Disaccharides are held together by a glycosidic bond. Hydrolysis of the disaccharide requires_____

Answers

Answer 1

Answer:

monosaccharides and glycosidic, I think

Explanation:

Answer 2

Answer:

pasagottt po plss

Explanation:

edi wow


Related Questions

Consider a disubstituted aromatic compound. The parent name is benzene and there is a chloro and bromo substituent. Disubstituted benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor. Br
Select the correct names for the structure.
1. 1-bromo-3-chlorobenzene
2. 3-bromo-1-chlorobenzene
3. meta-bromochlorobenzene
4. o-bromochlorobenzene
5. ortho-bromochlorobenzene
6. m-bromochlorobenzene

Answers

Answer:The correct names for the structure are:

--> 1. 1-bromo-3-chlorobenzene.

--> 3. meta-bromochlorobenzene.

--> 6. m-bromochlorobenzene.

Explanation:

Benzene is the simplest member of the aromatic hydrocarbons. It has a ring structure consisting of six carbon and six hydrogen atoms. This equally means that a benzene can have up to six substituents. One of the chemical properties is that benzene and other members of its series undergo substitution reaction whereby one or more of its six hydrogen atoms is replaced by monoatomic reagents.

Disubstituted benzene consists of two substituents which are described based on either numerical locants or specific words for the three possible forms.

The numerical locant method are used the same naming substitutes of other hydrocarbons. From the question, the numerical locant method was derived through using the following steps:

--> the functional group is benzene

--> there are two substituents which includes bromine( written as bromo) and chlorine ( written as chloro)

--> while placing the number, it's done alphabetically ('1-bromo' comes before '3-chloro') in a clockwise manner. This is to give chorine the lowest locant number.

The second naming method for a disubstituted benzene is the the ortho-, meta-, para- (or their singel letter equivalent) nomenclature method. This is only used for benzene structures.

--> ortho or O : this is used when the substituents are close to each other in the benzene ring.

--> meta or (m) : This is used when the substituents are separated by one carbon in the benzene ring.

--> para or (p): This is used when the substituents are across each other in the benzene ring

From the question, the bromine substituent is separated from the chlorine by one carbon atom, therefore it's meta-bromochlorobenzene or m-bromochlorobenzene.

Which of the following would most likely be caused by a tsunami?

A. reshaping of the shoreline
B. seafloor spreading
C. island formation
D. mountain formation


ASAP please

Answers

the answer Is A hope it helps

I think it’s A but also hear me out on this, Socratic is a really good app for questions like these and you don’t have to wait for someone to answer it!

Calculate the mass of water produced when 7.26 g of butane reacts with excess oxygen

Answers

Answer:

11.3 g.

Explanation:

Hello there!

In this case, since the combustion of butane is:

[tex]C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O[/tex]

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

[tex]m_{H_2O}=7.26gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}}*\frac{5molH_2O}{1molC_4H_{10}} *\frac{18.02gH_2O}{1molH_2O}[/tex]

Therefore, the resulting mass of water is:

[tex]m_{H_2O}=11.3gH_2O[/tex]

Best regards!

What is the mass in grams of 2.21 mole of Ca3(PO4)4?

Answers

Answer:

1105.29 grams

Explanation:

If you calculate the molar mass of Ca3(PO4)4 you'll get 500.13. Molar mass is the mass of one mole of a substance. Multiply 500.1194 by 2.21 because we have 2.21 moles to get 1105.264 grams.

The molar mass of Ca is 40.078 grams, and there are 3 of them. So 40.078 x 3 is 120.234 grams.

The molar mass of P is 30.974 and there are 4 P's, so 30.974 x 4 is 123.896 grams.

The molar mass of O is 16 grams and there are 6 of them. Again, 16 x 16 is 256 grams.

Add up 120.234 + 123.896 + 256 to get the molar mass of Ca3(PO4)4, 500.13.

a reaction vessel contains a small piece of magnesium metal and air (20%) of which is oxygen gas. The mixture is ignited and burns with a burst of light and heat, producing solid magneisum oxide. The mass of mgO, however, is less than the initital mass of magnesium and oxygen combined. What loss of mass

Answers

Answer: see below

Explanation:

Mg burning in air gives MgO and a smaller amount of Mg3N2

2Mg+O2=2MgO. 2*24.3+32=2*40.3

3Mg+N2=Mg3N2

Ignoring the nitride, MgO loss of mass during the reaction can be ascribed to

(1) relativistic loss as energy (too small to be measurable)

(2) During the reaction, which is strongly exothermic, a fraction f the material is blown off as tiny particles which adhere to the vessel.

explain how the particles of a substance change as a substance changes from a solid to a liquid to a gas.

Answers

Answer:

Some substances can change from the solid state to the gas state without ever becoming a liquid. During this process, known as sublimation, the sur- face particles of the solid gain enough energy to become a gas.When dry ice becomes a gas, it absorbs thermal energy from water vapor in the air.

Explanation:

For the reaction of reducing benzil (MW 210.23 g/mol) with sodium borohydride (MW 37.83 g/mol), if 2.56 g of benzil and 0.38 g of sodium borohydride were used to make hydrobenzoin (MW 214.26 g/mol), and 2.22 g of hydrobenzoin was obtained, which chemical is limiting reagent

Answers

Answer:

NaBH₄

Explanation:

First, we need to write the chemical formula of all the compounds:

Benzil: C₁₄H₁₀O₂

Sodium Borhydride: C₁₄H₁₀O₂

Hydrobenzoin: C₁₄H₁₄O₂

Now, let's write the reaction that is taking place and write all the products:

C₁₄H₁₀O₂ + 2NaBH₄ + 2H₂O -----------> C₁₄H₁₄O₂ + 2BH₃ + 2NaOH

We can see that the reaction is already balanced, so we don't need to do anything else.

The question of this exercise is to determine the limiting reagent of the reaction, in other words, the reagent that controls the reaction and produces the 2.22 g of the hydrobenzoin. And to know this we need to see the mole ratio in both reactants, and compare them to the given moles (That can be obtained with the given masses and MW)

According to the above reaction, we have a mole ratio of 1:2, so, let's calculate the moles of benzil and the borohydride, and see which of them is the limiting reactant:

moles C₁₄H₁₀O₂ = 2.56 / 210.23 = 0.0122 moles

moles NaBH₄ = 0.38 / 37.83 = 0.01 moles

moles  C₁₄H₁₄O₂ = 2.22 / 214.26 = 0.0103 moles

We have the moles of every species, now, let's see the mole ratio

If 1 mole of C₁₄H₁₀O₂ -----------> 2 moles of NaBH₄

Then 0.0122 moles C₁₄H₁₀O₂ ----------> X moles of NaBH₄

Solving for X:

X = 0.0122 * 2 / 1 = 0.0244 moles of NaBH₄ are required.

However, we only have 0.01 moles of NaBH₄, and we need so much more of this to completely react with the moles of the benzil. Therefore we can safely assume that the limiting reagent is the NaBH₄

Another data that we can use for this, is the fact the produced moles were 0.0103, and this value is nearest to the moles of NaBH₄ rather than the moles of the benzil.

So, in conclusion, Limiting reagent NaBH₄

Hope this helps

(10 points) A basement (with volume V) in a residence is found to be contaminated with radon coming from the ground through the floor drains. The concentration of radon in the room is [Co] under steady-state conditions. The room behaves as a CSTR, and the decay of radon is a firstorder reaction with a decay rate constant of [k]. a. Now the condition changes: The source of radon is closed off but there is no ventilation. What is the equation that describes the concentration of radon in the basement with time [Ct]

Answers

Answer:

[tex]\mathbf{C_{Out} = C_o \ exp \Big [ - \Big ( \dfrac{1}{\dfrac{V}{Q} } + k \Big) t \Big ] }[/tex]

Explanation:

The equation that describes the concentration of the radon in the basement with time Ct is;

[tex]\mathbf{C_{Out} = C_o \ exp \Big [ - \Big ( \dfrac{1}{\theta} + k \Big) t \Big ] }[/tex]

where;

[tex]C_o[/tex] = concentration of the radon

[tex]C _ {Out}[/tex] = allowable radon concentration

k = decay rate constant

= theoretical detention

t = time needed to lower the radon concentration

The theoretical detention [tex]\theta =\dfrac{V}{Q}[/tex]

[tex]\mathbf{C_{Out} = C_o \ exp \Big [ - \Big ( \dfrac{1}{\dfrac{V}{Q} } + k \Big) t \Big ] }[/tex]

Which climate is a subcategory of polar climate

A ice cap
B subarctic
C highlands
D humid continental

Answers

Answer:

Ice cap

Explanation:

See its polar so like north pole and north pole is ice cap.

Answer:

Ice cap

Explanation:

The Chinese first began recording astronomical observations about 2,000 years ago.


True
False

Answers

The answer is false

Why is the liquid oxygen machine producing less liquid oxygen than normal?

Answers

Answer:

Liquid oxygen evaporates at only a slightly higher temperature than liquid nitrogen because they have similarly low attraction between molecules. This would mean less liquid oxygen is coming out of tank 3 because some of it is evaporating as a gas instead.

The liquid oxygen machine is producing less liquid oxygen than normal because there's a low attraction between the molecules.

It should be noted that oxygen in its liquid state will take up less space. It can also be stored at a lower pressure than when it's in its gaseous state.

From the complete question, the liquid oxygen evaporates at a slightly higher temperature than the liquid nitrogen. The reason for this is due to the fact that they have similarly low attraction between molecules.

Read related link on:

https://brainly.com/question/16173485


Determine the the nuclei indicated in blanks in the
right side when Radium (Ra-226) undergoes an
alpha decay
Ne
226/ 88
Ra -->
+

Answers

The daughter isotope  : Radon-222 (Rn-222).

Further explanation

Given

Radium (Ra-226) undergoes an  alpha decay

Required

The daughter nuclide

Solution

Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,  

alpha α particles ₂He⁴ beta β ₋₁e⁰ particles gamma particles ₀γ⁰ positron particles ₁e⁰ neutron ₀n¹

The decay reaction uses the principle: the sum of the atomic number and mass number before and after decay are the same

Radium (Ra-226) : ₈₈²²⁶Ra

Alpha particles : ₂⁴He

So Radon-226 emits alpha α particles ₂He⁴  , so the atomic number decreases by 2, mass number decreases by 4

The reaction :

₈₈²²⁶Ra ⇒ ₂⁴He + ₈₆²²²Rn

what Li(s) + O2(g) -> Li2O(s) balanced is

Answers

Answer:

4 1 2

Explanation:

4 Li(s) + 1 O2(g) -> 2 Li2O(s)

To calculate the atoms of an element in a given molecule, we need to multiply stoichiometry by the number that is written on the foot of that element. Therefore, the balanced equation is 4 Li(s) + 1 O[tex]_2[/tex](g) [tex]\rightarrow[/tex] 2 Li[tex]_2[/tex]O(s).

What is Balanced equation?

Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side. The mass of the overall reaction should be conserved. There are so many types of chemical reaction reaction like combination reaction, displacement reaction.

The other characteristic of balanced reaction is that physical state should be written with each compound or molecule on reactant and product side. Physical state should be written in brackets. s means solid, l means liquid, g means gas. The balanced equation for the given reaction is 4 Li(s) + 1 O[tex]_2[/tex](g) [tex]\rightarrow[/tex] 2 Li[tex]_2[/tex]O(s)

Therefore, the balanced equation is 4 Li(s) + 1 O[tex]_2[/tex](g) [tex]\rightarrow[/tex] 2 Li[tex]_2[/tex]O(s).

Learn more about the balanced equation, here:

https://brainly.com/question/7181548

#SPJ2

g) How many grams of aluminum (Al) are present in 2.98 mol of Al?


h) How many moles of Br are there if the sample contained 5.6 x 1024 atoms of Br?

Answers

Answer:

26.982 g

i think so..........

Many popular brands of toothpaste contain about 1.00 mg of fluoride per gram of toothpaste. The fluoride compound that is most often used in toothpaste is sodium fluoride, NaF, which is 45% fluoride by mass. How many milligrams of NaF are in a 250.0 g tube of toothpaste

Answers

Answer:

Mass of NaF in 250 g tube of toothpaste = 100 mg of NaF

Explanation:

Mass of fluoride per gram of toothpaste = 1 mg

From the given data, the fluoride compound that is most often used in toothpaste is sodium fluoride, NaF, which is 45% fluoride by mass, mass of sodium fluoride per gram of toothpaste can be determined as follows:

1 mg of fluoride per gram of toothpaste = 45% total mass of NaF per gram of toothpaste

100% mass of NaF in toothpaste = 100/45 * 1 mg = 2.22 mg of NaF.

Therefore, mass of NaF per gram of toothpaste is 2.22 mg.

The mass of NaF in 250 g of toothpaste is then calculated below:

In 250 g of toothpaste, mass of NaF = 250 * 2.22 mg = 99.9 mg of NaF

How are the cells made by meiosis different from the original parent cell that
produced them?

Answers

Mitosis creates two identical daughter cells that each contain the same number of chromosomes as their parent cell. In contrast, meiosis gives rise to four unique daughter cells, each of which has half the number of chromosomes as the parent cell.

You are working to earn enough money for a vacation which costs 2100. Your take-home pay is $16.50/hour, but you only work 4-hour shifts each day. How many days will it take for you to earn enough money to pay for your vacation if all the money you earn goes towards your vacation?

Answers

Answer:

32 days.

Explanation:

First we determine how much is made in a day.

16.50 x 4 = 66.

Next, we divide 2100 by 66 to reach our amount of days needed.

2100 / 66 = 31.818181... [81 is what repeats over and over.]

We round this up to the nearest whole number. You can't underpay, so you have to round.

The next whole number would be 32, so our answer is 32 days.

how many NaF is 4.50 mol

Answers

The molar mass of NaF is 41.98817 g/mol so 4.5 * 41.98817 is 188.946765 g.

The value of the rate constant for a gas phase reaction can be changed by increasing the A. temperature of the reaction vessel. B. volume of the reaction vessel. C. pressure of the reactant. D. amount of product.

Answers

Answer:

temperature of the reaction vessel

Explanation:

temperature of the reaction vessel

The value of the rate constant for a gas phase chemical reaction can be changed by increasing the: A. temperature of the reaction vessel.

What is the rate constant?

In Chemistry, rate constant is typically used with rate law to tell the reaction rate or rate of a chemical reaction that is affected by activation energy.

The rate law equation.

Mathematically, the rate law is given by this formula:

[tex]R = k[A]^x[B]^y[/tex]

Where:

k is the rate constant.A is the concentration of reactant A.B is the concentration of reactant B.

Generally, the value of the rate constant for a gas phase chemical reaction can be changed by increasing the temperature of the vessel (container) that is used in conducting the chemical reaction.

Read more on rate constant here: brainly.com/question/24749252

A 40.5 g sample of aluminum is cooled 7.5°C. The specific heat capacity of aluminum is
0.900 J/g°C. What is the energy change for this sample?

Answers

Q=mc\Delta T
Q= 40.5g x 0.900 J/g degree Celsius x 7.5
Q= 273.4 J.
Even if it is cooled , we use the same temperature as heating it.

2. What is the final temperature when a 32.0 g piece of diamond at 33.5°C is heated with 360 J of energy?
(Cp = 0.509

Answers

Answer:

55.6 °C

Explanation:

From the question given above, the following data were obtained:

Mass (M) of diamond = 32.0 g

Initial temperature (T₁) = 33.5°C

Heat (Q) required = 360 J

Specific heat capacity (C) of diamond = 0.509 J/gºC

Final temperature (T₂) =?

Next, we shall determine the change in temperature. This can be obtained as follow:

The final temperature can be obtained as follow:

Mass (M) of diamond = 32.0 g

Heat (Q) required = 360 J

Specific heat capacity (C) of diamond = 0.509 J/gºC

Change in temperature (ΔT ) =?

Q = MCΔT

360 = 32 × 0.509 × ΔT

360 = 16.288 × ΔT

Divide both side by 16.288

ΔT = 360 / 16.288

ΔT = 22.1 °C

Finally, we shall determine the final temperature. This can be obtained as follow:

Initial temperature (T₁) = 33.5°C

Change in temperature (ΔT ) = 22.1 °C

Final temperature (T₂) =?

ΔT = T₂ – T₁

22.1 = T₂ – 33.5

Collect like terms

22.1 + 33.5 = T₂

T₂ = 55.6 °C

Therefore, the final temperature is 55.6 °C.

What are essential elements in plants?​

Answers

Answer:

Chlorophyll is one. I can't quite remember other

THE ANSWER IS
Magnesium hydroxide (Mg(OH)2): 58.33

Iron(III) oxide (Fe2O3): 159.70

Answers

Answer:

Ok, thanks?

Have a good day

Thanks for the answer ^^...yes i only commented for the points

Convert 8.876 × 10^12 m^2 to units of km^2.

Answers

Answer:

[tex]8.876\times 10^{18}\ km^2[/tex]

Explanation:

In this problem, we need to convert [tex]8.876 \times 10^{12}\ m^2[/tex] to km².

We know that,

1 km = 1000 m

⇒ 1 km² = 10⁶ m²

So,

[tex]8.876 \times 10^{12}\ m^2=8.876 \times 10^{12}\times 10^6\ km^2\\\\=8.876\times 10^{18}\ km^2[/tex]

So, [tex]8.876 \times 10^{12}\ m^2[/tex] is equal to [tex]8.876\times 10^{18}\ km^2[/tex].

If you were to burn a candle inside of a closed jar and the mass of the
closed jar and candle was 50 grams to begin with, what would the mass of
the jar and smoke be after the candle is done burning?

Answers

Answer:

50g

Explanation:

At the end of the burning process, the mass of the jar and smoke should be 50g after the candle burning is done.

In most systems, the law of conservation of matter finds expression. According to this law "matter is neither created nor destroyed but atoms are rearranged".

In this kind of system, no matter is allowed to escaped and the starting mass of the reactants compared to that of the product will be the same.

what is 78%
of 100? help​

Answers

78. Any percent of 100 is literally the number just wi th out the percent. Like 38 percent of 100 is 38. PLEASE MARK BRAINLIEST

Answer:

78

Explanation:

You have 100%, you take 22% and get 78%

(30 POINTS) Which order shows the levels of organization from largest to smallest?

organism, organ system, cell, organ, tissue
organism, tissue, organ system, organ, cell
organism, organ, organ system, cell, tissue
organism, organ system, organ, tissue, cell

Answers

Answer:

cell,tissue,organ,organ system,organism

Explanation: Cells becoming specialized are better able to carry out specific functions. So they work together in groups. different tissues are grouped together to form specialized organs which may perform one or more functions. Organs work together in organ systems. Systems then work together ina an organized way to form a multicellular organism.

Answer:

Some students use an apple to represent the Earth. What is the best reason to use an apple for this comparison?

a. The skin of an apple is very thin, and the crust of the Earth very thin.

b. The flesh of an apple is made of the same material all the way through, and the interior of the Earth is the same all the way through.

c. The seeds of the apple are very light in comparison to the rest of the apple, and the core of the Earth is also made of very light matter.

d. The stem of the apple comes from the core and the North Pole comes from the Earth’s core.

Answers

C.The seeds of the apple are very light in comparison to the rest of the apple, and the core of the earth is also made of very light matter.

Calculate the number of grams of 02, produced when 43 grams of potassium chlorate decomposes.
2KClO3=3O2+2KCl

Answers

Mass O2 = = 16.832 g

Further explanation

Given

43 grams of potassium chlorate

Required

Mass of O2

Solution

Reaction

2KClO3 ⇒3O2 + 2KCl

Mol KClO3 :

= mass : MW

= 43 g : 122,55 g/mol

= 0.3509

From the equation, mol O2 :

= 3/2 x moles KClO3

= 3/2 x 0.3509

= 0.526

Mass O2 :

= 0.526 x 32 g/mol

= 16.832 g

Why is one side of the moon called "the dark side of the moon"?

Answers

Answer:

Option C

Explanation:

The answer is option C or "The amount of time it takes to rotate around it's axis is the same amount of time it takes to revolve around Earth."Remember that the Earth and the Moons amount of time to make a full rotation is almost in sync and they're two sides of the moon, one side we do not see and that's because that side is currently faced away from the Earth which is called the dark side of the moon. Each side has two weeks oh night, and two weeks of day because of how long it takes the moon to revolve, so while we have a side towards the Earth which is illuminated by the sun we have another pointing away in the dark.

Hope this helps.

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