Explain how a musical instrument such as a piano may be tuned by using the phenomenon of beats.

Answers

Answer 1

Hence , musical instrument such as a piano may be tuned by using the phenomenon of beats.

Suppose 2 sound waves of various frequencies reach your ear. the 2 waves can interfere with one another leading to constructive and damaging interference. This may lead to the sound being instead soft and loud, that we have a tendency to decision beats. The beat frequency is that the distinction between the frequency of the 2 sound waves.

A musician typically uses the development of beat frequency to tune their piano. They pluck one string of the piano and faucet a implement at the same time. If the 2 sound sources turn out completely different beats, their frequencies will not be identical, and that they are aforementioned to be out of tune. The musician can modify the string's tension and repeatedly repeat the above mentioned method till the beats cannot be distinguished, that means the frequencies are identical. they're aforementioned to be in tune.

This methodology can work a lot of expeditiously for associate degree instrument entirely out of tune as a result of it'll be easier to differentiate the beats of the instruments and also the implement.

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Related Questions

Bats have poor vision and use echo-location to find their way.The frequency produced by bats is 100kHz. If the speed of the sound is 345m/s , how deep is the cave if the bat makes peeping sounds that return to the bat after 0,15s??

Answers

The distance covered is 25.9 m.

How deep is the cave?

We know that the speed of sound refers to the speed with which an sound moves in an object.

Given that;

speed of sound = 345m/s

Time taken =  0.15s

We know that;

v = 2d/t

v = speed of sound

d = distance

t = time taken

vt = 2d

d = vt/2

d = 345m/s *  0.15s/2

d = 25.9 m

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Write a hypothesis based on observations and scientific principles.

Answers

Answer:

An example of a hypothesis based on observation and scientific principles is:

Deaf children whose parents are deaf will acquire language faster than deaf children whose parents are not deaf.

A hypothesis is an informed prediction or a tentative statement about what you think that would occur in a scientific experiment as a result of experience from observations accepted by scientific rules and law.

A hypothesis is a testable statement obtained from the research question but questions cannot be tested directly, it is the proposed relationship between the variables that are tested.

An example of a hypothesis is:

Deaf children whose parents are deaf will acquire language faster than deaf children whose parents are not deaf.

This specifies the direction of the hypothesis because one group is faster than the other.

Explanation:

2 Calculate the mass of a car that hits a wall, during an accident, with a force of 961 N and an acceleration of 31m/s2. (4D) (F = m * a) *

Answers

Answer: 31kg

Explanation:

(F=mxa)

Rearranged

M=f÷a

961÷31=31

what is the electric force on a due to b in component form? express your answer in terms of the unit vectors i^ and j^ . use the 'unit vector' button to denote unit vectors in your answer.

Answers

The electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]

Charge of A = 4 nC = [tex]4\times 10^{-9}[/tex] C

Charge of B = -8 nC = [tex]-8\times 10^{-9}[/tex] C

A is on the origin, (0,0) and B is at the point (0 cm,2cm).

Therefore, distance between charges A and B, r = [tex]\sqrt{(0-0^2)+(0-2)^2} =2[/tex]

Using Coulomb's law, the electric force is directly proportional to the product of charges and inversely proportional to the square of distance between charges.

i.e., [tex]F_{A\ on\ B}=\frac{kq_1q_2}{r^2}[/tex], where k = [tex]9\times 10^9 Nm^2C^{-2}[/tex], the Coulomb constant.

So [tex]F_{A\ on\ B}=\frac{9\times 10^9\times 4\times 10^{-9}\times 8\times 10^{-9}}{2^2} = \bold{72\times 10^{-9} N}[/tex]

Since there is no x-component for this force,

the electric force on a due to b in component form = [tex]\bold{0\vec i+72\times10^{-9}\vec j\ N}[/tex]

The question incomplete. Find the complete question here:

Object A, which has been charged to +4.0 nC is at the origin. Object B, which has been charged to -8.0 nC, is at (x, y)=(0.0 cm, 2.0 cm).  What is the electric force on A due to B in component form? Express your answer in terms of the unit vectors i and j. Use the 'unit vector button to denote unit vectors in your answer.

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The magnetic moment of the Earth is approximately 8.00 ×10²²A.m² . Imagine that the planetary magnetic field were caused by the complete magnetization of a huge iron deposit. with density 7900 kg / m³, and approximately 8.50×10²⁸ atoms / m³, (a) How many unpaired electrons, each with a magnetic moment of 9.27 ×10⁻²⁴A.m² , would participate?

Answers

[tex]4.315 \times10^{45}[/tex] unpaired electrons,are required each with a magnetic moment of 9.27 ×10⁻²⁴A.m² , to participate .

Magnetic moment, additionally referred to as dipole moment, may be a live of the  tendency of associate degree object to align with a field of force. torsion may be a vector amount. Objects tend to be placed in order that their torsion vectors square measure parallel to the lines of magnetism. The direction of the torsion points from the South Pole of the magnet to the North Pole. The field of force made by a magnet is directly proportional to its torsion."Magnetic moment is outlined because the magnetic strength and orientation of a magnet or alternative object that produces a field of force."

It is given that magnetic moment of the Earth is approximately 8.00 ×10²²A.m² .

Number of unpaired is found by dividing the magnetic moment of the Earth to the given magnetic moment of 9.27 ×10⁻²⁴A.m²

   [tex]n=\frac{8.00\times10^{22}}{9.27\times10^{-24}} \\\\n=8.63\times10^{45}[/tex]

Each iron atom has two unpaired electrons, so the number of iron atoms required is [tex]\frac{1}{2}\times 8.63\times10^{45}=4.315\times10^{45}[/tex] electrons.

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Two motorcycles start at the same point. One motorcycle travels 15 km due north and stops. The second motorcycle travels 32 km due west and stops. Which value is closest to the distance between the motorcycles when they stop?.

Answers

Two motorcycles start at the same point, one motorcycle travels 15 km due north and stops, the second motorcycle travels 32 km due west and stops, value closest to the distance between the motorcycles when they stop is 35.3 km.

What is Meant by Kilometers to Miles?

In general, kilometers to miles is the conversion of distance from the kilometers to miles. kilometers and miles are used to measure length from one point to the other. In metric system, kilometer is the unit of length and it is considered as the International System of Units, whereas miles are used in the imperial and US customary units. The kilometer is abbreviated as “km”, and mile is abbreviated as “mi”. These two measures are mostly used to measure the geographical land areas.

You are aware that hypotenuse of a right triangle is shorter than the total of the legs and longer than the longest leg.

The relevant distance in this geometry is greater than the 32 km and less than 15+32 = 47 km. The only option that falls within acceptable range is 35.3 kilometers.

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hi im in class and i need help!

Answers

Answer:

I think its D.

Explanation:

) observer a, who is at rest in the laboratory, is studying a particle that is moving through the laboratory at a speed of v

Answers

The distance between the markers in the laboratory where the particle is produced and where it decays is 30.24m.

What is radioactive decay?

Radioactive decay, also known as nuclear decay, radioactivity, radioactive disintegration, or radioactive decay, is the process by which an unstable atomic nucleus loses energy through radiation. A substance that has unstable nuclei is regarded as radioactive. Alpha decay, beta decay, and gamma decay are three of the most frequent kinds of decay, and they all entail the emission of one or more particles. Beta decay is a result of the weak force, while the nuclear force and electromagnetism are in charge of the other two mechanisms. Electron capture, which occurs when an unstable nucleus seizes an inner electron from one of the electron shells, is the fourth prevalent kind of decay.

Explanation:

From the perspective of observer A, the particle had a lifetime of 112 ns and moved at a speed of 0.9c.

0.9c = 2.7e8 m/s

112 ns = 1.12e-7 s

Since we already know the time and speed from the viewpoint of observer A, we can use those to determine the distance from that viewpoint without the need for any modifications.

[tex]d=v*t=2.7e8*1.12e-7=30.24m[/tex]

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revise and repeat: run a similar experiment with seeds B and C. Do seeds B and C need light to germinate? Describe your findings.

(Earth Science.)

Answers

Answer:فربما الى اغبر وابقاء على كل من اراد من دون اي نية لا اريد له الزواج او غيره او لا ربرلرل

الفيفي قثصشسيبزروت

Explanation:١٤٢٣٦٧٧٨٩

A spring with a constant of 92N/m is compressed 2.8 cm. How much potential energy is stored in the spring?

PE= J

Answers

Answer:

0.036J

Explanation:

Given parameters:

Spring constant , K  = 92N/m

Compression  = 2.8cm  = 0.028m

Unknown:

Potential energy  = ?

Solution:

To solve this problem;

          P.E  =[tex]\frac{1}{2}[/tex] K e²

 K is the spring constant

 e is the compression

so;

      P.E = [tex]\frac{1}{2}[/tex]  x 92 x 0.028²  = 0.036J

Which of the following is not a component of a normal experiment?
A. Control group
OB. Dependent variable
C. Independent variable
D. Validity group
Reset Selection

Answers

Answer:

D. Validity group

Explanation:

A validity group is not necessarily a component of a normal experiment.

A normal experiment is made up of the dependent variables, independent variables, and most times the control group.

The dependent variable is one that relies on the outcome of the effect produced from the experimental designThe independent variable is the one that causes a desired effect under the study. The control group is a group that does not receive any treatment nor attenuation of the conditions.

Review. A wire having a linear mass density of 1.00 g/cm is placed on a horizontal surface that has a coefficient of kinetic friction of 0.200. The wire carries a current of 1.50 A toward the east and slides horizontally to the north at constant velocity. What are (b) the direction of the smallest magnetic field that enables the wire to move in this fashion?

Answers

The direction of the smallest magnetic field that enables the wire to move in this fashion to East.

A magnetic force in the direction of north that is equal in strength to the friction force will be required.

Fm - f = 0

I L B = uk mg = 0.

(1.50 x 1 x B) - (0.20 x 0.1 x 9.8) = 0

B = 0.131 T

b) the magnetic force, Fm = IL x B. (cross product )

- > north F

What emf is induced across the ends of the wire?

The formula can be used to calculate the magnetic force for a moving charge particle;

∈= Bvlsinθ

Due to the parallel motion of the wire, the angle between the magnetic field and velocity is zero degrees.

B = 0.500 T

v = 1.50 m/s

l = 0.200 m

Therefore,

∈ = (0.500 T) (1.50 m/s) * (0.200 m) *sin 0

∈=0.15 * sin 0

∈= 0

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One long wire carries current 30.0 A to the left along the x axis. A second long wire carries current 50.0 A to the right along the line (y = 0.280m, z = 0). (c) What If? A uniform electric field is applied to allow this particle to pass through this region unelected. Calculate the required vector electric field.

Answers

The vector electric field is [tex]-1.73 \times 10^{4} {~}\hat{j} {~}N/C[/tex] .

A stream of charged particles, such as electrons or ions, flowing through an electrical conductor or a vacuum is known as an electric current.

One long wire carries a current I = 30.0 A to the left along the x-axis. I' = 50.0 A of current is being carried by a second lengthy wire to the right along the line (y = 0.280 m, z = 0).

Now,

The charge of a particle is q = - 2.00 μC which is moving with a velocity of [tex]v = 150\hat{i} {~}Mm/s[/tex].

At y = 0.1 m the total magnetic field is:

B = 1.16 × 10⁻⁴ T

Then the force on the particle is:

F =q(v × B)

[tex]F = (-2 \times 10^{-6} )[ ( 150 \times 10^{6})\hat{j} \times (1.16 \times 10^{-4})\hat{k} ][/tex]

F = 3.47 × 10⁻² N

A uniform electric field is applied.

Then the vector electric field will be:

F = qE

3.47 × 10⁻² = (-2 × 10⁻⁶ )E

[tex]E = -1.73 \times 10^{4}{~}\hat{j} {~}N/C[/tex]

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two particles, one with charge −3.77 μc and one with charge 6.91 μc, are 5.84 cm apart. what is the magnitude of the force that one particle exerts on the other?

Answers

The magnitude of the force that one particle exerts on the other = [tex]6.8644 \times 10^{13}[/tex] N

Charge of one particle,[tex]Q_1[/tex] = -3.77  μC

Charge of the other particle,[tex]Q_2[/tex]  = 6.91 μC

The opposite signs of the charges implies the presence of force of attraction between the particles.

Given distance between particles, r = 5.84 cm = 0.0584 m

Coulomb's law states that the magnitude of the force exerted between two particles is directly proportional to the product of magnitude of charges of the particle and inversely proportional to the square of the distance between the particles.

From this we can infer the equation, [tex]F=\frac{kQ_1Q_2}{r^2}[/tex]

where F is the force between the particles and k =[tex]9\times 10^9 Nm^2C^{-2}[/tex] is the Coulomb's Constant.

So F = (9 x 10^9 x 3.77 x 6.91)/(0.0584 x 0.0584)

        = [tex]6.8644 \times 10^{13}[/tex] N

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Can you please answer qeastion

Answers

Answer:

the mantel

Explanation:

yeeeeaaaaaaa

A child rides a bicycle in a circular path withí a radius of 3.0 m. The
tangential speed of the bicycle is 2.0 m/s. The combined mass of the bicycle and the child is 43 kg.

Answers

Answer:

57.3N

Explanation:

Given parameters:

radius of the path = 3m

tangential speed  = 2m/s

mass of the bicycle and child  = 43kg

Unknown:

centripetal force  = ?

Solution:

The centripetal force is the inward force on a body round a circular path.

It is expressed as;

    F  = [tex]\frac{mv^{2} }{r}[/tex]  

F is the centripetal force

m is the mass

v is the tangential speed

r is the radius

        F  = [tex]\frac{43 x 2^{2} }{3}[/tex]   = 57.3N

bob hits a baseball.what two systems are working together to make this happen

Answers

Answer:

Kinetic Energy and Mechanical energy

Explanation:

dynamical stability of giant planets: the critical adiabatic index in the presence of a solid core kundu, s.k., coughlin, e.r., youdin, a.n., armitage, p.j., 2021, mnras, submitted

Answers

The critical adiabatic index in the presence of a solid core dynamical stability of giant planets is called adiabatic index.

What is adiabatic index?

In warm material science and thermodynamics, the intensity limit proportion, otherwise called the adiabatic record, the proportion of explicit warms, or Laplace's coefficient, is the proportion of the intensity limit at steady strain to warm limit at consistent volume. The Adiabatic Index adding machine processes the adiabatic list ( γ) otherwise called the intensity limit proportion or proportion of explicit warms. Accordingly, for normally happening diatomic gases at close to standard circumstances, the adiabatic file can be roughly viewed as around 7/5 or 1.4. The particular intensity proportion or adiabatic list is connected with the levels of opportunity () of a gas particle by the situation.

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Two neutral objects, 1 and 2, are suspended by strings near one another. Object 2 is touched by a positively-charged insulated rod.


Immediately after the insulated rod is removed, Object 1 and Object 2 repel. What causes the two objects to repel?

Answers

Answer:

When 2 objects are in contact with one another and one of them receives a positive or a negative charge, then the objects  will repel one another because they are similarly charged.

explain how electric motors convert electrical energy to mechanical energy​

Answers

Answer:

[tex]\rightarrow[/tex] Electric motors build energy through the interaction between magnetic fields.

Magnetic fields may be generated by passing a current through a wire. Winding that wire into a coil intensifies the sector. Wrapping the coil around an iron core can intensify it more. One is going to be of the coil are North, the other South. Reverse the flow of current through the coil. The magnetic poles can swap. Place 2 separate coils close to one another and organize them therefore one turns whereas the opposite is fastened. Then build arrangements for this within the moving coil to reverse even as the opposite poles are about to line up.

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A wire is formed into a circle having a diameter of 10.0cm and is placed in a uniform magnetic field of 3.00mT . The wire carries a current of 5.00 A. Find (b) the range of potential energies of the wire-field system for different orientations of the circle.

Answers

The range of potential energies of the wire-field system for different orientations of the circle are -

θ                  U

0°             375 π x [tex]10^{-7}[/tex]

90°              0

180°        - 375 π x [tex]10^{-7}[/tex]

We have current carrying wire in a form of a circle placed in a uniform magnetic field.

We have to the range of potential energies of the wire-field system for different orientations of the circle.

What is the formula to calculate the Magnetic Potential Energy?

The formula to calculate the magnetic potential energy is -

U = M.B = MB cos [tex]$\theta[/tex]

where -

M is the Dipole Moment.

B is the Magnetic Field Intensity.

According to the question, we have -

U = M.B = MB cos [tex]$\theta[/tex]

We can write M = IA (I is current and A is cross sectional Area)

U = IAB cos [tex]$\theta[/tex]

U = Iπ[tex]r^{2}[/tex]B cos [tex]$\theta[/tex]

For [tex]$\theta[/tex] = 0°

U(Max) = MB cos(0) = MB =  Iπ[tex]r^{2}[/tex]B = 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =

375 π x [tex]10^{-7}[/tex].

For [tex]$\theta[/tex] = 90° →

U = MB cos (90) = 0

For [tex]$\theta[/tex] = 180°

U(Min) = MB cos(0) = - MB =  - Iπ[tex]r^{2}[/tex]B = - 5 × π × [tex]( 0.05 ) ^{2}[/tex] × 3 × [tex]10^{-3}[/tex] =

- 375 π x [tex]10^{-7}[/tex].

Hence, the range of potential energies of the wire-field system for different orientations of the circle are -

θ                  U

0°             375 π x [tex]10^{-7}[/tex]

90°              0

180°        - 375 π x [tex]10^{-7}[/tex]

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M With particular experimental methods, it is possible to produce and observe in a long, thin rod both a transverse wave whose speed depends primarily on tension in the rod and a longitudinal wave whose speed is determined by Young's modulus and the density of the material according to the expression v = √(Y/rho) . The transverse wave can be modeled as a wave in a stretched string. A particular metal rod is 150cm long and has a radius of 0.200cm and a mass of 50.9 g . Young's modulus for the material is 6.80× 10¹⁰N/m² . What must the tension in the rod be if the ratio of the speed of longitudinal waves to the speed of transverse waves is 8.00 ?

Answers

The tension in the rod when the ratio of speed is 8 is 1.34 × 10⁴ N.

The longitudinal waves speed is determined using the density of the material and the Youngs modulus with the expression:

v = √(Y/rho)

A wave in a stretched string can be used to represent the transverse wave.

The length of the metal rod is 150 cm and the radius of the rod is  cm.

The mass of the rod is 50.9 g.

Now, the Youngs modulus for the material is 6.80× 10¹⁰ N/m².

For the longitudinal wave

v(l) = (Y/ρ)^{1/2}

For the transverse wave :

v(T) = (Y/μ)^{3/2}

Now, we need

v(L) / v(T) = 8

And we know,

T = (μY) / (64ρ) where μ= m /L

And the density, ρ = mass / volume = (m) / (πr²L)

Therefore,

T = (πr²Y) / 64

T =  (π)(2 × 10⁻³)² × (6.8 × 10¹⁰) / 64

T = 1.34 × 10⁴ N

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Calculate the current in the above circuit.

Answers

Answer:

4 A

Explanation:

From the question given above, the following data were obtained:

Voltage (V) = 12 V

Resistance (R) = 3 Ω

Current (I) =?

From ohm's law,

Voltage (V) = Current (I) × Resistance (R)

V = IR

With the above formula, we can obtain the current flowing in the circuit as illustrated below:

Voltage (V) = 12 V

Resistance (R) = 3 Ω

Current (I) =?

V = IR

12 = I × 3

Divide both side by 3

I = 12/3

I = 4 A

Therefore, the current flowing in the circuit is 4 A.

Sound waves cause air to oscillate. What do light waves oscillate?​

Answers

Light waves oscillate a magnetic field and an electric field.

Mankind causes major disruptions within ecosystems

- true

-false

Answers

Answer:

true

Explanation:

common sense i am just guessing.

Answer: True

Explanation: For instance cutting trees for paper.

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A power supply is connected to an electric motor using two low resistance wires. the battery supplies 800 j of energy. how much of this energy will be transferred to the kinetic store of the motor?

Answers

The energy transfer to the kinetic store of the motor will be less than 800 J because some of the energy is dissipated in the surrounding.

A piece of electrical equipment that is used to supply power to the electrical load is called an electric power supply.

The basic objective of this device is to transfer power from the source to the consumer with the correct amount of voltage, frequency, and current.

Furthermore, this device transforms alternative current (AC) into low voltage direct current (DC).

It consists of four major elements: filter, transformer, regulator circuits, and rectifier.

To put it simply, a power supply transforms Ac voltage to DC voltage.

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how does the thickness of wood affect its stability

Answers

Answer:

Making the lumber thick will make it stiff, which seems good. On the other hand, with thicker lumber, differences in expansion on the two faces have more leverage to make the lumber move.

The image above shows two opposite forces acting on a rope, what can we say is true about the affect of the forces on
the rope?

Answers

Answer:

your answer is D

Explanation:

..........

Answer:

d

Explanation:

UsaTestPrep

In a diffraction experiment, a laser beam incident on a single slit of width a = 0.02
mm produces a diffraction pattern on a screen 100 cm from the slit. The width of the
central maximum is 2.8 cm. What is the wavelength of the light?

Answers

The n-th place is 2×10 −4 m

The diffraction pattern's minima is

nDλ =(3−1) d

Dλ = d

2Dλ

​ d= x 3 −x

​ 2Dλ = 3×10 −3

2×0.50×6000×10 −10

=2×10 −4 m

Why do diffraction patterns occur?

Diffraction of light, as it is used to describe light, occurs more explicitly when a light wave passes by a corner or via an aperture or slit that is physically

Light is diffracted primarily as a function of wavelength (frequency), amplitude, and slit width. The incident waves must have a larger amplitude than the slit width for any diffraction to take place. Diffraction won't happen if the wave is less than the slit width.

The quantity of diffraction increases with the wave's wavelength. When the gap size is almost equal to the wavelength, the most 2×10 −4 m occurs.

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What is the displacement of the object from 12 seconds to 16 seconds ?

Answers

Answer:

Displacement is the distance between an object’s initial position and its final position and is usually measured or defined along a straight line. Since this is a calculation that measures distance, the standard unit is the meter (m).

Explanation:

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