Based on your understanding of the ideas of external consistency and fruitfulness, which of the following statements best describes the relevance of these ideas to the acceptance of hypotheses?a. A fruitful hypothesis is considered stronger because fruitful hypotheses are always externally consistent with previously held theories. b. A fruitful hypothesis is considered stronger because fruitful hypotheses promote scientific progress by revealing new avenues of research and analysis.c. An adequate theory is always a fruitful theory. d. All internally coherent theories are fruitful.

Answer:

The third degree polynomial function = x³ + 27x² + 200x + 300

Step-by-step explanation:

The third-degree polynomial function has zeros −2 and −15.

From the above, we have been given two factors of the polynomial function. Let's derive the factors from the two zeros of the polynomial given.

The two given zeros of the polynomial can be written as:

x= -2

x+2 = 0

(x+2) is a factor of the polynomial

x= -15

x+15 = 0

(x+15) is a factor of the polynomial

So we have two factors of the polynomial (x+2) and (x+15). But since it is a third degree polynomial, we have to find the third factor.

Let (x-b) be the third factor and f(x) represent the third degree polynomial

f(x) = (x-b) (x+2) (x+15)

Expanding (x+2) (x+15) = x² + 2x + 15x + 30

(x+2) (x+15) = x² + 17x + 30

f(x) = (x-b) (x² + 17x + 30)

From the given information, a value of 1,170 is obtained when x=3

f(3) = 1170

Insert 3 for x in f(x)

f(3) = (3-b) (3² + 17(3) + 30)

1170 = (3-b) (9 + 51 + 30)

1170 = (3-b) (90)

1170/90 = 3-b

3-b = 13

b = 3-13 = -10

Insert value of b in f(x)

f(x) = [x-(-10)] (x² + 17x + 30)

f(x) = (x+10) (x² + 17x + 30)

f(x) = x³ + 17x² + 30x + 10x² + 170x + 200x + 300

f(x) = x³ + 27x² + 200x + 300

The third degree polynomial function = x³ + 27x² + 200x + 300

Answer:

There will be 66 bacteria in 8 hours.

Step-by-step explanation:

The number of bacteria after t hours is given by the following formula.

[tex]P(t) = P(0)(1-r)^{t}[/tex]

In which P(0) is the initual number of bacteria and r is the decay rate.

Researchers recorded that a certain bacteria population declined from 750,000 to 250 in 48 hours after the administration of medication.

This means that [tex]P(0) = 750000, P(48) = 250[/tex]

We use this to find r. So

[tex]P(t) = P(0)(1-r)^{t}[/tex]

[tex]250 = 750000(1-r)^{48}[/tex]

[tex](1-r)^{48} = \frac{250}{750000}[/tex]

[tex]\sqrt[48]{(1-r)^{48}} = \sqrt[48]{\frac{250}{750000}}[/tex]

[tex]1-r = 0.84637[/tex]

So

[tex]P(t) = 750000(0.84637)^{t}[/tex]

How many bacteria will there be in 8 hours?

8 hours from now, in this context, is 8 + 48 = 56 hours. So this is P(56).

[tex]P(56) = 750000(0.84637)^{56} = 65.83[/tex]

Rounding to the nearest number

There will be 66 bacteria in 8 hours.

Answer:

197,488

Step-by-step explanation:

This problem requires two main steps. First, we must find the unknown rate, k. Then, we use that value of k to help us find the unknown number of bacteria.

Identify the variables in the formula.

AA0ktA=250=750,000=?=48hours=A0ekt

Substitute the values in the formula.

250=750,000ek⋅48

Solve for k. Divide each side by 750,000.

13,000=e48k

Take the natural log of each side.

ln13,000=lne48k

Use the power property.

ln13,000=48klne

Simplify.

ln13,000=48k

Divide each side by 48.

ln13,00048=k

Approximate the answer.

k≈−0.167

We use this rate of growth to predict the number of bacteria there will be in 8 hours.

AA0ktA=?=750,000=ln13,00048=8hours=A0ekt

Substitute in the values.

A=750,000eln13,00048⋅8

Evaluate.

A≈197,488.16

At this rate of decay, researchers can expect 197,488 bacteria.

First check for the critical points of f by checking where the first-order derivatives vanish.

[tex]\dfrac{\partial f}{\partial x}=4x-4=0\implies x=1[/tex]

[tex]\dfrac{\partial f}{\partial y}=2y-4=0\implies y=2[/tex]

Notice how the point (1, 2) lies on the line y = 2x ; at this point, we get a value of f(1, 2) = -5 (MIN).

Next, check the points where the boundary lines intersect, which occurs at the points (0, 0), (0, 2), and (1, 2). We already checked the last one. We find f(0, 0) = 1 (MAX) and f(0, 2) = -3.

Now check on the boundary lines themselves. If x = 0, then

[tex]f(0,y)=y^2-4y+1=(y-2)^2-3[/tex]

which has a maximum value of -3 when y = 2 (so we get the same critical point as before).

If y = 2, then

[tex]f(x, 2)=2x^2-4x-3=2(x-1)^2-5[/tex]

with a maximum of -5 when x = 1.

If y = 2x, then

[tex]f(x,2x)=6x^2-12x+1=6(x-1)^2-5[/tex]

with the same maximum of -5 when x = 1.

This question is based on the absolute maximum and absolute minimum.

We get this by differentiating the terms.

Given:

f(x,y) =   [tex]2x^{2} - 4x + y^2 - 4y +1[/tex], bounded by the lines x=0,y=2,y=2x in the first quadrant,bounded by the lines x=0,y=2,y=2x in the first quadrant.

We need to determined the absolute maximum and absolute minimum of the function.

Now, partial differentiating wrt x and y.

[tex]\dfrac{\partial f}{ \partial x} = 4x -4 = 0 \Rightarrow x= 1 \\\dfrac{\partial f}{ \partial y} = 2y - 4 = 0 \Rightarrow y = 2[/tex]

Now, point (1, 2) lies on the line y = 2x ; at this point, we get a value of

f(1, 2) = -5 (MIN).

Next, check the points where the boundary lines intersect, which occurs at the points (0, 0), (0, 2), and (1, 2).

Now, find f(0, 0) = 1 (MAX) and f(0, 2) = -3.

Now check on the boundary lines themselves.

If x = 0, then we get,

[tex]f(0,y) = y^2 - 4y +1 = ( y-2)^2 -3\\[/tex]

which has a maximum value of -3 when y = 2 (so we get the same critical point as before).

If y = 2, then we get,

f(x,2) = [tex]2x^2-4x -3 = 2(x-1)^2 -5[/tex] with a maximum of -5 when x = 1.

If y = 2x, then we get,

f(x,2x) = [tex]6x^2 -12x +1 = 6(x-1)^2 -5[/tex] with the same maximum of -5 when     x = 1.

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Answer:

14

Step-by-step explanation:

each square is 2 you count across then up or the other way is fine too from point A to B it equals to 14

Answer:

Step-by-step explanation:

all numbers except y = 1

because (f*g)(x) = 1+1/x

and 1/x cannot be equal to 0

Answer:

see below

Step-by-step explanation:

To find the x intercept set y =0 and solve for x

6x+5y = -30

6x = -30

Divide by 6

x = -30/6 = -5

The x intercept is (-5,0)

To find the y intercept set x =0 and solve for y

6x+5y = -30

5y = -30

Divide by 5

y = -30/5 = -6

The y intercept is (0,-6)

To find the x-intercept set y =0. Solve for x.

6x+5y=-30

6x+5(0)=-30

6x+0=-30

6x=-30

x=-30/6

x=-5

The x-intercept is at (-5, 0)

To find the y-intercept set x =0. Solve for y.

6x+5y=-30

6(0)+5y=-30

0+5y=-30

5y=-30

y=-30/5

y=-6

The y-intercept is at (0, -6)

Answer:

The Predictor variable is the amount of precipitation received while the Response variable is the crop harvest.

Step-by-step explanation:

The Response variable in an experiment is the factor being measured or studied. They are also known as the dependent variables. Predictor variables are those values that explain the changes in the Response variable. They are also known as the independent variables.

In the question above, the amount of precipitation provides an explanation for the harvest of his crops. Therefore, the amount of precipitation can be rightly described as the predictor or independent variable, while the harvest of his crops is described as the response or dependent variable.

The units of tile will he need to surround his pool is 13.42

The given parameters are:

[tex]AB =2.24[/tex]

[tex]BD =5[/tex]

Start by calculating the distance BC using the following Pythagoras theorem

[tex]BD^2 = AB^2 + BC^2[/tex]

So, we have:

[tex]5^2 = 2.24^2 + BC^2[/tex]

[tex]25 = 5 + BC^2[/tex]

Collect like terms

[tex]BC^2 = 25 - 5[/tex]

[tex]BC^2 = 20[/tex]

Take the square roots of both sides

[tex]BC = 4.47[/tex]

The unit of tiles is then calculated using the following perimeter formula

[tex]Tiles = 2 \times (AB + BC)[/tex]

So, we have:

[tex]Tiles = 2 \times (2.24 + 4.47)[/tex]

[tex]Tiles = 13.42[/tex]

Hence, the units of tile will he need to surround his pool is 13.42

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Answer: The x-intercept is  4  and the y-intercept is 2.

Step-by-step explanation:

The x is intercept is when y is 0 and the y intercept is when x is 0.So using this information you can put in 0 for x and another 0 for y and solve for the x and y intercepts.

7(0) + 14y = 28

0    + 14y = 28

   14y = 28

  y =  2

7x + 14(0) = 28

7x + 0 = 28

  7x = 28

x =  4

The [tex]x[/tex]-intercept of the given equation is [tex]4[/tex] and the [tex]y[/tex]-intercept is [tex]2[/tex].

Given:

The equation is:

[tex]7x+14y=28[/tex]

To find:

The [tex]x[/tex]-intercept and [tex]y[/tex]-intercept of the given equation.

Explanation:

We have,

[tex]7x+14y=28[/tex]          ...(i)

Substitute [tex]x=0[/tex] in (i) to find the [tex]y[/tex]-intercept.

[tex]7(0)+14y=28[/tex]

[tex]14y=28[/tex]

[tex]\dfrac{14y}{14}=\dfrac{28}{14}[/tex]

[tex]y=2[/tex]

Substitute [tex]y=0[/tex] in (i) to find the [tex]x[/tex]-intercept.

[tex]7x+14(0)=28[/tex]

[tex]7x=28[/tex]

[tex]\dfrac{7x}{7}=\dfrac{28}{7}[/tex]

[tex]x=4[/tex]

Therefore, the [tex]x[/tex]-intercept of the given equation is [tex]4[/tex] and the [tex]y[/tex]-intercept is [tex]2[/tex].

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A = 14 m^2

Step-by-step explanation:

The equation for the area of a triangle is...

[tex]A=\frac{1}{2}bh[/tex]

For this we need the base and the height. Looking at the picture, we can see that the height is 4. The base is split into 2 parts, so we just need to add the 3 and the 4 together, that will make our base 7. Now we can plug these into the equation, but I'm also just going to make the 1/2 a 0.5.

[tex]A=0.5*4*7[/tex]

[tex]A=[/tex]

14 m^2

Answer:

28

Step-by-step explanation:

number of copies done in 5 minute 15 seconds = 147

60 seconds is equal to 1 minute

1 second is equal to 1/60 minutes

therefore 15 seconds is equal to 1/60 * 15 minutes = 1/4 minutes

thus,

number of copies done in 5 1/4 minute = 147

number of copies done in 1 minute = 147/ 5 1/4   (as 147/21 = 7)

                                                = 147/ (21/4) = 7*4 = 28

Thus, A copy machine makes 28 copies in 1 minute.

Answer: 363 cm squared

Step-by-step explanation:

So we can split the shape into 1 triangle and 3 rectangles.

We can start with the top right rectangle which is a 4 by 5.

4*5 = 20 cm squared

We can now do the horizontal rectangle. We need to find the dimensions firs by subtracting 4 from 31 to find the length and add 4 and 5 to find the height.

This means the dimensions are 27 by 9.

27 * 9 = 243 cm squared

Now the final square toward the bottom left will be a 10 by 7.

10 * 7 = 70 cm squared.

Now for the final piece is the triangle in the bottom left. We need to first find the height which we can determine by taking the the right hand side values of 10 , 4 and 5 and adding those together then subtracting that number by 13 to get the missing length that will add to 6 to find the height.

10 + 4 + 5 = 19

19 - 13 = 6

6 + 6 = 12

Now that we have the height and base of the triangle we solve for the area.

0.5 * 5 * 12 = 30 cm squared

Now we add all the areas together to find the total area.

20 + 243 + 70 + 30 = 363 cm squared

Answer:

f(x) = x³ - 2x²

=>

f(i) = i³- 2i²

Hope this helps!

:)

Answer:

The inverse function is [tex]f^{-1}(x) = \frac{x-1}{2}[/tex]

Step-by-step explanation:

We have the following function:

y = 2x + 1

Finding the inverse:

Exchange y and x, and then isolate y again. So

y = 2x + 1

Exchange y and x

x = 2y + 1

2y = x - 1

[tex]y = \frac{x-1}{2}[/tex]

So

The inverse function is [tex]f^{-1}(x) = \frac{x-1}{2}[/tex]

Answer:

5

Step-by-step explanation:

Divide both sides by 3 to get

1:5

Multiply by 5

To get 5:25

5 nurses for 25 patients

Answer:

5

Step-by-step explanation:

3 x 5 = 15

n x 5 = 25

n = 5

I think just two reflections would do it.

First we reflect around y = -x, the 45 degree line through the origin and the second and fourth quadrant.

Then we reflect through the y axis, x=0.

The composition of the two reflections is equivalent to a 90 degree clockwise rotation.

Answer: No, it is not possible to get the same image as a 90-degree clockwise rotation using only translations and/or reflections. In the rotation, the x- and y-coordinates are switched. There is no way to reverse the order of the coordinates using only reflections or translations.

Step-by-step explanation:

ITS CORRECT. EDGE 2020

Answer:

Pre-image ABCD has been shifted 2 units right and 1 unit upwards.

Step-by-step explanation:

Coordinates of the points A,B,C and D of the pre-image ABCD,

A(-4, 4), B(-1, 4), C(-5, 1), D(-2,1)

Coordinates of the points A', B', C' and D' of the image A'B'C'D'.

A'(-2, 5), B'(1, 5), C'(-3, 2), D'(0, 2)

Now we choose points A from the pre-image and A' from the image,

A(-4, 4) → A'(-2, 5)

Rule for the translation will be,

A(-4, 4) → A'(-4+2, 4+1)

Or A(x, y) → A'(x+2, y+1)

Therefore, pre-image ABCD has been shifted 2 units right and 1 unit upwards to form image A'B'C'D'.

Answer: It's D

Step-by-step explanation:

the last one I just took the quiz

Answer:

y = -3/5 x +3

Step-by-step explanation:

3x + 5y = 15

Subtract 3x from each side

-3x+3x + 5y = -3x+15

5y = -3x+15

Divide each side by 5

5y/5 = -3x/5 +15/5

y = -3/5 x +3

Answer:

10 players

Step-by-step explanation:

If you count the x’s, there are 10.

Why ask this question? You could have just counted

Answer:

22 players

Step-by-step explanation:

It specifically says 'at least 3 runs' so you would have to count all the x's in the columns 3, 4, and 5.

There are 10 x's in the 3 column

There are 3 x's in the 4 column

There are 9 x's in the 5 column

Hope this helps!

Answer:

34°

Step-by-step explanation:

According to the theorem, "any two angles in the same segmant are congruent"

<BED = <BCD

So

<BED = 34°

Answer:

  (0, ∞)

Step-by-step explanation:

An exponential function has a horizontal asymptote at y=0. Its vertical extent is toward infinity.

The range is ...

  0 < f(x) < ∞

Answer:

1. Diverges

2. Converges

3. Diverges

Step-by-step explanation:

Solution:-

Limit comparison test:

- Given, ∑[tex]a_n[/tex] and suppose ∑[tex]b_n[/tex] such that both series are positive for all values of ( n ). Then the following three conditions are applicable for the limit:

                          Lim ( n-> ∞ )   [tex][ \frac{a_n}{b_n} ][/tex]  = c

Where,

1) If c is finite: 0 < c < 1, then both series ∑[tex]a_n[/tex] and ∑[tex]b_n[/tex] either converges or diverges.

2) If c = 0, then ∑[tex]a_n[/tex] converges only if ∑[tex]b_n[/tex] converges.

3) If c = ∞ or undefined, then ∑[tex]a_n[/tex] diverges only if ∑[tex]b_n[/tex] diverges.

a) The given series ∑[tex]a_n[/tex] is:

                   (n = 1) ∑^∞  [tex][ \frac{n^2+1}{2n^3-1} ][/tex]

- We will make an educated guess on the comparative series  ∑[tex]b_n[/tex] by the following procedure.

                  (n = 1) ∑^∞   [tex][ \frac{n^2( 1 + \frac{1}{n^2} )}{n^3 ( 2 - \frac{1}{n^2} ) } ] = [ \frac{( 1 + \frac{1}{n^2} )}{n( 2 - \frac{1}{n^2} ) } ][/tex]

- Apply the limit ( n - > ∞ ):

                 (n = 1) ∑^∞  [tex][ \frac{1}{2n}][/tex]    .... The comparative series ( ∑[tex]b_n[/tex] )

- Both series  ∑[tex]a_n[/tex] and ∑[tex]b_n[/tex] are positive series. You can check by plugging various real number for ( n ) in both series.

- Compute the limit:

                 Lim ( n-> ∞ )  [tex][ \frac{n^2 + 1}{2n^3 - 1} * 2n ] = [ \frac{2n^3 + 2n}{2n^3 - 1} ][/tex]

                 Lim ( n-> ∞ )    [tex][ \frac{2n^3 ( 1 + \frac{1}{n^2} ) }{2n^3 ( 1 - \frac{1}{2n^3} ) } ] = [ \frac{ 1 + \frac{1}{n^2} }{ 1 - \frac{1}{2n^3} } ][/tex]

- Apply the limit ( n - > ∞ ):

                Lim ( n-> ∞ )  [tex][ \frac{a_n}{b_n} ][/tex]  = [tex][ \frac{1 + 0}{1 + 0} ][/tex] = 1   ... Finite

- So from first condition both series either converge or diverge.

- We check for ∑[tex]b_n[/tex] convergence or divergence.

- The ∑[tex]b_n[/tex] = ( 1 / 2n ) resembles harmonic series ∑ ( 1 / n ) which diverges by p-series test ∑ ( [tex]\frac{1}{n^p}[/tex] ) where p = 1 ≤ 1. Hence, ∑

- In combination of limit test and the divergence of ∑[tex]b_n[/tex], the series ∑[tex]a_n[/tex] given also diverges.

Answer: Diverges    

b)          

The given series ∑[tex]a_n[/tex] is:

                   (n = 1) ∑^∞  [tex][ \frac{n}{n^\frac{5}{2} +5} ][/tex]

- We will make an educated guess on the comparative series  ∑[tex]b_n[/tex] by the following procedure.

                  (n = 1) ∑^∞   [tex][ \frac{n( 1 )}{n ( n^\frac{3}{2} + \frac{5}{n} ) } ] = [\frac{1}{( n^\frac{3}{2} + \frac{5}{n} )} ][/tex]

- Apply the limit ( n - > ∞ ) in the denominator for  ( 5 / n ), only the dominant term n^(3/2) is left:

                  (n = 1) ∑^∞    [tex][ \frac{1}{n^\frac{3}{2} } ][/tex] .... The comparative series ( ∑[tex]b_n[/tex] )

- Both series  ∑[tex]a_n[/tex] and ∑[tex]b_n[/tex] are positive series. You can check by plugging various real number for ( n ) in both series.

- Compute the limit:

                 Lim ( n-> ∞ )   [tex][ \frac{n}{n^\frac{5}{2} +5} * n^\frac{3}{2} ] = [ \frac{n^\frac{5}{2}}{n^\frac{5}{2} +5} ][/tex]

                 Lim ( n-> ∞ )    [tex][ \frac{n^\frac{5}{2}}{n^\frac{5}{2} ( 1 + \frac{5}{n^\frac{5}{2}}) } ] = [ \frac{1}{1 + \frac{5}{n^\frac{5}{2}} } ][/tex]

- Apply the limit ( n - > ∞ ):

                Lim ( n-> ∞ )  [tex][ \frac{a_n}{b_n} ][/tex]  = [tex][\frac{1}{1 + 0}][/tex] = 1   ... Finite

- So from first condition both series either converge or diverge.

- We check for ∑[tex]b_n[/tex] convergence or divergence.

- The ∑[tex]b_n[/tex] = ( [tex][ \frac{1}{n^\frac{3}{2} } ][/tex] ) converges by p-series test ∑ ( [tex]\frac{1}{n^p}[/tex] ) where p = 3/2 > 1. Hence, ∑

- In combination of limit test and the divergence of ∑[tex]b_n[/tex], the series ∑[tex]a_n[/tex] given also converges.

Answer: converges

Comparison Test:-  

- Given, ∑[tex]a_n[/tex] and suppose ∑[tex]b_n[/tex] such that both series are positive for all values of ( n ).

-Then the following conditions are applied:

1 ) If ( [tex]a_n[/tex] - [tex]b_n[/tex] ) < 0 , then ∑[tex]a_n[/tex] diverges only if ∑[tex]b_n[/tex] diverges

2 ) If ( [tex]a_n[/tex] - [tex]b_n[/tex] ) ≤ 0 , then ∑[tex]a_n[/tex] converges only if ∑[tex]b_n[/tex] converges

c) The given series ∑[tex]a_n[/tex] is:

                   (n = 1) ∑^∞ [tex][ \frac{4 + 3^2}{2^n} ][/tex]

- We will make an educated guess on the comparative series  ∑[tex]b_n[/tex] by the following procedure.

                  (n = 1) ∑^∞ [tex][ \frac{3^n ( \frac{4}{3^n} + 1 )}{2^n} ][/tex]

- Apply the limit ( n - > ∞ ) in the numerator for  ( 4 / 3^n ), only the dominant terms ( 3^n ) and ( 2^n ) are left:  

                 (n = 1) ∑^∞ [tex][ \frac{3^n}{2^n} ][/tex]   ... The comparative series ( ∑[tex]b_n[/tex] )

- Compute the difference between sequences ( [tex]a_n[/tex] - [tex]b_n[/tex] ):

                 [tex]a_n - b_n = \frac{4 + 3^n}{2^n} - [ \frac{3^n}{2^n} ] \\\\a_n - b_n = \frac{4 }{2^n} \geq 0[/tex], for all values of ( n )

- Check for divergence of the comparative series ( ∑[tex]b_n[/tex] ), using divergence test:

               ∑[tex]b_n[/tex] = (n = 1) ∑^∞ [tex][ \frac{3^n}{2^n} ][/tex]  diverges

- The first condition is applied when  ( [tex]a_n[/tex] - [tex]b_n[/tex] ) ≥ 0, then ∑diverges only if ∑[tex]b_n[/tex] diverges.

Answer: Diverges

Answer:

1 5/16

Step-by-step explanation:

(-1/4 - 1/2) ÷ (-4/7)

PEMDAS says parentheses first

Get a common denominator

(-1/4 - 2/4)  ÷ (-4/7)

(-3/4)  ÷ (-4/7)

Copy dot flip

-3/4 * -7/4

21/16

Change to a mixed number, 16 goes into 21  1 time with 5 left over

1 5/16

Answer:

y=-1/4x -1

Step-by-step explanation:

y-y1 = -1/4(x1-x)

y-(-4) = -1/4(x-(-3)

y+4 = -1/4x +3

y=-1/4x-1

Answer:

Answers below

Step-by-step explanation:

a. Is x​ (approximately) a binomial random​ variable?

b. Give the probability distribution for x as a formula.

c. Find p(x = 2).

d. Find P(x <= 1).

Answer:

No roots

Step-by-step explanation:

the discriminant Δ = 12²-4×(-10)×(-9) = -216

since ∆ is negative then the equation -10x^2 + 12x − 9 = 0 has no solution .

Answer:

a=(d-c)/d

Step-by-step explanation:

ab+c=d

ab=d-c

a= (d-c)/b

Answer:

4√73

Step-by-step explanation:

x^2= 12^2 + 32^2

x^2= 144+ 1024

x^2=1168

x= 4√73

Answer:

Step-by-step explanation:

WITH THE GIVEN DATA

A ) using regression to investigate the relationship between the number of fatal accidents and the percentage of drivers under the age pf 21

to fit into a regression line we must have ∝ and β

where β = [tex]\frac{S_{xy} }{S_{xx} }[/tex]   = 0.2871

and ∝ = y - βx   =  - 1.5974

regression line = ∝ + β * x

insert values into regression line equation

regression line = -1.5974 + 0.2871 * x

we can conclude that for every single unit of : x, y would be increased by 0.2871.  and intersection of x and y will be through =1.5974

B ) conclusion and recommendations can you derive from your analysis

it  can be  concluded that they are strongly positively correlated. There is strong and positive correlation between them. i.e the number of fatal accidents and the drivers under the age of 21

using the correlation coefficient  ( r ) = [tex]\frac{S_{xy} }{\sqrt{S_{xx}*S_{xy} } }[/tex]    = 0.8394

Answer:

0.8394

Step-by-step explanation:

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