Answer:
The ratio of the new internal energy to the old is 4
Explanation:
let the old pressure of the gas = P₁
let the old volume of the gas = V₁
then, the new pressure of the gas = 2P₁
the new volume of the gas = 2V₁
The internal energy of the gas is given as;
PV = nRT
PV = k
P₁V₁ = P₂V₂
[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]
The ratio of the new internal energy to the old is 4
7. What is the acceleration of a 24.00 kg mass pushed by an 8.0 N force?
Answer:
3 m/s²Explanation:
The acceleration of an object given it's mass and the force acting on it can be found by using the formula
[tex]a = \frac{f}{m} \\ [/tex]
f is the force
m is the mass
From the question we have
[tex]a = \frac{24}{8} \\ [/tex]
We have the final answer as
3 m/s²Hope this helps you
As a 3.0 kg bucket is being lowered into a 10 m deepwell, starting from top, the tension in the rope is 9.8 N. theacceleration of the bucket will be:____________A) 6.5 m/s2 downwardB) 9.8 m/s2 downwardC) zeroD) 3.3 m/s2 upwardE) 5.6 m/s2 upward
Answer:
A) 6.5 m/s²
Explanation:
Mass of the bucket, m = 3.0 kg
depth of the well, d = 10 m
tension on the rope, T = 9.8 N
The net downward force on the bucket is given as;
T = mg - ma
where;
a is downward acceleration of the bucket
9.8 = (3 x 9.8) - 3a
9.8 = 29.4 - 3a
3a = 29.4 - 9.8
3a = 19.6
a = 19.6 / 3
a = 6.53 m/s² downwards
Therefore, the acceleration of the bucket is 6.53 m/s² downwards
HELP URGENT- will give brainliest if correct
Answer:
6 km is the right answer
hope it helps you
Explanation:
please mark me as brainliest
How many grams are in 2 kg
As a ladder leans against a wall it exerts a force on both the wall and ground. What are the two reactant forces on the ladder?
Responses
−Fwall on ladder and −Fground on ladder
−Fwall on ladder and −Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline
Fwall on ladder and −Fground on ladder
Fwall on ladder and −Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline
Fwall on ladder and Fground on ladder
Fwall on ladder and Fground on ladder
upper F subscript ball on bat baseline equals negative upper F subscript bat on ball baseline
−Fwall on ladder and Fground on ladder
−Fwall on ladder and Fground on ladder
Its -Fwallonladdy and -fgroundonladder just made sure to add this since no one else did yet
The two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder
What are the two reactant forces on the ladder?To know the reactant forces on the ladder, we use Newton's third law of motion.
What is Newton's third law of motion?Newton's third law of motion states that for every action, there is an equal and opposite reaction.
So, for the ladder, as the ladder leans against a wall it exerts a force on both the wall and ground.
Now, since the ladder exerts a force on the wall, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the wall is Fladder on wall, then the reaction force of wall on the ladder is Fwall on ladder.
So, Fladder on wall = -Fwall on Ladder
Also, since the ladder exerts a force on the ground, according to Newton's third law, the ground also exerts an equal but opposite force on it. If the force of the ladder on the ground is Fladder on ground, then the reaction force of ground on the ladder is Fground on ladder.
So, Fladder on ground = -Fground on Ladder
So, the two reactant forces on the ladder are -Fwall on Ladder and -Fground on Ladder
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To pass a vehicle inspection, your Must be heard from 200 feet away.
Ohorn
Omuffler
windshield wipers
stereo
A I think sorry if I'm wrong
when does a circuit is said to be over loaded?
Answer:
Every electric circuit in a wiring system must be protected against overloads. A circuit overload occurs when the amount of current flowing through the circuit exceeds the rating of the protective devices. The amount of current flowing in a circuit is determined by the load -- or the "demand" -- for current.
Explanation:
Hope this helps :)
The world record for a woman running a marathon is approximately 2.25 hours. If a marathon's distance is 26.2 miles (42164.81 meters) and it is run
in a southeast direction, what is the velocity?
60 mph southeast
0.09 mph southeast
Omph southeast
11.6 mph southeast
Answer:
11.6mph South East
Explanation:
Given parameters:
Time = 2.25hrs
Displacement = 26.2miles south east
Unknown:
Velocity = ?
Solution:
Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.
Now;
Velocity = [tex]\frac{displacement}{time taken}[/tex]
Velocity = [tex]\frac{26.2}{2.25}[/tex] = 11.6mph South East
Answer:
11.6mph south east.
A man runs at 7.5 m s-1 due east across the deck of a ship which moves at 10.0 m s-' due
north. Determine the resultant velocity of the man (his velocity relative to the water).
The resultant velocity of the man is 12.5 m/s N of E.
Velocity of the man, Vm = 7.5 m/s
Velocity of Ship, Vs= 10 m/s
Since, velocity is a vector quantity, it will have both the magnitude and the direction.
So the magnitude for the resultant vector can be calculated by using the formula
[tex]\sqrt{x^{2} +y^{2} }[/tex] ; where x is the magnitude of the x-axis component and y is the magnitude of the y-axis component
i.e.
= [tex]\sqrt{Vm^{2} +Vs^{2} }[/tex]
= [tex]\sqrt{7.5^{2} + 10^{2} }[/tex]
= [tex]\sqrt{156.25}[/tex]
= 12.5 m/s
Also the direction can be calculated by Tan[tex]\alpha[/tex]
Tan[tex]\alpha[/tex] = [tex]\frac{10}{7.5}[/tex]
= Tan⁻(1.33)
= 58.9°
The angle between the resultant velocity and the horizontal axis is 58.9°.
Therefore the resultant velocity of the man relative to the water is 12.5 m/s towards NORTH-EAST direction.
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How much work is done by an applied force to lift a 15-Newton 3Meters and 9.8?
Given=
Unknown=
Formula=
Solution=
Answer=
The work done by the applied force of 15 Newton to lift the object up 3 meters is 45 J
W = F d
W = Work done
F = Force
d = Distance
F = 15 N
d= 3 m
W = 15 * 3
W = 15 J
Work done is the amount of force required to move an object. It is denoted by W. Its unit is usually Joules.
Therefore, the work done to lift the object is 15 J
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Convert 1.54 mg/cm³ to kg/dm³.
The converted unit 1.54 (mg / (cm^3)) is :
=0.00154 kg / (dm^3.)
What does unit conversion mean?A unit conversion is used to express the same property in a distinct unit of measurement. Minutes can be used to measure time instead of hours, and feet, kilometres, or any other measure can be used to measure distance in place of miles.
Why is conversion of units required?Showing someone the precise amount you have will be helpful. help with a mathematical problem, especially one involving chemistry where the solution can be found by following the units. Indicate the person's preferred system of measurement (i.e. metric or standard).
Briefing:1.54 mg/ cm³ x 1g/1000mg
Continue likewise until you have achieved kg:
1.54 mg/ cm³ x 1g/1000mg x 1 kg/ 10000g
Now, work on cm³
1.54 mg/ cm³ x 1g/1000mg x 1 kg/ 1000g x 10³ cm/1dm³ = ?
= .00154 kg/dm³
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Find the force exerted by a pressure of 40N/m² acting over an area of 0.0025 cm
Answer:
[tex]1.0*10^{-5} N[/tex]
Explanation:
To answer this question we can use the formula: [tex]P=\frac{F}{A}[/tex]
Pressure (Pascals) = Force (Newtons) divided by Area (Square Meters)
We are given pressure and area in the question and are trying to find force so we can rearrange the equation to suit our needs by multiplying both sides by Area:
[tex]P(A) = \frac{F}{A} (A)\\ \\F =PA[/tex]
The next step is to ensure all given information is in the correct units. Because we are given pressure in the units [tex]N/m^{2}[/tex], we need to convert 0.0025[tex]cm^{2}[/tex] into [tex]m^{2}[/tex].
There are 10,000 [tex]cm^{2}[/tex] in 1 [tex]m^{2}[/tex], therefore to convert between them, we need to divide 0.0025 by 10,000.
[tex]0.0025/10000 = 0.00000025m^{2}[/tex]
OR [tex]2.5*10^{-7} m^{2}[/tex]
Now we just need to multiply them together to get force:
[tex]F=PA\\F=40*2.5*10^{-7}\\F=1.0*10^{-5} N[/tex]
Hope this helped!
If a container, with a fixed number of molecules inside, is
reduced in volume, less molecules will hit the sides of the
container per unit time, causing less pressure.
TRUE
FALSE
Check it
Answer:
FALSE
FALSE
FALSE
FALSE
What become v if we use 2 risistors of 4w in parallel
Dale and Alex push on opposite sides of a couch. Dale pushes to the left with a force of 40 N, while Alex pushes to the right with a force of 32 N. If the
couch has a mass of 28 kg, what is the acceleration of the couch?
A. 2.6 m/s^2 right
B. 2.6 m/s^2 left
C. 0.3 m/s^2 left
D. 0.3 m/s^2 right
0.3 m/s^2 left will be the acceleration of the couch.
we have given in the statement
force towards left 40 N
force towards right 32 N
net force = 40-32 = 8 N towards left
couch mass = 28 kg
now we will use newtons 2nd law to find acceleration
F=ma, here f is force m is mass a is acceleration
a=F/m
a=8/24
a=0.285 ≅ 0.3 N
An object's rise in velocity rate is referred to as acceleration. It is a vector quantity that is sign-sensitive, and the route shift and body speed variance establish the sign norm. it's unit is m/s^2To know more about acceleration visit : https://brainly.com/question/3046924
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0.3 m/s squared left Answer:
Explanation:
Britney is on the starting line to run a track race. The distance around the track is 400m.
She starts the race and runs 400m around the track. She ends up in the same place where
she started. What distance did she cover? What was her displacement?
Which of the following will increase if the voltage in a circuit is increased?
Check all that apply
A.Magnetic force
B. Resistance
C. Current
D. Heat produced by the circuit
Answer:
D i think (apologies if incorrect)
The subjective perception of the frequency of sound is called ?
Answer: The subjective perception of the frequency of sound is called a Pitch
Explanation: Because the Pitch has a lowest and highest of a sound fundamental
If you are satisfied please leave a like
What is the mass of a block accelerating at 2 m/s2 and pushed by a 9 N force?
Answer:
1 Newton (N) 1 kg*m/s²
Acceleration is measured in m/s², so combine your starting figures in such a way as to get m/s² (you have to divide away the kg):
9N/2kg = 4.5 m/s²
Explanation:
Suppose, that you are measuring the length of a wood block and the edge of your block appears to be lined up exactly with a millimeter mark. How would you express the estimate part of a millimeter when you record the block’s length?
When taking the measurement, the estimate part of a millimeter when recording the block’s length can be expressed as ± 0.5 mm.
What are measurements?Measurements are the processes by which the attributes and properties of a given object or substance is quantified.
There are two types of measurements that can be obtained from any given object and they are:
quantitative measurementsqualitative measurementsQuantitative measurements measures the properties of objects in terms of numbers. Some examples of quantitative measurements are length, temperature, time, mass, etc.
Qualitative measurements describe the non-numerical features of objects such as color, texture, etc.
The measurement of length of a block of wood is a quantitative measurement.
The uncertainty or estimate of a measurement is half plus or minus the smallest division in the measurement.
The uncertainty or estimate of the millimeter block = ¹/₂ * 1 mm
The uncertainty or estimate of the millimeter block = ±0.5 mm
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A person holds a ladder horizontally at its center. Treating the ladder as a uniform rod of length 4.15 m and mass 7.98 kg, find the torque the person must exert on the ladder to give it an angular acceleration of 0.396 rad/s2.
Answer:
4.535 N.m
Explanation:
To solve this question, we're going to use the formula for moment of inertia
I = mL²/12
Where
I = moment of inertia
m = mass of the ladder, 7.98 kg
L = length of the ladder, 4.15 m
On solving we have
I = 7.98 * (4.15)² / 12
I = (7.98 * 17.2225) / 12
I = 137.44 / 12
I = 11.45 kg·m²
That is the moment of inertia about the center.
Using this moment of inertia, we multiply it by the angular acceleration to get the needed torque. So that
τ = 11.453 kg·m² * 0.395 rad/s²
τ = 4.535 N·m
The Torque will be "4.535 N.m".
Given:
Mass of ladder,
m = 7.98 kgLength of ladder,
L = 4.15 m
The moment of inertia will be:
→ [tex]I = \frac{mL^2}{12}[/tex]
[tex]= \frac{7.98\times (4.15)^2}{12}[/tex]
[tex]= \frac{7.98\times 17.2225}{12}[/tex]
[tex]= 11.45 \ kg.m^2[/tex]
hence,
The torque will be:
→ [tex]\tau = 11.453\times 0.395[/tex]
[tex]= 4.535 \ N/m[/tex]
Thus the above approach is correct.
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needdd helppppppppp
Answer:
divide 223 by 74 and you'll get your answer
HELP right awayyy !!!
Answer:
Question 4 is actually Acceleration
006 (part 1 of 4) 3.0 points
Both car A and car B leave school at the same time, traveling in the same direction. Car A travels at a constant speed of 74 km/h, while car B travels at a constant speed of 93 km/h. How far is Car A from school 2.7 h later? Answer in units of km.
007 (part 2 of 4) 3.0 points
How far is car B from school 2.7 h later? Answer in units of km.
008 (part 3 of 4) 3.0 points
How long does it take car A to reach a gas station a distance 189 km from the school? Answer in units of h.
009 (part 4 of 4) 3.0 points
How long does it take car B to reach the gas station? Answer in units of h.
1. The distance of car A from the school is 199.8 Km
2. The distance of car B from the school is 251.1 Km
3. The time taken for car A to reach the station is 2.55 hours
4. The time taken for car B to reach the station is 2.03 hours
What is speed?Speed is the distance travelled per unit. Mathematically, it can be expressed as:
Speed = distance / time
1. How to determine the distance of car A from the schoolSpeed = 74 Km/hTime = 2.7 hoursDistance of car A =?Speed = Distance / time
Cross multiply
Distance = speed × time
Distance of car A = 74 × 2.7
Distance of car A = 199.8 Km
2. How to determine the distance of car B from the schoolSpeed = 93 Km/hTime = 2.7 hoursDistance of car B =?Speed = Distance / time
Cross multiply
Distance = speed × time
Distance of car B = 93 × 2.7
Distance of car B = 251.1 Km
3. How to determine the time taken for car A to reach the gas stationSpeed = 74 Km/hDistance = 189 KmTime for car A =?Speed = distance / time
74 = 189 / time
Cross multiply
74 × time = 189
Divide both side by 14
Time = 189 / 74
Time for car A = 2.55 hours
4. How to determine the time taken for car B to reach the gas stationSpeed = 93 Km/hDistance = 189 KmDistance = 189 KmTime for car B =?Speed = distance / time
93 = 189 / time
Cross multiply
93 × time = 189
Divide both side by 93
Time = 189 / 93
Time for car B = 2.03 hours
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Helium balloons pop in a hot car because
Answer:
This is because helium molecules get bigger when they heat up , so if your balloons keep getting hotter , they will eventually pop
Answer:
the helium molecules within the ballon expand as they heat up, resulting in the eventually resulting in popping.
Explanation:
^^^^^
Soil erosion is the wearing down of soil. This map provides data on the rate of soil erosion in the united states for a given year. What trend does the mad show? A. Soil erosion rates are high across the united states B. Soil erosion rates are low across the united states C. Siol erosion rates are uniform across the united states D. Soil erosion rates vary across the united states
Soil erosion is the wearing down of soil. The trend that the map shows is that soil erosion rates vary across the united states.
Hence, option (D) is correct.
What is Soil Erosion?
The removal of the top layer of soil by the action of wind, water, or human activities is known as soil erosion.Sometimes, soil erosion is good for the environment, especially in depositing fertile soil.Soil erosion is a geological action of moving soil.The areas with the highest agricultural activities have the highest rate of erosion.As shown on the map, soil erosion vary across the United States.
Therefore, option (D) is correct.
Soil erosion is a slow method that happens while the impact of water or wind detaches and gets rid of soil particles, inflicting the soil to go to pot. Soil deterioration and low water excellent because of erosion and surface runoff have turn out to be intense troubles international.
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What does an electromagnet in an electric motor do? I need help asap
Answer:the Correct Answer is
It transforms electrical energy into mechanical energy.
Explanation:
I got the answer right
A toy car in the figure below runs off the edge of a table that is h = 1.36 m high. The
car lands d= 0.88 m from the base of the table. How fast was the car going on the
table?
The toy car was going at a speed of 1.66 m/s on the table.
When the toy car runs off the edge of the table, it travels vertically as well as horizontally and it is an example of a horizontal projectile from a height.
The distance covered vertically will be equal to the height of the table which is 1.36m. And horizontal distance is given as d.
Vertical distance = H = 1.36m
Horizontal distance = d = 0.88m
Now, we for a free-falling body, in
Speed in vertical direction = u = 0 m/s
Distance = h = 1.36
Using the second equation of motion,
h = ut + 1/2gt²
Put in the value, we get
1.36 = (0)t + 1/2(9.8)t²
t² = 1.36/4.9
t² = 0.278
t = 0.53 seconds
Now distance traveled in a horizontal direction is given by
Distance in horizontal direction = Speed on table × time of travel
Put in the value, we get
0.88 = V × 0.53
V = 0.88/0.53
V = 1.66 m/s
So, the toy car was going at a speed of 1.66 m/s on the table.
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A car is stopped for a traffic signal. When the light turns green,
the car accelerates, increasing its speed from 0 to 5.20 m/s in
0.832 s. What are the magnitudes of (a) the linear impulse and
(b) the average total force experienced by a 70.0-kg passenger
in the car during the time the car accelerates?
Answer:
Impulse, p = 364 N·s
Force F = 437.5 N
Explanation:
First some definitions:
Part (a)
Since the car is initially at rest, its initial momentum is 0.
When the car reaches a velocity of 5.20 m/s, the momentum experienced by a 70 kg passenger is
Δv = 5.20 - 0 = 5.20 m/s
p = 70 kg x 5.20 m/s = 50.3248 kg m/s = 364 N·s
p = 384 N.s
Part (b)
Force is given by F=m(Δv/Δt) = 70 kg x (5.20 m/s / 0.832 s) = 437.5 N
F = 437.5 N
A: In a second contest, the three displacements given are 90.9 m , 30.0 ∘ west of north; 15.5 m straight north; and 80.9 m , 45.0 ∘ south of east. What magnitude does the winner calculate for the displacement to find the keys to the Porsche?
B: What direction does the winner calculate for the displacement to find the keys to the Porsche?
A. Magnitude that the winner calculates for the displacement to find the keys to the Porsche is 38.83m.
B. The direction that the winner calculates for the displacement to find the key to the Porsche is 72.38° East of North.
When a particle moves from position A to point B, its displacement cannot be expressed using scalars. Always represented as a vector.
If an object's beginning and final positions are the same, its displacement is zero. That is, if a person begins a voyage at one location, walks some distance, and then returns to that location, his mobility will be zero.
The distance to the item will be 0 in this situation. Furthermore, there is no direction of zero displacements.
Given,
S1 = 90.9m, 30.0° west of north
S1 = 90.9 sin 30°( - î) + cos 30° j
∴ S1 = -45.45î + 78.72j
S2 = 15.5 m straight north
S2= 15.5 j
S3 = 80.9m, 45° south of east
S3 = 80.9 cos 45° î + 80.9 sin 45° j
S3 = 57.21 î - 57.21 j
Now,
Total displacement, S = S1 + S2 + S3
S = (-45.45î + 78.72j) + ( 15.5 j) + (57.21 î - 57.21 j)
= ( -45.45 + 57.21) î + ( 78.72 + 15.5 -57.21) j
S = 11.76 î + 37.01 j
|S| = 38.38m
tan α = y / x
tan α = 37.01 / 11.76
tan α = 3.15
α = 72.38° from East of North
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