A vSphere Administrator is receiving complaints a database VM is experiencing performance issues. The VM is a member of the high priority resource pool and the cluster has not experienced contention.
Which condition should be checked to address immediate performance concerns?
A. VM snapshots
B. VMFS version
C. Resource Pool share value
D. Configured CPU shares

Answer:

Explanation:

a.  

// Rewriting the given function without using any square brackets

double computeAverage(const double* scores, int nScores)

{

const double* ptr = scores;

double tot = 0;

int i;//declaring integer variable

for(i=0;i<nScores;i++)

{

//using an integer variable i to visit each double in the array

tot += *(ptr+i);

}

return tot/nScores;

}

b.

// Rewriting the given function without using any square brackets

const char* findTheChar(const char* str, char chr)

{

for(int k=0;(*(str+k))!='\0';k++)

{

if ((*(str+k)) == chr)

return (str+k);

}

return nullptr;

}

c.

//Now rewriting the function shown in part b so that it uses neither square brackets nor any integer variables

const char* findTheChar(const char* str, char chr)

{

while((*str)!='\0')

{

if ((*str) == chr)

return (str);

str++;

}

return nullptr;

}

Answer:

The pseudocode is as given below in the explanation while the flow diagram is attached herewith

Explanation:

The pseudocode is as follows

input cust_name, num_texts  

Set Main_bill=5 $;

if the num_texts is less than or equal to 60

Excess_Charge=0;

If the num_texts is greater than 60 and less than or equal to 200

num_text60200 =num_texts-60;

Excess_Charge=0.1*(num_text60200);

else If the num_texts is greater than 60

num_texts200 =num_texts-200;

Excess_Charge=0.25*(num_texts200)+0.1*(200-60);

Display cust_Name

Total_Bill=Main_bill+Excess_Charge;

Total_Bill_after_Tax=Total_Bill*1.12;

Answer: you want to list all LC structers

Explanation:

Answer:

automated

Explanation:

Basically a Business Impact Analysis (BIA) estimates and determines the effects of a business activity and process disturbances. These disruptions can be natural or electronic disasters. It also collects information which is used to establish recovery plan. It identifies the business vulnerabilities and works on the strategies in order to reduce such potential hazards. The BIA involves both manual and automated processes. BIA involves automated processes which include the automated software tools that enables the protection of the confidential information of the users and also generates automated reports about the critical business processes.

Answer:

A digital security risk is an action that could result in damage to a computer or similar device's hardware, software, data etc.

Answer:

The correct option is D

D) CVS

Explanation:

A CVS file saves a workbook as a comma-delimited text file for use on another windows operating system. It ensures that line breaks, tab characters and other characteristics are interpreted correctly.

A CVS file stands for Comma Separated Value file, which basically allows the data to be saved in tabular format. However they differ from other spreadsheet file types because you can only have a single sheet in a file. Moreover, you cannot save cell, column or row in it.

Answer:

Given: K(x,y) denotes statement:

"x knows y"

D denote domain of all people.

Explanation:

1. Everybody knows somebody.

Solution:

∀x∈D ∃y∈D : K(x, y)

∀ means for all. Here it is used for Everybody.

∃ means there exists some. Here it represents Somebody.

∈ means belongs to . Both x and y belongs to the domain D of all people.

2. There is somebody that no one knows.

Solution:

∀x∈D ∃y∈D : ¬K(x, y)

∀ means for all. ∃ means there exists some. ∈ means belongs to both x and y belongs to the domain D of all people.¬ this is negation sign which means not K(x,y). So the negation of everybody knows somebody can be expressed as there is somebody that no one knows.

3. There is no one who knows everybody

Solution:

This can be represented in both the ways below.

∀ y∈D ∃ x∈D : K(x, y)

∀ means for all. ∃ means there exists some. ∈ means belongs to both x and y belongs to the domain D of all people.

∀x∈D ∀y∈D : ¬K(x, y)

∀ means for all. The negation shows that there is no one who knows everybody.

Answer:

6

Explanation:

Answer:

4

Explanation:

It is between 3 and 13. Please answer some of my questions too! :)

Answer:

Explanation:

MIPS program which increments from 0 to 15 and display results in Decimal on the console

In this program the user defined procedures print_int and print_eot were used to print the integer values and new line characters(\n) respectively.the mechanisam of the loop is explaine in the comment section of the program.

     addi $s0, $0, 0

     addi $s1, $0, 15

print_int:

              li $v0, 1                # system call to print integer

              syscall                

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s1<$s0

beq $s0, $0, end

end:

MIPS progam to increment from 0 to 15 and display results in Hexadecimal on the console

this program is slightly differed from the previous program in this program the system call issued in print_int is implemented with a system call that prints numbers in hex.

addi $s0, $0, 15

     addi $s1, $0, 0

print_int:

   li      $v0,34                  # syscall number for "print hex"

   syscall                         # issue the syscall

              jr $ra                     # return

print_eol:                      # prints "\n"

            li $v0, 4            

              la $a0, linebrk      

              syscall              

              jr $ra                  # return

main: . . .          

              li $a0, 0                # print 0

              jal print_int         # print value in $a0

loop:   move $a0, $s0           # print loop count

       jal print_int        

       jal print_eol           # print "\n" character

       addi $s0, $s0, 1        # increment loop count by 1

       ble $s1, $s0, loop      # exit if $s0>$s1

beq $s0, $0, end

end:

Answer:

Following are the code to this question:

import java.util.*; //importing package for user input

public class Main //defining class

{

public static void main(String []ar) //defining main method

{

double investment_amount,interest_rate,future_investment_value; //defining double variables

int years; //defining integer variable

Scanner obx=new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter invest value: "); //print message

investment_amount=obx.nextDouble(); //input value

System.out.print("Enter interest rate: ");//print message

interest_rate=obx.nextDouble();//input value

System.out.print("Enter number of years: ");//print message

years=obx.nextInt();//input value

future_investment_value=investment_amount*Math.pow((1+interest_rate/1200.),years*12); //calculating value by apply formula

System.out.println("you enter amount: $"+investment_amount); //print calculated value

System.out.println("annual interest rate:"+interest_rate+"%");//print calculated value

System.out.printf("Number of years: "+years+" the future investment value is :$%.2f\n",future_investment_value);//print calculated value

}

}

output:

please find the attachment.

Explanation:

Program Description:

Answer:

getInfo(); ==

getSy.Info()

Explanation:

Get System Info

Answer:

Explanation:

I mean I would copy and paste it. I hope thats right

Answer:

Network Operating System (NOS)

Explanation:

A network operating system (NOS) is an operating system that makes different computer devices connect to a common network in order to communicate and share resources with each other using a server. A network operating system can be used by printers, computers, file sever among others, and they are connected together using a local area network. This local area network which they are connected to works as the server.

The NOS also acts as a network security because it could be used as an access control or even user authentication.

There are two types of NOS

1) Peer to peer network operating system.

2) Client/server network operating system

A network operating system (NOS) is a server-based operating system oriented to computer networking and may include directory services, network management, network monitoring, network policies, user group management, network security, and other network-related functions.

Answer:1) Parse-by-value

2) Parse-by-reference

3) Parse-by-name

Explanation: Parameter parsing refers to a communication among procedures or functions.

The values of a variable procedure are transferred to the called procedure by some mechanisms. Different techniques of parameter-parsing include; parse-by-value, parse-by-reference, parse-by-copy restore, parse-by-name.

Answer:

In dynamic scoping the current block is searched by the compiler and then all calling functions consecutively e.g. if a function a() calls a separately defined function b() then b() does have access to the local variables of a(). The visible variables with the name of the function in which it was defined are given below.

Explanation:

a. main calls fun1; fun1 calls fun2; fun2 calls fun3

Solution:

b. main calls fun1; fun1 calls fun3

Solution:

c. main calls fun2; fun2 calls fun3; fun3 calls fun1

Solution:

Here variables c, d and e of fun2 are not visible .

d. main calls fun1; fun1 calls fun3; fun3 calls fun2

Solution:

Answer:

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

Explanation:

This program that we are told to write will be done by using python programming language/ High-level programming language.

The question wants us to write a program in which the output will be as below;

hey 1

hi 2

Mark 1

hi 2

mark 1

Just by imputing hey hi mark hi mark.

Just copy and run the code below.

#Declare variable to get the input

#list from the user

input_list = input()

#split the list into words by space

list = input_list.split()

#Begin for-loop to iterate each word

#to get the word frequency

for word in list:

#get the frequency for each word

frequency=list.count(word)

#print word and frequency

print(word,frequency)

In this exercise we have to use the knowledge in computational language in python to write the following code:

We have the code can be found in the attached image.

So in an easier way we have that the code is

input_list = input()

list = input_list.split()

for word in list:

frequency=list.count(word)

print(word,frequency)

See more about python at brainly.com/question/18502436

Answer:

Explanation:

The objective of this task is to compute a program that involves the usage of Python code to save the data to MongoDB and to query  the database.

Due to the error that occur which makes me to be unable to submit this answer, I've created a word document instead and the attached file can be found below.

Thanks!

Answer:

#main function start

def main():

#list to store names entered by user

name_list=[]

#variable to take input from user to keep rotating the loop and take input from user again and again

ch='y'

fname=""

lname=""

while ch=='y' or ch=='Y':#keep the loop taking input from user till user do not want to enter more

#take input from user

name=[]

fname=input("Enter first name: ")

lname=input("Enter last name: ")

name.append(fname)

name.append(lname)

#append the previously input first and last name in main list

name_list.append(name)

ch=input("Do you want to continue: (y/Y for yes)")

#main function end

#get file name from user

filename=input("Enter output file name")

#open file in write mode

file=open(filename,"w")

#keep loop add data in file till main list 'name_list' have

for i in name_list:

#Write data in file

file.write("%s, %s\r\n" % (i[0],i[1]))

#close the file

file.close()

#call main function

main()

Explanation:

input the above code and see output

Answer:

~CaptnCoderYankee

Don't forget to award brainlyest if I got it right!

Filtering is a useful way to see only the data that you want displayed in Access databases.

Explanation:

1. I grew up in a small community and my family owned a small business which involved manual labor. Although, having little income, my Dad sought to give us the best education he could afford from his little savings. With the small family savings I went to college where I studied Information Technology, after graduating I worked for a startup firm for two years before I decided to proceed with post graduate studies and I attained my Masters in UA. I met a friend who recommended I study in University of Cumberlands, I hesitated initially but was convinced after I researched the institution.

2. I'm particularly interested in the applications of information technology in labor intensive businesses and work because of my family background.

3. I have my own startup firm that designs work communication software for companies, however I intend to broaden my knowledge through this program into Information Technology based systems using machine learning algorithm.

4. I am committed to work and study, as some have called me a curious mind because of my passion towards learning.

5. I view obtaining a doctorate as not just a personal achievement but of lasting benefits to society as I use knowledge derived to improve the work experience of society.

I am confident that after my program I would be one the renowned contributors to the applications of information technology in labor intensive businesses.

Answer:

Sorted Array A { } = { 1, 4, 23, 32, 34, 34, 67, 78, 89, 100 }

Explanation:

Binary tree is drawn given that the binary tree do not follow both minimum heap and maximum heap property, therefore, it is not a heap.

See attached picture.

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

The specification should be developed to help your mother buy her hardware and software on her own is hardware.

Hardware refers back to the computer's tangible additives or shipping structures that shop and run the written commands furnished through the software program. The software program is the intangible a part of the tool that shall we the consumer have interaction with the hardware and command it to carry out unique tasks.

Read more about the hardware :

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Answer:

total = 0

count = 0

while(True):

   grade = float(input("Enter a grade: "))

   if grade < 0:

       break

   else:

       total += grade

       count += 1

average = total/count

print("The average is: " + str(average))

Explanation:

*The code is in Python.

Initialize the total and count as 0

Create a while loop that iterates until a specific condition is met inside the loop

Inside the loop, ask the user to enter a grade. If the grade is smaller than 0, stop the loop. Otherwise, add the grade to the total and increment the count by 1.

When the loop is done, calculate the average, divide the total by count, and print it

Answer:

A. Make Laws

Explanation:

Montesquieu believed the ways to go about limiting the power of a monarch would be to split up power among 3 groups, Judicial, Legislative and Executive. The American Presidential system and Constitution used Montesquieu's writings as a foundation for their principles.

Answer:

Explanation:

PROGRAM

main.c

#include <fcntl.h>

#include <stdio.h>

#include <stdlib.h>

#include <sys/stat.h>

#include <sys/types.h>

#include <unistd.h>

#include "myio.h"

int checkInt(char *arg);

int main(int argc, char *argv[]) {

  int doubles, i, ints, lines;

  char newline;

  FILE *out;

  int x, y, z;

  newline = '\n';

  if (argc != 5) {

     printf("Usage is x y z output_filename\n");

     return 0;

  }

  if (checkInt(argv[1]) != 0)

     return 0;

  ints = atoi(argv[1]);

  if (checkInt(argv[2]) != 0)

     return 0;

  doubles = atoi(argv[2]);

  if (checkInt(argv[3]) != 0)

     return 0;

  lines = atoi(argv[3]);

  out = fopen(argv[4], "a");

  if (out == NULL) {

     perror("File could not be opened");

     return 0;

  }

  for (x = 0; x < ints; x++) {

     int n = ReadInteger();

     printf("%d\n", n);

     fprintf(out, "%d\n", n);

  }

  for (y = 0; y < doubles; y++) {

     double d = ReadDouble();

     printf("%lf\n", d);

     fprintf(out, "%lf\n", d);

  }

  for (z = 0; z < lines; z++) {

     char *l = ReadLine();

     printf("%s\n", l);

     fprintf(out, "%s\n", l);

     free(l);

  }

  fclose(out);

  return 0;

}

int checkInt(char *arg) {

  int x;

  x = 0;

  while (arg[x] != '\0') {

     if (arg[x] > '9' || arg[x] < '0') {

        printf("Improper input. x, y, and z must be ints.\n");

        return -1;

     }

     x++;

  }

  return 0;

}

myio.c

#include <limits.h>

#include <stdio.h>

#include <stdlib.h>

#include <unistd.h>

char *ReadInput(int fd) {

  char buf[BUFSIZ];

  int i;

  char *input;

  int r, ret, x;

  i = 1;

  r = 0;

  ret = 1;

  input = calloc(BUFSIZ, sizeof(char));

  while (ret > 0) {

     ret = read(fd, &buf, BUFSIZ);

     for (x = 0; x < BUFSIZ; x++) {

        if (buf[x] == '\n' || buf[x] == EOF) {

           ret = -1;

           break;

        }

        input[x*i] = buf[x];

        r++;

     }

     i++;

     if (ret != -1)

        input = realloc(input, BUFSIZ*i);

  }

  if (r == 0)

     return NULL;

  input[r] = '\0';

  input = realloc(input, r+1);

  return(input);

}

int ReadInteger() {

  char *input;

  int go, num, x;

  go = 0;

  do {

     go = 0;

     printf("Input an integer\n");

     input = ReadInput(STDIN_FILENO);

     for (x = 0; x < INT_MAX; x++) {

        if (x == 0&& input[x] == '-')

           continue;

        if (input[x] == 0)

           break;

        else if (input[x]> '9' || input[x] < '0') {

           go = 1;

           printf("Improper input\n");

           break;

        }

    }

  } while (go == 1);

  num = atoi(input);

  free(input);

  return num;

}

double ReadDouble(void) {

  int dec, exp;

  char *input;

  int go;

  double num;

  int x;

  do {

     go = 0;

     dec = 0;

     exp = 0;

     printf("Input a double\n");

     input = ReadInput(STDIN_FILENO);

     for (x = 0; x < INT_MAX; x++) {

        if (x == 0&& input[x] == '-')

           continue;

        if (input[x] == 0)

           break;

        else if (input[x] == '.' && dec == 0)

           dec = 1;

        else if (x != 0&& (input[x] == 'e' || input[x] == 'E') && exp == 0) {

           dec = 1;

           exp = 1;

        }

        else if (input[x]> '9' || input[x] < '0') {

           go = 1;

           printf("Improper input\n");

           break;

        }

     }

  } while (go == 1);

  num = strtod(input, NULL);

  free(input);

  return num;

}

char *ReadLine(void) {

  printf("Input a line\n");

  return(ReadInput(STDIN_FILENO));

}

char *ReadLineFile(FILE *infile) {

  int fd;

  fd = fileno(infile);

  return(ReadInput(fd));

}

myio.h

#ifndef _myio_h

#define _myio_h

/*

* Function: ReadInteger

* Usage: i = ReadInteger();

* ------------------------

* ReadInteger reads a line of text from standard input and scans

* it as an integer. The integer value is returned. If an

* integer cannot be scanned or if more characters follow the

* number, the user is given a chance to retry.

*/

int ReadInteger(void);

/*

* Function: ReadDouble

* Usage: x = ReadDouble();

* ---------------------

* ReadDouble reads a line of text from standard input and scans

* it as a double. If the number cannot be scanned or if extra

* characters follow after the number ends, the user is given

* a chance to reenter the value.

*/

double ReadDouble(void);

/*

* Function: ReadLine

* Usage: s = ReadLine();

* ---------------------

* ReadLine reads a line of text from standard input and returns

* the line as a string. The newline character that terminates

* the input is not stored as part of the string.

*/

char *ReadLine(void);

/*

* Function: ReadLine

* Usage: s = ReadLine(infile);

* ----------------------------

* ReadLineFile reads a line of text from the input file and

* returns the line as a string. The newline character

* that terminates the input is not stored as part of the

* string. The ReadLine function returns NULL if infile

* is at the end-of-file position. Actually, above ReadLine();

* can simply be implemented as return(ReadLineFile(stdin)); */

char *ReadLineFile(FILE *infile);

Answer: Provided in the explanation section

Explanation:

(a). BIND is a type of DNS server used on the internet, actually it is reported to be most widely used DNS server on the internet. Also BIND is the de-facto standard on Unix like operating systems and Linux. Thus it can be used to locate computers on a network using domain names instead of their IP addresses. BIND was originally programmed at the University of California, Berkeley in the 1980s, this was made possible by a grant from US based DARPA program.

Originally, BIND stood for Berkeley Internet name daemon, but nowadays it is called Berkeley Internet name domain.

(b). In some of the clients in windows and Windows servers we will install LDP. By the LDP.exe we can test tDNS, Active directory woking , even we can add or modify. LDP is used to test and verify the Active Directory objects. We will install in windows machine then open the software, then from the menu we will select connect and type the IP adress of the Active Directory then we will select or type the objects of Active directory. For Linux system we have to openldap and can search the AD.

From Linux or Unix we can use the nmap tool which can test the network connectivity between all the computers whether it is windows or Linux. By nmap we can test by ICMP protocol to verify the network connectivity. By nmap we can scan all the port which are required to open from client to the server. We can also use nslookup to test DNS server from the client. By nslookup we can check that client can connect the server.

Find the given attachments

Answer:

w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]

for i in range (len(w)):

   print(w[i].upper())

Explanation:

every element needs to be upper cased

A loop that prints the words in uppercase letters is written below with the help of Python.

Simply said, a function is a "chunk" of code that you may reuse repeatedly so instead of having to write it out several times. Software developers can divide an issue into smaller, more manageable parts, which can each carry out a specific task, using functions.

A function, according to a technical definition, is a relationship between an amount of parameters and a set of potential outputs, where every other input is connected to precisely one output.

All the functions are to be written in uppercase:

w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]

for i in range (len(w)):

  print(w[i].upper())

Learn more about function, Here:

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