A boat goes 30 km upstream and 44 km downstream in 10 hours. In 13 hours, it can go 40 km upstream and 55 km down-stream. Determine the speed of the stream and that of the boat in still water.

Answers

Answer 1

Answer:

Average speed of boat = 3.67 km/h

Average speed of stream = 0.63 km/h

Step-by-step explanation:

30 km upstream in 10 hours gives a speed of 30/10 = 3 km/h relative speed of boat and stream

Same way, 44 km in 10 hrs = 4.4 km/h relative speed of boat and stream.

Let the speed of the stream be y

Let the speed of both be x, then

x - y = 3.... (1)

x + y = 4.4.... (2)

Subtract 1 from 2

2y = 1.4

y = 1.4/2 = 0.7 km/h

substitute value of y in 1

x - 0.7 = 3

x = 3.7 km/h

Also, 40 km upstream in 13 hrs gives speed of 3.08 km/h

55 km in 13 hrs gives 4.2 km/h

Let speed of boat be x and that of stream be y

x - y = 3.08.... (1)

x + y = 4.2..... (2)

Subtract 1 from 2

2y = 1. 12

y = 0.56 km/h

Substitute value of y in 1

x - 0.56 = 3.08

x = 3.64 km/h

Average speed of boat = (3.7 + 3.64)/2

= 3.67 km/h.

Average speed of stream = (0.7 + 0.56)/2 = 0.63 km/h

Answer 2

Answer:

Let the speed of boat in stream be x km/hrAnd the speed of boat in still water be y km/hr.For upstream = x - yFor downstream = x + y

As we know that,

[tex]\bigstar \: \: \sf Time = \dfrac{Distance}{Speed} \\ \\ [/tex]

[tex]\bigstar\:\underline{\boldsymbol{According\: to \:the\: Question\:now :}} \\[tex]

[tex]:\implies \sf \dfrac{30}{x - y} + \dfrac{44}{x + y} = 10 \\ \\ \\ [/tex]

[tex]:\implies \sf \dfrac{40}{x - y} + \dfrac{55}{x + y} = 13 \\ \\ \\[/tex]

[tex]\sf Let \: \dfrac{1}{x - y} = \textsf{\textbf{m}} \sf \: \: and \: \: \sf{\dfrac{1}{x + y} = \textsf{\textbf{n} }}\\ \\ \\[/tex]

[tex]:\implies \sf 30m + 44n = 10\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (i)}}\Bigg\rgroup \\ \\ \\[/tex]

[tex]:\implies \sf 40m + 55n = 13\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (ii)}}\Bigg\rgroup \\ \\ \\[/tex]

[tex]\qquad\tiny \underline{\frak{ Multiply \: equation \: (ii) \: by \: 3 \: and \: equation \: (i) \: by \: 4 :}} \\[/tex]

[tex]:\implies \sf 120m + 176n = 40\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (iii)}}\Bigg\rgroup \\ \\ \\[/tex]

[tex]:\implies \sf 120m + 165n = 39\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (iv)}}\Bigg\rgroup \\ \\ \\[/tex]

[tex]\qquad\tiny \underline{\frak{ Substracting \: equation \: (iii) \: from \: equation \: (iv) \: we \: get :}} \\[/tex]

[tex]\sf 120m + 176n = 40 \\ \\

\sf 120m + 165n = 39 \\ \\ [/tex]

[tex]\sf \: \: ( - ) \:\:\: \: \: ( - ) \: \: \: \: \: \: \: ( - ) [/tex]

_____________________

[tex]\: \: \: \: \qquad\sf 11n= 1 \\[/tex]

[tex]\: \: \: \: \: \qquad\sf n= \dfrac{1}{11} \\ \\ [/tex]

[tex]\qquad\tiny {\frak{ Put\: n = \dfrac{1}{11}\:in\:equation \: (i) \: we \: get :}} \\[/tex]

[tex]\dashrightarrow\:\:\sf 30m + 44 \times \dfrac{1}{11} = 10 \\ \\ \\[/tex]

[tex]\dashrightarrow\:\:\sf 30m= 10 - 4 \\ \\ \\[/tex]

[tex]\dashrightarrow\:\:\sf 30m= 6 \\ \\ \\[/tex]

[tex]\dashrightarrow\:\:\sf m= \dfrac{6}{30} \\ \\ \\ [/tex]

[tex]\dashrightarrow\:\:\sf m= \dfrac{1}{5} \\ \\ \\[/tex]

____________________....

[tex]\dashrightarrow\:\:\sf \dfrac{1}{x - y} = m\\ \\ \\[/tex]

[tex]\dashrightarrow\:\:\sf x - y= 5\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (v)}}\Bigg\rgroup \\ \\ \\[/tex]

[tex]\dashrightarrow\:\:\sf \dfrac{1}{x + y} = n\\ \\ \\[/tex]

[tex]\dashrightarrow\:\:\sf x + y= 11\: \: \: \: \Bigg\lgroup \textsf{\textbf{Equation (vi)}}\Bigg\rgroup \\ \\ \\[/tex]

[tex]\qquad\tiny {\frak{Adding\:equation \: (v) \: and \: equation \: (vi) \: we \: get :}} \\[/tex]

[tex]:\implies \sf 2x = 16 \\ \\ \\[/tex]

[tex]:\implies \underline{ \boxed{ \textsf {\textbf{x = 8 km/hr}}}} \\ \\[/tex]

[tex]\qquad\tiny {\frak{Putting\:x = 8\: in \: equation \: (v) \: we \: get :}} \\[/tex]

[tex]:\implies \sf 8 - y = 5 \\ \\ \\ [/tex]

[tex]:\implies \sf y = 8 - 5 \\ \\ \\[/tex]

[tex]:\implies \underline{ \boxed{ \textsf {\textbf{y = 3 km/hr}}}} \\ \\[/tex]

_________________....

[tex]\bigstar\:\underline{\sf{Therefore\: speed\: of \:boat\: in\: still \:water\: and\: speed\: of\: stream:}} \\[/tex]

[tex]\bullet\:\:\textsf{Speed of boat in stream = \textbf{8 km/hr}}\\[/tex]

[tex]\bullet\:\:\textsf{Speed of boat in still water = \textbf{3 km/hr}}\\[/tex]


Related Questions

i suck at geo please help

Answers

Answer:

It's B

Step-by-step explanation:

Because you see a reflection would show the traingle flipped translation would mean the traingle is in a totally different space and rotation would mean the shape is rotated and so B is left and so B is the correct answer.

find the gradient of the line through (0, 2) and (3,14)​

Answers

Answer:

gradient = 4

Step-by-step explanation:

Calculate the gradient using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (3, 14)

m = [tex]\frac{14-2}{3-0}[/tex] = [tex]\frac{12}{3}[/tex] = 4

an elevator moves at a rate of -5.8 feet per second from a height of
300 feet above the ground. the elevator takes 3 seconds to make its first stop.
how many feet above the ground is the elevator now?

Answers

Answer:

282.6 ft

Step-by-step explanation:

First you must figure out how far the elevator drops in three seconds.

To do so you multiply how far it falls per second (5.8 ft) by how long it falls for (3 seconds). 5.8 * 3 = 17.4

now you subtract 17.4 from 300 to get 282.6 ft

LAT QUESTION AND LAST TRY!!! WILL GIVE BRANLIEST!!!! AT LEAST TAKE A LOOK, SHARE YO SMARTNESSS!!!!!!!! PLS

13. Which is not a pair of congruent sides in the diagram below?

A) KJ AND JH
B) EF AND JH
C) KJ AND FG
D) EK AND GH

Answers

Answer:

A) KJ AND JH

Step-by-step explanation:

EF = JH  The three lines indicate they are equal

EK = GH  The one line indicates they are equal

KJ = FG  The two lines indicates they are equal

Answer:

A) KJ and JH

Step-by-step explanation:

KJ has 2 tally Mark's which differentiate from the number of 3 tally marks that JH hasKJ is congruent to EG JH is congruent to EF(If the number of tally's are different that means that they are not the same length = not congruent)B - EF and JH both have 3 tally marks therefore indicating it is correct and they are equalC - KJ and FG both have 2 tally marks therfore indicating it is correct and they are equalD - EK and GH both have 1 tally mark therefore indicating it is correct and they are both equal

Please help! Correct answers only!

There is a raffle with 200 tickets. One ticket will win a $550 prize, one ticket will win a $510 prize, one ticket will win a $280 prize, and the rest will win nothing. If you have a ticket, what is the expected payoff?

Answers

Answer:

" Expected Payoff " = $ 6.70

Step-by-step explanation:

Consider the steps below;

[tex]Probability of Winning the 550 Dollar Prize - 1 / 200,\\Probability * Money Won = " Expected Payoff " For The 550 Dollar Prize,\\\\1 / 200 * 550,\\" Expected Payoff " - 2.75 Dollars,\\\\Probability of Winning the 510 Dollar Prize - 1 / 200,\\\\1 / 200 * 510,\\" Expected Payoff " - 2.55 Dollars,\\\\Probability of Winning the 280 Dollar Prize - 1 / 200,\\\\1 / 200 * 280,\\" Expected Payoff " - 1.4 Dollars,\\\\[/tex]

[tex]Conclusion ; Expected Payoff = 6.70 Dollars[/tex]

Share £45 in the ratio 4:5

Answers

Answer:

20 : 25

Step-by-step explanation:

A : B : total

4 : 5 : 4+5 = 9

We want to share 45

45/9 = 5

Multiply each share by 5

A :     B    : total

4*5 : 5*5 : 9*5

20 : 25   : 45

What is the volume of a rectangular prism with l = 412 cm, w = 312 cm, and h = 6 cm?

A. 9012 cubic centimeters

B. 9412 cubic centimeters

C. 95 cubic centimeters

D. 9512 cubic centimeters

Answers

The required volume of the rectangular prism is 765792 cubic centimeters. None of the options are correct.

To find the volume of a rectangular prism, you can use the formula:

Volume = length (l) * width (w) * height (h)

Given:

l = 412 cm

w = 312 cm

h = 6 cm

Volume = 412 cm * 312 cm * 6 cm
Volume = 128544 * 6 cubic centimeters
Volume = 771264 cubic centimeters

Thus, the volume of the given rectangular prism is 771264 cubic centimeters.

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if(x+3) and 133 digree is a pair of vertically opposite angles then the measure of x is

Answers

Answer:

x=130

Step-by-step explanation:

as vertically opposite angles are equal therefore,

133=X+3

x=133-3= 130

I hope it helps

Bill and Pete shared 1/2 of a cake. Bill got to eat twice as much cake as Pete. What fraction of the whole cake did Bill eat?

Answers

Answer:

Step-by-step explanation:

Total cake shared=1/2

Pete share=x

Bill= twice as much as Pete

=2x

Pete's share+ Bill's share=total share

x+2x=1/2

3x=1/2

x=1/2÷3

x=1/2×1/3

=1/6

Pete's share=x=1/6

Bill's share=2x

=2(1/6)

=2/6

=1/3

A worker pushes a wheelbarrow with a force of 20N downward and to the left, as shown in the figure below. The angle the handle makes with the horizontal is 34°. Note that the figure is not drawn to scale. Write the force vector F in the form =F+aibj. Do not round any intermediate computations, and round the values in your answer to the nearest hundredth. f=

Answers

Answer:

The values of F will be "16.58 i + 11.18 j".

Step-by-step explanation:

The given values are:

Force, F = 20 N

Angle, Ф = 33°

The formula use in the given scenario will be:

⇒  [tex]x=a \ Cos\theta[/tex]

⇒  [tex]y=a \ Sin\theta[/tex]

Now,

For Force, [tex]F=ai+bj[/tex]

⇒  [tex]a=F \ Cos\theta[/tex]

⇒     [tex]=20 \ Cos(34^{\circ})[/tex]

⇒     [tex]=20\times .829[/tex]

⇒     [tex]=16.58[/tex]

and,

⇒  [tex]b=F \ Sin\theta[/tex]

⇒     [tex]=20 \ Sin(34^{\circ})[/tex]

⇒     [tex]=20\times .55[/tex]

⇒     [tex]=11.18[/tex]

So that,

⇒  [tex]F=16.58 \ i+11.18 \ j[/tex]


A sector with a central angle measure of 4pi/5
(in radians) has a radius of 5 cm.
What is the area of the sector?


Answers

Answer:

10 pi

Step-by-step explanation:

25 pi

20 pi

10 pi

5 pi

C is the answer

The area of the shaded sector of the circle will be 10π units².

What is the Area of a Sector?

Area of a sector of a circle = θ/360 × πr², where r is the radius of the circle and θ is the central angle.

As per the question, QR = 5 and m∠RQS = 4π/5 = 144°.

As per the given question given data:

θ = 4π/5

r = QR = 5

Substitute the values in the formula to get:

Area of sector of a circle = 144/360 × π(5)²

Area of sector of a circle = 1/4 × π(25)

Apply the multiplication operation, and we get

Area of a sector of a circle = 10π units²

Thus, the area of the shaded sector of the circle is 10π units².

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The question seems to be incomplete the correct question would be:

In circle Q, QR = 5 and m∠RQS = 4π/5. Find the area of the shaded sector.

Express your answer as a fraction times pi.

What is the area of the figure? A. 360 km² B. 432 km² C. 720 km²
D. 864 km²​

Answers

The answer is 360km^2

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

25x⁴+4x⁴y²+4y⁴ answer this​

Answers

Answer:

(5x²+2y² + 2xy)(5x²+2y²-2xy)

Step-by-step explanation:

25x⁴+4x²y²+4y⁴= (5x²)²+2*5x²*2y²+(2y²)² - 16x²y²= (5x²+2y²)² - (4xy)²= (5x²+2y² + 2xy)(5x²+2y² - 2xy)

Someone have the answer please ?!

Answers

True because they are vertical angles

True if the lines were not vertical this would be false.

find the vertical asymptote. y = x - 1 / x + 4

Answers

Answer:

x = - 4

Step-by-step explanation:

Given

y = [tex]\frac{x-1}{x+4}[/tex]

The denominator of y cannot be zero as this would make y undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 4 = 0 ⇒ x = - 4

Thus the vertical asymptote is x = - 4

solve using eliminates method 3x-4y=15 2x-2y=8​

Answers

Answer:

Step-by-step explanation:

Which of the equations below represents a line parallel to the y-axis? A. x = -y B. x = y C. x = 4y D. x = 4

Answers

Answer:

D

Step-by-step explanation:

A line parallel to the y- axis is a vertical line with equation

x = c

where c is the value of the x- coordinates the line passes through, thus

x = 4 is the equation of a line parallel to the y- axis → D

Which quadratic equation is equivalent to (x + 2)^2 + 5(x + 2) – 6 = 0? A. (u + 2)^2 + 5(u + 2) – 6 = 0 where u = (x – 2) B. u^2 + 4 + 5u – 6 = 0 where u = (x – 2) C. u^2 + 5u – 6 = 0 where u = (x + 2) D. u^2 + u – 6 = 0 where u = (x + 2) (This is a question from Edg by the way)

Answers

Answer:

C. u^2 + 5u – 6 = 0 where u = (x + 2)

Step-by-step explanation:

(x + 2)^2 + 5(x + 2) – 6 = 0

Let u = x+2

(u)^2 + 5(u) – 6 = 0

Answer:

C.u^2+5u-6=0

Step-by-step explanation:

By comparing (x+2)^2+5(x+2)-6=0 to answer C,that is u^2+5u-6=0,u=(x+2).

By sustituting (x+2)into answer C,we get;

(x+2)^2+5(x+2)-6=0 which is the same as the quadriatic equation given in the question.

a cuboid has length 4.2 m breadth 1.4 m and height 1.2 m . find the number of cubes each of lengh 20cm ,which canbe cut from the cuboid.

Answers

l= 4.2 m = 4.2 * 100 = 420 cm

b = 1.4 m = 1.4*100 = 140 cm

h =1.2 m =1.2 *100 =120 cm

Volume of cuboid = l*b*h =  420 * 140 * 120  = 705600 cubic cm

Volume of cube = a*a*a = 20*20*20 = 8000 cubic cm

No.of cubes = Volume of cuboid / volume of cube

      = 705600 / 8000 = 882 cubes

or  420*140*120 / 20*20*20 = 42*14*12/2*2*2 = 21*7*6 = 882 cubes

find the coordinates of the vertices of the triangle after a reflection across the line x= -1 and then across the x-axis​

Answers

Answer:  C

Step-by-step explanation:

Reflection across x = -1

The simplest way to calculate the new coordinates is to draw x = -1, count how many units away the point is from x = -1, then count the same number of units from x = -1 in the OPPOSITE direction to find the reflection. (see attachment)

J = (0, 0) is 1 unit to the right of x = -1

J' = (-2, 0) is 1 unit to the left of x = -1

K = (1, 4) is 2 units to the right of x = -1

K' = (-3, 4) is 2 units to the left of x = -1

L = (3, 3) is 4 units to the right of x = -1

L' = (-5, 3) is 4 units to the left of x = -1

Reflection across x-axis

Change the sign of the y-value:  (x, y) → (x, -y)

J' = (-2, 0)           J'' = (-2, 0)

K' = (-3, 4)           K'' = (-3, -4)  

L' = (-5, 3)            L' = (-5, -3)

Sean began jogging to live a healthier lifestyle. In his first run he ran one half mile he increased his workouts by adding two miles a month to his run he wrote the equation f(x)=0.5+2x to model his progress the variable x represents the number of___?

Answers

Answer:

Step-by-step explanation:

The words "two iles a month" tells us that the expression represened by those words is the "2x" part of the equation. x represents the number of months. The .5 part tells us that he began this process with a half mile.

State the solution
5x-y=14 and x+3y=-10

Answers

Answer:

x = 2, y = - 4

Step-by-step explanation

5x-y=14

x+3y= - 10

x = - 10 - 3y

5(- 10 - 3y) - y = 14

- 50 - 15y - y = 14

-16y = 64

y = - 4

x = -10 - 3y = - 10 - 3*(- 4) = - 10 + 12 = 2

x = 2

A certain substance has a half life of 1 hour. If you start with 3000 grams of the substance, how much will you have in 1 hour?

Answers

Answer:

1500 grams

Step-by-step explanation:

A= P(0.5)^t

A=3000(0.5)^1

A=1500

The answer is 1500 grams

the coordinates of point G ar (4,-2) and the gradient of the straight line GH is -2.The coordinates of point H could be
A.(-1,6)
B.(-1,8)
C.(-1,10)
D.(-1,12)​

Answers

Step-by-step explanation:

Given that the formula of gradient is :

[tex]m = \frac{y2 - y1}{x2 - x1} [/tex]

So you have to try for every coordinates :

Option A,

[tex] \frac{6-(-2)}{-1-4} = - \frac{8}{5} (incorrect) [/tex]

Option B,

[tex] \frac{8-(-2)}{-1-4} = -2 (correct) [/tex]

Option C,

[tex] \frac{10-(-2)}{-1-4} = - \frac{12}{5} (incorrect) [/tex]

Option D,

[tex] \frac{12-(-2)}{-1-4} = - \frac{14}{5} (incorrect) [/tex]

A livestock vaccine is to be given at the rate of 2 milliliters for each 15 pounds of body weight. How much should be given to a 60-pound goat?

Answers

Answer:

8

Step-by-step explanation:

There are 4 times 2 milliliters in each 15 pounds of a 60-pound goat

Answer:80milliliters/pound

Step-by-step explanation:

Rate per a pound = 20/15=4/3

For 60pounds =4*60/3

=80milliliter/pound

What is the slope of a line that passes through (-14,-13) and (7,0)?

A. 21/13

B. 13/21

C. -13/21

D. -21/13

Answers

Answer:

The answer is B.

Step-by-step explanation:

You have to apply gradient formula by using coordinates :

[tex]m = \frac{y2 - y1}{x2 - x1} [/tex]

Let (x1,y1) be (-14,-13),

L3t (x2,y2) be (7,0),

[tex]m = \frac{0 - ( - 13)}{7 - ( - 14)} [/tex]

[tex]m = \frac{13}{21} [/tex]

Please answer correctly !!!!!! Will mark brainliest answer !!!!!!!!!!

Answers

Answer:

see below

Step-by-step explanation:

1. 0 = (r + 1)(r + 8)

Using Zero Product Property, r = -1, r = -8

2. h(r) = (r + 1)(r + 8)

         = r² + 9r + 8

         = (r + 9/2)² - 81/4 + 8

         = (r + 4.5)² - 12.25 (Complete the square)

   Vertex: (-4.5, -12.25)

What is the volume of the rectangular prism, in cubic cm?
9 cm
4 cm
12 cm

Answers

Answer:

V =432 cm^3

Step-by-step explanation:

The volume is given by

V = l*w*h

V = 9*4*12

V =432 cm^3

Write an equation to represent the following statement. 33 is 15 less than k. Solve for k. k= ___

Answers

Answer:

k = 48

Step-by-step explanation:

k - 15 = 33

Add 15 to both sides

k - 15 +15 = 33 +15

k = 48

What would this be and how do i find the answer?

Answers

Answer:

d

Step-by-step explanation:

this says x is greater than -4 meaning the integers cannot include -4

it also says x is less than or equal to one meaning that it can include 1 but not more than 1

d satisfies this inequality.

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The genes of the ath operon code for the enzymes necessary to use athelose as an energy source.You have found the following:The genes of the ath operon are expressed only when the concentration of athelose in the bacterium is high.When glucose is absent, the bacterium needs to metabolize athelose as an energy source as much as possible.The same catabolite activator protein (CAP) involved with the lac operon interacts with the ath operon.Based on this information, how is the ath operon most likely controlled?Drag the labels onto the diagram to identify the small molecules and the states of the regulatory proteins. Not all labels will be used.POSITIVE CONTROLa) Inactive Activator (not glowing, w/o yellow square)b) cAMPc) Active Activator (glowing, w/ yellow square)NEGATIVE CONTROLd) Active Repressor (glowing, w/o yellow square)e) athelosef) Inactive repressor (not glowing, w/ yellow square) The friends now feel ready to try a problem. Suppose an Atwood machine has a mass of m1 = 2.5 kg and another mass of m2 = 8.5 kg hanging on opposite sides of the pulley. Assume the pulley is massless and frictionless, and the cord is ideal. Determine the magnitude of the acceleration of the two objects and the tension in the cord. Describe the procedure of preparing vision and mission statement of an organisation which expression is equivalent to 4(5x+3y) Hace dos das mi prima Eulalia y su novio Javier (se casaron / se llevaron bien) en San Antonio, Texas. La ceremonia fue en una iglesia (mayor / antigua). Ahora no (charlo / recuerdo) de qu ao es la iglesia, pero s que tiene ms de 200 aos. En la boda (haba / naca) mucha gente. Todos los parientes (charlaban / lloraban) con los novios y les decan, ("Felicidades!" / "Sorpresa!"). Eulalia y Javier (cumplan aos / se despedan) el mismo da y la boda fue el da de su cumpleaos. Ahora va a ser una (costumbre / sorpresa) para ellos celebrar su (aniversario / desfile) de bodas y su cumpleaos el mismo da! Nunca estuve en una (antigua / reunin) familiar tan grande. Los (mayores / das festivos) contaban chistes y se rean, (alrededor de / mientras que) los ms jvenes y los nios se divertan bailando o jugando en el patio. Para m el mejor momento fue cuando los novios salan para el aeropuerto mientras que se vean los (mayores / fuegos artificiales) impresionantes. 8. The function of lipoproteins in blood serum is to:a. aid in blood clottingb. transport cholesterolc. maintain pHd. remove defective red blood cells The driver of a train moving at 23m/s applies the breaks when it pases an amber signal. The next signal is 1km down the track and the train reaches it 76s later. The acceleration is -0.26s^2. Find its speed at the next signal. At a state park, the rangers' office knows the current population of deer in the park is 482 animals and predicts the population will increase by 5% per year for the foreseeable future. The park's acreage can currently sustain a population of 645 deer, and the rangers estimate that number will increase over the next t years by 20t - t2. Which system of equations can be solved to find the number of years from now, t, when the population of deer will exceed the number sustainable by the park's acreage? Timm Inc., a calendar year, accrual basis taxpayer, is being sued by a customer who was injured when she tripped over a loose carpet in Timm's retail store. Timm's auditors required the corporation to accrue a $500,000 contingent liability and current year expense. Which of the following statements is true?a. Timm can deduct the $500,000 accrued expense. b. Timm can never deduct the $500,000 expense. c. Timm can deduct the expense in the year in which the liability becomes fixed and determinable. d. Timm can deduct the expense in the year of payment.