A cart sitting at the top of a hill has 9000 J of potential energy. The cart is then pushed and by the time it is half way down the hill it has converted half of its potential energy . If the carts weighs 1000 kilograms then how fast is the cart rolling when it is halfway down the hill?

The direction of magnetic field is towards east.

We have a wire having a mass per unit length carrying 2A current horizontally to the south.

We have to determine the direction of magnetic field intensity.

The mass per unit length is called Linear mass density of any linear body. It is denoted by λ. Mathematically -

λ = m/L

According to the question, we have -

Direct your thumb in the direction of the current which is horizontally towards south and curl the remaining fingers. Now, advance in the direction of the current, you will notice that the direction of magnetic field is eastwards.

Hence, the direction of magnetic field is towards east.

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Answer:

How we know, the equation is:

W = mg

Replacing according our data:

W = 53 kg × 9,8 m/s^2

Resolving:

W = 519,4 N

The weight of the object is of 519,4 Newtons.

Considering the conversion between Celsius degree and Fahrenheit degree, the correct answer is option (e): -25°C is equivalent to -13 Fahrenheit temperature.

The Celsius degree, represented as °C, is the unit created by Anders Celsius. This scale is also called the "Centigrade scale" and in it the temperature is divided into 100 degrees, with 0º C being the freezing point of water and 100º C the boiling point of water.

The Fahrenheit degree is the unit of temperature proposed by Gabriel Fahrenheit in 1724, whose scale sets zero and one hundred in the freezing and evaporation temperatures of ammonium chloride in water. On this temperature scale, unlike the Celsius scale, the freezing point of water is 32º F while the boiling point of water is 212º F.

To perform the conversion, the expression must be applied:

°F= °C× 9/5 + 32

On a very cold day in upstate New York, the temperature is -25°C. Fahrenheit temperature is calculated as:

°F= (-25°C)× 9/5 + 32

Solving:

°F= -13

In summary, the correct answer is option (e): -25°C is equivalent to -13 Fahrenheit temperature.

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Answer:

5600 + 6650 = 12250

Explanation:

Answer:

The water cycles energy source comes from the sun

Explanation:

The sun's solar energy helps evaporate water from several bodies of water which causes the process of transportation

The energy transferred to the eardrum which was exposed to the sound for 1.00 min is [tex]3 \times 10^{-3} J[/tex]

Given:

Threshold of hearing intensity = I = [tex]1[/tex] × [tex]10^-12W/m^2[/tex]

Area of the ear drum = A = [tex]5[/tex] × [tex]10^5m^2[/tex]

Incident power = P = IA

                          = [tex](1* 10^-12W/m^2(5 * 10^5m^2) =[/tex][tex]5[/tex] ×[tex]10^-17W[/tex]

For threshold of pain  the intensity I = [tex]1.00W/m^2[/tex]

The incident power  at the threshold of pain

P  = [tex](5[/tex] × [tex]10^5m^2( 1.00W/m^2) =[/tex] [tex]5[/tex]× [tex]10^-5W[/tex]

b) Ear drum exposed to this sound  t = 1.00min

                                                              = 60s

Energy transferred to ear drum is  E = P × t

                                                             =  [tex]5 \times 10^{-5} \times 60[/tex]

                                                             = [tex]3 \times 10^{-3}\;J[/tex]

 Hence, [tex]3[/tex] ×[tex]10^-3 J[/tex] energy is transferred to the eardrum exposed to this sound for 1.00 min.

The capacity to perform work is known as energy in physics. Potential, kinetic, thermal, electrical, chemical, nuclear, and other types are all possible. As energy is transferred from one body to another, there is also heat and work. Energy is always categorized after it has been transferred based on its nature. As a result, heat transfer may result in thermal energy, whereas labor done may result in mechanical energy.

Motion is a common feature of all energy types. Whenever a body is in motion, for instance, it contains kinetic energy. Even while at rest, a tensioned object like a spring or bow has the ability to move; this is because of the configuration of the object, which carries potential energy. Nuclear energy is similar in that it has potential energy.

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The freezing Point of water is a physical property

The ability of oxygen to react with iron to cause rust is chemical property

Explanation:

Answer:

The object's velocity would increase due to the change in force.

Explanation:

Answer:

d

Explanation:

because ik igvddhh56yfdsaw66 u77rfgtd gyy f music nutren

The component that Chang could leave out and still be able to light up the bub is the switch.

The electric circuit refers to a path that is created for the flow of current. We know that current is the movement of electrons. When we connect a circuit, a proper conduit has been set up so that electrons can pass through.

In this case, we have been told that Chang wants to build a circuit that will light up a bulb from a flashlight, and has a battery, switch, wire, and a light bulb.

The component that Chang could leave out and still be able to light up the bub is the switch.

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Missing parts;

Chang wants to build a circuit that will light up the bulb from a flashlight. Which component could Chang leave out and still light up the bulb? the switch the battery the wire the light bulb

Answer:

A) the battery

Explanation:

The value of m = 1.6 and n = -19

When there are more or fewer protons in an atom than electrons, the substance has an electric charge. While electrons have a negative charge, protons have a positive charge. If a substance has more protons than electrons, it is positively charged; if it has more electrons, it is negatively charged.

The ability to conduct electricity is a characteristic of many fundamental, or subatomic, components of matter. As an illustration, protons and neutrons both have positive charges but electrons have a negative charge.

given:  [tex]q=0.000000000000000000160c[/tex]

Scientific notation of [tex]q= 1.6 X 10^{-19}[/tex]

now compare with the standard form [tex]m X 10^{n}[/tex]

we can say m = 1.6 and n = -19

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Answer:i think its D

Explanation:

The statement that describes the objects’ inertias is "Object A has a greater inertia than Object B.

Newton's first law of motion, states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

This law is also called the law of inertia because it depends on mass of the object.

The greater the mass of an object, the more reluctant it will be to move.

Thus, the statement that describes the objects’ inertias is "Object A has a greater inertia than Object B.

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Answer: The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.

Explanation:

The oxygen gas has  root mean square velocity of 1651.67 m/s.

What is specific heat capacity ?

Scientifically, specific heat capacity is the quantity of heat (J) absorbed by a material when its temperature increases 1 K (or 1 °C) per unit mass, expressed as J/(kg K) or J/(kg °C).

Q = mCΔT

Calculation of temperature of oxygen gas is done below using formulae :

V(rms) = √3RT/M

where;

M is molar mass of oxygen gas = 32 g/mol = 0.032 kg/mol

value of gas constant R = 8.314 J/K.mol

T is temperature of the oxygen gas = 77+273 = 350 k

V(rms) = √3RT/M

V(rms) = √(3x8.314x350)/0.032

V(rms) = √87297/0.032

V(rms) = √2728031.25

V(rms) = 1651.67 m/s

Thus, The oxygen gas has root mean square velocity of 1651.67 m/s.

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The total time taken by the ball to reach Dina is  7.5 × 10³ s.

A frame of reference is a set of reference points—geometric points whose positions are known mathematically and physically—that define the origin, orientation, and scale of an abstract coordinate system.

If a body does not continuously adjust its position in relation to its environment throughout the course of time, it is said to be at rest.

In the frame S', Dina and Owen are at rest.

The speed of the ball with respect to Owen, u =0.800c

The speed of the frame S' with respect to frame S,  v = 0.600c

Distance between Dina and Owen, L(p) = 1.8 × 10¹² m

Speed of light, c = 3 × 10⁸ m/s

Therefore, the ball reaches Dina in time:

t = L(p) / u

t = 1.8 × 10¹² m / 0.8c

t = 1.8 × 10¹² m /(0.8)(3 × 10⁸ m/s)

t = 7.5 × 10³ s

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The two forces that act on the orbit of a planet are velocity of planet and gravity between sun and planet.

The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity. Gravity applies to everything that has mass. Gravity is stronger for objects with higher mass. Along with distance, gravity weakens as well. Therefore, the gravitational pull of two things becomes stronger the closer they are to one another.

The mass of the Earth is what creates gravity. The combined gravitational force of all of its mass acts on the mass in your body.

Velocity of the planet is also related to its gravity.

Forces that acts on the orbit of a planet is force due to velocity and gravity.

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The sound level at a distance of 3.00m from a source is 120dB at  [tex]9.48*10^{5}\;m[/tex] distance is the sound level 10.0 dB

The RMS (root-mean-squared) of the sound pressure measured and averaged over a given length of time is the sound level in decibels. When measured by contemporary integrating sound level meters, measurements are often A-weighted to coincide with the human reaction; see the time-average sound level definition for more information. These measurements are now commonly referred to as the LA eq. Sound pressure is defined as having a sound level when it is compared to a reference sound pressure of 20 Pa using a standard exponential time weighting and a standard frequency weighting. The ratio of the base ten logarithms to the ratio of the sound level in decibels.

(Lw) = 10·log (W/Wo) dB

Given:

Sound level, [tex]Beta = 120\;dB[/tex]

Sound level, [tex]Beta_{a} = 10\;dB[/tex]

r = 3 m

[tex]P = 4\pi r^{2}I\;\;\;\;------equation(1)[/tex]

We know that,

[tex]\beta = 10 \times log(\frac{I}{I_{o} } )[/tex]

Where, [tex]I_{o}=1 \times 10^{-12}\;W/m^{2}[/tex]

Substitute the known value in the sound level equation,

[tex]10 = 10 \times log(\frac{I_{a} }{1 \times 10^{-12} } )[/tex]

[tex]1 = log(\frac{I_{a}}{1 \times 10^{-12} } )[/tex]

[tex]10= \frac{I_{a}}{1 \times 10^{-12} }[/tex]

[tex]I_{a}= 10 \times 1 \times 10^{-12}[/tex]

[tex]I_{a}=1 \times 10^{-11}\;W/m^{2}[/tex]

[tex]P = 4\pi r_{a} ^{2}x_{123} I_{a} \;\;\;\;------equation(2)[/tex]

equation(1) and (2) are equal,

[tex]4\pi r^{2}I = 4\pi r_{a} ^{2}x_{123} I_{a}[/tex]

Simplify the above equation,

[tex]r_{a} = \sqrt{(\frac{I}{I_{a} } )}\;\;r[/tex]

Substitute the known values in the above equation,

[tex]r_{a} = \sqrt{(\frac{1 \times 10^{-12} }{1 \times 10^{-11} } )}\;\times 3[/tex]

By solving the above equation, We get,

[tex]r_{a} = 9.48 \times 10^{5}\;m[/tex]

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Answer:

Magnetic repulsion Is evidernt.

Answer:

The magnetic field flows from the north pole of one magnet to the south pole of the other magnet.

Plato :)

A physical field called an electric field surrounds electrically charged particles and attracts or repels all other charged particles nearby. The physical field of a system of charged particles can also be referred to as the electric field.

In a uniform electric field E, a particle with electric charge q moves in a straight line. The speed of the particle is u.

The electric force exerted in the charge is qE.

The electric field and the velocity of the particle are both in the x direction.

Now,

The particle starts from rest i.e. x = 0 and t = 0.

We have the acceleration of the particle as:

a = (du/dt) = (qE/m) (( 1 - (u²/c²) )⁻³/²

Now,

du/ (( 1 - (u²/c²) )⁻³/² = (qE/m) t

Integrating the above equation with limits for x as 0 to u and for t as 0 to t.

We get,

u/(1 - (u²/c²))^{-1/2} = qEt/m

Therefore,

u = (qEct)/[√(m²c² + q²E²t²)]

For the position of the particle:

The position of the particle will be the integration of the speed of the particle in t = 0 to t = t.

Therefore,

x = ∫udt

x = qEc∫ tdt/(√(m²c² + q²E²t²) )

x = (c/qE) ( √(m²c² + q²E²t²) - mc)

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Answer:

kinetic energy is the answer

Explanation:

kinetic energy is movement

The bat's observation of the echo's frequency is 41.2 kHz

A bat flies speedily in this problem [tex]$$v_{\text {bat }}=5.0 \mathrm{~m} / \mathrm{s}$$[/tex] .

It makes a frequency chirp [tex]$$f_S=40 \mathrm{kHz}=4.0 \times$$10^{4} Hz.[/tex]

An adjacent wall reflects the sound. We determine the echo's frequency based on the bat's observations.

(b) Sound propagates at a speed of [tex]v=345 \mathrm{~m} / \mathrm{s}[/tex]

The sound will undergo two Doppler shifts. The first Doppler change occurs when the sound travels toward the wall, and the second Doppler shift occurs as the sound returns to the bat.

     [tex]\begin{aligned}f_{O, 1} &=f_S\left(\frac{v+v_O}{v-v_S}\right) \\&=f_S\left(\frac{v+0}{v-\left(+v_{\mathrm{bat}}\right)}\right) \\f_{O, 1} &=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]

The moving bat, which moves in the direction of the source, serves as the observer in the second Doppler shift. The wall that isn't moving is the source. The bat's frequency observations must be

[tex]\begin{aligned}f_{\text {echo }} &=f_{O, 1}\left(\frac{v+v_O}{v-v_S}\right) \\&=f_{O, 1}\left(\frac{v+\left(+v_{\text {bat }}\right)}{v-0}\right) \\&=f_{O, 1}\left(\frac{v+v_{\text {bat }}}{v}\right) \\&=f_S\left(\frac{v}{v-v_{\mathrm{bat}}}\right)\left(\frac{v+v_{\text {bat }}}{v}\right) \\\Rightarrow f_{\text {echo }} &=f_S\left(\frac{v+v_{\mathrm{bat}}}{v-v_{\mathrm{bat}}}\right)\end{aligned}[/tex]

By substituting values in the equation, we get

   [tex]\begin{aligned}f_{\text {echo }} &=f_S\left(\frac{v+v_{\text {bat }}}{v-v_{\text {bat }}}\right) \\&=\left(4.0 \times 10^4 \mathrm{~Hz}\right)\left(\frac{345+5.0}{345-5.0}\right) \\&=4.11765 \times 10^4 \mathrm{~Hz} \\f_{\text {echo }} &=41.2 \mathrm{kHz}\end{aligned}[/tex]

Hence, The bat's observation of the echo's frequency is 41.2 kHz.

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Answer:

compressions or refractions

Explanation:

Answer:

how heavy you are and how light you are

Explanation: