BD bisects angle ABC. Solve for x and find m angle ABC.
m angle ABD = 6x-8, m angle CBD = 3x + 4

Answer:

This is why [tex]\frac{1}{14}[/tex] x 42 = 3

Step-by-step explanation:

[tex]\frac{1}{14}[/tex] x 42 can also be written as [tex]\frac{1}{14}[/tex] x [tex]\frac{42}{1}[/tex]

we can reduce diagonally by 7 so [tex]\frac{1}{14}[/tex] x [tex]\frac{42}{1}[/tex] = [tex]\frac{1}{2}[/tex] x [tex]\frac{6}{1}[/tex]

now we multiply across [tex]\frac{1}{2}[/tex] x [tex]\frac{6}{1}[/tex] = [tex]\frac{6}{2}[/tex]

6 divided by two or [tex]\frac{6}{2}[/tex] = [tex]\frac{3}{1}[/tex] or 3

Answer:

7/8

Step-by-step explanation:

1/8 + 3/4 =

1/8 + 6/8 =

7/8

Answer: About 16 snaps

Step-by-step explanation:

In a box and whisker plot, the rightmost line in the "box" of the plot is the third quartile, which represents the 75th percentile.

In this graph, although it is difficult to pinpoint the EXACT number of snaps sent, the 75th percentile would be marked at about 16 snaps.

Answer:

that's your answer

The unknown number will be equal to 64.

The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.

Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.

Given that the cube of the product of 8 and the number is 512. The unknown number will be calculated as,

8 x = 512

x = 512 / 8

x = 64

The number which is the product of 8 will be equal to 64.

The complete question is given below.

The cube of the product of 8 and the number is 512. What is the number?

To know more about an expression follow

https://brainly.com/question/1713767

#SPJ2

Answer:

3/4

Step-by-step explanation:

21/16 ÷ 7/4

21/16 × 4/7

3/4

Answer:

288

Step-by-step explanation:

please review the attachment for step by step soluation

Answer:

Volume of cylinder is: Volume=1808.64 ft³

Step-by-step explanation:

Height of cylinder = 9 ft

Base diameter of cylinder = 16 ft

We need to find volume of cylinder .

The formula used is: [tex]Volume=\pi r^2h[/tex]

We need radius:

The radius = diameter/2 = 16/2 = 8 ft

Putting values and finding volume of cylinder

[tex]Volume=\pi r^2h[/tex]

[tex]Volume=3.14\times (8)^2\times (9) \\Volume=3.14\times 64\times (9) \\Volume=1808.64 \: ft^3[/tex]

So, Volume of cylinder is: Volume=1808.64 ft³

Answer:

Domain: -3 ≤ x ≤ 3

Range: -2 ≤ y ≤ 4

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

According to the graph, our x-values span from -3 to 3. Since both are closed dot, they are inclusive in the domain:

[-3, 3] or -3 ≤ x ≤ 3

According to the graph, our y-values span from -2 to 4. Since both are closed dot, they are inclusive in the range:

[-2, 4] or -2 ≤ y ≤ 4

Answer:

The average daily maximum temperature is

26.56 °C higher than the average daily minimum temperature

Step-by-step explanation:

Here, we simply want to calculate how higher is the average daily maximum temperature to average daily minimum temperature

We simply proceed to subtract the two

Mathematically, that will be;

21.85 - (-4.7)

= 21.85 + 4.7

= 26.56 °C

Answer:

y-100

x-250

Step-by-step explanation:

because the lines are insecting the other lines on that line

Answer:

x-83=70

x = 70 + 83

x= 153

Answer:

[tex]\displaystyle (-\infty, -\frac{1}{6})[/tex]

Step-by-Step explanation:

We have the function:

[tex]\displaystyle y=\int_{1}^{x}\frac{1}{3+t+3t^2}\, dt[/tex]

And we want to find the interval for which y is concave upwards.

Therefore, we will need to find the second derivative of y, find its inflection points (where y''=0), and test for values.

So, let's take the derivative of both sides with respect to x. So:

[tex]\displaystyle y^\prime=\frac{d}{dx}\Bigg[\int_{1}^{x}\frac{1}{3+t+3t^2}\, dt\Bigg][/tex]

By the Fundamental Theorem of Calculus:

[tex]\displaystyle y^\prime=\frac{1}{3+x+3x^2}[/tex]

So, we will take the derivative again. Hence:

[tex]\displaystyle y^\prime^\prime=\frac{d}{dx}\Big[\frac{1}{3+x+3x^2}\Big]=\frac{d}{dx}\Big[(3+x+3x^2)^{-1}\Big][/tex]

We will use the chain rule. Let:

[tex]\displaystyle u=x^{-1}\text{ and } v=3+x+3x^2[/tex]

Differentiate:

[tex]\displaystyle y^\prime^\prime=-(3+x+3x^2)^{-2}(1+6x)[/tex]

Rewrite:

[tex]\displaystyle y^\prime^\prime=-\frac{6x+1}{(3+x+3x^2)^2}[/tex]

So, points of inflection, where the concavity changes, is whenever the second derivative is 0 or undefined.

We can see that the second derivative will never be undefined since the denominator can never equal 0.

So, our only possible inflection points are when it's equal to 0. Hence:

[tex]\displaystyle 0=-\frac{6x+1}{(3+x+3x^2)^2}[/tex]

Multiplying both sides by the denominator gives:

[tex]0=-(6x+1)[/tex]

Then it follows that:

[tex]\displaystyle x=-\frac{1}{6}[/tex]

So, our only possible point of inflection is at x=-1/6.

We will test for values less than and greater than this inflection point.

Testing for x=-1, we see that:

[tex]\displaystyle y^\prime^\prime=-\frac{6(-1)+1}{3+(-1)+3(-1)^2}=1>0[/tex]

Since the result is positive, y is concave up for all values less than -1/6.

And testing for x=0, we see that:

[tex]\displaystyle y^\prime^\prime=-\frac{6(0)+1}{3+(0)+3(0)^2}=-\frac{1}{3}[/tex]

Since the result is negative, y is concave down for all values greater than -1/6.

Therefore, the interval for which y is concave up is:

[tex]\displaystyle (-\infty, -\frac{1}{6})[/tex]

Note that we use parentheses instead of brackets since at exactly x=-1/6, our graph is neither concave up nor concave down.

Answer: use mahthway it hels

Step-by-step explanation:

Answer:

It is A or D but mostly A is correct.

Step-by-step explanation:

give brainliest

[tex]\frac{x}{2}-\frac{2}{x+1}=1[/tex]

We have 2 denominators that we need to get rid of. Whenever there are the denominators, all we have to do is multiply all whole equation with the denominators.

Our denominators are both 2 and x+1. Therefore, we multiply the whole equation by 2(x+1)

[tex]\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)][/tex]

Then shorten the fractions.

[tex]\frac{x}{2}[2(x+1)]-\frac{2}{x+1}[2(x+1)] = 1[2(x+1)]\\x(x+1)-2(2)=1(2x+2)[/tex]

Distribute in all.

[tex]x^2+x-4=2x+2[/tex]

We should get like this. Because the polynomial is 2-degree, I'd suggest you to move all terms to one place. Therefore, moving 2x+2 to another side and subtract.

[tex]x^2+x-4-2x-2=0\\x^2-x-6=0\\[/tex]

We are almost there. All we have to do is, solving for x by factoring. (Although there are more than just factoring but factoring this polynomial is faster.)

[tex](x-3)(x+2)=0\\x=3,-2[/tex]

Thus, the answer is x = 3, -2

Heres the answer welcome btw

Answer:

8

Step-by-step explanation:

8/1

Step-by-step explanation:

8 dollars.........

Answer: I believe it's 13 > 5x or 5x+13. . But I'm not completely sure.

Answer:

In Step 2.

Step-by-step explanation:

They should have distributed the 2 to the x and 1 instead of subtracting it.

Answer:

x<3

Step-by-step explanation:

2x<6
/     /

2    2

x<3

Answer:

8:20

Step-by-step explanation:

8+20=28 and all that has happened is the ratio got bigger.

Answer:

one that looks like triangle

Step-by-step explanation:

Given:

LCM(a,b) = 90 and GCD(a,b) = 3.

b is three more than a.

To find:

The values of a and b.

Solution:

We have,

LCM(a,b) = 90

GCD(a,b) = HCF(a,b) = 3

According to the question,

[tex]b=a+3[/tex]

If a and b are two positive integers, then

[tex]a\times b=HCF(a,b)\times LCM(a,b)[/tex]

[tex]a\times (a+3)=3\times 90[/tex]

[tex]a^2+3a=270[/tex]

[tex]a^2+3a-270=0[/tex]

Splitting the middle terms, we get

[tex]a^2+18a-15a-270=0[/tex]

[tex]a(a+18)-15(a+18)=0[/tex]

[tex](a+18)(a-15)=0[/tex]

Using zero product property, we get

[tex]a+18=0[/tex] and [tex]a-15=0[/tex]

[tex]a=-18[/tex] and [tex]a=15[/tex]

a is a positive integer so it cannot be negative. So, a=15.

Now,

[tex]b=a+3[/tex]

[tex]b=15+3[/tex]

[tex]b=18[/tex]

Therefore, the value of a is 15 and the value of b is 18.

Answer: $15.37

Yes, proportional

Step-by-step explanation:

Ok So the Equation Here is

y = 1.73x + 4.99

The reason why 4.99 doesn't have a variable is because of the fact it's not being manipulated by time like the 1.73 is. It's a flat rate of 4.99 for the card itself, no increase or decrease in years. However, the 1.73 is affected by how ever many years the player is in retirement. That's why it has X because the amount of 1.73 needs to be multiplied by however many years hes been in retirement.

So Substitute 6 (because 2006 is what year we need to find) for x and we get

y = 1.73(6) + 4.99

Which if you simplify in a calculator or do it in your paper, comes out to be $15.37

*If this Helped I'd Also Appreciate 5* and a ♥ Thanks!*