Answer:
The percentage uncertainty in his calculated value of density is [tex]\pm 0.713\,\%[/tex].
Explanation:
We can estimate the absolute uncertainty by the definition of total differential. That is:
[tex]\Delta \rho \approx \frac{\partial \rho}{\partial m}\cdot \Delta m + \frac{\partial \rho}{\partial d}\cdot \Delta d + \frac{\partial \rho}{\partial l}\cdot \Delta l[/tex] (1)
Where:
[tex]\frac{\partial \rho}{\partial m}[/tex] - Partial derivative of the density with respect to mass, measured in [tex]\frac{1}{mm^{3}}[/tex].
[tex]\frac{\partial \rho}{\partial d}[/tex] - Partial derivative of the density with respect to diameter, measured in grams per cubic milimeter.
[tex]\frac{\partial \rho}{\partial l}[/tex] - Partial derivative of the density with respect to length, measured in grams per cubic milimeter.
[tex]\Delta m[/tex] - Mass uncertainty, measured in grams.
[tex]\Delta d[/tex] - Diameter uncertainty, measured in milimeters.
[tex]\Delta l[/tex] - Length uncertainty, measured in milimeters.
[tex]\Delta \rho[/tex] - Density uncertainty, measured in grams per cubic milimeters.
Partial derivatives are, respectively:
[tex]\frac{\partial \rho}{\partial m} = \frac{4}{\pi\cdot d^{2}\cdot l}[/tex] (2)
[tex]\frac{\partial \rho}{\partial d} = -\frac{8\cdot m}{\pi\cdot d^{3}\cdot l}[/tex] (3)
[tex]\frac{\partial \rho}{\partial l} = - \frac{4\cdot m}{\pi\cdot d^{2}\cdot l^{2}}[/tex] (4)
And we expand (1) as follows:
[tex]\Delta \rho \approx \frac{4\cdot \Delta m}{\pi\cdot d^{2}\cdot l} - \frac{8\cdot m\cdot \Delta d}{\pi\cdot d^{3}\cdot l}-\frac{4\cdot m\cdot \Delta l}{\pi\cdot d^{2}\cdot l^{2}}[/tex]
[tex]\Delta \rho \approx \left(\frac{4}{\pi\cdot d^{2}\cdot l}\right)\cdot \left(\Delta m -\frac{m\cdot \Delta d}{d}-\frac{m \cdot \Delta l}{l} \right)[/tex] (5)
If we know that [tex]d = 2\,mm[/tex], [tex]l = 25\,mm[/tex], [tex]m = 6.2\,g[/tex], [tex]\Delta m = \pm 0.1\,g[/tex], [tex]\Delta d = \pm 0.01\,mm[/tex] and [tex]\Delta l = \pm 0.1\,mm[/tex], then the absolute uncertainty is:
[tex]\Delta \rho \approx \pm\left[\frac{4}{\pi\cdot (2\,mm)^{2}\cdot (25\,mm)} \right]\cdot \left[(0.1\,g)-\frac{(6.2\,g)\cdot (0.01\,mm)}{2\,mm} -\frac{(6.2\,g)\cdot (0.1\,mm)}{25\,mm} \right][/tex]
[tex]\Delta \rho \approx \pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}}[/tex]
And the expected density is:
[tex]\rho = \frac{4\cdot m}{\pi\cdot d^{2}\cdot l}[/tex] (6)
[tex]\rho = \frac{4\cdot (6.2\,g)}{\pi\cdot (2\,mm)^{2}\cdot (25\,mm)}[/tex]
[tex]\rho \approx 78.941\times 10^{-3}\,\frac{g}{mm^{3}}[/tex]
The percentage uncertainty in his calculated value of density is:
[tex]\%e = \frac{\Delta \rho}{\rho}\times 100\,\%[/tex] (7)
If we know that [tex]\Delta \rho \approx \pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}}[/tex] and [tex]\rho \approx 78.941\times 10^{-3}\,\frac{g}{mm^{3}}[/tex], then the percentage uncertainty is:
[tex]\%e = \frac{\pm 5.628\times 10^{-4}\,\frac{g}{mm^{3}} }{78.941\times 10^{-3}\,\frac{g}{mm^{3}} }\times 100\,\%[/tex]
[tex]\%e = \pm 0.713\,\%[/tex]
The percentage uncertainty in his calculated value of density is [tex]\pm 0.713\,\%[/tex].
When a space shuttle was launched, the astronauts on board experienced an acceleration of 29.0 m/s2. If one of the astronauts had a mass of 60.0 kg, what net force in Newton’s did the astronaut experience?
1. Three vehicles are traveling at the same speed in the same direction on a 1 point
highway, as shown in the diagram below. If the position of the front of the
white van is -21 m, what is the point of reference?
9514 1404 393
Answer:
The front of the black car
Explanation:
The position -21 is shown on the diagram at the front of the white van. The reference point is the position 0, which is shown on the diagram as the front of the black car.
Answer:
Explanation:
I'm answering this just so you can give the Brainliest to Squaredancefan, a master answerer in my opinion.
The reference point is where the 0 is. Everything to the right is positive and everything left of 0 is minus. 0 is the reference point because it is neither.
how is an object's motion related to speed, velocity, and acceleration?
Answer:
Speed describes only how fast an object is moving, whereas velocity gives both the speed and direction of the object’s motion being a vector quantity. The standard unit to measure velocity is meter per second (m/s or ms-1). For example, “10 meters per second” is scalar and “10 meters per second West” is vector. Acceleration
What is the speed in kilometers per hour of a 27.78m/s baseball pitch?
Answer:
I actually don't know
Explanation:
ok chillll
The diagram shows the forces acting on an object at an instant of time. Which of the following statements about the forces is true?
Answer:
If you want help, try showing that diagram and the following statements.
Bird man is flying horizontally at a speed of 30m/a and a height of 69 m. Bird man releases a turd directly above the start of the field. How far from the start of the field should the robot hood the bucket to catch the turd?
Answer:
The distance is [tex]d = 112.5 \ m[/tex]
Explanation:
From the question we are told that
The horizontal speed is [tex]v_x = 30 \ m/s[/tex]
The height is [tex]s = 69 \ m[/tex]
Generally from kinematic equation we have that
[tex]s = ut + \frac{1}{2} gt^2[/tex]
Here u is the initial velocity of the turd in the vertical direction and the value is 0 m/s
So
[tex]69 = 0 * t + \frac{1}{2} * 9.8 t^2[/tex]
=> [tex]t = \sqrt{\frac{2 * 69}{4.9} }[/tex]
=> [tex]t = 3.75 \ s[/tex]
Generally the distance which the robot have to hood the bucket in order to catch the turd is mathematically represented as
[tex]d = v_x * t[/tex]
=> [tex]d = 30 * 3.75[/tex]
=> [tex]d = 112.5 \ m[/tex]
En un año se otorgará uno de tres premios (a la investigación, la enseñanza y el servicio) a algunos de los estudiantes, de un grupo de 25, de posgrado del departamento de estadística. Si cada estudiante puede recibir un premio como máximo, ¿cuántas selecciones posibles habría?
Answer:
Habría 13,800 selecciones posibles.
Explanation:
Permutar es colocar elementos en distintas posiciones.
Se llama permutación de m elementos a cada una de las diferentes ordenaciones que se pueden hacer con esos elementos. En otras palabras, se llama permutaciones de m elementos en n posiciones a las distintas formas en que se pueden ordenar los m elementos ocupando únicamente las n posiciones.
En el caso de la permutación no se repiten los elementos, ya que de repetirse o ser iguales entre si, al intercambiarlos no se genera una nueva permutación.
El número de permutaciones de n elementos elegidos k a la vez es calculado como:
[tex]P=\frac{n!}{(n-k)!}[/tex]
Como los premios son distinguibles, la permutación es usada en este caso, donde n=25 y k=3
Entonces:
[tex]P=\frac{25!}{(25-3)!}[/tex]
Resolviendo:
[tex]P=\frac{25!}{(22)!}[/tex]
Recordando que el factorial es una operación matemática que indica que se deben multiplicar todos los números enteros y positivos que hay entre el número al cual deseas calcular el factorial y el número 1, entonces se obtiene:
P= 13,800
Habría 13,800 selecciones posibles.
La selección de los alumnos se puede realizar de 2300 formas.
Teniendo en cuenta eso, tenemos 25 estudiantes graduados para ser seleccionados para tres tipos diferentes de premios, como pabellones de investigación, docencia y servicio.
Ahora;
25C3 = 25! / 3! (25 - 3)!
25C3 = 25! / 3! 22!
25C3 = 2300
La selección de los alumnos se puede realizar de 2300 formas.
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Density Questions
How many blocks of ice-cream each 10cm x 10 cm x 4cm can be stored in the compartenent of a deep-freeze measuring 40 cm x 40cm x 20cm?
Explanation:
let's take the volume of each first:
ice cream: 10×10×4=400cm^3
freezer: 40×40×20=32,000cm^3
now we just divide: 32000/400=80
Under what conditions can an object have forces acting on it, but its motion does not change ?
Answer: An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion.
Explanation: I hoped that helped!!
What would be the y-component of a velocity vector that had a
magnitude of 37m/s in a direction 30° from the x-axis?
Answer:
18.5 m/s
Explanation:
Just did it on EdPuzzle
The y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s .
What is a vector quantity?The quantities that contain the magnitude of the quantities along with the direction are known as the vector quantities.
Examples of vector quantities are displacement, velocity acceleration, force, etc.
As given in the problem we have to find out the y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis.
The y-component of a velocity vector = 37 × sin 30
= 18.5 m / s
Thus , y-component of a velocity vector that had a magnitude of 37 m / s in a direction 30° from the x - axis would be 18.5 m / s.
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Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to 350 K. If the volume of the bottle remains constant, what is the pressure, in pascals, inside the hot water bottle!
Answer:
128.205.1
Explanation:
I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!
Answer:
h
Explanation:
Coulomb's law, or Coulomb's inverse-square law, is an experimental law[1] of physics that quantifies the amount of force between two stationary, electrically charged particles. The electric force between charged bodies at rest is conventionally called electrostatic force or Coulomb force.[2] The law was first discovered in 1785 by French physicist Charles-Augustin de Coulomb, hence the name. Coulomb's law was essential to the development of the theory of electromagnetism, maybe even its starting point,[1] as it made it possible to discuss the quantity of electric charge in a meaningful way.[3]
The law states that the magnitude of the electrostatic force of attraction or repulsion between two point charges is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them,[4]
{\displaystyle F=k_{\text{e}}{\frac {q_{1}q_{2}}{r^{2}}}}{\displaystyle F=k_{\text{e}}{\frac {q_{1}q_{2}}{r^{2}}}}
Here, ke is Coulomb's constant (ke ≈ 8.988×109 N⋅m2⋅C−2),[1] q1 and q2 are the signed magnitudes of the charges, and the scalar r is the distance between the charges.
The force is along the straight line joining the two charges. If the charges have the same sign, the electrostatic force between them is repulsive; if they have different signs, the force between them is attractive.
Being an inverse-square law, the law is analogous to Isaac Newton's inverse-square law of universal gravitation, but gravitational forces are always attractive, while electrostatic forces can be attractive or repulsive.[2] Coulomb's law can be used to derive Gauss's law, and vice versa. In the case of a single stationary point charge, the two laws are equivalent, expressing the same physical law in different ways.[5] The law has been tested extensively, and observations have upheld the law on the scale from 10−16 m to 108 m.[5]
A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?
Complete Question
A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the ball's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?
Answer:
The distance covered horizontally is [tex]d = 43 \ m[/tex]
Explanation:
From the question we are told that
The initial horizontal velocity is [tex]u = 10 \ m/s[/tex]
The time taken by the ball in the air is [tex]t = 4.3 \ s[/tex]
Generally the distance traveled by the ball is
[tex]d = u * t[/tex]
=> [tex]d = 10 * 4.3[/tex]
=> [tex]d = 43 \ m[/tex]
An insulated rigid tank initially contains 1.4-kg saturated liquid water and water vapor at 200°C. At this state, 25 percent of the volume is occupied by liquid water and the rest by vapor. Now an electric resistor placed in the tank is turned on, and the tank is observed to contain saturated water vapor after 20 min. Determine:
(a) the volume of the tank
(b) the final temperature
(c) the electric power rating of the resistor
Solution:
Mass of liquid water and water vapor in the insulated tank initially = 1.4 kg
Temperature = 200 °C
And 25% of the volume by liquid water is steam.
State 1
[tex]$m=\frac{V}{v}$[/tex]
[tex]$m=m_f+m_g$[/tex]
[tex]$1.4=\frac{0.25V}{v_f}+\frac{0.75V}{v_g}$[/tex]
[tex]$1.4=\frac{0.25V}{1.1565 \times 10^{-3}}+\frac{0.75V}{0.1274}$[/tex] (taking the value of [tex]$v_g$[/tex] and [tex]$v_g$[/tex] at 200°C )
[tex]$V=6.304 \times 10^{-3}$[/tex]
Now quality of vapor
[tex]$x=\frac{m_g}{m}$[/tex]
[tex]$=3.377 \times 10^{-3}$[/tex]
Internal energy at state 1 can be found out by
[tex]$u_1=u_f+xu_{fg}$[/tex]
[tex]$=850.65+3.377\times10^{-3}\times 1744.65$[/tex]
= 856.54 kJ/kg
After heating with the resistor for 20 minutes, at state 2, the tank contains saturated water vapor [tex]$v_2=v_g \text { and }\ x=1$[/tex]
Tank is rigid, so volume of tank is constant.
[tex]$v_g=v_2=\frac{V}{m}$[/tex]
[tex]$v_g=\frac{6.304\times 10^{-3}}{1.4}$[/tex]
[tex]$v_g=4.502 \times 10^{-3} \ m^3 /kg$[/tex]
Now interpolate the value to get temperature at state 2 with specific volume value to get final temperature
[tex]$T_2=360+(374.14-360)\left(\frac{0.004502-0.006945}{0.003155-0.006945}\right)$[/tex]
= 369.11° C
Internal energy at state 2
[tex]$u_2=2154.9 \ kJ/kg$[/tex]
Now power rating of the resistor
[tex]$P=\frac{m(u_2-u_1)}{t}$[/tex]
[tex]$P=\frac{1.4(2154.9-856.54)}{20 \times 60}$[/tex]
= 1.51 kW
HELP PLZ IM BEING TIMED!!
What is the vertical acceleration of a dart that is launched horizontally with an initial velocity of 2.3 m/s?
-9.8 m/s
2 0 m/s2
2.3 m/s2
9.8 m/s2
Answer:
-9.8
Explanation:
EDGE 2021
The vertical acceleration of a dart is equal to the negative of acceleration due to gravity (- g). The vertical acceleration of the dart is equal to -9.8m/s². Therefore, option (1) is correct.
What is the acceleration due to gravity?Acceleration due to gravity is the acceleration acquired by a body due to gravitational force. As gravity has both magnitude and direction, so it is a vector quantity. Acceleration due to gravity is expressed by the symbol 'g'. The SI unit of g is m/s² and the value of g (acceleration due to gravity) on the surface of the earth is 9.8 m/s².
Let us suppose a body with mass (m) is dropped from a height ‘h’ above the surface of the earth with mass (M), it starts to move downwards with an increase in velocity to the earth's surface.
The body starts to accelerate toward the earth’s center under the action of gravitational force which is at a distance ‘r’.
Then, ma = GMm/r²
a = GM/r²
Therefore, the value of the acceleration due to gravity (g) = GM/r2.
Any object freely falling to the surface of the earth has acceleration due to gravity is 9.8m/s².
If the object moves away from the surface of the earth then it experiences the gravitational pull of the earth. Therefore, the acceleration of dart vertically is equal to -g.
Therefore, the vertical acceleration of the dart is equal to -9.8m/s².
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. True/False mass is a fundamental Quantity
2. True/False the unit of density is g/cm3
3. True/False to convert from mm to cm, one must multiply by 10
4. True/False a micrometre screw gauge can measure the lengths greater than 3 cm
5. True/False the Vernier calliper can be used to measure small depths
6. True/False the mass of the bob affects the period of oscillation of a pendulum
7. True/False systematic error can be corrected by repeating the experiment
8. True/False a graph that rises from left to right would have a positive gradient
9. True/False gradient can be calculated using the formula rise over run
10. True/False acceleration is defined as the rate of change of displacemen
Answer:
truefalsefalsetruesorrtrue I really sorry I can't give answer because I don't know answerSilver has a mass of 10.5 grams and a volume of 19.3 cm3. What is its density?
Answer:
The answer is 0.54 g/cm³Explanation:
The density of a substance can be found by using the formula
[tex]density = \frac{mass}{volume} \\ [/tex]
From the question we have
[tex]density = \frac{10.5}{19.3} \\ = 0.54404145...[/tex]
We have the final answer as
0.54 g/cm³Hope this helps you
What happens to the strength of an electromagnet when the number of coils
in the solenoid is increased?
O A. It depends on what metal makes up the solenoid.
B. It increases.
C. It remains the same.
D. It decreases.
Answer:
It decreases
Explanation:
<3
When the number of coils in the solenoid is increased, the strength of the electromagnet also increases. So, the correct option is B.
What is meant by a solenoid ?A solenoid is defined as a type of electromagnet formed by winding a wire into a helical coil on a rod made of solid iron or steel.
Here,
The number of coils in the solenoid is increased. This increase in the number of coils, would affect the strength of the electromagnet.
The equation for the strength of the magnetic field of a solenoid can be written as,
B = μ₀NI/L
where,
B is the magnetic field strength
μ₀ is the permeability of free space
N is the number of turns of the coil
I is the current flowing through the solenoid
L is the length of the solenoid
From the equation, we can say that the magnetic field strength of a solenoid is directly proportional to the number of turns or the number of coils formed.
B [tex]\alpha[/tex] N
Therefore,
As, the number of coils in a solenoid increases, the magnetic field strength of the solenoid also increases.
Hence,
When the number of coils in the solenoid is increased, the strength of the electromagnet also increases.
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You are traveling down the highway when you notice a cop 200 meters ahead of you. For the next 5 seconds, you step on the bake to avoid a speeding ticket. The brake causes an acceleration on your car of -2.0 m/s^2.
What is the time it takes?
What is the displacement of your car?
What is the acceleration of your car?
Write the equation you will use to solve the problem.
What was your initial velocity?
Answer:200 5 -20 = v=323
Explanation:
6. Another engine reaches its top speed from rest in 7.5 s. It is able to perform 250,000 J of wok in
that time How much power does this engine have in that time?
Answer:
0.8N
Explanation:
your welcome:)
A box is pushed horizontally with constant speed across a rough horizontal surface.
Which of the following must be true?
Answer:
what is the answers? so i can't answer.
Explanation:
The statement that is true as regards movement of the box when pushed horizontally with constant velocity is given by;
Option D; The friction is equal to the applied force
The missing options are;
a) The friction is less than the applied force
b) There is no friction acting on the box
c) The friction is greater than the applied force
d) The friction is equal to the applied force
We are told that the box is pushed with constant speed. We know that at constant speed, acceleration is equal to zero. If acceleration is zero, the 2 forces acting on the box will be the applied force and the frictional force from the rough horizontal surface.
Now, if the frictional force was less than the applied force, it means the velocity of the box will gradually be increasing but we are told the velocity is constant.
Also, if the frictional force is more than the applied force, it means the object will not move because the force of resistance is more than the applied force.Finally, if the frictional force is equal to the applied force, then the box will move with a constant motion.
Thus, in conclusion the friction is equal to the applied force.
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OC wykonuje około 112 pełnych wahnięć skrzydłami w ciągu jednej sekundy Zaznacz poprawne dokończenie zdania okres drgań skrzydeł osy wynosi około a 112 sekund b 112 h z c9n s d 0,009 h l z
Answer:
T = 0.009 s
Explanation:
It is given that, an OC makes about 112 full wing swings in one second. We need to find the oscillation period of the wasp's wings.
No of oscillations per unit time is called the frequency of an object. It means 112 is the frequency of wing swings. Let T is the oscillation period. It is equal to the reciprocal of frequency as follows :
[tex]T=\dfrac{1}{f}\\\\T=\dfrac{1}{112}\\\\= 0.00892\ s\\\\=0.009\ s[/tex]
Hence, the oscillation period is 0.009 s.
When the car was stopped by the tree, its change in velocity during the collision was -6 meters/second. This change in velocity occurred in 2 seconds. What was the acceleration of the car?
Un delfín nada en el mar, a una profundidad tal que experimenta es de 2,22 x 10⁵ PA. Si la densidad del agua del mar es de 1030kg/m³, ¿A qué profundidad nada el delfín?
Answer:
El delfín nada a una profundidad de 22 m
Explanation:
El principio fundamental de la hidrostática establece que la presión en un punto del interior de un fluido (presión hidrostática) es directamente proporcional a su densidad, a la profundidad que se encuentre dicho punto y a la gravedad del sitio en el que se encuentre el fluido.
Esto se expresa como:
P=ρ⋅g⋅h
donde:
P es la presión en un punto del fluido. ρ es la densidad del fluido .g es la gravedad del lugar donde se encuentre el fluido. h es la profundidad.En este caso:
P= 2.22*10⁵ Paρ= 1,030 [tex]\frac{kg}{m^{3} }[/tex]g= 9.8 [tex]\frac{m}{s^{2} }[/tex]h= ?Reemplazando:
2.22*10⁵ Pa= 1,030 [tex]\frac{kg}{m^{3} }[/tex] * 9.8 [tex]\frac{m}{s^{2} }[/tex] * h
Resolviendo:
[tex]h=\frac{2.22*10^{5} Pa}{1,030\frac{kg}{m^{3} }*9.8 \frac{m}{s^{2} }}[/tex]
h= 21.993 m ≅ 22 m
El delfín nada a una profundidad de 22 m
3.4 x 10 (fifth power)
=
Convert from scientific notation
Answer:
340000
Explanation:
The answer is 340000 because there will be six digits, as it is one digit followed by five zeroes, but one of the zeroes is a 4 because of the 4 in 3.4. 3.4x10^5 is 340000 in standard form.
Two teams are competing in a tug-of-war contest. Team A is pulling at 4000N and Team B is pulling at 4900N is the opposite direction.
Answer:
There is 8900N of force on the rope and team B wins
Explanation:
what is measurement
Answer:
the size, length, or amount of something, as established by measuring.
Explanation:
A jogger takes five minutes to run a distance of three kilometres. His speed, in metres per second, is approximately A) 5.5 M/S B) 10 M/S C) 36 M/S D) 4.5 M/S
Answer:
His speed, in metres per second, is approximately 10m/s. The correct option is B.
Explanation:
Speed is defined as the rate in which an object cover a distance in a given time. It is measured in meters per second ( m/s). From the question, the jogger covered a distance of 3Km which when converted to meter is 3000meters in a given time 5 minutes which is 300seconds. The calculation of his speed in meter per second is shown below:
Distance= 3Km to meters ( as 1000meters = 1Km). Therefore 3× 1000 = 3000m
Time= 5 minutes to seconds ( as 1 minute = 60 Seconds). Therefore 5× 60= 300.
Speed= distance/ time
= 3000/300
= 10m/s
Therefore his speed, in metres per second, is approximately 10.
Why are wildfires getting worse ? Does is have to do with Climate Change ?
Answer:
There is a logical explanation for that.
Explanation:
Human activities such as lighting campfires and discarding lit cigarettes are responsible for starting fires, hotter weather makes forests drier and more susceptible to burning.
Rising temperatures, a key to climate change, evaporate moisture from the ground, drying out the soil, and making vegetation more flammable. At the same time, winter snowpacks are melting a month earlier, meaning forests are drier for longer periods.
As drought and rising heat continue with rising greenhouse gas emissions, there will be more expected wildfires in the years ahead, especially with the fire seasons getting longer.
Which statement describes the pattern in the density of gases in the
atmosphere?
A. They are least dense in the atmosphere near sea level
B. They are less dense near the top of the atmosphere
C. They are densest near the middle of the
atmosphere
D. They are every dense thoughout the attesohere
Gases are less dense near the top of the atmosphere.
What is atmosphere?All life on Earth is shielded by the atmosphere, a layer of gases that regulates temperatures within a narrow range and deflects harmful solar rays.
The layer of gases that covers Earth is known as the atmosphere. The gravitational pull of the Earth keeps it close to the planet's surface. The three primary gases that make up the atmosphere are argon, oxygen, and nitrogen.
Density of atmosphere is high at sea level and gradually decreases with height. And at top of the atmosphere, gas is less dense.
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