Convert 90 mph into meter seconds and feer seconds 1 mile equals 1600 m 1 m equals 3.3 feet one hour equals 3600 seconds

Answer:

It reduces the force necessary to move a load a certain distance up by providing a path for the load to move at a low angle to the ground.

Explanation:

Answer:

23 seconds

Explanation:

Step one:

given data

mass m= 170kg

The spring constant is 1250 N/m

Required

The period required for 10 oscillations

Step two:

The expression relating period, mass, and spring constant is

[tex]T=2 \pi \sqrt{\frac{m}{k} } \\[/tex]

substituting our data we have

[tex]T=2 *3.142 \sqrt{\frac{170}{1250} } \\\\T=6.284* \sqrt{0.136}\\\\T=6.284*0.3687\\T=2.3s[/tex]

A Period is defined as the time required to complete one full oscillation

hence, having found the period to be 2.3 seconds, the time required for 10 oscillations will be 2.3*10= 23seconds

Answer:

I’m pretty sure it’s B. It is harmful to the person and beneficial to the bacteria.

Explanation:

I’m taking the test right now. But if you think about it the bacteria is fighting off the medicine to which means the bacteria will just keep growing. So I’m 97% sure it’s B. Good luck you can do it don’t stop believing in yourself!!!!!! Hope I helped. And remember at the end of the day all that matters is love and happiness not grades!!!!!!!

Answer:

Answer is B!

Explanation:

I took the cumulative exam and got 100%

The free body diagram of the falling stone's motion involves the weight of the stone acting downwards and the air resistance acting upwards.

A free-body diagram is a sketch of an object of interest with all the surrounding objects stripped away and all of the forces acting on the body shown.

the given forces on the falling stone include;

weight of the falling stone, W = 8.0 N, this force is acting downwards

Air resistance, R, = 2.4N, this is a frictional force resisting the stone motion. This force is acting upwards.

                                                ↑ R = 2.4 N

                                                Ф

                                                 ↓ W = 8.0 N

Thus, the free body diagram of the falling stone's motion involves the weight of the stone acting downwards and the air resistance acting upwards.

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Answer:

The ratio of the new internal energy to the old is 4

Explanation:

let the old pressure of the gas = P₁

let the old volume of the gas = V₁

then, the new pressure of the gas = 2P₁

the new volume of the gas = 2V₁

The internal energy of the gas is given as;

PV = nRT

PV = k

P₁V₁ = P₂V₂

[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]

The ratio of the new internal energy to the old is 4

Answer:

The period of the ride when it is being operated at the maximum acceleration is T=2.81 s.

Explanation:

We can use the centripetal acceleration here:

[tex]a_{c}=\frac{v^{2}}{R}=\omega^{2}R[/tex]

Let's find the angular velocity ω at the maximum acceleration.

[tex]20=\omega^{2}*4[/tex]

[tex]\omega=2.24 rad/s[/tex]

The period is given by:

[tex]T=\frac{2\pi}{\omega}[/tex]

[tex]T=\frac{2\pi}{2.24}[/tex]

Therefore, the period will be T=2.81 s.

I hope it helps you!

Answer:

The value  [tex]f = 21.49 \ cm[/tex]

Explanation:

From the question we are told that

    The index of refraction is  [tex]n = 1.60[/tex]

     The outer radius of curvature is  [tex]R = 2.08 \ cm = 0.0208 \ m[/tex]

     The  inner radius is  [tex]r = 2.48 \ cm = 0.0248 \ m[/tex]

Generally from  Maker's equation we have that

       [tex]\frac{1}{f} = [n - 1 ][\frac{1}{(R)} - \frac{1}{r} ][/tex]

=>    [tex]\frac{1}{f} = [1.60 - 1 ][\frac{1}{( 0.0208 )} - \frac{1}{0.0248} ][/tex]

=>    [tex]\frac{1}{f} = 4.65[/tex]

=>    [tex]f = 0.2149 \ m[/tex]

=>    [tex]f = 21.49 \ cm[/tex]

Answer:

A)  0.303 s  (3 s.f.)

B)  6.76 ms⁻¹  (3 s.f.)

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]  

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the projectile separately.

As the projectile is fired horizontally, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↓ as positive:

[tex]s=0.450\quad u=0\quad a=9.8[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\0.450&= (0)t+\dfrac{1}{2}(9.8)t^2\\0.450&= 4.9t^2\\t^2&= \dfrac{0.450}{4.9}\\t&=\sqrt{\dfrac{0.450}{4.9}\\t &=0.3030457634...\\ \implies t&=0.303\:\sf s\;\;(3\:s.f.)\\\end{aligned}[/tex]

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

[tex]s=2.050 \quad a=0 \quad t=0.3030457634...[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\2.050&= u(0.3030457634...)+\dfrac{1}{2}(0)(0.3030457634...)^2\\2.050&= 0.3030457634...u\\u&= \dfrac{2.050}{0.3030457634...}\\ u &=6.764654873...\\\implies u & = 6.76\:\sf ms^{-1}\;\;(3\:s.f.)\end{aligned}[/tex]

The term which is described as a seamount with a flattened top is called as guyots.

Guyot, commonly known as Tablemount, is an uninhabited submarine volcano with a flat peak that is more than 200 meters (660 feet) above sea level. These flat summits could be more than 10 kilometres in circumference (6 miles).

Seamounts called guyots have grown above sea level. The seamount's top was eroded by erosion by waves, leaving it with a flattened shape. The sea bottom gradually falls as a result of the ocean floor moving away from oceanic ridges, submerging the flattened guyots to form undersea flat-topped peaks. Once the guyot is formed, on it's top a coral colony will start developing and little by little make a circle shaped island, which represents the formation of the atoll.

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Answer:

N = 648.55[N]

Explanation:

To solve this problem we must use Newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

∑F =  Forces applied [N]

m = mass = 73.2 [kg]

a = acceleration = 0.950 [m/s²]

Let's assume the direction of the upward forces as positive, just as if the movement of the box is upward the acceleration will be positive.

By performing a summation of forces on the vertical axis we obtain all the required forces and other magnitudes to be determined.

[tex]-m*g + N = -m*a\\[/tex]

where:

g = gravity acceleration = 9.81 [m/s²]

N = normal force (or weight) measured by the scale = 83.4 [N]

Now replacing:

[tex]-(73.2*9.81)+N=-73.2*0.950\\-718.092+N=-69.54\\N = -69.54+718.092\\N = 648.55[N][/tex]

The acceleration has a negative sign, this means that the elevator is descending at that very moment.

The resultant of the external forces that act on Amy are the force due to gravity, friction and air resistance which equals 243.26 N

Given that,

Force due to air resistance, [tex]F_{air}[/tex] = 10 N

Angle of slope, θ = 30°

Mass, m = 60 kg

Coefficient of dynamic friction, μ = 0.08

Force due to gravity, w = m g

w = 60 * 9.8 = 588 N

Since the slope is at an angle, the weight exerted on the ground is not along the axis of slope. So resolving the axis into its vertical and horizontal components,

cos θ = [tex]w_{y}[/tex] / w

[tex]w_{y}[/tex] = 588 * cos 30°

[tex]w_{y}[/tex] = 509.2 N

Frictional force, [tex]F_{fr}[/tex]  = μ * [tex]F_{N}[/tex]

where,

[tex]F_{N}[/tex] = Normal force = [tex]w_{y}[/tex]

[tex]F_{N}[/tex] = 509.2 N

[tex]F_{fr}[/tex]  = 0.08 * 509.2

[tex]F_{fr}[/tex]  = 40.74 N

sin θ = [tex]w_{x}[/tex] / w

[tex]w_{x}[/tex] = 588 * sin 30°

[tex]w_{x}[/tex] = 294 N

Force due to gravity, [tex]F_{g}[/tex] = [tex]w_{x}[/tex]

[tex]F_{g}[/tex] = 294 N

The resultant of external forces acting on Amy, [tex]F_{R}[/tex] =  [tex]F_{g}[/tex] - [tex]F_{air}[/tex] - [tex]F_{fr}[/tex]  

[tex]F_{R}[/tex] = 294 - 10 - 40.74

[tex]F_{R}[/tex] = 243.26 N

Therefore, the resultant of the external forces that act on Amy is 243.26 N

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Answer:

here is the answer

Explanation:

117974.472

Explanation:

a matter is solid gas and liquid

Answer:

matter is anything made of mass which occupys volume

Explanation:

matter is a thing which concludes mass and mentioned and also has volume ( volume is defined as space too) so everything is made of matter

Answer:

im not really good at explaining, but i found this website url:

https://www.numerade.com/questions/a-cyclist-travels-from-point-a-to-point-b-in-10-min-during-the-first-20-min-of-her-trip-she-maintain/

same question just with the explanation

Given :

A copper rod has a length of 1.7 m and a cross-sectional area of [tex]3.2 \times 10^{-4} \ m^2[/tex].

One end of the rod is in contact with boiling water and the other with a mixture of ice and water.

To Find :

The mass of ice per second that melts.

Solution :

Amount of heat transfer from boiling water to ice through the copper bar is :

[tex]Q = \dfrac{kA\Delta T }{L}\\\\Q = \dfrac{390\times 3.2 \times 10^{-4} \times 100}{1.7}\\\\Q = 7.34 \ J/s[/tex]

Let, amount of ice melts per second is :

[tex]m=\dfrac{Q}{L_f}[/tex]

Here, [tex]L_f[/tex] is the latent of fusion of water and is equal to [tex]L_f = 3.34\times 10^5 \ J/s[/tex].

Putting all values in above equation, we get :

[tex]m=\dfrac{7.34}{3.34\times 10^5}\\\\m = 2.19 \times 10^{-5} \ kg/s[/tex]

Hence, this is the required solution.

Answer:

I think the answer is  

a "cookbook" recipe for performing scientific investigations

Explanation:

Answer:

True

Explanation:

Because I had a test on this

Answer:

Moving slower in the negative direction.

Explanation:

This pig has an initial velocity of -10 (negative) and is accelerating at a rate of 2 m/s/s (positive). Since the acceleration has an opposite sign than the velocity, the object will be slowing down. Since the initial velocity was negative, it will be slowing down in the negative direction.

A more precisely defined value for the measurement of a second is now necessary due to decades of technological and scientific advancements. Right now, the second serves as the foundational unit of time in the International System of Units (SI).

Time is the continuous progression of existence and events that take place in what seems to be an irrevocable order from the past through the present and into the future. This is one of the quantities that make up numerous measurements which are used to compare the lengths of events or even the gaps between them, order events in time, and measure the rates at which those quantities in the physical world or in conscious experience change. In relation to the four spatial dimensions, time is frequently considered a fourth dimension.

Although time is long gone to been a crucial topic for research in philosophy, theology, and science, any definition of time that is universally applicable and free of roundness has ever been reached by academics.

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Days and hours are often used as units of time instead of seconds because they are more practical and convenient for measuring longer durations.

There are a few reasons why we use days and hours instead of seconds in everyday life.

Days and hours are more intuitive for humans to understand. It is easier to conceptualize a day or an hour than it is to conceptualize a second. For example, we can say that it takes 24 hours to make a day, or that it takes 60 minutes to make an hour. These units of time are also more relatable to our daily lives.

Days and hours are more practical for many applications. For example, it is more practical to measure the length of a day or an hour than it is to measure the length of a second. This is because days and hours are longer units of time, and they are more divisible.

Days and hours are more compatible with our calendars and timekeeping systems. Our calendars are based on days and hours, and our timekeeping systems are also based on days and hours. This makes it easier to keep track of time and schedule events.

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The car lands at a distance of 60 m from the base of the cliff.

s = ut + 1 / 2 a[tex]t^{2}[/tex]

s = Displacement

u = Initial velocity

t =Time

a = Acceleration

u = 20 m / s

[tex]s_{y}[/tex] = 30 m

θ = 20°

g = 9.8 m / s²

Resolving the velocity into its horizontal and vertical components

sin θ = [tex]u_{y}[/tex] / u

[tex]u_{y}[/tex] = - 20 sin 20°

[tex]u_{y}[/tex] = - 6.84 m / s

Considering only the vertical components,

[tex]s_{y}[/tex] = [tex]u_{y}[/tex] t + 1 / 2 g t²

30 = - 6.84 t + 4.9 t²

4.9 t² + ( - 6.84 ) t - 30 = 0

This is in the form of a quadratic equation,

t = - ( - 6.84 ) + √ [ ( - 6.84 )² - ( 4 * 4.9 * ( - 30 ) ) ] / 2 ( 4.9 )

t = 3.2 sec

The distance we need to calculate is in horizontal direction,

[tex]v_{x}[/tex] = [tex]s_{x}[/tex] / t

[tex]s_{x}[/tex] = 20 cos 20° / 3.2

[tex]s_{x}[/tex] = 60 m

Therefore, the car lands at a distance of 60 m from the base of the cliff.

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I'm not sure of this question, yet i know you may get angry but, just know your loved and if going through a hard time i'm so so sorry, i know how it feels it sucks. take care of yourself, drink water, listen to that one song that makes you dance in your room and go do what YOU love. your beautiful your perfect and dont listen to what anyone says. i love u, everyone loves u, i know its scary but it happens to everyone life isnt a peice of cake unfortunatly and it sucks but woahh your strong! if you need someone to talk to leave a comment below, happy hoildays everyone!

P.S, im looking into the answer of this question. I may not answer it right on time (since i'm not the smartest...) but i promise ill try my best! Also, i am not doing this for points im doing this to make others smile. I hate how no one checks up on anyone, lots of people are going through a stressful time (including me) and i just want to let everyone know that its okay not to be okay! I hope that you all find happiness in every possible situation, once again  HAPPY HOLIDAYS!

Answer:

12.5 Ns.

Explanation:

From the question given above, the following data were obtained:

Force (F) = 250 N.

Time (t) = 0.05 s

Impulse =?

Impulse can be obtained by using the following formula:

Impulse = force × time

Impulse = 250 × 0.05

Impulse = 12.5 Ns

Thus, the Impulse applied to the ball is 12.5 Ns.

Answer: 40 Celsius, 40 Fahrenheit, and 40 Kelvin

Work: I just converted them to Fahrenheit, and here's their Fahrenheit form, and with this information, I put them from highest to lowest.

- 40 Kelvin: -387.67 degrees

- 40 Celsius: 104 degrees

I hope this helps, and Happy Holidays! :)

Answer:

40 °C > 40 °F > 40 K

General Formulas and Concepts:

Chemistry

Explanation:

Step 1: Define

40 °F

40 °C

40 K

Step 2: Convert

40 °F = 5/9(40 - 32) = 4.4444... °C = 4.4444... + 273.15 = 277.594 K

40 °C = 40 + 273.15 = 313.15 K

Step 3: Compare

40 K < 277.594 K < 313.15 K

40 K < 40 °F < 40 °C

40 °C > 40 °F > 40 K

Answer:

decreases;inversely

Answer:

The increase in pressure inside the lungs is 0.09 atm

Explanation:

From the Pressure law

Pressure law states that the volume of a fixed mass of gas is directly proportional to the absolute temperature provided that the volume remains constant.

That is,

P ∝ T

Where P is the Pressure and T is the temperature.

Then, we can write that

P = kT

Where k is the proportionality constant

∴ [tex]\frac{P}{T} = k[/tex]

Then,

[tex]\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }[/tex]

From the question, [tex]P_{1}[/tex] = 1.0 atm

[tex]{T_{1}[/tex] = 12 °C = (12 + 273.15) K = 285.15K

[tex]{T_{2}[/tex] = 37 °C = (37 + 273.15) K = 310.15K

Therefore,

[tex]\frac{1.0}{285.15} = \frac{P_{2} }{310.15}[/tex]

[tex]P_{2} = \frac{1.0 \times 310.15}{285.15}[/tex]

[tex]P_{2} = 1.09[/tex] atm

Increase in pressure = [tex]P_{2} - P_{1}[/tex] = 1.09 atm - 1.0 atm

Increase in pressure = 0.09 atm

Hence, the increase in pressure inside the lungs is 0.09 atm

At constant volume, pressure of the gas is directly proportional to the temperature of the gas. The increased pressure inside the lungs is 0.9 atm.

From Gas law,

[tex]\bold {\dfrac {P_1} {T_1 } = \dfrac {P_2} {T_2 } }[/tex]

Where,

P1 - initial pressure = 0.1 atm

P2 - final pressure = ?

T1 - initial temperature = 12 °C = (12 + 273.15) K = 285.15 K

T2 - final temperature = 37 °C = (37 + 273.15) K = 310.15 K

Put the values in the formula,

[tex]\bold {\dfrac {1.0} {285.15 } = \dfrac {P_2} {310.15 } }[/tex]

[tex]\bold {P_2 = 1.09\ atm}[/tex]

Thus, increased pressure in the lungs

= 1.9 - 1.0

= 0.9 atm

Therefore, the increased pressure inside the lungs is 0.9 atm.

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Explanation:

This equation for acceleration can be used to calculate the acceleration of an object that is acted on by a net force. For example, Xander and his scooter have a total mass of 50 kilograms. Assume that the net force acting on Xander and the scooter is 25 Newtons. What is his acceleration? Substitute the relevant values into the equation for acceleration:

a=Fm=25 N50 kg=0.5 Nkg

The Newton is the SI unit for force. It is defined as the force needed to cause a 1-kilogram mass to accelerate at 1 m/s2. Therefore, force can also be expressed in the unit kg • m/s2. This way of expressing force can be substituted for Newtons in Xander’s acceleration so the answer is expressed in the SI unit for acceleration, which is m/s2:

a=0.5 Nkg=0.5 kg⋅m/s2kg=0.5 m/s2

Answer:

31.3mph North

Explanation:

Given parameters:

Distance traveled  = 1500miles

Time taken  = 48hrs

Unknown:

Velocity of the group of explorers = ?

Solution:

Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.

 So;

       Velocity = [tex]\frac{displacement}{time}[/tex]

Displacement is the distance moved in a specific direction = 1500miles North

 Insert the parameters and solve;

   Velocity = [tex]\frac{1500}{48}[/tex]   = 31.3mph North

Answer:

The value is [tex]L = 0.0073 \ H[/tex]      

Explanation:

From the question we are told that

    The number of turns is  [tex]N = 650 \ turns[/tex]

     The length is  [tex]l = 28 \ cm = 0.28 \ m[/tex]

      The radius of the cross-section is [tex]r = 3.5 \ cm = 0.035 \ m[/tex]

Generally the cross-sectional area  is mathematically represented as

       [tex]A = \pi * r^2[/tex]

=>    [tex]A = 3.142 * 0.035^2[/tex]

=>    [tex]A = 0.00384 \ m^2[/tex]

Generally the inductance is mathematically represented as

      [tex]L = \frac{N^2 * \mu _o * A }{ l}[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]

=>    [tex]L = \frac{ 650^2 * 4\pi * 10^{-7} * 0.00384 }{0.28}[/tex]

=>    [tex]L = 0.0073 \ H[/tex]