Answer:
22,203 ft^2
Step-by-step explanation:
The area of a triangle with angle ∅ and two sides a and b is;
Area A = 1/2 × absin∅ ......1
The park is in the shape of a triangle, with two sides and an angle given;
Given;
a = 190 ft
b = 235 ft
∅ = 84°
Substituting the values into equation 1;
Area of the park;
A = 1/2 × 190 × 235 × sin84°
A = 22,202.70131409 ft^2
A = 22,203 ft^2 (to the nearest whole number)
Area of the park is 22,203 ft^2
Indicate which of the following situations inferential statistics: a. An annual stockholders' report details the assets of the corporation. b. A history instructor tells his class the number of students who received an A on a recent exam. c. The mean of a sample set of scores is calculated to characterize the sample. d. The sample data from a poll are used to estimate the opinion of the population. e. A correlational study is conducted on a sample to determine whether educational level and income in the population are related. f. A newspaper article reports the average salaries of federal employees from data collected on all federal employees.
Answer:
The situations c, d and e are Inferential statistics.
Step-by-step explanation:
Inferential statistics is used to determine reasons for a situation or phenomenon. It helps to draw conclusions grounded on extrapolations, and is hence fundamentally dissimilar from descriptive statistics that only summarizes the data that has truly been measured.
Descriptive statistics are short-term descriptive coefficients that condenses a given data set, which can be a demonstration of the whole or a sample of a whole population.
All descriptive statistics are either central tendency measure or variability measure. Measures of central tendency define the epicenter position of a distribution for a data set.
From the provided situations the Inferential statistics are:
c. The mean of a sample set of scores is calculated to characterize the sample.
d. The sample data from a poll are used to estimate the opinion of the population.
e. A correlational study is conducted on a sample to determine whether educational level and income in the population are related.
Thus, the situations c, d and e are Inferential statistics.
The one that demonstrates inferential statistics would be:
c). The mean of a sample set of scores is calculated to characterize the sample.
d). The sample data from a poll are used to estimate the opinion of the population.
e). A correlational study is conducted on a sample to determine whether the educational level and income in the population are related.
Inferential StatisticsInferential statistics is denoted as the kind of statistics that is concluded through a small sample employed which will act as the representative of the larger population.
The smaller sample's characteristics are analyzed and deductions are made in general about the entire population.
The above statements exemplify these characteristics by calculating the mean of the sample population and performing a correlational examination.
Thus, options c, d, and e are the correct answers.
Learn more about "Statistics" here:
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Round 90.2844097979 to 3 decimals
Answer:
only allow 3 decimals
90.284 is the answer we removed all others except for 3
Suppose that a population of people has an average weight of 160 lbs, and standard deviation of 50 lbs, and that weight is normally distributed. A researcher samples 100 people, and measures their weight. Find the probability that the researcher observes an average weight of the 100 people to be between 150 and 170. [Round your answer to four decimal places]
Answer:
0.9544 = 95.44% probability that the researcher observes an average weight of the 100 people to be between 150 and 170.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
[tex]\mu = 160, \sigma = 50, n = 100, s = \frac{50}{\sqrt{100}} = 5[/tex]
Find the probability that the researcher observes an average weight of the 100 people to be between 150 and 170.
This is the pvalue of Z when X = 170 subtracted by the pvalue of Z when X = 150. So
X = 170
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{170 - 160}{5}[/tex]
[tex]Z = 2[/tex]
[tex]Z = 2[/tex] has a pvalue of 0.9772
X = 150
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{150 - 160}{5}[/tex]
[tex]Z = -2[/tex]
[tex]Z = -2[/tex] has a pvalue of 0.0228
0.9772 - 0.0228 = 0.9544
0.9544 = 95.44% probability that the researcher observes an average weight of the 100 people to be between 150 and 170.
In how many ways can a president and a vice president be randomly selected from a class of 20 students?
Answer:
n how many ways can a president, vice president, and a secretary be chosen? It is 12X11X10. Permutation of n things taken r at a time: nPr=n!/(n-r)! 12P3=12*11*10*9!/9!= 12*11*10=1320 ways.
Step-by-step explanation:
16 of 22
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Sample Space: Tutorial
Activity
In this exercise, you'll use the formula for the probability of the complement of an event.
Another game you've set up at casino night involves rolling a fair six-sided die followed by tossing a fair coin. In this game, players earn points
depending on the number they get on the die and which side of the coin turns up. For example, the player earns 5 points for getting (2, tails).
Question 1
Find the total number of possible outcomes in each trial of this game.
Answer:
The number of possible outcomes in each trial of this game is 12
Step-by-step explanation:
Given
Rolling of a 6 sided die followed by tossing of a fair coin
Required
Number of possible outcomes
The first step is to list out the possible outcomes of rolling a die and tossing a coin
Rolling a fair die = {1,2,3,4,5,6}
Tossing a coin = {Head, Tail}
Let Head be represented by H and Tail be represented by T;
So,
Rolling a fair die = {1,2,3,4,5,6}
Tossing a coin = {H, T}
The question states that a roll of a 6 sided die is followed by a toss of a fair coin
This means that each trial is {A roll of die and A toss of coin}
So, the sample space is as follows
Sample Space = {1H, 2H, 3H, 4H, 5H, 6H, 1T, 2T, 3T, 4T, 5T, 6T}
Number of outcomes in the sample space is 12.
Hence, the number of possible outcomes in each trial of this game is 12
Answer:
the total number of possible outcomes in each trial of this game is 12
Step-by-step explanation:
uhhhhhh none :) kk bye <3
One vertex of a triangle is located at (0, 5) on a coordinate grid. After a transformation, the vertex is located at (5, 0). Which transformations could have taken place? Select two options. R0, 90° R0, 180° R0, 270° R0, –90° R0, –180°
Answer:
The Transformations are R(O , -90°) & R(O , 270)
Step-by-step explanation:
* Lets revise the rotation of a point
- If point (x , y) rotated about the origin by angle 90° anti-clock wise
∴ Its image is (-y , x)
- If point (x , y) rotated about the origin by angle 90° clock wise
(270° anti-clockwise or -90°)
∴ Its image is (y , -x)
- If point (x , y) rotated about the origin by angle 180°
∴ Its image is (-x , -y)
* There is no difference between rotating 180° clockwise (-180°) or
anti-clockwise (180°) around the origin
* Lets solve the problem
∵ One vertex of a triangle is located at (0, 5) on a coordinate grid
∵ The image of the point after the transformation is (5 , 0)
- The coordinates are switched with each other
∴ There is no rotation with 180° or -180° because in the rotation with
180° and -180° around the origin we change only the signs of the
coordinates without switch them
∴ There is a rotation with 90° are 270° or -90°
- The zero has no sign
- When we rotate the point (0 , 5) by -90° or 270° around the origin
we will change the sign of x-coordinate and switch the two
coordinates
∴ The image of the point is (y , -x)
∵ x = 0 and y = 5
- There is no sign for zero, so we switch the coordinates only
∴ The vertex is located at (5, 0)
∴ The Transformations are R(O , -90°) & R(O , 270)
Answer:
R(O , -90°) & R(O , 270)
Step-by-step explanation:
52 is what percent of 93?
Answer:
55.9139785%
Step-by-step explanation:
Is means equals and of means multiply
52 = P * 93
Divide each side by 93
52/ 93 = P
.559139785
Change to percent form
55.9139785%
How many degrees was ABCD rotated?
the answer is 180°
Step-by-step explanation:
because it rotated 2x and 90+90 is 180
In the rectangular prism, express each of the following in terms of s, t, and u. Give an explanation for each of your answers.
(a) HK
(b) GL
(c)JH
Complete Question
The complete question is shown on the first and second uploaded image
Answer:
a
[tex]\= HK = \= t + \= u[/tex]
b
[tex]\= GL = \= s - \= t[/tex]
c
[tex]\= JH = \= u + \= s[/tex]
Step-by-step explanation:
Now looking at the diagram
Following the direction of the unit vectors [tex]\= u , \= s, \= t[/tex]
[tex]\= {HK} = \= {KI} + \= KL[/tex]
=> [tex]\= HK = \= t + \= u[/tex]
And
[tex]\= GL = \= GH + \= GF[/tex] jjj
=> [tex]\= GL = \= s - \= t[/tex]
Also
[tex]\= JH = \= JG + \= JI[/tex]
=> [tex]\= JH = \= u + \= s[/tex]
A garden measuring 12 meters by 6 meters is going to have a walkway constructed all around the perimeter, increasing the total area to 160 square meters. What will be the width of the pathway? (The pathway will be the same width around the entire garden).
Answer:
x=2
Step-by-step explanation:
Original width = 6
New width 6+x+x
Orignal length 12
New length 12+x+x
A = l*w
160 = ( 6+2x) ( 12+2x)
Factor
160 = 2( 3+x) 2(6+x)
Divide each side by 4
40 = (3+x) (6+x)
FOIL
40 = 18+ 6x+3x+ x^2
40 = 18 +9x+x^2
Subtract 40 from each side
0 = x^2 +9x -22
Factor
0 = (x +11) (x-2)
Using the zero product property
x +11 =0 x-2 =0
x= -11 x=2
Since we cannot have a negative sidewalk
x =2
Answer:
2
Step-by-step explanation:
Original width = 6
New width = 6 + x + x = 6 + 2x
Orignal length = 12
New length = 12 + x + x = 12 + 2x
A = l * w
160 = (6 + 2x)(12 + 2x)
160 = 2(3+x) * 2(6+x)
160 = 4 * (3 + x)(6 + x)
160/4 = (3 + x)(6 + x)
40 = 18 + 6x + 3x + x^2
40 = 18 + 9x + x^2
x^2 + 9x - 22 = 0
= x^2 + 11x - 2x - 22 = 0
= x(x + 11) - 2(x + 11) = 0
= (x + 11) (x - 2) = 0
x = - 11, 2
Since we cannot have a negative width because it's a dimension,
x = 2 is right
List the steps taken and find the area of the figure below
6cm
6 CM
6 cm
6 cm
Answer:
36 cm
Step-by-step explanation:
Since all measurements of the figure are the same, that means that this figure is a square. To find the area of a figure multiply length by width. Since this figure is a square and all sides are equal, we multiply 6 by 6 for an area of 36 cm.
A box is a cuboid with dimensions 28cm by 15cm by 20cm all measured to the nearest centimetre.
Disc cases are cuboid which measure 1.5 by 14.2 cm by 19.3 cm all measure to the nearest millimetre. Show that 17 disc cases, stacked as shown, will definitely fit the box
Answer:
The 17 disc cases would definitely fit into the box.
Step-by-step explanation:
The given cuboid box has the dimensions 28cm by 15cm by 20cm.
Disc cases are cuboid with dimensions 1.5cm by 14.2cm by 19.3cm.
volume of a cuboid = length × width × height
Volume of the box = 28 × 15 × 20
= 8400 cubic centimeters
Volume of each disc case = 1.5 × 14.2 × 19.3
= 411.09 cubic centimeters
When the 17 disc cases are stacked it would have a volume.
The volume of 17 disc cases = 17 × volume of a case
= 17 × 411.09
= 6988.53 cubic centimeters
Thus comparing the volume for 17 disc cases and that of the cuboid box, the disc cases would definitely fit into the box.
i.e = [tex]\frac{volume of box}{volume of 17 disc cases}[/tex]
= [tex]\frac{8400}{6988.53}[/tex]
= 1.20
Answer:
Step-by-step explanation:
27.5×14.5×19.5 =7775.625 cm³
1.55 x 14.25 x 19.35=427.393125
427.393125 x 17=7265.683
7775.625>7265.683
19.5x27.5x14.5=7775.625
1.45x14.15x19.25=394.961875
394.961875x17=6714.35
7775.63>6714.35
1.55x17=26.35
27.5>26.35
Describe the rate of change of f(x)=lnx. Your answer should explain how the slope changes when x is small and when x is large.
Answer:
By plotting the graph of f(x)=lnx, you can conclude that when x is small, dy/dx has a larger value. For instance, the gradient of the curve when x=0.5 is 2. However, as you move along the x axis, you will see that the graph levels off, indicating a decrease in the slope, or dy/dx. For example, if x=10, dy/dx = 0.1 and when x=20, dy/dx= 0.05 and so on. Eventually, when x is large enough the value of dy/dx will be negligible.
Thus, as x increases, the slope decreases.
Answer:
Explanation shown below
Step-by-step explanation:
f(x)=lnx;
The rate of change is defined as dy/dx;
dy/dx[Inx] = 1/x
and dy/dx is defined as the slope
The nature of the slope is as x increases ; the slope decreases and conversely meaning as x decreases, the slope increases.
We are planning on introducing a new internet device that should drastically reduce the amount of viruses on personal computers. We think the price should be $39.99, but are not sure on the percentage of people that would buy it. We do some research and find the following information; Studies from the 1930’s indicate that percentage should be between 30% and 40% Similar products were launched recently at a price of $4,000 and nobody bought it. A nationwide poll on this type of product and price was run earlier this year, with percentages running from 75% to 80%. We are going to conduct an additional focus group before we launch the product. What should the sample size be if we want a 95% CI to be within 5% of the actual value?
Answer:
The sample size required is 289.
Step-by-step explanation:
Let p be population proportion of people that would buy the product.
It is provided that the nationwide poll on this type of product and price was run earlier this year, with percentages running from 75% to 80%.
Assume that the sample proportion of people that would buy the product is, [tex]\hat p=0.75[/tex].
A 95% Confidence Interval is to be constructed with a margin of error of 5%.
We need to determine the sample size required for the 95% Confidence Interval to be within 5% of the actual value.
The formula to compute the margin of error for a (1 - α)% confidence interval of population proportion is:
[tex]MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]
The critical value of z for 95% confidence interval is,
z = 1.96.
Compute the sample size required as follows:
[tex]MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]
[tex]n=[\frac{z_{\alpha/2}\ \sqrt{\hat p(1-\hat p)} }{MOE}]^{2}[/tex]
[tex]=[\frac{1.96\cdot \sqrt{0.75(1-0.75)} }{0.05}]^{2}\\\\=(16.9741)^{2}\\\\=288.12007081\\\\\approx 289[/tex]
Thus, the sample size required is 289.
Please answer this correctly
Answer:
The answer is 2.5ft².
Step-by-step explanation:
Given that the area of trapezoid formula is A = 1/2×(a+b)×h where a and b is the length and h is the height. Then substitute the following values into the formula :
[tex]area = \frac{1}{2} \times (a + b) \times h[/tex]
Let a = 1.2,
Let b = 0.8,
Let c = 2.5,
[tex]area = \frac{1}{2} \times (1.2 + 0.8) \times 2.5[/tex]
[tex]area = \frac{1}{2} \times 2 \times 2.5[/tex]
[tex]area = 2.5 {feet}^{2} [/tex]
Assume that the weight loss for the first month of a diet program varies between 6 pounds and 12 pounds, and is spread evenly over the range of possibilities, so that there is a uniform distribution. Find the probability of the given range of pounds lost. Between 8 pounds and 11 pounds.
A. 1/2.B. 1/4.C. 2/3.D. 1/3.
Answer:
A. 1/2
Step-by-step explanation:
In this uniform distribution (from 6 to 12 pounds), the probability of any given range (from 'a' to 'b' pounds) is determined by:
[tex]P = \frac{b-a}{12 - 6}[/tex]
For a = 8 pounds and b = 11 pounds, the probability is:
[tex]P=\frac{11-8}{12-6}\\P=\frac{3}{6}=\frac{1}{2}[/tex]
The probability of the range of pounds lost being between 8 pounds and 11 pounds is 1/2.
What's 2|–9| – |–2|?
Answer:
Step-by-step explanation: AS YOU KHOW THW ABSOLUTE VALUE OF A QUESTION IS NUMBER ITSELF IF THERE IS MINUS SIGH THEN THE SIGH OF A NUMBER WILL BECOME PLUS OR IF THERE IS A PLUS SIGH THEN THERE IT WILL REMAIN AS IT IS. IF THERE IS NO NUMBER WITH THE MINUS SIGH THEN THE MINUS SIGH WILL REAMIN AS IT IS.
+2 +9 - +2
The answer has same sigh, then Plus answer will you get is
+11 - 2 then you will minus the answer will be
+9
HOPE IT HELP YOU
I need help
On these two
Answer:
10.
A. 10240
6.
B. 2^18 = 262144
Step-by-step explanation:
Dan earns £8.10 per hour how much will he earn for 7 hours work
Set C is the set of two-digit even numbers greater than 34 that are divisible by 5
C=
Find lim x→3 sqrt 2x+3-sqrt 3x/ x^2-3x. you must show your work or explain your work in words plsss I need help
I'm assuming the limit is supposed to be
[tex]\displaystyle\lim_{x\to3}\frac{\sqrt{2x+3}-\sqrt{3x}}{x^2-3x}[/tex]
Multiply the numerator by its conjugate, and do the same with the denominator:
[tex]\left(\sqrt{2x+3}-\sqrt{3x}\right)\left(\sqrt{2x+3}+\sqrt{3x}\right)=\left(\sqrt{2x+3}\right)^2-\left(\sqrt{3x}\right)^2=-(x-3)[/tex]
so that in the limit, we have
[tex]\displaystyle\lim_{x\to3}\frac{-(x-3)}{(x^2-3x)\left(\sqrt{2x+3}+\sqrt{3x}\right)}[/tex]
Factorize the first term in the denominator as
[tex]x^2-3x=x(x-3)[/tex]
The [tex]x-3[/tex] terms cancel, leaving you with
[tex]\displaystyle\lim_{x\to3}\frac{-1}{x\left(\sqrt{2x+3}+\sqrt{3x}\right)}[/tex]
and the limand is continuous at [tex]x=3[/tex], so we can substitute it to find the limit has a value of -1/18.
Y is directly proportional to 1/x. Write this in proportion notation.
2 points
d is proportional to e. When d is 10, e is 16. What is an equation connecting d and e
.
2.
.
I hope it helps you
If P(-2, 1) is rotated 90°, its image is
The image of P(-2,1) after it is rotated 90° is (-1,-2).
Can someone please help me with this I’m stuck and I need to finish but I don’t understand
Answer:
28
Step-by-step explanation:
Because the lines are parallel:
[tex]\dfrac{m}{21}=\dfrac{8}{6} \\\\m=\dfrac{8}{6}\cdot 21=28[/tex]
Hope this helps!
Please answer this correctly
Answer:
10 people
Step-by-step explanation:
Count the x's for more than 1 scarf, which is 2 or 3 scarfs
2 = 9
3 =1
total = 10
Mai deposited $4000 into an account with 4.8% interest, compounded quarterly. Assuming that no withdrawals are made, how much will she have in the
account after 7 years?
Do not round any intermediate computations, and round your answer to the nearest cent.
Answer:
5,586.17
Step-by-step explanation:
A = $ 5,586.17
A = P + I where
P (principal) = $ 4,000.00
I (interest) = $ 1,586.17
Compound Interest Equation
A = P(1 + r/n)^nt
Where:
A = Accrued Amount (principal + interest)
P = Principal Amount
I = Interest Amount
R = Annual Nominal Interest Rate in percent
r = Annual Nominal Interest Rate as a decimal
r = R/100
t = Time Involved in years, 0.5 years is calculated as 6 months, etc.
n = number of compounding periods per unit t; at the END of each period
The number of seconds, t it takes for an object to fall a distance of d meters can be found using the formula t=2dg−−√, where g is the constant acceleration due to gravity, 9.8msec2. How many meters does an object fall in 5 seconds? Round your answer to the nearest whole number.
Answer:
d = 61.25 m
Step-by-step explanation:
The number of seconds, t it takes for an object to fall a distance of d meters can be found using the formula :
[tex]t=2\sqrt{\dfrac{d}{g}}[/tex] .....(1)
It is required to find the distance covered by ab object in 5 seconds
Solving equation (1) for d. So,
[tex]d=\dfrac{t^2g}{4}[/tex]
Putting all the values we get :
[tex]d=\dfrac{(5)^2\times 9.8}{4}\\\\d=61.25\ m[/tex]
So, the distance covered by the object is 61.25 m.
The object will fall at a distance of 122.5 meters.
What is acceleration?Acceleration is the rate of change of velocity with time, both in terms of speed and direction.
Given that, t = √(2d/g).
t = √(2d/g
t√(g/2) = √d
t²(g/2) = d
Or, d = t²(g/2)
Substitute g = 9.8 and t = 5:
d = 5²(9.8/2)
d = 122.5 meters
Hence, the object will fall at a distance of 122.5 meters.
Learn more on acceleration here:
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Examine the details of the chi‑square test and conclude in context. There is good evidence (cite P-value) of an association between treatment and outcome in the population of women just treated for a UTI. There were substantially fewer than expected women getting a UTI recurrence in the study among those drinking cranberry juice daily. The conditions for inference are not met. There is good evidence (cite P-value) of an association between treatment and outcome in the population of women just treated for a UTI. There were substantially fewer than expected women getting a UTI recurrence among those abstaining from both drinks. There is good evidence (cite P-value) of an association between treatment and outcome in the population of women just treated for a UTI. There were substantially fewer than expected women getting a UTI recurrence among those drinking Lactobacillus drink. There is good evidence (cite P-value) that, in the population of women just treated for a UTI, women drinking cranberry juice daily have fewer UTI recurrences, on average. Question Source: Baldi 4e - The Practice Of Statistics
Answer:
Step-by-step explanation:
We will examine and outline the details of this chi-square test and then conclude in context.
(A) A population of women have just been treated for a urinary tract infection.
(B) Since the chi-square test is done for categorical variables, we will pick out the variable involved here.
That variable is: "UTI Recurrence"
Hence, we are looking at the recurrence of a urinary tract infection, among samples of the population of women who have recently been treated of it.
(C) There are three samples from this population and they are distinguished thus:
SAMPLE 1: Those drinking cranberry juice daily
SAMPLE 2: Those taking lactobacillus drink
SAMPLE 3: Those abstaining from both drinks (the placebo sample)
(D) The result of the test gave good evidence that SAMPLE 1 has the lowest value of the categorical variable involved; as compared to the values from SAMPLE 2 and SAMPLE 3.
In other words, on the average (average here is equal to mode or frequency of occurrence of the variable), the lowest number of UTI recurrences stems from Sample 1, as compared to the numbers of UTI recurrences in the other two samples
Fraction - Subtrction : 15 5/11 - 7 3/12
Answer:
[tex]= 8 \frac{27}{132} = 8\frac{9}{44}\\ [/tex]
Step-by-step explanation:
[tex]15 \frac{5}{11} - 7 \frac{3}{12} \\ \frac{170}{11} - \frac{87}{12} \\ \frac{2040 - 957}{132} \\ = \frac{1083}{132} \\ = 8 \frac{27}{132} [/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
Answer:
8 9/44.
Step-by-step explanation:
15 5/11 - 7 3/12
= 15 - 7 + 5/11 - 1/4 The LCD of 4 and 11 is 44 so we have:
15 - 7 + 20/44 - 11/44
= 8 + 9/44
= 8 9/44.
liam is a tyre fitter it takes him 56 minutes to fit 4 tyres to a van
Answer:
Step-by-step explanation:
I am not really sure because u did not finish the question but is u are asking how much time it takes to fit one tyre:
answer is time/tyres
56min./4
14 min. Per type