A population of protozoa develops with a constant relative growth rate of 0.7781 per member per day. On day zero the population consists of six members. Find the population size after four days. (Round your answer to the nearest whole number.) P(4)

Answers

Answer 1

Answer:

[tex] P(t) = A (1+r)^t [/tex]

Where P represent the population after t days. a the initial amount on this case 6 and r the growth factor rate of 0.7781. so then our model would be given by:

[tex] P(t)= 6(1.7781)^t [/tex]

And replacing t=4 we got:

[tex] P(4) = 6(1.7781)^4 =59.975 \approx 60[/tex]

So then after 4 days we would expect about 60 protzoa

Step-by-step explanation:

For this case we can use the following function to model the population of protzoa:

[tex] P(t) = A (1+r)^t [/tex]

Where P represent the population after t days. a the initial amount on this case 6 and r the growth factor rate of 0.7781. so then our model would be given by:

[tex] P(t)= 6(1.7781)^t [/tex]

And replacing t=4 we got:

[tex] P(4) = 6(1.7781)^4 =59.975 \approx 60[/tex]

So then after 4 days we would expect about 60 protzoa


Related Questions

Which of the following expressions shows the correct amount of sales tax for the computer at Store A? Select all that apply. 6%($1,200) 0.6($1,200) 0.06($1,200) 1/6($1,200) 3/50($1,200)

Answers

Answer:

1, 3,5

Step-by-step explanation:

Answer:

1,3,5

Step-by-step explanation:

A company services home air conditioners. It is known that times for service calls follow a normal distribution with a mean of 75 minutes and a standard deviation of 15 minutes. A random sample of twelve service calls is taken. What is the probability that exactly eight of them take more than 93.6 minutes

Answers

Answer:

The probability that exactly eight of them take more than 93.6 minutes is 5.6015 [tex]\times 10^{-6}[/tex] .

Step-by-step explanation:

We are given that it is known that times for service calls follow a normal distribution with a mean of 75 minutes and a standard deviation of 15 minutes.

A random sample of twelve service calls is taken.

So, firstly we will find the probability that service calls take more than 93.6 minutes.

Let X = times for service calls.

So, X ~ Normal([tex]\mu=75,\sigma^{2} =15^{2}[/tex])

The z-score probability distribution for the normal distribution is given by;

                              Z  =  [tex]\frac{X-\mu}{\sigma}[/tex]  ~ N(0,1)

where, [tex]\mu[/tex] = mean time = 75 minutes

           [tex]\sigma[/tex] = standard deviation = 15 minutes

Now, the probability that service calls take more than 93.6 minutes is given by = P(X > 93.6 minutes)

       P(X > 93.6 min) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{93.6-75}{15}[/tex] ) = P(Z > 1.24) = 1 - P(Z [tex]\leq[/tex] 1.24)

                                                                = 1 - 0.8925 = 0.1075

The above probability is calculated by looking at the value of x = 1.24 in the z table which has an area of 0.8925.

Now, we will use the binomial distribution to find the probability that exactly eight of them take more than 93.6 minutes, that is;

[tex]P(Y = y) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; y = 0,1,2,3,.........[/tex]

where, n = number of trials (samples) taken = 12 service calls

            r = number of success = exactly 8

            p = probability of success which in our question is probability that

                   it takes more than 93.6 minutes, i.e. p = 0.1075.

Let Y = Number of service calls which takes more than 93.6 minutes

So, Y ~ Binom(n = 12, p = 0.1075)

Now, the probability that exactly eight of them take more than 93.6 minutes is given by = P(Y = 8)

               P(Y = 8)  =  [tex]\binom{12}{8}\times 0.1075^{8} \times (1-0.1075)^{12-8}[/tex]

                             =  [tex]495 \times 0.1075^{8} \times 0.8925^{4}[/tex]

                             =  5.6015 [tex]\times 10^{-6}[/tex] .

Math Activity #1
The number of the day is 1,853,604,297.
Write this number in word form:

Answers

One billion, eight hundred fifty-three million, six hundred four thousand, two hundred ninety-seven

Maria, Daniel, Stephanie, Michael, Elena, Tyler, Sue, and Dimitri have reserved eight seats in a row at the theater, starting at an aisle seat. In how many ways can they arrange themselves if Maria and Daniel are to sit next to each other?

Answers

Answer:

1x1x6x5x4x3x2x1 = 720 also they can sit in:

6x1x1x5x4x3x2x1 = 720

6x5x1x1x4x3x2x1 = 720

6x5x4x1x1x3x2x1 = 720

6x5x4x3x1x1x2x1 = 720

6x5x4x3x2x1x1x1 = 720

6x5x4x3x2x1x1x1 = 720 or you could have gone 720 x 7

Find the slope and y-intercept of this linear function:
2x + x = 4(y - 1)

Answers

Answer:

slope: 3/4y-intercept: 1

Step-by-step explanation:

Solve for y to put the equation in slope-intercept form.

  3x = 4y -4 . . . . . eliminate parentheses, collect terms

  3x +4 = 4y . . . . . add 4

  y = 3/4x +1 . . . . . divide by 4

The slope is the x-coefficient: 3/4.

The y-intercept is the constant: 1.

which transformations are non ridged transformations pick two options (dialation, reflection, rotation, stretch, translation)

Answers

it would definitely be the last 2

Watermelon A is 2 kg lighter than watermelon B and it weighs one fifth of the weight of watermelon C. Watermelons A and C together are 3 times as heavy as watermelon B. How heavy is each watermelon?

Answers

Answer:

A: 2 kgB: 4 kgC: 10 kg

Step-by-step explanation:

We can write some equations to describe the given relationships:

  A = B - 2 . . . . . A is 2 kg lighter than B

  A = C/5 . . . . . . A is 1/5 the weight of C

  A+C = 3B . . . . together, A and C are 3 times the weight of B

__

Let's solve for A.

  B = A+2 . . . from the first equation

  C = 5A . . . . from the second equation

  A +5A = 3(A+2) . . . . substituting for B and C in the third equation

  6A = 3A +6

  3A = 6

  A = 2

__

  B = A+2 = 4

  C = 5A = 10

Watermelon A weighs 2 kg; B weighs 4 kg; and C weighs 10 kg.

Answer:

2 kg 4 kg 10 kg

I BLESS THE EYES!

Please answer this correctly

Answers

So if we know the perimeter of the circle we can find it's radius using the formula for perimeter:

[tex]p = 2\pi(r)[/tex]

So we can solve for radius:

[tex]r = \frac{10.71}{2\pi} [/tex]

Then we can plug this radius into the formula for the area of a circle:

[tex]a = \pi {r}^{2} [/tex]

[tex]a = \pi( \frac{10.71}{2\pi} ) ^{2} [/tex]

Then it only wants a quarter of that area so we divide that value by 4 which upon simplification becomes the answer:

[tex]2.28 {ft}^{2} [/tex]

Answer:

[tex] \boxed{Area \: of \: quarter \: circle = 7.065 \: square \: feet} [/tex]

Given:

Perimeter of quarter circle = 10.71 feet

To find:

Area of quarter circle

Step-by-step explanation:

First we need to calculate the radius of quarter circle:

Let the radius of quarter circle be 'r'

[tex]Perimeter \: of \: quarter \: circle = \frac{\pi r}{2} + 2r[/tex]

[tex] \implies 10.71 = \frac{\pi r}{2} + 2r \\ \\ \implies 10.71 = \frac{\pi r}{2} +2r \frac{2}{2} \\ \\ \implies 10.71 = \frac{\pi r}{2} + \frac{4r}{2} \\ \\ \implies 10.71 = \frac{\pi r + 4r}{2} \\ \\ \implies 10.71 \times 2 = \pi r + 4r \\ \\ \implies 21.42 = \pi r + 4r \\ \\ \implies 21.42 = (\pi + 4)r \\ \\ \implies 21.42 = (3.14 + 4)r \\ \\ \implies 21.42 = 7.14r \\ \\ \implies 7.14r = 21.42 \\ \\ \implies r = \frac{21.42}{7.14} \\ \\ \implies r = 3 \: ft[/tex]

[tex] Area \: of \: quarter \: circle = \frac{\pi {r}^{2} }{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{\pi \times {(3)}^{2} }{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{\pi \times 9}{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{3.14 \times 9}{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{28.26}{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =7.065 \: {ft}^{2} [/tex]

What is the center of a circle represented by the equation (x+9)2+(y−6)2=102? Please Help

Answers

(-9, 6) that’s the answer

Answer:

(-9, 6)

Step-by-step explanation:

edgenuity 2020

hope this helps!

What’s the correct answer for this?

Answers

Answer:

I think the answer is 282.6 but my answer is 297.33.

Answer:

the answer will be 282.6m^2

but that is not entirely correct

Step-by-step explanation:

Mrs. Fields needs more chocolate chips to make cookies. The store has bags that weigh 0.45 lbs., 0.434 lbs., and 0.4 lbs. Which bag should she purchase if she wants the most chocolate chips?

Answers

Answer:

bag weigh 0.45 lbs

Step-by-step explanation:

Data on return-to-pay ratios was collected from CEOs of companies within both the low-tech industry and the consumer products industry.

Low-Tech Consumer Products
Sample size 14 12
Sample mean 157 218
Sample Variance 1563 1602
Assume population variances are unequal.

(a) The point estimate of the difference between the means of the two populations is

(b) The standard error for the difference between the two means is

(c) The correct distribution to use is :

t-distribution with 26 degrees of freedom

t-distribution with 23 degrees of freedom

normal distribution

t-distribution with 24 degrees of freedom

Answers

Answer:

Step-by-step explanation:

The confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of low-tech industry

x2 = sample mean of consumer products industry

s1 = sample standard deviation low-tech industry

s2 = sample standard deviation for consumer products industry

n1 = number of samples of low-tech industry

n2 = number of samples of consumer products industry

a) x1 - x2 is the point estimate of the difference between the means of the two populations

Therefore,

Point estimate = 157 - 218 = - 61

b) the formula for standard error is expressed as

√(s1²/n1 + s2²/n2)

Variance = standard deviation²(s²)

s1² = 1563

s2² = 1602

Standard error = √(1563²/14 + 1602²/12) = 623.2

c) Degree of freedom =

(n1 - 1) + (n2 - 1) = (14 - 1) + (12 - 1) = 24

t-distribution with 24 degrees of freedom

According to the data given, we have that:

a) 61

b) 15.65

c) t-distribution with 24 degrees of freedom

Item a:

The point estimate is the difference between the two sample means, hence:

218 - 157 = 61.

Item b:

For each sample, the standard errors are:

[tex]s_l = \sqrt{\frac{1563}{14}} = 10.57[/tex]

[tex]s_h = \sqrt{\frac{1602}{12}} = 11.54[/tex]

For the difference of the two means, it is:

[tex]s = \sqrt{s_l^2 + s_h^2} = \sqrt{10.57^2 + 11.54^2} = 15.65[/tex]

Item c:

Samples of 14 and 12, hence 14 + 12 - 2 = 24 df.

A similar problem is given at https://brainly.com/question/12490448

What’s the correct answer for this question? Select all that Apply

Answers

Answer:

B and G

Step-by-step explanation:

Square and rectangle

In ABC, mA = 46, mB = 105, and c = 19.8. Find a to the nearest tenth.

Answers

Answer:

a = 29.3785

Step-by-step explanation:

Given ∠A = 46° and ∠B = 105°

we know that ∠A +∠B+∠C = 180°

                       46° + 105° +∠C = 180°

                      ∠C = 180 - 46 -105

                     ∠ C = 29°

By using sine rule

[tex]\frac{a}{sin A} = \frac{b}{Sin B} = \frac{c}{Sin C} = 2 R[/tex]

[tex]\frac{a}{sin A} = \frac{c}{Sin C}[/tex]

Given ∠A = 46° and  ∠ C = 29° and c = 19.8

[tex]\frac{a}{sin 46} = \frac{19.8}{Sin 29}[/tex]

on cross multiplication , we get

[tex]a = \frac{19.8 X sin 46}{Sin 29}[/tex]

a = 29.3785

A group of professors investigated​ first-year college​ students' knowledge of astronomy. One concept of interest was the Big Bang theory of the creation of the universe. In a sample of 149149 freshmen​ students, 3232 believed that the Big Bang theory accurately described the creation of planetary systems. Based on this​ information, is it correct at the alphaαequals=0.100.10 level of significance to state that more than​ 20% of all freshmen college students believe the Big Bang theory describes the creation of planetary​ systems? State the null and alternative hypotheses. Choos

Answers

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

A group of professors investigated first-year college students' knowledge of astronomy. One concept of interest was the Big Bang theory of the creation of the universe. In a sample of 149 freshmen students, 32 believed that the Big Bang theory accurately described the creation of planetary systems. Based on this information, is it correct at the alpha = 0.01 level of significance to state that more than 20% of all freshmen college students believe the Big Bang theory describes the creation of planetary systems? State the null and alternative hypotheses. Choose the correct answer below. H_0: p = 0.20 H_a: p not equal to 0.20 H_0: p not equal to 0.20 H_a: p = 0.20 H_0: p = 0.20 H_a: p 0.20 If alpha = 0.05, find the rejection region for the test. Choose the correct answer below. z > 1.645 z > 1.96 z

Solution:

We would set up the null and alternative hypothesis. The correct options are

For null hypothesis,

p ≥ 0.2

For alternative hypothesis,

p < 0.2

This is a left tailed test.

Considering the population proportion, probability of success, p = 0.2

q = probability of failure = 1 - p

q = 1 - 0.2 = 0.8

Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 32

n = number of samples = 149

P = 32/149 = 0.21

We would determine the test statistic which is the z score

z = (P - p)/√pq/n

z = (0.21 - 0.2)/√(0.2 × 0.8)/149 = 0.31

The calculated test statistic is 0.31 for the right tail and - 0.31 for the left tail

Since α = 0.05, the critical value is determined from the normal distribution table.

For the left, α/2 = 0.05/2 = 0.025

The z score for an area to the left of 0.025 is - 1.96

For the right, α/2 = 1 - 0.025 = 0.975

The z score for an area to the right of 0.975 is 1.96

In order to reject the null hypothesis, the test statistic must be smaller than - 1.96 or greater than 1.96

Therefore, the rejection region is z > 1.96

The market and Stock J have the following probability distributions:
Probability rM rJ
0.3 14% 22%
0.4 10 4
0.3 19 12
1. Calculate the expected rate of return for the market. Round your answer to two decimal places.%
2. Calculate the expected rate of return for Stock J. Round your answer to two decimal places.%
3. Calculate the standard deviation for the market. Round your answer to two decimal places.%
4. Calculate the standard deviation for Stock J. Round your answer to two decimal places.%

Answers

Answer:

1) [tex] E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%[/tex]

2) [tex]E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%[/tex]

3) [tex] E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1 [/tex]

And the variance would be given by:

[tex]Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89[/tex]

And the deviation would be:

[tex] Sd(M) = \sqrt{13.89}= 3.73[/tex]

4) [tex] E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8 [/tex]

And the variance would be given by:

[tex]Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56[/tex]

And the deviation would be:

[tex] Sd(M) = \sqrt{55.56}= 7.45[/tex]

Step-by-step explanation:

For this case we have the following distributions given:

Probability  M   J

0.3           14%  22%

0.4           10%    4%

0.3           19%    12%

Part 1

The expected value is given by this formula:

[tex] E(X)=\sum_{i=1}^n X_i P(X_i)[/tex]

And replacing we got:

[tex] E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%[/tex]

Part 2

[tex]E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%[/tex]

Part 3

We can calculate the second moment first with the following formula:

[tex] E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1 [/tex]

And the variance would be given by:

[tex]Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89[/tex]

And the deviation would be:

[tex] Sd(M) = \sqrt{13.89}= 3.73[/tex]

Part 4

We can calculate the second moment first with the following formula:

[tex] E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8 [/tex]

And the variance would be given by:

[tex]Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56[/tex]

And the deviation would be:

[tex] Sd(M) = \sqrt{55.56}= 7.45[/tex]

Please answer this correctly

Answers

Answer:

50 inches

Step-by-step explanation:

Since the formula for the area of a triangle is bh/2, where b is the base and h is the height, you can set up the following equation:

30b/2=750

30b=1500

b=1500/30=50

Hope this helps!

The right answer is 50 inches.

Please see the attached picture for full solution

Hope it helps...

good luck on your assignment..

The following data show the brand, price , and the overall score for stereo headphones that were tested by Consumer Reports. The overall score is based on sound quality and effectiveness of ambient noise reduction. Scores range from (lowest) to (highest). The estimated regression equation for these data is = 23.194 + 0.318x, where x = price ($) and y = overall score.

Brand Price Score
Bose 180 76
Scullcandy 150 71
Koss 95 62
Phillips/O'Neill 70 57
Denon 70 30
JVC 35 34

Required:
a. Compute SST, SSR, and SSE (to 3 decimals).
b. Compute the coefficient of determination r2.
c. What is the value of the sample correlation coefficient?

Answers

Answer:

a. SST = 1816

SSR = 1511.804

SSE = 465.804

b. Coefficient of determination, R² = 0.832491079

c. The correlation coefficient r = 0.8636

Step-by-step explanation:

y = 23.194 + 0.318·x

Where:

x = Price

y = Overall score

The observed data are given as follows;

Brand                Price  Score

Bose                 180     76

Scullcandy       150      71

Koss                 95       62

Phillips/O'Neill 70       57

Denon              70       30

JVC                   35       34

[tex]SST = \sum \left (y - \bar{y} \right )^{2}[/tex]= 1816

[tex]SSR = \sum \left ({y}'-\bar{y{}'} \right )^{2}[/tex] = 1511.804

[tex]SSE = \sum \left (y - {y}' \right )^{2}[/tex] = 465.804

Coefficient of determination

[tex]Coefficient \, of \, determination = \dfrac{SSR}{SST}[/tex]= 0.832

Coefficient of correlation =

[tex]r = \dfrac{n\left (\sum xy \right )-\left (\sum x \right )\left (\sum y \right )}{\sqrt{\left [n\sum x^{2}-\left (\sum x \right )^{2} \right ]\left [n\sum y^{2}-\left (\sum y \right )^{2} \right ]}}[/tex]

Ʃxy  = 37500

Ʃx =600

Ʃy = 330

Ʃx² = 74950

Ʃy²  = 19966

[tex]r = \dfrac{6 \left (37500 \right )-\left (600 \right )\left (330 \right )}{\sqrt{\left [6\times 74950-\left (600 \right )^{2} \right ]\left [6 \times 19966-\left (330 \right )^{2} \right ]}} = 0.8636[/tex]

find the perimeter of this figure to the nearest hundredth use 3.14 to approximate pi P=?ft

Answers

Answer:

105.13ft^2

Step-by-step explanation:

[tex]A=lw\\=10*8\\=80ft^2[/tex]

Rectangle

[tex]A=\frac{1}{2} \pi r^2\\=\frac{1}{2\pi } 4^2\\=25.13[/tex]

Add both together

80+25.13

=105.13

Answer :  105.13

Step-by-step explanation:

Bob is a travel agent. He receives 7% commission when he books a cruise for a customer. How much commission will he receive for booking a $3,900 cruise?

Answers

Answer:

$273

Step-by-step explanation:

$3900= 100%

$39 = 1%

39(1%)*7= $273 (7%)

The commission will he received should be $273

Given that,

He receives 7% commission when he books a cruise for a customer

calculation:

= 7% of $3,900

= $273

Find out more information about percentage here:

https://brainly.com/question/26080842?referrer=searchResults

Determine whether the value is a discrete random​ variable, continuous random​ variable, or not a random variable. a. The number of points scored during a basketball game b. The number of free dash throw attempts before the first shot is made c. The response to the survey question "Did you smoke in the last week question mark " d. The number of people in a restaurant that has a capacity of 150 e. The time it takes for a light bulb to burn out f. The height of a randomly selected giraffe a. Is the number of points scored during a basketball game a discrete random​ variable, a continuous random​ variable, or not a random​ variable?

Answers

Answer:

a. Discrete random variable

b. Discrete random variable

c. Discrete random variable

d. Discrete random variable

e. Continous random variable

f. Continous random variable

Step-by-step explanation:

a. The number of points scored during a basketball game.

This is a random variable, that only takes integer values, so it is a discrete random variable.

b. The number of free dash throw attempts before the first shot is made.

This is a count, so it is a discrete random variable.

c. The response to the survey question "Did you smoke in the last week question mark".

This is a boolean random variable (only two values), and can be considered discrete.

d. The number of people in a restaurant that has a capacity of 150.

This is a count of people, so it is a discrete random variable.

e. The time it takes for a light bulb to burn out.

Time is continous, so it is a continous random variable.

f. The height of a randomly selected giraffe.

Height, as it is a distance, is also a continous variable, so it is a continous random variable.

What is the value of X ?

Answers

Answer:

D

Step-by-step explanation:

2² + 6² = x²

4 + 36 = x²

40 = x²

x = 2√10

Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.

sin(θ) =

cos(θ) =

tan(θ) =

csc(θ) =

sec(θ) =
✔ 17/8

cot(θ) =
✔ -8/15
i have only gotten the last two right and i need help with the others.

Answers

Answer:

cos =1/ sec

=8/17

tan =1/cot

= -15/8

sin = 15/17 or -15/17

cosec = 1/ sin

= 17/15 or -17/15

Answer:

Did the same assignment. lol can see how that went but here's the answers. hope it helps.

WILL GIVE BRAINLIST On a coordinate plane, 2 quadrilaterals are shown. The first figure has points A (negative 2, 1), B (negative 4, 1), C (negative 4, 5), and D (negative 2, 4). Figure 2 has points A prime (2, 1), B prime (4, 1), C prime (4, 5), and D prime (2, 4). What is the rule for the reflection? rx-axis(x, y) → (–x, y) ry-axis(x, y) → (–x, y) rx-axis(x, y) → (x, –y) ry-axis(x, y) → (x, –y)

Answers

The rule of reflection is ry-axis (x , y) → (-x , y)

Answer:

B) ry-axis(x, y) → (–x, y)

Step-by-step explanation:

Got it right on edge2020 you can trust me :D

Write an
explicit formula for
ans
the nth
term of the sequence 20, -10,5, ....

Answers

Answer:an=20(-1/2)^n-1

Step-by-step explanation:

M5-3/2x less than or equal to 1/3

Answers

Answer: choice A

Step-by-step explanation:

by rearranging the initial inequality you’ll get

[tex]\frac{3}{2} x\leq 5-\frac{1}{3}[/tex]

which equals

[tex]\frac{3}{2} x\leq\frac{14}{3}[/tex]

then multiply both sides by 2/3

[tex]x\leq \frac{28}{9}[/tex]

Factorise fully for this

Answers

Answer:

i hope this will help you

Step-by-step explanation:

-9t²v+3tv²

=-3tv(3t-v)

Answer:

[tex]- 3tv(3t - v) \\ [/tex]

Step-by-step explanation:

[tex] - 9 {t}^{2} v + 3t {v}^{2} \\ = - 3tv(3t - v)[/tex]

hope this helps you

brainliest appreciated

good luck! have a nice day!

Jodie Meeks's Free Throws During the 2015-16 NBA season, Jodie Meeks of the Detroit Pistons had a free throw shooting percentage of 0.906 . Assume that the probability Jodie Meeks makes any given free throw is fixed at 0.906 , and that free throws are independent.If Jodie Meeks shoots 6 free throws in a game, what is the probability that he makes at least 5 of them?

Answers

Answer:

0.8973

Step-by-step explanation:

Relevant data provided in the question as per the question below:

Free throw shooting percentage = 0.906

Free throws = 6

At least = 5

Based on the above information, the probability is

Let us assume the X signifies the number of free throws

So,  Then X ≈ Bin (n = 6, p = 0.906)

[tex]P = (X = x) = $\sum\limits_{x}^6 (0.906)^x (1 - 0.906)^{6-x}, x = 0,1,2,3,.., 6[/tex]

Now

The Required probability = P(X ≥ 5) = P(X = 5) + P(X = 6)

[tex]= $\sum\limits_{5}^6 (0.906)^5 (1 - 0.906)^{6-5} + $\sum\limits_{6}^6 (0.906)^6 (1 - 0.906)^{6-6}[/tex]

= 0.8973

need help in b and c. show calculation pls.​

Answers

√(16 - x^2) is defined only for -4 ≤ x ≤ 4, and is continuous over this domain, so

[tex]\displaystyle\lim_{x\to-4^+}\sqrt{16-x^2}=\sqrt{16-(-4)^2}=0[/tex]

From the other side, the limit does not exist, because all x < -4 do not belong to the domain.

Taken together, the two-sided limit also does not exist.

Na figura abaixo estão representadas cinco ruas do bairro onde moram João, Marcos, Pedro, Vitor e Samuel. A localização da casa de cada menino é identificada pela inicial de seu nome. Na esquina das ruas A e D fica a escola onde todos estudam. Sabe-se que as ruas A, B e C são paralelas e que todos os meninos vão a pé para a escola, sempre pelo caminho mais curto. Se Samuel caminha 100 m até a escola, Vitor caminha 260 m, João caminha 180 m e Marcos, 270 m, qual é a distância, em metros, que Pedro percorre de sua casa até a escola?


280m
300m
340m
460m
320m

Answers

Answer:

340 m  

Step-by-step explanation:

Assume the figure looks like the one below.

We have three parallel lines cut by two transversals.

1. Lengths of segments

(a) Segment VS

If Vitor walks 260 m,  

VS + SE = 260

VS + 100 = 260

VS = 260 - 100 = 160 m

(b) Segment MJ

If Marcos walks 270 m,  

MJ + JE = 270

VS + 180 = 270

VS = 270 - 180 = 90 m

(c) Segment PV

The segments on the transversals are proportional.

[tex]\begin{array}{rcl}\dfrac{x}{90} & = & \dfrac{160}{180} \\\\x & = & 90 \times \left (\dfrac{160}{180}\right )\\\\& = &\textbf{80 m}\\\end{array}\\\textbf{PV = 80 m}[/tex]

2. Distance travelled by Pedro

Distance = PV + VS + SE = 80 m + 160 m + 100 m = 340 m

Pedro walks 340 m to school.

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