Does this graph represent a function? Why or why not?
10+
8+
6-
110884
-8
O
A. No, because it is not a straight line.
B. Yes, because it passes the horizontal line test.
Ο Ο Ο
C. Yes, because it passes the vertical line test.
D. No, because it fails the vertical line test.

Answer:the answer would be 4. Hope this helps.

Step-by-step explanation:

Using the formula of union of three events, the number of patrons who didn't like any of given coffee drinks = 4.

Union of three events : P(A ∪ B ∪ C) = P(A) + P(B) + P(C) − P(A ∩ B) − P(A ∩ C) − P(B ∩ C) + P(A ∩ B ∩ C).

n (latte ∩ espressos) = 14

n (espressos ∩ cappuccinos) = 11

n (lattes ∩ cappuccinos) = 7

n (latte ∩ espressos ∩ cappuccinos) = 3

n (lattes) = 22

n (espressos) = 30

n (cappuccinos) = 23

n(latte ∪ espressos ∪ cappuccinos) =

= n (lattes) + n (espressos) + n (cappuccinos) - n (latte ∩ espressos) - n (espressos ∩ cappuccinos) - n (lattes ∩ cappuccinos) + n (latte ∩ espressos ∩ cappuccinos)

= 22 + 30 + 23 - 14 - 11 - 7 + 3

= 46

n (universe) = 50

Number of patrons who didn't like any of these drinks =  

= n (universe) - n (latte ∪ espressos ∪ cappuccinos) = 50 - 46 = 4

Learn more about union of three events here

https://brainly.com/question/14614116

#SPJ3

Answer:

see explanation

Step-by-step explanation:

Given

y = x² - 2x - 8

To find the x- intercepts let y = 0 , that is

x² - 2x - 8 = 0 ← in standard form

(x - 4)(x + 2) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 2 = 0 ⇒ x = - 2

x- intercepts : x = - 2, x = 4

The x- coordinate of the vertex is mid way between the x- intercepts, that is

[tex]x_{vertex}[/tex] = [tex]\frac{-2+4}{2}[/tex] = [tex]\frac{2}{2}[/tex] = 1

Substitute x = 1 into the equation for corresponding y- coordinate

y = 1² - 2(1) - 8 = 1 - 2 - 8 = - 9

vertex = (1, - 9 )

Answer:

Step-by-step explanation:

A. The front elevation of the pyramid in the direction of the arrow is herewith attached to this answer.

B. Base of the pyramid is a square of side 12 cm.

   The height of the pyramid is 8 cm.

   Slant height, XT, is 10 cm.

The total surface area of the pyramid can be determined by adding the surface areas that make up the shape.

Area of the triangular face = [tex]\frac{1}{2}[/tex] × base × slant height

                                            =  [tex]\frac{1}{2}[/tex] × 12 × 10

                                            = 60 [tex]cm^{2}[/tex]

Area of the square base = length × length

                                         = 12 × 12

                                         = 144  [tex]cm^{2}[/tex]

Total surface area of the pyramid = area of the base + 4 (area of the triangular face)

                              = 144 + 4(60)

                              = 144 + 240

                              = 384 [tex]cm^{2}[/tex]

Therefore, total surface area of the pyramid is 384 [tex]cm^{2}[/tex].

Answer:

Savannah

Step-by-step explanation:

Emery has solved it incorrectly;

x = 100

Answer:

z=10 i hope this will help you

Step-by-step explanation:

3z+5=35

3z=35-5

3z=30

z=10

Answer:

Z = 10

Step-by-step explanation:

3Z+5=35

Subtract 5 from both sides

3Z=30

Divide both sides by 3

Z=10

Answer:

The experimental group in this case are the group of bees that are put in the small cage.

Step-by-step explanation:

The experimental group is the group of subjects that participate in the test. They are usually assigned to the treatments in study. In some cases there is a control group, with no assigned treatment.

In this case, the bees that she put in the cage, and they are not assigned to a particular treatment. It can be considered a control group.

Answer:

Step-by-step explanation:

[tex]\int\limits^{\infty}_0 {A^2_1} (e^{-r/a})r^2dr= {A^2_1}\int\limits^{\infty}_0r^2(e^{-r/a})^2\, dr)[/tex]

[tex]=A_1^2\int\limits^{\infty}_0 r^2e^{-2r/a}\ dr[/tex]

[tex]=A_1^2[\frac{r^2e^{2r/a}}{-2/a} |_0^{\infty}-\int\limits^{\infty}_0 2r\frac{e^{-2r/a}}{-2/a} \ dr][/tex]

[tex]=A^2_1[0+\int\limits^{\infty}_0 a\ r\ e^{-2r/a}\ dr][/tex]

[tex]=A^2_1[\frac{a \ r \ e^{-2r/a}}{-2/a} |^{\infty}_0-\int\limits^{\infty}_0 \frac{a \ e^{-2r/a}}{-2/a} \ dr][/tex]

[tex]=A_0^2[0-0+\int\limits^{\infty}_0 \frac{a^2}{2} e^{-2r/a}\ dr\\\\=A_1^2\frac{a^2}{2} \int\limits^{\infty}_0 e^{-2r/a}\ dr\\\\=A_1^2\frac{a^2}{2} [\frac{e^{-2r/a}}{-2/a} ]^{\infty}_0[/tex]

[tex]=\frac{A_1^2a^2}{2} -\frac{a}{2} [ \lim_{r \to \infty} [e^{-2r/a} -e^0]\\\\=\frac{A_1^2a^2}{2} -(\frac{a}{2}) (0-1)[/tex]

[tex]=\frac{A_1^2a^3}{4}[/tex]

[tex]\therefore A_1^2\int\limits^{\infty}_0 r^2(e^{-r/a}) \ dr =\frac{A_1^2a^3}{4}[/tex]

Find the unique positive value of A1

[tex]=4\pi (\frac{A_1^2a^3}{4} )\\\\=A_1^2a^3\pi\\\\A_1^2=\frac{1}{a^3\pi} \\\\A_1=\sqrt{\frac{1}{a^3\pi} }[/tex]

Answer:

(a)Area

(b)Andre is Right

Step-by-step explanation:

(a)Frost is spread on the surface of a cookie, therefore the question is talking about the area of the circular cookie.

(b)

Andre says, "The diameter of the cookie is about 3 inches, so the space for frosting is about 2.25 sq. in

Area of a Circle[tex]=\pi r^2[/tex]

Radius =Diameter/2 =3/2=1.5 Inches

Therefore, Space for frosting on the cookie

[tex]=\pi *1.5^2\\=2.25\pi$ in^2[/tex]

Andre is right.

Answer:

D. 150°

Step-by-step explanation:

x= 150°

Choice D

Answer:

40 litres

Step-by-step explanation:

V = l x w x h

50 x 40 x 20 = 40000

40000 cm^3

1cm^3 = 1ml

40000 cm^3/ 1cm^3 = 40000ml

40000 x 10^-3 = 40 litres

Answer:

The correct answer will be Option B (multinomial population).

Step-by-step explanation:

Other given options are not connected to the given situation. So that Option B seems to be the perfect solution.

Answer:

a

Step-by-step explanation:

(-1.00000005)^n

as n becomes very large, the function increases in both positive and negative direction.

If n=1, -1.00000005

if n=2, 1.0000001

if n= 3, -1.00000015

if n=20, 1.000001

if n=21, -1.00000105

Answer:

D. (250, 80)

Step-by-step explanation:

a) Outliers are values that "lie outside" the other values in a dataset, because their values are "far away" from the main group of data.

b) In this case, the values of A, B, and C have ratios of their coordinates of about 2.5, but the coordinate ratio of D is more than 3.  This makes it to lie far away from the group of data, and therefore an outliner.

c) The Ratios of the Coordinate Values are calculated as follows: A = 2.5 (150/60), B = 2.5 (50/20), C = 2 (200/100), while D = 3.125 (250/80).

Answer:

The answer is 8

Step-by-step explanation:

Plug -2 in for x. The double-negative inside the parenthesis makes it positive, then do the exponent.

Answer:

-(-2)^3 = 2^3 = 8

Answer is C

Step-by-step explanation:

So we plug in the numbers. We have -2 as x. (-(-2)^3 would be our thing. Thats  because our x is the negative so the negative of -2 is 2.

2^3 = 8

therefore its 8

Answer:

  ∠F ≈ 43.9°

Step-by-step explanation:

The Law of Cosines is used to find an angle when all triangle sides are known.

  f² = d² +e² -2de·cos(F)

  cos(F) = (d² +e² -f²)/(2de) = (25² +28² -20²)/(2·25·28) = 1009/1400

  F = arccos(1009/1400)

  F ≈ 43.9°

Answer:

The Probability that will pick a red tile from the bag

[tex]P(E) = \frac{6}{11}[/tex] = 0.545

Step-by-step explanation:

Explanation:-

Given data 4 blue tiles, 12 red tiles, and 6 green tiles in a bag

Total = 4 B + 12 R + 6 G = 22 tiles

Total number of exhaustive cases

         n (S) = [tex]22 C_{1} = 22 ways[/tex]

The Probability that will pick a red tile from the bag

[tex]P(E) = \frac{n(E)}{n(S)} = \frac{12 C_{1} }{22 C_{1} } = \frac{12}{22}[/tex]

[tex]P(E) = \frac{6}{11}[/tex]

P(E) = 0.545

Final answer:-

The Probability that will pick a red tile from the bag = 0.545

Answer:

Relative frequency:

[tex]\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\[/tex]

The most serious threat to aviation safety is, according to this data, "mechanical failures". It can be improved by more rigorous inspection and better maintenance policies and execution.

Step-by-step explanation:

We have the data for fatal plane crashes. The sum of plane crashes is

We can calculate the relative frequency as:

[tex]\text{Pilot error}=415/1370=0.30\\\\\text{Other human error}=96/1370=0.07\\\\\text{Weather}=169/1370=0.12\\\\\text{Mechanical problems}=622/1370=0.45\\\\\text{Sabotage}=68/1370=0.05\\\\[/tex]

We can see that the most frequent cause is "mechanical problems", with a relative frequency of 0.45.

Answer:

  (x, y) = (-3, -6)

Step-by-step explanation:

The (x, y) distance from R to T is ...

  (Δx, Δy) = T - R = (3, -3) -(-5, -7) = (3 -(-5), -3 -(-7)) = (8, 4)

Then 1/4 of the distance is ...

  (Δx, Δy)/4 = (8, 4)/4 = (2, 1)

This is added to the R coordinates to find the desired point:

  point = R +(2, 1) = (-5, -7) +(2, 1) = (-5+2, -7+1) = (-3, -6)

The coordinates are ...

  x-coordinate: -3

  y-coordinate: -6

Answer:

C

Step-by-step explanation:

2/3x - 5>3

Add 5 to each side

2/3x - 5+5>3+5

2/3x > 8

Multiply each side by 3/2

3/2 *2/3x > 8*3/2

x > 12

There is an open circle at 12 and the lines goes to the right

Answer:

The functions g and f are said to commute with each other if g ∘ f = f ∘ g. Commutativity is a special property, attained only by particular functions, and often in special circumstances. For example, |x| + 3 = |x + 3| only when x ≥ 0. ... The composition of one-to-one functions is always one-to-one.

\

Answer:

a) 48.80% probability that his travel time to work is less than 30 minutes

b) The mean is 30.7 minutes and the standard deviation is of 3.83 minutes.

c) 13.13% probability that in a random sample of 36 NJ workers commuting to work, the mean travel time to work is above 35 minutes

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

[tex]\mu = 30.7, \sigma = 23[/tex]

a. If a worker is selected at random, what is the probability that his travel time to work is less than 30 minutes?

This is the pvlaue of Z when X = 30. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{30 - 30.7}{23}[/tex]

[tex]Z = -0.03[/tex]

[tex]Z = -0.03[/tex] has a pvalue of 0.4880.

48.80% probability that his travel time to work is less than 30 minutes

b. Specify the mean and the standard deviation of the sampling distribution of the sample means, for samples of size 36.

[tex]n = 36[/tex]

Applying the Central Limit Theorem, the mean is 30.7 minutes and the standard deviation is [tex]s = \frac{23}{\sqrt{36}} = 3.83[/tex]

c. What is the probability that in a random sample of 36 NJ workers commuting to work, the mean travel time to work is above 35 minutes?

This is 1 subtracted by the pvalue of Z when X = 35. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{35 - 30.7}{3.83}[/tex]

[tex]Z = 1.12[/tex]

[tex]Z = 1.12[/tex] has a pvalue of 0.8687

1 - 0.8687 = 0.1313

13.13% probability that in a random sample of 36 NJ workers commuting to work, the mean travel time to work is above 35 minutes

Answer:

The test statistic to test the null hypothesis equals 1.059

Step-by-step explanation:

From the given information; we have:

Treatment               Observations

A                                20        30         25       33

B                                22         26        20       28

C                               40         30         28       22

The objective is to find the  test statistic to test the null hypothesis; in order to do that;we must first run through a series of some activities.

Let first compute the sum of the square;

Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex]  +    Error sum of squares   (ESS)

where:

(TSS) = [tex]\sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}oo)^2[/tex]  with (n-1)   df

[tex](T_r SS)[/tex]   [tex]= \sum \limits ^v_{i=1} n_i( \overline yio- \overline {y}oo)^2[/tex]   with (v-1)  df

[tex](ESS) = \sum \limits ^v_{i=1} \sum \limits ^{n_i}_{j-1}(yij- \overline {y}io)^2[/tex]   with (n-v) df

where;

v= 3

[tex]n_i=[/tex]4

i = 1,2,3

n =12

[tex]y_{ij}[/tex] is the [tex]j^{th[/tex] observation for the [tex]i^{th[/tex] treatment

[tex]\overline{y}io[/tex] is the mean of the  [tex]i^{th[/tex] treatment  i = 1,2,3 ;  j = 1,2,3,4

[tex]\overline y oo[/tex]   is the overall mean

From the given data

[tex]\overline y oo = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij)^2= 27[/tex]

[tex]TSS = \dfrac{1}{12} \sum \limits ^3_{i=1} \sum \limits ^{4}_{j=1}(yij- 27)^2 = 378[/tex]

[tex]T_r SS= \sum \limits^3_{i=1}4 (\overline y io - \overline yoo)^2[/tex]

[tex]=4(27-27)^2+4(24-27)^2+4(30-27)^2 = 72[/tex]

Total sum of squares (TSS) = Treatment sum of squares [tex](T_r SS)[/tex]  +    Error sum of squares   (ESS)

(TSS) =  378 - 72

(TSS) =  306

Now; to the mean square between treatments (MSTR); we use the formula:

MSTR = TrSS/df(TrSS)

MSTR = 72/(3 - 1)

MSTR = 72/2

MSTR = 36

The mean square within treatments  (MSE) is:

MSE = ESS/df(ESS)

MSE = 306/(12-3)

MSE = 306/(9)

MSE = 34

The test statistic to test the null hypothesis is :

[tex]T = \dfrac{ \dfrac{TrSS}{\sigma^2}/(v-1) }{ \dfrac{ESS}{\sigma^2}/(n-v) } = \dfrac{MSTR}{MSE} \ \ \ \approx \ \ T(\overline {v-1}, \overline {n-v})[/tex]

[tex]T = \dfrac{36}{34}[/tex]

T = 1.059

Answer:

x=-2

Step-by-step explanation:

3 + -4x = 5+ -3x

-4x = 2 - 3x

-x = 2

x = -2

Answer:

  closest choice: (-2, 0.2)

Step-by-step explanation:

The attached image from a graphing calculator shows the solutions (to the nearest tenth) to be ...

  (-1.9, 0.2)

  (1.0, 6.0)

The closest of the offered choices is (-2, 0.2). None are actually correct.

Answer:

  2 + h = 14 and k - 25 = 2

Step-by-step explanation:

An equation has an equal sign.

Apparently, your answer choices are of the form ...

  (math expression) and (math expression)

In order for this to be "only equations", each "math expression" must contain an equal sign. That is, you must have ...

  ( ... = ... ) and ( ... = ... )

Something like ...

  c -14  and  d +134

contains no equal signs, so has no equations.

It looks like your appropriate choice is ...

  2 + h = 14 and k - 25 = 2

Answer:

the answer is a

Step-by-step explanation:

i took the test

:)

note: have a wonderful day!

Answer:

x<_ 21

Step-by-step explanation:

5(x+27)>_ =6(x+26)

5x +135 >_ 6x +156

5x >_6x +21

-x>_21

x<_21

Answer:

Height = 12 inches

Step-by-step explanation:

Volume = Area × Height

1080 = 90 × H

H = 1080/90

H = 12 inches

Answer:

A.0.059 , B.0.063

Step-by-step explanation:

1. There are 13 clubs in a pack of 52 cards;

Hence the probability of picking the first club is 13/52;

The probability of picking the second is 12/ 51( remember one card has been removed already so the total number of cards decreases).

Probability of picking two clubs in succession is ;

13/52 × 12/51 = 0.0588 = 0.059( to the nearest thousandth).

2. The probability of drawing a club followed by a club with replacement is;

13/52 × 13 /52 = 0.0625 = 0.063( to the nearest thousandth)

Answer:

There were 210 downloads of the standard version.

Step-by-step explanation:

This question can be solved using a system of equations.

I am going to say that:

x is the number of downloads of the standard version.

y is the number of downloads of the high-quality version.

The size of the standard version is 2.6 megabytes (MB). The size of the high-quality version is 4.2 MB. The total size downloaded for the two versions was 4074 MB.

This means that:

[tex]2.6x + 4.2y = 4074[/tex]

Yesterday, the high-quality version was downloaded four times as often as the standard version.

This means that [tex]y = 4x[/tex]

How many downloads of the standard version were there?

This is x.

[tex]2.6x + 4.2y = 4074[/tex]

Since [tex]y = 4x[/tex]

[tex]2.6x + 4.2*4x = 4074[/tex]

[tex]19.4x = 4074[/tex]

[tex]x = \frac{4074}{19.4}[/tex]

[tex]x = 210[/tex]

There were 210 downloads of the standard version.