Answer:
2910 to binary = 101101011110
2910 to hexadecimal = B5E
2910 to octal = 5536
E316 to binary = 1110001100010110
E316 to octal = 161426
E316 to decimal = 58134
5916 to binary = 101100100010110
5916 to decimal = 22806
5916 to octal = 54426
010010102 to decimal = 149
010010102 to octal = 225
010010102 to hexadecimal = 95
FOR 438 and 618, 8 is not a valid digit for octal..
In addition to compiling the list of user access requirements, applications, and systems, the BIA also includes processes that are ____________. These processes safeguard against any risks that might occur due to key staff being unavailable or distracted.
Answer:
automated
Explanation:
Basically a Business Impact Analysis (BIA) estimates and determines the effects of a business activity and process disturbances. These disruptions can be natural or electronic disasters. It also collects information which is used to establish recovery plan. It identifies the business vulnerabilities and works on the strategies in order to reduce such potential hazards. The BIA involves both manual and automated processes. BIA involves automated processes which include the automated software tools that enables the protection of the confidential information of the users and also generates automated reports about the critical business processes.
Create a Python program that: Allows the user to enter a person's first name and last name. The user should be able to enter as many names as they desire. Create a function that takes the first name and last name, puts them together with the last name first, followed by the first name; with the names separated by commas. Take the result from the function, and place the resulting name in a list. Once the user finishes entering names, sort the contents of the list. Write the sorted names from a list into a text file. When you create the text file, allow the user to enter a name for the file to be created. After you finish writing names to the file, close the file and end the program.
Answer:
#main function start
def main():
#list to store names entered by user
name_list=[]
#variable to take input from user to keep rotating the loop and take input from user again and again
ch='y'
fname=""
lname=""
while ch=='y' or ch=='Y':#keep the loop taking input from user till user do not want to enter more
#take input from user
name=[]
fname=input("Enter first name: ")
lname=input("Enter last name: ")
name.append(fname)
name.append(lname)
#append the previously input first and last name in main list
name_list.append(name)
ch=input("Do you want to continue: (y/Y for yes)")
#main function end
#get file name from user
filename=input("Enter output file name")
#open file in write mode
file=open(filename,"w")
#keep loop add data in file till main list 'name_list' have
for i in name_list:
#Write data in file
file.write("%s, %s\r\n" % (i[0],i[1]))
#close the file
file.close()
#call main function
main()
Explanation:
input the above code and see output
A number of LC-3 instructions have an "evaluate address" step in the instruction cycle, in which a 16-bit address is constructed and written to the Memory Address Register via the MARMUX. List all LC-3 instructions that write to the MAR during the evaluate address phase of the instruction cycle, with the Register Transfer description of each.
Answer: you want to list all LC structers
Explanation:
In 1987, Congress passed the Computer Security Act (CSA). This was the first law to address federal computer security. Under the CSA, every federal agency had to inventory its IT systems. Agencies also had to create security plans for those systems and review their plans every year.
A. True
B. False
Answer:
A.) True is the answer hope it helps
An introduction to object-oriented programming.
Write a GUI program named EggsInteractiveGUI that allows a user to input the number of eggs produced in a month by each of five chickens. Sum the eggs, then display the total in dozens and eggs. For example, a total of 127 eggs is 10 dozen and 7 eggs.
Answer:
The csharp program is given below.
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button6_Click(object sender, EventArgs e)
{
int total = (Convert.ToInt32(textBox1.Text) + Convert.ToInt32(textBox2.Text) + Convert.ToInt32(textBox3.Text) + Convert.ToInt32(textBox4.Text) + Convert.ToInt32(textBox5.Text));
int dozen = total / 12;
int eggs = total % 12;
textBox6.Text = dozen.ToString();
textBox7.Text = eggs.ToString();
}
private void button7_Click(object sender, EventArgs e)
{
textBox1.Text = "";
textBox2.Text = "";
textBox3.Text = "";
textBox4.Text = "";
textBox5.Text = "";
textBox6.Text = "";
textBox7.Text = "";
}
private void button8_Click(object sender, EventArgs e)
{
Close();
}
}
}
Explanation:
1. The integer variables are declared for total eggs, number of dozens and number of eggs.
2. The input of each text box is converted into integer by using the Convert.ToInt32() method on the value of that particular text box.
3. All the inputs are added and the sum is assigned to variable, total.
4. The number of dozens are obtained by dividing total by 12 and assigning the value to the variable, dozen.
5. The number of extra eggs are obtained by taking the modulus of total and 12 and the value is assigned to the variable, eggs.
6. The integer values in the variables, dozen and eggs, are converted into string using the ToString() function with that particular value.
dozen.ToString();
eggs.ToString();
7. The text boxes are assigned the respective values of dozens and number of eggs.
textBox6.Text = dozen.ToString();
textBox7.Text = eggs.ToString();
8. Two additional buttons, clear and exit, are also added.
9. The clear button erases the contents of all the text boxes. The Text property of each textbox is set to “” thereby clearing all the text fields.
10. The exit button closes the application using Close() function.
11. The program is made in visual studio and the output is attached.
When implementing a physical database from a logical data model, you must consider database performance by allowing data in the database to be accessed more rapidly. In order to increase data availability, the DBA may break up data that are accessed together to be stored together. Which method will improve the performance of this structure when running queries? What are advantages and disadvantages of this method?
Answer:
A method used to improve the performance of structure when running queries is known as Partitioning indexes.
The advantages of partitioning indexes are, It enables data management operations for example, index creation and rebuilding, It increases query performance.
The disadvantages are, one cannot define the primary index of partitioned table to be unique unless the whole partitioning column set is part of the primary index definition.
Explanation:
Solution
Partitioning indexes are known as b -tress indexes that shows hon how to break up the index into separate or different partitions.
Partitioning is usually done to enhance the performance and increased availability. when data are spread over multiple partitions, one can be able to operate on one partition without affecting others. i.e to run utilities, or to take data offline.
Almost all DBMS products support partitioning, but in various ways. we must be sure to know the nuances of an individual a particular DBMS execution before partitioning.
The advantages of Partitioned indexes are as follows:
It enables data management operations for example, index creation and rebuilding
It increases performance of query
It can significantly the impact of schedule downtime for maintenance operations
Disadvantages:
The primary index of partitioned table cannot be described to be unique except if the whole partitioning column set is part of the primary index definition.
Write a program that lets the Michigan Popcorn Company keep track of their sales for seven different types of popcorn they produce: plain, butter, caramel, cheese, chocolate, turtle and zebra. It should use two parallel seven-element arrays: an array of strings that holds the seven popcorn names and an array of integers that holds the number of bags of popcorn sold during the past month for each popcorn flavor. The names should be stored using an initialization list at the time the flavors array is created. The program should prompt the user to enter the number of bags sold for each flavor. Once the popcorn data has been entered, the program should produce a report for each popcorn type, total sales, and the names of the highest selling and lowest selling products. Be sure to include comments throughout your code where appropriate. Complete the C++ code using Visual Studio or Xcode, compress (zip) and upload the entire project folder to the Blackboard assignment area by clicking on the Browse My Computer button or by dragging the file inside the Attach Files box g
Answer:
#include <iostream>using namespace std;int main(){ // declare and initialize popcorn name array string popcorn_name[7] = {"plain", "butter", "caramel", "cheese", "chocolate", "turtle", "zebra"}; // declare and initialize sales array with 7 elements int sales[7]; // A loop to prompt user to enter sales for each popcorn for(int i=0; i < 7; i++){ cout<<"Enter number of sales for " + popcorn_name[i] + " :"; cin>>sales[i]; } // Find maximum sales int max = sales[0]; int maxIndex = 0; for(int j=1; j < 7; j++){ if(max < sales[j]){ max = sales[j]; maxIndex = j; } } // Find minimum sales int min = sales[0]; int minIndex = 0; for(int k=1; k < 7; k++){ if(min > sales[k]){ min = sales[k]; minIndex = k; } } // Print popcorn name and sales for(int l=0; l < 7 ; l++){ cout<<popcorn_name[l]<<"\n"; cout<<"Sales: "<< sales[l]<<"\n\n"; } // Print popcorn name with maximum and minimum sales cout<<"Highest selling: "<< popcorn_name[maxIndex]<<"\n"; cout<<"Lowest selling: "<<popcorn_name[minIndex]<<"\n"; return 0;}Explanation:
Create two arrays to hold the list of popcorn name and their sales (Line 5-8). Next prompt user to input the sales for each popcorn (Line 10-14). Get the maximum sales of the popcorn (Line 17-24) and minimum sales (Line 27-34). Print the popcorn name and sales (Line 37-40) and the popcorn name with highest and lowest selling (Line 43-44).
In which situations would it be most helpful to filter a form? Check all that apply.
Filtering is a useful way to see only the data that you want displayed in Access databases.
You acquire a network vulnerability-scanning tool and try it out on a network address segment belonging to people at your university of business. The scanner identifies one computer named Prince Hal that has many serious vulnerabilities. You deduce to whom the machine belongs. Explain the ethical implication of:________.
a. telling the owner what you have found,
b. telling you local administrator or security officer what you have found
c. exploiting one of the relatively minor vulnerabilities to show the owner how serious the exposure is
d. exploiting a relatively minor vulnerability as a prank without telling the owner,
e. telling the owner what you have found and the demanding money for details on the vulnerabilities
f. using one of the vulnerabilities to acquire control of the machine, downloading and installing patches and changing settings to address all the vulnerabilities, and never telling anyone what you have done.
Answer and Explanation:
The speculates on either the morality of transmitting vulnerabilities to an individual over all the internet. The node is a very possible target of a criminal charge, these are highly recommended in terms of the problem not just ethical.The question argues the etiquette of telling a compromised network infrastructure to something like a domain admins or security guard. Throughout this case the primary admin issue is power. Informing individuals about both the potential problem is prudent or legal, which is also preferable to recommend the future course of action.The speculates on either the moral values of leveraging the infrastructure for a mild vulnerability. This same proprietor including its node is truly likely to be victims of a prospective infringement, and therefore it is advantageous to notify him including its problem that the equitable access is considered to become an ethical manipulate susceptibility for possessor data as well as potential threats to understanding.The theories a small flaw throughout the channel's ethics. The device's leader is the likely guilty party of even a future offense to notify him of both the actual problem. The law is ridiculous as well as comparable to trying to hack without permission vulnerability it's immoral vulnerability.The content upon the ethical principles of manipulating the channel's small susceptibility. The device's owner seems to be the likely casualty of such a future offense to instruct him including its subject. As well as trying to sell him much farther documents socially responsible borders. It's the holder who has so far notified the weakness she perhaps she has just one option to obtain products and services. Having clear data on the sale still seems to be ethical.The issue argues mostly on ethics with repairing security flaws without channel assent. Although the controlled variable of the modules has been the true likely target of such a future infringement, exploiting susceptibility without permission is appropriate as well as unethical, this same objective being honorable as well as noble.Create a program that asks the user to enter grade scores. Use a loop to request each score and add it to a total. Continue accepting scores until the user enters a negative value. Finally, calculate and display the average for the entered scores.
Answer:
total = 0
count = 0
while(True):
grade = float(input("Enter a grade: "))
if grade < 0:
break
else:
total += grade
count += 1
average = total/count
print("The average is: " + str(average))
Explanation:
*The code is in Python.
Initialize the total and count as 0
Create a while loop that iterates until a specific condition is met inside the loop
Inside the loop, ask the user to enter a grade. If the grade is smaller than 0, stop the loop. Otherwise, add the grade to the total and increment the count by 1.
When the loop is done, calculate the average, divide the total by count, and print it
What is an accessory?
A.a security setting that controls the programs children can use
B.a tool that provides proof of identity in a computing environment
C.a set of programs and applications that help users with basic tasks
D.a set of gadgets and widgets that makes it easier to create shortcuts
Answer:
C
Explanation:
Accessories are in Microsoft windows, a set of programs and applications that help users with some basic tasks
Write a program that reads a list of words. Then, the program outputs those words and their frequencies. Ex: If the input is: hey hi Mark hi mark the output is: hey 1 hi 2 Mark 1 hi 2 mark 1
Answer:
#Declare variable to get the input
#list from the user
input_list = input()
#split the list into words by space
list = input_list.split()
#Begin for-loop to iterate each word
#to get the word frequency
for word in list:
#get the frequency for each word
frequency=list.count(word)
#print word and frequency
print(word,frequency)
Explanation:
This program that we are told to write will be done by using python programming language/ High-level programming language.
The question wants us to write a program in which the output will be as below;
hey 1
hi 2
Mark 1
hi 2
mark 1
Just by imputing hey hi mark hi mark.
Just copy and run the code below.
#Declare variable to get the input
#list from the user
input_list = input()
#split the list into words by space
list = input_list.split()
#Begin for-loop to iterate each word
#to get the word frequency
for word in list:
#get the frequency for each word
frequency=list.count(word)
#print word and frequency
print(word,frequency)
In this exercise we have to use the knowledge in computational language in python to write the following code:
We have the code can be found in the attached image.
So in an easier way we have that the code is
input_list = input()
list = input_list.split()
for word in list:
frequency=list.count(word)
print(word,frequency)
See more about python at brainly.com/question/18502436
A/an ____ file saves a workbook as a comma-delimited text file for use on another windows operating system??
A. XPS
B. TXT
C. ODS
D. CVS
Answer:
The correct option is D
D) CVS
Explanation:
A CVS file saves a workbook as a comma-delimited text file for use on another windows operating system. It ensures that line breaks, tab characters and other characteristics are interpreted correctly.
A CVS file stands for Comma Separated Value file, which basically allows the data to be saved in tabular format. However they differ from other spreadsheet file types because you can only have a single sheet in a file. Moreover, you cannot save cell, column or row in it.
What is a digital security risks?
Answer:
A digital security risk is an action that could result in damage to a computer or similar device's hardware, software, data etc.
what is computer aided design
What program is best for teaching young people code?
Python high school assignment: please keep simpleIn pythonInstructionsUse the following initializer list:w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]Write a loop that prints the words in uppercase letters.Sample RunALGORITHMLOGICFILTERSOFTWARENETWORKPARAMETERSANALYZEALGORITHMFUNCTIONALITYVIRUSES
Answer:
w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]
for i in range (len(w)):
print(w[i].upper())
Explanation:
every element needs to be upper cased
A loop that prints the words in uppercase letters is written below with the help of Python.
What is a function?Simply said, a function is a "chunk" of code that you may reuse repeatedly so instead of having to write it out several times. Software developers can divide an issue into smaller, more manageable parts, which can each carry out a specific task, using functions.
A function, according to a technical definition, is a relationship between an amount of parameters and a set of potential outputs, where every other input is connected to precisely one output.
All the functions are to be written in uppercase:
w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]
for i in range (len(w)):
print(w[i].upper())
Learn more about function, Here:
https://brainly.com/question/29050409
#SPJ5
Part 1: For this assignment, call it assign0 Implement the following library and driver program under assign0: Your library will be consisting of myio.h and myio.c. The function prototypes as well as more explanations are listed in myio.h. Please download it and accordingly implement the exported functions in myio.c. Basically, you are asked to develop a simple I/O library which exports a few functions to simplify the reading of an integer, a double, and more importantly a string (whole line). In contrast to standard I/O functions that can read strings (e.g., scanf with "%s", fgets) into a given static size buffer, your function should read the given input line of characters terminated by a newline character into a dynamically allocated and resized buffer based on the length of the given input line. Also your functions should check for possible errors (e.g., not an integer, not a double, illigal input, no memory etc.) and appropriately handle them. Then write a driver program driver.c that can simply use the functions from myio library. Specifically, your driver program should get four command-line arguments: x y z output_filename. It then prompts/reads x many integers, y many doubles, and z many lines, and prints them into a file called output_filename.txt. Possible errors should be printed on stderr.
myio.h file
/*
* File: myio.h
* Version: 1.0
* -----------------------------------------------------
* This interface provides access to a basic library of
* functions that simplify the reading of input data.
*/
#ifndef _myio_h
#define _myio_h
/*
* Function: ReadInteger
* Usage: i = ReadInteger();
* ------------------------
* ReadInteger reads a line of text from standard input and scans
* it as an integer. The integer value is returned. If an
* integer cannot be scanned or if more characters follow the
* number, the user is given a chance to retry.
*/
int ReadInteger(void);
/*
* Function: ReadDouble
* Usage: x = ReadDouble();
* ---------------------
* ReadDouble reads a line of text from standard input and scans
* it as a double. If the number cannot be scanned or if extra
* characters follow after the number ends, the user is given
* a chance to reenter the value.
*/
double ReadDouble(void);
/*
* Function: ReadLine
* Usage: s = ReadLine();
* ---------------------
* ReadLine reads a line of text from standard input and returns
* the line as a string. The newline character that terminates
* the input is not stored as part of the string.
*/
char *ReadLine(void);
/*
* Function: ReadLine
* Usage: s = ReadLine(infile);
* ----------------------------
* ReadLineFile reads a line of text from the input file and
* returns the line as a string. The newline character
* that terminates the input is not stored as part of the
* string. The ReadLine function returns NULL if infile
* is at the end-of-file position. Actually, above ReadLine();
* can simply be implemented as return(ReadLineFile(stdin)); */
char *ReadLineFile(FILE *infile);
#endif
Answer:
Explanation:
PROGRAM
main.c
#include <fcntl.h>
#include <stdio.h>
#include <stdlib.h>
#include <sys/stat.h>
#include <sys/types.h>
#include <unistd.h>
#include "myio.h"
int checkInt(char *arg);
int main(int argc, char *argv[]) {
int doubles, i, ints, lines;
char newline;
FILE *out;
int x, y, z;
newline = '\n';
if (argc != 5) {
printf("Usage is x y z output_filename\n");
return 0;
}
if (checkInt(argv[1]) != 0)
return 0;
ints = atoi(argv[1]);
if (checkInt(argv[2]) != 0)
return 0;
doubles = atoi(argv[2]);
if (checkInt(argv[3]) != 0)
return 0;
lines = atoi(argv[3]);
out = fopen(argv[4], "a");
if (out == NULL) {
perror("File could not be opened");
return 0;
}
for (x = 0; x < ints; x++) {
int n = ReadInteger();
printf("%d\n", n);
fprintf(out, "%d\n", n);
}
for (y = 0; y < doubles; y++) {
double d = ReadDouble();
printf("%lf\n", d);
fprintf(out, "%lf\n", d);
}
for (z = 0; z < lines; z++) {
char *l = ReadLine();
printf("%s\n", l);
fprintf(out, "%s\n", l);
free(l);
}
fclose(out);
return 0;
}
int checkInt(char *arg) {
int x;
x = 0;
while (arg[x] != '\0') {
if (arg[x] > '9' || arg[x] < '0') {
printf("Improper input. x, y, and z must be ints.\n");
return -1;
}
x++;
}
return 0;
}
myio.c
#include <limits.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
char *ReadInput(int fd) {
char buf[BUFSIZ];
int i;
char *input;
int r, ret, x;
i = 1;
r = 0;
ret = 1;
input = calloc(BUFSIZ, sizeof(char));
while (ret > 0) {
ret = read(fd, &buf, BUFSIZ);
for (x = 0; x < BUFSIZ; x++) {
if (buf[x] == '\n' || buf[x] == EOF) {
ret = -1;
break;
}
input[x*i] = buf[x];
r++;
}
i++;
if (ret != -1)
input = realloc(input, BUFSIZ*i);
}
if (r == 0)
return NULL;
input[r] = '\0';
input = realloc(input, r+1);
return(input);
}
int ReadInteger() {
char *input;
int go, num, x;
go = 0;
do {
go = 0;
printf("Input an integer\n");
input = ReadInput(STDIN_FILENO);
for (x = 0; x < INT_MAX; x++) {
if (x == 0&& input[x] == '-')
continue;
if (input[x] == 0)
break;
else if (input[x]> '9' || input[x] < '0') {
go = 1;
printf("Improper input\n");
break;
}
}
} while (go == 1);
num = atoi(input);
free(input);
return num;
}
double ReadDouble(void) {
int dec, exp;
char *input;
int go;
double num;
int x;
do {
go = 0;
dec = 0;
exp = 0;
printf("Input a double\n");
input = ReadInput(STDIN_FILENO);
for (x = 0; x < INT_MAX; x++) {
if (x == 0&& input[x] == '-')
continue;
if (input[x] == 0)
break;
else if (input[x] == '.' && dec == 0)
dec = 1;
else if (x != 0&& (input[x] == 'e' || input[x] == 'E') && exp == 0) {
dec = 1;
exp = 1;
}
else if (input[x]> '9' || input[x] < '0') {
go = 1;
printf("Improper input\n");
break;
}
}
} while (go == 1);
num = strtod(input, NULL);
free(input);
return num;
}
char *ReadLine(void) {
printf("Input a line\n");
return(ReadInput(STDIN_FILENO));
}
char *ReadLineFile(FILE *infile) {
int fd;
fd = fileno(infile);
return(ReadInput(fd));
}
myio.h
#ifndef _myio_h
#define _myio_h
/*
* Function: ReadInteger
* Usage: i = ReadInteger();
* ------------------------
* ReadInteger reads a line of text from standard input and scans
* it as an integer. The integer value is returned. If an
* integer cannot be scanned or if more characters follow the
* number, the user is given a chance to retry.
*/
int ReadInteger(void);
/*
* Function: ReadDouble
* Usage: x = ReadDouble();
* ---------------------
* ReadDouble reads a line of text from standard input and scans
* it as a double. If the number cannot be scanned or if extra
* characters follow after the number ends, the user is given
* a chance to reenter the value.
*/
double ReadDouble(void);
/*
* Function: ReadLine
* Usage: s = ReadLine();
* ---------------------
* ReadLine reads a line of text from standard input and returns
* the line as a string. The newline character that terminates
* the input is not stored as part of the string.
*/
char *ReadLine(void);
/*
* Function: ReadLine
* Usage: s = ReadLine(infile);
* ----------------------------
* ReadLineFile reads a line of text from the input file and
* returns the line as a string. The newline character
* that terminates the input is not stored as part of the
* string. The ReadLine function returns NULL if infile
* is at the end-of-file position. Actually, above ReadLine();
* can simply be implemented as return(ReadLineFile(stdin)); */
char *ReadLineFile(FILE *infile);
A vSphere Administrator is receiving complaints a database VM is experiencing performance issues. The VM is a member of the high priority resource pool and the cluster has not experienced contention.
Which condition should be checked to address immediate performance concerns?
A. VM snapshots
B. VMFS version
C. Resource Pool share value
D. Configured CPU shares
Answer:
C. Resource Pool share value.
Explanation:
The vSphere is a term used to describe the VMware’s virtualization cloud platform. The vSphere comprises of the following, vCenter Server, ESXi, Virtual Machine File System (VMFS) and vCenter Client.
If a vSphere Administrator receive complaints that a database Virtual Machine (VM) is experiencing performance issues and the Virtual Machine (VM) is a member of the high priority resource pool and the cluster has not experienced contention.
In order to address immediate performance concerns, the vSphere Administrator should check the Resource Pool share value.
VMware resource pool refers to the aggregated central processing unit and memory allocated to a Virtual Machine (VM) for flexible management of the resources.
Also, the vSphere Administrator should install VMware tools to check which processes are having high CPU usage by using vimtop, as well as checking if vCenter Server is swapping.
For this assignment, you will create flowchart using Flow gorithm and Pseudocode for the following program example: Hunter Cell Phone Company charges customer's a basic rate of $5 per month to send text messages. Additional rates apply as such:The first 60 messages per month are included in the basic billAn additional 10 cents is charged for each text message after the 60th message and up to 200 messages.An additional 25 cents is charged for each text after the 200th messageFederal, state, and local taxes add a total of 12% to each billThe company wants a program that will accept customer's name and the number of text messages sent. The program should display the customer's name and the total end of the month bill before and after taxes are added.
Answer:
The pseudocode is as given below while the flowchart is attached.
Explanation:
The pseudocode is as follows
input customer name, number of texts
Set Basic bill=5 $;
if the number of texts is less than or equal to 60
Extra Charge=0;
If the number of texts is greater than 60 and less than 200
number of texts b/w 60 and 200 =number of texts-60;
Extra Charge=0.1*(number of texts b/w 60 and 200);
else If the number of texts is greater than 200
number of texts beyond 200 =number of texts-200;
Extra Charge=0.25*(number of texts beyond 200)+0.1*(200-60);
Display Customer Name
Total Bill=Basic bill+Extra Charge;
Total Bill after Tax=Total Bill*1.12;
In which contingency plan testing strategy do individuals follow each and every IR/DR/BC procedure, including the interruption of service, restoration of data from backups, and notification of appropriate individuals?
a. Full-interruption
b. Desk check
c. Simulation
d. Structured walk-through
Answer:Full-interruption--A
Explanation: The Full-interruption is one of the major steps for a Disaster Recovery Plan, DRP which ensures businesses are not disrupted by saving valuable resources during a disaster like a data breach from fire or flood.
Although expensive and very risky especially in its simulation of a disruption, this thorough plan ensures that when a disaster occurs, the operations are shut down at the primary site and are transferred to the recovery site allowing Individuals follow every procedure, ranging from the interruption of service to the restoration of data from backups, also with the notification of appropriate individuals.
Write a program that keeps track of where cars are located in a parking garage to estimate the time to retrieve a car when the garage is full. This program will demonstrate the following:_________.
How to create a list for use as a stack,
How to enter and change data in a stack.
Answer: Provided in the explanation section
Explanation:
Code to use;
# Define the main() function.
def main():
# Declare the required variables.
stack_cars = []
move_time = 1
retrieve_time = 2
# Start the loop to display the menu.
while True:
# Display the choices to the user.
print("\n\t\t\t Car Stack Menu")
print("\n1. Add a car")
print("2. Retrieve a car")
print("3. Show the car stack")
print("4. Exit")
# Prompt the user to enter the input.
choice = input("\nEnter your choice: ")
# Append the car in the stack if the choice is 1.
if choice == '1':
car = input("Enter the car name to add: ")
stack_cars.append(car)
# Remove the car from the stack if the choice is 2.
elif choice == '2':
car = input("Enter the car name to retrieve: ")
# Display the error message if the car is not present.
if car not in stack_cars:
print(car + " is not present in the stack.")
# Otherwise, compute the time to retrieve a car.
else:
# Declare a temp stack to move the cars.
temp = []
x = stack_cars.pop()
count = 0
# Start the loop to pop the cars from the stack
# until the car to be retrieved is found.
while x != car:
count += 1
# Store the car in the temp stack.
temp.append(x)
x = stack_cars.pop()
# Start the loop to move the cars back in the
# original stack.
while len(temp) != 0:
stack_cars.append(temp.pop())
# Compute and display the total time.
total_time = move_time * count + retrieve_time
print("Total time to retrieve", car, "=", total_time)
# Display the stack if the choice is 3.
elif choice == '3':
print("Car stack =", stack_cars)
# Return from the funtion if the choice is 4.
elif choice == '4':
print("Exiting from the program...")
return
# Display the message for invalid input.
else:
print("Error: Invalid choice!")
# Call the main() function.
if __name__ == "__main__":
main()
Compute -ABE16-DF416 using 15’s complement
Answer:
33600
Explanation:
Let M = ABE16
and N = DF416
In hexadecimal representation: 10 = A, 11 = B, 12 = C, 13 = D, 14 = E, 15 = F
Step 1: Find the 15's complement of N
F F F F F
- D F 4 1 6
2 0 B E 9
Step 2: Add 15's complement of N to M
A B E 1 6
+ 2 0 B E 9
C C 9 F F
Step 3: Find the 15's complement of CC9FF
F F F F F
- C C 9 F F
3 3 6 0 0
Therefore, ABE16 - DF416 using 15's complement is 33600
Consider a recurrent neural network that listens to a audio speech sample, and classifies it according to whose voice it is. What network architecture is the best fit for this problem
Answer:
Many-to-one (multiple inputs, single output)
Explanation:
Solution
In the case of a recurrent neural network that listens to a audio speech sample, and classifies it according to whose voice it is, the RNN will listen to the audio and will give result by doing classification.
There will be a single output, for the classified or say identified person.
The RNN will take a stream of input as the input is a audio speech sample.
Therefore, there will be multiple inputs to the RNN and a single output, making the best fit Architecture to be of type Many-to-one(multiple inputs, single output).
public class Student {
private String getFood() {
return "Pizza";
}
public String getInfo() {
return this.getFood();
}
}
public class GradStudent extends Student {
private String getFood() {
return "Taco";
}
public void teach(){
System.out.println("Education!");
getInfo();
}
}
What is the output from this:
Student s1 = new GradStudent();
s1.teach();
Education! would be printed, followed by a run-time error when getInfo is called.
Education! Pizza
This code won't run because it won't compile.
Education! Taco
This code causes a run-time error because getInfo is not declared in the GradStudent class.
Answer:
getInfo(); ==
getSy.Info()
Explanation:
Get System Info
The new Director of Information Technology has asked you to recommend a strategy to upgrade the servers on their network. Recommendations on server hardware, CPU chip set, speed, and caching are needed. You should also recommend which servers to upgrade first and determine whether any servers are still appropriate to keep.
Answer:
servers to be upgraded are : APPLICATION AND LOAD BALANCING SERVERS
servers still appropriate to use : DNS AND DHCP SERVERS
Explanation:
The recommendations to be made in line with what the new director of information is asking for includes :
1 ) For the servers to be upgraded : The servers that requires upgrades includes the APPLICATION SERVER and LOAD BALANCING SERVER. this is because these two servers are critical to the growth/expansion of any business, and they handle large volume of data
Recommendations on the servers upgrade includes:
Hardware : 2.3 GHz Intel Xeon Gold 5118 12-Core
CPU chip set : Socket: FCLGA3647, Type: NSBM
Speed : processor 3.2 GHz
caching: > 100 Gb
2) For servers that do not necessarily need to be upgraded : The servers that do not need immediate upgrade are DNS and DHCP
Convert each of the following for loops into an equivalent while loop. (You might need to rename some variables for the code to compile, since all four parts a-d are in the same scope.)
// a.
System.out.println("a.");
int max = 5;
for (int n = 1; n <= max; n++) {
System.out.println(n);
}
System.out.println();
// b.
System.out.println("b.");
int total = 25;
for (int number = 1; number <= (total / 2); number++) {
total = total - number;
System.out.println(total + " " + number);
}
System.out.println();
// c.
System.out.println("c.");
for (int i = 1; i <= 2; i++) {
for (int j = 1; j <= 3; j++) {
for (int k = 1; k <= 4; k++) {
System.out.print("*");
}
System.out.print("!");
}
System.out.println();
}
System.out.println();
// d.
System.out.println("d.");
int number = 4;
for (int count = 1; count <= number; count++) {
System.out.println(number);
number = number / 2;
}
Answer:
~CaptnCoderYankee
Don't forget to award brainlyest if I got it right!
Probability of theft in an area is 0.03 with expected loss of 20% or 30% of things with probabilities 0.55 and 0.45. Insurance policy from A costs $150 pa with 100% repayment. Policy with B, costs $100 pa and first $500 of any loss has to be paid by the owner. Which data mining technique can be used to choose the policy?
Answer:
Decision trees
Explanation:
Decision trees mainly include categorization and estimation. It is often used as a measure of selection. This also encourages the usage and choice of particular data within the overall structure.
In the given situation, we should choose Policy A has cost $150 as it has 100% repayment while on the other hand Policy B has cost $100 and the first $500 of loss would be paid by the owner
So for choosing the policy, we use the decision tree data mining technique as we have to take the decision with respect to minimizing the cost
Data mining technique which can be used to choose the policy is decision tree.
The data mining technique that can be used are as follows,
Categorization and estimate are the two major functions of decision trees,Decision tree frequently used as a selection criterion. This promotes the use and selection of specific data within the broader framework.According to given data,
We should pick Policy A, which costs $150 and has a 100% payback rate.Whereas, the owner would be responsible for the first $500 of loss under Policy B, which costs $100.Here choosing the correct policy, decision tree is used.
Learn more: brainly.com/question/15247828
The following numbers are inserted into a linked list in this order:
10, 20, 30, 40, 50, 60
What would the following statements display?
pCur = head->next;
cout << pCur->data << " ";
cout << pCur->next->data << endl;
a) 20 30
b) 40 50
c) 10 20
d) 30 40
Answer:
A. 20 30
Explanation:
Given
Linked list: 10, 20, 30, 40, 50, 60
Required
The output of the following code segment
pCur = head->next;
cout << pCur->data << " ";
cout << pCur->next->data << endl;
A linked list operates by the use of nodes which begins from the head to the next node, to the next, till it reaches the last;
The first line of the code segment; "pCur = head->next; " shifts the node from the head to the next node
The head node is the node at index 0 and that is 10;
This means that the focus has been shifted to the next at index 1 and that is 20;
So, pCur = 20
The next line of the code segment; cout << pCur->data << " "; prints pCur and a blank space
i.e. "20 " [Take note of the blank space after 20]
The last line "cout << pCur->next->data << endl; " contains two instructions which are
1. pCur = next->data;
2. cout<<pCur->data;
(1) shifts focus to the next node after 20 ; This gives pCur = 30
(2) prints the value of pCur
Hence, the output of the code segment is 20 30
You are writing a paragraph in a word processor. You
want to use the same text that appears elsewhere in a
different document, but you want to keep it in the other
document. To get the other text into the new document
most efficiently, you should:
Cut and paste
Ctrl + S
Copy and paste
Print the text and retype it so you don't make any mistakes.
Answer:
Explanation:
I mean I would copy and paste it. I hope thats right