Can the sum of the magnitudes of two vectors ever be equal to the magnitude of the sum of the same two vectors? If no, why not? If yes when ?

A Thermal energy of the air is 17 J of heat to the surroundings.

Thus, Thermal energy is produced by materials whose molecules and atoms vibrate more quickly as a result of a rise in temperature.

The atoms and molecules that make up matter are always in motion. The increase in temperature caused by heating a substance causes these particles to accelerate and collide.

The energy that arises from a heated substance is referred to as thermal energy. The more the substance's thermal energy and the more its particles travel at higher temperatures.

Thus, A Thermal energy of the air is 17 J of heat to the surroundings.

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According to figure where the point P is located so that the magnitude of the Field at point p= Zero electric field will be [tex]E=\frac{1}{4\pi \epsilon_0s^3} \sqrt{q^2d^2}[/tex].

The electric field is a fundamental concept in physics that describes the force experienced by a charged particle in the presence of other charges. It is a vector field, which means it has both magnitude and direction at each point in space.

The electric field is created by electric charges. A positive charge creates an outward electric field, while a negative charge creates an inward electric field.

The strength or magnitude of the electric field at a given point depends on the magnitude of the charge creating the field and the distance from that point to the charge.

E due to the dipole formed by charges at extreme end,

[tex]E_x=k_p/d^3[/tex] in the x-direction

E due to the charge at center

[tex]E_y=k_q/d^3[/tex]

Net electric field is,

[tex]E=\frac{1}{4\pi \epsilon_0s^3} \sqrt{q^2d^2}[/tex]. as p = 0.

Thus, the answer is  [tex]E=\frac{1}{4\pi \epsilon_0s^3} \sqrt{q^2d^2}[/tex].

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Your question seems incomplete, the probable complete question is:

According to figure below where the point P is located so that the magnitude of the Field at point p= Zero ?

We can measure the flow rate of various liquid by pouring the liquid down an incline and time how long it takes each one to reach the bottom.

option C.

The flow rate of a liquid is how much fluid passes through an area in a particular time.

Flow rate can be articulated in either in terms of velocity and cross-sectional area, or time and volume. As liquids are incompressible, the rate of flow into an area must be equivalent to the rate of flow out of an area.

Generally, the best equipment to measure the flow rate of a liquid is flow meters. In the absence of flow meters, we can other methods such as the one given in the options.

We can pour the various liquid down an incline and time how long it takes each one to reach the bottom.

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Answer:

3 : Presence of a catalyst and Temperature

4 : correct, nothing needed to change

5 : Le Chatelier's principle states that when an equilibrium system is subjected to a disturbance or stress, it will undergo a shift in the direction that counteracts the impact of the stress, ultimately reestablishing a new state of equilibrium.

The 1st order bright spot is located approximately 1.1025x10^-9 m away from the central bright spot.

To determine the distance of the 1st order bright spot from the central bright spot in a double-slit interference setup, we can use the formula for the position of bright fringes:

y = (m * λ * L) / d

where:

y is the distance from the central bright spot to the m-th order bright spot,

m is the order of the bright spot (in this case, m = 1 for the 1st order),

λ is the wavelength of light,

L is the distance from the slits to the screen (in this case, L = 50 cm = 0.5 m), and

d is the distance between the slits (d = 2.00x10^4 cm = 200 m).

Given that the frequency of light is 6.8x10^14 Hz, we can use the relationship between frequency and wavelength to calculate the wavelength (λ) using the formula:

c = λ * f

where c is the speed of light (approximately 3x10^8 m/s).

Rearranging the formula, we have:

λ = c / f

λ = (3x10^8 m/s) / (6.8x10^14 Hz)

Calculating the value of λ, we get:

λ = 4.41x10^-7 m

Now we can substitute the values into the formula for the position of the bright spot:

y = (1 * 4.41x10^-7 m * 0.5 m) / 200 m

Simplifying the equation, we have:

y = 1.1025x10^-9 m

In summary, the distance of the 1st order bright spot from the central bright spot in this double-slit interference setup is approximately 1.1025x10^-9 m.

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Answer:

both objects are negatively charged.

The final amount of pressure caused by the force is 90 N/m².

Initial amount of force, F₁ = 22 x 10³ N

Initial amount of pressure produced, P₁ = 110 N/m²

Final amount of force exerted, F₂ = 18 x 10³ N

Pressure is defined as the amount of force acting on an object per unit area of the object.

So, we can say that the force and pressure are directly proportional.

F ∝ P

So, F₁/P₁ = F₂/P₂

Therefore, the final amount of pressure caused by the force is,

P₂ = F₂P₁/F₁

P₂ = 18 x 10³x 110/22 x 10³

P₂ = 18/0.2

P₂ = 90 N/m²

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Answer:

4000 Nm^-2

Explanation:

Dude that "zam" drove me away, anyway:

Given:

Force on the large piston (F1) = 4000 N

Cross-sectional area of the large piston (A1) = 1 m²

Cross-sectional area of the small piston (A2) = zam (let's assume zam represents the area in square meters)

According to Pascal's law, the pressure exerted on the large piston (P1) is equal to the pressure exerted on the small piston (P2):

P1 = P2

Pressure is defined as force divided by area:

P1 = F1 / A1

P2 = F2 / A2

Since P1 = P2, we can equate the two expressions:

F1 / A1 = F2 / A2

Rearranging the equation to solve for F2, the force on the small piston:

F2 = (F1 / A1) * A2

Substituting the given values:

F2 = (4000 N / 1 m²) * zam

Now, to calculate the pressure exerted on the small piston (P2), we can divide the force by the area:

P2 = F2 / A2

Substituting the values we obtained:

P2 = [(4000 N / 1 m²) * zam] / zam

The area "zam" cancels out in the equation, leaving us with:

P2 = 4000 N/m²

Therefore, the pressure exerted on the small piston is 4000 N/m².

To determine the effort required on the small piston, we need to know the area of the small piston. Once we have that information, we can substitute it into the equation for F2 to calculate the effort required

1. The angular momentum of the combined bullet-block system about the vertical pivot axis is 0.

2. The fraction of the original kinetic energy of the bullet converted into internal energy within the bullet-block system during the collision is given by [m * v² - (M + m) * V²] / [m * v²].

1. To find the angular momentum of the combined bullet-block system about the vertical pivot axis, we need to consider the initial and final angular momentum.

Initially, before the collision, the bullet has no angular momentum about the pivot axis since it is moving parallel to the table and perpendicular to the rod.

After the collision, when the bullet embeds within the block, the combined bullet-block system starts rotating about the pivot axis due to the conservation of angular momentum.

The angular momentum of the system can be calculated using the formula:

Angular momentum = moment of inertia × angular velocity

The moment of inertia of the system depends on the distribution of mass and the axis of rotation. Assuming the block and bullet have negligible rotational inertia compared to the rod, we can consider the moment of inertia to be that of the rod.

The moment of inertia of a rod rotating about one end (pivot) is given by:

I = (1/3) * M * ℓ²

where M is the mass of the block, and ℓ is the length of the rod.

The angular velocity (ω) can be determined by considering the conservation of angular momentum:

Initial angular momentum = Final angular momentum

0 = (1/3) * M * ℓ² * ω

Since the initial angular momentum is zero, the final angular momentum of the system is also zero.

Therefore, the angular momentum of the combined bullet-block system about the vertical pivot axis is 0.

2. To find the fraction of the original kinetic energy of the bullet that is converted into internal energy within the bullet-block system during the collision, we can use the principle of conservation of kinetic energy.

The initial kinetic energy of the bullet before the collision is given by:

Initial kinetic energy = (1/2) * m * v²

After the collision, the bullet embeds within the block, and both the bullet and the block gain internal kinetic energy due to their rotational motion.

The final kinetic energy of the bullet-block system is given by:

Final kinetic energy = (1/2) * (M + m) * V²

where V is the final velocity of the combined bullet-block system after the collision.

Since the bullet and block are now rotating about the pivot axis, part of the initial kinetic energy is converted into internal rotational kinetic energy.

The fraction of the original kinetic energy converted into internal energy can be calculated as:

Fraction of kinetic energy converted = (Initial kinetic energy - Final kinetic energy) / Initial kinetic energy

Substituting the values:

Fraction of kinetic energy converted = [(1/2) * m * v² - (1/2) * (M + m) * V²] / [(1/2) * m * v²]

Simplifying the equation, we can cancel out common terms:

Fraction of kinetic energy converted = [m * v² - (M + m) * V²] / [m * v²]

Therefore, the fraction of the original kinetic energy of the bullet converted into internal energy within the bullet-block system during the collision is given by [m * v² - (M + m) * V²] / [m * v²].

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Sound travels more quickly through a solid than through a liquid or a gas because the particles in a solid are closer together than the particles in a liquid or a gas

The speed of sound in a material is said to be determined by the density of the material and the elasticity of the material.

The density of a material is a measure of how much mass is contained in a given volume.

The elasticity of a material is a measure of how much the material can be stretched or compressed without breaking.

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Answer:

Explanation:

Unfortunately, as an AI text-based model, I cannot directly view or interpret images. However, I can still provide you with the information you need to identify Polaris and its position in the night sky.

To locate Polaris using the stars of the Big Dipper (also known as the Great Dipper or Ursa Major), you can follow these steps:

1. Locate the Big Dipper: The Big Dipper is a prominent asterism, or a recognizable pattern of stars, within the constellation Ursa Major (the Great Bear). It is visible in the northern hemisphere during most of the year.

2. Identify the pointer stars: The two stars on the outer edge of the Big Dipper's bowl, farthest from the handle, are called the pointer stars. These stars are named Dubhe and Merak.

3. Extend the line between the pointer stars: Mentally extend an imaginary line that passes through Dubhe and Merak, extending it for approximately five times the distance between the pointer stars.

4. Locate Polaris: The extended line will lead you to Polaris, also known as the North Star. Polaris is relatively bright and appears as the last star in the handle of the Little Dipper (Ursa Minor constellation). It lies almost directly above the North Pole of the Earth and remains nearly fixed in the sky while other stars appear to rotate around it as the Earth rotates.

By following these steps, you should be able to identify Polaris and its position in the night sky, even without an image.

Polaris is positioned directly above the celestial North Pole in the sky, making it a useful navigation tool. The easiest way to locate it is by identifying the Great Dipper constellation and using its two pointer stars, Dubhe and Merak, to lead to the North Star.

The star Polaris, also known as the North Star, is beneficial for navigation due to its fixed position in the sky above the celestial North Pole. The best way to locate it is by first finding the Great Dipper constellation. Two stars in the bowl of this Dipper, named Dubhe and Merak, form a line that leads directly to Polaris.

In the given image, without the benefit of visual reference, it is difficult to identify the specific position of Polaris. However, remember that in actual practice, you would find the two pointer stars of the Great Dipper and follow a line from these stars to locate Polaris.

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The spring constant k based on the information is 12.0 N/m.

From the information, a spring stretches 0.294-m when a 0.360-kg mass is gently suspended from it as in Fig. 11–3b. The spring is then set up horizontally with the 0.431-kg mass resting on a frictionless table.

The spring constant k is the force required to stretch or compress the spring by a unit distance. In this case, the spring is stretched by 0.294 m when a 0.360 kg mass is suspended from it.

This means that the force exerted by the spring is equal to the weight of the mass, which is 0.360 kg x 9.8 m/s^2 = 3.53 N.

Therefore, the spring constant k is:

= 3.53 N/0.294 m

= 12.0 N/m.

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Here are five potential-kinetic energy conversions that could be shown in the construction of a device: Pendulum, Roller Coaster, Wind-up Toy, Elastic Slingshot, Windmill.

Pendulum: A pendulum consists of a weight attached to a string or rod, suspended from a fixed point. When the weight is lifted to a certain height, it possesses gravitational potential energy.

As the weight is released, it swings back and forth, converting the potential energy into kinetic energy. At the highest point of each swing, the weight briefly comes to a stop and has maximum potential energy, which is then converted back to kinetic energy as it swings downward.

Roller Coaster: In a roller coaster, potential-kinetic energy conversions occur throughout the ride. When the coaster is pulled up to the top of the first hill, it gains gravitational potential energy.

As the coaster descends, the potential energy is converted into kinetic energy, resulting in a thrilling and high-speed ride. Subsequent hills and loops continue to convert potential energy into kinetic energy and vice versa as the coaster moves along the track.

Wind-up Toy: Wind-up toys typically have a spring mechanism inside. When the toy is wound up, potential energy is stored in the wound-up spring. As the spring unwinds, it transfers its potential energy into kinetic energy, causing the toy to move or perform actions. The kinetic energy gradually decreases as the spring fully unwinds.

Elastic Slingshot: With an elastic slingshot, potential-kinetic energy conversions are evident when the slingshot is stretched. As the user pulls back on the elastic band, potential energy is stored.

Windmill: Windmills harness the kinetic energy of the wind and convert it into other forms of energy. As the wind blows, it imparts kinetic energy to the blades of the windmill. The rotating blades then transfer this kinetic energy into mechanical energy, which can be used for various purposes such as grinding grains or generating electricity.

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The voltage supplied to the wire is 120 volts.

To calculate the voltage supplied to a wire, we can use Ohm's Law, which states that voltage (V) is equal to the product of current (I) and resistance (R). Mathematically, this relationship is expressed as V = I * R.

In this case, the wire has a resistance of 1200 Ω (ohms) and a current of 0.10 amps. We can substitute these values into the formula to find the voltage:

V = I * R

V = 0.10 A * 1200 Ω

V = 120 A * Ω

Therefore, the voltage supplied to the wire is 120 volts.

It's important to note that Ohm's Law holds true for resistors and other components in a circuit that obey Ohm's Law. In real-world scenarios, there may be other factors to consider, such as the presence of non-ohmic devices or components with varying resistance.

Additionally, in an AC (alternating current) circuit, the relationship between voltage, current, and resistance may involve complex quantities and phase differences. However, for a simple DC (direct current) circuit with a linear resistor, Ohm's Law provides an accurate relationship between voltage, current, and resistance.

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Answer:

Yes, the shark's weight or mass is what causes the bottom string to break. The weight of the shark creates tension on the bottom string, which can cause it to snap if the tension becomes too great.

Answer:

In the string pull illustration you described, the gradual pull of the lower string causes the top string to break. This occurs because of the tension that is created in the top string as a result of the pull. The weight or mass of the ball is not the primary cause of the breakage in this case.

Using active solar energy for a home offers benefits such as lower installation costs, homeowner control over the system, reduced reliance on the grid, and potential cost savings over time. Option A

A) Installation costs are less with active solar systems: Active solar energy systems, such as solar panels or solar water heaters, can be installed directly on the home or property, eliminating the need for extensive infrastructure development associated with utility-scale solar energy projects.

B) Homeowner is not responsible for installation costs: While utility-scale solar energy projects may require homeowners to bear the costs of installation and infrastructure development, active solar systems for homes typically allow homeowners to directly invest in their own renewable energy solutions.

This means that homeowners have control over the installation process and can choose the system that best fits their budget and energy needs.

C) Energy comes from the active system, not a grid: Active solar systems for homes generate energy on-site using sunlight, allowing homeowners to reduce their reliance on the traditional power grid.

This independence from the grid provides benefits such as energy self-sufficiency, reduced vulnerability to power outages, and potential savings on utility bills. It also allows homeowners to have a direct and tangible impact on reducing their carbon footprint.

D) Homeowners will see less cost savings over time: This statement is incorrect. Over time, homeowners who invest in active solar energy systems can potentially experience significant cost savings. By generating their own renewable energy, homeowners can reduce their reliance on electricity provided by the utility company, which often comes with rising costs.

As utility rates increase, the savings from generating solar energy can become more substantial, allowing homeowners to recoup their initial investment and potentially even earn credits through net metering programs.

In summary, using active solar energy for a home offers benefits such as lower installation costs, homeowner control over the system, reduced reliance on the grid, and potential cost savings over time. These advantages make it an attractive option for homeowners seeking to embrace renewable energy and reduce their environmental impact. Option A

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The current flowing over the 30 Ω resistor is 0.4 A.

To discover the current streaming over the 30 Ohm resistor, able to apply Ohm's Law, which states that the current (I) is break even with to the voltage (V) partitioned by the resistance (R). In this case, the voltage over the circuit is given as 9.0 V.

To calculate the full resistance of the circuit, we ought to consider the resistors in arrangement and parallel. The resistors with values of 40 Ω and 50 Ω are in serie.

Hence, the sum of their value (R_series )= 40 Ω + 50 Ω = 90 Ω. The 20 Ω and 10 Ω resistors are in parallel, hence, their resistance is represented as (1/R_parallel) = 1/20 Ω + 1/10 Ω = 1/10 Ω. Disentangling this expression gives R_parallel = 6.67 Ω.

Presently, ready to calculate the entire resistance of the circuit. The resistors with values of 30 Ω and 90 Ω (from the arrangement combination) are in parallel, so their identical resistance is given by 1/R_total = 1/30 Ω + 1/90 Ω = 1/22.5 Ω. Rearranging this expression gives R_total = 22.5 Ω.

At last, able to apply Ohm's Law to discover the current over the 30 Ω resistor. I = V / R_total = 9.0 V / 22.5 Ω ≈ 0.4 A.

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The greatest horizontal range of the rocket beyond point A is approximately 17.89 meters.

To find the greatest horizontal range of the rocket beyond point A, we need to analyze the projectile motion of the rocket after it leaves the incline.

We can break down the rocket's motion into horizontal and vertical components. The horizontal component remains constant, while the vertical component is influenced by gravity. Since the rocket is subject only to gravity after leaving the incline, the horizontal velocity remains constant throughout the motion.

First, let's calculate the initial velocity of the rocket in the horizontal direction. We can use the acceleration and the distance traveled along the incline to find the time taken to reach the end of the incline.

Using the equation of motion: distance = initial velocity × time + (1/2) × acceleration × time^2, we can substitute the given values:

200.0 m = 0 × t + (1/2) × 1.60 m/s^2 × t^2.

Simplifying the equation, we get:

[tex]1.60 t^2 = 200.0,\\t^2 = 200.0 / 1.60,\\t^2 = 125,[/tex]

t = √125,

t ≈ 11.18 s.

Now that we have the time taken to reach the end of the incline, we can calculate the horizontal distance traveled by the rocket using the formula: distance = velocity × time.

Since the horizontal velocity remains constant at 1.60 m/s, the horizontal distance is:

distance = 1.60 m/s × 11.18 s,

distance ≈ 17.89 m.

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The increase in length of the iron wire when warmed from 20°C to 45°C is approximately 8.25 millimeters. The specific heat capacity of the object is approximately 9.62 J/kg°C. The heat capacity of the object is approximately 1.83 J/°C.

ΔL = L × α × ΔT

Where:

ΔL is the change in length

L is the original length of the wire

α is the coefficient of linear expansion for iron

ΔT is the change in temperature

The coefficient of linear expansion for iron is typically 1.1 x [tex]10^(^-^5^)[/tex] °[tex]C^(^-^1^)[/tex].

Given:

L = 30 m (original length of the wire)

α = 1.1 x [tex]10^(^-^5^)[/tex] °[tex]C^(^-^1^)[/tex] (coefficient of linear expansion)

ΔT = 45°C - 20°C = 25°C (change in temperature)

ΔL = 30 m × (1.1 x [tex]10^(^-^5^)[/tex] °[tex]C^(^-^1^)[/tex]) × 25°C

= 30 m × 1.1 x[tex]10^(^-^5^)[/tex] × 25

= 8.25 x [tex]10^(^-^3^)[/tex] m

2) Q = mcΔT

Where:

Q is the heat energy transferred

m is the mass of the object

c is the specific heat capacity

ΔT is the change in temperature

Given:

Q = 2200 J (heat energy transferred)

m = 190 g (mass of the object)

ΔT = 12°C (change in temperature)

a. Specific heat capacity (c):

one need to rearrange the formula to solve for c:

c = Q / (m × ΔT)

Substituting the given values:

c = 2200 J / (190 g × 12°C)

First, need to convert the mass to kilograms:

m = 190 g = 190 g / 1000 = 0.19 kg

Now can calculate the specific heat capacity:

c = 2200 J / (0.19 kg × 12°C)

= 9.62 J/(kg°C)

b. Heat capacity (C):

The heat capacity is the amount of heat energy required to raise the temperature of the object by 1 degree Celsius.

C = mc

Substituting the given values:

C = 0.19 kg × 9.62 J/(kg°C)

= 1.83 J/°C

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Mass is the measure of the amount of matter in an object and remains constant regardless of location, measured in units like kilograms or grams, while weight represents the gravitational force exerted on an object, varying with the strength of the gravitational field and measured in units like newtons or pounds.

Mass and weight are distinct concepts in physics, differing in their definitions, units of measurement, how they are measured, and what they depend on. Here's a breakdown of their differences:

Mass:

Definition: Mass refers to the amount of matter in an object. It is an intrinsic property and remains constant regardless of the object's location or gravitational environment.

Units of measurement: The standard unit of mass in the International System of Units (SI) is the kilogram (kg). Other common units include grams (g) and metric tonnes (t).

Measurement: Mass can be measured using various techniques, including balances and scales. These instruments compare the unknown mass to known masses and determine the equilibrium or balance point.

Dependence: Mass is independent of gravity and remains the same regardless of the gravitational force acting on the object.

Weight:

Definition: Weight is the force exerted on an object due to the gravitational pull of a celestial body (usually Earth). It represents the measure of the object's gravitational attraction towards that body.

Units of measurement: The standard unit of weight in the SI system is the newton (N). However, weight is commonly expressed in units of force, such as pounds (lb) or kiloponds (kp).

Measurement: Weight is typically measured using a spring scale or a device known as a weighing scale. These instruments rely on the deformation or stretching of a spring to determine the gravitational force acting on an object.

Dependence: Weight depends on the strength of the gravitational field where the object is located. The weight of an object will vary depending on the celestial body it is interacting with, as gravitational forces differ.

Therefore, mass refers to the amount of matter in an object and is measured in units like kilograms or grams. It remains constant regardless of location and is determined using balances or scales. Weight, on the other hand, represents the gravitational force exerted on an object and is measured in units like newtons or pounds. It varies based on the strength of the gravitational field and is measured using spring scales or weighing instruments.

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Ohm's law is defined as the applied voltage (V) is directly proportional to the current flow (I) in the circuit. V =IR, where R is the resistance of the circuit that resists the current flow in the circuit, and the unit of resistance is the ohm.

From the given,

1) a) resistors in the circuit are connected in parallel, then the voltage in the circuit remains the same. The voltage across each resistor is 9V.

  b) the current in each resistor is given by, V=IR

I₁ = V/R₁ = 9/10kΩ=0.9mA.

I₂ = V/R₂ = 9/2kΩ = 4.5mA

I₃ = V/R₃ = 9/1kΩ = 9mA.

2) a) the resistances are connected in parallel, the effective resistance is 1/R(eff) = 1/R₁ + 1/R₂

1/R(eff) = 1/(100) + 1/(250)

           = 250+100/25000

          = 350/25000

          = 7/500

R₁(eff) = 500/7

1/R(eff) = 1/R₁ + 1/R₂

            = 1/350 + 1/200

            = 200+350/70000

            = 550/70000

            = 11/1400

R₂(eff) = 1400/11

Thus, the two effective resistances are connected in series,

R(e) = R₁(eff) + R₂(eff)

      = 500/7 + 1400/11

      = (500×11) + (1400×7)/77

      = 5500 + 9800 / 77

      = 15300/77

R(e) = 198 Ω.

B) total current, I = V/R

  I = 24 /198

   = 121mA.

3) a) the resistances are connected in series, the total resistance,

R(eff) = R₁ + R₂

         = 3+3

R(eff) = 6Ω

b)Current, I = V/R

I = 12/6

  = 2A

c)Power, P = I²R = 2×2×6

      P = 24W is the power in each bulb.

d) Power, P = VI = 12×2 = 24 W, is the power in battery.

4) a) the resistances are connected in parallel,

1/R(eff) = 1/R₁ + 1/R₂

           = 1/3 + 1/3

           = 2/3

R(eff) = 3/2Ω

b) In a parallel circuit, the voltage remains unchanged.

Voltage = 12V

c) Current, I = V/R

I₁ = V/R₁ = 12/3 = 4A

I₂ = V/R₂ = 12/3 = 4A.

d) power, P = I²R =4²3=48W.

e) Total current in the circuit, I = I₁+I₂

I = 4 + 4

 = 8A

f) power supplied by a battery, P = VI

P = 12×4 = 48 W.

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Answer:

60 kilometers per hr

Explanation:

Gas and plasma are indeed phases of matter, but they have distinct characteristics and applications.

Gas is a state of matter where particles have high energy and are free to move around, filling the space they occupy. Gaseous substances, like air, are typically composed of neutral atoms or molecules.

Plasma, on the other hand, is an ionized gas consisting of positively and negatively charged particles. It is formed when gas is heated to extremely high temperatures or exposed to a strong electric field. Plasma is found in stars, lightning, and fluorescent lights, and it also plays a crucial role in technologies like plasma TVs and fusion reactors.

The similarity in names can be attributed to the ionized nature of plasma. In plasma, particles become charged, similar to the positive and negative ions found in the human body's blood plasma. Both terms derive from the Greek word "plasma," meaning "something molded or formed."

This connection may have influenced the choice of naming the ionized state of matter and the component of blood plasma using similar terminology.

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3. Fulcrum left

Explanation:

The resistance of the second wire is twice the resistance of the first wire R₂ = 2R₁

The resistance of a wire is directly proportional to its length and inversely proportional to the cross-sectional area.

Let:

R₁ = resistance of the first wire

R₂ = resistance of the second wire

L₁ = length of the first wire

L₂ = length of the second wire

r₁ = radius of the first wire

r₂ = radius of the second wire

Given:

L₂ = L₁/2

r₂ = r₁/2

A₂ = A₁/4

Since resistance is inversely proportional to the cross-sectional area, which is proportional to the square of the radius.

Now, we can use the formula for resistance:

R = (ρL) / A

where

ρ is the resistivity,

L is the length,  

A is the cross-sectional area.

For the first wire:

R₁ = (ρL₁) / A₁

For the second wire:

R₂ = (ρL₂) / A₂

Substituting the relationships we derived earlier:

R₂ = (ρ(L₁/2)) / (A₁/4)

R₂ = (ρL₁) / (A₁/2)

R₂ = 2(ρL₁) / A₁

Since ρL₁/A₁ is equal to R₁ (the resistance of the first wire), we can substitute:

R₂ = 2R₁

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Answer:

similar or identical traits.

The pressure of a tank of uniform cross-sectional area 4.0m2 when the tank is filled with water at a depth of 6m is 58800 Pa.

To find the pressure in the tank, we can use the formula for pressure:

Pressure = density x gravity x height

Density of water (ρ) = 1000 kg/m³

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) = 6 m

Thus:

Pressure = 1000 kg/m³ x 9.8 m/s² x 6 m

Pressure = 58800 kg/(m·s²)

Since the unit of pressure is Pascal (Pa), which is equivalent to kg/(m·s²), the pressure in the tank is:

Pressure = 58800 Pa

Therefore, the pressure in the tank when it is filled with water to a depth of 6 m is 58800 Pascal.

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