Consider the relation S(x, y) : x is a brother or sister of y on the set, H, of living humans. (For the purposes of this problem, a sibling of a person means another person with the same two parents, so don’t consider half siblings.) Determine which of the three properties, reflexive, symmetric, transitive, hold for the relation S (explain your three answers). Is S an equivalence relation on H?

Answer: 0.66 ft

Step-by-step explanation:

Let assume that the initial position of the worker is x.

Given that the worker walks away with a constant speed of 2 ft/s. Therefore, dx/dt = 2

As the worker moves away, the rope makes a triangle, with width length x and the height length will be 30.

Using pythagorean theorem, the length of rope on this side of the pulley will be √(x² + 30²)

Also, the length of rope on the other side will be 60 - √(x² + 30²),

and the height h of the weight will be 30 - (60 - √(x² + 30²)) = √(x² + 30²) - 30

dh/dt = dx/dt × x/√(x² + 30²)

= 4x/√(x² + 30²)

dh/dt = 4x/√(x² + 30²)

If the worker moves 5ft away, then

dh/dt = (4×5)/√(5² + 30²)

dh/dt = 20/√(25 + 900)

dh/dt = 0.66 ft

Answer: 2ND ONE

Step-by-step explanation:

Answer:

-3

Step-by-step explanation:

5x+3=4x

5x-4x=-3

x=-3

Edit: Check by plugging in x = -3

5(-3)+3=4(-3)

-15+3=-12

-12=-12✅

Answer:

[tex]x^{6} y^{3}[/tex]

Step-by-step explanation:

[tex](x^2y)3[/tex]

[tex]x^{2 \times 3} \times y^3[/tex]

[tex]x^{6} \times y^3[/tex]

Answer:

Surface Area = 84.8 cm²

Step-by-step explanation:

This wedge is simply a triangular prism.

We are given;

Height of door wedge; H = 5 cm

Height of triangular base;h = 3.7 cm

Congruent sides; S2 = S3 = 5cm

base of triangular side;b = S1 = 4 cm

Now, formula for surface area of triangular prism is;

SA = bh + (s1 + s2 + s3)H

Thus, plugging in the relevant values, we have;

SA = (4 x 3.7) + (4 + 5 + 5)5

SA = 14.8 + 70

SA = 84.8 cm²

Answer:

there are none

Step-by-step explanation:

a triangle its is own shape and does not have any name for each side.

Answer:

k  ÷  5  <  25

Step-by-step explanation:

Edg.

Answer:

k ÷ 5 < 25

Step-by-step explanation:

Answer:

Ms. Barclay ordered 9 cupcakes.

Step-by-step explanation:

$1.25x9=11.25

11.25+3.25=$14.50

Answer: [tex]\frac{21}{4}[/tex]

Step-by-step explanation:

Multiply each side by 2 to get rid of the fraction on the right side. That basically gets rid of the 1/2 and the 2.

Youre now stuck with 2x + y = 21. They gave us y which is 2x. 2x + 2x = 4x

You now have 4x = 21

Divide each side by 4 to get x = 21/4

Answer:

the radius

Step-by-step explanation:

the correct answer is the radius

Answer:

x= -40

Step-by-step explanation:

Cost

C(x)=1,600+20x

P(x)=100-x

Revenue=x*p(x)

=x*(100-x)

=100x-x^2

Cost=Revenue

1600+20x=100x-x^2

1600+20x-100x+x^2=0

1600-80x+x^2=0

Solve using quadratic formula

Formula where

a = 1, b = 80, and c = 1600

x=−b±√b2−4ac/2a

x=−80±√80^2−4(1)(1600) / 2(1)

x=−80±√6400−6400 / 2

x=−80±√0 / 2

The discriminant b^2−4ac=0

so, there is one real root.

x= −80/2

x= -40

Answer:

Step-by-step explanation:

An option to buy a stock is priced at $150. If the stock closes above 30 next Thursday, the option will be worth $1000. If it closes below 20, the option will be worth nothing, and if it closes between 20 and 30, the option will be worth $200. A trader thinks there is a 50% chance that the stock will close in the 20-30 range, a 20% chance that it will close above 30, and a 30% chance that it will fall below 20.

a) Let X represent the price of the option

$1000         20/100 = 0.2

$200          50/100 = 0.5

$0              30/100 = 0.3

b) Expected option price

[tex]= \sum x.P(X=x)\\\\ = 1000 * 0.2 + 200 * 0.5 + 0 = \$ 300[/tex]

Therefore expected gain = $300 - $150 = $150

c) The trader should buy the stock. Since there is an positive expected gain($150) in trading that stock option.

Answer:

A. The causal connection is valid. Students who spend more time and effort studying will be able to memorize more​ information, so their test grades will be higher.

Step-by-step Explanation:

The causal connection between the test grades of students and the amount of time and effort spent the students spend in studying and preparing for the test appears to be valid. This is valid because students who spend more time and effort studying would most likely be able to memorize more information of which they are most likely to come by in the test they take. Invariably, they'd be able to easily recall what they've memorize and give the right answers to the questions they are asked in the test, and this definitely will earn them higher test grades.

Answer:

The average rate of change is 12x=12.0x.

Description:

Function: x= 1x = 3  convert to short form: x 1x 3

Interval:  x= 1  ,       x 3

Steps:

Input:  Find the average rate of change of f(x)=3x2 on the interval [x,3x].

We have that a=x, b=3x, f(x)=3x2

Thus, f(b)−f(a)b−a=3((3x))2−(3(x)2)3x−(x)=12x.

Answer: the average rate of change is 12x=12.0x.

Please mark brainliest

Hope this helps.

Answer:

3

Step-by-step explanation:

A P E X

Answer:

Thats not possible

Step-by-step explanation:

There is no:

Answer:

4 sqrt(6)

Step-by-step explanation:

sqrt(96)

We know sqrt(ab) =sqrt(a) sqrt(b)

sqrt(16*6)

sqrt(16) sqrt(6)

4 sqrt(6)

Answer:

A) 3, 9, 15, 21, 27, . . .

Step-by-step explanation:

EDGE 2020

Answer:

The second answer is 6.

Step-by-step explanation:

D=6

Answer:

The equation of the parallel  line to the given equation is

3 x-4 y = -4    and

The equation of the parallel  line to the given equation is

[tex]y = 1 + \frac{3 x}{4}[/tex]

Step-by-step explanation:

Explanation:-

Given equation of the line 3 x -4 y = 7 and given point ( -4 , -2 )

The equation of the parallel line to the given equation is

3 x - 4 y = k

it is passes through the point ( -4 , -2)

3 (-4) - 4 ( -2) = k

-12 +8 = k

k = -4

The equation of the parallel  line to the given equation is

3 x- 4 y = -4

Dividing '4' on both sides , we get

[tex]\frac{3 x-4 y}{-4} = 1[/tex]

[tex]\frac{-3 x}{4} +y =1[/tex]

[tex]y = 1 + \frac{3 x}{4}[/tex]

Conclusion:-

∴ The equation of the parallel  line to the given equation is

3 x- 4 y = -4

and

The equation of the parallel  line to the given equation is

[tex]y = 1 + \frac{3 x}{4}[/tex]

Answer:

the answer is b and d edge 2021

Step-by-step explanation:

I am finished taking the test got a 100%

If the length of OB was ³/₄, then the length of OB' after dilation is; Option B: 3 units.

What this means is that it was enlarged by a scale factor of 4 with point O as the center of dilation.

Scale factor = new dilated length OB'/(³/₄)

new dilated length OB' = ³/₄ × 4

new dilated length OB' = 3 units

Read more on dilation at; https://brainly.com/question/8532602

Answer:

its 4 units trust just answered it

Step-by-step explanation:

Answer:

x<12

Step-by-step explanation:

subtract both sides by -3 because you need to isolate x. then you have x/4<3. now you need to get rid of the 4. so you do the opposite of division and multiply 4 by both sides so you get x<12

Answer: recantagle

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given the rate at which an eucalyptus tree will grow modelled by the equation 0.5+6/(t+4)³ feet per year, where t is the time (in years).

The amount of growth can be gotten by integrating the given rate equation as shown;

[tex]\int\limits {0.5 + \frac{6}{(t+4)^{3} } } \, dt \\= \int\limits {0.5} \, dt + \int\limits\frac{6}{(t+4)^{3} } } \, dx } \, \\= 0.5t +\int\limits {6u^{-3} } \, du \ where \ u = t+4 \ and\ du = dt\\= 0.5t + 6*\frac{u^{-2} }{-2} + C\\= 0.5t-3u^{-2} +C\\= 0.5t-3(t+4)^{-2} + C[/tex]

a)  The number of feet that the tree will grow in the second year can be gotten by taking the limit of the integral from  t =1 to t = 2

[tex]\int\limits^2_1 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_1\\= [0.5(2)-3(2+4)^{-2}] - [0.5(1)-3(1+4)^{-2}]\\= [1-3(6)^{-2}] - [0.5-3(5)^{-2}]\\ = [1-\frac{1}{12}] - [0.5-\frac{3}{25} ]\\= \frac{11}{12}-\frac{1}{2}+\frac{3}{25}\\ = 0.9167 - 0.5 + 0.12\\= 0.5367feet[/tex]

b)  The number of feet that the tree will grow in the third year can be gotten by taking the limit of the integral from  t =2 to t = 3

[tex]\int\limits^3_2 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^3_2\\= [0.5(3)-3(3+4)^{-2}] - [0.5(2)-3(2+4)^{-2}]\\= [1.5-3(7)^{-2}] - [1-3(6)^{-2}]\\ = [1.5-\frac{3}{49}] - [1-\frac{1}{12} ]\\ = 1.439 - 0.9167\\= 0.5223feet[/tex]

c) The total number of feet grown during the second year can be gotten by substituting the value of limit from t = 0 to t = 2 into the equation as shown

[tex]\int\limits^2_0 {0.5 + \frac{6}{(t+4)^{3} } } \, dt = [0.5t-3(t+4)^{-2}]^2_0\\= [0.5(2)-3(2+4)^{-2}] - [0.5(0)-3(0+4)^{-2}]\\= [1-3(6)^{-2}] - [0-3(4)^{-2}]\\ = [1-\frac{1}{12}] - [-\frac{3}{16} ]\\= \frac{11}{12}+\frac{3}{16}\\ = 0.9167 - 0.1875\\= 0.7292feet[/tex]

Answer=6 . S/R . 4T

This is the answer because u have to simplify so to do this u have to divide all of this by R

Answer:

In fraction, Balu ate 1/2 of the whole cake

Step-by-step explanation:

Balu and Pumba shared 2/3 of a cake.

Balu eats three times as much cake as Pumba.

So let's take the 2/3 they shared as a whole.

Let's Balu share be x

And pumbs share be y

X = 3y

But x + 3y = 2/3

Since x = 3y

Y = x/3

x + x/3 = 2/3

4x/3 = 2/3

X = (2*3)/(4*3)

X = 2/4

X = 1/2

Balu ate half of the whole cake

In fraction, Balu ate 1/2 of the whole cake

Answer:

s = 4.43

Step-by-step explanation:

Using formula for bigger circle

s =r∅

Where s is the Arc length, r is rdius and ∅ is theta(angle)

8.84=5∅

∅= 8.84/5

Angle = 1.77 radians

So both angles equal to 1.77 radians

Now again

Using formula

s = r∅

Where s is the Arc length, r is rdius and ∅ is theta(angle)

s = (2.5)(1.77)

s ≈ 4.43

Answer: 5 (estimate)

Step-by-step explanation:

x - 17 4/5 = -13 1/5

Estimate:  x - 18 = -13

x - 18 + 18 = -13 + 18

x = 5

actual answer without estimating using exact numbers is 4 3/5 (so estimate is reasonable)

Answer:

a. P(X>695)=0.026

b. P(X<485)=0.44

Step-by-step explanation:

The question is incomplete:

a. higher than 695 on the test.

b. at most 485 on the test.

We have a normal distribution with mean 500 and standard deviation of 100 for the test scores. We will use the z-scores to calculate the probabilties with the standard normal distribution table.

a. We want to calculate the probability that a randomly selected student scores higher than 695.

We calculate the z-score and then we calculate the probability:

[tex]z=\dfrac{X-\mu}{\sigma}=\dfrac{695-500}{100}=\dfrac{195}{100}=1.95\\\\\\P(X>695)=P(z>1.95)=0.026[/tex]

a. We want to calculate the probability that a randomly selected student scores at most 485.

We calculate the z-score and then we calculate the probability:

[tex]z=\dfrac{X-\mu}{\sigma}=\dfrac{485-500}{100}=\dfrac{-15}{100}=-0.15\\\\\\P(X<485)=P(z<-0.15)=0.44[/tex]

Answer:

103

Step-by-step explanation:

A number to the power of a negative exponent, means 1 divided by that same number to the power of the positive exponent.

1/(216^(-2/3)) + 1/(256^(-3/4)) + 1/(243^(-1/5))

Break it apart into three pieces.

1/(216^(-2/3))

216^(2/3) = 36

1/(256^(-3/4))

256^(3/4) = 64

1/(243^(-1/5))

243^(1/5) = 3

So...

1/(216^(-2/3)) = 36

1/(256^(-3/4)) = 64

1/(243^(-1/5)) = 3

Add the numbers gives:

36 + 64 + 3 = 103