Answer:
The pressure of the air in the tyre is 20 kPa
Explanation:
The parameters for the bicycle pump and tyre are;
The volume of air contained in the bicycle pump, V₁ = 20 cm³
The pressure of the air contained in the bicycle pump, P₁ = 100 kPa
The volume (available) of the tyre, where the air is pumped, V₂ = 100 cm³
Let P₂ represent the pressure in the tyre after the air is pumped
By Boyle's law, we have that at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure;
Mathematically, Boyle's law gives the following equation;
P₁ × V₁ = P₂ × V₂
∴ P₂ = (P₁ × V₁)/V₂
Substituting the known values gives;
P₂ = (100 kPa × 20 cm³)/(100 cm³)
∴ P₂ = 100 kPa × 1/5 = 20 kPa
P₂ = 20 kPa
The pressure of the air in the tyre = P₂ = 20 kPa.
What is the netforce of the dog thanks!
Answer:
5 Newtons Up and 5 Newtons Right
Explanation:
Treat each force vector as a value and choose the upward and rightward directions to be positive. Downward and Leftward forces will be considered "negative". For the vertical net force we have a positive 10 N upwards and a negative 5 N downwards. The net force in the vertical will be 5 N upwards. In the horizontal we have 10 N to the right and 5 N to the left. The net force in the horizontal will be 5 N to the Right.
It is easier if you split the motion into horizontal and vertical components.
And tell me I was holding a 1 pound bag of apples and his left hand and a 2 pound bag of apples in his right hand which sentences about this situation are true
Answer:
B. Antonio is applying a 1-pound force to hold the 1-pound bag. E. The mass of the bag in his left hand is less than the mass of the bag in his right hand.Explanation:
In order for one to carry something, they need to be exerting a force that is equal to the weight of the object. For Antonio therefore to hold the 1-pound bag, he needs to apply a 1-pound force.
Pounds measure the mass of an object. On his left hand Antonio has 1 pound and on the right he has 2. He is therefore carrying more mass on his right hand than on his left.
Can someone help me :(
Din Djarin pushes on a crate of frog eggs (with a mass of 88) with a force of 240 N, if µs= .4 and µk= .133 what is the net force acting on the crate?
I'll give brainliest to anyone who can answer this, too.
Answer:
R = mg
F = µsR
Fs= 0.4 × ( 88 × 10)
Fs = 772 N
Fk= µk R
Fs= 1.33 × 880 N
Net force = (772+(1.33×880))-240 N
Which of the following is an example of an unbalanced force?
A. Book sitting on a table
B. Car sitting in the garage
C. Person on an elevator going down
D. Person leaning on a wall
How did the leaning tower of Pisa start leaning?
Answer:
The foundation was somewhat bad
Explanation:
The leaning was caused by the uneven settling of the building's foundations in the soft ground. Three of its eight stories had been completed when the uneven settling of the building’s foundations in the soft ground became noticeable. At that time, war broke out between the Italian city-states, and construction was halted for almost a century. This pause allowed the tower’s foundation to settle and likely prevented its early collapse.
hope this helps:)
A negative charge of -2.0 C and a positive charge of 3.0 C are separated by 80 m. What is the electrostatic force between the two charges? Is the force attractive or repulsive? How do you know?
Answer:
1. 8437500 N
2. The force between the two charges is attractive.
Explanation:
1. Determination of the force between the two charges.
Charge 1 (q₁) = –2.0 C
Charge 2 (q₂) = 3.0 C
Distance apart (r) = 80 m
Electrical constant (K) = 9×10⁹ Nm²/C²
Force (F) =?
F = Kq₁q₂ / r²
F = 9×10⁹ × 2 × 3 / 80²
F = 5.4×10¹⁰ / 6400
F = 8437500 N
Thus, the force of attraction between the two charges is 8437500 N
2. From the question given, the charges are:
Charge 1 (q₁) = –2.0 C
Charge 2 (q₂) = 3.0 C
We understood that like charges repels while unlike charges attract. Since the two charges (i.e –2 C and 3 C) has opposite signs, it means they will attract each other.
Thus the force between them is attractive.
Which of the following is not a product of a complete combustion reaction of a hydrocarbon?
A. energy
B. carbon dioxide
C. carbon
D. water
Answer:
I think the answer might be C
C. Carbon is not a product of a complete combustion reaction of a hydrocarbon.
What is complete combustion?Complete combustion is a process in which all carbon contained in a fuel or gas stream is converted to carbon dioxide.
The generic equation for the complete combustion of a hydrocarbon is:
CxHy + O₂ ⇒ CO₂ + H₂O + Energy
Let's consider which of the following is a product of a complete combustion reaction of a hydrocarbon.
A. energy. YES.
B. carbon dioxide. YES.
C. carbon. NO.
D. water. YES.
C. Carbon is not a product of a complete combustion reaction of a hydrocarbon.
Learn more about complete combustion here: https://brainly.com/question/9913173
sort the facts into the category that they best describe sound waves and electromagnetic waves
Answer:
Sound waves have a low speed of 330 m/s
Sound waves are mechanical waves
Electromagnetic waves have a greater speed of 3.0×10^8 m/s
Electromagnetic waves are due to disturbance of electromagnetic objects.
A dilute solution has of solute in the solvent
Explanation:
"The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution. A concentrated solution is one that has a relatively large amount of dissolved solute. A dilute solution is one that has a relatively small amount of dissolved solute."
The world's largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds. What is the velocity for one of the blades? (THIS IS PHYSICS, CIRCULAR MOTION)
Answer:
The velocity of the blades is 88.185 m/s.
Explanation:
Given;
length of the blade, r = 80 m
angular speed, ω = 1 rev per 5.7 seconds
The velocity of the blades is calculated by applying the following circular motion equation that relates linear velocity (V) and angular speed (ω);
[tex]V = \omega r\\\\V = (\frac{1 \ rev}{5.7 \ s} \times \frac{2 \pi \ rad}{ 1 \ rev} )(80 \ m)\\\\V = 88.185 \ m/s[/tex]
Therefore, the velocity of the blades is 88.185 m/s.
What is a transferable skill?
ОА.
a summary of experiences
OB.
the ability to do something
C.
the movement of skills from one experience to another
OD
a skill you learn from another person
Answer:
I think D is correct option
For the lever below calculate the position of the fulcrum if mass "A" = 25
kg and mass "B" = 100 kg and the leaver is 25 meters in length.
How many different genera are represented?
The subject is in SCIENCE
Explanation:
Numbers of accepted genera
The numbers of either accepted, or all published genus names is not known precisely; Rees et al., 2020 estimate that approximately 310,000 accepted names (valid taxa) may exist, out of a total of c.
A weight of 6 kg increases the speed of its force from 2 m / s to 4 m / s. By how many joules does the kinetic energy of the body increase?
Answer:
36 J
Explanation:
Let's start off with the Kinetic Energy formula: 1/2m[tex]v^{2}[/tex]
So to find the change in Kinetic Energy, you would first have to find the Kinetic Energy in the beginning and in the end.
*Note: Mass: you incorrectly wrote weight = 6 kg- because weight is a force you have to write 6 Newtons. If you are talking about the mass, you would write 6 kg. If you are talking about weight, you would write 6 Newtons. The difference will make significant changes to the answer, so I will give you the answer for both.
If 6 kg is the MASS:
Beginning: find the kinetic energy.
Plug in all parts of the formula: 1/2mv^2 = [tex]\frac{1}{2}[/tex](6)(2 squared)= [tex]\frac{1}{2}[/tex](6)(4)= 12 J
End: find the kinetic energy.
Plug in all parts of the formula: 1/2mv^2=[tex]\frac{1}{2}[/tex](6)(4 squared)=[tex]\frac{1}{2}[/tex](6)(16)= 48 J
Answer:
36 J
If 6 kg is the WEIGHT:
We know that the weight formula is mg, or mass times acceleration due to gravity (which is always 9.8 m/s^2). Plug in the numbers:
Weight = mass x acceleration due to gravity
6 = mass x 9.8
6 = 9.8m
*Divide both sides*
mass = 0.6 kg
Now, we can use the mass to find the kinetic energy.
Beginning: find the Kinetic Energy
Plug in all parts of the formula: 1/2mv^2 = [tex]\frac{1}{2}[/tex](0.6)(2 squared)= [tex]\frac{1}{2}[/tex](0.6)(4)= 1.2 J
End: find the Kinetic Energy
Plug in all parts of the formula: 1/2mv^2=[tex]\frac{1}{2}[/tex](0.6)(4 squared)=[tex]\frac{1}{2}[/tex](0.6)(16)= 4.8 J
Answer:
3.6 J
(this answer is not very feasible, so 36 J is the way to go. But just remember, don't mix up weight and mass again- as you can see, they lead to different answers!)
HELP PLEASE WILL GIVE BRAINLIEST!
Find the mass of an object that has a density of 1.5 g/cm^3 and has a volume of 8 cm^3
Answer:
12 grams
Explanation:
To calculate mass, we can use the following formula:
Mass = density × volume
Plug in the values
Mass = 1.5 × 8
Mass = 12
Therefore, the mass of the object is 12 grams.
I hope this helps!
Given that both liquid A and B exert the same amount of pressure .What would be the height of column of liquid A if the density of liquid A is twice the density of liquid B and the height of column of liquid B is 10cm ?show you are work?
Answer:
ans 5
Explanation:
hope it's help It seems to me
The blades of a metal cutter are shorter than the blades of paper cutter scissor. Give reason
Answer:
Metal is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the metal. Paper on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.
A 1.00 kg object moving in the + x direction at 10.0 m/s collides with a 1.50 kg object traveling at 5.00 m/s in the - x direction. After the collision, the 1.00 kg object moves with a velocity of 4.00 m/s in the - x direction. How much kinetic energy was lost during the collision?
Answer:
The amount of kinetic energy lost during the collision is 60.75 J
Explanation:
The given parameters are;
The mass of the object moving in the +x direction, m₁ = 1.00 kg
The velocity of the object moving in the +x direction, v₁ = 10.0 m/s
The mass of the object moving in the -x direction, m₂ = 1.50 kg
The velocity of the object moving in the +x direction, v₂ = 5.00 m/s
The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s
The direction of motion of the 1.00 kg mass after collision = -x direction
The total initial kinetic energy of the system, [tex]K.E._{total \ initial}[/tex] = 1/2·m₁·v₁² + 1/2·m₂·v₂²
∴ [tex]K.E._{total \ initial}[/tex] = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J
The final kinetic energy of the system, [tex]K.E._{final}[/tex] = 1/2·m₁·v₃²
[tex]K.E._{final}[/tex] = 1/2×1.00×4² = 8 J
The amount of kinetic energy lost during the collision, [tex]\Delta K.E._{system}[/tex] is given as follows;
[tex]\Delta K.E._{system}[/tex] = [tex]K.E._{final}[/tex] -[tex]K.E._{total \ initial}[/tex] = 8 J - 68.75 J = -60.75 J
The amount of kinetic energy lost during the collision = 60.75 J.
Soccer is technically know as what ?
a - Futbol
b - Association football
c - Association soccer
Answer:
c - Association soccer
because there is football in form of American football, hence it's soccer
Answer:
B.
Explanation:
Soccer was the only football-type game in the United States until American-style football became popular in the 1870s
a person who drives under the influence of alcohol or drugs blank?
Answer:
alcohol
Explanation:
alcohol is drives under the influence
Answer:
Has lost the ability to make wise decisions
The laws of reflection holds for__
a) plane mirrors. b) spherical mirrors.
c)both. d) None of them.
Answer:
c)both
Explanation:
The laws of reflection hold true for all the reflecting surfaces either spherical or plane. Therefore, the plane mirror, concave mirror and the convex mirror all will follow the laws of reflection.
Answer:
It holds for only plane mirrors
It states that the angle of incidence is equal to the angle of reflection.
This is only possible in plane mirrors only
A ball is thrown horizontally at a speed of 24 meters per second from the top of a cliff. if the ball hits the ground 4.0 seconds later, approximately how high is the cliff?
Answer:
78.4 m
Explanation:
To obtain the height of the cliff;
We can use the Relation to obtain the final velocity, v
v = u + at
a = acceleration due to gravity = 9.8m/s²
v = 0 + (9.8*4)
v = 0 + 39.2
v = 39.2 m/s
To obtain the Height, S
v² = u² + 2aS
39.2^2 = 0 + 2(9.8)S
39.2^2 = 0 + 19.6S
1536.64 = 19.6S
S = 1536.64 / 19.6
S = 78.4 m
A flexible container holds 1.5 L of gas at a pressure of 3 atm. The volume is adjusted and the new pressure is measured at 2 atm. What is the new volume of the container?
Answer:
The final volume of the gas is 2.25 L.
Explanation:
Given;
initial volume of the gas, V₁ = 1.5 L
initial pressure of the gas, P₁ = 3 atm
final pressure of the gas, P₂ = 2 atm
final volume of the gas, V₂ = ?
Apply Boyle's law to determine the final volume of the gas;
P₁V₁ = P₂V₂
V₂ = (P₁V₁) / P₂
V₂ = (3 x 1.5) / (2)
V₂ = 2.25 L
Therefore, the final volume of the gas is 2.25 L.
What temperature will the hot plate reach when set to 300 degrees celsius?
The bouncing back of a ray of light , sound , or heat when the ray hits a surface that it does not penetrate
A . Refraction
B . Reflection
C. Resonance
D. Standing Wave
Answer:
B. reflection
Explanation:
Have a good day! :)
The bouncing back of a ray of light, sound, or heat when the ray hits a surface that it does not penetrate is called a reflection, so option B is correct.
What is Reflection?Reflection is the abrupt change in a wave's propagation direction when it encounters a boundary between two media. The approaching wave disturbance is still present in the same medium, at least in part. At plane borders, reflection happens regularly and follows a straightforward law.
Angles of incidence (between the oncoming wave's direction of motion and a perpendicular to the reflecting surface) are identical to angles between the reflected wave's direction of motion and a perpendicular (angle of reflection). Diffuse reflection occurs at uneven or irregular boundaries. The percentage of the wave's energy that is reflected by a surface material is known as its reflectivity.
Therefore, the bouncing back of a ray of light, sound, or heat when the ray hits a surface that it does not penetrate is called a reflection.
To know more about Reflection:
https://brainly.com/question/2254222
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Describe the conceptual relationship between energy and force.
Answer:
When two objects interact, each one exerts a force on the other that can cause energy to be transferred to or from the object. For example, when energy is transferred to an Earth-object system as an object is raised, the gravitational field energy of the system increases.
Explanation:
Force and work are directly proportional to each other, while force and displacement are indirectly propotional. The equation showing the relationship is W= Fd. W represents work measured in joules; F represents force in newtons; and d represents distance in meters.
When comparing mass and size data for the planets Earth and Jupiter, it is observed that Jupiter is about 300 times more massive than Earth. One might quickly conclude that an object on the surface of Jupiter would weigh 300 times more than on the surface of the Earth. For instance, one might expect a person who weighs 500 N on Earth would weigh 150000 N on the surface of Jupiter. Yet this is not the case. In fact, a 500 N person on Earth weighs about 1500 N on the surface of Jupiter. Explain how this can be.
Answer:
This situation happens because radius of Jupiter is 10 times greater than radius of the Earth.
Explanation:
According to Newton's Law of Gravitation, weight is directly proportional to the mass of the planet ([tex]M[/tex]), measured in kilograms, and inversely proportional to the square of the radius of the planet ([tex]R[/tex]), measured in meters. That is:
[tex]W \propto \frac{M}{R^{2}}[/tex]
[tex]W = \frac{k\cdot M}{R^{2}}[/tex](1)
Where [tex]k[/tex] is proportionality constant, measured in Newton-square meters per kilogram.
Then, we eliminate the proportionality constant by constructing this relationship:
[tex]\frac{W_{J}}{W_{E}} = \left(\frac{M_{J}}{M_{E}}\right)\cdot \left(\frac{R_{E}}{R_{J}} \right)^{2}[/tex]
Where subindices J and E mean "Jupiter" and "Earth", respectively. If we know that [tex]\frac{M_{J}}{M_{E}} = 300[/tex], [tex]W_{E} = 500\,N[/tex]and [tex]W_{J} = 1500\,N[/tex], then the ratio of radii is:
[tex]\frac{R_{E}}{R_{J}} = \sqrt{\left(\frac{W_{J}}{W_{E}} \right)\cdot \left(\frac{M_{E}}{M_{J}} \right)}[/tex]
[tex]\frac{R_{E}}{R_{J}} = \sqrt{3\cdot \left(\frac{1}{300} \right)}[/tex]
[tex]\frac{R_{E}}{R_{J}} = \frac{1}{10}[/tex]
Therefore, this situation happens because radius of Jupiter is 10 times greater than radius of the Earth.
A merry-go-round of radius 2 m is rotating at one revolution every 5 s. A
child is located at 1 m from the axis. A teenager is located at 2 m from the
axis.
What is the angular speed of the child?
What is the angular speed of the teenager?
What is tangential speed of the child?
What is the tangential speed of the teenager?
Answer:
a) The angular speed of the child is approximately 1.257 rad/s
b) The angular speed of the teenager is approximately 1.257 rad/s
c) The tangential speed of the child is approximately 1.257 m/s
d) For the child, r = 2 m
The tangential speed of the teenager is approximately 2.513 m/s
Explanation:
The revolutions per minute, r.p.m. of the merry-go-round = 1 revolution/(5 s)
The radius of the merry-go-round = 2 m
The location of the child = 1 m from the axis
The location of the teenager = 2 m from the axis
1 revolution = 2·π radians
Therefore, we have;
The angular speed, ω = (Angle turned)/(Time elapsed) = (2·π radians)/(5 s)
∴ The angular speed of the merry-go-round, ω = 2·π/5 radians/second
a) The angular speed of the child = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s
b) The angular speed of the teenager = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s
c) The tangential speed, v = r × The angular speed, ω
Where;
r = The radius of rotation of the object
For the child, r = 1 m
The tangential speed of the child = 1 m × 2·π/5 radians/second = 2·π/5 m/s ≈ 1.257 m/s
d) For the child, r = 2 m
The tangential speed of the teenager = 2 m × 2·π/5 radians/second = 4·π/5 m/s ≈ 2.513 m/s
it regulates the amount of light passing through the spicemen. A. arm B. base C. body tube D. diaphragm
Answer:
D. diaphragm
Explanation:
The question above is related to the different parts of the microscope. Among the choices above, it is the diaphragm that regulates the amount of light passing through the specimen. This is located below the stage (the platform where the slide of specimen is placed). With the help of the diaphragm, the intensity of light is controlled, which allows the observer to see the specimen in the best contrast.
Additional Information:
The arm links the base of the microscope to its head.
The base simply supports the microscope.
The body tube links the objective lenses to the eyepiece.