1 x 10⁻¹² C are stored in the system.
The power required to move a charge in opposition to an electric field is known as electric potential energy. A charge must be moved through a stronger electric field with more energy, but it also must be moved through a weaker electric field with more energy.
Electric potential at a place in an electric field is the amount of work done to move the unit positive charge from infinity to that point, and electric potential energy is fundamentally different.
Given are the following values: Stored charge, Q= 1x 10⁻¹⁰ C Voltage, V=100 v
We are aware that the formula for a system's capacitance is C=Q/V
= 1 x 10⁻¹⁰ / 100.
=1 x 10⁻¹² C
As a result, it is the necessary remedy.
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A nuclear explosion results in a mass decrease of 2.10 g. how much energy is released during this explosion?(c = 3.00 x 108 m/s)
a. 2.25 x 10^12J
b. 1.89 x 10^13J
c. 1.89 x 10^14J
d. 6.30 x 10^5J
Answer: c. 1.89 x 10^14 J
Explanation:
By Einstein's equation, we know that:
E = m*c^2
Where m is the mass-consumed in this case:
m = 2.10g
And we must rewrite this in Kg, knowing that:
1kg = 1000g
Then:
m = 2.10g = (2.10/1000) kg = 0.0021 kg
And c is the speed of light:
c = 3*10^8 m/s.
Then the energy will be:
E = 0.0021 kg*(3*10^8 m/s)^2 = 1.89*10^14 Joules.
The correct option is:
c. 1.89 x 10^14J
Need Help Please and Thank You). Question 1: Explain how longitudinal waves and transverse waves are similar to each other and different from each other. Question 2) Compare and contrast reflection and refraction. Question 3) What does it mean that energy is neither created nor destroyed? ( Please No Plagiarism and Be 100% positive with your answer. Will Mark Brainliest. If you write anything down that doesn't contain to my question you will be reported. Need two answers.
Answer:The direction a wave propagates is perpendicular to the direction it oscillates for transverse waves. A wave does not move mass in the direction of propagation; it transfers energy.
Explanation:
A piece of metal has a mass of 200g in air and 170g when immersed in water.calculate its volume and density.(Density of water is 1000kgm take g=9.8ms)
density of object is 6.7g/cm³ and volume is 30cm³.
First, air has a low density, so the mass in air is very close to the true mass (mass in a vacuum). Let's say the true mass is 200g.
Then we can use the following formula to find the volume:
AM=TM-V•D where AM is the apparent mass (in water) and TM is the true mass (mass in vacuum which approximates mass in air). , V is the volume of water displaced by the object (which is also the volume of the object) and D is the density of the water, i.e.
170g=200g-V*(1,000g/cm3)
V=30cm³
Therefore The density of is approximately 200g÷30cm³=6.7g/cm³
If you want an exact answer, you can find the density of air under laboratory conditions. For example,
1.20g/L or 0.00120g/cm³. Then, using the above equations, we can set up a system of two equations with two unknowns.
200g=TM-V*(0.00120 g/cm³)
170g=TM-V*(1.000 g/cm³)
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Which type of wave can travel through enpty space? EXPLAIN.
a. Electromagnetic wave
b. Sound wave
c. Water wave
d.Seismic wave
Answer:
Electromagnetic waves carry energy.
Explanation:
The waves consist of transverse vibrations in electrical and magnetic fields, not vibrating particles.
8. A penny on its side moving at speed v slides off the horizontal surface of a table a vertical distance y from the floor.
(a) Show that the penny lands a distance v12y/g from the base of the coffee table.
(b) If the speed is 3.5 m/s and the coffee table is 0.4 m tall, show that the distance the coin lands from the base of the table is 1.0 m. (Use g = 9.8 m/s2.)
The horizontal distance of the penny from the base of the table is v(2y/g)^1/2.
The distance the coin lands from the base of the table is 1.0 m
Time of motion of the penny
The time of motion of the penny is calculated as follows;
y = vt + ¹/₂gt²
where;
v is initial vertical velocity = 0y = ¹/₂gt²
2y = gt²
t² = 2y/g
t = √(2y/g)
Horizontal distance of the pennyThe horizontal distance of the penny is calculated as;
X = Vₓt -----(1)
where;
Vₓ is initial horizontal velocity = vSubstitute the value of "t" into equation (1)
X = v(√(2y/g)),
X = v(2y/g)^1/2, shown
Distance of the coinUse the formula above to determine the distance the coin lands from the base of the table.
X = v(√(2y/g)),
X = 3.5[√(2x0.4/9.8)]
X = 3.5(0.2857)
X = 1.0 m, shown
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A 1.0 kg object is attached to a 0.50 m string. It is twirled in a horizontal circle above the ground at a speed of 5.0 m/s.
The direction of the acceleration at the point shown points towards which letter?
Given that,
Mass of the object, m = 1 kg
It moves in a circle of radius 0.5 m with a speed of 5 m/s
To find,
The direction of the acceleration.
Solution,
Whenever an object moves in a circular path, the only force that acts on its is centripetal force which is given by the formula as follows :
[tex]F=\dfrac{mv^2}{r}[/tex]
The centripetal acceleration acts in the direction of force. It acts along the radius of the circular path. In this figure, the direction of the acceleration is shown at point d.
Answer:
D!
Explanation:
took the test
If you are driving 80 km/h along a straight road and you look to the side for 1.7 s , how far do you travel during this inattentive period?
Express your answer using two significant figures.
Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.
How far did the driver travel during the inattentive period?Speed is simply referred to as distance traveled per unit time.
Mathematically, Speed = Distance ÷ time.
Given the data in the question;
Speed = 80 km/hTime = 1.7sDistance travelled = ?First, convert 1.7 seconds to hours.
Time = 1.7s = (1.7 / (60×60)hr = 1.7/3600 hrs
Now, find the distance traveled during the inattentive period.
80 km/h = Distance ÷ 1.7/3600 hrs
Distance = 80 km/h × 1.7/3600 hrs
Distance = 136/3600 km
Distance = 0.037 km.
Given the speed of the driver and the time elapsed, distance traveled during his inattentive period is 0.037 kilometers.
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Explain how the situation shown above would be different if the skier experiences friction while traveling downhill. Include the terms kinetic energy, heat energy, mechanical energy, total energy and friction. Must answer in complete sentences.
Answer:
The force of friction acts in the direction opposite to the direction of motion. If friction would have been applied to the skier it would have resulted in a lower velocity and less kinetic energy.
Explanation:
Suppose that you’re in a moving car and the motor stops running. You step on the brakes and slow the car to half speed. If you release your foot from the brakes, will the car speed up a bit, or will it continue at half speed and slow due to friction?
The car will continue at half speed and slow down due to friction after the brakes are released.
The given situation is that the car's motor is stopped and brakes are applied until the car reaches its half speed and the brakes are released. So after the brakes are released, the car will not gain any speed, since there is no force applied. Then it will gradually slow down due to friction.
According to the law of inertia ( i.e., Newton's first law of motion ), an object will tend to stay at rest or motion until an external force is applied. So based on this law, the car will continue at the speed the brakes were released and eventually slow down.
Therefore, the car will continue at half speed and slow down due to friction after the brakes are released.
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A girl of mass 50kg jumps out of a rowing boat of mass
300 kg on to the bank, with a horizontal velocity of 3 m/s.
With what velocity does the boat begin to move backwards?
Given that,
Mass of a girl, m = 50 kg
Mass of the boat, m' = 300 kg
Speed of girl, v = 3 m/s
To find,
The velocity with which the boat begin to move backwards.
Solution,
Let the velocity be v'. Using the conservation of momentum to find it. It is given by :
[tex]mv=m'v'\\\\v'=\dfrac{mv}{m'}\\\\v'=\dfrac{50\times 3}{300}\\\\v'=0.5\ m/s[/tex]
So, the velocity moves backward with a speed of 0.5 m/s.
What is the period of an object that makes 6 revolutions a minute?
Answer:
T = 10 s
Explanation:
First, we need to find the frequency of the object as follows:
[tex]Frequency = f = \frac{Speed\ in\ rpm}{60}[/tex]
where,
Speed = Angular Speed = 6 rpm
Therefore,
[tex]f = \frac{6\ rpm}{60}\\\\f = 0.1\ Hz[/tex]
Now, for time period (T):
[tex]Time\ Period = T = \frac{1}{f}\\\\T = \frac{1}{0.1\ Hz}\\\\[/tex]
T = 10 s
How much work is required to slide a 3.00 kg box 6.90 m along (up) a frictionless incline plane that is inclined at an angle of 25 degrees?
The amount of work required to slide the 3 Kg box 6.90 m along (up) the frictionless incline plane is 183.85 J
What is work done?Work is defined as the product of force and distance moved in the direction of the force. mathematically it is expressed as:
Work done (Wd) = force (F) × distance (d)
Wd = fd
Where height is involved, the workdone is given as as:
Work done (Wd) = mass (m) × acceleration due to graity (g) × height (h)
Wd = mgh
Considering angle projection,
Wd = mghCosθ
Thus, we can detertmine the work done as follow:
Mass (m) = 3 KgHeight (h) = 6.9 mAcceleration due to gravity (g) = 9.8 m/s²Angle (θ) = 25°Workdone (Wd) =?Wd = mghCosθ
Wd = 3 × 9.8 × 6.9 × Cos 25
Wd = 183.85 J
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A ball is dropped from a tall bridge of height 48 m. What will the speed of the ball be immediately before it hits the ground, in units of m/s?
Answer:
2700
Explanation:
because calculate the minute1=60×45=2700
Answer:
[tex]v \approx 30.67\,\,\frac{m}{s}[/tex]
Explanation:
We use the kinematic formula for constantly accelerated motion given below:
[tex]v^2=v_0^2+2\,a\Delta x\\v^2=0+2\,g\,(48)\\v^2=940.8\\v \approx 30.67\,\,\frac{m}{s}[/tex]
A car is driving directly north on the freeway at a speed of 119 km/h and a truck is leaving the freeway driving 87.7 km/h in a direction that is 35° west of north. Assume north to be in the +y-direction and east to be in the +x-direction.
What is the magnitude of the velocity of the truck relative to the car?
What is the direction of the velocity of the truck relative to the car?
The magnitude of the velocity of the truck relative to the car is 183.9 km/h
The direction of the velocity of the truck relative to the car is 67 ⁰ north of west.
Velocity of the truck relative to the carThe velocity of the truck relative to the car is the resultant velocity of the vehicles.
The resultant velocity of the car is calculated as follows;
Vertical component of the velocityVyi = 119 km/h
Vy2 = 87.7 km/h x sin(35) = 50.3 km/h
Vy(total) = 119 km/h + 50.3 km/h = 169.3 km/h
Horizontal component of the velocityVx = -87.7 x cos(35) = -71.84 km
Resultant velocityv = √Vy² + Vx²
v = √[(169.3²) + (-71.84)²]
v = 183.9 km/h
Direction of the velocityθ = arc tan(Vy/Vx)
θ = arc tan(169.3 / -71.84)
θ = -67 ⁰
θ = 67 ⁰ north of west.
Thus, the magnitude of the velocity of the truck relative to the car is 183.9 km/h and the direction of the velocity of the truck relative to the car is 67 ⁰ north of west.
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The speed of sound in air is approximately 340 m/s. The speed of light in air is approximately 3 x 108 m/s. If 10 seconds elapses between seeing a lightning strike and hearing the thunder, how far away was the lightning strike?
Answer:
3400 m
Explanation:
Both lightning and thunder happen at the same time but one is faster than the other. The distance traveled by a sound can be calculated from its speed such that;
speed = distance/time, hence, distance = speed x time.
For a thunder with 340 m/s speed and 10 seconds away from lightning, the distance between the thunder and the lightning can be calculated as;
distance = 340 m/s x 10 s = 3400 m
When practicing deep breathing, it is best to repeat the steps for
minutes to start and then increase the time as needed.
Answer:
c.) 10 to 15 minutes
Explanation:
yw :)
Answer:
c.) 10 to 15 minutes
Explanation:
Mary and John are seated on a bench a distance 2 part. Suddenly, John moves closer to Mary and claims that he has been drawn by the gravitational force. Is John’s claim justifiable? Show quantitatively. (Assume the masses of John and Mary are 67 and 55 respectively, and the coefficient of static friction between John and the bench is 0.15). [4]
Answer:
no
gravitational force between them is far smaller than the frictional force between the guy and the bench
What's the quantum number for a particle in an infinite square well if the particle's energy is 64 times the ground-state energy?
Answer:
8
Explanation:
The energy levels is given as
E(n) = n² * h² / ( 8 * m * L²), where
n = 1, 2, 3, 4,... etc
At ground state energy (n = 1), therefore is E(g) = h² / (8 * m * L²).
We can then say that
E(n) = n² * Eg
Therefore, to have E = 64 Eg, we must have n² = 64. And for n² to be equal to 64, we find the square root of n
n = √64
n = 8
Essentially, the needed quantum number is 8
what do the sound waves made by the bell carry to your ear
Answer:
When these waves reach our ears, they make our eardrums vibrate, and we hear the sound of the bell ringing.
Explanation:
Answer: When a bell is pounded, the metal vibrates. The vibrations travel through the air as sound waves. When these waves reach our ears, they make our eardrums vibrate.
Explanation:
We hear the sound of the bell ringing. Sound always needs to travel through some kind of medium, such as air, water, or metal.
Sorry if this is not the answer you are looking for
A student applies an upward force of 52 N to a 5.6-kg physics textbook. Find the book’s acceleration (positive for up, negative for down).
Answer: The acceleration is roughly 9.3 m/s^2
The acceleration is positive.
=====================================================
Work Shown:
Using Newton's Second Law, we get,
F = m*a
52 = 5.6a
5.6a = 52
a = 52/5.6
a = 9.28571428571429 which is approximate
a = 9.3
I rounded to 2 significant figures because both 52 and 5.6 are to 2 sig figs.
The acceleration is positive because the student applied an upward force.
The units for the acceleration are in meters per second squared, abbreviated as m/s^2.
An acceleration of 9.3 m/s^2 means that after every second, the velocity has increased by 9.3 m/s.
Which of the following is a disadvantage of hybridization? 1.offspring are genetic copies of the parent 2.offspring are stronger and larger than the parents 3.offspring have a combination of traits from both parents 4.offspring often have health problems and are sterile
Answer:
Explanation:
4 is right
are aliens real in 2020
Answer:
i believe that they are or there's something out there
Explanation:
:)
what is the object's position at 6s?
Answer:
6sec and 8 postion
Explanation:
A section of a sphere has a radius of curvature of 0.72 m. If this section is painted with a reflective coating on both sides, what is the focal length of:
Answer:
The value is [tex]f = 0.36 \ m[/tex]
Explanation:
From the question we are told that
The radius of curvature is [tex]R = 0.72 \ m[/tex]
Generally the radius of curvature is mathematically represented as
[tex]R = 2f[/tex]
Here [tex]f[/tex] is the focal length hence
[tex]f = \frac{R}{2}[/tex]
=> [tex]f = \frac{0.72}{2}[/tex]
=> [tex]f = 0.36 \ m[/tex]
Which of the following would be examples of derived demand?
1. A school hiring more teachers because the school's enrollment increased.
II. More people working at the movie theatre on Friday night because attendance increased.
III. More construction workers are needed because more people can afford to buy a new house.
O I and II only
o I and III only
Il and Ill only
O I, II and III
Answer:
The last one
Explanation:
on the exam
Among the following the derived demands are options 1 and 3 only. Because in each case, the demand for one thing is originated by the demand for another.
What is derived demand?The phrase derived demand in economics refers to the demand for a factor of production or intermediate good that results from the demand for another intermediate or final good. In essence, consumer demand for the firm's product determines how much a firm will need.
Additionally, if activity in one area rises, any sector that contributed to the success of the first sector may also experience growth. Here, the school is hiring more teachers because enrollment is increased. Thus, enrolling more teachers satisfies the demand by greater enrollments.
Similarly by recruiting more construction workers the increased demand for new house by people can be solved. However, the second case for filling the attendance is a necessary and not a derived demand.
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Which of these would have a high velocity? * O zamboni lamborgini O shopping cart O golf cart Search A
Golf carts have a high velocity.
Without any improvements, the conventional golf cart's peak velocity is between 12 and 14 miles per hour. The highest velocity that you can get on a golf cart without any upgrades or modifications is around 14 mph.
We can determine how quickly or slowly an item is traveling using the phrases velocity and speed. It occurs to us frequently that we must determine which of two or more moving things is traveling quicker. If both vehicles are traveling in the same direction along the same route, it is simple to determine which is quicker. It is challenging to identify who is moving quickest when their direction of motion is opposing. The idea of velocity is useful in these situations.
When gravity first exerts force on an item, its initial velocity defines how quickly the thing moves. The final velocity, on the other hand, is a vector number that gauges a moving body's speed and direction after it has attained its maximum acceleration.
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What did kind of energy did the ruler gain when you bent it with your left hand? why?
Answer:
potential energy
Explanation:
The bent ruler possesses elastic potential energy.
• The bending of the ruler depends upon the material of which it is made up of.
• The ruler after bending will gain elastic potential energy.
• The energy stored as an outcome of applying a force to deform an elastic object is known as the elastic potential energy.
• This energy is stored unless and until the removal of force takes place and the ruler moves back to its original shape.
• When the energy is released or when the bent ruler is released from the left hand, then the potential energy stored in it gets convert to kinetic energy and the ruler will recoil or vibrate briskly.
Thus, it is the elastic potential energy gained by the ruler when one bent it with the left hand.
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What is the total charge of barium oxide?
Conveyor belts are often used to move packages around warehouses. The conveyor shown below moves packages at a steady 4.0 m/s. A 500 N employee decides to catch a ride by sitting on a 1,000 N box for a 50 m trip as shown below:
What is the work done by the employee on the box?
Answer:
0 j
Explanation:
The work done by the employee on the box at the given zero displacement is 0 J.
The given parameters;
Constant velocity of the conveyor, v = 4 m/sWeight of the employee, W = 500 NWeight of the box, W = 1,000 NDistance of the trip, h = 50 mThe work done by the employee on the box is calculated as follows;
W = Fd
where;
F is the applied force on the box by employee = weight of the employeed is the distance through which the box is movedSince the employee sits on the box without moving it, the distance moved by the box = 0
W = 500 x 0
W = 0 J
Thus, the work done by the employee on the box is 0 J.
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What is the frequency of a wave that has a period of 0.5 seconds?
A. 0.5 Hz
B. 2 Hz
C. 200 Hz
D. 20 Hz
Answer:
B. 2 Hz
Explanation:
Given parameters:
Period of the wave = 0.5Hz
Unknown:
Frequency of the wave = ?
Solution:
Frequency is the number of waves that passes through a point.
Period is the time taken for a number of waves to pass through a point.
Period is the inverse of frequency
Frequency = [tex]\frac{1}{t}[/tex]
t is the period
Frequency = [tex]\frac{1}{0.5}[/tex] = 2Hz
Answer:2
Explanation: