A car drives 0.696 km North, and then turns and drives 4.326 km East. Calculate the magnitude of the car's resultant displacement. Include equation, substitution with units, and answer with units.
Answer:
4.3186km
Explanation:
If a car drives 0.696 km North, and then turns and drives 4.326 km East, the magnitude of the car's resultant displacement will be gotten using the Pythagoras theorem as shown;
d² = x²+y²
Given;
x = 4.326km
y = 0.696km
Substitute into the formula and get d;
d² = (4.326)²+(0.696)²
d² = 18.714276+0.484416
d² =19.198692
d = √19.198692
d = 4.3816km
Hence the magnitude of the car's resultant displacement is 4.3186km
The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g of air by 10°C? Use the table below to help you.
Answer:
50.25 j
Explanation:
Alex HEYYYYYYYYY
Answer:
The table shows the specific heat capacities of various substances. How much energy is required to raise the temperature of 5g of air by 10°C? Use the table below to help you.
"10 J" is WRONG
The right answer is "50.25 J"
Explanation:
hope this helps
in a free body diagram the weight is
Answer:
Explanation:
a. WEIGHT: As we have seen, weight is the gravitational force exerted on an object by the Earth (or any other celestial body). If an object is near the Earth's surface and has mass, then the object has a weight. The magnitude of its weight is w = mg and its direction is toward the center of the Earth.
An object O is acted upon by a 6 N force and a 5 N force. The angle between these two forces is 60°. Draw a scale diagram showing the forces acting on object O and determine the resultant force.
Answer:
Resultant force = [tex]\sqrt{91}[/tex]N
Explanation:
Rf = [tex]\sqrt{f1²+f2²+2.f1.f2.cos60}[/tex]
Rf = [tex]\sqrt{6²+5²+2.6.5.1/2}[/tex]
Rf = [tex]\sqrt{36+25+30}[/tex]
Rf = [tex]\sqrt{91}[/tex]
doesn't look right though...
The magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Given parameters:
Two forces are 6 N and 5N.
Angle between them is 60 degree.
So, magnitude of resultant force be = √(6² + 5² + 2× 6 × 5 × cos60°) N = = 9.54 N.
Angle of the resultant force with respect to 5 N is = tan⁻¹{6sin60°/(5 +6 cos60°) } = 33⁰.
Hence, magnitude of resultant force is 9.54 N and it is acting an angle 33° with the direction of 5 N force.
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The force of a plane's engine is moving the plane toward the right with 800N. Coming from the left you have
resistance forces of air with 60N and friction with 40N. What is the direction and net forces that is being applied
the plane?
Answer:es la F
Explanation:
In which scenario will the two objects have the least gravitational force between them?
Answer:
A
Explanation:
In scenario A the two objects have the least gravitational force between them.
What is gravitational force?Gravitational force is defined as the force which one mass exert on the other mass separated by finite distance. Mathematically gravitational force is directly proportional to product of mass and inversely proportional to square of distance between them.
Force between two mass,
F = Gmm/r²
Given question, to find when have the least gravitational force between two masses so from option A we see there separation distance is maximum 1.5 m and mass product is less than option B.
So least gravitational force when masses are 12 kg and separation distance is 1.5 meter.
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What happens to potential energy as the car goes up the hill?
5. Explain how forming an ionic bond makes metal and nonmetal atoms more stable.
6. Describe how metallic bonds contribute to the physical characteristics of a metal.
7. Describe the type of ions created through metallic bonding.
8. List the three types of atomic bonds and describe the types of atoms-metal
or nonmetal-that form each type of bond.
What are the main differences between asexual reproduction and sexual reproduction?
Asexual reproduction requires two parents and produces non-identical offspring, while sexual reproduction requires only one parent and produces identical offspring.
Asexual reproduction requires two parents and produces identical offspring, while sexual reproduction requires only one parent and produces non-identical offspring.
Asexual reproduction requires only one parent and produces identical offspring, while sexual reproduction requires two parents and produces non-identical offspring.
Asexual reproduction requires only one parent and produces non-identical offspring, while sexual reproduction requires two parents and produces identical offspring.
Answer:
option c
Asexual reproduction requires only one parent and produces identical offspring, while sexual reproduction requires two parents and produces non-identical offspring.
Answer:
C
Explanation:
How do I graph distance ,speed ,velocity, and acceleration?
Answer:
distance is how much space is between, speed is how fast they are going, velocity is money and acceleration is going
Explanation:
The planet Jupiter is about 300 times as massive as Earth, but an object on its surface would weigh only 2.5 times as much as it would on earth. Can you come up with an explanation?
Answer:
here you go
Explanation:
so it might seem that a body on the surface of Jupiter would weigh 300 times as much as on Earth. ... But the radius of Jupiter is about 10 times that of Earth, weakening gravity by a factor of 100, resulting in 3 times its Earth weight.
what is a science book
Answer:
A book containing information on various types of science related topics.
Answer: a science book is a textbook you use for science.
When you open the front door to your warm house on a cold day, which way does the heat flow? For example, which is correct to say: "Close the door, you're letting the cold in!" or "Shut the door, you're letting the heat in!".
Answer:
close the door your letting the cold in
if you had to be an animal, which would you be and why?
Erik Erikson's theory of psychosocial development emphasizes that development occurs by overcoming an emotional
crisis in each of the eight stages of one's lifetime.
Please select the best answer from the choices provided
true or false??????
Answer:
trueeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
Explanation:
The theory is true that psychosocial development emphasizes that development occurs by overcoming an emotional crisis.
What is psychosocial development?The term "psychosocial development" refers to how a human's personality changes during childhood and adulthood, as well as how social skills are acquired. The eight phases of psychosocial development were first described by psychologist Erik Erikson in the 1950s. According to Erikson, each stage is marked by a "psychosocial crisis" that can either have a good or negative impact on a person's personality.
Erikson asserts that a person's personality and social abilities change over the course of eight stages that span the entirety of their life. A person encounters a psychosocial crisis—critical issues—at each level, which must be overcome.
The way a person handles each of these crises has an impact on their personality. If people respond favorably, they acquire virtue (moral behavior).
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The distance recorded for riding a motorcycle on its rear wheel without stopping is more than 320 km! Suppose the rider in this impressive position is traveling with an initial velocity of 8.0 m/s before accelerating. Then the rider travels 40.0 m at a constant acceleration of 2.00 m/s2. What is the rider's velocity after the acceleration?
Answer:
14.97m/sExplanation:
Given
Initial velocity of the car u = 8m/s
Distance travelled by the rider S = 40m
Acceleration a = 2m/s²
Required
rider's velocity after the acceleration v
Using the equation of motion
v² = u²+2as
v² = 8²+2(2)(40)
v² = 64+160
v² = 224
v = √224
v = 14.97m/s
Hence the rider's velocity after the acceleration is 14.97m/s
A bee is flying in your garden. There are Unbalanced forces act on the bee. List 3 things that can happen to the bee’s motion.
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A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)
1. Calculate the pressure of an object with an area of 10m2 force of 5N exerted
on it
Answer:
2
Explanation:
pressure(p)=force(f)\area(a)
Why does a bowling ball and a feather hit the ground at the same time when they are dropped in a vacuum?
Answer:
See the explanation below.
Explanation:
This is because the vacuum chamber removes all the air contained and for this reason, there is no force that opposes the movement of the feather when falling. We must remember that the free fall equation of kinematics is not a function of the mass of an object.
[tex]v_{f} =v_{o} +g*t[/tex]
where:
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
g = gravity acceleration [m/s²]
t = time [s]
As we can see the mass of the object is not included in the equation.
Three vectors , , and , each have a magnitude of 52.0 m and lie in an xy plane. Their directions relative to the positive direction of the x axis are 29.0 ˚, 191 ˚, and 311 ˚, respectively. What are (a) the magnitude and (b) the angle of the vector (relative to the +x direction in the range of (-180°, 180°)), and (c) the magnitude and (d) the angle of in the range of (-180°, 180°)? What are (e) the magnitude and (f) the angle (in the range of (-180°, 180°)) of a fourth vector such that ?
Answer:
a) A´= A
b) θ₁´ = 29º, θ₂´ = - 169º , θ₃´ = -49º
Explanation:
In this exercise you are asked to give the magnitudes and angles of the vectors from another system of
reference
a) The magnitudes
The magnitude of a vector, the size of which is a scalar, this does not depend on the reference system, since it is obtained by subtracting the coordinates of the end point minus the coordinate of the origin of the vector
A = [tex]x_{f}[/tex]- x₀
if the vectors are measured in another reference frame
x_{f}´ = xx_{f}- U
x₀´ = x₀ -U
where U is the distance between the two reference frames
A´ = x_{f}´ - x₀´
we substitute
A´ = (x_{f} - U) - (x₀-U) = x_{f} - x₀
A´ = A
it does not change
b) Angles
The given angles are measured from the positive part of the x axis in a counterclockwise direction, it is asked to give these angles from the x axis
θ₁ = 29º
does not change
θ₁´ = 29º
θ₂ = 191º
we measure clockwise
θ₂´ = θ₂ - 360
θ₂´ = 191 - 360
θ₂´ = - 169º
θ₃ =311º
we measure clockwise
θ₃´ = 311 -360
θ₃´ = -49º
Which situation is most likely to lead to improving a scientific theory?
A. Repeating an experiment to verify results
B. Development of new technologies
C. Increased funding for research
D. Relaxing government restrictions
Answer:
A. Repeating an experiment to verify results
Explanation:
A scientific theory may be defined as the theory of science that is a thought out explanation of the observations done in the nature or that happens in the natural world. They are constructed using several scientific methods by observing many facts and hypothesis.
According to the question, repeating of an experiment a number of times and verifying its result may help in improving a scientific theory as if we get the similar result for each experiments, then it confirms the basis of the hypothesis or the facts that are observe in the nature and conclude a scientific theory.
Answer:
b
Explanation:
In a container there are 2 liters of liquid, of which 75% is alcohol and the remaining 25% is water.
Determine how many cm3 of alcohol must be added to bring the alcohol percentage to 80%.
Answer:
There must be added 500 cm3 of alcohol to bring the concentration to 80%.
Explanation:
Concentration
The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solution.
In the container, there are 2 liters (2000 cubic centimeters) of a solution, 75% of which is alcohol (solute) and 25% of water (solvent).
The original amount of alcohol is:
H = 2000*75% = 1500 cc
The original amount of water is:
W = 2000*25% = 500 cc
When we add x cc of pure alcohol, there are 1500+x cc of alcohol out of 2000+x cc of solution.
The new concentration is calculated as:
[tex]\displaystyle \frac{1500+x}{2000+x}[/tex]
And it's known this concentration is 80% (0.8), thus:
[tex]\displaystyle \frac{1500+x}{2000+x}=0.8[/tex]
Multiplying by 2000+x:
[tex]1500+x = 0.8(2000+x)[/tex]
Operating:
[tex]1500+x = 1600+0.8x[/tex]
Rearranging:
[tex]x-0.8x=1600-1500[/tex]
[tex]0.2x=100[/tex]
[tex]x=100/0.2[/tex]
x= 500
There must be added 500 cm3 of alcohol to bring the concentration to 80%
A car of mass 1167 kg accelerates on a flat highway from 10 m/s to 28.0 m/s. How much work does the car's engine do on the car?
Answer:
Workdone = 465766038 Joules.
Explanation:
Given the following data;
Mass = 1167
Initial velocity = 10m/s
Final velocity =28m/s
To find the workdone;
We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.
Mathematically, it is given by the equation;
W = Kf - Ki
W = ½MVf² - ½MVi²
Substituting into the equation
W = ½(1167)*28² - ½(1167)*10²
W = ½ * 1361889* 784 - ½ * 1361889 * 100
W = 533860488 - 68094450
Workdone = 465766038 Joules.
An object is projected straight upward with an initial speed of 25.0 m/s. What's the maximum height obtained by the object ?
Answer:
The maximum height obtained by the object is approximately 31.855 m
Explanation:
The vertical velocity of the object = 25.0 m/s
The height reached by the object, is given by the following formula;
v² = u² - 2 × g × h
Where;
u = The initial velocity of the object = 25.0 m/s
v = The final speed of the object = 0 m/s at maximum height
h = The maximum height obtained by the object
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values, gives;
0² = (25.0 m/s)² - 2 × 9.81 m/s² × h
2 × 9.81 m/s² × h = (25.0 m/s)²
h = (25.0 m/s)²/(2 × 9.81 m/s²) ≈ 31.855 m
The maximum height obtained by the object, h ≈ 31.855 m.
If a car manufacturer reduced the mass of a new car model, so that it took a force of 4000 N
to accelerate towards the barrier at 4 m/s2, what would be the mass of
the new car?
Answer:
1000 kg
Explanation:
Force = mass x acceleration, Hence, mass = Force/acceleration
mass = 4000/4 = 1000 kg
The ___________________ ______________ (two words) is the least dense layer of the Earth.
Answer:
lithosphere
Explanation:
the least densest layer is the outer most layer
the densest layer is the inner most layer and the inner most layer is the inner core
Answer:
lithosphere
Explanation:
i took the test and i got it right
A 2,100kg car drives toward a 55kg cart that has a velocity of 0.50m/s west. The two objects collide giving the car a final velocity of 6.31m/s east and the shopping cart a velocity of 13.5m/s east what the initial velocity of the car?
A. 6.68m/s east
B. 7.19m/s west
C. 6.68m/s west
D. 7.19m/s east
Answer: A. 6.68m/s east
Explanation: just did it on ap3x
"Johnson is throwing rocks at a bug. The bug in response first flies up 117 Cm, then down 32 cm. After dodging another rocks, the bug again flies up 15 cm. This all takes place of 7 seconds"
What is the Average Velocity of the bug in m/s?
What is the Average Speed of the bug in m/s?
(I know this is very dry, but I could really use some help)
Don't solve the problem, just give the equation/method of solving
IM SORRY THIS IS JUST FUNNY TO ME AHDAHJASHJHADJAS THE BUG FLEW HIGH GOD DAYUM
A 200 N net force acts on a 50 kg box. What is the acceleration of the box?
Answer:
a= 4m/s^2
Explanation:
Fnet =200N
m=50kg
a=?
Fnet = ma
200=50a then divide both sides by 50 to get acceleration
Taking into account the Newton's second law, the acceleration of the box is 4 [tex]\frac{m}{s^{2} }[/tex].
In first place, you have to know that Newton's second law, called the fundamental law or fundamental principle of dynamics, states that a body accelerates if a force is applied to it.
Then, the amount of force necessary is proportional to the acceleration that the body acquires, and the constant of proportionality is the mass of the body.
Mathematically, Newton's second law is:
F= m×a
where:
F = Force [N] m = Mass [kg] a = Acceleration [m/s²]In this case, you know:
F= 200 N m= 50 kg a= ?Replacing in the Newton's second law:
200 N= 50 kg×a
Solving:
a=200 N÷ 50 kg
a= 4 [tex]\frac{m}{s^{2} }[/tex]
In summary, the acceleration of the box is 4 [tex]\frac{m}{s^{2} }[/tex].
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