Chemistry College

A compound is found to contain 3.622 % carbon and 96.38 % bromine by weight.
The molecular weight for this compound is 331.61g/mole. What is the molecular formula for this compound?

Answers

Answer 1

If a compound is found to contain 3.622 % carbon and 96.38 % bromine by weight. The molecular formula for the compound is CBr4.

First, get the empirical formula in order to calculate the molecular formula of the chemical. The empirical formula shows the atoms of a compound in their most straightforward whole number ratio.

Suppose 100 grams of the substance. To determine the mass of carbon and bromine in the compound using the provided percentages.

Mass of C = 3.622% of 100g

= 3.622g

Mass of Br = 96.38% of 100g

= 96.38g

The next step is to determine the atomic masses of carbon and bromine in order to determine the number of moles for each.

Atomic mass of carbon = 12.01 g/mol

Atomic mass of bromine = 79.90 g/mol

Moles of C = (mass of carbon) / (atomic mass of carbon)

= 3.622g / 12.01 g/mol

= 0.3016 mol

Moles of Br = (mass of bromine) / (atomic mass of bromine)

= 96.38g / 79.90 g/mol

= 1.205 mol

Divide the moles of each element by the fewest number of moles obtained, in this case the moles of carbon, to arrive at the empirical formula.

Empirical formula ratio:

C: (0.3016 mol) / (0.3016 mol)

= 1

Br: (1.205 mol) / (0.3016 mol)

= 4

The empirical formula for the compound is C₁Br4.

To determine the molecular formula, it is required to know the molecular weight of the compound. The molecular weight is  331.61 g/mol.

To find the number of empirical formula units in the molecular formula, divide the molecular weight by the empirical formula weight.

Empirical formula weight:

C = 12.01 g/mol × 1

= 12.01 g/mol

Br= 79.90 g/mol × 4

= 319.60 g/mol

Empirical formula weight = 12.01 + 319.60

= 331.61 g/mol

Now find the number of empirical formula units in the molecular formula:

Number of empirical formula units

= (molecular weight) ÷ (empirical formula weight)

Number of empirical formula units

= 331.61 g/mol / 331.61 g/mol

= 1

The number of empirical formula units is 1, the empirical formula C₁Br4 is would be  the molecular formula for this compound.

Thus, the molecular formula for the compound is CBr₄.

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Related Questions

A gas has a pressure of 2.70 atm at 50.0 °C. What is the pressure at standard temperature (0°C)?

Answers

Answer:

2.282 atm

P1V1/T1 = P2V2/T2

2.70atm / (50+273) = X/ 273

make x subject of formula

:. X = 2.28 atm

or 2.28 * 1.01 *10⁵ N/m²

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