According to the question a plastic rod that has been charged to − 15nc touches a metal sphere. Afterward, the rod's charge is − 1.0nc.The electrons will be transferred from the plastic rod to the metal sphere and the number of electrons ( n ) = 8.73 * 10^10
First of all, write the initial charge on the plastic rod, and then it touches the metallic sphere. Then, a few amounts of charge are transferred to the steel sphere. Later, calculating the price difference between the plastic rod and metal sphere, the kind of charged particle transferred may be decided. Ultimately, the number of electrons may be calculated by the use of the overall charge and the rate of the electron.
The expression of the total charge in electrostatics is Q = ne
Q = charge
n = number of electrons
e = charge of the electron
The initial charge on the plastic rod ( Qplastic ) = -15nC
Final charge on the metal sphere after it was touched by the plastic rod ( Qmetal ) = -1nC
The charge transferred from the metal rod to the sphere = ( Q = Qplastic - Qmetal )
Therefore Q = - 15nC - ( -1nC )
Q = -14nC
The plastic rod is negatively charged, so the electrons will be transferred to the metal sphere. The electrons will be transferred from the plastic rod to the metal sphere.
The expression of the total charge in electrostatics is Q = ne
The expression for n = Q / e
Q = -14nC
The charge on 1 electron = 1.602 * 10^-19 C.
Number of electrons ( n ) = -14nC ( 10^-9C/1nC ) / -1.602 * 10^-19 C.
Number of electrons ( n ) = 8.73 * 10^10
Threfore the number of electrons ( n ) = 8.73 * 10^10
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Review. A wire having a linear mass density of 1.00 g/cm is placed on a horizontal surface that has a coefficient of kinetic friction of 0.200 . The wire carries a current of 1.50 A toward the east and slides horizontally to the north at constant velocity. What are (a) the magnitude
Magnetic field due to current in wire is 0.1308 Tesla.
Define Coefficient of friction?The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing those surfaces from moving. Typically, it is represented by the Greek letter mu.
Given:
[tex]Mass\;per\;unit\;length(\frac{m}{l})=1.0\;g/cm=0.1\;kg/m\\[/tex]
[tex]Coefficient\;of\;friction,\;(\mu)=0.2[/tex]
[tex]Current,\;(I)=1.5\;A[/tex]
[tex]According\;to\;the\;question,\;wire\;is\;moving\;on\;a\;surface\;with\;\mu\;and\;force\;that\;is[/tex][tex]moving\;the\;wire\;is\;magnetic\;force\;f_{m} , then,[/tex]
[tex]f_{m}=\mu f_{N} (f_{N}=normal\;reaction\;of\;wire)[/tex]
[tex]Also, f_{m}=B\;L\;I\;sin\propto[/tex]
Therefore,
[tex]B_{b}=\frac{\mu\;m\;g}{L\;I\;sin\propto}[/tex]
[tex]B=magnetic\;field[/tex]
[tex]f_{N}=mass \times accelaration\;due\;to\;gravity[/tex]
Therefore,
[tex]B_{b}=\frac{0.2\times0.1\times10}{1.5\times sin\propto}[/tex]
[tex]sin \propto = angle\;magnetic\;field\;and\;the\;current\;in\;the\;wire=sin\;90^{\circ}=1[/tex]
Therefore,
[tex]B_{b}=0.1308\;T[/tex]
Now, from the figure shown and using Fleming's Right Hand rule in which the fore finger indicates current that is in east direction and the thumb indicates force that is in north direction and then direction, shown by your middle finger shows the direction of induced magnetic field.
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a mass on a spring undergoing simple harmonic motion completes 8 oscillations in 4.0 s. what is the period of the motion?
The period of oscillation is 0.5 second.
We need to know about period of oscillation to solve this problem. Period is how much time taken to do one oscillation. It can be determined as
T = t / n
where T is period, t is time and n is how many oscillations.
From the question above, we know that
n = 8
t = 4 s
By substituting the parameters, we get
T = t / n
T = 4 / 8
T = 0.5 second
Hence, the period of oscillation is 0.5 second.
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At a convergent boundary, what is the relative motion of plates on each side of the boundary?.
Answer:
The plates move toward each other
Explanation:
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GEO 1405 Chapter 2 Quiz
A light aircraft makes a flight during changeable weather conditions.
(a) Initially, in still air, the aircraft travels at a velocity of 44 ms' relative to the ground, on a bearing of 056°. Calculate the magnitude of the component of the aircraft's velocity that is directed northwards.
(b) A southward wind begins to blow with a velocity of 11 ms. The pilot does not correct the aircraft in response to the changing wind. Calculate the magnitude and bearing of the aircraft's new velocity.
Answer: a it goes north b goes south
Explanation:
What does weight require?
Responses
gravity and volume
gravity and volume
only mass
only mass
mass and gravity
mass and gravity
mass and volume
Answer:
Mass and gravity
Explanation:
[tex]{ \rm{weight = mass \times gravity}}[/tex]
Weight is the force exerted on an object due to gravity. The correct answer is mass and gravity. The correct option is an option (3).
Weight requires both mass and gravity.
The formula for calculating weight is given by:
Weight = mass × gravitational acceleration
W = m × g
The gravitational acceleration is known by the strength of the gravitational field, which is typically constant at any given point.
The mass of an object and the strength of its gravitational field is its weight. It is the gravitational force that pulls an object toward the center of the Earth.
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Therefore, The correct option is (3).
The complete question is:
What does weight require?
1) gravity and volume
2) only mass
3) mass and gravity
4) mass and volume
An object is moving and velocity of 8 m/s and accelerates to 35 m/s or 6.3 seconds. what is the acceleration?
Answer:
4m/s^2
Explanation:
u find the average of the two velocities then place the outcome in the acceleration formula given time as 6.3 seconds .....dividing the average of the velocities
(a) A proton moving with velocity →v = vi experiences a magnetic force →F = Fi(j) . Explain what you can and cannot infer about \overrightarrow{\mathbf{B}} from this information.
The current must be along +x axis.
What is electric current?
A stream of charged particles, such electrons or ions, traveling through an electrical conductor or a vacuum is known as an electric current. It is calculated as the net rate of passage of electric charge through a surface or into a control volume. Charge carriers, which can be any one of a number of particle kinds depending on the conductor, are the moving particles. Electrons travelling through a wire are frequently the charge carriers in electric circuits. They may be electrons or holes in semiconductors. Ions are the charge carriers in an electrolyte, whereas ions and electrons make up plasma, an ionized gas.
Explanation:
Given,
Velocity of proton,V = [tex]V_{i} i[/tex]
Magnetic force,F = [tex]F_{i} j[/tex]
Magnetic Field= B
(a)
If proton (p+) is moving in ve x-direction.
So,current(I) must be along +x axis.
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if you Launch a cannonball at a launch angle of 55° and an initial speed of 30m/s. What is the cannonball's range?
Answer:
86.2 m range
Explanation:
Vertical component of initial shot = 30 sin 55= 24.575 m/s
Now you can find out for how long it is in the air
when it hits the ground , position = 0
0 = 24.575 t - 1/2 ( 9.81) t ^2
finds t = 5.01 seconds (Using quadratic formula)
HORIZONTAL component = 30 cos 55 = 17.21 m/s
it travels this speed for 5.01 seconds
5.01 * 17.21 = 86.2 m
you should begin viewing a bacteria specimen with what objective lens? view available hint(s)for part g you should begin viewing a bacteria specimen with what objective lens? 100x 10x 40x
It is important to choose the appropriate magnification for your needs so that you can properly examine the specimen under study.
Why is the 100x objective lens necessary to see bacteria?Bacteria must, of course, be viewed at the maximum magnification and resolution possible because to their small size. Due to optical restrictions, this is approximately 1000x in a light microscope. To improve resolution, the oil immersion method is performed. This calls for a unique 100x objective.To learn more about bacterial specimen, visit:
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2. Do you think the density of the ice affected the melting rate of the ice, or do you think adding the objects affected the melting rates?
The density of ice does not affect its melting rate. Adding objects will affect the melting rate.
A physical process called melting or fusing causes a substance to change its phase from a solid to a liquid. This happens when the solid's internal energy rises, usually as a result of heat or pressure being applied, which raises the substance's temperature to the melting point.The term "density" refers to an extensive quality, which means that it is independent of the substance's concentration. Every substance in the world demonstrates its distinctive density. Since it does not fluctuate, it would not affect the rate of melting. The addition of the objects could speed up the process, though, as each one generates heat that could act as the mediating force for the melting process.To learn more about density, visit :
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what does is mean if the VR of the machine is 2?
Answer:
Velocity ratio of simple machine is the ratio of distance traveled by the effort to the distance traveled by the load in the machine. As velocity ratio or ideal mechanical advantage is a simple ratio of two distances.Hence always remains constant. Option A is correct.
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Answer:
Velocity ratio of simple machine is the ratio of distance traveled by the effort to the distance traveled by the load in the machine. As velocity ratio or ideal mechanical advantage is a simple ratio of two distances.Hence always remains constant. Option A is correct.
Explanation:
EXTRA:Velocity ratio of a lever is 3 means distance travelled by effort is 3 times the distance travelled by the load. Efficiency of the pulley is 60% means 40% of the energy is lost in the machine due to the friction.
EXTRA:Ans:- MA of a lever is 3 it means that the load is 3 times of effort and VR of a lever is 4 it means that effort distance is 4 times of load distance.
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The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in 1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n=1.33 is the index of refraction of water.(b) Show that for v<
It is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .
Given ,
The motion of a transparent medium influences the speed of light .
The water moves with speed v in a horizontal pipe .
Assume that the light travels in the same direction as the water moves .
The speed of the light with respect to the water is c/n
Where n = 1.33 is the refractive index of water .
Let us assume ,
u' be the speed of light in water , in the frame moving with the water .
u' is related to the refractive index of water ,n as :
u'=c/n
where , c is the speed of light .
let , u be the speed of light in water in the lab frame .
Now , u and u' are related as : u = (u'+ v )/(1+ u'v/c^2)
Here v is the speed of water in the horizontal pipe .
we know the value of u' , so by substituting the value , we will get ,
u= (c/n+ v)/(1+cv/nc^2)
u= c/n(1+ nv/c)/(1+v/nc)
(b) We have , v<<c
v/c<<1 .
so , (1+v/nc )^-1 = (1-v/nc)
Now substituting this , we will get ,
u = c/n(1+nv/c) (1-v/nc)
u≈c/n(1+ nv/c-v/cn)
u≈c/n + v - v/n^2
Hence , it is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .
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Disclaimer : incomplete question , here is the complete question .
Question: The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n=1.33 is the index of refraction of water.(a) Use the velocity transformation equation to show that the speed of the light measured in the laboratory frame isu = c/n (1 + nv/c / 1+ v/nc) . (b) show that for v<<c , the expression from part (a) becomes , to a good approximation , u ≈ c/n + v - v/n^2 .
An interstate highway has been built through a neighborhood in a city. In the afternoon, the sound level in an apartment in the neighborhood is 80.0 dB as 100 cars pass outside the window every minute. Late at night, the traffic flow is only five cars per minute. What is the average latenight sound level?
The level of sound intensity at the late-night is β₂ = 67.0dB
What is a sound level meter?Acoustic measurements are made with a sound level metre, often known as a sound pressure level metre (SPL). A hand-held device with a microphone is the most typical type. The condenser microphone is the best kind of microphone for sound level metres because it combines accuracy with stability and dependability. Sound waves generate changes in air pressure, which the microphone's diaphragm reacts to. The device is sometimes referred to as a sound pressure level metre because of this (SPL).
We are given:
The level of sound intensity in the afternoon is β₁ = 80dB
No. of cars per min in the afternoon = 100
No. of cars per min in late night = 5
The level of sound intensity in the late night β₂ =?
The level of sound intensity in the late night I² =?
Reference sound intensity, I₀ = 10⁻¹²W/m²
The sound intensity level is given by: β = 10Log(I/I₀)
Numerically evaluating,
β₂ = 10 log (5X10⁻⁶/10⁻¹²)
β₂ = 67.0dB
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A cheetah can accelerate from rest to a speed of 30. 0 m/s in 7. 00 s. What is its acceleration?.
The cheetah that can accelerate from rest to a speed of 30.0 m/s in 7.00s has an acceleration of: 4.285 m/s²
The formula and procedure we will use to solve this exercise is:
a = (vf - vi) /t
Where:
a = accelerationvf = final velocityvi = initial velocityt = timeInformation about the problem:
vi= 0 m/svf = 30.0 m/st = 7.00 sa=?Applying the acceleration formula we have:
a = (vf - vi) /t
a = (30.0 m/s - 0 m/s) /7.00 s
a = (30.0 m/s m/s) /7.00 s
a = 4.285 m/s²
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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A long, vertical, metallic wire carries downward electric current. (i) What is the direction of the magnetic field it creates at a point 2cm horizontally east of the center of the wire? (a) north (b) south (c) east (d) west (e) up
At a point 2 cm horizontally east of the wire's center, the magnetic field generated by the vertical wire is pointing south. As a result, option B south is the correct answer.
Why are magnetic fields created?There are north and south poles on every magnet. The same poles repel one another whereas opposite poles are attracted to each other. The north-seeking poles of the iron's atoms pairing in the same direction when it is touched against a magnet. A magnetic field is produced by the force that the aligned atoms produce. The iron object has changed into a magnet. An electric current has the ability to magnetize specific materials. A magnetic field results from the flow of electricity through a coil of wire. But as quickly as the electric current is cut off, the field around the coil will disappear.
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A football player pushes a 590 n tackling sled. his coach observes this and believes that this is too light and wants to present the player with a greater physical challenge. he asks two players (player a weighs 100 kg and player b weighs 125 kg). the coefficient of static friction between the sled and grass is 0.70. how much force must the player exert to start the tackling sled in motion with players a and b on it
The player has to apply a force of 1956.5N to start tackling sled in motion.
Coefficient of static friction μ[tex]_{s}[/tex] = 0.70
Weight of sled = mg
= 590N
Weight of Player A = [tex]m_{a}g[/tex]
= 100 × 9.8
= 980N
Weight of Player B = [tex]m_{b}g[/tex]
= 125 × 9.8
= 1225N
Combined weight of sled:
W = (590+980+1225)N
= 2795N
Now, friction on sled:
f = μ[tex]_{s}[/tex]R
= 0.70 × 2795
= 1956.5N
Therefore, the player has to apply force equal to static friction to start tackling sled in motion.
∴ Force = Static friction = 1956.5N
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Sam jumped from a plane. His acceleration was -9.8 m/s². He hit the ground in 30
seconds. What was his velocity just before he hit the ground?
The velocity of Sam just before hitting the ground is 294 m/s.
The above situation represents a case of motion in one dimension.
This type of motion is governed by the following three equations of motion,
v = u + at
v² - u² = 2as
S = ut + 1/2 at²
As in the given case, the acceleration and time have been given and the final velocity is to be calculated, therefore the 1st equation can be used,
v = u+ at
As Sam jumped from the plane, his initial velocity is zero.
So,
v = 0 + 9.8(30)
v = 294 m/s.
Thus, Sam's velocity just before hitting the ground is 294 m/s.
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A stone of mass 0.12 kg is fired from a catapult. The velocity of the stone changes from 0 to 5.0 m / s in 0.60 s. What is the average resultant force acting on the stone while it is being fired?
Answer:
Explanation:
The answer will be the 1.66N
According to the 1 equation of motion:
v=u+at; where v=final velocity, u=initial velocity, a= acceleration, t=time
According to the given value in question
0=5+a*0.60
a= -5/0.60
a=-13.88m/s2
Now according to the Newton’s 2 law
F=ma; where F=force, m=mass
F=0.12*13.88
F=1.66N
So, the average resultant force acting on the stone while it is being fired will be 1.66N.
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A monochromatic light beam is incident on a barium target that has a work function of 2.50 \mathrm{eV} . If a potential difference of 1.00 \mathrm{~V} is required to turn back all the ejected electrons, what is the wavelength of the light beam? (a) 355 nm(b) 497 nm(c) 744 nm(d) 1.42 pm(e) none of those answers
The wavelength of the light beam required to turn back all the ejected electrons is 497 nm which is option (b).
Work function is a material property defined as the minimum amount of energy required to infinitely remove electrons from the surface of a particular solid. The potential difference required to support all emitted electrons is called the stopping potential which is given by [tex]v_0=\frac{K.E_m_a_x}{e}[/tex] .....(1)where [tex]v_0[/tex] is the stopping potential and e is the charge of the electron given by [tex]1.6\times10^-^1^9[/tex] .It is given that work function (Ф) of monochromatic light is 2.50 eV.
Einstein photoelectric equation is given by:
[tex]K.E_m_a_x=E-\phi[/tex] ....(2)
where K.E(max) is the maximum kinetic energy.
Substituting (1) into (2) , we get
[tex]ev_0=E-\phi\\1.6\times10^{-19} \times1=E-2.50\\E=1.6\times10^{-19}+2.50\\E=2.50eV[/tex]
As we know that [tex]E=\frac{hc}{\lambda}[/tex] ....(3)
where Speed of light,[tex]c = 3\times10^8 m/s[/tex] and Planck's constant , [tex]h = 6.63\times 10^-^1^9Js = 4.14\times 10^-^1^5 eVs[/tex]
From equation (3) , we get
[tex]\lambda=\frac{hc}{E} \\\\\lambda=\frac{ 4.14\times 10^-^1^5 \times 3 \times10^8}{2.50} \\\\\lambda=\frac{1240\times10^-^9}{2.50} \\\\\lambda=496.8\times10^-^9\\\\\lambda=497nm[/tex]
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A ball is rolled at a velocity of 2.0 m/s. After 3.6 seconds, it comes to a stop. What is the
acceleration of the ball?
Answer: Given -
Initial velocity of the ball, u = 0 m/sfinal velocity of the ball, v = 12 m/sTime taken = 36 secTo find -
Acceleration of the ball.Solution -
[tex]A=\frac{v-u}{t}\\A=\frac{12-0}{36} \\A=\frac{12}{36} \\A=0.33m/s^2[/tex]
Therefore, the acceleration of the ball is 0.33 m/s².
I hope this helps.
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A proton moves at 0.950 c . Calculate its (c) kinetic energy.
The kinetic energy of the proton is 1982.31 MeV.
We need to know about relativistic energy to solve this problem. The rest energy of the object can be determined by
Eo = m₀ . c²
where Eo is rest energy, m₀ is rest mass and c is the speed of light (3 x 10⁸ m/s).
The total energy of object can be described as
E = Eo / √(1 - v²/c²)
where E is total energy, v is the object speed.
Kinetic energy can be defined as energy change from rest energy until total energy. It can be determined as
KE = E - Eo
where KE is kinetic energy.
From the question above, we know that :
m₀ = 1.6 x 10¯²⁷ kg
c = 3 x 10⁸ m/s
v = 0.95c
Find the rest energy
Eo = m₀ . c²
Eo = 1.6 x 10¯²⁷ . (3 x 10⁸)²
Eo = 1.44 x 10¯¹⁰ joule
Eo = 1.44 x 10¯¹⁰ / (1.6 x 10¯¹⁹) eV
Eo = 900 x 10⁶ eV
Eo = 900 MeV
Determine the total energy
E = Eo / √(1 - v²/c²)
E = 900 / √(1 - (0.95c)²/c²)
E = 900 / 0.31
E = 2882.31 MeV
Calculate the kinetic energy
KE = E - Eo
KE = 2882.31 MeV - 900 MeV
KE = 1982.31 MeV
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a car with a velocity of 22 m/s is accelerated uniformly at the rate of 1.6 m/s'' for 6.8 s. what is its final velocity?
The final velocity of the car, given the data is 32.88 m/s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the final velocityThe following data were obtained from the question:
Initial velocity (u) = 22 m/sAcceleration (a) = 1.6 m/s²Time (t) = 6.8 s Final velocity (v) = ?The final velocity of the car can be obtained as follow:
a = (v – u) / t
1.6 = (v – 22) / 6.8
Cross multiply
v – 22 = 1.6 × 6.8
v – 22 = 10.88
Collect like terms
v = 10.88 + 22
v = 32.88 m/s
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Halley’s comet has a perihelion distance of 0. 6 au and an orbital period of 76 years. What is the aphelion distance of halley’s comet from the sun?.
The aphelion distance of Hailey's comet from the sun is 36 A. U.
The perihelion distance of Hailey's comet = 0.6 amu
The orbital period of Hailey's comet = 76 years
According to Kepler's law,
The time duration is T.
T = 76 years.
The semi-major axis is a.
The semi-major axis is,
[tex]T ^{2} =a ^{3} [/tex]
[tex]a = \sqrt[3]{(T) ^{2} }[/tex]
[tex]a = \sqrt[3]{(76) ^{2} }[/tex]
= 18 A. U
The aphelion distance of Hailey's comet from the sun is,
= 2 × a
= 2 × 18
= 36 A. U
Therefore, the aphelion distance of Hailey's comet from the sun is 36 A. U.
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a large beaker of water is filled to its rim with water. a block of wood is then carefully lowered into the beaker until the block is floating. in this process, some water is pushed over the edge and collects in a tray. the weight of the water in the tray is a large beaker of water is filled to its rim with water. a block of wood is then carefully lowered into the beaker until the block is floating. in this process, some water is pushed over the edge and collects in a tray. the weight of the water in the tray is less than the weight of the block. greater than the weight of the block. equal to the weight of the block.
The correct answer is Equal to the weight of the block.
We are aware that when an object floats, the water it displaces weighs the same as the weight of the floating body. The upthrust is now equivalent to the body weight in this situation. The beaker is overflowing with water in this instance. The body was then created to float into it. When it reaches equilibrium in water, it expels water that must have been the same weight as it. Over the edge, the liquid spilled, collecting on the tray.
Therefore, the amount of water gathered on the tray must match the weight of the person floating.
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what is the repulsive force between two pith balls that are 13.5 cm apart and have equal charges of 44.0 nc?
One pith ball's charge, q1, is equal to 30 nC, or 30x10-9C.
the second pith ball's charge, q2 = -30n c= -30x 10-9 c
They are separated by d=8 cm, or 8x10-2 metres.
They repel one another by a force of F = (81/64) x 10-3.
F = 1.266x10^-3 N
Is the force of gravity repellent?The gravitational force is solely an attracting one in both the General Theory of Relativity and Newton's theory of gravity. But quantization of gravity demonstrates that there are opposing gravitational forces as well.
A force between two or more opposite or different charges is called attraction. Two charges that are at odds with one another are attracted to one another. A force between two or more like or comparable charges is called repulsion. Two identical charges separate themselves.
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Review. A global positioning system (GPS) satellite moves in a circular orbit with period 11h 58 min.(b) Determine its speed.
The global positioning system (GPS) satellite that moves in a circular orbit with period of 11h 58 min has a speed of: 3872.9848 m/s
To solve this problem the formulas and the procedures we will use are:
r =[(G* m *T²)/(4 * π²)]v = (2*π * r)/ TWhere:
r = orbital radiusG = Gravitational constantm = Mass of the EarthT = Time period of the satelliteπ = mathematical constantv = tangential velocityInformation about the problem:
T = 11h 58 minG = 6.67 × 10⁻¹¹ m³/kgs²m= 5.972 × 10²⁴ kgπ = 3.1416r =?v =?By converting the time period of (h) and (min) from (s) we have:
T = (11h *3600 s/ 1 h) + (58 min * 60 s/1 min)
T = 39600 s +3480 s
T = 43080 s
Applying the orbital radius formula we get:
r =[(G* m *T²)/(4 * π²)]
r =[(6.67 × 10⁻¹¹ m³/kgs² * 5.972 × 10²⁴ kg *(43080 s)²)/(4 * (3.1416)²)]
r =[1.8725*10^22 m³]
r= 26.55465166*10^6 m
Applying the tangential velocity formula we get:
v = (2*π * r)/ T
v = (2 * 3.1416 * 26.55465166*10^6 m)/ 43080 s
v = 3872.9848 m/s
What is the orbital radius?It is the maximum of the radial distribution curve of the outermost orbital.
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Marta gives long, involved answers to every question, even simple ones. She uses technical vocabulary even if the people she is talking to do not understand it. What is the BEST advice Marta’s supervisor could give her?
A.
Use technology to your team’s advantage.
B.
Manage information, not people.
C.
Make sure your networks are strong.
D.
Adapt your communication style.
Please HELP
Answer:
D. Adapt your communication style.
Explanation:
It is quite difficult to gauge the protocol here given the lack of information about the work environment; but as a general answer, communication skills are always handy. Furthermore, it seems that Marta in particular struggles with this. Assuming Marta is providing a specialized service of a sort, she would need to understand that there is a reason why her services are required at all. Through this, hopefull she'll understand that they are most likely outside of this field of work, and ergo [she] must cater and gear her actions towards the interest of the person(s) in question.
It is to be noted that this is merely my surmise.
Some towns depend on water from snow that falls high up in the mountains, melts, and flows down the mountain. Some years, spring comes early and the snow begins to melt earlier than usual. What is one problem of early water runoff that engineers might be asked to solve? What criteria and constraints might need to be considered for concerns such as materials, space, and cost?
The problem of early water runoff that engineers might be asked to solve is the issue of Impervious surfaces, or surfaces that are unable to absorb water.
What criteria and constraints might need to be considered are?They are:
RoadsSidewalks, Parking lots are impervious surfaces. Car-washing soapsLitterSpilled gas, etc.In the water cycle, runoff is known to be when water just "streaming off" the surface of the ground. The rain need to also drains downhill, just like the water a person use to wash their car does as a person work are all part of runoff.
Therefore, The problem of early water runoff that engineers might be asked to solve is the issue of Impervious surfaces, or surfaces that are unable to absorb water.
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As the people sing in church, the sound level everywhere inside is 101 dB . No sound is transmitted through the massive walls, but all the windows and doors are open on a summer morning. Their total area is 22.0 m² . (a) How much sound energy is radiated through the windows and doors in 20.0 min?
The sound energy radiated through the windows and doors in 20 min is 332.6 J.
What do you mean by Sound energy?When a force, such as sound or pressure, causes an item or substance to vibrate, the result is sound energy. That energy moves through the substance in waves. Those sound waves are called kinetic mechanical energy. Sound waves are sometimes dubbed mechanical waves because sound waves require a physical medium to propagate. Liquids, gases, or solid materials transfer pressure variations, creating mechanical energy in waves. Like all waves, sound waves include peaks and valleys. The peaks are called compressions, while rarefaction is the term used for the lows. The oscillations between compression and rarefaction move through gaseous, liquid, or solid media to produce energy. The number of compression/rarefaction cycles in a given period determines the frequency of a sound wave.
Sound energy = E = power x time
energy = force x time / area
Given:
sound level, [tex]\beta=101 dB[/tex]
Area, A = [tex]22\;m^{2}[/tex]
Time, [tex]\triangle t=20\;min=1200\;s[/tex]
Intensity, [tex]I_{o}=1 \times 10^{-12}\;W/m^{2}[/tex]
We know that, Sound level is,
[tex]\beta=10 \times log\frac{I}{I_{o} }[/tex]
Solving the above equation for sound intensity,
[tex]I=I_{o}\times 10^{\frac{\beta}{10} }[/tex]
[tex]I=I \times 10^{-12} \times 10^{\frac{101}{10} }[/tex]
[tex]I=0.0126\;W/m^{2}[/tex]
Therefore, The sound energy is,
[tex]E = P \times \triangle t[/tex]
Substitute [tex]P=I \times A[/tex] in the above equation,
[tex]E = I \times A \times \triangle t[/tex]
[tex]E = 0.0126 \times 22 \times 1200[/tex]
[tex]E = 332.6\;J[/tex]
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