Different structures give compounds different properties

Answer:

gap junctions,tight junctions,and desmosomes

Answer:

Power of 5 watts is used

Explanation:

Mechanical Work and Power

Mechanical work is the amount of energy transferred by a force.

Being F the force vector and s the displacement vector, the work is calculated as:

[tex]W=\vec F\cdot \vec s[/tex]

If both the force and displacement are parallel, then we can use the equivalent scalar formula:

W=F.s

Power is the amount of energy converted per unit of time. The SI unit of power is the watt, equal to one joule per second.

The power can be calculated as:

[tex]\displaystyle P=\frac {W}{t}[/tex]

Where W is the work and t is the time.

It's required to calculate the power used in t=30 seconds when W=150 Joules of work are completed. Substitute in the formula:

[tex]\displaystyle P=\frac {150}{30}[/tex]

P = 5 Watt

Power of 5 watts is used

Answer:

  v_{f} = -0.693 m / s

Explanation:

The acceleration of the runner can be obtained from Newton's second law

       F = m a

        a = F / m

the bold are vectors, therefore the acceleration throughout the journey varies as the force has variations.

For the part of finding the velocity of the body we can use the relationship between the momentum and the variation of the momentum

            I = Δp

           ∫ F Δt = m [tex]v_{f}[/tex] - m v₀

           int F dt = m (v_{f}-v₀)

1) To find the change in velocity we must find the area under the curve of the graph, this can be done analytically if we know the functional of the curve or approximate it by intervals

a) between 0 <t <0.20 s

v) between 0.20 <t <0.30 s

a reasonable curve shape can be a Gaussian.

2) If we do not have the form of the cure, we can perform a graphical integration to find the area under the curve, we can do this by dividing the curve into small rectangles, finding the area of ​​each one and adding them.

3) Another even more approximate way is to create an average force in each interval and find the area of ​​this force, the average force is the average value of the force in the interval, let's use this method in the exercise

a) first interval 0 <t <0.20 Average force [tex]F_{mean}[/tex] = 300 N

    area = F_{mean} Δt

    area = I = 300 0.20

    I = 60 N s

the speed change is

    I = m Δv

    Δv = I / m

    Δv = 60/65

    Δv = 0.923 m / s

If we assume that the runner starts from rest, his final velocity is v = 0.923 m / s in the direction of the force.

b) second interval 0.2 <t <0.30s average force F_mean = 150 N

    area = I = 150 (0.30 - 0.20)

    I = 15 N s

the speed change is

    Δv = 15/65

    Δv = 0.23 m / s

Note that in this case the initial speed is not zero and since the two impulses are in the opposite direction the speed decreases

        [tex]v_{f}[/tex]= -0.923 + 0.23

        v_{f} = -0.693 m / s

Answer:

Looks like  streak color.

Explanation:

Wind is the stream of air rushing in to fill an area of low pressure. Winds are  generated by the differential distribution of temperature resulting in a pressure difference.

The natural movement of air or other gases in relation to a planet's surface is referred to as wind. There are many different sizes of winds, ranging from thunderstorm flows that last only a few minutes to local breezes.

Large-scale atmospheric circulation is primarily brought on by the planet's rotation and the difference in temperature between the equator and the poles (Coriolis effect).

Thermal low circulations over topography and high plateaus can cause monsoon circulations in the tropics and subtropics. Local winds can be defined in coastal regions by the sea breeze/land breeze cycle; in regions with varying terrain, mountain and valley.

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Answer:

F = Changing momentum / time

Explanation:

change in momentum = final momentum - initial momentum

Answer:

184 feets

Explanation:

Given the data:

time (sec) __ velocity (ft/sec)

0 __________30

1 __________ 54

2 __________56

3 __________34

4 __________ 8

5 __________ 2

6 __________22

Using left end approximation:

(0,1) ___ f(0) = 30

(1,2) ___ f(1) = 54

(2,3) ___f(2) = 56

(3,4) ___f(3) = 34

(4,5) ___f(4) = 8

(5,6) __ f(5) = 2

Hence, the Total distance traveled during the 6 second interval is:

Change ; dT = 1

1 * (30 + 54 + 56 + 34 + 8 + 2) = 184

Answer:

It depends on the medium is answer.

Explanation:

I hope it's helpful!

The energy of sound waves depends on the nature of medium it travels through. As the speed of the wave increases in the medium its energy increases. Hence, option d is correct.

Sound waves are type of mechanical waves passing through a medium. Sound waves are longitudinal waves hence, the oscillation of particles is in the same direction of of the wave propagation.

The energy of a wave is directly proportional to the frequency of the wave and inversely proportional to the wavelength. As the density of the medium increases, the speed of the wave decreases and thereby energy too.

Sound waves travels with higher speed through solids. As their energy increases, the waves moves with higher speed. Hence, the energy of sound waves depends on the nature of the medium.

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Answer:

Between 120 and 180 seconds

Answer:

Explanation:

Heat is probably the easiest energy you can use to change your physical state. The atoms in a liquid have more energy than the atoms in a solid.

Answer:

The easiest way is to heat matter which raises its internal energy andso the mass as well. Another possibility is to accelerate matter as in case of protons or heavy ions in the LHC, Protons ,for example , are accelerated to the energies of 6500 GeV which means increase of the rest mass by a factor of almost 7000.

Answer:

[tex]Position:(3.38m ,2.53m)[/tex]

[tex]Velocity=(1.72m/s,1.22m/s)[/tex]

Explanation:

From the question we are told that

Mass of particle 1  

 [tex]M_1=2.0kg[/tex]

Co-ordinate of particle 1 (2.0m,6.0m)

Velocity of Particle 1  

 [tex]V_1= (3.1 m / s , 2.6 m / s )[/tex]

Mass of particle 2  

[tex]M_2=4.5kg[/tex]

Co-ordinate of particle 2 (4.0m,1.0m)

Velocity of Particle 1  

[tex]V_2=( 1.1 m / s , 0.6 m / s )[/tex]

Generally the Position is mathematically given as  

[tex]X =\frac{ ((M_1 * Cx_1) + (M_2 *Cx_2)}{(M_1 + M_2)}[/tex]

 [tex]X=\frac{2*2+4.5*4}{2+4.5}[/tex]

[tex]X=3.38[/tex]

[tex]Y=\frac{(M_1* Cy_1 + M_2* Cy_2)}{(M_1 + M_2)}[/tex]

[tex]Y =\frac{(2 * 6 + 4.5 * 1)}{(2 + 4.5)}[/tex]

[tex]Y= 2.53 m[/tex]

Therefore the position is given as

[tex]Position:(3.38m ,2.53m)[/tex]

 Solving for Velocity

Generally the velocity of the system is mathematically Given as

[tex]V_x =\frac{ (M_1 * vx_1 + M_2 * Vx_2)}{(M_1 + M_2)}[/tex]

[tex]V_x=\frac{ (2 * 3.1 + 4.5 *1.1)}{(2 + 4.5)}[/tex]

[tex]V_x=1.72m/s[/tex]

For Y

[tex]V_y =\frac{(M_1* vy_1 + M_2* Vy_2)}{(M_1 + M_2)}[/tex]

[tex]V_y=\frac{ (2 * 2.6) + (4.5*0.6)}{(2 + 4.5)}[/tex]

[tex]V_y=1.22m/s[/tex]

Therefore Velocity

[tex]V=(1.72m/s,1.22m/s)[/tex]

Answer:

The height at point of release is 10.20 m

Explanation:

Given:

Spring constant : K= 5 x 10 to the 3rd power n/m

compression x = 0.10 m

Mass of block m= 0.250 kg

Here spring potential energy converted into potential energy,

mgh = 1/2 kx to the 2 power

For finding at what height it rise,

0.250 x 9.8 x h = 1/2 x 5 x 10 to the 3 power x (0.10)to the 2 power) - ( g= 9.8 m/8 to the 2 power

h= 10.20

Therefore, the height at point of release is 10.20 m

Answer:

[tex]v_2 = 6.406 / cos25.29[/tex]

Explanation:

From the question we are told that

Speed of snow ball 7.6m/s

Speed of chunk 9.3m/s at [tex]19 \textdegree[/tex]

Generally the equation for the conservation  of momentum is mathematically given as

Let the snow ball be b

and the chunk b/2

According to conservation of momentum we have

        [tex]b_u = (b /2) v_1 cos\theta_1 + (b / 2) v_2cos\theta_2[/tex]

        [tex]v_2 cos\theta_2 = 2 * 7.6 -9.3 * cos_19[/tex]

        [tex]v_2 cos\theta_2 = 15.2 -8.793 = 6.406[/tex]    

Therefore

          [tex](b/2)v_1 sin\theta_1 = (b/2) v_2sin\theta_2[/tex]

          [tex]v_2 sin\theta_2 = 9.3 * sin_19[/tex]

          [tex]v_2 sin\theta_2 = 3.027[/tex]

Mathematically From  above equations

        [tex]tan\theta_2 = 0.4726[/tex]

        [tex]\theta_2 = 25.29 \textdegree[/tex]

Therefore the speed and direction of second chunk

        [tex]v_2 = 6.406 / cos25.29[/tex]

        [tex]v2 = 7.0855m/s[/tex]

Answer:

0.0048kg

Explanation:

Given parameters:

Height of flight  = 8km  = 8000m

Gravitational potential energy  = 376J

Unknown:

Mass  = ?

Solution:

To solve this problem;

     Gravitational potential energy  = mgh

m is the mass of the body

g is the acceleration due to gravity

h is the height of the helicopter

    Insert the parameters and solve;

       376  = m x 9.8 x 8000

       376  = 78400m

         m  = 0.0048kg

Answer: 20496N

Explanation:

The formula to calculate the net force will be given as:

Net force = Acceleration × Mass

Since 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s, the net force would be:

= 10248 × 2

= 20496N

Answer:

t = 3.0s

Explanation:

U = 2.0m/s , V = 0 (stop) , S = 3m , t =?

From V^2 - U^2 = 2aS

=) a = -4/6 = -0.667m/s^2

Now again by V-U = at

We have t = -U/a = 2/0.667 = 3s

Required time is t = 3.0s

Answer:

In picture one because string telephones are best heard when there is more tension on the string

Explanation:

Answer:

car A reaches and immediately overtakes the car B at 22.56 s.

Explanation:

After car A accelerate at 1.8 m/s2, it travels a distance x(A) and car B will have travels a distance x(B), let's recall that the initial distance between them is 300 m, so we have:

[tex]x_{A}=300+x_{B}[/tex]

Now, we can rewrite this equation in terms of speed and time

[tex]V_{iA}t+\frac{1}{2}at^{2}=300+V_{iB}t[/tex]

Where:

V(iA) is the initial speed of car A

V(iB) is the initial speed of car B

t is the time when car A reaches the car B

a is the acceleration

[tex]18t+\frac{1}{2}1.8t^{2}=300+25t[/tex]

[tex]0.9t^{2}-7t-300=0[/tex]  

Solving this quadratic equation for t, and taking just the positive value, we will have:

t=22.56 s

Therefore, car A reaches and immediately overtakes the car B at 22.56 s.

I hope it helps you!

Answer:

1.2825 * 10^3 kg/m³

Explanation:

Given that :

Mass of aluminum ball (m1) = 4kg

Apparent mass of ball (m2) = 2.10 kg

Density of aluminum (d1) = 2.7 * 10^3 kg/m³

Density of liquid (d2) =?

Using the relation :

d1 / d2 = m1 / (m2 - m1)

(2.7 * 10^3) / d2 = 4 / (4 - 2.10)

2700 / d2 = 4 / 1.9

4 * d2 = 2700 * 1.9

4 * d2 = 5130

d2 = 5130 / 4

d2 = 1282.5 kg/m³

Hence, density of liquid = 1.2825 * 10^3

Answer:

the relative error is similar in all of them, which is why they all have the same precision.

Explanation:

For this question we must be careful since there are several important concepts to take into account:

* the absolute error that is directly related to the precision or error in the mean given by the instrument

* the relative error to take into account the precision of the instrument and the magnitude of the measurement

The precisions of the different measuring instruments are

metric conta           ± 0.1 cm

micrometric screw ±0.001 cm

vernier                    ± 0.005 cm or 0.001 cm

goniometers           ± 1º

I tilt meters              ± 1º

Mobile applications varies a lot, but on the order of  ±0.01cm

We can see that the tape measure, the micrometric screw and the vernier are the only ones that give us a direct measurement, in the others some calculation must be made to obtain the distance reading, for which the error must also be propagated for the calculation.

We must also take into account that the vernier and micrometric screw are for short measurements only a few centimeters, the meters allow a medium to about 20 m, for measurements of more distance the other instruments are needed

If we only take into account the absolute error, the device with a smaller error is the most accurate, but this is not very correct.

The precision must be related to the magnitude of the measurement carried out, that is why the error or relative uncertainty was defined.

Let's take an example with the tape measure.

If we measure a distance of 1 cm the relative error is ±0.1, for a distance of 10 cm the relative error is ±0.01 which is very good

if we use a vernier to measure 2 cm the error is ±0.0025

if we use an inclinometer or a goniometer to measure a distance of 100 m in error it is of the order of ±0.09 m

With a cell phone it depends on the form of measurement, but all programs involve the measurement of time of a pulse of light, and assume a constant speed of light regardless of the refractive index of the medium that changes this speed. In principle this could be a very precise method, but you must know the calculation procedure and the approximations used.

As we can see, to give a correct answer we must use the relative error in this case the instruments that use the optical measurement method should be the most accurate, but the software for the calculation can involve large approximations.

Of the other instruments, the relative error is similar in all of them, which is why they all have the same precision.

Answer:

Explanation:

while it is still falling it is turned into kinetic energy. While on the floor it turns onto potential energy. Remember energy cannot be created or the destroyed so the other ones are automatically out.

Answer: 15000 J

Explanation:

Given ;

Temperature change, dθ = 10

Mass of substance, m = 5 kg

Specific heat capacity, C = 300 j/kg°C

Quantity of heat, Q required is obtained using the relation ;

Q = mCdθ

Q = 5kg * 300 j/kg°C * 10°C

Q = 5 * 300 J * 10

Q = 15000 J

Answer:

As opposites attract, q is pulled to Q. And that force from Q is working on q, force over distance. Which means the potential energy q started with is being converted into kinetic energy. q is accelerating and picking up speed.  

Explanation:

Answer:

A

Explanation:

into the galaxies of the

Answer:A

Explanation:I’m taking the test rn