Answer:
For the given data, the mean is 50.8, the median is 51, and the mode is 52.
For the sample with this error, the mean is 48.7, the median is 51, and the mode is 52.
For the sample with this value removed, the mean is 43.2, the median is 50, and the mode is 52.
Step-by-step explanation:
We are given the following set of sample data below;
18, 26, 30, 42, 50, 52, 52, 76, 78, 84.
The formula for calculating mean is given by;
Mean = [tex]\frac{\text{Sum of all data values}}{\text{Total number of observations}}[/tex]
= [tex]\frac{18+ 26+ 30+ 42+ 50+ 52+ 52+ 76+ 78+ 84}{10}[/tex]
= [tex]\frac{508}{10}[/tex] = 50.8
For calculating median, we have to observe that the number of observations (n) in our data is even or odd, i.e;
If n is odd, then the formula for calculating median is given by;Median = [tex](\frac{n+1}{2})^{th} \text{ obs.}[/tex]
If n is even, then the formula for calculating median is given by;Median = [tex]\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}[/tex]
Now, here in our data the number of observations is even, i.e. n = 10.
So, Median = [tex]\frac{(\frac{n}{2})^{th}\text{ obs.} +(\frac{n}{2}+1)^{th}\text{ obs.} }{2}[/tex]
= [tex]\frac{(\frac{10}{2})^{th}\text{ obs.} +(\frac{10}{2}+1)^{th}\text{ obs.} }{2}[/tex]
= [tex]\frac{5^{th}\text{ obs.} +6^{th}\text{ obs.} }{2}[/tex]
= [tex]\frac{50+52 }{2}[/tex] = 51
A Mode is a value that appears the maximum number of times in our data.
In our data, the value 52 is appera]ing maximum number of times, i.e. 2 times which means that mode of our data is 52.
Now, suppose the value 76 in the data is mistakenly recorded as 55 instead of 76. For the sample with this error,
Mean will be changed as value has been changed.New Mean = [tex]\frac{18+ 26+ 30+ 42+ 50+ 52+ 52+ 55+ 78+ 84}{10}[/tex]
= [tex]\frac{487}{10}[/tex] = 48.7
There will be no change in median because there is no change in the 5th and 6th observation of the data.Also, there will be no change in mode as stiil 52 appears maximum number of times in our data.Now, suppose the value 76 in the original sample is inadvertently removed from the sample. For the sample with this value removed,
Mean will be changed as value has been removed from data.New Mean = [tex]\frac{18+ 26+ 30+ 42+ 50+ 52+ 52+ 78+ 84}{9}[/tex]
= [tex]\frac{432}{10}[/tex] = 43.2
Median will also get changed because the number of observation is now odd, i.e. n = 9So, Median = [tex](\frac{n+1}{2})^{th} \text{ obs.}[/tex]
= [tex](\frac{9+1}{2})^{th} \text{ obs.}[/tex]
= [tex]5^{th} \text{ obs.}[/tex] = 50
Also, there will be no change in mode as stiil 52 appears maximum number of times in our data.What is the approximate value for the modal daily sales?
Answer:
Step-by-step explanation:
Hello!
The table shows the daily sales (in $1000) of shopping mall for some randomly selected days
Sales 1.1-1.5 1.6-2.0 2.1-2.5 2.6-3.0 3.1-3.5 3.6-4.0 4.1-4.5
Days 18 27 31 40 56 55 23
Use it to answer questions 13 and 14.
13. What is the approximate value for the modal daily sales?
To determine the Mode of a data set arranged in a frequency table you have to identify the modal interval first, this is, the class interval in which the Mode is included. Remember, the Mode is the value with most observed frequency, so logically, the modal interval will be the one that has more absolute frequency. (in this example it will be the sales values that were observed for most days)
The modal interval is [3.1-3.5]
Now using the following formula you can calculate the Mode:
[tex]Md= Li + c[\frac{(f_{max}-f_{prev})}{(f_{max}-f_{prev})(f_{max}-f_{post})} ][/tex]
Li= Lower limit of the modal interval.
c= amplitude of modal interval.
fmax: absolute frequency of modal interval.
fprev: absolute frequency of the previous interval to the modal interval.
fpost: absolute frequency of the posterior interval to the modal interval.
[tex]Md= 3,100 + 400[\frac{(56-40)}{(56-40)+(56-55)} ]= 3,476.47[/tex]
A. $3,129.41 B. $2,629.41 C. $3,079.41 D. $3,123.53
Of all options the closest one to the estimated mode is A.
14. The approximate median daily sales is …
To calculate the median you have to identify its position first:
For even samples: PosMe= n/2= 250/2= 125
Now, by looking at the cumulative absolute frequencies of the intervals you identify which one contains the observation 125.
F(1)= 18
F(2)= 18+27= 45
F(3)= 45 + 31= 76
F(4)= 76 + 40= 116
F(5)= 116 + 56= 172 ⇒ The 125th observation is in the fifth interval [3.1-3.5]
[tex]Me= Li + c[\frac{PosMe-F_{i-1}}{f_i} ][/tex]
Li: Lower limit of the median interval.
c: Amplitude of the interval
PosMe: position of the median
F(i-1)= accumulated absolute frequency until the previous interval
fi= simple absolute frequency of the median interval.
[tex]Me= 3,100+400[\frac{125-116}{56} ]= 3164.29[/tex]
A. $3,130.36 B. $2,680.36 C. $3,180.36 D. $2,664
Of all options the closest one to the estimated mode is C.
The mean annual salary for intermediate level executives is about $74000 per year with a standard deviation of $2500. A random sample of 36 intermediate level executives is selected. What is the probability that the mean annual salary of the sample is between $71000 and $73500?
Answer:
11.51% probability that the mean annual salary of the sample is between $71000 and $73500
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal probability distribution
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question, we have that:
[tex]\mu = 74000, \sigma = 2500, n = 36, s = \frac{2500}{\sqrt{36}} = 416.67[/tex]
What is the probability that the mean annual salary of the sample is between $71000 and $73500?
This is the pvalue of Z when X = 73500 subtracted by the pvalue of Z when X = 71000. So
X = 73500
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{73500 - 74000}{416.67}[/tex]
[tex]Z = -1.2[/tex]
[tex]Z = -1.2[/tex] has a pvalue of 0.1151
X = 71000
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{71000 - 74000}{416.67}[/tex]
[tex]Z = -7.2[/tex]
[tex]Z = -7.2[/tex] has a pvalue of 0.
0.1151 - 0 = 0.1151
11.51% probability that the mean annual salary of the sample is between $71000 and $73500
If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and the sum of the ages of all 3 is 147 years, what is the age difference between oldest the youngest?
Answer:
48
Step-by-step explanation:
Esinam shere a common ratio hence,
the lcm of 3 and 5 is 15
Kissi:Esinam= 9:15 and Esinam:Lariba=15:25
Combining; 9:15:25
Let x be the ages such that,
Kissi=9x and Esinam=15x and Lariba=25x
9x+15x+25x=147
49x=147
x=3
Youngest; Kissi=9x=9(3)=27
Oldest; Lariba=25x=25(3)=75
Difference 75-27=48
Debby is working on her typing.
• At first, Debby typed at a rate of 80 words per minute
After she took a typing class, she could type 300 more words per hour than she could before the typing class.
How many words per minute could Debby type after taking the typing class?
85
130
220
e
300
Answer:
300/60=5 more words per minute
80+5 = 85 words per minute
or
80 x 60 = 4800 + 300 = 5100
5100 / 60 = 85 words per minute
Hope this helps
Step-by-step explanation:
What’s the correct answer for this question?
Answer:
C:
Step-by-step explanation:
In a circle, the measure of an inscribed angle is half the measure of the central angle with the same intercepted arc
So
AQD = ARC AD/2
<AQD = 78/2
<AQD = 39°
What’s the correct answer for this question ?
Answer:
C
Step-by-step explanation:
It closely resembles to a sphere.
whats the percentage of 56/100
Answer:
56%
Step-by-step explanation:
Percent means out of 100
56/100
56 out of 100
56%
Answer:
56%
Step-by-step explanation:
How much is 56 out of 100 written as a percentage? Convert fraction (ratio) 56 / 100 Answer: 56%
On average, a major earthquake (Richter scale 6.0 or above) occurs three times a decade in a certain California county. Find the probability that at least one major earthquake will occur within the next decade. A. .1992 B. .7408 C. .9502 D. .1494
A sports car manufacturer paints its cars silver, white, black, and red in the following proportions: ?
Color: Silver White Black Red
Proportion: .2 .3 .1 .4
We know that 40% of these cars are manufactured with tan leather upholstery while the remaining 60% are manufactured with gray leather.
A. Assuming that the choice of exterior color and leather color are independent, what is the probability that a randomly selected sports car from this manufacturer will be white with gray upholstery?
B. Assuming that we know the car has tan upholstery, what is the probability that the car is either silver or white?
Answer:
A. The probability that a randomly selected sports car from this manufacturer will be white with gray upholstery is P=0.12.
B. Assuming that we know the car has tan upholstery, the probability that the car is either silver or white is P=0.50.
Step-by-step explanation:
We first start by stating that the events "exterior color" and "leather color" are independent, so the probability of the outcomes of each event is not affected by the outcomes of the other event.
A. The probability of having a car that is white (W) with gray upholstery (G) is equal to the probability of having a car that is white multiplied by the probability of having a car with gray leather upholstery. Mathematically, this is:
[tex]P(\text{W\&G})=P(W)\cdot P(G)=0.3\cdot 0.4=0.12[/tex]
B. As the events are independent, the probability of having a silver or white car, given that the car has tan upholstery, is the same as the probabiltiy of having a silver or white car:
[tex]P(S\,or\,W | T)=P(S\,or\,W)=P(S)+P(W)=0.20+0.30=0.50[/tex]
the sum of the three numbers in 2003,two of the numbers are 814 and 519 what is the third number
Answer:
idk dont ask me
Step-byi-step explanation:
Answer:
a+b+c=2003
a+b=814
2003-819=189
Step-by-step explanation:
Please help! Correct answer only, please! The following information matrices shows how many of each vehicle type sold and the bonus amount each salesperson receives for selling that type of vehicle for the car dealership for the week. What does the element LaTeX: A_{2,3}A 2 , 3represent? A. Mark sold 2 vans B. Scott sold 1 Van C. Mark sold 4 trucks D. Kelly sold 2 trucks
Answer: B) Scott sold 1 van
Step-by-step explanation:
A₂,₃ represents: matrix A - 2nd row - 3rd column
The second row is Scott and and the 3rd row is Vans
If you look at Scott - Vans, you will see that Scott sold 1 van.
Consider the following geometric series.
[infinity]∑n=1 (−8)n−19n
a) Find the common ratio.
b) Determine whether the geometric series is convergent or divergent.
c) If it is convergent, find its sum. (If the quantity diverges, answer diverges.)
Answer:
a) -8/9
b) The series is a convergent series
c) 1/17
Step-by-step explanation:
The series a+ar+ar²+ar³⋯ =∑ar^(n−1) is called a geometric series, and r is called the common ratio.
If −1<r<1, the geometric series is convergent and its sum is expressed as ∑ar^(n−1) = a/1-r
a is the first tern of the series.
a) Rewriting the series ∑(-8)^(n−1)/9^n given in the form ∑ar^(n−1) we have;
∑(-8)^(n−1)/9^n
= ∑(-8)^(n−1)/9•(9)^n-1
= ∑1/9 • (-8/9)^(n−1)
From the series gotten, it can be seen in comparison that a = 1/9 and r = -8/9
The common ratio r = -8/9
b) Remember that for the series to be convergent, -1<r<1 i.e r must be less than 1 and since our common ratio which is -8/9 is less than 1, this implies that the series is convergent.
c) Since the sun of the series tends to infinity, we will use the formula for finding the sum to infinity of a geometric series.
S∞ = a/1-r
Given a = 1/9 and r = -8/9
S∞ = (1/9)/1-(-8/9)
S∞ = (1/9)/1+8/9
S∞ = (1/9)/17/9
S∞ = 1/9×9/17
S∞ = 1/17
The sum of the geometric series is 1/17
Charlotte is creating a triangular pennant with geometry software.
The base measure of the pennant on screen is 550 pixels. The height
is 275 pixels. Charlotte resizes the pennant, keeping the aspect ratio
constant, so the height is 165 pixels. What is the scale factor of the
dilation? What is the base of the pennant?
~~~~~~~~~~~~~~
pls help T-T
Answer:
Base of the Pennant = 330 pixels
Scale Factor =0.6
Step-by-step explanation:
The base measure of the pennant on screen is 550 pixels.
The height is 275 pixels.
[tex]A$spect Ratio=\dfrac{Base}{Height}=\dfrac{550}{275} =2:1[/tex]
If Charlotte resizes the pennant, keeping the aspect ratio constant.
Height = 165 pixels
Therefore:
[tex]\dfrac{Base}{165}=\dfrac{2}{1} \\\\$Base= 2 *165 =330[/tex]
Therefore, the scale factor of the dilation [tex]=\dfrac{330}{550}= \dfrac{165}{275}=0.6[/tex]
Base of the Pennant = 330 pixels
Scale Factor =0.6
Given ∠E≅∠P, K is the midpoint of EP Prove EG≅MP
Answer:
∠E≅∠P || Given
∠EKG≅∠PKM || Vertical angles
EK≅KP || Midpoint Theorem
EKG≅PKM || AAS(Angle Angle Side)
EG≅MP || CPCTC (Corresponding Parts of Congruent Triangles are Congruent)
Step-by-step explanation:
write eight hundred and seven thousand, two hundred and five in figures
Answer:
807,205
Step-by-step explanation:
Take the eight hundred and seven thousand and express that has 807,000. Then, add the two hundred and five at the end to get 807,205
The given statement is written in figures 807,205.
The given statement is eight hundred and seven thousand, two hundred and five in figures.
We need to write the given statement as the number.
What are numbers?A number is a mathematical object used to count, measure, and label. The original examples are the natural numbers 1, 2, 3, 4, and so forth. Numbers can be represented in language with number words.
Now, eight hundred and seven thousand, two hundred and five=807,205.
Therefore, the given statement is written in figures 807,205.
To learn more about the numbers visit:
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Find the area of the compound shape below..
Answer:
32 cm²
Step-by-step explanation:
6*4+ 1/2*4*4= 32 cm²
An OSU senior is studying for exams in psychology and economics. The student has time to read 50 pages of psychology and 10 pages of economics. Or, in the same amount of time the student could read 30 pages of psychology and 70 pages of economics. How many pages of economics can the student read instead of reading just 1 page of psychology
Answer:
3 Pages
Step-by-step explanation:
Let the pages of economics read = eLet the pages of psychology read = pLet the total time taken on each instance=tIn the first instance, the student has time to read 50 pages of psychology and 10 pages of economics.
t=50p+10eThe student could read 30 pages of psychology and 70 pages of economics.
t=30p+70eSince the two situations take the same amount of time, we have:
50p+10e=30p+70e
Collect like terms
50p-30p=70e-10e
20p=60e
Divide both sides by 20
p=3e
Therefore, in the time it will take the student to read 1 page of psychology, the student can read 3 pages of economics.
Simplify [tex]4(y+11)2-3y^2[/tex]
Answer:
[tex]y^2+88y+484[/tex]
Step-by-step explanation:
[tex]4(y+11)^2-3y^2= \\\\4(y^2+22y+121)-3y^2= \\\\4y^2-3y^2+88y+484= \\\\y^2+88y+484[/tex]
Hope this helps!
what is an example of a literal question
Answer:
an example of a literal question is "what size do you wear", "what time does the show start", "who was the protagonist in your story" etc
Step-by-step explanation:
Pedro owns a shrimp truck near the beach. He sells garlic shrimp for $8 a plate and spicy shrimp for $6 a plate. Each day Pedro stocks enough shrimp to sell at most 120 plates total, but he would like to earn at least $800. Which combination of garlic shrimp plates and spicy shrimp plates can Pedro sell to meet his goal? A. 15 garlic shrimp plates and 110 spicy shrimp plates B. 80 garlic shrimp plates and 20 spicy shrimp plates C. 90 garlic shrimp plates and 25 spicy shrimp plates D. 70 garlic shrimp plates and 55 spicy shrimp plates
Answer:
C
Step-by-step explanation:
You can plug in each combination to see what would work
C is the only combination that satisfies all the constraints: it earns him more than $800 and is less than 120 plates.
The combination of 40 plates of garlic shrimp was sold, and 80 plates of spicy shrimp were sold can Pedro sell to meet his goal.
Given that,
Pedro owns a shrimp truck near the beach.
He sells garlic shrimp for $8 a plate and spicy shrimp for $6 a plate.
Each day Pedro stocks enough shrimp to sell at most 120 plates total, but he would like to earn at least $800.
We have to determine,
Which combination of garlic shrimp plates and spicy shrimp plates can Pedro sell to meet his goal?
According to the question,
Let the x plates of garlic shrimp sold,
And y plates of spicy shrimp sold.
Each day Pedro stocks enough shrimp to sell at most 120 plates,
Then,
Plates of garlic shrimp + Plates of spicy shrimp = Total number of shrimp sell each day.
[tex]\rm x + y =120[/tex]
And He sells garlic shrimp for $8 a plate and spicy shrimp for $6 a plate.
He would like to earn at least $800.
Then,
Cost of garlic shrimp per plate + Cost of spicy shrimp per plate = Total earning,
[tex]\rm 8x + 6y = 800[/tex]
On solving both the equation,
[tex]\rm x+y = 120\\\\8x + 6y = 800[/tex]
From equation 1,
[tex]\rm y= 120-x[/tex]
Substitute the value of x in equation 2,
[tex]\rm 8x +6y = 800\\\\8(120-y) + 6y = 800\\\\960 - 8y + 6y = 800\\\\-2y = 800-960\\\\-2y = -160\\\\y = \dfrac{-160}{-2}\\\\y = 80[/tex]
Substitute the value of y in equation 1,
[tex]\rm x + y =120\\\\x +80=120\\\\x = 120-80\\\\x =40[/tex]
Hence, The combination of 40 plates of garlic shrimp was sold, and 80 plates of spicy shrimp were sold can Pedro sell to meet his goal.
For more details refer to the link given below.
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Express (In 35+ln(1/7))/ In 25 in terms of In 5 and In 7
Properties of the logarithm: for any base of logarithm,
log(a*b) = log(a) + log(b)
If we replace b with 1/b, or b^-1, we have
log(a/b) = log(a) + log(1/b) = log(a) - log(b)
since
log(1/b) = log(b^-1) = - log(b)
using the power property of logarithms,
log(b^n) = n log(b)
Now,
ln35 = ln(5*7) = ln5 + ln7
ln(1/7) = - ln7
ln25 = ln(5^2) = 2 ln5
Putting everything together, we have
(ln35 + ln(1/7))/ln25 = (ln5 + ln7 - ln7)/(2 ln5) = ln5/(2 ln5) = 1/2
What is 11/12 divided 1/3
Answer:
2.75 or 2 3/4
Step-by-step explanation:
so here you use the recipricle of 1/3. so you would do 11/12 X 3/1 =33/12= 2 3/4
Answer: 11/4
Step-by-step explanation:
to divide a fraction by another, you multiply by the reciprocal(the opposite of a certain fraction). the reciprocal of 1/3 is 3/1. so:
[tex]\frac{11}{12} / \frac{1}{3} = \frac{11}{12} * \frac{3}{1} = \frac{33}{12} = \frac{11}{4}[/tex] (divide both sides by 3 to simplify for the last one)
Two samples are randomly selected from each population. The sample statistics are given below.
n1 = 150 n2 = 275
x1 = 72.86 -x2 = 67.34
s1 = 15.98 s2 = 35.67
The value of the standardized test statistic to test the claim that μ1 > μ2 is _________.
-2.19
2.19
3.15
-3.15
Answer:
Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]
Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]
The statistic is given by:
[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]
And replacing we got:
[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]
And the best option would be:
2.19
Step-by-step explanation:
We have the following info given:
n1 = 150 n2 = 275
[tex]\bar x_1 = 72.86, \bar x_2 = 67.34[/tex]
s1 = 15.98 s2 = 35.67
We want to test the following hypothesis:
Null hypothesis: [tex]\mu_1 \leq \mu_2[/tex]
Alternative hypothesis: [tex]\mu_1 > \mu_2[/tex]
The statistic is given by:
[tex]t= \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}}[/tex]
And replacing we got:
[tex] t=\frac{72.86-67.34}{\sqrt{\frac{15.98^2}{150} +\frac{35.67^2}{275}}}=2.194[/tex]
And the best option would be:
2.19
Venera sent a chain letter to her friends, asking them to forward the letter to more friends.
The relationship between the elapsed time t, in months, since Venera sent the letter, and the number of
people, P(t), who receive the email is modeled by the following function:
3t+7
P(t) = 2
Complete the following sentence about the monthly rate of change in the number of people who receive
the email.
Round your answer to two decimal places.
Every month, the number of people who receive the email is multiplied by a factor of
Answer:
It is multiplied by a factor of 8
Step-by-step explanation:
Every month, the number of people who receive the email is multiplied by a factor of 8.
What is an exponent?Let b is the base and x is the power of the exponent function and a is the leading coefficient. The exponent is given as
y = a(b)ˣ
Venera sent a chain letter to her friends, asking them to forward the letter to more friends.
The relationship between the elapsed time t, in months, since Venera sent the letter, and the number of people, P(t), who receive the email is modeled by the following function:
[tex]\rm P(t) = 2^{3t+7}[/tex]
Every month, the number of people who receive the email is multiplied by a factor will be
For t = 2, we have
P(2) = 2³⁽²⁾⁺⁷
P(2) = 2¹³
For t = 3, we have
P(3) = 2³⁽³⁾⁺⁷
P(3) = 2¹⁶
Then the factor will be
⇒ P(3) / P(2)
⇒ 2¹⁶ / 2¹³
⇒ 2³
⇒ 8
More about the exponent link is given below.
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1. What is the approximate area of a circle with a diameter of 20 inches?
2. What is the volume of a cube with a side length of 3 cm?
3. What is the median of the data set { 35,20, 30,25,20 }?
Answer:
1. 100[tex]\pi[/tex]
2. 27 [tex]cm^{3}[/tex]
3. 30
Step-by-step explanation:
Area = [tex]\pi[/tex][tex]r^{2}[/tex]
= [tex]\pi[/tex] x [tex]10x^{2}[/tex]
= 100[tex]\pi[/tex]
Volume = l x w x h
= 3 x 3 x 3
= 27
Find the number of possible outcomes if the numbers 1 through 7 are written on different pieces of paper and placed in a hat. Two of these numbered pieces of paper are selected without replacement, and a 2-digit number is formed using the first number drawn in the tens place and the second number drawn used in the ones place.
Answer:
The number of the possible outcomes are:
12,13,14,15,16,17
21,23,24,25,26,27
31,32,34,35,36,37
41,42,43,45,46,47
51,52,53,54,56,57
61,62,63,64,65,67
71,72,73,74,75,76
The total number of possible outcomes = 42
Step-by-step explanation:
Given that :
the numbers 1 through 7 are written on different pieces of paper; &
Two of these numbered pieces of paper are selected without replacement;
Also,
a 2-digit number is formed using the first number drawn in the tens place and the second number drawn used in the ones place.
Then:
if the first number drawn is 1 , then the possible outcomes will be :
12,13,14,15,16,17
If the first number drawn is 2; then the possible outcomes will be:
21,23,24,25,26,27
If the first number drawn is 3; then the possible outcomes will be:
31,32,34,35,36,37
If the first number drawn is 4; then the possible outcomes will be:
41,42,43,45,46,47
If the first number drawn is 5; then the possible outcomes will be:
51,52,53,54,56,57
If the first number drawn is 6; then the possible outcomes will be:
61,62,63,64,65,67
If the first number drawn is 7; then the possible outcomes will be:
71,72,73,74,75,76
The number of the possible outcomes are:
12,13,14,15,16,17
21,23,24,25,26,27
31,32,34,35,36,37
41,42,43,45,46,47
51,52,53,54,56,57
61,62,63,64,65,67
71,72,73,74,75,76
The total number of possible outcomes = 7 × 6 = 42
f(x)=x^3+10x^2-25x-250
Answer:
-16x^5
Step-by-step explanation:
f(x)=x^3+10x^2-25x-250
f(x) = x^3-15x+x^2-250
f(x) = x^5-15x-250
f(x) = x^5 -x + 16
f(x) = -x^5+16
f(x) = -16x^5
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The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standard deviation 7.6 mm.(a)What is the probability that defect length is at most 20 mm
Answer:
14.69% probability that defect length is at most 20 mm
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 28, \sigma = 7.6[/tex]
What is the probability that defect length is at most 20 mm
This is the pvalue of Z when X = 20. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{20 - 28}{7.6}[/tex]
[tex]Z = -1.05[/tex]
[tex]Z = -1.05[/tex] has a pvalue of 0.1469
14.69% probability that defect length is at most 20 mm
Which system of linear inequalities is represented by the
graph?
O y2x - 2 and y = x + 1
O y< x-2 and y> x + 1
O y < x-2 and y? x + 1
O y> x-2 and y < x + 1
Answer:
answer c.
y <= x - 2 and y >= x + 1
Step-by-step explanation:
You wrote the given answers wrong. Here are the right choices that are given as possible solutions:
O y >= x - 2 and y <= x + 1
O y < x - 2 and y > x + 1
O y <= x - 2 and y >= x + 1
O y > x - 2 and y < x + 1
The graph clearly shows two lines and the intended area is shaded and it is clearly including the lines.
Because the lines are included in the solution, by that alone, you can exclude two answers b and d.
Now you still need to decide between the in equalities in answer a and c. Both lines have a gradient of 1, so that does not help to distinguish...
The y intercept of the top line is at y= +1 and the shaded area is bigger then that....
So y >= x + 1 is the right inequality.By now it is absolutely clear that answer c must be the right answer and you are done!
EXTRA
Although you have deduced beyond any doubt, that answer c must be the right answer, you still can check your findings 'to be sure' by looking and checking for the bottom line...
BE CAREFUL, ONLY DO THIS IF YOU HAVE ENOUGH TIME. Again, you already know the right answer, and this is "just to confirm", so what is the harm in that?
By double checking yourself, it will sort of "undermine" your appproach. Basically you are doing something which is strictly spoken not nessasary any more. So I urge you to basically step over the urge to check yourself, and stick to your answer.
However, if you can not resit the temptation of checking to see if you actually found the right answer, you could test the y intercept of the bottom line, which is at y= -2 and the shaded area is smalller then that....
So y <= x - 2 is the right inequality.So again, it is now confirmed that answer c is indeed the right answer.
The correct system of linear inequalities is represented by the graph are,
⇒ y > x - 2
⇒ y < x + 1
What is mean by Inequality?A relation by which we can compare two or more mathematical expression is called an inequality.
Given that;
The system of linear inequalities is shown in graph.
Hence, By graph;
The value of y - intercepts are,
⇒ - 2 and - 1
Hence, The correct system of linear inequalities is represented by the graph are,
⇒ y > x - 2
⇒ y < x + 1
Thus, The correct system of linear inequalities is represented by the graph are,
⇒ y > x - 2
⇒ y < x + 1
Learn more about the inequality visit:
https://brainly.com/question/25944814
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Please answer this correctly
Answer:
698 cm²
Step-by-step explanation:
The volume is given by ...
V = LWH
Filling in the given values, we have ...
1020 = (17)(5)y . . . . . . . using L=17, W=5, H=y
y = 1020/(17·5) = 12
The surface area is given by ...
A = 2(LW +H(L+W))
A = 2(17·5 +12(17+5)) = 2(85 +264) . . . . . . . using L=17, W=5, H=y=12
A = 698 . . . . square centimeters