At a pressure of 1.13 atm and a volume of 35.9 L, 0.750 mol of an ideal gas will occupy a temperature of approximately 387.66°C.
Given information,
Pressure (P) = 1.13 atm
Volume (V) = 35.9 L
Number of moles (n) = 0.750 mol
The ideal gas law equation: PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
Now,
T = PV / (nR)
T = (1.13 * 35.9 ) / (0.750 * 0.0821)
T = (40.607 atm·L) / (0.061575 mol·L/(K·atm))
T ≈ 660.81 K
T(°C) = T(K) - 273.15
T(°C) ≈ 660.81 - 273.15
T(°C) ≈ 387.66°C
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A gas occupies a volume of 139.3-mL at 135.5-kPa. What volume will the gas occupy at 138.7-kPa if the temperature remains the same?
The volume the gas will occupy at pressure of 138.7 KPa, given that the temperature remains the same is 136 mL
How do i determine the new volume of the gas?The new volume of the gas, given that the new pressure is 138.7 KPa can be obtained as follow:
Initial volume of gas (V₁) = 139.3 mLInitial pressure of gas (P₁) = 135.5 KPaNew pressure of gas (P₂) = 138.7 KPaNew volume of gas (V₂) =?P₁V₁ = P₂V₂
Inputting the given parameters, we have:
135.5 × 139.3 = 138.7 × V₂
18875.17 = 138.7 × V₂
Divide both side by 138.7
V₂ = 18875.17 / 138.7
V₂ = 136 mL
Thus, we can conclude that the volume of the gas will be 136 mL
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B2 2- orbital picture
Plants need light from the sun in order to go through photosynthesis. Which type of air pollution would most likely decrease the amount of sunlight a plant can absorb?
Answer:
Particulate matter pollution decreases the amount of sunlight plants can absorb for photosynthesis.
Explanation:
examples of chemical compounds that are formed by swapping the valencies
Some examples of chemical compounds that are formed by swapping the valencies are:
Sodium chloride (NaCl)Magnesium oxide (MgO)Carbon dioxide (CO2)Water (H2O)What is valency?In chemistry, one can analyze an element's combining capacity with other atoms through its valency, crucial for creating chemical compounds or molecules.
Recently, an article featured a comparable description detailing atomic valence as "the electrons utilized by the atom during bonding." There are also two distinct formulas available to determine the element's level of valence.
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Look at the graph that shows the progress made in reducing fuel cell system costs. Graph of progress in reducing Fuel Cell System has an x axis labeled Years from 2002 to 2010, and a y axis labeled cost in dollars per kilowatt hour from 0 to 300. Data is: 2002, 248 dollars. 2003, 198 dollars. 2004, 149 dollars. 2005, 99 dollars. 2007, 82 dollars. 2008, 60 dollars. 2009, 51 dollars. 2010, 43 dollars. 2015 goal is 30 dollars per kilowatt hour. Which conclusion is supported by the information in the graph? The cost of producing a kilowatt of power with a fuel cell will be less than $30 in 2015. Fuel cell cars are unlikely to be affordable in the near future. The rate of emissions is decreasing because of inexpensive fuel cell technology. The environment is unlikely to improve as a result of cheap fuel cell technology.
CHEM FINAL TOMORROW!!! Need some help with concentration stuff. If someone could tell me how this works it would be incredibly helpful!!
The boiling point of a solution is influenced by the presence of solute particles, which can cause a change in the boiling point compared to the pure solvent. This phenomenon is known as boiling point elevation.
The magnitude of boiling point elevation depends on the concentration of the solute and the nature of the solute particles. In general, the greater the concentration of solute particles, the greater the boiling point elevation.
Comparing a 0.5m sodium chloride (NaCl) solution to a 0.3m aluminum sulfate ([tex]Al_2(SO_4)_3[/tex]) solution, we can determine the relative boiling point elevation.
Sodium chloride (NaCl) dissociates into two ions in solution (Na+ and Cl-), while aluminum sulfate ([tex]Al_2(SO_4)_3[/tex])dissociates into three ions (2[tex]Al_3[/tex]+ and 3[tex]SO_4[/tex]2-). This means that the aluminum sulfate solution will have a greater concentration of solute particles per mole than the sodium chloride solution.
Therefore, the boiling point of the 0.5m sodium chloride solution will be lower than the boiling point of the 0.3m aluminum sulfate solution.
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How many atoms of carbon are there in 0.37 mol of procaine, C13H20N202. a "pain killer" used by dentists?
There are approximately 2.8939 x[tex]10^2^4[/tex] carbon atoms in 0.37 mol of procaine. The molecular formula of procaine (C₁₃H₂₀N₂₀₂), one can see that there are 13 carbon atoms (C13) in one molecule of procaine.
Avogadro's number (6.022 x [tex]10^2^3[/tex]) represents the number of particles (atoms, molecules, or formula units) in one mole of a substance
The number of molecules of procaine in 0.37 mol:
Number of molecules = 0.37 mol x (6.022 x[tex]10^2^3[/tex] molecules/mol)
Number of carbon atoms = Number of molecules x 13 carbon atoms/molecule
Number of molecules = 0.37 mol x (6.022 x [tex]10^2^3[/tex]molecules/mol)
= 2.22614 x [tex]10^2^3[/tex]molecules
Number of carbon atoms = 2.22614 x [tex]10^2^3[/tex] molecules x 13 carbon atoms/molecule
= 2.8939 x [tex]10^2^4[/tex]carbon atoms
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For this question choose three answered which question should be asked before writing the name for H2SO4 (aq) HURRY
The name for H2SO4(aq) is Sulfuric acid.
Sulfuric acid (H2SO4) is a highly corrosive and strong acid. It is one of the most important industrial chemicals produced worldwide. Sulfuric acid is commonly used in various industries for a wide range of applications. It is used in the production of fertilizers, detergents, dyes, pharmaceuticals, and various chemical processes.
Sulfuric acid is also utilized in laboratories for its acidic properties and as a dehydrating agent due to its strong affinity for water. It is a dense, oily liquid that is colorless when pure but can appear yellowish or brownish due to impurities. When handling sulfuric acid, caution must be exercised as it can cause severe burns and is harmful if ingested or inhaled.
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Determine the type of reaction, predict the product and balance the equation for the following:
LiOH + HBr --->
From the uncompleted equation, we have:
LiOH + HBr ->
LiOH is an ionic substance that can dissociate to produce Li⁺ and OH⁻ HBR is an ionic substance that can dissociate to produce H⁺ and Br⁻Since we have two ionic substance reacting, we can conclude that the type of reaction is double displacement reaction as the reaction will involve exchange of ions between the reacting species.
How do i determine the products of the reaction?The products of the reaction can be obtained by balancing the equation. This is shown below:
LiOH + HBr ->
By exchange of ion, we have
LiOH + HBr -> LiBr + H₂O
Now, observing the equation, we can see that the equation is balanced.
Thus, the products of the reaction are LiBr and H₂O
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Determine the limiting reactant:
2BF3 (1) + 3Li2SO4 (aq) --> B₂(SO4)3 (aq) + 6LiF (aq) (balanced)
300 grams of BF3 react with 800 grams of Li₂SO4.
Answer:
The limiting reactant is BF3 because there is less of it than Li2SO4.
Explanation:
‼️‼️‼️need help asap‼️‼️‼️
24. To calculate the molarity of a solution, we must first find out how many moles of [tex]BaI_2[/tex] are in the solution.
Molar mass of BaI2 = (1 x atomic mass of Ba) + (2 x atomic mass of I)
= (1 x 137.33 g/mol) + (2 x 126.90 g/mol)
= 137.33 g/mol + 253.80 g/mol
= 391.13 g/mol
Number of moles of BaI2 = mass of BaI2 / molar mass of BaI2
= 413 g / 391.13 g/mol
= 1.056 mol
the molarity of the solution using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Volume of solution = 750 ml = 750 ml / 1000 ml/L = 0.750 L
Molarity = 1.056 mol / 0.750 L
= 1.408 M
Therefore, the molarity of the solution is 1.408 M.
25. a. [tex]P_20_7[/tex] - Ionic compound (Phosphorus(V) oxide)
b. [tex]SnBr_2[/tex] - Ionic compound (Tin(II) bromide)
c. [tex]Fe(OH)_2[/tex]- Ionic compound (Iron(II) hydroxide)
d. [tex]Cl_30_8[/tex] - Not a valid chemical formula
26.
A. (NH4)2CO3 is soluble in water (NH4) in an ionic substance called 2CO3 containing the ions carbonate and ammonium.
B. Fe(OH)2 is insoluble in water. Iron(II) hydroxide is only sparingly soluble.
C. CaOH is not soluble in water. Only very little calcium hydroxide is soluble.
D. PbCl2 is insoluble in water. The chloride of lead(II) is sparingly soluble.
27. FeS + 2KCl = FeCl2 + K2S
FeS is an insoluble precipitate.
2KCl dissolves in aqueous solution.
ZnCl2 + SrSO4 = ZnSO4 + SrCl2
SrSO4 is an insoluble precipitate.
ZnCl2 dissolves in aqueous solution.
28. In salt water, the solute is the salt (sodium chloride, or NaCl), and the solvent is water. The element which dissolves in the solvent to form a solution is called solute.
29. Charles's law states that, if the pressure and volume of a gas remain constant, the volume of a gas falls as the temperature increases. As a result, the capacity of the balloon will decrease as it ascends to altitudes where the temperature is -15 °C.
30. The average kinetic energy of the particles of a substance increases with increase in its temperature. This is because temperature is a gauge for the specific kinetic energy of the constituent particles of a substance. On the other hand, the average kinetic energy falls as the temperature increases.
31. When the volume of a gas decreases, its pressure increases. Boyle's law, which states that at a given temperature, the pressure of a gas is inversely proportional to its volume, describes this relationship. On the other hand, pressure falls when volume increases.
32. The pressure of a gas increases along with its temperature. Gay–Lussac's law, which states that the pressure of a gas is directly proportional to its temperature, given the volume and volume of the gas is constant, describes this relationship.
33. The volume of a syringe is reduced as a marshmallow is pressed and the plunger is depressed. As a result the pressure inside the syringe increases. This is because Boyle's law states that the volume and pressure of a gas are inversely proportional. The decrease in volume causes the air inside the syringe to contract, exerting more pressure on the marshmallow, which is then crushed.
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Human activities are responsible for almost all of the increase in greenhouse gases in the atmosphere over the last 150 years. If we review the pie chart, we can determine the source greenhouse gas emissions by percentages. But ultimately, there is one huge cause of these emissions: it is involved with every piece of this pie chart. What is this human activity?
The underlying foundation of all these emissions can be traced back to the burning of fossil fuels, making it the dominant and pervasive cause of human-induced greenhouse gas emissions.
The human activity that is intricately connected to every piece of the pie chart representing greenhouse gas emissions is the burning of fossil fuels. Fossil fuel combustion, including coal, oil, and natural gas, is the primary contributor to the rise in greenhouse gas concentrations over the past 150 years. When these fuels are burned for energy generation, transportation, industrial processes, and residential use, carbon dioxide (CO2) is released into the atmosphere. CO2 is the most significant greenhouse gas, accounting for approximately 75% of total emissions. The other greenhouse gases, such as methane (CH4) and nitrous oxide (N2O), are also released as byproducts of certain human activities, such as agriculture, deforestation, and waste management.
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someone help ASAP!!
What are possible components of ionic compounds? Check all that apply.
1: a metal and a nonmetal
2: 2 metals
3: a metal and a polyatomic anion
4: a polyatomic cation and a metal
What happens to ions during bonding to form an ionic compound?
Cations accept electrons and anions give away electrons.
Anions and cations share electrons.
Cations give away electrons and anions accept those electrons.
Answer:
Question 1:
1: a metal and a nonmetal
3: a metal and a polyatomic anion
4: a polyatomic cation and a metal
Question 2:
Cations give away electrons and anions accept those electrons
balanced equation for the decomposition of aluminium tetraoxosulphate
Identify the conjugate acid-base pairs in the reaction between amonia and hydrofluoric acid in aqueous solution
NH3 (aq) + HF (aq) = NH4+ (aq) + F- (aq)
The conjugate acid-base pairs in the reaction between ammonia and hydrofluoric acid in aqueous solution are NH3/NH4+ and HF/F-.
In the reaction between ammonia (NH3) and hydrofluoric acid (HF) in aqueous solution, the following conjugate acid-base pairs can be identified:
NH3 (ammonia) and NH4+ (ammonium ion):
Ammonia (NH3) acts as a base by accepting a proton (H+) from hydrofluoric acid (HF) to form the ammonium ion (NH4+). In this reaction, ammonia acts as a Lewis base by donating an electron pair to the proton, resulting in the formation of the ammonium ion as the conjugate acid.
HF (hydrofluoric acid) and F- (fluoride ion):
Hydrofluoric acid (HF) acts as an acid by donating a proton (H+) to ammonia (NH3) to form the fluoride ion (F-).
In this reaction, hydrofluoric acid acts as a Lewis acid by accepting an electron pair from ammonia, resulting in the formation of the fluoride ion as the conjugate base.
To summarize, in the reaction NH3 (aq) + HF (aq) = NH4+ (aq) + F- (aq), the conjugate acid-base pairs are NH3/NH4+ and HF/F-. Ammonia (NH3) is the base that forms its conjugate acid, the ammonium ion (NH4+), while hydrofluoric acid (HF) is the acid that forms its conjugate base, the fluoride ion (F-).
It is important to note that in an aqueous solution, ammonia is present as NH3 molecules, and hydrofluoric acid dissociates into H+ and F- ions. The resulting ammonium ion (NH4+) and fluoride ion (F-) remain in the solution.
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convert 7.54 x 10^-8 m to nanometers
7.54 *[tex]10^8[/tex] meters is 75.4 nanometers.
To convert 7.54 * [tex]10^8[/tex] meters to nanometers, you can multiply the value by [tex]10^9[/tex]
as, [tex]10^9[/tex]nanometers = 1 meter.
7.54 * [tex]10^8[/tex] m * [tex]10^9[/tex] = 7.54 x [tex]10^1[/tex] nm
Therefore, 7.54 *[tex]10^8[/tex] meters is equal to 75.4 nanometers.
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To convert 7.54 x 10^-8 meters to nanometers, you multiply 7.54 x 10^-8 by 1 x 10^9 to get 75.4 nanometers.
Explanation:To convert meters to nanometers, you need to know that 1 meter is equivalent to 1 x 109 nanometers. Therefore, if you were to convert 7.54 x 10-8 m to nanometers, you would multiply 7.54 x 10-8 by 1 x 109.
Here's how you'd do it: 7.54 x 10-8 m * 1 x 109 nm/m = 75.4 nm. So, 7.54 x 10-8 meters is equivalent to 75.4 nanometers.
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Describe two ways in which sodium chloride is different from sodium
Answer:
Sodium (Na) is a highly reactive metal, while sodium chloride (NaCl) is a compound formed by the combination of sodium and chlorine (Cl). Sodium exists as a pure element, whereas sodium chloride is a stable, crystalline compound.
Sodium is a soft, silvery-white metal that is highly reactive and can easily react with water or air. In contrast, sodium chloride is a white crystalline solid that is highly stable and does not react readily with water or air. Sodium chloride is commonly known as table salt and is widely used as a seasoning and food preservative.
determine if the following are ionic or covalent compounds
a. P2O7
b. SnBr2
c.Fe(OH)2
d.Cl3O8
Answer:
a. P2O7 - This is a covalent compound. P and O have similar electronegativities and they form a covalent bond between them, rather than an ionic bond.
b. SnBr2 - This is a covalent compound. Sn and Br have different electronegativities, but they still form a covalent bond due to their relatively small difference in electronegativity.
c. Fe(OH)2 - This is an ionic compound. Fe has a higher electronegativity than O and H, so it tends to donate its electrons and become positively charged. This results in the formation of ionic bonds between Fe and OH.
d. Cl3O8 - This is a covalent compound. Cl and O have similar electronegativities, so they form covalent bonds rather than ionic bonds.
Water arrived on earth in the form of
Answer:
the water arrives on the earth in the form of water rich objects(planetesimals)
Identify reactions types and balancing equations
The following chemical equations must be balanced:
1. N2 + 3 H2 → 2 NH3
Type: Synthesis
2. 2 KClO3 → 2 KCl + 3 O2
Type: Single Replacement
3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl
Type- Decomposition
4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2
Type- Double Replacement
5. 2 H2 + O2 → 2 H2O
Type: Combustion
6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2
Type: Synthesis
7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2
Type: Decomposition
8. C3H8 + 5 O2 → 3 CO2 + 4 H2O
Type: Combustion
9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O
Type: Double Replacement
10. 4 P + 5 O2 → 2 P2O5
Type: Synthesis
11. 2 Na + 2 H2O → 2 NaOH + H2
Type: Single Replacement
12. 2 Ag2O → 4 Ag + O2
Type: Decomposition
13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
Type: Combustion
14. 2 KBr + MgCl2 → 2 KCl + MgBr2
Type: Double Replacement
15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O
Type: Double Replacement
16. C5H12 + 8 O2 → 5 CO2 + 6 H2O
Type: Combustion
17. 4 Al + 3 O2 → 2 Al2O3
Type: Synthesis
18. Fe2O3 + 2 Al → 2 Fe + Al2O3
Type: Single Replacement
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some1 please help me with this problem
for reference: it’s speaking about 3H2 + N2 -> 2NH3 (ammonia)
Theoretically, if 20 grams of hydrogen reacts then 112.5 grams of ammonia is produced.
The balanced chemical equation can be given as:
N₂+3H₂→ 2NH₃
From stoichiometry, 2 mol of NH₃is produced from 3 mol of H₂
5 mol of NH₃ will be produced from = 3/2×5 = 7.5 mol of H₂
∴mass of H₂=7.5×2= 15gm of H₂.
Excess reagents are those reactants in a chemical reaction that are not exhausted at the end of the reaction. A completely exhausted or reacted reagent is called a limiting reagent because its amount limits the number of products formed. In this reaction, the excess reagent is Nitrogen as 35 grams of nitrogen and 15 grams of hydrogen react to produce 34 grams of ammonia.
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What is the percent strength of a 1:25 (weight/volume) solution?
Answer:
First, let's consider the ratio: 1:25. This means that for every 1 gram of solute, we have 25 milliliters of solvent. Therefore, if we have 100 milliliters of the solution, we can set up a proportion to find the amount of solute in grams:
1 gram solute / 25 milliliters solvent = x grams solute / 100 milliliters solution
Cross-multiplying, we get:
25 * x = 1 * 100
25x = 100
x = 100 / 25
x = 4
So, in 100 milliliters of a 1:25 (weight/volume) solution, there are 4 grams of solute.
To calculate the percent strength, we divide the mass of the solute (4 grams) by the volume of the solution (100 milliliters) and multiply by 100:
Percent strength = (mass of solute / volume of solution) * 100
Percent strength = (4 g / 100 mL) * 100
Percent strength = 4%
Therefore, the percent strength of a 1:25 (weight/volume) solution is 4%.
The system at equilibrium below is heated.
How does the system adjust to reestablish
equilibrium?
2SO₂(g) + O₂(g) ⇒ 2SO3(g) + 198 kJ
I need help with question 5
What is the molal concentration of 30% ethanol solution C2H2OH
To determine the molal concentration of a solution, we need to know the amount of solute (ethanol) in moles and the mass of the solvent (usually water) in kilograms.
Given that the solution is 30% ethanol, it means that there are 30 grams of ethanol in 100 grams of the solution. Let's assume we have 100 grams of the solution.
To find the amount of ethanol in moles, we need to convert grams to moles using the molar mass of ethanol (C2H5OH).
The molar mass of C2H5OH:
2 * atomic mass of carbon (C) = 2 * 12.01 g/mol = 24.02 g/mol
6 * atomic mass of hydrogen (H) = 6 * 1.01 g/mol = 6.06 g/mol
1 * atomic mass of oxygen (O) = 1 * 16.00 g/mol = 16.00 g/mol
1 * atomic mass of hydrogen (H) = 1 * 1.01 g/mol = 1.01 g/mol
Total molar mass of C2H5OH = 24.02 + 6.06 + 16.00 + 1.01 = 47.09 g/mol
Now, let's calculate the amount of ethanol in moles:
30 grams ethanol * (1 mol / 47.09 g) = 0.637 moles ethanol
Next, we need to determine the mass of the solvent (water) in kilograms. Let's assume we have 100 grams of the solution, so the mass of water would be 100 - 30 = 70 grams.
Converting the mass of water to kilograms:
70 grams * (1 kg / 1000 grams) = 0.07 kg
Finally, we can calculate the molal concentration (m) using the formula:
molal concentration (m) = moles of solute/mass of solvent in kilograms
m = 0.637 moles / 0.07 kg ≈ 9.10 mol/kg
Therefore, the molal concentration of the 30% ethanol solution (C2H5OH) is approximately 9.10 mol/kg.
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SECTION 1 Surface Water Movement (continued)
MAIN IDEA
DETAILS
Load/Stream magnesium compounds found in surface water, compare to the
Stream Explain how minerals, such as calcium carbonate and soluble
sugar in lemonade.
Answer:
Basically, they r different chemically and radically.
Explanation:
Here is how:
So,
Magnesium compounds found in surface water can vary depending on the specific water source and environmental factors. However, some common magnesium compounds that can be present in surface water include:
Magnesium Carbonate (MgCO3): This compound can form when magnesium ions (Mg2+) react with carbonate ions (CO32-) present in the water. It is often found in areas where there are limestone or dolomite formations.
Magnesium Hydroxide (Mg(OH)2): This compound can occur when magnesium ions react with hydroxide ions (OH-) in the water. It is more likely to be present in alkaline or basic water conditions.
Magnesium Sulfate (MgSO4): This compound can form when magnesium ions react with sulfate ions (SO42-) in the water. It can be found in areas where there are sulfates present, such as in some mining or industrial areas.
Now, let's compare these magnesium compounds to minerals like calcium carbonate and soluble sugar in lemonade:
Calcium Carbonate (CaCO3): Calcium carbonate is a common mineral found in many natural sources, including limestone, chalk, and shells of marine organisms. It is insoluble in water and tends to precipitate out of the solution, forming solid deposits or scale.
Soluble Sugar in Lemonade: Lemonade typically contains sucrose or other soluble sugars. These sugars are highly soluble in water, meaning they readily dissolve and form a homogeneous mixture with water.
In comparison to magnesium compounds found in surface water, calcium carbonate and soluble sugar in lemonade are chemically different. Calcium carbonate is insoluble in water and tends to separate from the solution, while soluble sugars dissolve completely.
If you placed 413g of Bal2 in a beaker and filled it with water to a total volume of 750ml, calculate the molarity of the solution
To calculate the molarity of a solution, we need to determine the number of moles of the solute (Bal2) and then divide it by the volume of the solution in liters.
Given:
Mass of Bal2 = 413 g
Volume of solution = 750 ml = 0.75 L
1. Calculate the number of moles of Bal2:
First, we need to convert the mass of Bal2 to moles using its molar mass. The molar mass of Bal2 can be calculated by summing the atomic masses of boron (B) and iodine (I):
Molar mass of Bal2 = (atomic mass of B × 1) + (atomic mass of I × 2)
Molar mass of Bal2 = (10.81 g/mol × 1) + (126.90 g/mol × 2)
Molar mass of Bal2 = 10.81 g/mol + 253.80 g/mol
Molar mass of Bal2 = 264.61 g/mol
Now we can calculate the number of moles of Bal2:
Moles of Bal2 = Mass of Bal2 / Molar mass of Bal2
Moles of Bal2 = 413 g / 264.61 g/mol
Moles of Bal2 ≈ 1.561 mol
2. Calculate the molarity of the solution:
Molarity (M) = Moles of solute / Volume of solution (in liters)
Molarity (M) = 1.561 mol / 0.75 L
Molarity (M) ≈ 2.081 M
Therefore, the molarity of the solution is approximately 2.081 M.
The molarity of the solution is approximately 1.408 M as to calculate the molarity of a solution, one must need to know the number of moles of the solute and the volume of the solution in liters.
The molar mass of BaI₂ is:
Ba (barium) atomic mass = 137.33 g/mol
I (iodine) atomic mass = 126.90 g/mol
Molar mass of BaI₂ = (Ba atomic mass) + 2 × (I atomic mass)
= 137.33 + 2 × 126.90
= 137.33 + 253.80
= 391.13 g/mol
Given that the mass of BaI₂ is 413 g,
Number of moles = Mass / Molar mass
= 413 g / 391.13 g/mol
= 1.056 moles
Volume of solution = 750 ml = 750/1000 = 0.75 L
Finally, one can calculate the molarity of the solution using the formula:
Molarity = Number of moles / Volume of solution
= 1.056 moles / 0.75 L
= 1.408 M
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Which statement best explains why different gases effuse at different rates?
Different gases effuse at different rates due to the relationship between their molecular masses, average velocities, and kinetic energy.
Lighter gases have higher average velocities and effuse more rapidly, while heavier gases have lower average velocities and effuse at slower rates. Graham's law of effusion provides a quantitative explanation for this phenomenon.
Different gases effuse at different rates due to variations in their molecular masses and average velocities. Effusion is the process by which gas molecules escape through a small opening or porous barrier into a vacuum or a region of lower pressure.
According to Graham's law of effusion, the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Mathematically, it can be expressed as:
Rate A / Rate B = √(Molar mass B / Molar mass A)
This means that lighter gas molecules, with lower molar masses, effuse faster compared to heavier gas molecules. The reason behind this can be understood by considering the kinetic theory of gases.
Gas molecules are in constant random motion, colliding with each other and the walls of the container. The average velocity of gas molecules is directly related to their kinetic energy, which depends on their mass and temperature. Lighter gas molecules have higher average velocities due to their lower mass and therefore higher kinetic energy.
During effusion, gas molecules near the opening of the container collide with the walls more frequently and possess higher velocities. Lighter gas molecules have a higher chance of having a velocity that exceeds the escape velocity threshold, allowing them to effuse more easily.
On the other hand, heavier gas molecules have lower average velocities and collide less frequently with the walls. They require more energy or higher velocities to overcome intermolecular forces and effuse through the opening.
In summary, different gases effuse at different rates due to the relationship between their molecular masses, average velocities, and kinetic energy. Lighter gases have higher average velocities and effuse more rapidly, while heavier gases have lower average velocities and effuse at slower rates. Graham's law of effusion provides a quantitative explanation for this phenomenon.
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Calculate the volume in L of Oxygen gas collected at STP if the sample has a mass of 2.67g?
Answer:
[tex]\huge\boxed{\sf 1.869\ L}[/tex]
Explanation:
Given that,
Mass = m = 2.67 g
Molar mass (O₂) = 16 × 2 = 32 g/mol
Finding no. of moles:We know that,
No. of moles = mass in g / molar massNo. of moles = 2.67 / 32
No. of moles = 0.08 moles
Also, we know that:
1 moles of O₂ at STP = 22.4 LMultiply both sides by 0.081 × 0.08 moles of O₂ at STP = 22.4 × 0.08 L
0.08 moles of O₂ at STP = 1.869 LSo, the volume of 0.08 moles of oxygen gas at STP will be 1.869 L.
[tex]\rule[225]{225}{2}[/tex]
Identify reactions types and balancing equations???
The following chemical equations must be balanced:
1. N2 + 3 H2 → 2 NH3
Type: Synthesis reaction
2. 2 KClO3 → 2 KCl + 3 O2
Type: Single Replacement reaction
3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl
Type- Decomposition reaction
4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2
Type- Double Replacement reaction
5. 2 H2 + O2 → 2 H2O
Type: Combustion reaction
6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2
Type: Synthesis reaction
7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2
Type: Decomposition reaction
8. C3H8 + 5 O2 → 3 CO2 + 4 H2O
Type: Combustion reaction
9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O
Type: Double Replacement reaction
10. 4 P + 5 O2 → 2 P2O5
Type: Synthesis reaction
11. 2 Na + 2 H2O → 2 NaOH + H2
Type: Single Replacement reaction
12. 2 Ag2O → 4 Ag + O2
Type: Decomposition reaction
13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
Type: Combustion reaction
14. 2 KBr + MgCl2 → 2 KCl + MgBr2
Type: Double Replacement reaction
15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O
Type: Double Replacement reaction
16. C5H12 + 8 O2 → 5 CO2 + 6 H2O
Type: Combustion reaction
17. 4 Al + 3 O2 → 2 Al2O3
Type: Synthesis reaction
18. Fe2O3 + 2 Al → 2 Fe + Al2O3
Type: Single Replacement reaction
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