atm = 1 * M * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 KM = 0.047 Mb.) We calculate the moles of solute, using the volume and molar concentration:
725 mL / 1000 = 0.725 L0.047 M * 0.725 L = 0.6778 molesc.) We calculate the molar mass, using the mass and the number of moles:
4.58 g / 0.6778 moles = 6.76 g/molA. The molar concentration of the solution is 0.047 M
B. The mole of the solute in the solution is 0.034 mole
C. The molar mass of the solute is 134.7 g/mol
A. Determination of the molar concentration of the solution.
Osmotic pressure (π) = 875 torr = 875 / 760 = 1.15 atm
Temperature (T) = 25 °C = 25 + 273 = 298 K
Van't Hoff's factor (i) = 1 (non-electrolyte)
Gas constant (R) = 0.0821 atm.L/Kmol
Molarity (M) =?π = iMRT
1.15 = 1 × M × 0.0821 × 298
1.15 = M × 24.4658
Divide both side by 24.4658
M = 1.15 / 24.4658
M = 0.047 MB. Determination of the mole of the solute.
Molarity = 0.047 M
Volume = 725 mL = 725 / 1000 = 0.725 L
Mole of solute =?Mole = Molarity x Volume
Mole of solute = 0.047 × 0.725
Mole of solute = 0.034 moleC. Determination of the molar mass of the solute
Mole of solute = 0.034 mole
Mass of solute = 4.58 g
Molar mass of solute =?Molar mass = mass / mole
Molar mass of solute = 4.58 / 0.034
Molar mass of solute = 134.7 g/molLearn more on Osmotic pressure: https://brainly.com/question/5925156
A student combines a sample of gas (2.0 L) at 3.5 atm with with another gas (1.5 L) at 2.8 atm pressure into an empty 7.0 L flask. Assuming the gases are combined at constant temperature, what is the total gas pressure (in atmospheres) in the 7.0 L flask?
Answer:
Total gas pressure is 1.60 atm
Explanation:
To solve this question we can use the Ideal Gases Law. We need to determine how many moles of each gas will be finally present at the flask of 7 L.
Let's asume the gas, are at Asbsolute T°, 273K
P. V = n . R . T
3.5 atm . 2L = n . 0.082 . 273K
(3.5 atm . 2L) / (0.082 . 273K) = 0.313 moles
(2.8 atm . 1.5L) / (0.082 . 273K) = 0.188 moles
Total moles = 0.313 mol + 0.188 mol = 0.501 mol
Let's calcualte the hole pressure
P . 7L = 0.501 moles . 0.082 . 273K
P = (0.501 moles . 0.082 . 273K) / 7L → 1.60 atm
what is the molecular geometry of c atom in ch3nh2
Answer:
compound is sp3.
Explanation:
The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.
Answer:
1.86 M
Explanation:
From the question given above, the following data were obtained:
Mass of sucrose (C12H22O11) = 22.5 g
Volume of solution = 35.5 mL
Molarity of solution =?
Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:
Mass of sucrose (C12H22O11) = 22.5 g
Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)
= 144 + 22 + 176
= 342 g/mol
Mole of C12H22O11 =?
Mole = mass /Molar mass
Mole of C12H22O11 = 22.5 /342
Mole of sucrose (C12H22O11) = 0.066 mole
Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:
1000 mL = 1 L
Therefore,
35.5 mL = 35.5 mL × 1 L / 1000 mL
35.5 mL = 0.0355 L
Thus, 35.5 mL is equivalent to 0.0355 L.
Finally, we shall determine the molarity of the solution as follow:
Mole of sucrose (C12H22O11) = 0.066 mole
Volume of solution = 0.0355 L.
Molarity of solution =?
Molarity = mole /Volume
Molarity of solution = 0.066/0.0355
Molarity of solution = 1.86 M
Therefore, the molarity of the solution is 1.86 M.
2. Find the ΔH for the reaction below, given the following reactions and subsequent ΔH
values:
2C2(g) + H2O(g) → C2H2(g) + ⁵/₂ O2(g)
C2H2(g) + 2H2(g) → C2H6(g) ΔH = –94.5 kJ
H2O(g) → H2(g) + ½ O2 (g) ΔH =71.2 kJ
C2H6(g) + ⁷/₂ O2(g) → 2 CO2(g) + 3 H2O(g) ΔH = –283 kJ
Using the two models, compare the processes of nuclear fusion and nuclear fission. What do the two processes have in common?
Choose all that apply.
A)
Energy is released.
B)
Elements are created
0)
A chain reaction occurs.
D)
Besides energy, neutrons are released.
E)
Both processes begin with an unstable nucleus.
Answer:it’s A and B
Explanation:
Answer:
A and B
Explanation:
They’re both fusion.
In a coffee-cup calorimeter, 1.60 g of NH4NO3 was mixed with 75.0 g of water at an initial temperature of 25.008C. After dissolution of the salt, the final temperature of the calorimeter contents was 23.348C.
Required:
a. Assuming the solution has a heat capacity of 4.18 J 8C21 g21, and assuming no heat loss to the calorimeter, calculate the enthalpy of solution (DHsoln) for the dissolution of NH4NO3 in units of kJ/mol.
b. If the enthalpy of hydration for NH4NO3 is 2630. kJ/mol, calculate the lattice energy of NH4NO3.
Answer:
Explanation:
mass of the solution m = 1.6 + 75 = 76.6 g
fall in temperature = 25 - 23.34 = 1.66°C
heat absorbed = mass x specific heat x fall in temperature
= 76.6 x 1.66 x 4.18
= 531.5 J .
= .5315 kJ .
mol weight of ammonium nitrate = 80 g
heat absorbed by 1.6 g = .5315 kJ
heat absorbed by 80 g or one mole = 26.575 kJ
enthalpy change ΔH = +26.575 kJ
b )
enthalpy of hydration = 2630 kJ / mol
lattice energy = enthalpy of hydration + enthalpy change
= 2630 + 26.575
= 2656.575 kJ .
the difference in energy between the n=1 and n=2 energy levels in a hydrogen atom is 1.64x10^-18 J. what happens when an electron in a hydrogen atom transitions from n=2 to n=1?
Answer:
It emits 1.64 x 10⁻¹⁸J of energy
Explanation:
The n = 1 is a lower quantum level compared to n = 2.
When a hydrogen atom moves from a higher level to a lower one, it simply emits the energy difference between the two levels.
If a hydrogen atom moves from a lower energy level to a higher one such as from 1 to 2, they absorb the energy difference to attain the new excited state. So, for an electron in the hydrogen atom to move from a higher energy level to a lower one, it must emit 1.64 x 10⁻¹⁸J of energy.I need help, due in 30 mins
Answer:
1.Reaction rate is how fast a chemical reaction proceeds.
2.Nature of the reaction, Pressure factor
, Solvent, Catalyst and inhibitors.
3.Physical change is a temporary change. A chemical change is a permanent change. A Physical change affects only physical properties i.e. shape, size, etc.
4. One example of the effect of temperature is the use of lightsticks or glowsticks.
5.When the particle size of a fixed mass of a solid reactant becomes smaller, the total exposed surface area becomes larger, the rate of reaction increases. an example could be ice and water when the atoms are stuck together a solid but all over the place as a liquid.
6. Sometimes a reaction depends on catalysts to do their job. In that case, changing the concentration of the catalyst can speed up or slow down the reaction. For example, enzymes speed up biological reactions, and their concentration affects the rate of reaction.
7.A catalyst is a chemical substance that affects the rate of a chemical reaction by altering the activation energy required for the reaction to proceed. For example, a catalyst could cause a reaction between reactants to happen at a faster rate or at a lower temperature than would be possible without the catalyst.
Explanation:
I hope this helps have a great day! :)
how does mass and volume affect sinking and floating? Please don't plagiarize....
Answer:
If an object has a higher density than the fluid it is in (fluid can mean liquid or gas), it will sink. If it has a lower density, it will float. Density is determined by an object's mass and volume. If two objects take up the same volume, but have one has more mass, then it also has a higher density.
Explanation:
is a salt water solution saturated when there is undissolved salt at the bottom of the bottle?
Answer:
Yes
Explanation:
Lake Michigan holds 13 billion gallons of water. If just Chicago removed water from the lake and it never rained again, how many decades would the water last?
Answer:
Check explanation section.
Explanation:
In order to be able to answer this question accurately,there is need to follow the formula below for the calculation;
Numbers of decades = total volume/ volume per decade. ----------------------(1).
So, we are given from the Question above that the volume of water in Lake Michigan = 13 billion gallons of water.
And if chicago uses 5 million gallons of water every decade.
Therefore, using the formula (1) above, we have;
Numbers of decades = 13 × 10^9/ 5 × 10^6 = 2.6 × 10^15 decades.
Explain why a buffer can be prepared from a mixture of NH4CL and NaOH but not from NH3 and NaOH .
A buffer solution is often referred to as a mixture of an aqueous solution of a weak acid and its conjugate base or weak base and its conjugate acid.
NH4CL is a weak base and NaOH is a strong base and when both it gives you a basic buffer and the result will give you an acid/base needed for the buffer.NH 3 is a weak base, but NaOH is a strong base and therefore the combination of these solutes would not make a buffer solution because both will give you a base and no acid.Conclusively we can say that an acid or base needed for making buffer solutions and not base alone
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For a 0.300 mol sample of helium gas in a 0.200 L container at 248K, will the pressure be greater if calculated with the ideal gas law or the van der Waals equation, and by roughly how much? (For He,a=0.0342L2atmmol2,b=0.0237 Lmol)
Answer:
It changes by roughly 1 atm.
Explanation:
Hello!
In this case, since the ideal gas equation differs from the van der Waals' one by the presence of the a and b parameters which correct the assumption of no interactions into the container, they are written as:
[tex]P=\frac{nRT}{V}\\\\P=\frac{RT}{v_m-b}-\frac{a}{v_m^2}[/tex]
Thus, the pressure via the ideal gas equation is:
[tex]P=\frac{0.300mol*0.082\frac{atm*L}{mol*K}*248K}{0.200L}=30.5atm[/tex]
And the pressure via the van der Waals equation, considering the molar volume (vm=0.200L/0.300L=0.667L/mol) is:
[tex]P=\frac{0.082\frac{atm*L}{mol*K}*248K}{0.667L/mol-0.0237L/mol}-\frac{0.0342atm*L^2/mol^2}{(0.667L/mol)^2}\\\\P=31.6atm-0.0769atm\\\\P=31.5atm[/tex]
It means that the pressure change by 1 atm, which is not a significant difference for helium.
The difference in pressure calculated by the two methods is 84 atm.
The ideal gas equation is given by
PV =nRT
From the data given in the question;
P = ?
V = 0.200 L
n = 0.300 mol
T = 248K
R = 0.082 atmLK-1Mol-1
P = nRT/V
P = 0.300 mol × 0.082 atmLK-1Mol-1 × 248K/0.200 L
P = 30.5 atm
From Van der Waals equation;
P = RT/V - b - a/V^2
P = (0.082 × 248/0.200 - 0.0237) - (0.0342/ 0.200^2)
P = 114.5 atm
The difference in pressure calculated by the two methods is;
114.5 atm - 30.5 atm = 84 atm
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Is adding food coloring to frosting a chemical reaction?
Answer:
no
Explanation:
Answer:
Yes
Explanation:
Adding food coloring to batter or to your icing involves a chemical reaction of the two products bonding together. This bonding process starts when you add the color and mix it in, but it doesn't end straight away as the color needs some time to fully integrate and settle.
The equation for the reaction of magnesium ribbon and hydrochloric acid is
Mg(s) + 2 HCl(aq) → MgCl2(aq) + H2(g)
If 1.53 g magnesium reacted, how many moles of hydrogen gas was produced?
Report your answer to three significant figures.
Mg = 24.3 g/mol
Answer: .063
Explanation:
1.53g Mg * (1 mol Mg/ 24.3 g Mg) * (1 mol H2/1 mol Mg) = .063 mol H2
The mole of hydrogen gas that will be produced from the reaction would be 0.0630 moles.
From the equation of the reaction:
[tex]Mg(s) + 2 HCl(aq) ---> MgCl_2(aq) + H_2(g)[/tex]
The mole ratio of Mg to H2 gas is 1:1. Thus, for every one mole of Mg consumed by the reaction, 1 mole of H2 is produced, all other things being equal.
Recall that: mole = mass/molar mass
1.53 g of magnesium = 1.53/24.3
= 0.0630 mole (to 3 significant figures)
Since the mole ratio of Mg to H2 is 1:1, it means that the number of moles of hydrogen gas produced would also be 0.0630 moles.
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How is thermal energy transferred during conduction? Check all that apply.
Thermal energy is transferred hetween particles that are not touching each other.
Thermal energy is transferred between particles that are in direct contact with each other.
Thermal energy is transferred between objects of different temperatures.
Thermal energy is transferred between objects of the same temperature.
Thermal energy is transferred from slow-moving particles to fast-moving particles.
Thermal energy is transferred from fast-moving particles to slow-moving particles.
Answer:energy
Explanation:needed points sorry
What is the difference between homogeneous and heterogeneous mixtures?
1) If a bottle of olive oil contains 1.3 kg of olive oil, what is the volume, in milliliters, of the olive oil? Express your answer to two significant figures and include the appropriate units. 2) A cannon ball made of iron has a volume of 116 cm^3. What is the mass, in kilograms, of the cannon ball? Express your answer to three significant figures and include the appropriate units. 3) A balloon filled with helium has a volume of 6.1 L. What is the mass, in grams, of helium in the balloon? Express your answer to two significant figures and include the appropriate units.
Answer:
1) 1.4 × 10³ mL
2) 0.913 kg
3) 1.1 g
Explanation:
1)
Step 1: Calculate the volume of 1.3 kg of olive oil
The density of olive oil is 0.917 kg/L.
1.3 kg × (1 L/0.917 kg) = 1.4 L
Step 2: Convert the volume to mL
We will use the relationship 1 L = 10³ mL.
1.4 L × (10³ mL/1 L) = 1.4 × 10³ mL
2)
Step 1: Calculate the mass of the cannon ball
The density of iron is 7.87 g/cm³.
116 cm³ × 7.87 g/cm³ = 913 g
Step 2: Convert the mass to kg
We will use the relationship 1 kg = 10³ g.
913 g × (1 kg / 10³ g) = 0.913 kg
3)
Step 1: Calculate the mass of the helium in the balloon
The density of balloon is 0.18 g/L.
6.1 L × 0.18 g/L = 1.1 g