A skydiver is using wind to land on a target that is 120 m away horizontally. The skydiver starts from a height of 70 m and is falling vertically at a constant velocity of 7.0 m/s downward with their parachute open (terminal velocity). A horizontal gust of wind helps push them towards the target. What must be their total speed if they want to just hit their target

Answers

Answer 1

Answer:

13.9 m/s.

Explanation:

Since the vertical velocity of the skydiver is constant at v = 7.0 m/s, we find the time, t it takes him to drop from a height of h = 70 m.

So, distance = velocity time

h = vt

t = h/v = 70 m/7 m/s = 10 s

This is also the time it takes him to move horizontally a distance of d = 120 m to the target.

So, his horizontal velocity is v' = distance/time = d/t = 120m/10 s = 12 m/s.

Since both vertical and horizontal velocities are perpendicular, we add them vectorially to obtain the skydivers total speed, V.

So, V = √(v² + v'²)

= √((7.0 m/s)² + (12.0 m/s)'²)

= √(49 m²/s² + 144 m²/s²)

= √(193 m²/s²)

= 13.9 m/s.

The direction of this velocity is Ф = tan⁻¹(v/v')

= tan⁻¹(7 m/s/12 m/s)

= tan⁻¹(0.5833)

= 30.3°


Related Questions

What makes electromagnets useful for sorting metals in recycling centers?
O A. The current can be turned on to pick up items containing all
metals and turned off to drop them.
O B. The current can be turned off to pick up items containing all
metals and turned off to drop them.
O C. The current can be turned on to pick up items containing iron and
turned off to drop them.
D. The current can be turned off to pick up items containing iron and
turned on to drop them.

Answers

it’s c sorry if i’m wrong

C

It is right because I took this and I got this answer correct

A car accelerates from zero to a speed of 110
km/hr in 15 seconds. What is the car's rate of
acceleration?

Answers

The car's rate of  acceleration : a = 2.04 m/s²

Further explanation

Given

speed = 110 km/hr

time = 15 s

Required

The acceleration

Solution

110 km/hr⇒30.56 m/s

Acceleration is the change in velocity over time

a = Δv : Δt

Input the value :

a = 30.56 m/s : 15 s

a = 2.04 m/s²

a. Use the graph and the element made in question 2 to determine the mass of the star.

Answers

Black balls with blue waffles

A certain brand of hotdog cooker works by applying a potential difference of 144 V across opposite ends of a hot dog and allowing it to cook by means of the thermal energy produced. The current is 10.5 A, and the energy required to cook one hot dog is 60.6 kJ. If the rate at which energy is supplied is unchanged, how long will it take to cook three hot dogs simultaneously

Answers

Answer:

120.237 seconds

Explanation:

Given that:

V = 144 V

I = 10.5 A

H = 60.6 kJ

Using the formula:

H = I²RT

From H = I²RT; making T the subject, we have:

[tex]T = \dfrac{H}{I^2R}[/tex]

where;

[tex]R = \dfrac{V}{I}[/tex]

[tex]T = \dfrac{H}{V \times I}[/tex]

[tex]T = \dfrac{60.6 \times 10^3 }{144 \times 10.5}[/tex]

T = 40.079

[tex]T_{neq} = 3T[/tex]

[tex]T_{neq} =3 \times 40.079[/tex]

[tex]\mathbf{T_{neq} =120.237 \ sec}[/tex]

Question 18 of 25
Which type of reaction is shown in this energy diagram?
Energy
Products
Activation
Energy
Reoctants
to
ti
Time
A. Endothermic, because the products are lower in energy
B. Exothermic, because the reactants are lower in energy
C. Endothermic, because the reactants are lower in energy
D. Exothermic, because the products are lower in energy

Answers

Answer:

Endothermic, because the reactants are lower in energy (C)

Explanation:

From the graph, you can see the energy of the products is higher than the energy of the reactants. If you recall that  when the enthalpy change  Eproducts is gretater than  Ereactants, the reaction is said to be endothermic.

What simple machine can best be described as "a simple machine that uses an inclined plane wrapped around a rod"?

a wedge
a screw
a wheel and axle
a lever

Answers

A screw I think I’m sorry if you get it wrong

Answer:

It is a screw.

Explanation:

A body moves on a coordinate line such that it has a position sequals​f(t)equalstsquaredminus4tplus3on the interval 0less than or equalstless than or equals7​,with s in meters and t in seconds.a. Find the​ body's displacement and average velocity for the given time interval.b. Find the​ body's speed and acceleration at the endpoints of the interval.c.​ When, if​ ever, during the interval does the body change​ direction?

Answers

Answer:

A)  Δf = - 49 m, B)  v (7)  = -56 m / s, a = - 8 m / s², C)  t = 0.866 s

Explanation:

A) In this exercise ask to find the displacement and the average velocity, give the function of the movement

           f (t) = - 4t² +3

and the range of motion 0≤ t ≤ 7

the displacement is

for t = 0

           f (0) = 3

for t = 7 s

           f (7) = - 4 7² +3

           f (7) = -46 m

the total displacement is

           Δf = f (7) - f (0)

           Δf = -46 - 3

            Δf = - 49 m

the average speed is defined as the displacement between the time interval

           v = Df / Dt

           v = -49 / 7

           v = - 7 m / s

B) the speed and acceleration of the end points of the motion

         

the speed of defined by

          v = [tex]\frac{dx}{dt}[/tex]

in this case

         v = [tex]\frac{df}{dt}[/tex]

         v = -8t

         

let's calculate

          v (7) = -8 7

          v (7)  = -56 m / s

acceleration is defined by

          a = [tex]\frac{dv}{dt}[/tex]

          a = - 8 m / s²

acceleration is constant throughout the movement

C) the point where the direction changes.

This point is a point where the position goes from positive to negative, the point f = 0

        0 = -4t² +3

        t = √¾

        t = 0.866 s

Thomas knows that many machines transform electrical energy into other forms of energy

Answers

Question:-
So? Gd for him though

Answer:

Only the car transforms electrical energy into more than one form of energy.

Explanation:

The motion of the car is mechanical energy but it can also transform into another energy witch is electrical energy

A plane wishes to fly due north to an airport which is 205 km away. The plane can fly at a speed in still air of 220 km/h. A wind of 43 km/h blows from east to west.


a. In which direction,relative to north, should the plane head to reach it’s destination?

b. How long does this take?

Answers

Answer:

nique ta mama  

Explanation:

Q4. What is the speed of light in a block of glass that
has an Index of refraction of 1.11?

Answers

Refractive index(n)= speed of light in vacuum/ speed of light in medium.
Since refractive index is 1.11, and usually we know that the speed of light is 300,000km/s, simply divide 300,000km/s over 1.11. That is, 270,270.2703 when simply rounding, its 270,270 km/s.

2. A force of 10 N is applied to an object which accelerates at a rate of 2m/s2. What is the mass
of the object?
(10 Points)
10 kg
5 kg
2 kg
20 kg

Answers

5 kg because to find mass you’re going to divide force by acceleration 10/2 is 5

A 10,000 g body falls from a height of 20 m. Calculate the potential energy when it is at a height of 10 m

Answers

Answer:

Ep = 980 J

Explanation:

First, grams must be converted to kilograms. So, we must divide the value of the mass, by 1000.

[tex]\boxed{\frac{10000}{1000}=\boxed{10kg}}[/tex] ---------- Converted to kg.

==================================================================

Data:

Mass (m) = 10 kgGravity (g) = 9.8 m/s²Height (h) = 10 mPotential Energy (Ep) = ?

Use formula:

Ep = m * g * h

Replace:

Ep = 10 kg * 9.8 m/s² * 10 m

Multiply operations, with units:

Ep = 980 J

What is the potential energy?

The potential energy is 980 Joules.

You are walking on a moving walkway in the airport. The length of the walkway is 59.1 m. If your velocity relative to the walkway is 2.35 m/s, and the walkway moves with a velocity of 1.85 m/s, how long will it take you to reach the other end of the walkway

Answers

Answer:

14.1seconds approx

Explanation:

Given data

Distance= 59.1m

Your velocity= 2.35m/s

Walkway velocity= 1.85m/s

Total velocity= 2.35+1.85= 4.2m/s

We know that

Velocity= distance/time

time= distance/velocity

substitute

time= 59.1/4.2

time= 14.07

time=14.1seconds approx

Hence the time is 14.1seconds approx

how can you decrease the numbers
of calories you consume

Answers

Answer: by eating less of the recommendEd servings

Explanation:

Eating less or eating healthy

what are the precautions to be taken while performing a rectangular glass prism experiment​

Answers

Answer:

PRECAUTIONS

-The refracting faces of the glass prism should be smooth, transparent and without any air bubble or broken edge. ...

-Use a sharp pencil to draw boundary of the prism and rays of light.

-The alpins should have sharp tip and should be fixed exactly vertical to the plane of the paper.

Explanation:

Please give thanks to all my answers and please mark as brilliant and please follow me

A spacecraft and a staellite are at diametrically opposite position in the same circular orbit of altitude 500 km above the earth. As it passes through point A, the spacecraft fires its engine for a short interval of time to increase its speed and enter an elliptical orbit. Knowing that the spacecraft returns to A at the same time the satellite reaches A after completing one and a half orbits, determine (a) the increase in speed required, (b) the periodic time for the elliptic orbit

Answers

Answer:

Hello the diagram related to your question is attached below

answer: a) 851 m/s

             b)  8506.1 secs

Explanation:

calculate the periodic time of the satellite using the equation below

t = [tex]\frac{2\pi }{R} \sqrt{\frac{(R+h)^{3} }{g} }[/tex]  --  ( 1 )

where ; R = 6370 km

h = 500 km

g = 9.81 m/s^2

input given values into equation 1

t = 5670.75 secs

next calculate the periodic time taken by the space craft  

a) determine the increase in speed

V = v - [tex]\sqrt{\frac{gR^2}{R + h} }[/tex]  

where ; v = 8463 m/s , R = 6370 km, h = 500 km

V = 851 m/s

b) Determine the periodic time for the elliptic orbit

τ = [tex]\frac{3t}{2}[/tex]

 = [tex]\frac{3*5670.76}{2}[/tex]  =  8506.1 secs

attached below is the remaining part of the detailed solution

A ball is dropped from a building taking 3sec to fall to the ground. Calculate:
Speed ​​when falling to the ground
The height of the building

Answers

Answer:

Vf = 29.4 m/s

h = 44.1 m

Explanation:

Data:

Initial Velocity (Vo) = 0 m/sGravity (g) = 9.8 m/s²Time (t) = 3 sFinal Velocity (Vf) = ?Height (h) = ?

==================================================================

Final Velocity

Use formula:

Vf = g * t

Replace:

Vf = 9.8 m/s² * 3s

Multiply:

Vf = 29.4 m/s

==================================================================

Height

Use formula:

[tex]\boxed{h=\frac{g*(t)^{2}}{2}}[/tex]

Replace:

[tex]\boxed{h=\frac{9.8\frac{m}{s^{2}}*(3s)^{2}}{2}}[/tex]

Multiply time squared:

[tex]\boxed{h=\frac{9.8\frac{m}{s^{2}}*9s^{2}}{2}}[/tex]

Simplify the s², and multiply in the numerator:

[tex]\boxed{h=\frac{88.2m}{2}}[/tex]

It divides:

[tex]\boxed{h=44.1\ m}[/tex]

What is the velocity when falling to the ground?

The final velocity is 29.4 meters per seconds.

How high is the building?

The height of the building is 44.1 meters.

Which type of electromagnetic radiation is most likely to cause sunburn?
A. Ultraviolet
B. Visible light
C. Infrared
D. X-rays

Answers

-The Answer is A Ultraviolet-

Explanation: UVA (Ultraviolet) rays can cause serious damage to your skin.
The answer is Ultraviolet

Help me out please. It’d be greatly appreciated

Answers

Answer:

Option D

2Na + Cl₂ —> 2NaCl

Explanation:

We'll begin by stating the law of conservation of matter.

The law of conservation of matter states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

For an equation to comply with the law of conservation of matter, the number of atoms of each element must be the same on both side of the equation. This simply means that the equation must be balanced!

NOTE: An unbalanced equation simply means matter has been created or destroyed.

Now, we shall determine which equation is balanced. This can be obtained as follow:

For Option A

Na + Cl₂ —> 2NaCl

Reactant:

Na = 1

Cl = 2

Product:

Na = 2

Cl = 2

Thus, the equation is not balanced!

For Option B

2Na + 2Cl₂ —> 2NaCl

Reactant:

Na = 2

Cl = 4

Product:

Na = 2

Cl = 2

Thus, the equation is not balanced!

For Option C

2Na + Cl₂ —> NaCl

Reactant:

Na = 2

Cl = 2

Product:

Na = 1

Cl = 1

Thus, the equation is not balanced!

For Option D

2Na + Cl₂ —> 2NaCl

Reactant:

Na = 2

Cl = 2

Product:

Na = 2

Cl = 2

Thus, the equation is balanced!

From the above illustrations, only option D has a balanced equation. Thus, option D illustrate the law of conservation of matter.

On a scale of 1-10 how much do you care of what people think of you?

Answers

Answer:

3

Explanation:

my family i hope thinks of me.  And I don't have friends for them to think of me.

Iron has a specific heat of o.45 J/g °C. Removing -1.16 E 2 J of energy lowered the temperature of iron from 89 °C to 26.41 °C. What was the mass of the iron?

Answers

Answer:

m = 4.11 grams

Explanation:

Given that,

The specific heat of Iron, c = 0.45 J/g°C

Heat removed, [tex]Q=1.16\times 10^2\ J[/tex]

Initial temperature, [tex]T_i=89^{\circ} C[/tex]

Final temperature, [tex]T_f=26.41^{\circ} C[/tex]

We need to find the mass of the iron. We know that the heat removed in terms of specific heat is given by :

[tex]Q=mc\Delta T\\\\m=\dfrac{Q}{c\Delta T}\\\\m=\dfrac{-1.16\times 10^2}{0.45\times (26.41-89)}\\\\m=4.11\ g[/tex]

So, the mass of the iron is 4.11 grams.

is
5
The specific heat of copper is 0.385 J/g
°C. How much thermal energy is required
to increase the temperature of a 20g
sample of copper from 20°C to 50°C?
Q = m CAT
A 154 )
B 231 )
C 308 )
D 385 )

Answers

Answer:

Required energy Q = 231 J

Explanation:

Given:

Specific heat of copper C = 0.385 J/g°C

Mass m = 20 g

ΔT = (50 - 20)°C = 30 °C

Find:

Required energy

Computation:

Q = mCΔT

Q = 20(0.385)(30)

Required energy Q = 231 J

The planet Mars is host to five functioning spacecraft, three in orbit about the planet and two on the surface of the planet. Thanks to those spacecraft, we know that the planet Mars has a mass that is 0.11 times that of Earth and a radius that is 0.53 times that of Earth. The acceleration of an object in free-fall near the surface of Mars is most nearly what in terms of the local value of g on Earth

Answers

Answer:

0.392

Explanation:

Mm = 0.11Me

Rm = 0.53Re

g = GM / r^2

G = 6.67 * 10^-11

gmars = (G * 0.11Me) / (0.53Re)^2

Recall:

gearth = GMe /Re^2

Hence, gmars in terms of gearth equals

gmars = gearth * (0.11 / 0.53^2)

gmars = gearth * 0.3915984

gmars = 0.392gearth

Hearing rattles from a snake, you make two rapid displacements of magnitude 1.8 m and 2.4m. Draw sketches, roughly to scale, to show how your two displacements might add to give the following resultant of magnitudes.
a. 4.2 m
b. 0.6 m
c. 3.2 m

Answers

Answer:

The answer is a 4.2m

Explanation:

Given data

Please see attached the rough drawing for your reference.

From the drawing, you ran 18m west and 2.4m south

The displacement is

= 1.8+2.4

=4.2m

A pendulum has a period of 6.98s. Calculate the length of the pendulum. Use
9.8m/s^2 for gravity. *

Answers

Answer:

Length, l = 0.126 meters.

Explanation:

Given the following data;

Period = 6.98s

Acceleration due to gravity, g = 9.8m/s²

To find the length, l;

[tex] Period, T = 2 \pi \sqrt {lg} [/tex]

Substituting into the equation, we have;

[tex] 6.98 = 2*3.142 \sqrt {l*9.8} [/tex]

[tex] 6.98 = 6.284 \sqrt {9.8l} [/tex]

[tex] \frac {6.98}{6.284} = \sqrt {9.8l} [/tex]

[tex] 1.1108 = \sqrt {9.8l} [/tex]

Taking the square of both sides

[tex] 1.1108^{2} = 9.8l [/tex]

[tex] 1.2339 = 9.8l [/tex]

[tex] l = \frac {1.2339}{9.8} [/tex]

Length, l = 0.126m.

What do you call the height of a wave?
a. wavelength
b. frequency
c. amplitude
d. resonance

Answers

Answer:

amplitude is the answer

Answer : C) Amplitude

How fast would an object have to travel on the surface of Jupiter at the equator to keep up with the Sun​ (that is, so the Sun would appear to remain in the same position in the​ sky)? Use the facts that the radius of Jupiter is approximately 44,360 miles and its revolution is approximately 10 hours.

Answers

Answer:

27872.2 miles per hour

Explanation:

Given that :

Radius of Jupiter is approximately = 44,360 miles

Revolution is 10 hours ;

Jupiter makes one revolution in 10 hours :

Using the relation to obtain the velocity :

V = re

r = radius

w = 2π/T

Hence,

V = r * 2π/ T

V =44360 * 2 * π/10

V = 88720 * π/10

V = 278722.10 / 10

V = 27872.210

V = 27872.2 miles per hour

Explain two reasons why astronomers are continually building larger and larger telescopes. Explain two reasons why astronomers are continually building larger and larger telescopes. Larger telescope mirrors have a larger surface area and can therefore collect more light, which makes faint objects bright enough to detect. Also, larger telescope mirrors produce more scattering of light due to diffraction, which contributes to better angular resolution. Larger telescope mirrors have a larger surface area and can therefore collect more light, which contributes to better angular resolution. Also, larger telescope mirrors produce more scattering of light due to diffraction, which makes faint objects bright enough to detect. Larger telescope mirrors have a larger surface area and can therefore collect more light, which contributes to better angular resolution. Also, larger telescope mirrors produce less scattering of light due to diffraction, which makes faint objects bright enough to detect. Larger telescope mirrors have a larger surface area and can therefore collect more light, which makes faint objects bright enough to detect. Also, larger telescope mirrors produce less scattering of light due to diffraction, which contributes to better angular resolution.

Answers

Answer:

* Larger mirrors collect more light and therefore fainter and more distant objects can have enough intensity to be detected

* arger mirrors decreases the angle of dispersion giving a better resolution of the bodies

Explanation:

Refracting telescopes get bigger every day for two main reasons.

* Larger mirrors collect more light and therefore fainter and more distant objects can have enough intensity to be detected

* the diffraction process for circular apertures is given by

               θ = 1.22 λ / D

where d is the diameter of the mirror, therefore having larger mirrors decreases the angle of dispersion giving a better resolution of the bodies

Violet pulls a rake horizontally on a frictionless driveway with a net force of 2.0 N for 5.0 m.
How much kinetic energy does the rake gain?

Answers

Answer:

10 J.

Explanation:

Given that,

Net force acting on the rake, F = 2 N

Distance moved by the rake, d = 5 m

We need to find the kinetic energy gained by the rake. We know that,

Kinetic energy = work done

So,

K = F×d

K = 2 N × 5 m

K = 10 J

So, 10 J of kinetic energy is gained by the rake.

Violet pulls a rake horizontally on a frictionless driveway with a net force of 2.0 N for 5.0 m.

How much kinetic energy does the rake gain?

Answer: 10 J

How does Doppler ultrasound technology differ from ultrasound technology
that does not use the Doppler effect?
A. Doppler ultrasound collects data from moving objects.
B. Other ultrasound technology creates images, but Doppler
ultrasound does not.
C. Doppler ultrasound creates images, but other ultrasound
technology does not.
D. Doppler ultrasound is based on absorption of sound, and other
ultrasound technology is based on reflection.

Answers

Answer:

A. Doppler ultrasound collects data from moving objects

Explanation:

Did the test !!

Answer:A. Doppler ultrasound collects data from moving objects.

Explanation: just got it right

on my test

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