Answer:
32 cm^3.
Step-by-step explanation:
Formulas for calculating:
sphere's volume - ;[tex]V_{sphere}=\frac{4\pi r^3}{3}[/tex]
cylinder's volume - .[tex]V_{cylinder}=\pi r^2 h[/tex]
Note that h=2r (height of the sphere consists of two radius).
Then [tex]V_{cylinder}= \pi r^2 h=\pi r^2 2r= 2\pi r^3[/tex]
Since [tex]V_{sphere}= \frac{4\pi r^3}{3}[/tex]
on calculating we get
[tex]V_{cylinder}= \frac{3V_{sphere}}{2}\\ \Rightarrow V_{sphere}=\frac{2V_{cylinder}}{3} =\frac{2\times48}{3} =32 cm^3[/tex]
What is the value of X ?
A-12
B-17
C-23
D-25
Step-by-step explanation:
25 answer by considering
A bag contains 4 green, 5 red, and 6 purple balls. The probability that all of them are red is?
Answer:
The percentage would be 20% (5x20=100)
Step-by-step explanation:
During the worst periods of inflation in America, the price of food increased at a rate of 12 % per month. If your food bill was $300 one month during this period, what was it two months later?
Exponential; $337.08
Linear; $672.00
Exponential; $376.32
Linear; $372.00
Answer:
Exponential; $376.32
Step-by-step explanation:
Generally, an increase of 12% in a month means the prices are 12% more than they were in the previous month. That is, the value has been multiplied by 1.12.
The same would be true for the second month, so the overall multiplier for the two months is ...
(1.12)(1.12) = 1.12^2 = 1.2544
This makes the food bill for the second month amount to ...
1.2544 × $300 = $376.32
_____
As with all percentages, you need to be clear about what base is being used. Here, we have assumed the base for a monthly increase is the value at the beginning of the month.
If, instead, it is the value at the beginning of the year, then the increase is linear, not exponential. 12% of the value at the beginning of the year is the same throughout the year.
Find the area of a regular hexagon with a side length of 5cm, Round to the nearest tenth.
Answer:
i think its 64.95cm
Step-by-step explanation:
A swimming pool is to be drained. The pool is shaped like a Rectangular prism with length 12m , with 10 m, and depth 3m. Suppose water is pumped out of the pool at a rate of 18 m3 per hour.if the pool starts completely full , how many hours does it take to empty the pool ?
Answer:
20 hours
Step-by-step explanation:
first calculate volume:
12x10x3=360
then divide by 18
360/18=20
So 20 hours in total
The length of a rectangle is increasing at a rate of 8 cmys and its width is increasing at a rate of 3 cmys. When the length is 20 cm and the width is 10 cm, how fast is the area of the rectangle increasing?
Answer:
The area of the rectangle increasing at the rate of 140 cm²/s
Step-by-step explanation:
Rectangle area:
A rectangle has two dimensions, length l and width w.
It's area is:
A = l*w.
When the length is 20 cm and the width is 10 cm, how fast is the area of the rectangle increasing?
We apply implicit differentiation to solve this question:
[tex]A = l*w[/tex]
So
[tex]\frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}[/tex]
Length is 20, so [tex]l = 20[/tex].
Width is 10, so [tex]w = 10[/tex]
The length of a rectangle is increasing at a rate of 8 cm/s and its width is increasing at a rate of 3 cm/s.
This means that [tex]\frac{dl}{dt} = 8, \frac{dw}{dt} = 3[/tex]
So
[tex]\frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}[/tex]
[tex]\frac{dA}{dt} = 20*3 + 10*8 = 140[/tex]
Area in cm².
So
The area of the rectangle increasing at the rate of 140 cm²/s
6(4x - 3) - 30
24x - 18 = 30
24% -18 + 18 = 30 + 18
24x = 48
24x 48
24 24
X = 2
Original Equation
Step 1
Step 2
Step 3
Step 4
Step 5
Which of these is not part of the solution process?
A. Using the associative property
B. Adding 18 to both sides to isolate the variable term
C. Dividing both sides by 24 to isolate the variable
D. Using the distributive property
Answer:
A-using the associative property
Step-by-step explanation:
Write down five numbers with a mode of 6.
Answer:
6 4 5 6 7
Step-by-step explanation:
The mode would be 5. The first 2 letters of MODE are MO, which can be an abbreviation for MOST OFTEN.
Which of the following represents "two times the sum of a number and fifteen is equal to six times the number?"
A. 2(6N + 15) = N
B. 2N + 15 = 6N
C. 2(N + 15) = 6N
A company manager for a tire manufacturer is in charge of making sure there is the least amount of defective tires. If the tire manufacturing process is working properly, the average weight of a tire for a 4-door sedan is normally distributed with a mean of 22 pounds and a standard deviation of 0.76 pounds. The manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires. What proportion of tires will be rejected by this process?
Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
The proportion of the tires that would be denied for being underweight through the given process would be:
[tex]0.347[/tex]% of the total tires will be rejected as underweight.
Given that,
Interquartile Range [tex]= 1.5[/tex]
Standard Deviation [tex]= 0.76[/tex]
Considering Mean = 0
and Standard Deviation = 1
Since lower quartile = -0.67448
Upper quartile = +0.67448
IQ range = 1.34896
To find,
The proportion of tires would be rejected due to being underweight through the process would be:
1.5 of Interquartile Range = 1.5 × [tex]1.34896 = 2.02344[/tex]
Now,
1.5 of the IQ range below the lower quartile [tex]= (lower quartile) - (1.5 of Interquartile range)[/tex]
[tex]= -0.67448 - 2.02344[/tex]
[tex]= -2.69792[/tex]
The proportion of tires that would be under 1.5 of the interquartile range below the lower quartile:
[tex]= P(x < -2.69792)[/tex] ≈ [tex]P(x < -2.70)[/tex]
Using data through the Normal Distribution Table,
[tex]P(x < -2.70)[/tex] [tex]= 0.00347[/tex]
[tex]= 0.347[/tex]%
Thus, 0.347% of the total tires would be rejected as underweight.
Learn more about "Proportion" here:
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Please answer this correctly
Answer:
40 - 59 ⇒ 6
60 - 79 ⇒ 5
Answer:
40-59: 6
60-79: 5
Step-by-step explanation:
If you just added up, you can find all the values.
Simplify 1 · 0 - . can someone please help out
Answer:
That would be just 0 because anything multiplied by 0 is 0.
Which inequality is represented by this graph?
Answer:
its probably a. x>-53
my appolgies if it's wrong
A shareholders' group, in lodging a protest, claimed that the mean tenure for a chief executive office (CEO) was at least eight years. A survey of companies reported in the Wall Street Journal found a sample mean tenure x = 7.56 of years for CEOs with a standard deviation of years s = 6.67 years.
A. Formulate hypotheses that can be used to challenge the validity of the claim made by the shareholders' group.
B. Assume 70 companies were included in the sample. What is the p-value for your hypothesis test?
C. At α = 0.02, what is your conclusion?
Answer:
could be c might be a also
Step-by-step explanation:
??!!!?!?
.....
....
...
Answer:
A) (3,2)
Step-by-step explanation:
Conditions:
x+y ≤ 6x ≥ 0y ≥ 0A) (3,2)
yes, as all 3 conditions are met3+2≤6, 3≥0, 2≥0B) (0,7)
no, as the first condition is not met0+7 > 6A tank contains 180 liters of fluid in which 50 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min; the well-mixed solution is pumped out at the same rate. Find the number A(t) of grams of salt in the tank at time t.
Answer:
[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]
Step-by-step explanation:
Given that:
A tank contains 180 liters of fluid in which 50 grams dissolved inside.
Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min
The salt pumped out[tex]= \dfrac{6 L}{180 L} = \dfrac{1}{30}[/tex] of initial amount added salt
At (t = 0) = 50
To determine the number A (t)
[tex]\dfrac{dA}{dt}=Rate_{in} - Rate _{out}[/tex]
[tex]A' = 6 - \dfrac{1}{30}A[/tex]
[tex]A' + \dfrac{1}{30}A = 6[/tex]
Integrating factor [tex]y = e^{\int\limits pdt[/tex]
[tex]y = e^{\int\limits \dfrac{1}{30}dt}[/tex]
[tex]y = e^{\dfrac{t}{30}}[/tex]
[tex](e^{ \frac{t}{30}}A)' =4 e ^{\dfrac{t}{30}}+c[/tex]
Taking integral on the both sides;
[tex]Ae ^{\dfrac{t}{30}}= 6 * 30 e^{\dfrac{t}{30}} + c[/tex]
[tex]A = 180+ ce^ {-\dfrac{t}{30}}[/tex]
At A(t = 0) = 50
50 = 180 + C (assuming C = [tex]ce ^{-\dfrac{t}{30}}[/tex])
C = 50 - 180
C = 130
[tex]\mathbf{A(t) = 180 - 130e ^{-\dfrac{t}{30}}}[/tex]
If f(3x − 1) = 6x − 1, find f(x) and f(0)
f(3x - 1) = 6x - 1
Rewrite 6x - 1 as a function of 3x - 1:
6x - 1 = 6x - 2 + 1 = 2(3x - 1) + 1
That is,
f(3x - 1) = 2(3x - 1) + 1
which means
f(x) = 2x + 1
and so
f(0) = 2*0 + 1 = 1
Two positive numbers have a difference of 8. The larger number is three more than twice the smaller. Find the two numbers.
Answer:
5 and 13
Step-by-step explanation:
Let x represent the smaller number. Then the larger number is 2x+3, and the difference is ...
(2x+3) -(x) = 8
x = 5
The two numbers are 5 and 13.
_____
Check
Twice the smaller number is 10. 3 more than that is 13, the larger number. Their difference is 13 -5 = 8.
the average mark of candidates in an aptitude test was 138.5 with a standard deviation of 10.6. three scores extracted from the test are 178,122,100.what is the average of the extracted scores that are extreme value
Answer:
The average of the extracted scores = 133.33
Step-by-step explanation:
Given data the average mark of candidates in an aptitude test was 138.5 with a standard deviation of 10.6
mean of the aptitude test = 138.5
Standard deviation of the aptitude test = 10.6
Given three scores extracted from the test are 178,122,100
The average of the extracted scores = ∑x / n
The average of the extracted scores
= [tex]\frac{178 +122 +100}{3}[/tex]
= 133.33
Final answer:-
The average of the extracted scores = 133.33
Five people (Aaron , Byron , Carina , Duncan , and Evelyn ) form a club, Nequals {A, B, C, D, E}. Carina and Evelyn are women, and the others are men. If they choose a treasurer randomly, find the odds in favor of Evelyn becoming treasurer . The odds in favor of Evelyn becoming treasurer are
================================================
Explanation:
When we talk about "odds in favor", we will use a colon to separate two whole numbers. The first number represents the number of ways for Evelyn to be chosen treasurer (just one way) and the second number represents all the ways she doesn't get chosen (the four other people)
Put another way, writing "odds in favor are 1:4" basically means "there's 1 way to get Evelyn elected and 4 ways for her to not get elected"
Instead of writing 1:4 you could write "1 to 4"
-----------
Side note: Contrast this with "odds against" and the ratio would flip from 1:4 to 4:1. Same idea, but the number of failures is listed first because we're focusing on the "against" (instead of "favor") portion. We read "4:1" as "4 to 1".
The odds in favor of Evelyn becoming treasurer are 1:5 or 1/5.
To determine the odds in favor of Evelyn becoming treasurer, we need to know the total number of possible outcomes and the number of favorable outcomes.
There are five members in the club, so there are five possible outcomes for the treasurer position, one for each member. Since Evelyn is one of the five members, she has one favorable outcome.
Therefore, the odds in favor of Evelyn becoming treasurer are 1:5 or 1/5.
Learn more about odds in favor here:
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Determine the number of ways three trumpet players out of 6 are chosen for 1st chair, 2nd chair, and 3rd chair.
Answer:
120 ways
Step-by-step explanation:
There are 3 spots and 6 options
_ _ _
1 2 3
6 ways for 1st chair to be chosen
5 ways for 2nd chair to be chosen (1st chair is chosen already, so there are 5 players left)
4 ways for 3rd chair to be chosen (1st and 2nd are already chosen, only 4 players left)
Multiply 6*5*4 to find the total number of ways (120)
I NEED HELP PLEASE SOMEONE HELP ME
Answer:
2nd option is the correct answer
Step-by-step explanation:
3 times a number decreased by 6 is - 2
Triangle QRS is dilated according to the rule DO,2 (x,y). On a coordinate plane, (0, 0) is the center of dilation. Triangle Q R S has points (negative 3, 3), (2, 4), and (negative 1, 1). What is true about the image ΔQ'R'S'? Select three options. Which statements are true? DO,2 (x,y) = (2x, 2y) Side Q'S' lies on a line with a slope of -1. QR is longer than Q'R'. The vertices of the image are closer to the origin than those of the pre-image. The distance from Q' to the origin is twice the distance from Q to the origin.
Answer:
Options A, B and E are correct
Step-by-step explanation:
From the information given above, we would draw a dilation that produces an image that is the same shape as the original image, but has a different size.
The scale factor is 2
QRS → Q'R'S' = (x,y) → 2(x,y)
The coordinates of ∆QRS
Q (-3, 3)
R (2, 4)
S (-1, 1)
To get the coordinates of Q'R'S', we would multiply each coordinate of the original triangle by the scale factor of 2 since the dilation is from the origin. In order words, each vertex of QRS is multiplied by 2 to get each of the vertex of Q'R'S'.
2 (x,y) = (2x, 2y)
The coordinates of ∆Q'R'S' becomes:
Q' (-6, 6)
R' (4, 8)
S' (-2, 2)
To determine the statements that are true about the image ΔQ'R'S,
we would graph the coordinates of the two triangles.
Starting with ΔABC, we would draw the dilation image of the triangle with a center at the origin and a scale factor of 2.
See attached the diagram for better explanation.
Let's check out each options and compare it with diagram we obtained:
a) DO, 2 (x,y) = (2x, 2y)
A dilation about the origin with a scale factor 2 is described using the above notation.
Q' = 2(-3,3) = [2(-3), 2(3)] = (-6, 6)
R' (4, 8) = 2(2,4) = [2(2), 2(4)] = (4, 8)
S' (-2, 2) = 2(-1,1) = [2(-1), 2(1)] = (-2, 2)
This option is correct
b) Side Q'S' lies on a line with a slope of -1
Q' (-6, 6)
S' (-2, 2)
coordinate (x, y)
Slope = m = (change in y)/(change in x)
m = (6-2)/[-6-(-2)]
= 4/(-6+2) = 4/-4
m = -1
This option is correct
c) QR is longer than Q'R'
Length of QR (-3 to 2) = 5
Length of Q'R' (-6 to 4) = 10
QR is not longer than Q'R'
This option is false
d) The vertices of the image are closer to the origin than those of the pre-image
The scale factor determines how much bigger or smaller the dilation image will be compared to the preimage. In a transformation, the final figure is referred to as the image. The original figure is referred to as the preimage.
From the diagram, the vertices of the preimage (original image) are closer to the origin than those of the dilation image.
This option is false
e) The distance from Q' to the origin is twice the distance from Q to the origin.
The distance from Q' to the origin (6 to 0) = 6
The distance from Q to the origin (3 to 0) = 3
The distance from Q' to the origin = 2(the distance from Q to the origin)
This option is correct
Answer:
A,B and E is correct
Step-by-step explanation:
Please answer this correctly
Answer:
Area of the figure = 254.5 cm²
Step-by-step explanation:
Area of rectangle = Length × Width
Area of triangle = 1/2(base × Height)
Dividing the figure into parts for convenience
So,
Rectangle 1 (the uppermost):
4 × 6 = 24 cm²
Rectangle 2 (below rectangle 1):
15 × 8 = 120 cm²
Rectangle 3 (with rectangle 2):
11 × 4 = 44 cm²
Triangle 1 :
1/2(7 × 19) = 133/2 = 66.5 cm²
Now adding up all to get the area of the figure:
Area of the figure = 24 + 120 + 44 + 66.5
Area of the figure = 254.5 cm²
as a last-minute deal Don and Mary booked a 7 day cruise for a total of $670 if the normal price for a couple is $1340, what discount percent did Don and Mary recieve?
Answer:
Don and Mary received a discount of 50%.
Step-by-step explanation:
Initially, we use a rule of three to find the percentage of the initial price that they paid.
The discount is 100% subtracted by the percentage they paid.
Percentage they paid:
The normal price for a couple is $1340, which is 100%.
They paid $670, which is x%. We have to find x.
$1340 - 100%
$670 - x%
[tex]1340x = 100*670[/tex]
[tex]x = \frac{100*670}{1340}[/tex]
[tex]x = 50[/tex]
They paid 50% of the original price.
What discount percent did Don and Mary recieve?
100 - 50% = 50%
Don and Mary received a discount of 50%.
g(x) = x2 – 5x + 2.
Answer:
Use the quadratic formula:
a = 1 b= -5 c= 2
x = - -5 +-sqr root (25 - 4 * 1 * 2) / 2 * 1
x = 5 +-sqr root (25 - 8) / 2
x = 5 +- sqr root (17) / 2
x1 = 5 +4.1231056256 / 2
x1 = 4.5615528128
x2 = 5 -4.1231056256 / 2
x2 = 4.5615528128
Step-by-step explanation:
I need help with this one
Answer:
Top right
Step-by-step explanation:
The solution to a system of equation is where the two graphs cross
The top right lines cross at (5,-3)
how many real solutions does the equation x2 − 9 = 0 have?
Answer:
Zero
Step-by-step explanation:
Because when you replace x with a number and solve it it doesn't have the same answer as x2 − 9 = 0.
I hope this helped. I am sorry if you get this wrong.
Each square in the grid is a 1 x 1 unit square. What is the area of the shape
Answer:
So since the formula for a square is w*h
That means that the area is 1*1 or 1 unit^2
I knew it was a joke question.
:))))
Step-by-step explanation:
The mean of the data set(9,5,y,2,x) is twice the data set(8,x,4,1,3).what is (y-x)
Answer:
[tex]y-x = 16[/tex]
Step-by-step explanation:
Given
Set 1: (9,5,y,2,x)
Set 2: (8,x,4,1,3)
Required
(y - x)
First the mean values of set 1 and set 2 has to be calculated
For set 1
[tex]Mean _1 = \frac{(9+5+y+2+x)}{5}[/tex]
Collect like terms
[tex]Mean _1 = \frac{9+5+2+y+x}{5}[/tex]
[tex]Mean _1 = \frac{16+ y+x}{5}[/tex]
For set 2
[tex]Mean _2 = \frac{(8+x+4+1+3)}{5}[/tex]
Collect like terms
[tex]Mean _2 = \frac{8+4+1+3+x}{5}[/tex]
[tex]Mean _2= \frac{16+ x}{5}[/tex]
Given that the mean of set 1 is twice the mean of set 2;
[tex]Mean_1 = 2Mean_2[/tex]
[tex]\frac{16+ y+x}{5} =2 * \frac{16+x}{5}[/tex]
Multiply both sided by 5
[tex]5 * \frac{16+ y+x}{5} = 5 * 2 * \frac{16+x}{5}[/tex]
[tex]16+ y+x = 2 * (16+x)[/tex]
Open bracket
[tex]16+ y+x = 32 + 2x[/tex]
Subtract 16 from both sides
[tex]16+ y+x- 16 = 32 + 2x - 16[/tex]
[tex]16 - 16 + y+x = 32 - 16 + 2x[/tex]
[tex]y+x = 16 + 2x[/tex]
Subtract 2x from both sides
[tex]y+x-2x = 16 + 2x-2x[/tex]
[tex]y-x = 16[/tex]