A crane used 250,000 Joules of work to move a beam to the top of a building in 20 seconds. How much power did the crane use?

a) 5,000,000 W
b) 5,000 W
c) 50 J
d) 12,500 W

Answer:

u have to divide the 2numbers and multiply by 2

Explanation:

At 13 seconds, the meteor's velocity is - 562.4 m / s, if it enters the earth's atmosphere at - 435 m / s

We know that,

v = u + at

where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

Given that,

u = - 435 m / s

a = - 9.8 m / s²

t = 13 s

v = - 435 - ( 9.8 * 13 )

v = - 562.4 m / s

Velocity is the rate of change of distance with respect to time. It is denoted by V.

Therefore, at 13 seconds, the meteor's velocity is - 562.4 m / s, if it enters the earth's atmosphere at - 435 m / s

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Answer:

Badminton game played with one player per side is true and Badminton game played with two players per side is also true.

Explanation:

To launch a 100 kg human so that he leaves a cannon moving at a speed of 4 m/s, you need a spring with an appropriate spring constant. This spring will be compressed 2. 0 m from its natural length to launch the person.400N/m spring constant is needed.

The spring constant, k, is a proportional constant. It gauges how firm the spring is. When a spring is compressed or extended to a length that differs by an amount x from its equilibrium length, it produces a force F = -kx that pushes it back towards its equilibrium position.

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The average speed of the plane is 3,967.7km/h or 1,102.15m/s.

Speed is a scalar number in kinematics that quantifies how quickly an item is moving. Since the plane's speed might fluctuate, we refer to the plane's average speed when describing its rate of motion. The whole distance travelled is divided by the total amount of time required to go that distance to arrive at this pace.

[tex]speed = \frac{distance}{time}[/tex]

For, [tex]time (t_{1} ) = \frac{615}{918}[/tex]

as 1m/s = 3.6km/h , therefore,

[tex]time (t_{1} ) = \frac{615}{918*3.6}[/tex]

[tex]time (t_{1} ) = 0.186 hours[/tex]

For, [tex]time(t_{2} ) = \frac{615}{1377}[/tex]

as 1m/s = 3.6km/h , therefore,

[tex]time (t_{2} ) = \frac{615}{1377*3.6}[/tex]

[tex]time (t_{2} ) = 0.124 hours[/tex]

Thus, the average speed of plane is,

[tex]s = \frac{615+615}{0.124+0.186}[/tex]

s = 3967.7km/h

or, [tex]\frac{3967.7}{3.6}[/tex] m/s = 1,102.15m/s

Therefore, the average speed of the plane is 3,967.7km/h or 1,102.15m/s.

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GP Submarine A travels horizontally at 11.0 m/s through ocean water. It emits a sonar signal of frequency f = 5.27× 10³Hzin the forward direction. Submarine B is in front of submarine A and traveling at 3.00 m/s relative to the water in the same direction as submarine A. A crewman in submarine B uses his equipment to detect the sound waves ("pings") from submarine A. We wish to determine what is heard by the crewman in submarine B. (b) In Equation 17.19, the sign of v(S) should be positive.

Recurrence is the quantity of events of a rehashing occasion for each unit of time. It is additionally once in a while alluded to as fleeting recurrence to underscore the difference to spatial recurrence, and customary recurrence to stress the differentiation to precise recurrence. Recurrence is communicated in units of hertz (Hz) which is comparable to one (occasion) each second. The comparing time frame is the time term of one cycle in a rehashing occasion, so the period is the corresponding of the recurrence. Recurrence is estimated in units called hertz (Hz). At the point when one wave passes in a single second its recurrence is 1 wave each second or 1 Hertz. Recurrence and period are really alternate extremes. While period is estimated in seconds per cycle, recurrence is estimated in cycles each second. Think about wave with a time of 2 seconds.

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The kinetic energy as measured in the Earth reference frame is 6.704*10^22 Joules.

To find the answer, we have to know about the Lorentz transformation.

It is given that, an alien spaceship traveling at 0.600 c toward the Earth, in the same direction the landing craft travels with a speed of 0.800 c relative to the mother ship. We have to find the kinetic energy as measured in the Earth reference frame, if the landing craft has a mass of 4.00 × 10⁵ kg.

                  [tex]V_x'=0.8c\\V=0.6c\\m=4*10^5kg[/tex]

                  [tex]KE=m_0c^2=\frac{mc^2}{1-(\frac{v_x^2}{c^2} )}[/tex]

                      [tex]V_x'=\frac{V_x-V}{1-\frac{VV_x}{c^2} } \\thus,\\V_x=V_x'(1-\frac{VV_x}{c^2} )+V[/tex]

          [tex]V_x=0.8c(1-\frac{0.8c*0.6c}{c^2} )+0.6c=(0.8c*0.52)+0.6c=1.016c[/tex]

              [tex]KE=\frac{4*10^5*(3*10^8)^2}{\sqrt{1-\frac{(1.016c)^2}{c^2} } } =\frac{1.2*10^{22}}{0.179}=6.704*10^{22}J[/tex]

Thus, we can conclude that, the kinetic energy as measured in the Earth reference frame is 6.704*10^22 Joules.

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The robot is moving with an acceleration of 1.0 m/s.

Magnitude is simply "distance or quantity" in the context of physics. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. In physics, the term "magnitude" often refers to a size or amount.

Scalar values serve as units of measurement, and scalar multiplication serves as the definition of magnitude. A quantity's magnitude in a particular unit multiplied by that unit equals the original quantity. This is true for all tensor types, including vectors and real-number tensors.

The given parameters;

mass of the toy doll, m = 0.2 kg

mass of the robot, M = 0.3 kg

force applied by the robot, F = 0.3 N

The magnitude of the acceleration of the robot is calculated from Newton's second law of motion;

F = ma

where;

a is the acceleration of the robot

Thus, the magnitude of the acceleration of the robot is 1 m/s²

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We describe the motion in the graph as

Motion is the change in position of an object with time.

Since on the graph

From the graph, in the first 2 seconds, the motion of the object is described as the object is at rest.

From the time , t = 2 seconds to t = 4 seconds, we see that the graph has a positive slope. During this time interval, from t = 2 seconds to t = 4 seconds, the object is accelerating.

So, the motion of the object is described as the object is accelerating

For the time interval t = 4 seconds to t = 6 seconds, we see that the velocity is a straight line parallel to the x(time) axis. This implies that the velocity of the object is constant for t = 4 seconds to t = 6 seconds. So, for t = 4 seconds to t = 6 seconds, the motion of the object is described as object is moving with constant velocity

So, we describe the motion in the graph as

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The calculated charge density on each plate is 8*10⁻⁸ C/m²

The charge density is a measurement of the amount of electric charge present per unit of surface area, body volume, or field. How much charge is held in a specific field is determined by the charge density. It is possible to calculate charge density in terms of length, area, or volume.

L = 50cm = 0.5m for side length. Q = 4*10⁻⁸C, charge on the plate

= Q/A for surface charge density

Each component's surface charge density is then equal to half of the plate's overall charge density. Thus,

σ(face) = 1/2σ

(face = Q/2A)

(face = Q/2L2) Now that we have Q and L, we can plug in.

σ(face) = 4*10⁻⁸/ 2*0.5²

σ(face) = 4*10⁻⁸ / 0.5

(face) = 8 * 10 ⁻⁸ C/m²

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The ball that is projected 125 meters straight upward has a total time in the air of: 10.1 s

The formulas for the vertical launch upward and the procedures we will use are:

Where:

Information about the problem:

Applying the maximum height formula and clearing the initial velocity we get:

y max = v₀²/(2*g)

v₀ = √(y max * (2*g))

v₀ = √( 125 m * (2 * 9.8 m/s²))

v₀ = √( 125 m * 19.6 m/s²)

v₀ = √2450 m²/s²

v₀ = 49.497 m/s

Applying the maximum time formula we get:

t max= v₀ / g

t max= 49.497 m/s / 9.8 m/s²

t max = 5.050 s

Applying  the time of flight formula, we get:

t(of) =2 * t max

t(of) =2 * 5.050 s

t(of) = 10.1 s

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

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The time taken now is 10 s

We know that in this case, the object was projected vertically upward and we know that in this direction the acceleration due to gravity is negative. Then the ball falls straight down to  the ground. We have to use the equation of kinematics under gravity to approach the problem.

We now have that;

h = ut + 1/2gt^2

Considering the downward motion were g is positive u = 0 m/s

h =  1/2gt^2

t = 2h/g

t = √2h/g

t = √ 2 * 125/10

t = 5 s

Given that the time taken to go up is the same as the time taken to come down;

Total time spent in air = 2 (5 s) = 10 s

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The correct answe is South Africa - Economic Growth and Development:

After the formal end of the previous apartheid system two decades ago, South Africa can now boast having one of the richest economies in Africa and a well-functioning democracy. It is the largest economy in Africa, but it also has deeply ingrained structural issues that limit its ability to expand and flourish.

One of the largest economies on the African continent is that of South Africa. However, despite a period of rapid development from 2003 to 2007, its real GDP average yearly growth rate between 2001 and 2010 has been very weak and unquestionably significantly below the African average. A number of African nations have had substantially faster growth rates, which has improved a number of development-related indices.

By the standards of the recent growth records of several Euro Zone nations, South Africa's development is hardly sluggish! One crucial aspect of the economy is that South Africa has achieved relatively modest progress in meeting a number of important development targets and some of the Millennium Development Goals, but her economy does not appear to have achieved the "take-off" required to kick start significant development progress, especially against the backdrop of her deep social problems.

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Three-dimensional shape the presence of suggests that an object has weight and gravity, while the absence of it suggests lightness or airiness.

A solid figure, object, or shape with three dimensions—length, breadth, and height—is known as a three-dimensional shape in geometry. Three-dimensional shapes have height, which is equivalent to thickness or depth, unlike two-dimensional shapes. These objects are sometimes referred to as 3-D forms because three dimensions can also be written as 3-D. Every 3-D shape takes up space, which is quantified by volume. For instance, The fundamental 3-dimensional shapes we encounter every day include a cube, rectangular prism, sphere, cone, and cylinder. We can see 3-D shapes all around us. A square prism can be seen in a book and a box, a cube in a Rubik's Cube and a die, etc.

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Gauss law states that the electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field.

Mathematically,

Φ=Q ϵo

Where;

Q is enclosed charge

ϵo is the permittivity of the free space

If the charge is moved to another location inside the same cube, the flux in the electric field remains the same. This is because as long as the charge remains within the plane of the electric field, the flux is calculated in all directions and thus the flux remains unchanged. It only changes when the charge is moved outside the cube.

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|E| = 16.67 N/C and the direction of this Electric field is in the downward direction.

We have a Charge particle present inside a Electric field.

We have to determine the magnitude (in n/c) and direction of an electric field that exerts a 2 x [tex]10^{-5}[/tex] Newton.

The electric field intensity at a point R meters away from a charge Q is the amount of force experienced by the test charge ([tex]$q_{o}[/tex]) of unit magnitude at a distance R meters away the Charge Q. Mathematically -

E = [tex]$\frac{F}{q}[/tex]

According to the question, we have -

F = 2 x [tex]10^{-5}[/tex] Newton

|Q| = - 1.2 [tex]\mu[/tex]C = - 1.2 x [tex]10^{-6}[/tex]  [tex]\mu[/tex]C = 1.2 x [tex]10^{-6}[/tex] [tex]\mu[/tex]C

Therefore -

E = [tex]$\frac{2\times 10^{-5} }{1.2\times 10^{-6} }= \frac{100}{6} = 16.67\;N/C[/tex]

Therefore -

|E| = 16.67 N/C and the direction of this Electric field is in the downward direction.

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By using Bragg's diffraction, the spacing d is 0.112 nm.

We need to know about Bragg's diffraction to solve this problem. Bragg's diffraction is described how monochromatic light travels through a crystal medium. The monochromatic light should follow

2d.sin(θ) = λ

where d is the spacing between the planes of the crystal, θ is the incident light angle and λ is the wavelength.

From the question above, we know that

θ = 70⁰

λ = 0.210 nm = 0.21 x 10¯⁹ m

By substituting the given parameters, we get

2d.sin(θ) = λ

2d.sin(70⁰) = 0.21 x 10¯⁹

2d . 0.94 = 0.21 x 10¯⁹

d = 1.12 x 10¯¹⁰ m

d = 0.112 nm

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Spectroscopy is the study of the absorption and emission of light and other radiation by matter.

Spectroscopy is the interaction of lights and atoms and the study of the emission and absorption of light.

Spectroscopy can be defined as the study of light absorption as well as its emission. It is also uses to study of structure of atoms.

It offers techniques that has to do with how a sample responds to the radiation of light.

Its applications are:

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The magnetic field 40.0 cm away from the middle of the straight cord, in the plane of the two wires is [tex]7.5\times 10^{-9}T[/tex]

Let [tex]B_1[/tex] be inside the plane and [tex]B_2[/tex] be outside the plane . It is required to calculate magnetic field at point A .

Direction of magnetic field at A is calculated using Right hand rule.

[tex]B_{net}=B_2-B_1\\\\B_{net}=\frac{u_0I}{2\pi (0.4-\frac{3\times10^{-3}}{2}) } -\frac{u_0I}{(0.4+\frac{3\times10^{-3}}{2})} \\\B_{net}=7.5\times 10^{-9}T[/tex]

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The gravitational field strength is 51.6925 N/kg.

We need to know about the gravitational field to solve this problem. The gravitational field is the area where affected by gravitational force. The magnitude of the gravitational field can be calculated by this equation

g = G . m / r²

where g is the gravitational field, G is gravitational constant (6.67 x 10¯¹¹ Nm²/kg²), m is the mass of the planet and r is the radius of the planet

From the question above, we know that

m = 3.10 x 10²⁴ kg

r = 2.00 x 10⁶ m

By substituting the given parameter, we get

g = G . m / r²

g = 6.67 x 10¯¹¹ . 3.10 x 10²⁴/ (2.00 x 10⁶)²

g = 51.6925 N/kg

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The force required to pull the block will be 13.89 kN.

Let μ be the viscosity of oil, y be thickness, v be the velocity of the block, and A be the base area of the block. Then the force is given as,

F = μAv / y

An inclined surface with a coating of sae 10w oil at 100°C is dragged up by a block that weighs 10 lbf and measures 10 in on each edge. if the oil coating is 0.001 in. thick and the block is moving at a speed of 2 ft/s. Assume that the oil film's velocity distribution is linear. A 25° angle from the horizontal separates the surface from the horizontal.

The diagram is given below. Then the force is given as,

F - 10 sin 25° = 10 × (10 / 12)² × 2 / 0.001

F = 4.226 + 13888.89

F = 13893.1 N

F = 13.89 kN

13.89 kN of force will be required for pulling the block.

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The magnitude of the velocity gradient of water is 892.86 s^-1 or 892.86/s

Given:

The shear stress in the fluid is 1 N/m^2

Solution:

The formula for velocity gradient is given below

(dµ / dy)  =  τ / µ

Here τ  is sheer stress, µ is the dynamic viscosity and dµ / dy represents the velocity.

In the above equation, put the values  N/m^2 for τ and 1.12 x 10^-3 Ns/m^2  for μ.

(dµ / dy)  =  1 / 1.12 x 10^-3 Ns/m^2

(dµ / dy)  = 892.86 s^-1

Thus, the magnitude of the velocity gradient of water is 892.86 s^-1 or 892.86/s

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The sound power incident on the eardrum at the threshold of pain is,

[tex]5 \times 10^{-5} W[/tex]

In physics, the power transferred per unit area is known as the intensity or flux of radiant energy, where the area is measured on a plane perpendicular to the direction of the energy's propagation. Watts per square meter (W/m2) and kilograms per square meter (kg/s3) are the units used in the SI system. With waves like acoustic waves (sound) or electromagnetic waves like light or radio waves, intensity is most usually employed to describe the average power transfer across one period of the wave. Other situations where energy is exchanged can also be described in terms of intensity. One could, for instance, figure out how much kinetic energy each drop of water from a sprinkler is carrying.

Power =  intensity x area

Given:

Area, A = [tex]5 \times 10^{-5} \;m^{2}[/tex]

Intensity, I = [tex]1\;W/m^{2}[/tex]

We know that,

Sound Power, P = [tex]I \times A[/tex]

P = [tex]1 \times 5 \times 10^{-5}[/tex]

P = [tex]5 \times 10^{-5}\;W[/tex]

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In the electron-transport chain, as electrons move along a series of carriers, they release energy that is used to pump protons across a membrane.

In plants and animals, the electron transport chain points to the consistent streaming of electrons across cells where electron donors donate electrons and electron acceptors accept electrons through an oxidation-reduction reaction.

As a result of the oxidation-reduction reaction, an electrochemical gradient is created and ATPs are generated for energy purposes.

Moreover, the chain comprises 4 key protein complex molecules that are transferred across the plasma membrane cell.

This cellular process takes place in mitochondria and is responsible for chemical reactions such as photosynthesis and cellular respiration. The four principle steps of this process are Krebs' cycle, glycolysis, oxidative phosphorylation, and pyruvate oxidation.

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Answer:تاتا البال،ًـلاللبببلا

لولاليثقغاايصسضشطذدزلب

Explanation:ابرلرتهىغرلب

 The electric field at the center of uniformly charge ring is zero if the charge were placed at a point on the axis of the ring other than the center.

if the charge were placed at a point on the axis of the ring other than the center the electric field then there is no motion.

electric field - It is a force produced by any charge near its surrounding.

If the charge were placed at a point on the axis of the ring other than the center then there is no motion because at the center of the ring E.F ( Electric field is zero.

electric filter the point on the axis of uniformly charged ring depend on the distance of the point from the center of the ring.

.

E.F =  0 because each half cancels each other . the negative charge will be in equilibrium as every part of the ring is uniformly attracted by it.

The electric field at the center of uniformly charge ring is zero if the charge were placed at a point on the axis of the ring other than the center.

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The instantaneous velocity of the ball is 18ft/s.

The pace at which an object's position changes as perceived from a particular point of view and as measured by a particular unit of time (for example, 60 km/h northbound) is defined as its velocity. Velocity is a fundamental concept in kinematics, the branch of classical mechanics that deals with the motion of bodies.

In order to be defined, the physical vector quantity known as velocity needs to have both a magnitude and a direction. Speed is a coherent derived unit whose quantity is measured in metres per second (m/s or m/s1) in the SI. Speed is the scalar absolute value (magnitude) of velocity (metric system).

Calculations:

at t=1s, the height is y=50(1)-16(12)=34ft.

at t=1.1s, the height is y=50(1.1)-16(1.12)=35.64ft

Between these two heights, the change in time is 0.1s. The change in height is 35.64ft-34ft=1.64ft.

Therefore [tex]V_{avg}=\frac{del y}{del t} = \frac{1.64ft}{0.1s} =16.4ft/s[/tex]

at t=1.01s, the height is y=50(1.01)-16(1.012)=34.1784ft

between t=1.01s and t=1s the change in time is 0.01s and the change in height is 0.1784ft.[tex]V_{avg}=\frac{0.1784ft}{0.01s} =17.84ft/s[/tex]

at t=1.001, the height is y=50(1.001)-16(1.0012)=34.017984ft

between t=1s and t=1.001s, the change in time is 0.001s and the change in height is 0.017984ft

[tex]V_{avg} =\frac{0.017984ft}{0.001s}=17.984ft/s[/tex]

It appears that as the time interval approaches 0, the average velocity approaches 18ft/s. Therefore it is safe to assume the instantaneous velocity at t=1s is 18ft/s.

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Answer:

In the given graph,

Velocity is constant between 4 to 8 which is 2m/s

So, at t=5s

Instantaneous velocity=2m/s

Explanation:

hope this help u thank u

The value of electric flux will be ​zero.

For a uniform electric field passing through a plane surface,

​electric flux(ϕ) = EAcosθ

where,

θ is the angle between the electric field and the normal to the surface

E is the electric field

A is surface area

(a)

The electric field is perpendicular to the surface,

so,

θ=0

​electric flux(ϕ) = EAcosθ

​electric flux(ϕ)   =(6.20×10⁵N/C)(3.20m²)cos0

​electric flux(ϕ) =1.98×10⁶Vm

(b)

The electric field is parallel to the surface

θ=90°

so,

cosθ=0 and the flux is zero For a uniform electric field passing through a plane surface,

therefore, ​electric flux(ϕ) =0

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