ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions.

ASAP! GIVING BRAINLIEST! Please Read The Question THEN Answer CORRECTLY! NO Guessing. I Say No Guessing

Answers

Answer 1

Answer:

B. 4x² - 20x  + 26

Step-by-step explanation:

→Set it up, like so:

(2x - 5)² + 1

4x² - 20x + 25 + 1

→Add like terms (25 and 1):

4x² - 20x + 26


Related Questions

1. OSHA is an agency responsible for workplace safety, read its rule and sketch a diagram that shows the proper relationship between the ladder, wall and ground

Answers

Completed Question

1. OSHA is an agency responsible for workplace safety, read its rule and sketch a  diagram that shows the proper relationship between the ladder, wall and ground .

Rule: Non-self-supporting ladders, which must lean against a wall or other support, are to be positioned at such an angle  that the horizontal distance from the top support to the foot of the ladder is about the 1/4 working length of the ladder.

2. Calculate the angle that the ladder makes with the ground using a trigonometric ratio.

3. If a ladder is x feet long, how high up a wall can it safely reach?

4. Would a 51-foot ladder be long enough to climb a 50-foot wall?

Answer:

(a)See attachment

(b)75.52 degrees

(c)[tex]Height ,h=\dfrac{x\sqrt{15}}{4} $ feet[/tex]

(d) NO

Step-by-step explanation:

Part 1

Let the length of the ladder =x

Since by the given rule, Horizontal Distance =[tex]\dfrac14$ of the length of the ladder[/tex]

Horizontal Distance = [tex]\dfrac14x[/tex]

In the sketch of the problem attached below,

The length of the ladder=ACHorizontal distance =BC

Part 2

From Triangle ABC

[tex]\cos C=\dfrac{BC}{AC} \\\cos C=\dfrac{x/4}{x} \\\cos C=\dfrac{1}{4}\\ C=\arccos \dfrac{1}{4}\\C \approx 75.52^\circ[/tex]

The angle that the ladder makes with the ground is 75.52 degrees.

Part 3

If the ladder is x feet long

Using Pythagoras theorem in Triangle ABC below

[tex]x^2=(x/4)^2+h^2\\h^2=x^2-\dfrac{x^2}{16}\\ h^2=\dfrac{15x^2}{16}\\h=\sqrt{\dfrac{15x^2}{16}} \\h=\dfrac{x\sqrt{15}}{4}$ feet[/tex]

Part 4

If x=51 feet

[tex]Height ,h=\dfrac{51\sqrt{15}}{4}$ = 49.38 feet[/tex]

Therefore, a 51 feet ladder would not be enough to climb a 50 feet wall as it would violate the safety rule.

Assignment
Use the function f(x) = 2x3 - 3x2 + 7 to complete the exercises.
f(-1) =
f(1) =
f(2)=
>

Answers

Answer:

The value of the function f(x) at x=a can be determined by substituting a instead of x into the function expression.

1. When x=-1, then

f(-1) = 2 * (-1)^3 - 3 * (-1)^2 + 7 = -2 - 3 + 7 = 2.

2. When x=1, then

f(1) = 2 * 1^3 - 3 * 1^2 + 7 = 2 - 3 + 7 = 6.

3. When x=2, then

f(-1) = 2 * 2^3 - 3 * 2^2 + 7 = 16 - 12 + 7 = 11.

Step-by-step explanation:

Answer:

f(−1) =✔ 2

f(1) = ✔ 6

f(2) =✔ 11

Step-by-step explanation:

~I will mark as BRANLIEST and give you 55 points if you answer correctly.

Answers

Answer:

The lines would intersect at: (6, -4)

Step-by-step explanation:

I graphed both lines.

Answer:

(4,-2)

Step-by-step explanation:

The equation for the graphed line is [tex]y=\frac{1}{2} x-4[/tex] as it has a slope of [tex]\frac{1}{2}[/tex] and a y-intercept of -4.

Now that we have the two equations, we can set them equal to each other to find the x-value at which they intersect

[tex]\frac{1}{2} x-4=-x+2[/tex]

First, we can add 4 to each side

[tex]\frac{1}{2} x=-x+6[/tex]

Then we can add x to each side

[tex]\frac{3}{2} x=6[/tex]

Now we need to divide both side by [tex]\frac{3}{2}[/tex], which is the same thing as multiplying by [tex]\frac{2}{3}[/tex]

[tex]x=6*\frac{2}{3} \\\\x=\frac{12}{3} \\\\x=4[/tex]

Now that we have the x-value, we can plug it into one of the equations to see the y-value for where they intersect.

[tex]y=-x+2\\\\y=-(4)+2\\\\y=-2[/tex]

This means that the coordinates for the intersection of these two lines would be [tex](4,-2)[/tex]

I really need help :( anybody ??

Answers

_______________________________

Hey!!

Answer:{2,4,5}

Explanation:

Range

Let R be relation from A to B.The set of second components or the set of elements of B are called range.

Hope it helps..

_______________________________

Triangle XYZ, XY= 80, ZY= 64 XZ= 48 what is the cosine

Answers

Answer:

[tex]cos=\frac{4}{5}[/tex]

Step-by-step explanation:

Cosine is the adjacent side over the hypotenuse (You can remember sin, cos, and tan by using sohcahtoa or sin = opposite/hypotenuse, cos = adjacent/hypotenuse, tan = opposite over adjacent). I think a picture would help, too.

I attached a picture of what I think the triangle would look like.

If the picture is right (we're assuming it is) and going with what we're given (the triangle was addressed as triangle XYZ, meaning that angle Y is in the middle and that's the one we'll use).

Looking at my picture then:

[tex]cos=\frac{64}{80} \\cos=\frac{8}{10} \\cos=\frac{4}{5}[/tex] .

simplify 8-(3a+8)=
havent done these in a while so...​

Answers

Answer:

3

Step-by-step explanation:

8-(3a+8)

8-(11a)

8-11a

a=11-8

a=3

Answer:

0

Step-by-step explanation:

8-(3a+8)=0

8-3a-8=0

-3a=0

a=0

angle x is coterminal with gale y. if the measure of angle x is greater than the measure of angle y which statement is true regarding the values of x and y

Answers

Answer:

The answer is C

Step-by-step explanation:

did the quiz

Answer:

He is right it C just did the quiz let him have the brainly ;)

Step-by-step explanation:

Jose runs a factory that makes stereo tuners. Each S100 takes 8 ounces of plastic and 4 ounces of metal. Each FS20 requires 4 ounces of plastic and 6 ounces of metal. The factory has 312 ounces of plastic, 372 ounces of metal available, with a maximum of 20 S100 that can be built each week. If each S100 generates $7 in profit, and each FS20 generates $13, how many of each of the stereo tuners should Jose have the factory make each week to make the most profit

Answers

Answer: Jose should have the factory make 50 FS20 stereo tuners and 14 S100 stereo tuners each week to make the most profit

Step-by-step explanation:

Since each S100 takes 8 ounces of plastic and 4 ounces of metal. Each FS20 requires 4 ounces of plastic and 6 ounces of metal. And the factory has 312 ounces of plastic, 372 ounces of metal available, then,

For plastic

8 ounces + 4 ounces = 12 ounces

The number of stereo tuners it can produce will be

312/12 = 26 stereo tuners

For metal

4 ounces + 6 ounces = 10 ounces

The number of stereo tuners it can produce will be

372/10 = 37.2 = 37 approximately

Since FS20 generate more profit than S100, let assume that Jose produces 50 FS20 by consuming

4 × 50 = 200 ounces of plastic

6 × 50 = 300 ounces of metal

The remaining plastic will be

312 - 200 = 112

The remaining plastic will be

372 - 300 = 72

Divide 112 by 8 in order to make S100

112/8 = 14

Also 72/4 = 18.

Therefore, Jose should have the factory make 50 FS20 stereo tuners and 14 S100 stereo tuners each week to make the most profit

convert 3.9cm to hm​

Answers

Answer:

Step-by-step explanation:

0.00039 hm

Answer:

0.00039 hm is ur answer....

3.9 cm to 0.00039 hm...

Mark me as Brainlist...

THIS QUESTION IS KILLING ME
Calculate the volume of the object by using the triple integral.

Answers

The volume of the solid (call it S) in Cartesian coordinates is

[tex]\displaystyle\iiint_S\mathrm dV=\int_{-1}^1\int_{-\sqrt{1-x^2}}^{\sqrt{1-x^2}}\int_{(x^2+y^2)^2-1}^{4-4(x^2+y^2)}\mathrm dz\,\mathrm dy\,\mathrm dx[/tex]

but I suspect converting to cylindrical coordinates would make the integral much more tractable.

Take

[tex]\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=z\end{cases}\implies\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz[/tex]

Then

[tex]4-4(x^2+y^2)=4-4r^2=4(1-r^2)[/tex]

[tex](x^2+y^2)^2-1=(r^2)^2-1=r^4-1[/tex]

and the integral becomes

[tex]\displaystyle\iiint_S\mathrm dV=\int_0^{2\pi}\int_0^1\int_{r^4-1}^{4(1-r^2)}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]

[tex]=\displaystyle2\pi\int_0^1r(4(1-r^2)-(r^4-1))\,\mathrm dr[/tex]

[tex]=\displaystyle2\pi\int_0^1r(5-4r^2-r^4)\,\mathrm dr[/tex]

[tex]=\displaystyle2\pi\int_0^15r-4r^3-r^5\,\mathrm dr[/tex]

[tex]=2\pi\left(\dfrac52-1-\dfrac16\right)=\boxed{\dfrac{8\pi}3}[/tex]

You get tired of the sand and head up to the amusement park. You can purchase 20 ride tickets for $14 or you can purchase 30 ride tickets for $22.50. Which is a better deal?

Answers

Answer:

The one with the better deal would be 30 ride tickets for $22.50 this is because you pay less money for more rides.

Step-by-step explanation:

First you divide 20 by 14. Doing this will give you the cost of a ride per ticket.

20/14 = 1.42

Then you do the same thing to 30 and 22.50.

30/22.50 = 1.30

Last you compare which deal has less money per ride.

1.42 > 1.30

Eliminate the variable t from the set of parametric equations. Graph the equation X=5cost Y=5sint Please explain this, I need to know how to do these kinds of equations for my trig final

Answers

Answer:

x^2 + y^2 = 25

Step-by-step explanation:

x = 5 cos t

            cos t = x/5

y = 5 sin t

           sin t = y/5

cos^2 t + sin^2 t = 1

(x/5)^2 + (y/5)^2  = 1

x^2/25 + y^2/25 = 1

(x^2 + y^2)/25 =1

x^2 + y^2 = 25

As a birthday gift, you are mailing a new personal digital assistant (PDA) to your cousin in Toledo. The PDA cost $414. There is a 3 percent chance it will be lost or damaged in the mail. Is it worth $4 to insure the mailing?Explain, using the concept of expected value.

Answers

Answer:

It is worth $4 to insure the mailing.

Step-by-step explanation:

The random variable X can be defined as the money value.

The PDA costs, $414.

It is provided that there is a 3% chance it will be lost or damaged in the mail.

So, there is 97% chance it will not be lost or damaged in the mail.

The insurance costs $4.

If the PDA is lost or damaged in the mail when there is no insurance the money value would be of -$414.

And if the PDA is lost or damaged in the mail when there is an insurance the money value would be of $414 - $4 = $410.

Compute the expected value of money as follows:

[tex]\text{E (X)}=(0.97\times 410)+(0.03\times -414)[/tex]

          [tex]=397.7-12.42\\=385.28[/tex]

The expected value of money in case the PDA is lost or damaged in the mail or not is $385.28.

Thus, it is worth $4 to insure the mailing.

The differential equation below models the temperature of a 91°C cup of coffee in a 17°C room, where it is known that the coffee cools at a rate of 1°C per minute when its temperature is 70°C. Solve the differential equation to find an expression for the temperature of the coffee at time t. dy dt = − 1 53 (y − 17)\

Answers

Answer:

[tex]t \approx 17.690\,min[/tex]

Step-by-step explanation:

This differential equation is a first order linear differential equation with separable variables, whose solution is found as follows:

[tex]\frac{dy}{dt} = - \frac{1}{53} \cdot (y - 17)[/tex]

[tex]\frac{dy}{y-17} = -\frac{1}{53} \, dt[/tex]

[tex]\int\limits^{y}_{y_{o}} {\frac{dy}{y-17} } = -\frac{1}{53} \int\limits^{t}_{0}\, dx[/tex]

[tex]\ln \left |\frac{y-17}{y_{o}-17} \right | = -\frac{1}{53} \cdot t[/tex]

[tex]\frac{y-17}{y_{o}-17} = e^{-\frac{1}{53}\cdot t }[/tex]

[tex]y = 17 + (y_{o} - 17) \cdot e^{-\frac{1}{53}\cdot t }[/tex]

The solution of the differential equation is:

[tex]y = 17 + 74\cdot e^{-\frac{1}{53}\cdot t }[/tex]

Where:

[tex]y[/tex] - Temperature, measured in °C.

[tex]t[/tex] - Time, measured in minutes.

The time when the cup of coffee has the temperature of 70 °C is:

[tex]70 = 17 + 74 \cdot e^{-\frac{1}{53}\cdot t }[/tex]

[tex]53 = 74 \cdot e^{-\frac{1}{53}\cdot t }[/tex]

[tex]\frac{53}{74} = e^{-\frac{1}{53}\cdot t }[/tex]

[tex]\ln \frac{53}{74} = -\frac{1}{53}\cdot t[/tex]

[tex]t = - 53\cdot \ln \frac{53}{74}[/tex]

[tex]t \approx 17.690\,min[/tex]

what is the value of this expression plssssss 8z-3 when z =7

Answers

Answer:

53

Step-by-step explanation:

8•7 is 56

56 - 3 is 53

Answer:

53

Step-by-step explanation:

z = 7

8z is the same as saying 8×z

8×7-3 (do multiplication first)

56-3 = 53

There is a bag with only milk and dark chocolates.
The probability of randomly choosing a dark chocolate is
2/9.
There are 24 dark chocolates in the bag and each is equally likely to be chosen.
Work out how many milk chocolates there must be.

Answers

Answer:

80 milk chocolates

Step-by-step explanation:

Probability of choosing a dark chocolate= number of dark

chocolate/number of total

chocolate

But the probability of choosing dark chocolate= 2/9

The number of dark chocolate= 24

Total chocolate= number of dark

chocolate/probability

of choosing dark

chocolate

Total chocolate= 24/(2/9)

Total chocolate=( 24*9)/2

Total chocolate= 108

Number of milk chocolate= total- dark

Number of milk chocolate

= 108-28

= 80

Let A be an n # n matrix, b be a nonzero vector, and x0 be a solution vector of the system Ax D b. Show that x is a solution of the nonhomogeneous system Ax D b if and only if y D x!x0 is a solution of the homogeneous system Ay D 0.

Answers

Complete Question

Let A be an n x n matrix, b be a nonzero vector, and x_0 be a solution vector of the system Ax = b. Show that x is a solution of the non-homogeneous system Ax = b if and only if y = x - x_0 is a solution of the homogeneous system Ay = 0.

Answer:

Step-by-step explanation:

From the question we are told that

    A is an  n × n matrix

   b is a zero vector

  [tex]x_o[/tex] us the solution vector of  [tex]Ax = b[/tex]

Which implies that  

     [tex]Ax_o = b[/tex]

So first we show that

  if [tex]x[/tex] is the solution matrix of [tex]Ax = b[/tex]

  and  [tex]y= x-x_o[/tex] is the solution of  [tex]Ay = 0[/tex]

Then

    [tex]A(x-x_o) = 0[/tex]

=>   [tex]Ax -Ax_o = 0[/tex]

=>   [tex]b-b = 0[/tex]

Secondly to show that

   if  [tex]y= x-x_o[/tex] is the solution of  [tex]Ay =0[/tex]

  then x is the solution of the non-homogeneous system

    [tex]Ax = b[/tex]

Now we know that [tex]y = x-x_o[/tex] is the solution of  [tex]Ay =0[/tex]

So

     [tex]Ay = 0[/tex]

=>  [tex]A(x- x_o) = 0[/tex]

=>   [tex]Ax - Ax_o = 0[/tex]

=>   [tex]Ax - b = 0[/tex]

=>    [tex]Ax = b[/tex]

Thus this has been proved

Does this graph represent a function? Why or why not?
10+
8+
6-
110884
-8
O
A. No, because it is not a straight line.
B. Yes, because it passes the horizontal line test.
Ο Ο Ο
C. Yes, because it passes the vertical line test.
D. No, because it fails the vertical line test.

Answers

Answer:

Option (C).

Step-by-step explanation:

In the graph attached,

An absolute function has been given.

To check a graph whether it's a relation or a function, vertical line test is a trusted tool.

In vertical line test a vertical line (parallel to y-axis) is drawn passing through the graph.

If the vertical line cuts the graph at only one point then the graph is said to be a function.

The given graph passes the vertical test.

Therefore, it's a function.

Option C. will be the answer.

Yes, this graph represents a function, because it passes the vertical line test. Option C is correct

What exactly is a function?

A function is a statement, rule, or law that specifies the connection between two variables. Functions are common in mathematics and are required for the formulation of physical connections.

An absolute function is shown in the graph that is attached. The vertical line test is a reliable method for determining if a graph represents a relation or a function.

In the vertical line test, a vertical line that is parallel to the y-axis and cuts through the graph is created. The graph is considered to be a function if the vertical line only intersects it once.

The vertical test is passed by the shown graph. It serves a purpose as a result.

Hence option C is correct.

To learn more about the function, refer to:

https://brainly.com/question/5245372

#SPJ5

what is the x-intercept of the line 10x-5y=40

Answers

Answer:

4

Step-by-step explanation:

The x-intercept occurs when y=0, if you think about it graphically.  Plug y=o into your equation:

10x - 5(0) = 40

10x = 40 (divide each side by 10)

x=4

A broker has calculated the expected values of two different financial instruments X and Y. Suppose that E(x)= $100, E(y)=$90 SD(x)= 90$ and SD(y)=$8. Find each of the following.

a. E(X+ 10) and SD(X+ 10)
b. E(5Y) and SD(5Y)
c) E(X+ Y) and SD(X+ Y)
d) What assumption must you make in part c?

Answers

Expectation is linear, meaning

E(a X + b Y) = E(a X) + E(b Y)

= a E(X) + b E(Y)

If X = 1 and Y = 0, we see that the expectation of a constant, E(a), is equal to the constant, a.

Use this property to compute the expectations:

E(X + 10) = E(X) + E(10) = $110

E(5Y) = 5 E(Y) = $450

E(X + Y) = E(X) + E(Y) = $190

Variance has a similar property:

V(a X + b Y) = V(a X) + V(b Y) + Cov(X, Y)

= a^2 V(X) + b^2 V(Y) + Cov(X, Y)

where "Cov" denotes covariance, defined by

E[(X - E(X))(Y - E(Y))] = E(X Y) - E(X) E(Y)

Without knowing the expectation of X Y, we can't determine the covariance and thus variance of the expression a X + b Y.

However, if X and Y are independent, then E(X Y) = E(X) E(Y), which makes the covariance vanish, so that

V(a X + b Y) = a^2 V(X) + b^2 V(Y)

and this is the assumption we have to make to find the standard deviations (which is the square root of the variance).

Also, variance is defined as

V(X) = E[(X - E(X))^2] = E(X^2) - E(X)^2

and it follows from this that, if X is a constant, say a, then

V(a) = E(a^2) - E(a)^2 = a^2 - a^2 = 0

Use this property, and the assumption of independence, to compute the variances, and hence the standard deviations:

V(X + 10) = V(X)  ==>  SD(X + 10) = SD(X) = $90

V(5Y) = 5^2 V(Y) = 25 V(Y)  ==>  SD(5Y) = 5 SD(Y) = $40

V(X + Y) = V(X) + V(Y)  ==>  SD(X + Y) = √[SD(X)^2 + SD(Y)^2] = √8164 ≈ $90.35

A credit card company monitors cardholder transaction habits to detect any unusual activity. Suppose that the dollar value of unusual activity for a customer in a month follows a normal distribution with mean $250 and variance $2400.
(a) What is the probability of $250 to $294 in unusual activity in a month? Round your answer to four decimal places (e.g. 98.7654) P-0.4861
(b) What is the probability of more than $294 in unusual activity in a month? Round your answer to four decimal places (e.g. 98.7654) P 0.0139
(c) Suppose that 10 customer accounts independently follow the same normal distribution. What is the probability that at least one of these customers exceeds $294 in unusual activity in a month? Round your answer to four decimal places (e.g. 98.7654)

Answers

Answer:

Step-by-step explanation:

Let x be the random variable representing the dollar value of unusual activity for a customer in a month. Since it is normally distributed and the population mean and population standard deviation are known, we would apply the formula,

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = 250

σ = √variance = √2400 = 48.99

a) the probability of $250 to $294 in unusual activity in a month is expressed as

P(250 ≤ x ≤ 294)

For x = 250,

z = (250 - 250)/48.99 = 0

Looking at the normal distribution table, the probability corresponding to the z score is 0.5

For x = 294

z = (294 - 250)/48.99 = 0.9

Looking at the normal distribution table, the probability corresponding to the z score is 0.8159

Therefore,

P(250 ≤ x ≤ 294) = 0.8159 - 0.5 = 0.3159

b) the probability of more than $294 in unusual activity in a month is expressed as

P(x > 294) = 1 - P(x < 294)

P(x > 294) = 1 - 0.8159 = 0.1841

c) since n = 10, the formula becomes

z = (x - µ)/(σ/n)

z = (294 - 250)/(48.99/√10) = 2.84

Looking at the normal distribution table, the probability is 0.9977

Therefore, the probability that at least one of these customers exceeds $294 in unusual activity in a month is

1 - 0.9977 = 0.0023

What’s the correct answer for this question?

Answers

Answer:

B) (1,2,3,4,5,6,7,8)

Step-by-step explanation:

The answer is B because the union of a set represents everything thing that is within the sets.

76,80,88,95,100,101,? Which number comes next in this sequence?

Answers

Answer:

112

Step-by-step explanation:

Difference between each 4,8,7,5,1

Add numbers next to each other in pairs = 12

So 12-1= 11 and

101+11=112

If a procedure meets all the conditions of a binomial distribution except that the number of trials is not fixed, then the geometric distribution can be used. The probability of getting the first success on the xth trial is given by
P
(
x
)
=
p
(
1

p
)
x

1
where
p
is the probability of success on any one trial.

Assume that the probability of a defective computer component is 0.21. Find the probability that the first defect is found in the fifth component tested.
(Round answer to four decimal places.)
P
(
5
)
=

Answers

Answer:

M.

Step-by-step explanation:

TWO PLANES INTERSECT IN A
A. point
B. Ray
C. Line
D. Line segments

Answers

Answer:

c. line

Step-by-step explanation:

the intersection of two planes is called a line

Answer:

Hello dear,

two planes intersect and forms line

so yaa your answer is C)

Hope I helped you ;)

please thank me !!!

satsriakal ji

Richard and Stephen win some money and share it in the ratio 6:1. Richard gets £60 more than Stephen. How much did they get altogether?

Answers

Answer:

They got £84 altogether.

Step-by-step explanation:

We can see that Richard get's 6 parts and Stephen gets 1 part. We can subtract these two to get 5 parts. We know that five parts equals £60, so we can divide by 5 to get 1 part equals £12. We are looking for the amount they got altogether, which is equal to 7 parts, 6 parts + 1 part. We multiply £12 by 7, leaving us with £84, which is our answer.

Which answer is equivalent to the equation shown below?
7c = 49
A.log7 c = 49
B.c = log49 7
C.logc49 = 7
D.c = log7 49

Answers

Answer:

D.

Step-by-step explanation:

The base of a log is also the base of an exponent. So 7 to the c power, our 7 would be the base. To find c, we simply just do log base 7 of 49, which comes out to be 2.

Answer: D
Hope this helped

Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that the highest bid in excess of $10,400 will be accepted. Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,400 and $15,400.

Required:
a. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?
b. Suppose you bid $14,000. What is the probability that your bid will be accepted (to 2 decimals)?
c. What amount should you bid to maximize the probability that you get the property (in dollars)?

Answers

Answer:

a) 0.32 = 32% probability that your bid will be accepted

b) 0.72 = 72% probability that your bid will be accepted

c) An amount in excess of $15,400.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

[tex]P(X \leq x) = \frac{x - a}{b-a}[/tex]

Assume that the competitor's bid x is a random variable that is uniformly distributed between $10,400 and $15,400.

This means that [tex]a = 10400, b = 15400[/tex]

a. Suppose you bid $12,000. What is the probability that your bid will be accepted (to 2 decimals)?

You will win if the competitor bids less than 12000. So

[tex]P(X \leq 12000) = \frac{12000 - 10400}{15400 - 10400} = 0.32[/tex]

0.32 = 32% probability that your bid will be accepted

b. Suppose you bid $14,000. What is the probability that your bid will be accepted?

You will win if the competitor bids less than 14000. So

[tex]P(X \leq 14000) = \frac{14000 - 10400}{15400 - 10400} = 0.72[/tex]

0.72 = 72% probability that your bid will be accepted

c. What amount should you bid to maximize the probability that you get the property (in dollars)?

His bid is uniformly distributed between $10,400 and $15,400.

So, to maximize the probability that you get the property, you should bid an amount in excess of $15,400.

The notation f:S→T denotes that f is a function, also called a map , defined on all of a set S and whose outputs lie in a set T . A function f:S→T is injective if for all x,y∈S , f(x)=f(y) implies that x=y . Alternatively: a function is injective if we can uniquely recover some input x based on an output f(x) . What functions are injective?

Answers

Answer:

There are many. Two examples are

[tex]f(x) = x, \\f(x) = x^3[/tex]

Step-by-step explanation:

There are many examples. The simplest is

1 -

[tex]f(x) = x[/tex]

It is trivial that

[tex]\text{if \,\,\,\,} f(x) = f(y) \,\,\,\,\,\text{then} \,\,\,\,\, x=y[/tex]

2 -

[tex]f(x) = x^3[/tex]

That function is injective as well.

[tex]\text{if \,\,\,\,} x^3 = y^3 \,\,\,\,\,\text{then} \,\,\,\,\, x=y[/tex]

An example of a function that is NOT injective is

[tex]f(x) = x^2[/tex]

Notice that

[tex]f(-2) = (-2)^2 = 2^2 = 4[/tex]

The area of a circle is 18 pi square inches. If the area of a sector of this circle is 6 pi square inches, then
which of the following must be the sector's central angle?

Answers

Answer:

120°

Step-by-step explanation:

Area of a sector = [tex]\frac{\theta}{360} * \pi r^{2}\ where\ \pi r^{2} \ is\ the\ area\ of\ the\ circle[/tex]

theta is the sector's central angle

Area of the sector = [tex]\frac{\theta}{360} * \ area\ of\ a\ circle[/tex]

Given area of a circle = 18πin² and area of a sector = 6πin²

On substituting;

6π = [tex]\theta/360 * 18 \pi[/tex]

Dividing both sides by 18π we have;

1/3 = [tex]\theta/360[/tex]

[tex]3 \theta = 360\\\theta = 360/3\\\theta = 120^{0}[/tex]

The sector's central angle is 120°

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