A rock is thrown vertically upwards at a velocity of 11 meters per second from an initial height of 1.5 meters.

Considering “up” to be the positive y direction, answer the following questions:


How high above the ground does the rock go?

How long does it take to get to the top of its travel?

What is the velocity of the rock half of a second after it is released?

What is the velocity of the rock 1.5 seconds after release?

Answer:

see below

Explanation:

1 139 m / 37 s = 30.784 m/s   South

Answer: F=400 N

Explanation:

F=ma ==> F=force, m=mass, a=acceleration

F=100*4

F=400 N

In each case, 0.5N  of force in a downward direction

No matter which way an object is moving, gravity's acceleration always works downward. In all three scenarios, the stone is just subject to the gravitational pull. According to Newton's second rule of motion, its magnitude is as follows:

Force=ma

Where, m is a mass of the pebble and a is acceleration due to gravity

F = Net force.

M = 0.05 kg of pebble mass

a=g=10m/s^2 F=0.05 × 10=0.5N

In all three scenarios, there is a downward-moving net force of 0.5N acting on the stone.

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The calculated answer is 320 cm/s.

The wave diagram is attached below.

The quantity of waves that pass a set location in a predetermined period of time is known as frequency. Therefore, if a wave passes through in half a second, the frequency is 2 per second. The frequency is 100 times per hour if it takes 1/100 of an hour. Even though the concept of frequency as it is commonly understood is based on events per second, other units of time, like minutes or hours, may also be employed.

For a wave with the equation y=Acos(kx)t,

k= 2 = 40cm² =0.157rad/cm,

v=28=50.3rad/s,

T= 1/ = 1/8Hz 

=0.125s.

Wave speed = k = 0.157*50.3

= 320 cm/s

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The tendency of an atom to attract electrons (or electron density) to itself is measured by its electronegativity. It determines the distribution of the shared electrons between the two atoms in a bond. The stronger an atom's electronegativity, the more strongly it would attract electrons to its bonds.

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Explanation:

[tex]{ \rm{ \vec{B}} = \frac{ \mu_{0}N}{l} } \\ [/tex]

N is number of turns

l is conductor length

mu_0 is permeability

[tex]{ \boxed{ \tt{ \mu_{0} = 4\pi \times {10}^{ - 7} }}}[/tex]

#include <stdio.h>

int main()

{

const int LENGTH = 10;

const int WIDTH = 5;

const char NEWLINE = '\n';

int area;

area = LENGTH * WIDTH;

printf("value of area : %d", area);

printf("%c", NEWLINE);

return 0;

}

Answer:

3ft/s²

Explanation:

[tex]a = \frac{60 - 45}{5} = 3ft \div {s}^{2} [/tex]

Answer:

okay

Explanation:

why don't you have any question in this app?

The two actions that the driver could take would be to (a) Push down on the accelerator and then (b) push down on the brakes, therefore the correct answer is option D.

The total displacement covered by any object per unit of time is known as velocity.

When the driver pushes down on the accelerator the velocity and the acceleration would be in the same direction.

When he pushes down on the brakes the acceleration vector would point in the opposite that of velocity, therefore the correct answer is option D.

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The distance traveled in meters is 290m. It can be solved using Newton's Laws of motion.

You can solve this problem by using the formula of

d = 1/2 a t^2

where d is the distance traveled in meters,

a = 20 m/s², and t =7 seconds

Plug-in the data to the formula and solve for the distance traveled after

7 s.

d = 1/2 a t^2

=1/2 × 20 × 7²

= 290m

Hence the dist travelled by the car is 290m

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The displacement of the victorious snail will be 336.0mm .

The term displacement refers to a change in an object's position. It is a vector quantity and has a direction and magnitude .

We are given here,

Average velocity of snail = Δv = 2.4 mm/s

Time interval taken by snail = Δt = 140 s

The average velocity can be define as, the rate of change in displacement in the particular time interval of the object. The formula can be given as,

Δv =  Δx / Δt

Where,  Δv is the average velocity, Δx is the change in displacement,  Δt is the time interval of an object. Unit can be written as meter/second.

Therefore, the displacement of snail during the race can be calculated by the relation i.e.

Δx =  Δv ×  Δt

Thus , putting the values in above equation we get,

Δx = 2.4mm/s × 140s  

Δx = 336.0 mm

Hence,  the snail would move 336.0 mm in 140s.

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A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate water.

Given the flow of current and the voltage, the resistance of the lamp is 80 Ohms.

Ohm’s law states that the potential difference between two points is directly proportional to the current flowing through the resistance.

V = IR

Where V is the voltage or potential difference, I is the current and R is the resistance.

Given the data in the question;

Plug the given values into the equation above and solve for R.

V = IR

120 = 1.5 × R

R = 120/1.5

R = 80Ω

Given the flow of current and the voltage, the resistance of the lamp is 80 Ohms.

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Answer:

80 is the answer

Explanation:

The time of motion of the coin is determined as t = √(0.204x).

The time of motion of an object or a projectile is the time taken for the objects to travel from its initial position to the final position.

The time taken for the coin to fall from the given height "x" is calculated as follows;

h = vt + ¹/₂gt²

where;

x = 0 + ¹/₂gt²

2x = gt²

t² = 2x/g

t = √(2x/g)

t = √(2x/9.8)

t = √(0.204x)

Thus, the time of motion of the coin is determined as t = √(0.204x)

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Answer:

Time difference = T1-T2 = D1/V1-D2/V2 = D ( 1/V1-1/V2)

Time difference = 5.5 min = 5.5*60=330 sec, V1 = .09 m/s, V2= 1.9 m/s

330 = D (1/.9 – 1/1.9)

330= D(1.11-.5263)

330=D(.585)

D= 330/.585 = 564.3 m

Explanation:

Answer:

The direction of the velocity vector is upward and the direction of the acceleration vector is downward. A ball thrown straight upward moves initially with a decreasing upward velocity.

Explanation:

Answer: ill do deeper reaseach because thats hard

Explanation:

John Deere, a U.S. company, sells a tractor to a farmer in Canada. It is a  GDP category is net exports.

Farmers are the person who usually cultivates and grows crops. They often also have cattle farming also. These farmers earn money by selling the crops in the market.

As a person is exporting goods and services to the US market, then we can say that the person is an exporter of court. There is GDP which is gross domestic product the US company that sells the status to Canada will be termed as the net exporter and represented over in that category.

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the final horizontal velocity of the soccer ball is 16.53 (m/s)

Typically, horizontal velocity is defined as horizontal displacement divided by time, expressed in units like meters per second or miles per hour. Simply put, displacement is the separation of a thing from its origin. V stands for the needed soccer ball's initial horizontal velocity (in m/s). T stands for the soccer ball's time of flight, expressed in seconds. The kinematic relations that result from the data given are as follows:

22 = 0 + (1/2) *g*T^2 [g = acceleration due to gravity]

or T^2 = 44/g

or T = √(44/g)

35 = V*T

or V = 35/T

or V = 35*√(g/44)

or V = 35*√ (9.81/44) (Assumed) g = 9.81 m/s2

V = 16.53 (m/s)

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Answer:

Approximately [tex]10410\; {\rm N}[/tex] (assuming that [tex]g = 9.81\; {\rm m \cdot s^{-2}}[/tex].)

Explanation:

There are two forces on this car:

The net force on this car would be:

[tex](\text{net force}) = (\text{tension}) - (\text{weight})[/tex].

Rearrange to obtain:

[tex](\text{tension}) &= (\text{net force}) + (\text{weight})[/tex].

Let the mass of this car be [tex]m[/tex]. The weight of the car would be [tex]m\, g[/tex].

If the acceleration of the car is [tex]a[/tex], the net force on this car would be [tex]m\, a[/tex].

Thus:

[tex]\begin{aligned}(\text{tension}) &= (\text{net force}) + (\text{weight}) \\ &= m\, a + m\, g \\ &= (m)\, (a + g) \\ &= (1000\; {\rm kg}) \, (0.60\; {\rm m \cdot s^{-2}} + 9.81\; {\rm m\cdot s^{-2}}) \\ &\approx 10410\; {\rm N}\end{aligned}[/tex].

The amount of velocity does the man who standing on a frictionless ice surface move across the ice(V)= 1 m/s in the opposite direction as the book.

Velocity of a particle is its speed and the direction in which it is moving.

It can also be described as the instantaneous rate of change of the particle's distance traveled.

To calculate the velocity we would be using the formula,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Here we are given that,

Apply the law of linear momentum

Before the throw:

M₁=Man initial mass= 80kg,

U₁=Man's initial velocity = 0,

M₂=Book  initial mass = 4kg,

U₂=Book's initial velocity = 0.

After the throw:

M₁=Man final mass = 80kg,

V₁=Man's final velocity = V.

M₂=Book final mass = 4kg,

V₂=Book final velocity = 20.

Now we put the values in the formula, we get,

M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂

Or, (80x0) + (4x0) = (80V) + (4x20)

Or, 0=80V + 80

Or, 80V = -80

Or, V = -80/80

Or, V= -1m/s.

From the above calculation we can conclude that,

The amount of velocity does the man move across the ice(V)= 1 m/s in the opposite direction as the book

[Note: The (-)Ve sign shows that the opposite direction]

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the current through each branch of the circuit and the potential difference across 12-ohm resistance is 0.711A

The flow of charge is the current. A component is used to measure current. Potential difference is measured between two points on either side of a component because it represents the energy transferred between two points in a circuit.

-12(I1+I2) -1I1+7=0

12(I1+I2) +1I1=7

For the loop

-12(I1+I2) -2I=13

From 1&2

2I -I1=13-7=6

I1=2I2-6

The crucial distinction between current and voltage. Current in the circuit flows due to voltage, which is the potential difference between two locations in an electric field. The term "current" refers to the rate at which electrons are moving.

I2=85/38=2.237A

I1=2I 2-6

I1=2 x 85/38-6=-1.526A

I=I1+I2=-1.526+2.237=0.711A

Potential difference across 12-ohm resistance

V=0.711 x 12=8.53 v

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The x and y component of the dog's velocity at  t₂ = 25.0 s is 7.53 m/s and 2.933 m/s respectively.

The magnitude of the dog's velocity is 8.076 m/s.

The velocity components of a dog running in an open field are:

[tex]v_{x}=2.8 {~}m/s\\v_{y}=-1.8{~}m/s[/tex] at t₁ = 12 sec.

The average acceleration of the dog in the time interval t₁ = 12 sec to t₂ = 25 sec is 0.45 m/s² and the direction 36°.

(A) The x component of the dog velocity at t₂ = 25 sec will be:

Vₓ = vₓ + aₓ(cos(36)) × (t)

Vₓ = 2.8 + ( 0.45) × (0.89) × ( 25 - 12 )

Vₓ = 2.8 + 4.7327

Vₓ = 7.53 m/s

(B) The y component of the dog's velocity at t₂ = 25 sec will be:

[tex]V_y=v_y+a_y(cos(\theta))t\\V_y=-1.8+(0.45)(cos(36))(25-12)\\V_y=-1.8+4.7327\\V_y=2.933{~}m/s[/tex]

(C) Therefore, the magnitude of the dog's velocity is:

[tex]V=\sqrt{(v_x)^{2}+(v_y)^{2}}\\V=\sqrt{(7.53)^{2}+(2.93)^{2}}\\ V=\sqrt{56.7+8.58}\\ V=\sqrt{65.28}\\ V=8.0796{~}m/s[/tex]

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The complete question is mentioned below:

A dog running in an open field has components of velocity vₓ = 2.8 m/s and [tex]v_y = -1.8{~} m/s[/tex] at time t₁ = 12.0 s. For the time interval from t₁ = 12.0 s to t₂ = 25.0 s, the average acceleration of the dog has a magnitude of 0.45 m/s² and a direction of 36.0° measured from the +x-axis toward the +y-axis.

(A) At time t₂ = 25.0 s, what is the x-component of the dog's velocity?

(B) At time t₂ = 25.0 s, what is the y-component of the dog's velocity?

(C) What is the magnitude of the dog's velocity?

Answer:

0

Explanation:

it takes 84 years for Uranus to orbit the Sun. It only takes 12 years for Jupiter to orbit the Sun. So technically by the time that Jupiter finishes it's one, Uranus will not be able to even finish half of its orbit.

He can increase the range of the ball covers during the throw by throwing the ball with a greater horizontal velocity

Assuming a projectile is launched from the ground level, the range is defined as the distance between the launch point and the point where the projectile hits the ground.

Range = [tex]u^{2}[/tex] sin (2 (theta )) / g

u = initial horizontal velocity

g= acceleration due to gravity

theta = angle of velocity vector with the ground

since , initial horizontal velocity is directly proportional to the range

hence , if we increase horizontal velocity range of the projectile will also increase .

hence , correct option is d) He could throw the ball with a greater horizontal velocity

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The height reached by the ball is 78.4 m.

Height can be defined as the vertical distance between two points.

To calculate the height reached by  the ball, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the height reached by the ball is 78.4 m.

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