A crow flies forward and backward. Its motion is shown on the following graph of horizontal position x vs. time t.
What is the instantaneous velocity of the crow at t = 9 s?
Answer: -0.50 m/s
A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.
From the figure, it shows that from t = 8sec to t = 12 sec the displacement is decreasing, so velocity will be the slope of the straight line.
The velocity is given by:
velocity = -Δx ÷ Δt
velocity = (-2) ÷ (12-8)
velocity = -2 ÷ 4
velocity = -0.5 m/s
Therefore, A crow flies forward and backward. Its motion is shown in the following graph and the instantaneous velocity of the crow at t = 9 s is -0.5 m/s.
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What is the frequency of a wave that has a period of 0.5 seconds?
A. 0.5 Hz
B. 2 Hz
C. 200 Hz
D. 20 Hz
Answer:
B. 2 Hz
Explanation:
Given parameters:
Period of the wave = 0.5Hz
Unknown:
Frequency of the wave = ?
Solution:
Frequency is the number of waves that passes through a point.
Period is the time taken for a number of waves to pass through a point.
Period is the inverse of frequency
Frequency = [tex]\frac{1}{t}[/tex]
t is the period
Frequency = [tex]\frac{1}{0.5}[/tex] = 2Hz
Answer:2
Explanation:
Which of the following is a disadvantage of hybridization? 1.offspring are genetic copies of the parent 2.offspring are stronger and larger than the parents 3.offspring have a combination of traits from both parents 4.offspring often have health problems and are sterile
Answer:
Explanation:
4 is right
A 1.0 kg object is attached to a 0.50 m string. It is twirled in a horizontal circle above the ground at a speed of 5.0 m/s.
The direction of the acceleration at the point shown points towards which letter?
Given that,
Mass of the object, m = 1 kg
It moves in a circle of radius 0.5 m with a speed of 5 m/s
To find,
The direction of the acceleration.
Solution,
Whenever an object moves in a circular path, the only force that acts on its is centripetal force which is given by the formula as follows :
[tex]F=\dfrac{mv^2}{r}[/tex]
The centripetal acceleration acts in the direction of force. It acts along the radius of the circular path. In this figure, the direction of the acceleration is shown at point d.
Answer:
D!
Explanation:
took the test
A football is kicked at an angle of 35° with a speed of 26 m/s.
To the nearest second, how long will the ball stay in the air?
The amount of time the ball stay in the air is (t)=3.04 Seconds
What is time?The best example that would help us understand and know what time are the clock and the calendar. This clock gives us the exact hour, minutes and seconds. The calendar tells us the exact day, month and year.
How can we calculate the time?To calculate the amount of time the ball stay in the air, we are using the formula,
T=2Vsinθ/g
Here we are given,
V= The velocity of the football.=26 m/s.
θ= The angle that the football makes in the air= 35°
g= The acceleration due to gravity = 9.8 m/s².
We have to calculate, the amount of time the ball stay in the air = T
Now, we put the known values in the above equation,
T=2Vsinθ/g
Or, T= 2*26*sin (35°)/9.80
Or, T= 3.04 Seconds.
Thus, from the above calculation we can conclude that the amount of time the ball stay in the air is (t)=3.04 Seconds
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When practicing deep breathing, it is best to repeat the steps for
minutes to start and then increase the time as needed.
Answer:
c.) 10 to 15 minutes
Explanation:
yw :)
Answer:
c.) 10 to 15 minutes
Explanation:
What's the quantum number for a particle in an infinite square well if the particle's energy is 64 times the ground-state energy?
Answer:
8
Explanation:
The energy levels is given as
E(n) = n² * h² / ( 8 * m * L²), where
n = 1, 2, 3, 4,... etc
At ground state energy (n = 1), therefore is E(g) = h² / (8 * m * L²).
We can then say that
E(n) = n² * Eg
Therefore, to have E = 64 Eg, we must have n² = 64. And for n² to be equal to 64, we find the square root of n
n = √64
n = 8
Essentially, the needed quantum number is 8
a total of 15000 ft. lb of work is used to lift a load of bricks to a height of 50 ft. the weight of the bricks is
Answer:
The weight of the brick is 300 lb.
Explanation:
Given that,
The work done in lifting a load of bricks = 15000 ft lb
It is lifted to a height of 50 ft
We need to find the weight of the brick. The work done by an object is given by :
[tex]W=F\times d[/tex]
Here, F = W (weight of the bricks)
[tex]F=\dfrac{W}{d}\\\\F=\dfrac{15000\ ft-lb}{50\ ft}\\\\F=300\ lb[/tex]
So, the weight of the brick is 300 lb.
The weight of the brick will be "300 lb".
Given:
Work done,
15000 ft.lbHeight,
50 ftAs we know the formula,
→ [tex]W = F\times d[/tex]
or,
→ [tex]F = \frac{W}{d}[/tex]
By substituting the values, we get
→ [tex]= \frac{15000}{50}[/tex]
→ [tex]= 300 \ lb[/tex]
Thus the response above is right.
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What is the total charge of barium oxide?
What did kind of energy did the ruler gain when you bent it with your left hand? why?
Answer:
potential energy
Explanation:
The bent ruler possesses elastic potential energy.
• The bending of the ruler depends upon the material of which it is made up of.
• The ruler after bending will gain elastic potential energy.
• The energy stored as an outcome of applying a force to deform an elastic object is known as the elastic potential energy.
• This energy is stored unless and until the removal of force takes place and the ruler moves back to its original shape.
• When the energy is released or when the bent ruler is released from the left hand, then the potential energy stored in it gets convert to kinetic energy and the ruler will recoil or vibrate briskly.
Thus, it is the elastic potential energy gained by the ruler when one bent it with the left hand.
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A crate of oranges on a horizontal floor has a mass of 30 kg. The coefficient of static friction is 0.62. The coefficient of kinetic friction is 0.52. The worker pulls the crate with a force of 200 N.
What is the equation to calculate the kinetic friction?
What is the kinetic friction on the crate?
Answer:
[tex]Fr_k=152.88\ N[/tex]
Explanation:
Net Force
The net force is defined as the vector sum of all the forces acting on a body at a certain moment.
We should recall some basic concepts and equations to solve the problem.
If no external forces are applied in the vertical direction, the weight of the object and the normal force have the same magnitude and point to opposite directions.
The friction force is defined as:
[tex]Fr_k=\mu_k N[/tex]
[tex]Fr_s=\mu_s N[/tex]
Where the subindices k and s are referred as to the kinetic and static friction forces respectively.
The condition for the object to move is that the applied force is greater than the friction force.
The crate of oranges has a mass of 30 Kg, thus its weight is:
W = m.g = 30 * 9.8 = 294 N
The normal force is:
N = W = 294 N
The kinetic friction is calculated as:
[tex]Fr_k=0.52* 294[/tex]
[tex]\mathbf{Fr_k=152.88\ N}[/tex]
A ball is dropped from a tall bridge of height 48 m. What will the speed of the ball be immediately before it hits the ground, in units of m/s?
Answer:
2700
Explanation:
because calculate the minute1=60×45=2700
Answer:
[tex]v \approx 30.67\,\,\frac{m}{s}[/tex]
Explanation:
We use the kinematic formula for constantly accelerated motion given below:
[tex]v^2=v_0^2+2\,a\Delta x\\v^2=0+2\,g\,(48)\\v^2=940.8\\v \approx 30.67\,\,\frac{m}{s}[/tex]
The angle between an incident
ray and the mirror is 40°.
1) What is the angle of reflection?
Answer:
1) 50°
Explanation:
We need to find the angle of incidence first before finding the angle of reflection.
Angle of incidence = 90° - 40°
= 50°
Since the angle of incidence is the same as the angle of reflection, the angle of reflection here would be 50°.
How much work is required to slide a 3.00 kg box 6.90 m along (up) a frictionless incline plane that is inclined at an angle of 25 degrees?
The amount of work required to slide the 3 Kg box 6.90 m along (up) the frictionless incline plane is 183.85 J
What is work done?Work is defined as the product of force and distance moved in the direction of the force. mathematically it is expressed as:
Work done (Wd) = force (F) × distance (d)
Wd = fd
Where height is involved, the workdone is given as as:
Work done (Wd) = mass (m) × acceleration due to graity (g) × height (h)
Wd = mgh
Considering angle projection,
Wd = mghCosθ
Thus, we can detertmine the work done as follow:
Mass (m) = 3 KgHeight (h) = 6.9 mAcceleration due to gravity (g) = 9.8 m/s²Angle (θ) = 25°Workdone (Wd) =?Wd = mghCosθ
Wd = 3 × 9.8 × 6.9 × Cos 25
Wd = 183.85 J
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what is the object's position at 6s?
Answer:
6sec and 8 postion
Explanation:
A cylinder is fitted with a piston, beneath which is a spring, as in the drawing. The cylinder is open to the air at the top. Friction is absent. The spring constant of the spring is 3400 N/m. The piston has a negligible mass and a radius of 0.028 m. (a) When the air beneath the piston is completely pumped out, how much does the atmospheric pressure cause the spring to compress
Answer:
x = 0.0734 m = 7.34 cm
Explanation:
First we shall calculate the area of the piston:
[tex]Area = \pi radius^2\\Area = \pi (0.028\ m)^2\\Area = 0.00246\ m^2[/tex]
Now, we will calculate the force on the piston due to atmospheric pressure:
[tex]Atmospheric\ Pressure = \frac{Force}{Area}\\\\Force = (Atmospheric\ Pressure)(Area)\\Force = (101325\ N/m^2)(0.00246\ m^2) \\Force = F = 249.56\ N[/tex]
Now, for the compression of the spring we will use Hooke's Law as follows:
[tex]F = kx\\[/tex]
where,
k = spring constant = 3400 N/m
x = compression = ?
Therefore,
x = 0.0734 m = 7.34 cm
A rock from a volcanic eruption is launched straight up into the air with no appreciable resistance Which one of the following statements about this rock while it is in the air is correct
AN AUTOMBILE IS TRAVELING AT 20 M/S. IT BEGINS TO ACCELERATE AT 3.8 M/S2 FOR 1.5S. HOW FAR DOES IT TRAVEL IN THOSE 1.5 SECONDS?
The distance that automobile travel in 1.5 seconds is (S)= 34.275 m.
What is distance?Distance is a scaler quantity that refers to "how much ground an object has covered" during its motion of time.
How can we calculate the amount of distance that automobile travel?To calculate the distance that automobile travel in 1.5 seconds, we are using the formula,
S= ut+(1/2)at²
Here we are given,
u= The initial velocity of the automobile = 20 m/s
t = The amount of time that the automobile travel = 1.5 Seconds.
a=The amount of acceleration of the automobile = 3.8 m/s².
We have to calculate the distance that automobile travel in 1.5 seconds = S
Now, we put the values in the above equation, we get
S= ut+(1/2)at²
Or, S= 20*1.5+(1/2)*3.8*(1.5)²
Or, S= 30+4.275
Or, S= 34.275m
Thus we can conclude that, the distance that automobile travel in 1.5 seconds is (S)= 34.275 m.
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Which of the following would be examples of derived demand?
1. A school hiring more teachers because the school's enrollment increased.
II. More people working at the movie theatre on Friday night because attendance increased.
III. More construction workers are needed because more people can afford to buy a new house.
O I and II only
o I and III only
Il and Ill only
O I, II and III
Answer:
The last one
Explanation:
on the exam
Among the following the derived demands are options 1 and 3 only. Because in each case, the demand for one thing is originated by the demand for another.
What is derived demand?The phrase derived demand in economics refers to the demand for a factor of production or intermediate good that results from the demand for another intermediate or final good. In essence, consumer demand for the firm's product determines how much a firm will need.
Additionally, if activity in one area rises, any sector that contributed to the success of the first sector may also experience growth. Here, the school is hiring more teachers because enrollment is increased. Thus, enrolling more teachers satisfies the demand by greater enrollments.
Similarly by recruiting more construction workers the increased demand for new house by people can be solved. However, the second case for filling the attendance is a necessary and not a derived demand.
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Which of these would have a high velocity? * O zamboni lamborgini O shopping cart O golf cart Search A
Golf carts have a high velocity.
Without any improvements, the conventional golf cart's peak velocity is between 12 and 14 miles per hour. The highest velocity that you can get on a golf cart without any upgrades or modifications is around 14 mph.
We can determine how quickly or slowly an item is traveling using the phrases velocity and speed. It occurs to us frequently that we must determine which of two or more moving things is traveling quicker. If both vehicles are traveling in the same direction along the same route, it is simple to determine which is quicker. It is challenging to identify who is moving quickest when their direction of motion is opposing. The idea of velocity is useful in these situations.
When gravity first exerts force on an item, its initial velocity defines how quickly the thing moves. The final velocity, on the other hand, is a vector number that gauges a moving body's speed and direction after it has attained its maximum acceleration.
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what do the sound waves made by the bell carry to your ear
Answer:
When these waves reach our ears, they make our eardrums vibrate, and we hear the sound of the bell ringing.
Explanation:
Answer: When a bell is pounded, the metal vibrates. The vibrations travel through the air as sound waves. When these waves reach our ears, they make our eardrums vibrate.
Explanation:
We hear the sound of the bell ringing. Sound always needs to travel through some kind of medium, such as air, water, or metal.
Sorry if this is not the answer you are looking for
A girl of mass 50kg jumps out of a rowing boat of mass
300 kg on to the bank, with a horizontal velocity of 3 m/s.
With what velocity does the boat begin to move backwards?
Given that,
Mass of a girl, m = 50 kg
Mass of the boat, m' = 300 kg
Speed of girl, v = 3 m/s
To find,
The velocity with which the boat begin to move backwards.
Solution,
Let the velocity be v'. Using the conservation of momentum to find it. It is given by :
[tex]mv=m'v'\\\\v'=\dfrac{mv}{m'}\\\\v'=\dfrac{50\times 3}{300}\\\\v'=0.5\ m/s[/tex]
So, the velocity moves backward with a speed of 0.5 m/s.
Need Help Please and Thank You). Question 1: Explain how longitudinal waves and transverse waves are similar to each other and different from each other. Question 2) Compare and contrast reflection and refraction. Question 3) What does it mean that energy is neither created nor destroyed? ( Please No Plagiarism and Be 100% positive with your answer. Will Mark Brainliest. If you write anything down that doesn't contain to my question you will be reported. Need two answers.
Answer:The direction a wave propagates is perpendicular to the direction it oscillates for transverse waves. A wave does not move mass in the direction of propagation; it transfers energy.
Explanation:
Suppose that you’re in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?
The car will continue at half speed and slow down due to friction after the brakes are released.
The given situation is that the car's motor is stopped and brakes are applied until the car reaches its half speed and the brakes are released. So after the brakes are released, the car will not gain any speed, since there is no force applied. Then it will gradually slow down due to friction.
According to the law of inertia ( i.e., Newton's first law of motion ), an object will tend to stay at rest or motion until an external force is applied. So based on this law, the car will continue at the speed the brakes were released and eventually slow down.
Therefore, the car will continue at half speed and slow down due to friction after the brakes are released.
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A piece of metal has a mass of 200g in air and 170g when immersed in water.calculate its volume and density.(Density of water is 1000kgm take g=9.8ms)
density of object is 6.7g/cm³ and volume is 30cm³.
First, air has a low density, so the mass in air is very close to the true mass (mass in a vacuum). Let's say the true mass is 200g.
Then we can use the following formula to find the volume:
AM=TM-V•D where AM is the apparent mass (in water) and TM is the true mass (mass in vacuum which approximates mass in air). , V is the volume of water displaced by the object (which is also the volume of the object) and D is the density of the water, i.e.
170g=200g-V*(1,000g/cm3)
V=30cm³
Therefore The density of is approximately 200g÷30cm³=6.7g/cm³
If you want an exact answer, you can find the density of air under laboratory conditions. For example,
1.20g/L or 0.00120g/cm³. Then, using the above equations, we can set up a system of two equations with two unknowns.
200g=TM-V*(0.00120 g/cm³)
170g=TM-V*(1.000 g/cm³)
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The speed of sound in air is approximately 340 m/s. The speed of light in air is approximately 3 x 108 m/s. If 10 seconds elapses between seeing a lightning strike and hearing the thunder, how far away was the lightning strike?
Answer:
3400 m
Explanation:
Both lightning and thunder happen at the same time but one is faster than the other. The distance traveled by a sound can be calculated from its speed such that;
speed = distance/time, hence, distance = speed x time.
For a thunder with 340 m/s speed and 10 seconds away from lightning, the distance between the thunder and the lightning can be calculated as;
distance = 340 m/s x 10 s = 3400 m
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor = how
many "drinks"?
6 drinks
7 drinks
12 drinks
PLS HURRY
Answer:
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
Explanation:
In the United States, a standard "drink" of beer has 12 ounces, a standard "drink" of wine has 5 ounces and standard drink of liquor has 1.5 ounces. Then, we obtain the quantity of drinks by dividing the total volume of each drink by its respective unit volume and summing each term. That is:
[tex]N = \frac{12\,oz}{12\,\frac{oz}{dr} }+\frac{12\,oz}{5\,\frac{oz}{dr} }+\frac{3\,oz}{1.5\,\frac{oz}{dr} }[/tex]
[tex]N = 1\,dr+2.4\,dr+2\,dr[/tex]
[tex]N = 5.4\,dr[/tex]
[tex]N = 6\,dr[/tex]
12 ounces of beer plus 12 ounces of wine plus 3 ounces of liquor are equivalent to 6 drinks.
2
Look at the circult dlagram.
Direction
of current
Battery
Bulb-
What type of circuit is shown?
A. open series circult
B. closed series circuit
C. open parallel circult
D. closed parallel circult
The direction of the current from the positive to the negative battery terminals and the fact that the bulbs are connected in parallel to each other suggests that this circuit is a Closed Parallel Circuit. The correct option is D.
What is the difference between open and closed circuits?An open circuit and a closed circuit are two types of electrical circuits that describe the flow of electrical current through a circuit.
An open circuit is a circuit in which there is a break in the path of the current, meaning that the current cannot flow through the circuit. In an open circuit, the switch is in the "off" position or there is a broken wire, and so no electrical current can flow through the circuit. This means that there is no voltage or electrical energy being transferred from the source to the load.
On the other hand, a closed circuit is a circuit in which there is a complete path for the current to flow through, meaning that the current can flow through the circuit. In a closed circuit, the switch is in the "on" position, and there is a continuous path for the current to flow from the source to the load and back to the source. This means that there is voltage and electrical energy being transferred from the source to the load.
Here in this question,
The direction of the current from the positive to the negative battery and the fact that the bulbs are connected in parallel to each other suggests that this circuit is a Closed Parallel Circuit.
In a closed parallel circuit, the components are connected in parallel to each other, meaning that they are connected to the same two points in the circuit and the current has multiple paths to flow through. The voltage across each component is the same, and the total current flowing through the circuit is divided among the components according to their resistance.
In contrast, an open series circuit is a circuit in which the components are connected in series, meaning that they are connected end to end in a single path, with no other branch points for the current to follow. If one component fails, the circuit becomes open and the current stops flowing.
Therefore, based on the information provided, the circuit described in the question is a Closed Parallel Circuit.
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Explain how the situation shown above would be different if the skier experiences friction while traveling downhill. Include the terms kinetic energy, heat energy, mechanical energy, total energy and friction. Must answer in complete sentences.
Answer:
The force of friction acts in the direction opposite to the direction of motion. If friction would have been applied to the skier it would have resulted in a lower velocity and less kinetic energy.
Explanation:
Conveyor belts are often used to move packages around warehouses. The conveyor shown below moves packages at a steady 4.0 m/s. A 500 N employee decides to catch a ride by sitting on a 1,000 N box for a 50 m trip as shown below:
What is the work done by the employee on the box?
Answer:
0 j
Explanation:
The work done by the employee on the box at the given zero displacement is 0 J.
The given parameters;
Constant velocity of the conveyor, v = 4 m/sWeight of the employee, W = 500 NWeight of the box, W = 1,000 NDistance of the trip, h = 50 mThe work done by the employee on the box is calculated as follows;
W = Fd
where;
F is the applied force on the box by employee = weight of the employeed is the distance through which the box is movedSince the employee sits on the box without moving it, the distance moved by the box = 0
W = 500 x 0
W = 0 J
Thus, the work done by the employee on the box is 0 J.
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If you are driving 80 km/h along a straight road and you look to the side for 1.7 s , how far do you travel during this inattentive period?
Express your answer using two significant figures.
Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.
How far did the driver travel during the inattentive period?Speed is simply referred to as distance traveled per unit time.
Mathematically, Speed = Distance ÷ time.
Given the data in the question;
Speed = 80 km/hTime = 1.7sDistance travelled = ?First, convert 1.7 seconds to hours.
Time = 1.7s = (1.7 / (60×60)hr = 1.7/3600 hrs
Now, find the distance traveled during the inattentive period.
80 km/h = Distance ÷ 1.7/3600 hrs
Distance = 80 km/h × 1.7/3600 hrs
Distance = 136/3600 km
Distance = 0.037 km.
Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.
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