The acceleration lasts 0.0077 seconds and is equivalent to 8450 m/s².
The rate at which an object's position changes with respect to time is defined as velocity.
Because it consist of both magnitude and direction, it is a vector quantity. Speed is a scalar quantity that represents the magnitude of velocity. The SI unit of velocity and speed is m/s.
Acceleration is the measure of how quickly a velocity varies over time. It is also a vector quantity. A negative sign of acceleration indicates that the velocity of the body is decreasing with time.
Given in the question
Initial speed = u = 0 m/s ( as the firework starts from rest)
Final velocity = v = 65 m/s
Distance traveled = 0.25 m
B) Acceleration
Using the third equation of motion,
[tex]v^{2} -u^{2} =2as[/tex]
Put in the value, we get
(65)² - (0)² = 2a(0.250)
0.5a = 4225
a = 8450 m/s²
As a result, fireworks accelerate at 8450 m/s².
A) Time the acceleration lasts
Acceleration is calculated as (Final Velocity - Initial Velocity)/Time.
Put in the values, we get
8450 = 65/time
Time = 65/8450
Time = 0.0077 seconds
Hence, the acceleration lasts for 0.0077 seconds and is 8450 m/s².
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A flat surface of area 3.20m² is rotated in a uniform electric field of magnitude E=6.20 × 10⁵N . m²/C . Determine the electric flux through this area (a) when the electric field is perpendicular to the surface
The electric flux is 0 N.m²/C.
We need to know about electric flux to solve this problem. Electric flux is the measure of the electric field through a given surface, although an electric field in itself cannot flow. It can be determined as
Φ = E . S = E . Scosθ
where Φ is electric flux, E is electric field, θ is angle of surface and S is surface area.
From the question above, we know that
E = 6.20 × 10⁵ N/C
θ = 90⁰
S = 3.20 m²
By substituting the following parameter, we get
Φ = E . Scosθ
Φ = 6.20 × 10⁵ . 3.20cos(90⁰)
Φ = 0 N.m²/C
Hence, the electric flux is 0 N.m²/C
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A generator produces 24.0V when turning at 900 rev/min. What emf does it produce when turning at 500 rev/min?
The EMF that will be produced is 13.3 V
What does EMF mean ?EMF is an acronym for Electromotive Force which can be defined as the potential difference between the terminals of a cell when it is not delivering any current in an external circuit.
Given that a generator produces 24.0V when turning at 900 rev/min. What EMF does it produce when turning at 500 rev/min?
The EMF produced by a generator is proportional to the angular speed at which the generator turns. That is, E [tex]\alpha[/tex] w
E1 = 24 VE2 = ?W1 = 900 rev/minW2 = 500 rev/minE1/E2 = W1/W2
24/E2 = 900/500
Reciprocate both side.
E2/24 = 500/900
E2 = 0.5556 x 24
E2 = 13.33 V
Therefore, the EMF that will be produced is 13.3 V
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A toy snake was horizontally thrown from a height of 115 m. It lands 595 m away. What is the toy snake’s initial speed? (TWO decimal places!!)
Initial speed for the toys snake will be 122.88 m/s
Given,
Height from where it has been dropped, h = 115 m
Height where the toy lands, s = 595 m
As we know that [tex]t = \sqrt{\frac{2h}{g} }[/tex]
here 'g' is acceleration due tp gravity = 9.81 m/s²
therefore [tex]t = \sqrt{\frac{2 * 115}{9.81\\ }[/tex]
[tex]t = \sqrt{23.445}[/tex]
t = 4.842 s
Now, According to the Second Equation of the Motion which relates distance with the acceleration and time, we can say that
[tex]S = ut + \frac{1}{2}at^{2}[/tex]
The toy snake is thrown horizontally, therefore acceleration acting on the toy will be zero (0).
s = 595 m
t = 4.842 s
therefore [tex]u = \frac{s}{t}[/tex]
[tex]u = \frac{595}{4.842}[/tex]
u = 122.88 m/s
The initial speed of the toy snake will be 122.88 m/s.
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Why increasing the resistance in a series circuit decreases the current in the circuit?
Answer:
Explanation:
In a series curcuit Current is divided across the resistors meaning the more you add resistors the more current is taken. The formula I= V/R also makes it easier to understand. The resistance is in the denominator. The more you increase it the more the current decreases.
Keep in mind Adding more resistors in a series curcuit reduc current.
__ which is a acidic mass of pratially decomped organic matter
Answer: partially decomposed
Explanation:
Assume that the variable name has the value 33. What is the value of name after the assignment name = name * 2 executes?
When the variable name has been assigned with the value 33, then the value of the name after the assignment name will be 66.
In the programming language the sign ' = ', is referred to as the assignment operator which is used to assign values to a particular variable, where the variable referred to the name of the memory location. As it is given the assignment name = name * 2, it means that name on the right-hand side is the assignment name, so whatever value it gets is replaced by twice that previous value according to the operation.
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The magnetic field 40.0 cm away from a long, straight wire carrying current 2.00 A is 1.00μT.(c) A t what distance is it one-tenth as large?
The distance should be 1.27 m from the wire in order to get magnetic field one-tenth as large .
The magnitude and direction of the magnetic field due to a straight wire carrying current can be calculated using the previously mentioned Biot-Savart law. Let "I" be the current flowing in a straight line and "r" be the distance. Then the magnetic field produced by the wire at that particular point is given by [tex]B=\frac{u_0I}{2\pi r}[/tex] ..(1)Since the wire is assumed to be very long, the magnitude of the magnetic field depends on the distance of the point from the wire rather than the position along the wire.Let [tex]B_1[/tex] be inside the plane and [tex]B_2[/tex] be outside the plane . It is required to calculate magnetic field at point A .
Direction of magnetic field at A is calculated using Right hand rule.
[tex]B_{net}=B_2-B_1\\\\B_{net}=\frac{u_0I}{2\pi (0.4-\frac{3\times10^{-3}}{2}) } -\frac{u_0I}{(0.4+\frac{3\times10^{-3}}{2})} \\\B_{net}=7.5\times 10^{-9}T[/tex]....(1)
Let a distance "R" from the wire so that the magnetic field is [tex]\frac{B_{net}}{10}[/tex]
Using the magnetic field equation , we get
[tex]\frac{B_{net}}{10} =B_2-B_1\\\\\\frac{7.5\times 10^{-9}}{10} =\frac{u_0I}{2\pi (R-\frac{3\times10^{-3}}{2}) } -\frac{u_0I}{(R+\frac{3\times10^{-3}}{2})} \\\\\R^2-2.25\TIMES10^{-6}=1.6\\\\R=1.27m[/tex]
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When the speaker is lowered into water, does the frequency of the sound increase, decrease, or remain the same?.
Answer: it remains the same
Explanation:
the frequency of a sound wave cannot change as it crosses the water-air boundary
6
Which of the following is NOT something that would lead astronomers to believe a black hole might be close-by in space?
A.
an object that has gas and dust appear to be funneling around an object
B.
an object that has spinning particles around an emptiness in space that emit x-rays
OC.
an object that has height and depth but no width
OD. an object in space with highly elevated temperatures
Reset
Next
The option that is NOT something that would lead astronomers to believe a black hole might be close-by in space is option C: an object that has height and depth but no width.
What is a black hole that can be close-by in space?There is said to be a wandering black hole that can be seen in an approximately 5,000 light-years away from earth.
It is one that can be seen in the Carina-Sagittarius spiral aspect of our galaxy.
Note that, its discovery gives room for astronomers to state that the nearest form of isolated stellar-mass black hole to Earth can be as close as about 80 light-years away.
Therefore, The option that is NOT something that would lead astronomers to believe a black hole might be close-by in space is option C: an object that has height and depth but no width because it has no width, no depth and no height.
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when charge 2 is 3.0 m away from charge 1, the strength of the electric force on charge 2 by charge 1 is 0.80 n. if instead, charge 2 were 6.0 m away from charge 1, what would be the strength of the electric force on charge 2 by charge 1 in that case?
The strength of the electrostatic force is inversely proportional to the square of the distance
between the charges. If the distance is doubled, the force is 1/4.
The new force is 0.80/4 = 0.20 N.
What is electrostatic force?Electrostatic force is the attractive or repulsive force that exists between two charged particles. Also known as Coulomb interaction or Coulomb force. For example, the electrostatic forces between the protons and electrons of an atom are responsible for the stability of the atom.
The force acting along a line joining two point charges is directly proportional to the product of the two charges and inversely proportional to the square of the distance between them.
[tex]F=K |\frac{q_{1} q_{2}}{r^{2} } |[/tex]
In the above formula, k is arbitrary and can be chosen to be any positive value. Since k is a constant, I chose to give the value of k as follows:
Therefore, with q₁ and q₂ values of 1 and r = 1 (two charges with 1 Coulomb charge each at a distance of 1 m), we get F = [tex]9 \times 10^9[/tex] N. In the above equation, ε₀ is given as the permittivity of free space and its value in SI units is [tex]8.854\times10^{-12} C^{2} N^{-1} m^{-2}[/tex].
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M A uniformly charged ring of radius 10.0cm has a total charge of 75.0μC . Find the electric field on the axis of the ring at from the center of the ring.(d) 100 cmat from the center of the ring
The electric field on the axis of the ring at the center of the ring at 100.00cm is 6.64×〖10〗^5N/C
Where a positive charge (q) is given, always note that the charges are pointing away from the electric field. The expression used to calculate the electric field away from the center of the ring is given by the equation below,
E=(K_e×b)/(r^3×Q)
Given that;
E = Electric field
Ke = electric field constant
a = radius of the charge q from the center of the circle
Q = electric charge = 75.0μC
The radius of the charge is a = 10cm= 0.1m
Distance from the electric field is 100cm = 1m
Ke is a constant given as 8.99×〖10〗^(9) Nm^2/c^2
E=(8.99×〖10〗^(9 ) Nm^2/c^2×1)/(〖0.1〗^3×75×〖10〗^(-6) )
E=6.64×〖10〗^5N/C
Therefore, the electric field away from the center of the ring is 6.64×〖10〗^5N/C away from the center of the ring.
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1: The ball is on the 50 yard line. The ball travels west 5 yards before it's
handed off and ran forward (EAST) 15 yards where they're tackled.
What is the distance the ball traveled?
Your answer
This is a required question
* 1 point
The ball is on the 50-yard line. The ball travels west 5 yards. The distance ball traveled was 60 yards.
WHAT IS DIFFERENCE BETWEEN DISTANCE AND DISPLACEMENT ?Distance can be defined as the length of any path between any two locations. Displacement is the direct distance between any two points when calculated via the shortest path between them. When computing distance, the direction is disregarded. The displacement computation takes the direction into consideration.
CALCULATIONThe 5 yard gain would bring the ball to the 45 yard line (ball was tackled at the 50 yard line, so 50 - 5 = 45), but the 15 yards lost due to the tackle and push back would bring ball to the 60 yard line (45 + 15 = 60).
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A cubical surface surrounds a point charge q. Describe what happens to the total flux through the surface if (b) the volume of the cube is doubled
The net electric flux is not dependent on the volume of the cube and hence no change to the electric flux.
According to Gauss law, which states that the electric flux is defined as the electric field multiplied by the area of the surface in a plane perpendicular to the field.
Φ=Q ϵo
Where;
Q is enclosed charge
ϵo is the permittivity of the free space
According to the above gaussian relation, If the volume of the cube is doubled, then flux will neither be doubled or changed. It remains the same. This is because there is no direct relationship between the total flux and volume of the cube in the electric field. This means that there is no change to the electric flux.
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the more matter an object has, the more ________ it has
Answer:
Mass
No matter where an object is in the universe, the more matter an object has, the more mass it will have as well.
You throw a dart horizontally towards the center of a dartboard. The dart reaches the board below the center with a velocity of 1.2 E 1 m/s at an angle of 355o.
a. Determine the distance below the center of the board where the dart hits.
The distance below the center of the board where the dart hits is 0.00056 m.
Distance below the center of the board reached by the dart
The distance below the center of the board reached by the dart is calculated as follows;
v² = u² + 2gh
where;
v is the final vertical velocity of the dartu is the initial vertical velocity of the darth is the distance below the center of the board reached by the dartThe initial vertical velocity of the dart = 0
v² = 0² + 2gh
v² = 2gh
h = v² /2g
h = (v sinθ)²/2g
where;
θ is the angle of projectionh = (1.2 x sin355)²/(2 x 9.8)
h = 0.00056 m
Thus, the distance below the center of the board where the dart hits is 0.00056 m.
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In the electron-transport chain, as electrons move along a series of carriers, they release energy that is used to do what?.
In the electron-transport chain, as electrons move along a series of carriers, they release energy that is used to pump protons across a membrane.
In plants and animals, the electron transport chain refers to the consistent streaming of electrons between cells where electron donors donate electrons and electron acceptors accept electrons through a redox reaction.
An electrochemical gradient is created as a result of the redox reaction and ATPs are produced.
In this chain, there are 4 major protein complexes that are transferred across the plasma membrane.
This cellular process occurs in mitochondria and is responsible for photosynthesis and cellular respiration. Its primary steps are Krebs' cycle, glycolysis, oxidative phosphorylation, and pyruvate oxidation.
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I need help with this ASAP... Please and thank you
Answer: 1) D & 2) H
Explanation:
D. Tropical rainy &
H. Long-term average temperature and precipitation for the area
what does it mean by the term self demagnetization.
Answer:
Self demagnetization means when magnets' poles are free (suspended) for too long, their magnetic attraction becomes weaker and thus, self demagnetizes.
2. A bookshelf is 200 cm and 40 N weight, with supports at its ends (X and Y).
a. A book weighing 12 N is placed in the middle of the shelf. What are the upward forces at X and Y?
b. The book is moved so that it is 40 cm from B. Use moments to calculate the forces at X and Y.
Answer:
force =m×a=40=200×a=a=200-40=160m/second sguaredExplanation:
always accerelation it measures in m/second sguared.
Why is the value of 'g' taken as negative when a body is thrown vertically upwards?
Answer:
See below
Explanation:
[tex]\displaystyle {\textsf {Acceleration is the rate of change of velocity with time:}}[/tex]
[tex]\boxed {g = \frac{dv}{dt}}[/tex]
[tex]\sf {where \;dv = \;change \;in \;velocity\; and \;dt \;the \;change \;in \;time}[/tex]
here g is the gravitational force
When a body is thrown vertically upward, it has an initial speed. As it keeps going up, it speed keeps decreasing until it becomes zero, then the ball starts dropping down
On the upward movement, the change in velocity is negative while the change in time is always positive
So dv/dt = a negative number divided by a positive number which is a negative value for g in the equation for g
Two boxes are at rest…
The pair of forces include;
Normal force of mass 1 on mass 2(F₁₂) and the reaction of mass 2 on mass 1 (F₂₁)
Normal force of mass 2 on the table A (F₂A) and the reaction of the table on the mass 2 (FA2).
What is normal force?
The normal force is an everyday force that is felt when a surface pushes against an object that is placed on that surface.
Normal force acts in opposite direction to the weight of the object.
Based on Newton's third law of motion, for every action, there is an equal and opposite reaction.
The downward force exerted on the table, is equal to the reaction of the table on the masses.
The pair of forces acting on the masses stacked together include the following;
Normal force of mass 1 on mass 2(F₁₂) and the reaction of mass 2 on mass 1 (F₂₁)Normal force of mass 2 on the table A (F₂A) and the reaction of the table on the mass 2 (FA2).Learn more about normal forces here: https://brainly.com/question/14486416
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PLEASE HELP HURRY a penny dropped out a window reaches a speed of 35 m/s. how far did it fall? initial velocity is 0 m/s and gravity is 9.8 m/s
Answer:
use v²=u²+2as
v=35
u=0
a=9.8
35²=0²+2*9.8s
1225/2=9.8s
s = 62.5m
answer=62.5m
Answer:
The height from which the coin fell:
H = 63 m
Explanation:
Given:
V₀ = 0 m/s
V = 35 m/s
g = 9.8 m/c²
___________
H - ?
The height from which the coin fell is calculated by the formula:
H = (V² - V₀²) / (2·g)
H = (35² - 0²) / (2·9.8) ≈ 63 m
Why is the primary mirror in a telescope curved?
Answer:
The primary mirror in a telescope is curved so that it changes the path of the light hitting its surface.
Explanation:
Brainliest please
Answer:
the primary mirror in a telescope is curved because it changes the path of the light hitting its surface.
in a parallel circuit with four 6-ohm resistors across a 24-volt battery, what is the total voltage across resistor-three (vr3) in the circuit?
The total voltage across resistor- three in the circuit is 24V
acc to ohm's law
the electrical current flowing through any circuit is directly proportional to the voltage applied across it.
i.e. V ∝ I
V= IR
I = current
v = voltage
R = resistance (proportionality constant)
R in parallel
(1/Rp = 1/R1 + 1/R2 + 1/R3 +1/R4)
on rearranging the above equation (V=IR)
I = V/R
I = 24/6 = 4A
I is the current in each resistor.
in the parallel circuit voltage across the component is same and total current is the sum of the current flowing through each component.
the total voltage across resistor-three (vr3) in the circuit is
V= IR₃ = 4×6= 24 volt
the total voltage across the resistor three (vr3) in the circuit is 24volt.
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starting from rest, a boulder rolls down a hill with constant acceleration and travels 4.00 m during the first second.
Starting from rest, a boulder rolls down a hill with constant acceleration and travels 4.00 m during the first second, 8 m first it is moving.
What is acceleration?Speed increase is the name we provide for any cycle where the speed changes. Since speed is a speed and a heading, there are simply two different ways for you to speed up: change your speed or shift your course — or change both. In mechanics, speed increase is the pace of progress of the speed of an item as for time. Speed increases are vector amounts (in that they have size and heading). The direction of an article's speed increase is given by the direction of the net power following up on that item. The extent of an articles. An item's typical speed increase throughout some undefined time frame is its adjustment of speed, partitioned by the span of the period. Numerically, Momentary speed increase, in the meantime, is the constraint of the typical speed increase over a microscopic time period. In the terms of analytics, immediate speed increase is the subsidiary of the speed vector regarding time.
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Doug, who runs track for his high school, was challenged to a race by his younger brother, matt. Matt started running first, and doug didn’t start running until matt had finished a quarter-mile lap on the school track. Doug passed matt as they both finished their sixth lap. If both boys ran at a constant speed, with doug running 2 miles an hour faster than matt, what was matt’s speed?.
The speed at which Matt ran is 10 miles per hour. Therefore, option (B) is the correct answer.
Matt runs at a speed of x miles per hour, whereas Doug does it at a speed of 2 miles per hour faster. Doug's speed will thereafter be equal to x + 2 miles per hour. Since there are four quarter-mile laps, Doug completes 1.5 miles in the time it requires Matt to complete 1.25 miles.
Matt:
Speed = x
Distance = 1.25
Time = [tex]\frac{1.25}{x}[/tex]
Doug:
Speed = x+2
Distance = 1.5
Time = [tex]\frac{1.5}{x+2}[/tex]
Making an equation by putting the two timings on the chart equal to one another and then solving for x will reveal that the two boys took the same amount of time from the moment Doug started.
[tex]\frac{1.5}{x+2}[/tex] = [tex]\frac{1.25}{x}[/tex]
1.5x = 1.25 (x+2)
0.25x = 2.5
x = 10
Therefore, Matt’s speed is 10 miles per hour.
The complete question is:
Doug, who runs track for his high school, was challenged to a race by his younger brother, Matt. Matt started running first, and Doug didn’t start running until Matt had finished a quarter-mile lap on the school track. Doug passed matt as they both finished their sixth lap. If both boys ran at a constant speed, with Doug running 2 miles an hour faster than Matt, what was Matt’s speed?
A. 10.5 miles per hour
B. 10 miles per hour
C. 9 miles per hour
D. 8 miles per hour
E. 7.5 miles per hour
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a test charge of 1µc is placed halfway between a charge of 4.7µc and another of 7.7 µc separated by 10 cm. what is the magnitude of the force (in newtons) on the test charge? your answer should be a number with two decimal places, do not include the unit.
The magnitude of the force on the test charge is 1.
What is magnitude?Greatness is the quantitative worth of seismic energy. It is a particular worth having no connection with distance and heading of the focal point. The idea of extents traces all the way back to the Ancient Greeks, when stars overhead was sorted into six sizes. Extent alludes to the evaluating of the splendor of stars, the first being the most splendid. It has been moved to different issues since basically the seventeenth 100 years. In Physics, greatness is characterized as the most extreme degree of size and the course of an item. Greatness is utilized as a typical consider vector and scalar amounts. By definition, we realize that scalar amounts are those amounts that have size as it were.
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1) In a standard lab, students drop blocks on moving carts. A cart with a mass of 3.4 kg is moving with a velocity of 23.9 m/s. A block with a mass of 2 kg is dropped onto the moving cart. What is the velocity of the cart after the block is dropped?
A. 3.4 m/s
B. 5.4 m/s
C.15.1 m/s
D. 23.9 m/s
2) Suppose that the vertical forces on a box are balanced, but the horizontal forces are not. There is a force due west of 50 N, and a force due east of 75 N. The weight of the box is 196 N. What is the net force and the acceleration?
A. The net force is 125 N and the acceleration is 1.25 m/s/s due east.
B. The net force is 25 N and the acceleration is 500 m/sec/sec due east.
C. The net force is 25 N and the acceleration is 1.25 m/s/s due east.
D.
The net force is 3750 N and the acceleration is 500 m/sec/sec due east.
3)
A car traveling with an initial speed of 25 m/s decelerates at −5 m/s2 to a complete stop. What best approximates the distance the car travels during its deceleration?
A. 25 m
B. 63 m
C. 125 m
D. 113 m
4) A 2000-kilogram car at rest at point A accelerates at a constant rate from point A to point B in 5.0 seconds, attaining a maximum speed of 30 meters per second at point B. What is the kinetic energy of the car at point B?
A. 60000 J
B. 590000 J
C. 900000 J
D. 1800000 J
5) Which of the following situations has the greatest momentum?
A. a car that accelerates from rest to 3.0 m/s
B. a rocket that crashes back to Earth with a force of 50.0 N for 0.3 m/s
C. a boxer that hits a punching bag with a net force of 30.0 N for 0.5 s
D. a baseball hit with a net force of 10.0 N for 3.0 s
6) Two objects are moved apart so that they are separated by three times their original distance of separation. Compared to the magnitude of the original gravitational force between them, the magnitude of the new gravitational force is which of the following?
A. one-ninth the amount
B. one-third the amount
C. three times the amount
D. nine times the amount
7) Carter and Sam want to find out about the motion of cars traveling on a stretch of highway. They measure out a segment on the highway and measure the time it takes for a car to pass along that segment. Using this data, which of the following pieces of data are they collecting?
A. Average acceleration
B. Instantaneous speed
C. Average speed
D. Instantaneous acceleration
8) Tommy wants to explore how the rate of change in the speed of a marble rolling down changes at different angles. Which of the following formulas should Tommy use to compare each trial in the experiment?
A. Distance traveled/time
B. Change in velocity/change in time
C. Distance traveled in a direction/time
D. Change in displacement/time
Please Explain
The correct responses are;
1) The velocity is 15.0 m/s
2) The net force is 25 N and the acceleration is 1.25 m/s/s due east.
3) The distance covered is 63 m
4) The kinetic energy is 900000 J.
5) The greatest momentum is displayed by a baseball hit with a net force of 10.0 N for 3.0 s
6) The force is now is one-ninth of the original amount.
7) The data that Carter and Sam want to find out is the Instantaneous speed
8) The appropriate formula is change in velocity/change in time
What is the momentum?The term momentum has to do with the product of the mass and the velocity of a body.
1) We know from the principle of the conservation of momentum that the momentum before collision is the equal to the magnitude of the momentum after Collison in a closed system thus;
3.4 * 23.9 m/s = (3.4 + 2) v
v = 3.4 * 23.9 m/s / (3.4 + 2)
v = 15.0 m/s
2) Mass of the box = 196/9.8 = 20 Kg
The net force that acts on the box = 75 N - 50 N = 25 N
Acceleration = 25 N/ 20 Kg
= 1.25 m/s/s due east.
Thus, the net force is 25 N and the acceleration is 1.25 m/s/s due east.
3) v^2 = u^2 - 2as
v = 0 m/s
u^2 = 2as
s = u^2/2a
s = (25 m/s )^2/ 2 * 5 m/s2
s = 63 m
The distance covered is 63 m
4) Kinetic energy = 1/2 mv^2 = 0.5 * 2000 * (30)^2
= 900000 J
The kinetic energy is 900000 J.
5) The greatest momentum is displayed by a baseball hit with a net force of 10.0 N for 3.0 s
6) The new magnitude of the force between them is one-ninth of the original amount.
7) The data that Carter and Sam want to find out is the Instantaneous speed
8) The formula that should be used is change in velocity/change in time.
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Two waves are traveling in the same direction along a stretched string. The waves are 90.0° out of phase. Each wave has an amplitude of 4.00cm . Find the amplitude of the resultant wave.
The resultant wave is calculated by adding the magnitude of both the waves traveling in same direction.The resulting wave is of the amplitude 5.66cm or 5.66 x 10⁻²m
Let us take A be the amplitude of both the waves that are travelling
We are given that waves are moving 90 degrees out of the phase
Let the equations of the waves be
y1= Asin(ωt-kx)
y2=Acos(ωt-kx)
Since the waves are ninety degrees travelling out of phase ,
The resultant wave is
y=y1+y2
= Asin(ωt-kx) +Acos(ωt-kx)
=√2 A sin(ωt-kx+π/4)
So, we can conclude resultant wave is √2A = √2 *4 =5.66cm
=5.66* 10 ⁻²m
Hence the resultant wave is 5.66cm
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What happens to the period when we change the​ amplitude​ (drop point) of the pendulum? question 2 options: the period does not change when we change the amplitude of the pendulum the period increases when we change the amplitude of the pendulum the period decreases when we change the amplitude of the pendulum
When we change the amplitude of the pendulum, the period does not change when we change the amplitude of the pendulum.
What is a pendulum?A pendulum is device that could be used to show oscillatory motion. The motion of the pendulum is that of an object that is tossed from one side to another. Typically, the simple pendulum is used in most school labs to show a motion that is regular and repeating.
Now we know that the amplitude refers to the point of highest displacement of the pendulum. The point of the highest displacement would depend on the angle at which the pendulum was displaced. The period has to do with the time that it takes for a particular pendulum to complete a full cycle.
We know that the period of the pendulum does not have an effect on the amplitude of the pendulum. It then follows that; When we change the amplitude of the pendulum, the period does not change when we change the amplitude of the pendulum.
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