A football is kicked with an initial speed of 11.0 m/s, at an angle of 35degrees above the horizontal across horizontal ground.
(Assume air resistance is negligible)
What is the range of the ball?

Answer:

13.5V

Explanation:

u=i*r

u=1.8×7.5=13.5V

Answer:

a) W = -4N,   b)  F_net = 0

Explanation:

The suspended weight of the spring ladder is subjected to two forces: the elastic force of the spring directed downwards and the gravitational force directed downwards.

             [tex]F_{e}[/tex] - W = 0

             F_{e} = W

             F_{e} = W = 4 N

a) the gravitational force is the weight of the body

             W = -4N

b) as the system is in equilibrium, the net force is zero

             F_net = 0

Answer:

I think it might be negative reinforcement.

Explanation:

Answer:

negative reinforcement

Explanation:

Answer:

D

Explanation:

Edge 2021

When just gravity is operating on an object, which is said to be in free fall.

The team is unable to set up the spike because the ball is at the rear of the court and has already been hit twice. Knowing this, the team receiving the ball shouts "free ball!" to signal everyone to get ready to start their offense as soon as they get possession of it.

informal idiom to consent to assisting or collaborating with someone as indicated by them: His family wanted him cared for at residence, but the insurance provider was uncooperative.

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Answer:

D) the decay rates of radioactive uranium and lead

Explanation:

As we know that when she found the substance it must have some fixed ratio of radioactive uranium and Lead in that substance.

Here since Uranium is radioactive substance so it will continuously convert into Lead and this ratio will change with time

So here we can say that the ratio of radioactive uranium and lead will depend on its decay rate

now to find the age of the substance we can find the present ratio of lead and uranium in that substance and then compare it with freshly prepared substance.

so by the formula

we can find the age of the sample

Answer:

Its D

Explanation:

Answer:

[tex]5.16*10^{14}Hz[/tex]

Explanation:

1 eV = 1.6 * 10⁻¹⁹ J

The work function is the minimum energy required to cause the photo-emission of electrons. The work function is dependent on the type of metal.  

Whereas the threshold frequency is the minimum frequency of light required to produce the work function energy. The work function is given by:

[tex]E=hf_o\\\\Where\ E = work \ function, h=plank's\ constant=6.63*10^{-34}Js,f=threshold\ frequency.\\\\Given\ that \ E=2.14eV, hence:\\\\E=hf_o\\\\2.14eV=6.63*10^{-34}Js*f_o\\\\f_o=\frac{2.14\ *1.6*10^-19}{6.63*10^{-34}Js} \\\\f_o=5.16*10^{14}Hz[/tex]

Answer:

[tex]Stress=12903.3923m[/tex]

Explanation:

From the question we are told that

Cable length 36,000km

The density of steel is 7900 kg/m3.

Generally mass is mathematically given as

  [tex]m= \rho v[/tex]

  [tex]m= \rho Al[/tex]

Generally the weight of cable is mathematically give as

  [tex]W_c=mg[/tex]

  [tex]W_c=(\rho Al)g[/tex]

Generally the stress on a material is mathematically represented as

  [tex]Stress=\frac{Force}{Area}[/tex]

  [tex]Stress=\frac{\rho Al}{A}*g[/tex]

  [tex]Stress=\frac{\rho l}{1}*g[/tex]

Stress or tensile strength of steel is [tex]1000*10^6N/m^2[/tex]

Therefore

     [tex]l=\frac{Stress}{pg}[/tex]

     [tex]Stress=\frac{1000*10^6}{(7900)(9.81)}[/tex]

    [tex]Stress=12903.3923m[/tex]

    [tex]Stress=12903.4m\ appro[/tex]

Answer:

B-Large groups of stars held together by gravity

Explanation:

If it starts at rest the initial velocity is 0.

For an acceleration, a, and time, t, the velocity is v=at. Since at t=4, v=7, then a=7/4=1.75m/s^2

The initial velocity and the acceleration of the ball start from rest, it rolls down a ramp and reaches the ground after 4 seconds are 0 m/s and 3.5 m / s² respectively.

The rate of change of an object's location when viewed from a particular angle and measured in a particular unit of time is known as its velocity.

The average speed of a point for a set period of time while it travels a predetermined distance along its path is equal to the distance traveled divided by the travel time. A train, for instance, moves at an average speed of 50 km/h when it travels 100 km in two hours.

Given:

A ball starts from rest, it rolls down a ramp and reaches the ground after 4 seconds. The final velocity when it reaches the ground is 7.0 m/s,

Calculate the acceleration as shown below,

[tex]v = u + at[/tex]

7 = u + a  × 4

7 = u + 4a

As it starts from rest, then the initial velocity is 0 m/s

a = 7/4 or 3.5  m / s²

Thus, the acceleration is 3.5 m / s² and the initial velocity is 0 m/s.

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Answer:

when pure water vapor from the water bodies get absorbed into polluted gases in the atmosphere, acid rain is caused and when this happens in a place where an element of the hydrosphere is located, it is polluted.in such a way hydrosphere is effected

Answer: When a parcel of air in the atmosphere becomes saturated with water, precipitation, such as rain or snow, can fall to Earth's surface.

Explanation:

Human contributions to greenhouse gases in the atmosphere are warming the earth's surface a process which is projected to increase evaporation of surface water and accelerate the hydrologic cycle. In turn, a warmer atmosphere can hold more water vapor.

Given that,

The frequency of a sonar signal, f = 288 Hz

Wavelength = 5 m

To find,

The speed of the sonar signal in water.

Solution,

Let the speed of the sonar signal is v. The speed in terms of wavelength and frequency is given by :

[tex]v=f\lambda\\\\v=288\times 5\\\\v=1440\ m/s[/tex]

So, the speed of the sonar signal in water is 1440 m/s.

Answer:

The particle model, because the metal is only absorbing radiation

of specific frequencies

Explanation:

The heating of a metal is an example of blackbody radiation. Blackbody radiation refers to the spectrum of light emitted by any heated object; common examples include the heating element of a toaster and the filament of a light bulb. The spectral intensity of blackbody radiation peaks at a frequency that increases with the temperature of the emitting body(Encyclopedia Britianica).

Max Plank proffered explanation to black body radiation by assuming that the oscillators in the heated body emit or absorb energy in discrete frequencies given by E=hf. Hence the energy was directly proportional to the frequency of the oscillator.

Answer:

D. Inverse square

Explanation:

According to the information you are giving me, you must be referring to Coulomb's law because the electrostatic force in proportion to the displacement of charged particles is [tex] F =\frac{kq_{1}q_{2}}{r²} [/tex].

As you can see, there is a reason as to why this is also referred to as Coulomb's inverse square law because the r² represents the displacement or distance relative to the position of the particles which is squared, and it is inverse because the force and the product of the distance squared is equal to the product of the two charges particles multiplied by coulomb's constant (k) which is approximately 8.9875517923×10⁹ kg⋅m³⋅s⁻²⋅C⁻².

The mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.

The electrostatic force is an attractive and repulsive force caused by the electric charges of particles. The electrostatic force is the electric force that exists between two stationary charged bodies. It is also known as Coulomb's force.

Hence,  electrostatic force inversely proportional to the distance between two charges. If two charges Q and q are separated by a distance r, the magnitude of electrostatic force between them is given by:

F = kQq/r²

So, the mathematical proportion that relates electrostatic force and displacement for a pair of charged particles is Inverse square. Hence, option (D) is correct.

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Answer:

The North American tectonic plate.

Explanation:

recall the formula for momentum: p = m * v

the subatomic particles have very small masses while high speeds, so the product results in values with negative exponents in scientific notation.

Negative exponents also result for the house fly when converting mg into kg (10^-6).

The positive exponents in scientific notation for the momentum come for the gigantic mass of the continental plate which exceeds the negative exponents contributed by the small velocity.

Answer:

[tex]a=4.19 m/s^{2}[/tex]

Explanation:

In order to solve this problem, we must first draw a free body diagram of the situation. (See attached picture)

from this diagram, we can do the following sum of forces:

[tex]\sum F=ma[/tex]

where m is the mass of the rocket and a is its acceleration.

[tex]F_{e}-mg=ma[/tex]

where [tex]F_{e}[/tex] is the force of exhaust. We can solve this for the acceleration, so we get:

[tex]a=\frac{F_{e}-mg}{m}[/tex]

we can find the force of exhaust by using the momentum formula:

Ft=mv

so we can solve this for the force:

[tex]F_{e}=\frac{mv}{t}[/tex]

the problem already tells us what m/t is equal to, so we can directly substitute:

[tex]F_{e}=(1.75x10^{4}kg/s)(2.40x10^3m/s)[/tex]

which yields:

[tex]F_{e}=42x10^6 N[/tex]

So we can now substitute:

[tex]a=\frac{42x10^6N-(3x10^6kg)(9.81m/s^{2})}{3x10^6kg}[/tex]

so:

[tex]a=4.19 m/s^{2}[/tex]

Answer:

it's answer is 117 N

F = Gm1m2/r^2

F = 6.67 * 10 ^-11 * 70 * 7.34 * 10 ^22/(1.71 * 10 ^6)^2

F = 117 N

hope it helps you

Answer:

13.54 tons

Explanation:

Let f be the amount of fuel oxidizer needed

v be the speed

The relationship between them is inverse in nature i.e

f ∝ 1/v

f = k/v

If a rocket for use in deep space is to have the capability of boosting a total load (payload plus the rocket frame and engine) of 3.25 metric tons to a speed of 10,000 m/s, then f = 3.25 when v  = 10,000

Substitute and get k

k = fv

k = 3.25 * 10,000

k = 32500

To get the amount of fuel oxidizer required to produce a speed of 2400m/s, we will find f when v = 2400m/s

Recall that f = k/v

f = 32500/2400

f = 13.54 metric tons

Hence the fuel plus oxidizer that will be required is 13.54 tons

Answer:

  R_eq = 6 Ω

Explanation:

In a series circuit the current is constant throughout the circuit and the resistance is the sum of all the resistances in it.

          R_eq = ∑ [tex]R_{i}[/tex]

in this case we have

          R_eq = R₁1 + 3 R₂

where R₁ is the resistance of the fan and R₂ the resistance of each light, we must clarify that we will assume that the resistance of the lights does not change with temperature

let's calculate

           R_eq = 3 + 3 1

            R_eq = 6 Ω

Answer:

The awnser is 6 ohms.

Explanation:

Answer:

i think guard but not sure

Answer:

The mass of Star 2 is Greater than the mass of Start 1. (This, if we suppose the masses of the planets are much smaller than the masses of the stars)

Explanation:

First of all, let's draw a free body diagram of a planet orbiting a star. (See attached picture).

From the free body diagram we can build an equation with the sum of forces between the start and the planet.

[tex]\sum F=ma[/tex]

We know that the force between two bodies due to gravity is given by the following equation:

[tex]F_{g} = G\frac{m_{1}m_{2}}{r^{2}}[/tex]

in this case we will call:

M= mass of the star

m= mass of the planet

r = distance between the star and the planet

G= constant of gravitation.

so:

[tex]F_{g} =G\frac{Mm}{r^{2}}[/tex]

Also, if the planet describes a circular orbit, the centripetal force is given by the following equation:

[tex]F_{c}=ma_{c}[/tex]

where the centripetal acceleration is given by:

[tex]a_{c}=\omega ^{2}r[/tex]

where

[tex]\omega = \frac{2\pi}{T}[/tex]

Where T is the period, and [tex]\omega[/tex] is the angular speed of the planet, so:

[tex]a_{c} = ( \frac{2\pi}{T})^{2}r[/tex]

or:

[tex]a_{c}=\frac{4\pi^{2}r}{T^{2}}[/tex]

so:

[tex]F_{c}=m(\frac{4\pi^{2}r}{T^{2}})[/tex]

so now we can do the sum of forces:

[tex]\sum F=ma[/tex]

[tex]F_{g}=ma_{c}[/tex]

[tex]G\frac{Mm}{r^{2}}=m(\frac{4\pi^{2}r}{T^{2}})[/tex]

in this case we can get rid of the mass of the planet, so we get:

[tex]G\frac{M}{r^{2}}=(\frac{4\pi^{2}r}{T^{2}})[/tex]

we can now solve this for [tex]T^{2}[/tex] so we get:

[tex]T^{2} = \frac{4\pi ^{2}r^{3}}{GM}[/tex]

We could take the square root to both sides of the equation but that would not be necessary. Now, the problem tells us that the period of planet 1 is longer than the period of planet 2, so we can build the following inequality:

[tex]T_{1}^{2}>T_{2}^{2}[/tex]

So let's see what's going on there, we'll call:

[tex]M_{1}[/tex]= mass of Star 1

[tex]M_{2}[/tex]= mass of Star 2

So:

[tex]\frac{4\pi^{2}r^{3}}{GM_{1}}>\frac{4\pi^{2}r^{3}}{GM_{2}}[/tex]

we can get rid of all the constants so we end up with:

[tex]\frac{1}{M_{1}}>\frac{1}{M_{2}}[/tex]

and let's flip the inequality, so we get:

[tex]M_{2}>M_{1}[/tex]

This means that for the period of planet 1 to be longer than the period of planet 2, we need the mass of star 2 to be greater than the mass of star 1. This makes sense because the greater the mass of the star is, the greater the force it applies on the planet is. The greater the force, the faster the planet should go so it stays in orbit. The faster the planet moves, the smaller the period is. In this case, planet 2 is moving faster, therefore it's period is shorter.

Answer:

If I say the correct answer is B.280

Answer:

k=6.666

Explanation:

F=kx

100=k 50-35

100=k*15

k=6.666

It is called a warm-up.

Answer:

We do warm-ups before we exercise. We do cool-downs after we exercise.

Explanation:

Warming up can help you get ready to do the actual exercise, so you are prepared.

Answer:

c

Explanation:

heat radiates off of thing most of the time

Diagram X = convection; Diagram Y = conduction; Diagram Z = radiation

The direction of heat transfer is first from the lower-temperature object to the higher-temperature object, then back again to the lower-temperature object, and so forth, until the objects are in thermal equilibrium.

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Answer:

The pressure exerted by the brick on the table is 18,933.3 N/m².

Explanation:

Given;

height of the brick, h = 0.1 m

density of the brick, ρ = 19,300 kg/m³

acceleration due to gravity, g = 9.81 m/s²

The pressure exerted by the brick on the table is calculated as;

P = ρgh

P = (19,300)(9.81)(0.1)

P = 18,933.3 N/m²

Therefore, the pressure exerted by the brick on the table is 18,933.3 N/m².